Answer:
Explanation:
Given that gravity on the Moon has approximately 1/6th of the strength of gravity on Earth, a man who weighs 60kg on Earth would weigh approximately 10kg on the Moon. His mass, however, remains constant.
An object of mass 25kg is falling from the height h=10 m. calculate
a. The total energy of an object at h=10m.
b. Potential energy of the object when it is at h= 4m
c. Kinetic energy of the object when it is at h= 4m
d. What will be the speed of the object when it hits the ground?
Answer:
a. E = 2452.5 J = 2.45 KJ
b. P.E = 981 J = 0.98 KJ
c. K.E = 1471.5 J = 1.47 KJ
d. vf = 14 m/s
Explanation:
a.
At the highest point the total energy is equal to the potential energy of the object:
E = Potential Energy = mgh
where,
E = Total energy =?
m = mass of object = 25 kg
g = acceleration due to gravity = 9.81 m/s²
h = height = 10 m
Theerfore,
E = (25 kg)(9.81 m/s²)(10 m)
E = 2452.5 J = 2.45 KJ
b.
P.E = mgh
where,
h = 4 m
Therefore,
P.E = (25 kg)(9.81 m/s²)(4 m)
P.E = 981 J = 0.98 KJ
c.
First, we will find the velocity at 4 m by using the third equation of motion:
[tex]2gh = v_f^2-v_i^2[/tex]
where,
h = height lost = 10 m - 4 m = 6 m
vf = final speed = ?
vi = initial speed = 0 m/s
Therefore,
[tex]2(9.81\ m/s^2)(6\ m) = v_f^2-(0\ m/s)^2\\v_f = \sqrt{117.72\ m^2/s^2} \\v_f = 10.85\ m/s[/tex]
Hence, the kinetic energy will be:
[tex]K.E = \frac{1}{2} mv_f^2\\\\K.E = \frac{1}{2} (25\ kg)(10.85\ m/s)^2[/tex]
K.E = 1471.5 J = 1.47 KJ
d.
We will find the velocity at the bottom by using the third equation of motion:
[tex]2gh = v_f^2-v_i^2[/tex]
where,
h = height lost = 10 m
vf = final speed = ?
vi = initial speed = 0 m/s
Therefore,
[tex]2(9.81\ m/s^2)(10\ m) = v_f^2-(0\ m/s)^2\\v_f = \sqrt{196.2\ m^2/s^2} \\[/tex]
vf = 14 m/s
If could watch a rocket that's putting a satellite into orbit around the Earth, you'd see that it doesn't just go straight up. It eventually leans over and flies basically parallel to the Earth's surface when it gets up high. Why does it do this?
a. It needs to stay close to the Earth, so that the satellite doesn't get affected by the gravity of the Moon.
b. It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.
c. It has to release the satellite inside the Earth's atmosphere.
d. If it doesn't turn over horizontally, it'll release the satellite in a region where there's no gravity.
Answer:
the correct answers B
It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.
Explanation:
In this exercise, let's look for the solution to the problem before reviewing the statements to find out which one is correct.
When the satellite is in orbit it must comply with Newton's law
F = m a
the force of the universal attractive force and the acceleration is centripetal
a = v² / r
we substitute
- G m M /r² = -m v² / r
v² = G M / r
v = [tex]\sqrt{\frac{GM}{r} }[/tex]
When analyzing this expression, the satellite is in a stable orbit because its centripetal acceleration creates a change in the direction of the velocity in such a way that it remains in an orbit
when reviewing the correct answers B
Kam does 4000J of work in climbing a set of stairs. if he does work in 6 seconds, whi is his power output?
Answer:
666.7 W
Explanation:
Power = P = W/t = 4000 J/6 s = 666.7 W (watts)
9. All of the following are adaptations of herbivores EXCEPT:
special digestive systems for digesting plant cellulose
Okeen eyesight for sporting prey
O coat colors that help them blend in with the land
fut teeth for chewing tough plant matter
PLZ HURRY PLZ IMM MARK BRAINLYEST
Answer:
B.KEEN EYESIGHT thats for predators !
Explanation:
Herbivores have multiple stomachs to process tough foods, coats to blend in so they don't get eaten, and tough teeth for chewing on the plants. THEY DO NOT HAVE PREY, THEY ARE THE PREY.
What is true about the direction of the force of friction? A. It always points straight down. B. It always opposes the direction of motion. C. It always points straight up. D. It never changes direction.
Answer: it always opposes the directions of motion is the right answer
Explanation:
Differentiate between mass and weight
Answer:
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
Explanation:
A thin rod has a length of 0.609m and rotates in a circle on a frictionless tabletop. The axis is perpendicular to the length of the rod at one of its ends. The rod has an angular velocity of 0.606rad/s and a moment of inertia of 1.05 x 10^-3 kg•m^2. A bug standing on the axis decides to crawl out to the other end of the rod. When the bug (whose mass is 5 x 10^-3 kg) gets where it’s going, what is the change in the angular velocity of the rod?
Answer:
-0.0069 rad/s
Explanation:
The change in angular velocity of the rod can be determined by using the conservation of angular momentum equation: Lf = Li.
The initial angular momentum of the rod is Li = Iwo and the final angular momentum of the rod is Lf = Iwf.
Plugging in the given values, we get:
(1.05 x 10^-3 kg•m^2)(0.606 rad/s) + (5 x 10^-3 kg)(0.609 m)^2(wf) = (1.05 x 10^-3 kg•m^2)(wo).
Solving for wf, we get wf = -0.0069 rad/s.
Therefore, the change in angular velocity of the rod is -0.0069 rad/s.
What makes water move through the water cycle? A the sun the rain C precipitation the ground
Answer: A. The Sun
Explanation: A. The Sun makes water move through the water cycle
Draw and label where the molecules of the test mixture ended up after the fan was turned off
Answer:
ahhahsvdjdjkd
Explanation:
sbnwtauajababcahajanavgzuz
As an object falls freely, the potential energy of the object
Which of the following light waves will have the highest frequency?
a. blue light
b. orange light
c. green light
d. red light
e. yellow light
This might help as well:
https://www.mathsisfun.com/physics/light.html
an electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the period of acceleration
===================================================
Explanation:
vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.
So,
x = 0.5*(vi + vf)*t
x = 0.5*(5+8)*20
x = 130 meters
represents the distance traveled. The first equation shown above is one of the four kinematics equations.
1. What is a node?
2. What is an antinode?
3. What is a wavelength?
Will mark brainliest if correct!!
Answer:
Node:-
A node is a point along a standing wave where the wave has minimum amplitude. For instance, in a vibrating guitar string, the ends of the string are nodes. By changing the position of the end node through frets, the guitarist changes the effective length of the vibrating string and thereby the note played.
Anti Node:-
An antinode is simply a point along a medium which undergoes maximum displacement above and below the rest position.
Wavelength:-
The total length of circle.
or
Wavelength can be defined as the distance between two successive crests or troughs of a wave.
Which describes the relationship between the frequency, wavelength, and speed of a wave as the wave travels through different media?
As speed changes, wavelength changes and frequency remains constant
As speed changes, frequency changes and wavelength remains constant As speed changes, wavelength and frequency change,
O As speed changes, wavelength and frequency remain constant
Answer: A) as speed changes, wavelength changes and frequency remains constant
Explanation: edg test
A car is travelling at 27m/s and decelerates at a=5m/s2 for a distance of 10m. Calculate its final velocity. (Hint does deceleration imply that the acceleration is positive or negative?)
If deceleration = 5 m/s²
then acceleration = -5 m/s²
According to third law of motion,
= v² = 2as + u²
= v² = 2×-5×10 + 27²
= v² = -100 + 729
= v =√ 629
= 25.08 m/s
Which letter of the following shows lateral inversion in a mirrior
i.A
ii.N
iii.M
iv.V
Answer:
ii. N
Explanation:
N is not laterally symmetrical. so it shows inversion in a mirror.
Answer:
ii) N
hope it is helpful to you
All of the following are examples of physical properties except which one?
A. conductivity
B. malleability
C. flammability
D. solubility
Answer:
the answer is c
Explanation:
melting = become liquefied by heat
solubility = a new bond formation
conductivity = electric transmitter
flammability = burnable
5.33 A constant force F= (4.70-379, 2.09) N. acts on an object of mass 180 kg, causing a displacement of that object by F= (4.25, 3.69-245) m What is the total work done by this force
The total work done by this force is 28.9-1457.86 N m.
What is total work?Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.
The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.
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The rabbit flea Spilopsyllus has a mass of 0.45 mg. It can jump vertically to aheight of about 3.5 cm. Biologists have hypothesized that the energy for the jump is most likely derived from the elastic potential energy stored in the resilin pads ofthe two rear legs of the flea. Each pad is estimated to have a volume of about and its strain typically reaches a value of 100%. The elastic modulus of resilience is about . Is the hypothesis plausible
Answer:
Therefore The hypothesis is not plausible Because
[tex]P.E \geq P.E_e[/tex]
[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]
Explanation:
From the question we are told that:
Mass [tex]M=0.45mg[/tex]
Jump height [tex]h=3.5cm \approx 0.03m[/tex]
Percentage strain [tex]\mu =100\%[/tex]
Generally the equation for potential energy is mathematically given by
[tex]P.E=mgh[/tex]
[tex]P.E=0.45*10^{-3}*9.8*0.03[/tex]
[tex]P.E=12.435*10^{-5}J[/tex]
Generally the equation for Elastic potential energy is mathematically given by
[tex]P.E_e=0.5*stress*strain *volume[/tex]
[tex]P.E_e=0.5*1*2*10^6*1*1.4*10^{-4*(10^-3)^3}[/tex]
[tex]P.E_e=1.4*10^{-7}J[/tex]
The hypothesis is only plausible at conditions where
[tex]P.E\leq P.E_e[/tex]
Therefore The hypothesis is not plausible Because
[tex]P.E \geq P.E_e[/tex]
[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]
Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3
a) What is the water pressure on the bottom of the tank? (pressure in psi)
Show calculations
b) What is the average force on the bottom?
Answer: [tex]0.1066\ psi, 15.611\ kN[/tex]
Explanation:
Given
the height of the tank is [tex]h=10\ cm[/tex]
The diameter of the tank is [tex]d=520\ cm[/tex]
Density of solution [tex]\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3[/tex]
[tex](a)[/tex] Water pressure at the bottom of the tank is
[tex]P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa[/tex]
[tex]1\ Pa=0.000145038\ psi[/tex]
[tex]\Rightarrow P=735\ Pa\ or\ 0.1066\ psi[/tex]
[tex](b) \text{Average force on the bottom is the product of pressure and area of the base}[/tex]
[tex]F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN[/tex]
What is the difference between positive and negative punishment?
In psychology
Answer: Negative punishment includes taking away a certain reinforcing item after the undesired behavior happens in order to decrease future responses. Positive punishment involves adding an aversive consequence after an undesired behavior is emitted to decrease future responses.
HOPE THIS HELPS
SUKHMANJOT
Millikan used tiny oil droplets and adjusted the electric field until the electric force balanced the weight of the droplet, and one of the droplets hovered in air. However, the drops are all different sizes and weights, and the amount of charge on each droplet also varies. So, the tuning of the electric field is different for droplets of different sizes, which carry different charges. Let us assume that the density of the oil Millikan used in his experiment is 800 kg m3
A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.
B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.
C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.
Answer:
A. 9.203 × 10⁻¹⁰ kg
B. 2.82 × 10¹⁰ V/m
C. 5.56 × 10³ V/m
Explanation:
A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.
We know density, ρ = mass of oil drop, m/volume of oil drop, v
m = ρv
ρ = 800 kg/m³ and v = 4πr³/3 (ince the oil drop is a sphere) where r = radius of oil drop = 65 μm = 65 × 10⁻⁶ m.
So, m = ρv = ρ4πr³/3
= 800 kg/m³ × 4π(65 × 10⁻⁶ m)³/3
= 800 kg/m³ × 4π274625 × 10⁻¹⁸ m³/3
= 878800000π × 10⁻¹⁸ kg/3
= 2760831623.97 × 10⁻¹⁸ kg/3
= 920277207.99 × 10⁻¹⁸ kg
= 9.203 × 10⁻¹⁰ kg
B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.
Since the electric force F = qE where q = charge on oil drop = 2e where e = electron charge = 1.602 × 10⁻¹⁹ C and E = electric field equals the weight of the oil drop W = mg where m = mass of oil drop = 9.203 × 10⁻¹⁰ kg and g = acceleration due to gravity = 9.8 m/s².
So, F = W
qE = mg
E = mg/q
E = mg/2e
substituting the values of the variables into the equation, we have
E = 9.203 × 10⁻¹⁰ kg × 9.8 m/s²/(2 × 1.602 × 10⁻¹⁹ C)
E = 90.1894 × 10⁻¹⁰ kg-m/s²/3.204 × 10⁻¹⁹ C
E = 28.15 × 10⁹ V/m
E = 2.815 × 10¹⁰ V/m
E ≅ 2.82 × 10¹⁰ V/m
C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.
Since F = W
qE = mg
E = mg/q
E = mg/11e
E = 10⁻¹⁵ kg × 9.8 m/s²/(11 × 1.602 × 10⁻¹⁹ C)
E = 9.8 × 10⁻¹⁵ kg-m/s²/17.622 × 10⁻¹⁹ C
E = 0.556 × 10⁴ V/m
E = 5.56 × 10³ V/m
Usain Bolt requires five seconds to step after he runs the 100 meter dash . When he wins the race he's running at 10 meters per second . What is his declaration? Please answer as soon as possible!
Answer:
d= -2
Explanation:
t=5s
S=100 meters
V= 10 m/ s
d=?
deceleration = (final velocity - initial velocity) / time. d = (vf - vi)/t.
The formula for acceleration can be used, recognizing that the final result must have a negative signe.
d= (0-10)/5
d= -2
The cooler star, the most ____ it is.
a) more luminous
b) more blue
c) redder
Answer:
c. more redder
def not blue cuz thats hottest and def not luminous
Answer:
it is c... redder
Explanation:
because i just look it up on googl3
What is the average time for the toy car to move 1.0 m on cement?
Answer:
24.4
Explanation:
you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4
Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.
To solve this we must be knowing each and every concept related to interval. Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as below.
What is interval?An interval is any set of numbers that fall between two distinct integers. This range includes all real values that fall between those two. All real numbers that lie in any 2 of a set's numbers are collectively referred to as an interval within mathematics.
For instance, the set of integers x fulfilling 0 x 1 is the interval consisting of 0, 1, and all numbers in between. a snapshot graph of wave on a string moving toward one another at 1 m/s at time t = 0 s.
At time t = 0,Y₀= 0 cm
At At time t =1, Y₁= 0 cm
At time t = 2, Y₂= 0 cm
At time t =3, Y₃= 0 cm
At time t =4, Y₄= 0 cm
At time t = 5 ,Y₅=0 cm
At time t = 6, Y₆= 0 cm
Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as above.
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A snowboarder on a slope starts from rest and reaches a speed of 3.4 m/s after 7.3 s.
The acceleration of the snowboarder is 0.466 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the snowboarder, we use the formula below.
Formula:
a = (v-u)/t........................ Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 3.4 m/su = 0 m/st = 7.3 sSusbtitute these values into equation 1
a = (3.4-0)/7.3a = 0.466 m/s²Hence, the acceleration is 0.466 m/s².
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What is the answer please help help ( science)
Answer:
Number 19
10 x 7.2
72N
Explanation:
20.
1.66 x 7.2
11.9
Which is approximately
12N
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
Answer:
the f is 1.3 m
Explanation:
Given that
An object 2.0m is from the concave mirror
And, the image is 4.0m from the mirror
We need to find out the f
So,
u = -2 m
v = -4 m
1 ÷ f = 1 ÷ v + 1 ÷ u
= (-1 ÷ 4) + (-1 ÷ 2)
= -3 ÷4
f = -4 ÷ 3
= |1.3| m
Hence, the f is 1.3 m
Which of the following is not a safety tip for outdoor activities
The following which is not a safety tip for outdoor activities is to go alone for a sense of oneness with nature and is therefore denoted as option A.
What is Safety?This is referred to as the condition of being protected from harm or other danger and it involves the use of various methods and activities and an example is to ensure that a basic first aid kit is available so as to help in the incident of an injury.
However going alone for a sense of oneness with nature is not a safety tip as should in case any issue arises there will be no one to support and rescue such individual.
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The full question is:
Which of the following is not a safety tip for outdoor activities
a. go alone for a sense of oneness with nature
b. bring a basic first aid kit
c. bring a flashlight or headlamp
d. pack plenty of water and energy-dense food