Help me plz snsnsns sn
Answer:
If the exponent is 0 the answer is 224/y^2
Step-by-step explanation:
Suppose the function H(t) gives the heart rate of a runner at various points in time during a 20 mile run. Describe an appropriate domain of this function. Include a description of the kinds of numbers in the domain as well as any limitations on their values.
.....................
64 is the product of vidya's height and 4
Answer:
16
Step-by-step explanation:
64 ÷ 4 = 16
Find the orthogonal decomposition of vector b = 9, 0, 0 with respect to vector a = 4, −5, 0 . (Your instructors prefer angle bracket notation < > for vectors.)
The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex] is
[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]
From the Question we are told that
Vector [tex]\vec b = <9, 0, 0>[/tex]
Vector [tex]\vec a = <4, -5, 0>[/tex]
Generally in the orthogonal decomposition of b to a we have
[tex]\vec b=\vec b"+\vec b'[/tex]
Where
[tex]\vec b"=(\frac{\vec b*\vec a}{\vec *\vec a})*\vec a[/tex]
[tex]\vec b"=(\frac{ <9, 0, 0>*<4, -5, 0>}{<4, -5, 0>*<4, -5, 0>})*<4, -5, 0>[/tex]
[tex]\vec b"=<\frac{4}{5},\frac{-8}{5},0>[/tex]
Therefore
[tex]b'= \vec b- \vec b"\\\\b'=<4,0,0>-<\frac{4}{5},\frac{-8}{5},0>[/tex]
[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]
in Conclusion
The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex] is
[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]
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Solve each equation V/8=13
Answer:
v = 114Step-by-step explanation:
[tex] \frac{v}{8} = 13[/tex]
=> v = 13 × 8
=> v = 114 (Ans)
solve the proportion:
40/24 =20/x
Answer:
12
Step-by-step explanation:
40/24 = 20/x
40x = 20 × 24
40x = 480
x = 480/40
x = 12
What do you call the set of numbers that
includes the whole numbers, their opposites and
zero?
Imaginary Numbers
Negatives
Integers
Positives
Answer:
integers
Step-by-step explanation:
so negative and positive are numbers in questions so no.
and def not Imaginary numbers
if n=4 and m=3 find 2n-3m
Answer:
hope it helps you........
Answer:
2n-3m
=2(4)-3(3)
=8 - 9
= -1
Which of the following represents the relationship
between h and C ?
A) C = 5h
3
B) C = - +5
4
C= +5
C) C = 3h + 5
D) h = 3C
Answer:
I think its c I hope I'm right
Help me pls i have to finish my homework i have more questions to post too
Answer:
17) 19
19) 8
Step-by-step explanation:
17)
(6 +6² -4)÷2
(6 +36 -4)÷2
(38)÷2
19
19)
3³ ÷3 - 1
27 ÷3 -1
9 -1
8
s= zh - 2zt^3 solve for z
Hi ;-)
[tex]s=zh-2zt^3\\\\z(h-2t^3)=s \ \ /:(h-2t^3)\\\\z=\dfrac{s}{h-2t^3}[/tex]
Answer:
z = [tex]\frac{s}{h-2t^3}[/tex]
Step-by-step explanation:
Given
s = zh - 2zt³ ← factor out z from each term
s = z(h - 2t³ ) ← divide both sides by h - 2t³
[tex]\frac{s}{h-2t^3}[/tex] = z
If BD=1,DC=2,AB=2,what must AC equal for the line segment AD to be an angle bisector?
(Show the correct, neat and understandable calculation steps to get the answer to this question)
Answer:
AC = 4
Step-by-step explanation:
For AD to be an angle bisector then it divides the opposite side into segments that are proportional to the other two sides, that is
[tex]\frac{AB}{AC}[/tex] = [tex]\frac{BD}{DC}[/tex] , substitute values
[tex]\frac{2}{AC}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
AC = 4
simplify 1/2+1/3-1/4
Answer:
7/12
Explanation:
Here are the steps to follow:
Write down the factors for the numerator and the denominator.
Determine the largest factor that is common between the two.
Divide the numerator and denominator by the greatest common factor.
Write down the reduced fraction.
Answer:
7/12
Step-by-step explanation:
[tex] \frac{1}{3} + \frac{1}{2} = \frac{2 + 3}{6} = \frac{5}{6} - \frac{1}{4} = \frac{20 - 6}{24} = \frac{7}{12} [/tex]
suppose the two vertical angles are measuring 6x + 15 and 4x + 32. what is the measure of each angle?
Answer:
measure of both angle is 66
Step-by-step explanation:
vertical angles are equal so,
6x+15=4x+32
6x-4x=32-15
2x= 17
X=8.5
now,
4X+32
= 4×8.5 +32
= 66
Express each mixed number as a percent 2 1/2 can someone please tell me the awnser
Answer:
im pretty sure its 250%
Step-by-step explanation:
Answer:
250%
Step-by-step explanation:
1 is 100% and double that is 200%
1/5 of 100% is 50%
200% + 50% = 250%
9/10 divided by 3/5
Answer:
1 1/2
Step-by-step explanation:
9/10 ÷ 3/5
Copy dot flip
9/10 * 5/3
Rewriting
9/3 * 5/10
3 * 1/2
3/2
1 1/2
Answer:
3/2
Step-by-step explanation:
9/10 ÷ 3/5
~Use copy dot flip
9/10 * 5/3
~Multiply
45/30
~Simplify
3/2
Best of Luck!
complete the steps of the calculation to find the value of x
Answer:
99 + x = 4x
99 = 3x
x =33
.....
The gradient of the line joining (4, q) to (6, 5) is twice the gradient
of the line joining (0, 0) to (4, q). Find q.
Answer:
q is 4
Step-by-step explanation:
[tex]gradient = \frac{y_{2} - y_{1} }{x _{2} - x _{1} } \\ [/tex]
let gradient of the line joining (4, q) to (6, 5) be x
let gradient of the line joining (0, 0) to (4, q) be y
[tex]y = 2x[/tex]
therefore:
[tex]( \frac{q - 0}{4 - 0} ) = 2( \frac{5 - q}{6 - 4} ) \\ \\ \frac{q}{4} = \frac{2(5 - q)}{2} \\ \\ \frac{q}{4} = 5 - q \\ \\ q = 4(5 - q) \\ q = 20 - 4q[/tex]
collect like terms:
[tex]q + 4q = 20 \\ 5q = 20 \\ q = \frac{20}{5} \\ \\ q = 4[/tex]
Let,
The gradient of line joining (4, q) to (6, 5) be "x".The gradient of line joining (0, 0) to (4, q) be "y".As we know,
[tex]Gradient = \frac{y_2-y_1}{x_2-x_1}[/tex][tex]y = 2x[/tex]then,
→ [tex]\frac{q-0}{4-0} = 2(\frac{5-q}{6-4} )[/tex]
[tex]\frac{q}{4} = \frac{2(5-q)}{2}[/tex]
[tex]\frac{q}{4} = 5-q[/tex]
By applying cross-multiplication, we get
[tex]q = 4(5-q)[/tex]
[tex]q = 20-4q[/tex]
By adding "4q" both sides, we get
[tex]q+4q= 20-4q+4q[/tex]
[tex]5q = 20[/tex]
[tex]q = \frac{20}{5}[/tex]
[tex]q = 4[/tex]
Thus the above value is correct.
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Determine the type and number of solutions of 4x - 4x + 1 = 0.
two real solutions
one real solution
two imaginary solutions
Answer:
1 real solution
Step-by-step explanation:
Use discramint formula.
[tex]b {}^{2} - 4ac[/tex]
If the discramint >0, the equation is going to have 2 real solutions
If the discramint =0, we going to have one real solution.
If the discramint<0, we going to have two imaginary solution
B is -4, A is 4 and C is 1 so
[tex] { - 4}^{2} - 4( 4)(1) = 0[/tex]
So the equation had one real solution.
Find the value of x.
A. 5.58
B. 9.14
C. 15.2
D. 10
PLEASE HELP!!! :(
Answer:
D. 10
Step-by-step explanation:
[tex]{ \sf{(12x + 12) \degree = 79\degree + (5x + 3)\degree}} \\ { \sf{ \{outer \: angle \: is \: equal \: to \: sum \: of \: inner \: angles \}}} \\ { \sf{12x - 5x = 79 + 3 - 12}} \\ { \sf{7x = 70}} \\ { \sf{x = 10}}[/tex]
Problem 11
Six friends who enjoy tennis decide to play a game of singles and a game
of doubles every day of the 7-week school holidays.
(a) Show that at least four of the games of singles will be between friends
playing each other for the fourth time.
(b) Show that at least four of the games of doubles will be between pairs
playing the same opposing pair for the second time.
Number combination can be used to find the number of selecting n items from m items
The known parameters are;
Number of days the six friends play a game of tennis = Every day = 7 days
Number of weeks the six friends the friends play for = 7 weeks
Therefore the total number of days = 7 × 7 days = 49 days
Required:
(a) The number of ways the friends can play with each other once is given as follows;
[tex]The \ number \ of \ 2 \ combinations \ in \ 6 \ options, C_6^2 = \dfrac{6!}{2!\times (6-2)!} = 15[/tex]
The number of ways the six friends can play with each other once is 15 ways
Therefore, minimum number of singles games that will be between the same friends playing each other is given as follows;
[tex]\mathbf{Number \ of \ games = \dfrac{7 \times 7}{C_6^2} }=3.2\overline 6[/tex]
Therefore, more than 3 of the games or four games will be between pairs playing the game more than four times together, and when at least four of the games of singles are counted it will be between friends playing each other for the fourth time
(b) The number of ways the friends can play game of doubles is given as follows;
[tex]C_6^4 = \dfrac{6!}{4! \times (6 - 4)!} = 15[/tex]
The number of pairs = ₆C₂ = 15
The number of games of doubles = 49
In 49 games, we have;
The number of times the same opposing will play a game of doubles where a member of the pair can be on either side of the court will given as follows;
[tex]\mathbf{Number \ of \ games \ of \ doubles \ between \ same \ pair} = \dfrac{7 \times 7}{15 } =3.2\overline 6[/tex]
Therefore, at least four of the of the games of doubles will be between the same set of four friends playing for the 4th time, which gives; at least four games of doubles between the same set of four friends, two of which are playing (as a pair) the same opposing pair for the 4/2 = second time
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ANSWER THIS ASAP PLEASE
Answer: 12 and -12
Step-by-step explanation:
Absolute value is the distance to zero (0)
Equation 1:
|(12) - 2| = 10
= 12-2
=10
Equation 2:
|(-12) - 2| = 10
= 12 - 2
= 10
) P is a set of prime numbers --- State it’s type.
A) Null set B) singleton set C) infinite set
E) A,B,C are correct.
Answer:
null set
Step-by-step explanation:
i am not sure but i hope it will help you
Answer:
singleton set is correct
How do you translate "Twelve decreased by a quarter of a number, x. in a variable expression
Answer:
12 - (1/4)x
Step-by-step explanation:
quarter of x is (1/4)x
Now, minus that from twelve.
is 1/2 √9 *√4 rational or irrational
Answer:
1/2 and 9 is rational but 4 is not
Step-by-step explanation:
A rational number is a number that can be written as a ratio. That means it can be written as a fraction, in which both the numerator (the number on top) and the denominator (the number on the bottom) are whole numbers.
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What is the period of the function y=tan (n/4(x-n/3)? 3 units 4 units 6 units 8 units
Answer:
8
Step-by-step explanation:
The function u given me is
[tex] \tan( \frac{\pi}{4} (x - \frac{\pi}{3} ) )[/tex]
The period of a function is represented by
[tex] \frac{2\pi}{ |b| } [/tex]
where b is the coefficient of the x variable.
The coefficient is pi/4 so
[tex] \frac{2\pi}{ \frac{\pi}{4} } = 8[/tex]
8 is the answer.
Answer: 4 units
Step-by-step explanation:
Triangle ABC with coordinates A (3,-2), B (5,5), and C (-4, 2) is reflected across
the x-axis. State the coordinates of the resulting triangle, A'B'C.
Step-by-step explanation:
the formula of coordinates (x, y) that reflected across the x-axis : (x, y) => (x, -y)
so,
A(3, -2) => A'(3, 2)
B(5, 5) => B'(5, -5)
C(-4, 2) => C'(-4, -2)
Coordinates of ∆ABC
A(3,-2)B(5,5)C(-4,2)Now co-ordibates of ∆A'B'C'
[tex]\\ \rm\longmapsto A'=(3,2)[/tex]
[tex]\\ \rm\longmapsto B'=(5,-5)[/tex]
[tex]\\ \rm\longmapsto C'=(-4,-2)[/tex]
What is the area of the figure?
A. 22 m2
B. 30 m2
O C. 33 m²
O D. 42 m2
E. 50 m2
Answer:
B. 30m2
Hope it helps you..Use a real number to represent the situation.
The temperature falls 14°F.
Answer:
-14°F
Step-by-step explanation:
Hey there!
can someone please give me an example of a position and motion of objects in space
Answer:
position of objects in space
for example: up, down, in front, behind, between, left, right.
motion of objects in space
for example: Stars, planets, moons.