#14. (10 points) An object is placed 16 [cm] in front of a diverging lens with a focal length of -6.0 [cm]. Find (a) the image distance and (b) the magnification.

Answers

Answer 1

To find the image distance and magnification of an object placed in front of a diverging lens, we can use the lens formula and the magnification formula.

(a) The lens formula relates the object distance (u), the image distance (v), and the focal length (f) of a lens:

1/f = 1/v - 1/u

Substituting the given values, we have:

1/-6.0 cm = 1/v - 1/16 cm

Simplifying the equation, we get:

1/v = 1/-6.0 cm + 1/16 cm

Calculating the value of 1/v, we find:

1/v = -0.1667 cm^(-1)

Taking the reciprocal, we find that the image distance (v) is approximately -6.00 cm.

(b) The magnification (m) of the lens can be calculated using the formula:

m = -v/u

Substituting the given values, we have:

m = -(-6.0 cm)/(16 cm)

Simplifying the equation, we find:

m = 0.375

Therefore, the image distance is -6.00 cm and the magnification is 0.375.

To know more about magnification, please visit

https://brainly.com/question/21370207

#SPJ11


Related Questions

A net torque on an object ________________________
a.will cause the rotational mass to change.
b.will cause the angular acceleration to change.
c.will cause translational motion.
d.will cause the angular velocity to change.

Answers

A net torque on an object will cause the angular acceleration to change. The correct option is B.

Torque is the rotational equivalent of force. It is a vector quantity that is defined as the product of the force applied to an object and the distance from the point of application of the force to the axis of rotation. The net torque on an object will cause the angular acceleration of the object to change.

The rotational mass of an object is the resistance of the object to changes in its angular velocity. It is a measure of the inertia of the object to rotation. The net torque on an object will not cause the rotational mass of the object to change.

Translational motion is the motion of an object in a straight line. The net torque on an object will not cause translational motion.

The angular velocity of an object is the rate of change of its angular position. The net torque on an object will cause the angular velocity of the object to change.

To learn more about angular acceleration click here

https://brainly.com/question/30237820

#SPJ11

Hoop 1=MR² Solid Sphere 1=3MR² Thin Spherical Shell 1=MR² Solid Cylinder 1 = MR² Thin Rod (Center) 1=MR² Thin Rod (End) 1=MR² 1. For the items above, assume that M and R remain constant, rank the items in terms of moments of inertia from least to greatest Greatest Least

Answers

Rotational inertia, commonly referred to as moments of inertia, is a feature of an object that governs how resistant it is to changes in rotational motion.

Here are the given items in terms of moments of inertia from least to greatest:

Moment of inertia of Thin Rod (End) 1=MR²

Moment of inertia of Thin Rod (Center) 1=MR²

Moment of inertia of Solid Sphere 1=3MR²

Moment of inertia of Hoop 1=MR²

Moment of inertia of Solid Cylinder 1 = MR²

Moment of inertia of Thin Spherical Shell 1=MR²

Note: When the mass and radius are the same, the moment of inertia of a thin spherical shell, a solid cylinder, and a thin rod are all equal to MR², but the moment of inertia of a solid sphere is equal to 3MR².

To know more about Moments of Inertia visit:

https://brainly.com/question/30051108

#SPJ11

6. [-/1 Points] DETAILS SERPSE10 7.4.OP.010. At an archery event, a woman draws the string of her bow back 0.392 m with a force that increases steadily from 0 to 215 N. (a) What is the equivalent spring constant (in N/m) of the bow? N/m (b) How much work (in 3) does the archer do on the string in drawing the bow? 3. Need Help? Read It

Answers

The question asks for the equivalent spring constant of a bow and the amount of work done by an archer in drawing the bow. The woman draws the string of the bow back 0.392 m with a steadily increasing force from 0 to 215 N.

To determine the equivalent spring constant of the bow (a), we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its displacement. In this case, the displacement of the bowstring is given as 0.392 m, and the force increases steadily from 0 to 215 N. Therefore, we can calculate the spring constant using the formula: spring constant = force / displacement. Substituting the values, we have: spring constant = 215 N / 0.392 m = 548.47 N/m.

To calculate the work done by the archer on the string (b), we can use the formula: work = force × displacement. The force applied by the archer steadily increases from 0 to 215 N, and the displacement of the bowstring is given as 0.392 m. Substituting the values, we have: work = 215 N × 0.392 m = 84.28 J (joules). Therefore, the archer does 84.28 joules of work on the string in drawing the bow.

Learn more about Equivalent Spring constant:

https://brainly.com/question/30039564

#SPJ11

A 7-cm-tall cylinder with a diameter of 4 cm is floating in a vat of glycerin (p = 1260 kg/m) . 5 cm of the cylinder are submerged. What is the density of the cylinder? A. 680 kg/m B. 900 kg/m C. 1512 kg/m D. 1764 kg/m

Answers

The density of the cylinder is 1260 kg/m^3. None of the given options (A, B, C, or D) matches the calculated density. It seems there might be an error in the provided options.

To determine the density of the cylinder, we need to use the principle of buoyancy.

The buoyant force acting on the cylinder is equal to the weight of the fluid displaced by the submerged portion of the cylinder. The weight of the fluid displaced is given by the volume of the submerged portion multiplied by the density of the fluid.

From question:

Height of the cylinder = 7 cm

Diameter of the cylinder = 4 cm

Radius of the cylinder = diameter / 2 = 4 cm / 2 = 2 cm = 0.02 m

Height of the submerged portion = 5 cm = 0.05 m

Volume of the submerged portion = π * radius² * height = π * (0.02 m)² * 0.05 m = 0.0000628 m³

Density of glycerin (ρ) = 1260 kg/m³

Weight of the fluid displaced = volume * density = 0.0000628 m³ * 1260 kg/m³ = 0.079008 kg

Since the buoyant force equals the weight of the fluid displaced, the buoyant force acting on the cylinder is 0.079008 kg.

The weight of the cylinder is equal to the weight of the fluid displaced, so the density of the cylinder is equal to the density of glycerin.

Therefore, the density of the cylinder is 1260 kg/m³.

None of the given options (A, B, C, or D) matches the calculated density. It seems there might be an error in the provided options.

To know more about buoyant force visit:

https://brainly.com/question/11884584

#SPJ11

A loop consists of 1.5 V battery and two 10 ohm bulbs in series.
Calculate the current.

Answers

The current flowing through the loop is 0.075 Amperes or 75 milliamperes. To calculate the current flowing through the loop, we can use Ohm's law, which states:

V = I * R

Where:

V is the voltage (potential difference) across the circuit,

I am the current flowing through the circuit, and

R is the total resistance of the circuit.

In this case, the voltage (V) is given as 1.5 V, and the total resistance (R) is the sum of the resistances of the two bulbs in series, which is 10 ohms + 10 ohms = 20 ohms.

Using Ohm's law, we can rearrange the equation to solve for the current (I):

I = V / R

Substituting the given values:

I = 1.5 V / 20 ohms

I = 0.075 A

Therefore, the current flowing through the loop is 0.075 Amperes or 75 milliamperes.

Learn more about battery:
https://brainly.com/question/26466203

#SPJ11

A 100kg satellite is orbiting the earth (ME = 5.97 x 1024 kg, RE = 6.37 x 10°m) in a circular orbit at an altitude of 200,000m (that is, it's 200,000m above the surface of the earth!) (a) Which force is keeping the satellite moving in a circle? (b) What is centripetal force on the satellite? (c) At what speed is the satellite moving? (d) What is the total mechanical energy of the satellite?

Answers

(a) The force keeping the satellite moving in a circle is the gravitational force between the satellite and the Earth.

In circular motion, there must be a force acting towards the center of the circle to maintain the motion. In this case, the gravitational force between the satellite and the Earth provides the necessary centripetal force.

The gravitational force can be calculated using Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

where F is the force, G is the gravitational constant (approximately 6.67 x 10^-11 N m^2/kg^2), m1 and m2 are the masses of the two objects (satellite and Earth, respectively), and r is the distance between their centers.

The mass of the satellite is given as 100 kg, and the mass of the Earth is approximately 5.97 x 10^24 kg. The distance between their centers can be calculated by adding the radius of the Earth (6.37 x 10^6 m) to the altitude of the satellite (200,000 m). Thus, the distance is 6.57 x 10^6 m.

Plugging in the values, we get:

F = (6.67 x 10^-11 N m^2/kg^2) * (100 kg) * (5.97 x 10^24 kg) / (6.57 x 10^6 m)^2

Calculating this yields:

F ≈ 980 N

The gravitational force between the satellite and the Earth is responsible for keeping the satellite moving in a circular orbit.

(b) The centripetal force on the satellite is equal to the gravitational force.

The centripetal force on the satellite is approximately 980 N.

In a circular motion, the centripetal force is the net force acting towards the center of the circle. In this case, the gravitational force provides the necessary centripetal force to keep the satellite in its circular orbit.

The centripetal force acting on the satellite is equal to the gravitational force, which is approximately 980 N.

(c) The speed at which the satellite is moving can be determined using the formula for circular motion.

The speed of an object moving in a circular path can be calculated using the formula:

v = √(G * M / r)

where v is the speed, G is the gravitational constant, M is the mass of the central object (Earth), and r is the distance between the centers of the satellite and the Earth.

Plugging in the values, we have:

v = √((6.67 x 10^-11 N m^2/kg^2) * (5.97 x 10^24 kg) / (6.57 x 10^6 m))

Calculating this yields:

v ≈ 7666 m/s

Conclusion: The satellite is moving at a speed of approximately 7666 m/s.

(d) The total mechanical energy of the satellite can be determined by summing its kinetic energy and gravitational potential energy.

The total mechanical energy of an object is the sum of its kinetic energy (resulting from its motion) and its potential energy (resulting from its position or height in a gravitational field).

The kinetic energy of the satellite can be calculated using the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass of the satellite, and v is its speed.

Plugging in the values, we have:

KE = (1/2) * (100 kg) * (7666 m/s)^2

Calculating this yields:

KE ≈ 2.95 x 10^9 J

The gravitational potential energy of the satellite can be calculated using the formula:

PE = -G * (m1 * m2) / r

where PE is the gravitational potential energy, G is the gravitational constant, m1 and m2 are the masses of the two objects (satellite and Earth, respectively), and r is the distance between their centers.

Plugging in the values, we have:

PE = -(6.67 x 10^-11 N m^2/kg^2) * (100 kg) * (5.97 x 10^24 kg) / (6.57 x 10^6 m)

Calculating this yields:

PE ≈ -2.92 x 10^9 J

Since the potential energy is negative, the total mechanical energy is the sum of the kinetic and potential energies:

Total mechanical energy = KE + PE ≈ 2.95 x 10^9 J + (-2.92 x 10^9 J)

Calculating this yields:

Total mechanical energy ≈ 2.5 x 10^7 J

The total mechanical energy of the satellite is approximately 2.5 x 10^7 joules.

To  know more about Force , visit;

https://brainly.com/question/12785175

#SPJ11

Terrence goes for a walk. He walks 2.0 km north, then turns and walks 4.0 km south of east. What is his displacement vector?

Answers

Terrence's displacement vector is 4.0 km east and 2.0 km north.

How can we arrive at this result?

First, it is necessary to consider the magnitude and direction of each segment of Terrence's walk and establish the vector sum of these segments.

Terrence walked 2.0 km north and then 4.0 km east. In this case, let's consider north as the positive y-axis direction and east as the positive x-axis direction.

Therefore, we can conclude that:

We have a component of displacement of 2.0 km in the y direction.We have a component of displacement of 4.0 km in the x direction.

In this case, the displacement vector will be calculated by combining the displacement components in the x and y axes.

Therefore, Terrence's displacement vector is 4.0 km east and 2.0 km north.

Learn more about vectors:

https://brainly.com/question/29740341

#SPJ4

Create your own kinematics word problem involving uniform
acceleration. Solve your word problem.

Answers

A car accelerates uniformly from rest at a rate of 2 m/s² for a distance of 100 meters. How long does it take for the car to reach this distance?

Using the kinematic equation s = ut + (1/2)at², where s is the distance, u is the initial velocity (0 m/s since the car starts from rest), a is the acceleration (2 m/s²), and t is the time, we can solve for t.

Given that the car starts from rest (u = 0 m/s) and accelerates uniformly at a rate of 2 m/s², we can use the kinematic equation s = ut + (1/2)at² to solve for the time taken (t) to cover a distance of 100 meters (s = 100 m).

Substituting the given values into the equation, we have 100 = 0 + (1/2)(2)t². Simplifying the equation, we get 100 = t². Taking the square root of both sides, we find t = ±10.

Since time cannot be negative in this context, the car takes 10 seconds to reach a distance of 100 meters when accelerating uniformly at a rate of 2 m/s².

To learn more about uniform acceleration

brainly.com/question/28641931

#SPJ11

:: Free-fall The path of an object in the (x,y) plane Projectile 2 An object moving under the influence of gravity * Range 3 Trajectory Motion of an object with no horizontal velocity or acceleration, moving only in the vertical direction under the influence of the acceleration due to gravity :: Velocity The horizontal distance traveled by a projectile 5 The slope of the position versus time graph H

Answers

The slope of the position versus time graph H is velocity. A position-time graph is a graph that shows an object's position as a function of time. Velocity is the slope of the position versus time graph. The slope of a position-time graph at a particular moment is the instantaneous velocity of the object at that moment.

Free-fall refers to the path of an object in the (x,y) plane, whereas a projectile is an object moving under the influence of gravity. The trajectory is the path of an object with no horizontal velocity or acceleration, moving only in the vertical direction under the influence of acceleration due to gravity. Range refers to the horizontal distance traveled by a projectile, and the slope of the position versus time graph H is velocity.

Motion of an object with no horizontal velocity or acceleration, moving only in the vertical direction under the influence of the acceleration due to gravity is trajectory. When an object is thrown or launched, it follows a path through the air that is called its trajectory. In the absence of air resistance, this path is a parabola.

Range is the horizontal distance traveled by a projectile. The greater the initial velocity of a projectile and the higher its angle, the greater its range. When an object is launched from a height above the ground, the range is the horizontal distance traveled by the object until it hits the ground.

To know more about Velocity visit:

https://brainly.com/question/30559316

#SPJ11

In roughly 30-50 words, including an equation if needed,
explain what a "derivative" is in calculus, and explain what
physical quantity is the derivative of displacement if an object
moves

Answers

In calculus, the derivative represents the instantaneous rate of change. In this case, if an object moves 1449 meters downward in 18 seconds, its velocity is approximately 80.5 meters per second downward.

In calculus, a derivative represents the instantaneous rate of change of a quantity with respect to another. In the context of motion, the derivative of displacement is velocity.

To calculate the velocity, we can use the equation:

velocity (v) = change in displacement (Δx) / change in time (Δt)

Given that the object moves 1449 meters downward in 18 seconds, we can substitute these values into the equation:

v = 1449 meters / 18 seconds

Simplifying the equation, we find that the object has an average velocity of approximately 80.5 meters per second in the downward direction.

The complete question should be:

In roughly 30-50 words, including an equation, if needed, explain what a “derivative” is in calculus, and explain what physical quantity is the derivative of displacement if an object moves 1449 meters downward in 18 seconds.

To learn more about  instantaneous rate of change, Visit:

https://brainly.com/question/28684440

#SPJ11

Questions 1. If a small resistance is introduced in the circuit due to a poor contact between the bridge wire and the binding post d, how would this effect the calculated value of the unknown resistance? Explain 2. a. What values of L1 and L2 would you get for Rk=1kΩ and Rx=220kΩ ? (Recall that L1+L2=100 cm.) b. Would the Wheatstone bridge give you a good measurement of R x​ in this case? Why or why not? 3. What does resistivity of a material mean? Is it a constant?

Answers

1. Introducing a small resistance due to poor contact affects the calculated value of the unknown resistance in a Wheatstone bridge.

2. For Rₖ = 1 kΩ and Rₓ = 220 kΩ, L₁ ≈ 0.45 cm and L₂ ≈ 99.55 cm.

3. The Wheatstone bridge may not provide an accurate measurement of Rₓ in this case due to the introduced resistance.

4. Resistivity is the material's property determining its resistance to electric current, not a constant.

If a small resistance is introduced in the circuit due to a poor contact between the bridge wire and the binding post d, it would affect the calculated value of the unknown resistance.

This is because the additional resistance changes the balance in the Wheatstone bridge circuit, leading to errors in the measurement of the unknown resistance.

The introduced resistance causes an imbalance in the bridge, resulting in an inaccurate determination of the unknown resistance.

For the values Rₖ = 1 kΩ and Rₓ = 220 kΩ, we can determine the values of L₁ and L₂ using the equation L₁/L₂ = Rₖ/Rₓ. Since L₁ + L₂ = 100 cm, we can substitute the given values into the equation and solve for L₁ and L₂.

(a) Substituting Rₖ = 1 kΩ and Rₓ = 220 kΩ into L₁/L₂ = Rₖ/Rₓ:

L₁/L₂ = (1 kΩ)/(220 kΩ) = 1/220

We know that L₁ + L₂ = 100 cm, so we can solve for L₁ and L₂:

L₁ = (1/220) * 100 cm ≈ 0.45 cm

L₂ = 100 cm - L₁ ≈ 99.55 cm

(b) The Wheatstone bridge may not provide an accurate measurement of Rₓ in this case. The poor contact introduces additional resistance, disrupting the balance in the bridge.

This imbalance leads to errors in the measurement, making it unreliable for determining the true value of Rₓ.

The resistivity of a material refers to its inherent property that determines its resistance to the flow of electric current. It represents the resistance per unit length and cross-sectional area of a material.

Resistivity is not a constant and can vary with factors such as temperature and material composition. It is denoted by the symbol ρ and is measured in ohm-meter (Ω·m).

Different materials have different resistivities, which impact their conductivity and resistance to the flow of electric current.

To know more about Wheatstone, refer here:

https://brainly.com/question/31777355#

#SPJ11

Why is the following situation impossible? A technician is testing a circuit that contains a resistance R. He realizes that a better design for the circuit would include a resistance 7/3 R rather than R. He has three additional resistors, each with resistance R. By combining these additional resistors in a certain combination that is then placed in series with the original resistor, he achieves the desired resistance.

Answers

The situation described is impossible because the resistance values in a circuit cannot be changed by combining resistors in series. When resistors are connected in series, their resistances add up.

In this case, if the technician wants to achieve a resistance of 7/3 R by combining three additional resistors with resistance R, the total resistance would be 4R (R + R + R + R). It is not possible to obtain a resistance of 7/3 R by combining resistors in series, as the sum of the resistance values will always be a multiple of R. Therefore, the technician cannot achieve the desired resistance by combining the resistors in series.

The situation described is impossible because the resistance values in a circuit cannot be changed by simply combining resistors in series. When resistors are connected in series, their resistances add up. In this case, the technician realizes that a better design for the circuit would include a resistance of 7/3 R instead of R. To achieve this, the technician has three additional resistors, each with resistance R.

To know more about values visit :

https://brainly.com/question/30145972

#SPJ11

A
body whose density is 2500 kg/m' weighs 98 N in air and 66.64 N
submerged in a liquid. N. Find the density of the liquid

Answers

Answer:  the density of the liquid is approximately 2499.2 kg/m³

Explanation:

To find the density of the liquid, we can use Archimedes' principle, which states that the buoyant force experienced by an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

The weight of the body in air is given as 98 N, and the weight of the body submerged in the liquid is given as 66.64 N. The difference in weight between the two states represents the weight of the liquid displaced by the body.

Weight of the liquid displaced = Weight in air - Weight submerged = 98 N - 66.64 N = 31.36 N

Now, we can use the formula for density:

Density = (Weight of the liquid displaced) / (Volume of the liquid displaced)

Since the weight of the liquid displaced is 31.36 N and the density of the body is given as 2500 kg/m³, we can rearrange the formula to solve for the volume of the liquid displaced:

Volume of the liquid displaced = (Weight of the liquid displaced) / (Density of the body)

Volume of the liquid displaced = 31.36 N / 2500 kg/m³ = 0.012544 m³

Now, we can find the density of the liquid:

Density of the liquid = (Weight of the liquid displaced) / (Volume of the liquid displaced)

Density of the liquid = 31.36 N / 0.012544 m³ ≈ 2499.2 kg/m³

If you draw a few electric field lines and equipotential surfaces outside a negatively charged hollow conducting sphere, what will be the shape of the equipotential surfaces? ! circle
semicircle Sphere hemisphere

Answers

The shape of the equipotential surfaces outside a negatively charged hollow conducting sphere will be spherical.

When considering a negatively charged hollow conducting sphere, the excess negative charge will distribute itself uniformly on the outer surface of the sphere. Due to this uniform charge distribution, the electric field inside the hollow region of the sphere is zero.

For points outside the sphere, the electric field lines will originate from the negative charge on the surface of the sphere and will extend radially outward. Since the electric field lines are perpendicular to the equipotential surfaces, the equipotential surfaces will be perpendicular to the electric field lines.

In a spherically symmetric system, the equipotential surfaces are concentric spheres centered at the origin. Therefore, the equipotential surfaces outside the negatively charged hollow conducting sphere will be spherical in shape.

Read more about equipotential surfaces here: https://brainly.com/question/28444466

#SPJ11

The wavelength of a particular source of light is approximately 399.44 nm. Express this wavelength in centimeters. O A. 3.99e-9 B. 3.99e9 C. 3.99e-5 D. 0.0399 E. 3.99e13

Answers

The wavelength of the light source is approximately 3.99e-5 cm.

To convert the wavelength of 399.44 nm to centimeters, we need to divide the value by 10,000 since there are 10,000 nanometers in one centimeter.

399.44 nm / 10,000 = 0.039944 cm

Rounded to four decimal places, the wavelength is approximately 0.0399 cm.

Therefore, the correct answer is option D: 0.0399.

Wavelength is a measure of the distance between two consecutive points on a wave. It represents the spatial extent of one complete cycle of the wave. In the case of light, it is often measured in nanometers (nm) or picometers (pm), but it can be converted to other units for convenience.

Since there are 10,000 nanometers in one centimeter, dividing the wavelength in nanometers by 10,000 gives the equivalent value in centimeters. In this case, the original wavelength of 399.44 nm is divided by 10,000 to obtain 0.039944 cm. Rounding it to four decimal places, we get 0.0399 cm.

This conversion is important in various scientific and engineering applications. It allows for easier comparison and understanding of wavelength values, especially when working with different unit systems. In this case, expressing the wavelength in centimeters provides a more relatable and comprehensible scale for measurement.

Therefore, the correct answer is option D: 0.0399, which represents the wavelength of the particular light source in centimeters.

To learn more about wavelength, click here: https://brainly.com/question/32900586

#SPJ11

The limit to the eye's acuity is actually related to diffraction by the pupil. Hint a. What is the angle between two just-resolvable points of light for a 2-mm-diameter pupil, assuming an average wavelength of 580 nm? The angle between two just-resolvable points is mrad. b. Take your result to be the practical limit for the eye. What is the greatest possible distance a car can be from you if you can resolve its two headlights, given they are 1 m apart? The greatest possible distance of a car with resolvable headlights is m. c. What is the distance between two just-resolvable points held at an arm's length (0.95 m) from your eye? The distance between two just-resolvable points is mm. Consider how your answers to (b) and (c) compare to your everyday experience. How does the diffraction-limited resolution limit compare to the details you normally observe in everyday circumstances?

Answers

a. The angle between two just-resolvable points of light for a 2-mm-diameter pupil, assuming an average wavelength of 580 nm, is approximately 1.43 milliradians (mrad).

b. Taking the result from part (a) as the practical limit for the eye, the greatest possible distance a car can be from you for you to resolve its two headlights, given they are 1 m apart, is approximately 697.2 meters (m).

c. The distance between two just-resolvable points held at an arm's length (0.95 m) from your eye is approximately 1.36 millimetres (mm).

In everyday circumstances, the diffraction-limited resolution limit is much finer than the details we typically observe. Our eyes are capable of perceiving much smaller angles and distances than the diffraction limit allows. This is why we can easily discern fine details in objects and perceive much greater distances between objects, such as cars with headlights 1 m apart, compared to the resolution imposed by diffraction. Our visual system integrates various factors, including the optics of the eye, neural processing, and cognitive factors, to provide us with a rich and detailed perception of the world around us.

To learn more about wavelength, click here:

brainly.com/question/7143261

#SPJ11

Diamagnets have the property that they "dampen" the effects of an external magnetic field by creating an opposing magnetic field. The diamagnet thus has an induced dipole moment that is anti-aligned, such that the induced north pole is closer to the north pole creating the external field. An application of this is that diamagnets can be levitated (Links to an external site.).
Now, the mathematics of generally describing a force by a non-uniform field on a dipole is a little beyond the scope of this course, but we can still work through an approximation based on energy. Essentially, whenever the theoretical loss of gravitational potential energy from "falling" no longer can "pay the cost" of increasing the magnetic potential energy, the object no longer wants to fall.
Suppose a diamagnetic object floats above the levitator where the magnitude of the magnetic field is 18 T, which is inducing* a magnetic dipole moment of 3.2 μA⋅m2 in the object. The magnetic field 2.0 mm below the object is stronger with a magnitude of 33 T. What is the approximate mass of the floating object?
Give your answer in units of g (i.e., x10-3 kg), and use g = 9.81 m/s2. You may assume the object's size is negligible.

Answers

The approximate mass of the floating object is approximately 37.99 grams.

To solve this problem, we can use the concept of potential energy. When the diamagnetic object floats above the levitator, the gravitational potential energy is balanced by the increase in magnetic potential energy.

The gravitational potential energy is by the formula:

[tex]PE_gravity = m * g * h[/tex]

where m is the mass of the object, g is the acceleration due to gravity, and h is the height from the reference point (levitator) to the object.

The magnetic potential energy is by the formula:

[tex]PE_magnetic = -μ • B[/tex]

where μ is the magnetic dipole moment and B is the magnetic field.

In equilibrium, the gravitational potential energy is equal to the magnetic potential energy:

[tex]m * g * h = -μ • B[/tex]

We can rearrange the equation to solve for the mass of the object:

[tex]m = (-μ • B) / (g • h)[/tex]

Magnetic dipole moment [tex](μ) = 3.2 μA⋅m² = 3.2 x 10^(-6) A⋅m²[/tex]

Magnetic field above the object (B1) = 18 T

Magnetic field below the object (B2) = 33 T

Height (h) =[tex]2.0 mm = 2.0 x 10^(-3) m[/tex]

Acceleration due to gravity (g) = 9.81 m/s²

Using the values provided, we can calculate the mass of the floating object:

[tex]m = [(-3.2 x 10^(-6) A⋅m²) • (18 T)] / [(9.81 m/s²) • (2.0 x 10^(-3) m)][/tex]

m = -0.03799 kg

To convert the mass to grams, we multiply by 1000:

[tex]m = -0.03799 kg * 1000 = -37.99 g[/tex]

Since mass cannot be negative, we take the absolute value:

m ≈ 37.99 g

Therefore, the approximate mass of the floating object is approximately 37.99 grams.

Learn more about gravitational potential energy from the given link

https://brainly.com/question/15896499

#SPJ11

A assumptive radioactive sample's half-life is unknown. In an initial sample of 6.6×10 10 radioactive nuclei, the initial activity is 4.0130×10 7 Bq(1 Bq=1 decay/s). Part A - What is the decay constant in s −1 ? Part B - What is the half-life in Minutes? 1 min=60 s Part C - What is the decay constant in min −1 ? Part D - After 10.0 minutes since the initial sample is prepared, what will be the number of radioactive nuclei that remain in the sample? - Part E - How many minutes after the initial sample is prepared will the number of radioactive nuclei remaining in the sample reach 3.682×10 10 ?

Answers

The given information is as follows:Initial sample (N0) = 6.6 × 10¹⁰ radioactive nucleiInitial activity (A₀) = 4.0130 × 10⁷ Bq.

Part A:The decay constant (λ) is given by the formula, λ = A₀/N₀λ = 4.0130 × 10⁷ Bq / 6.6 × 10¹⁰ nuclei = 6.079 × 10⁻⁴ s⁻¹Therefore, the decay constant is 6.079 × 10⁻⁴ s⁻¹.

Part B:The half-life (t₁/₂) can be calculated as follows: t₁/₂ = (0.693/λ) t₁/₂ = (0.693/6.079 × 10⁻⁴) = 1137.5 sNow, converting the seconds to minutes:t₁/₂ = 1137.5 s / 60 = 18.958 minTherefore, the half-life is 18.958 min.

Part C:The decay constant in minutes (λ(min⁻¹)) can be calculated as follows: λ(min⁻¹) = λ/60λ(min⁻¹) = (6.079 × 10⁻⁴)/60λ(min⁻¹) = 1.013 × 10⁻⁵ min⁻¹Therefore, the decay constant in minutes is 1.013 × 10⁻⁵ min⁻¹.

Part D:The formula to calculate the remaining number of radioactive nuclei (N) after a certain time (t) can be given as:N = N₀e^(−λt)Given: t = 10.0 minN₀ = 6.6 × 10¹⁰ radioactive nucleiλ = 1.013 × 10⁻⁵ min⁻¹N = N₀e^(−λt)N = (6.6 × 10¹⁰)e^(−1.013 × 10⁻⁵ × 10.0)N = 6.21 × 10¹⁰Therefore, the number of radioactive nuclei remaining in the sample after 10.0 minutes since the initial sample is prepared will be 6.21 × 10¹⁰.

Part E:The formula to calculate the time required to reach a certain number of radioactive nuclei (N) can be given as:t = (1/λ)ln(N₀/N)Given:N₀ = 6.6 × 10¹⁰ radioactive nucleiλ = 1.013 × 10⁻⁵ min⁻¹N = 3.682 × 10¹⁰t = (1/λ)ln(N₀/N)t = (1/1.013 × 10⁻⁵)ln(6.6 × 10¹⁰/3.682 × 10¹⁰)t = 1182.7 sNow, converting the seconds to minutes:t = 1182.7 s / 60 = 19.712 minTherefore, the number of minutes after the initial sample is prepared will the number of radioactive nuclei remaining in the sample reach 3.682 × 10¹⁰ is 19.712 min.

Learn more about radioactive here,

https://brainly.com/question/9932896

#SPJ11

A person with normal vision has a near point at 25 cm. Suppose a normal person uses special glasses to examine the details of a jewel. The glasses have a power of 4.25 diopters. Where is the corrected near point? You may neglect the space between the person's eyes and the lenses of hisher glasses

Answers

The corrected near point for the person wearing the glasses is approximately 12.12 cm.

To determine the corrected near point, we can use the lens formula:

1/f = 1/v - 1/u

Where f is the focal length of the lens, v is the image distance, and u is the object distance.

In this case, the glasses have a power of 4.25 diopters, which is equivalent to a focal length of f = 1/4.25 meters.

Since the person's near point without glasses is at 25 cm, which is the object distance (u), we can substitute these values into the lens formula to find the corrected near point.

1/(1/4.25) = 1/v - 1/(0.25)

Simplifying the equation:

4.25 = 1/v - 4

Rearranging the equation to solve for v:

1/v = 4.25 + 4

1/v = 8.25

v = 1/8.25

v ≈ 0.1212 meters or 12.12 cm

Therefore, the corrected near point for the person wearing the glasses is approximately 12.12 cm.

learn more about "focal length ":- https://brainly.com/question/28039799

#SPJ11

Q4. Light from the sky reflects off the surface of a pond. Use a refractive index of 1.33 for the water. (a) What should be the orientation of a polariser in order to attenuate reflections from the pond surface? (b) For what incident angle on the pond surface will the reflected light be observed to vanish?

Answers

a) To attenuate reflection from the pond surface, the polarizer should be oriented perpendicular to the surface of the pond.

b) The incident angle on the pond surface at which the reflected light vanishes is the Brewster's angle, which can be calculated using the formula θ_B = arctan(n), where n is the refractive index of water (1.33).

To attenuate reflections from the pond surface, the polarizer should be oriented perpendicular to the surface of the pond. This is because the polarizer filters out light waves that are oscillating in a specific direction, and when the polarizer is perpendicular to the surface, it effectively blocks the horizontally polarized light waves that are responsible for the strong reflections.

The angle at which the reflected light vanishes is known as the Brewster's angle. It can be calculated using the formula: θ_B = arctan(n), where n is the refractive index of water (1.33).

The Brewster's angle is the incident angle at which the reflected light is polarized in a direction parallel to the surface, resulting in minimal reflection. At this angle, the reflected light appears greatly attenuated or even vanishes.

To learn more about reflection click here:

brainly.com/question/29788343

#SPJ11

The only force acting on an object moving along x-axis is given by Fx= 8.57x Nm, where x is in meters. If the velocity of the object at x=0 is 4ms, and at x= 7.4 m the velocity is equal to 19ms, find the mass in units of kg of the object. Please round your answer to 1 decimal place.

Answers

The mass of the object is indeterminate or infinite.

To find the mass of the object, we can use the relationship between force, mass, and acceleration.

Since the only force acting on the object is given by Fx = 8.57x Nm, we can equate this force to the mass multiplied by the acceleration.

Fx = m * ax

Taking the derivative of the given force equation with respect to x, we can find the acceleration:

ax = d²x/dt²

Since we're given the velocity of the object at two different positions, we can find the acceleration by taking the derivative of the velocity equation with respect to time:

v = dx/dt

Taking the derivative of this equation with respect to time, we get:

a = dv/dt

Now, let's find the acceleration at x = 0 and x = 7.4 m:

At x = 0:

v = 4 m/s

a = dv/dt = 0 (since the velocity is constant)

At x = 7.4 m:

v = 19 m/s

a = dv/dt = 0 (since the velocity is constant)

Since the acceleration is zero at both positions, we can conclude that the force acting on the object is balanced by other forces (e.g., friction) and there is no net acceleration.

Therefore, the mass of the object is indeterminate or infinite.

Learn more about acceleration form this link:

https://brainly.com/question/25876659

#SPJ11

The circuit shown has been connected for a long time. If C= 3
mF and E= 22 V, then calculate the charge Q (in uC) in the
capacitor.
Question Completion Status: Question 1 0.5 points Save Answ The circuit shown has been connected for a long time. If C-3 uF and e-22 V, then calculate the charge Q (in uC) in the capacitor. www ww 10

Answers

The charge (Q) in the capacitor can be calculated using the formula Q = C * E, where Q represents the charge, C is the capacitance, and E is the voltage across the capacitor. We get 66 uC as the charge in the capacitor by substituting the values in the given formula.

In this case, the capacitance is given as 3 mF (equivalent to 3 * 10^(-3) F), and the voltage across the capacitor is 22 V. By substituting these values into the formula, we find that the charge in the capacitor is 66 uC.

In an electrical circuit with a capacitor, the charge stored in the capacitor can be determined by multiplying the capacitance (C) by the voltage across the capacitor (E). In this scenario, the given capacitance is 3 mF, which is equivalent to 3 * 10^(-3) F. The voltage across the capacitor is stated as 22 V.

By substituting these values into the formula Q = C * E, we can calculate the charge as Q = (3 * 10^(-3) F) * 22 V, resulting in 0.066 C * V. To express the charge in micro coulombs (uC), we convert the value, resulting in 66 uC as the charge in the capacitor.

Learn more about capacitors:

brainly.com/question/31627158

#SPJ11

What is the effect of increasing the tension in the vibrating string to the frequency if
linear mass density & vibrating length are held constant?

Answers

Increasing the tension in a vibrating string while keeping the linear mass density and vibrating length constant will result in an increase in the frequency of vibration.

This is because the frequency of vibration in a string is directly proportional to the square root of the tension in the string. By increasing the tension, the restoring force in the string increases, leading to faster vibrations and a higher frequency.

Therefore, increasing the tension in the vibrating string will result in a higher frequency of vibration.

The frequency of vibration in a string is determined by various factors, including tension, linear mass density, and vibrating length. When the linear mass density and vibrating length are held constant, changing the tension has a direct impact on the frequency.

Increasing the tension increases the restoring force in the string, causing the string to vibrate more rapidly and resulting in a higher frequency of vibration.

To know more about frequency of vibration refer here:

https://brainly.com/question/32093564#

#SPJ11

You are 10 km away from the town of Chernobyl having a picnic with your friends. You check your radiation detector and it says 900 counts. But, you’ve been told that 100 counts is the safe level (oh dear)!! How far away do you tell your friends you need to be to be safe?

Answers

You would need to be approximately 3.33 km away from Chernobyl to reach a safe radiation level. We can use the concept of inverse square law for radiation.

To determine the distance you need to be from Chernobyl to reach a safe radiation level, we can use the concept of inverse square law for radiation.

The inverse square law states that the intensity of radiation decreases with the square of the distance from the source. Mathematically, it can be expressed as:

I₁/I₂ = (d₂/d₁)²

where I₁ and I₂ are the radiation intensities at distances d₁ and d₂ from the source, respectively.

In this case, we can set up the following equation:

900/100 = (10/d)²

Simplifying the equation, we have:

9 = (10/d)²

Taking the square root of both sides, we get:

3 = 10/d

Cross-multiplying, we find:

3d = 10

Solving for d, we get:

d = 10/3

Therefore, you would need to be approximately 3.33 km away from Chernobyl to reach a safe radiation level.

To learn more about inverse square law click here

https://brainly.com/question/33029981

#SPJ11

If the amplitude of a sound wave is increased, there is an increase in the:
1: loudness of the sound
2: pitch of the sound
3: velocity of the wave
4: energy of the wave
5: wavelength of the wave
The phrase(s) that make the statement true are _____ and _____. Put the numbers of the phrases in any order.
5. The third harmonic in an open tube is a wave that is 1.5 wavelengths long.
True or False

Answers

The correct options are 1 and 4. If the amplitude of a sound wave is increased, there is an increase in the loudness of the sound, the energy of the wave.

The loudness of sound is the degree of sound volume.

Amplitude determines the amount of energy produced by sound. Hence, increasing the amplitude of a sound wave increases the loudness of the sound.

The energy of a wave is determined by the amplitude of the wave.

Therefore, when the amplitude of a wave is increased, the energy of the wave is also increased.

Hence, increasing the amplitude of a sound wave increases the energy of the wave.

The third harmonic in an open tube is a wave that is 3/2 or 1.5 wavelengths long.

Hence, the given statement is True.

To know more about amplitude visit:

https://brainly.com/question/9525052

#SPJ11

when an apple of 0.2kg is placed on a scale in a store, the scale
starts to oscillate at 4.8Hz. what is the force constant of the
scale

Answers

To determine the force constant, we need additional information such as the displacement or the restoring force exerted by the scale. The force constant of the scale is approximately 9.56 N/m.

The force constant of the scale can be determined using Hooke's law, which states that the force exerted by a spring is proportional to the displacement from its equilibrium position. The equation for Hooke's law is: F = -k * x

Where F is the force applied, k is the force constant (also known as the spring constant), and x is the displacement from the equilibrium position.

In this case, when the apple is placed on the scale, it causes the scale to oscillate. The oscillation frequency (f) is given as 4.8 Hz.

The relationship between the force constant (k) and the oscillation frequency (f) of a simple harmonic oscillator is:

k = (2 * pi * f)^2 * m

Where m is the mass attached to the spring (in this case, the mass of the apple, which is 0.2 kg).

Substituting the values, we have:

k = (2 * pi * 4.8 Hz)^2 * 0.2 kg

k ≈ 9.56 N/m

Therefore, the force constant of the scale is approximately 9.56 N/m.

To learn more about, force constant, , click here, https://brainly.com/question/29597873

#SPJ11

Question 48 1 pts The mass of Neptune can be calculated from measurements of the gravitational influence of Jupiter and Saturn on Neptune's orbit around the Sun. Neptune's orbital period and its distance from the Sun. the orbital period and distance of the moon Triton from Neptune. the masses of Neptune's moons, Triton and Nereid. the Sun's mass and how Neptune's speed changes during its elliptical orbit around the Sun.

Answers

The mass of Neptune cannot be directly calculated from measurements of the gravitational influence of Jupiter and Saturn on Neptune's orbit around the Sun. This method, known as gravitational perturbation, is used to determine the mass of celestial objects when their gravitational effects on other objects can be measured accurately.

To calculate the mass of Neptune, astronomers primarily rely on measurements of Neptune's orbital period and its distance from the Sun. These parameters, along with Newton's laws of gravitation and motion, allow for the determination of the mass of Neptune based on its gravitational interaction with the Sun.

Other factors such as the orbital period and distance of Neptune's moon Triton from Neptune, or the masses of Neptune's moons, Triton and Nereid, are not directly used to calculate Neptune's mass.

Understanding Neptune's speed changes during its elliptical orbit around the Sun can provide valuable information about its dynamics, but it does not directly determine its mass.

Therefore, the most accurate method for calculating the mass of Neptune involves analyzing its orbital parameters in relation to the Sun and applying the laws of celestial mechanics.

To know more about gravitational perturbation, please visit

https://brainly.com/question/32925849

#SPJ11

Given two vectors a = 3.6i
-3.2j and b
=6.8i+8.8j
Find the direction (in ° = deg) of the vector
a.
Find the direction of the vector a-b

Answers

a) The direction of vector a is 41.186° in the clockwise direction.

b) The direction of vector a-b is 73.742° in the counterclockwise direction.

The solution to the given problem is as follows:

The given vectors are: a = 3.6i - 3.2j and b = 6.8i + 8.8j

We can write both vectors as:

|a| = sqrt((3.6)^2 + (-3.2)^2) = 4.687

|b| = sqrt((6.8)^2 + (8.8)^2) = 11.294

Part 1: Find the direction (in ° = deg) of the vector

a. We can calculate the direction of a using the following formula:

θ = tan^(-1)(y/x)

where, x is the x-component of vector a = 3.6 and

            y is the y-component of vector a = -3.2

Therefore, θ = tan^(-1) (-3.2 / 3.6)θ = -41.186°

So, the direction of vector a is 41.186° in the clockwise direction.

Part 2: Find the direction of the vector a-bThe direction of the vector a-b can be found using the following formula:

θ = tan^(-1)(y/x)

where, x is the x-component of vector a-b = (3.6 - 6.8)i + (-3.2 - 8.8)j = -3.2i - 12j and

           y is the y-component of vector a-b = -12

Therefore, θ = tan^(-1) (-12 / -3.2)θ = 73.742°

So, the direction of vector a-b is 73.742° in the counterclockwise direction.

Learn more about direction of vector at https://brainly.com/question/27854247

#SPJ11

10/1 Points DETAILS PREVIOUS ANSWERS SERCP11 22.4.P.028 MY NOTES PRACTICE ANOTHER A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 m and an index of 1.6.0 for red light of wavelength 60 am. Item contaring the too incident at an angle of 30.0" piece of this gass, what is the angle between the two beams inside the 2 048 X Yoir response differs from the correct answer by more than 10%

Answers

The angle between the two beams inside the glass for blue light is approximately 17.65°, and for red light is approximately 19.10°.

To determine the angle between the two beams inside the glass, we can use Snell's Law, which relates the angles of incidence and refraction to the indices of refraction of the two media:

n₁sinθ₁ = n₂sinθ₂

Where:

n₁ = index of refraction of the initial medium (air)

θ₁ = angle of incidence in the initial medium

n₂ = index of refraction of the final medium (glass)

θ₂ = angle of refraction in the final medium

n₁ = 1 (index of refraction of air)

n₂ (for blue light) = 1.660

n₂ (for red light) = 1.600

θ₁ = 30.0° (angle of incidence)

For blue light (wavelength = 420 nm):

n₁sinθ₁ = n₂sinθ₂

(1)(sin 30.0°) = (1.660)(sin θ₂)

Solving for θ₂, we find:

sin θ₂ = (sin 30.0°) / 1.660

θ₂ = arcsin[(sin 30.0°) / 1.660]

Using a calculator, we find:

θ₂ ≈ 17.65°

For red light (wavelength = 600 nm):

n₁sinθ₁ = n₂sinθ₂

(1)(sin 30.0°) = (1.600)(sin θ₂)

Solving for θ₂, we find:

sin θ₂ = (sin 30.0°) / 1.600

θ₂ = arcsin[(sin 30.0°) / 1.600]

Using a calculator, we find:

θ₂ ≈ 19.10°

Therefore, the angle between the two beams inside the glass for blue light is approximately 17.65°, and for red light is approximately 19.10°.

Read more about angle

brainly.com/question/13954458

#SPJ11

A loop of area 200cm2 is positioned perpendicular to a uniform magnetic field. The magnetic field magnitude is reduced from 10T to 9T in the time interval 0.02 s. Find the average induced voltage in the loop?

Answers

The average induced voltage in the loop with an area of 200 cm², positioned perpendicular to a uniform magnetic field when the field is reduced from 10T to 9T in the time interval of 0.02 s is 1 volt.

To calculate the average induced voltage (emf) in a loop is:

     e = -A * (∆B/∆t)

Where:

e is the average induced voltage (emf) in volts (V)

A is the area of the loop in square meters (m²)

∆B is the change in magnetic field strength in teslas (T)

∆t is the change in time in seconds (s)

Let's calculate the average induced voltage using the given values:

A = 200 cm²

  = 0.02 m²

∆B = 9 T - 10 T

     = -1 T

∆t = 0.02 s

e = -0.02 m² * (-1 T / 0.02 s)

  = 1 V

Therefore, the average induced voltage in the loop is 1 volt (V).

Learn more about magnetic fields here:

https://brainly.com/question/7645789

#SPJ11

Other Questions
What features should you look for in code review? Please list at least six items: The following statements are true about the vitamins, except:A Vitamin C is also known as Ascorbic acidB Vitamin B1 is also known as ThiaminC vitamin B2 is also known as RiboflavinD Vitamin B6 is also known as pyridoxin Why is it essential to first be truthful (impeccable) with yourself prior to being truthful with others? Research the terms "narcissism" and "egocentrism." Using those terms, explain why people are inclined to take things personally. Question 2 Not yet answered Marked out of 1.00 P Flag question Input is received from an organization's management to create a project budget in: Select one: a. Zero-based budgeting. b. Bottom-up budgeting. c. Top-down budgeting. d. Activity-based budgeting youre working on an improvement project at a community mental health center. your project aim: "within two months, 100 percent of our patients will wait less than 30 minutes to be seen by a physician." you decide to gather data on patient wait times over a week-long period in order to establish a baseline. what might be an important consideration as you plan your data collection strategy? 2.1. Explain the five (5) main techniques used to select a probability sample. 2.2. List and explain any four (4) qualitative research designs. 2.3. Mention five (5) advantages of using interview as a data collection Find the length of KL. Assume a par value of $1,000. Caspian Sea plans to issue a 17.00 year, semi-annual pay bond that has a coupon rate of 7.83%. If the yield to maturity for the bond is 8.10% what will the price of the bond be? a. $957.22 b. $975.31 c. $1,000.00 d. $1,016.86 . The indicated function y(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2, e-/P(x) dx V = V(x) [ Y = y} (x) dx (5) as instructed, to find a second solution y(x). (1 - 2x - x)y" + 2(1+x)y' - 2y = 0; y = x + 1 a. If you had hedged your position with a forward hedge, how many dollars would you have received for the goods as of the end of the school term? Initial spot 1.2889,Total revenue $ 777,061, Fwd points-0.0020,Unit price0.777061 which is a key belief of buddhism? the cause of all suffering is desire the cause of all suffering is desire a person can escape conflicts by becoming one with nature a person can escape conflicts by becoming one with nature, only through reincarnation can a person become a brahman only through reincarnation can a person become a brahman relationships between people must be mutual the function below allows you to convert degrees celsius to degrees fahenheit. use this function to convert 20 degrees celsius to degrees fahrenheit. f(c) NO LINKS!Find the standard deviation of the data 9, 16, 23 ,30, 37, 44, 51. HELP This item is a multi-select answer type. Credit is given only if both answer selections are correct.Two objects, P and Q, attached by a thread, are separated by some distance. Consider them to be point masses.Given:The distance between the objects is 3 m.The mass of Object P is 5 kg.The mass of Object Q is 7 kg.The mass of the thread is negligible.What is the moment of inertia of the system of objects P and Q about a point midway between them? How does this compare to the moment of inertia of the system about its center of mass?Select an answer for both questionsQuestion 2 options:The moment of inertia about the midpoint is less than the moment of inertia about the center of mass108 kg m2The moment of inertia about the midpoint is greater than the moment of inertia about the center of mass16 kg m25 kg m2The moment of inertia about the midpoint is equal to the moment of inertia about the center of mass27 kg m218 kg m254 kg m2 You invested $9,000 at the end of each half-year for 7 years in an investment fund. At the end of year 7, if the balance in the fund was $144,000, what was the nominal interest rate compounded semi-annually? 0.00 % Round to two decimal places Question 8 of 10 SUBMIT QUESTION > Decide (and justify!) whether the equilibrium (0,0) of the system (a) is an attractor, a repeller, or neither of these; (b) is stable or unstable. dx dt dy dt = 4x-2x- - xy = 3y-xy-y The strings on a violin have the same length and approximately the same tension. If the highest string has a frequency of 659 Hz, and the next highest has a frequency of 440 Hz, what is the ratio of the linear mass density of the highest string to that of the next highest string? Can you paraphrase "His integrity is questioned with that of other good people. His attempt to prove his innocence is futile when his wife testifies intentionally against him". What would be the most likely result if humans stopped burning fossil fuels?A. Greenhouse gases levels would decreaseB. The polar ice caps would melt more quicklyC. There would be less oxygen in the atmosphereD. Global warming would increase George owns two small shops in a strip shopping centre in partnership with his wife and two children. The shops are leased out to tenants and yield an annual rent of approximately $40,000. While the partnership is not registered for GST, and does not have an ABN, George runs a market garden business as a sole trader that has an ABN and is registered for GST. The partnership sell the shop for $350,000 and settlement is due to take place in early May.Discuss the ABN and GST implications.