29 dekagrams equals 2900 what

Answers

Answer 1

Answer:

It equals 2900 decigrams

Step-by-step explanation:

29 dekagrams = 290 grams

290 grams = 2900 decigrams

Therefore, 29 dekagrams = 2900 decigrams

Answer 2

The equivalent weight in grams for a given weight in dekagrams is approximately 10 times the weight in dekagrams.

To find the equivalent weight in grams for a given weight in dekagrams, you can use the conversion factor that 1 dekagram (dag) is equal to 10 grams.

Given the information that 29 dekagrams equals 290 grams, you can set up a proportion:

[tex]\(\frac{29 \text{ dag}}{290 \text{ g}} = \frac{1 \text{ dag}}{x \text{ g}}\)[/tex]

Cross-multiplying:

[tex]\(29x = 290 \times 1\)[/tex]

Solving for x:

[tex]\(x = \frac{290}{29}\)\\\\\(x \approx 10\)[/tex]

Therefore, the equivalent weight in grams for a given weight in dekagrams is approximately 10 times the given weight in dekagrams.

To know more about weight, refer here:

https://brainly.com/question/32319871

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Complete Question:

If 29 dekagrams equals 290 grams, what is the equivalent weight in grams for a given weight in dekagrams?


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Answer:

P: 4x+10

A: [tex]x^{2}[/tex]+5x+4

Step-by-step explanation:

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Step-by-step explanation:

a) given slope=m1=a/3

slope of parallel line=m2=5/6

parallel lines have equal slopes:

m1=m2

a/3=5/6

a=5/6×3

a=5/2

b) m1=a/3

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a/3=-2/9

a=-2/9×3

a=-2/3

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a×2=-1

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Use the graphical representation and algebraic reasoning to identify the key features of the graph of the function
g(x) = -f(x) + 10.
Select all the correct answers.
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range of {y 0 < y < 00}
range of {y-oo < y < 10}
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y-intercept at (0,9)
horizontal asymptote of y = 10
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Answers

Answer:

4 answers to this question

Step-by-step explanation:

4 Answers: (#s 3, 5, 6, 7)

y-intercept at (0,9)

horizontal asymptote of y=10

x-intercept at (1,0)

range of {y|-∞<y<10}

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Answers

Answer:

(7/12) + (4q/6)

Step-by-step explanation:

[tex] \frac{11}{12} - \frac{1}{6} q + \frac{5}{6} q - \frac{1}{3} \\ = \frac{11}{12} + \frac{4}{6} q - \frac{1}{3} \\ = \frac{11}{12} - \frac{1}{3} + \frac{4}{6} q \\ = \frac{11}{12} - \frac{4}{12} + \frac{4}{6} q \\ = \frac{7}{12} + \frac{4}{6} q[/tex]

Answer:

Step-by-step explanation:

Like terms have same variable with same power.

(11/12  and 1/3 are like terms)  & (-1q/6 & 5q/6 are like terms}

[tex]\dfrac{11}{12}-\dfrac{1}{6}q+\dfrac{5}{6}q-\dfrac{1}{3}=(\dfrac{11}{12}-\dfrac{1}{3})-\dfrac{1}{6}q+\dfrac{5}{6}q\\\\=(\dfrac{11}{12}-\dfrac{1*4}{3*4})+[\dfrac{-1+5}{6}]q\\\\=(\dfrac{11}{12}-\dfrac{4}{12})+\dfrac{4}{6}q\\\\=\dfrac{(11-4)}{12}q+\dfrac{4}{6}q\\\\=\dfrac{7}{12}+\dfrac{4}{6}q[/tex]

What should I do when I’m tired and I have homework assignments to do?

Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answer:

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Answers

Answer:

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Answers

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Answers

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Answers

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Multiply 3x8 to find out how many balls there are total.

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|
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Answers

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\\ thank \: you[/tex]

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Answers

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