5. Mrs. Taylor painted her bathroom.
She began painting at 10:45 a.m.
She painted for 3 hours and 45
minutes. What time did she
finish painting?
A. 1:30 p.m.
B. 1:45 a.m.
C. 2:15 a.m.
D. 2:30 p.m.

Answer:

9 is A 10 is D

not sure of the other two

Step-by-step explanation:

9 increases by 4 every time

10 increases by 7 every time

Answer:

9. A

10. D

11. D

12. A

Step-by-step explanation:

9. Look at the pattern; 6+4=10, 10+4=14, 14+4=18, 18+4=22.

10. Same thing for number nine.

11 & 12. Its just vocab

Answer:

x = 27 units

Step-by-step explanation:

39 / ( 39+ 26) = x / (x+18)

x = 27

Answer:it would be 2:22

Step-by-step explanation:

If there’s 25 minutes till 10 so therefore it would be 9:35 and since it’s 9:35 four hours and 51 minutes from then would be 2:22 because the minutes would add up to 82 minutes and four hours so your answers to 2:22

Answer:

hi, where's mt 20pts

Step-by-step explanation:

0.3

12+6+9+13=40

12/40 (or 3/10 simplified)

Thus, 0.3 as a decimal

Hope this helps!

Let's consider what the problem wants us to find:

Let's find the fractional part:

 ⇒ the fractional part is equal:

       [tex]\frac{degree-covered-by-angle}{total-angle} =\frac{280}{180} =\frac{2*2*7*10}{2*2*3*3*5} =\frac{7*10}{3*3*5} =\frac{70}{45}=\frac{14}{9}[/tex]

  Answer: The angle 280 degrees covers 14/9 of a semicircle.

Let's find the angle measure in radians:

 ⇒ we know that [tex]2\pi[/tex] radians are equal to 360 degrees

    ⇒ to convert any degree to radians, you must multiply [tex]\frac{\pi }{180}[/tex]

        so [tex]280*\frac{\pi }{180} =\frac{28}{18}*\pi =\frac{28\pi }{18}=\frac{2*14*\pi }{2*9} =\frac{14\pi }{9}[/tex]

 Answer: The angle 280 degrees in radians is [tex]\frac{14\pi} {9}[/tex] which in terms of [tex]\pi[/tex] is

14/9

Hope that helps!

Volume of rectangle is

10 times 5 times 3

150 cm

3.14 times radius times 2 times height

So, 50.24 Cm

So its 200.24 Cm

Answer:

x = ± [tex]\sqrt{3}[/tex]

Step-by-step explanation:

3x² - 9 = 0 ( add 9 to both sides )

3x² = 9 ( divide both sides by 3 )

x² = 3 ( take square root of both sides )

x = ± [tex]\sqrt{3}[/tex]

or

3x² - 9 = 0 ← factor out 3 from each term

3(x² - 3) = 0

equate x² - 3 to zero and solve for x

x² - 3 = 0 ( add 3 to both sides )

x² = 3 ( take square root of both sides )

x = ± [tex]\sqrt{3}[/tex]

The values of y when x=5.7 will be 5. In the graphs, the function is represented as y=⌊x⌋

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

In the graphs the function y=⌊x⌋

The value of the y obtaining will be the whole number of the left axis of the integers.5 is the nearest whole number to the 5.7.

The given value of the function is ;

y = [ 5.7 ] = 5

Hence the value of the y is 5.

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Answer:

Step-by-step explanation:

Distance measure how far an object have gone. The length of the line segment that has the endpoints A (-3,2) and B (1,0) is 2√5.

The formula for calculating the distance between two coordinates is expressed as:

D = √(x2-x1)²+(y2-y1)²

Given the coordinate points A (-3,2) and B (1,0), the length of the line segment that has the endpoint is given as:

D = √(0-2)²+(1+3)²
D = √(2)²+(4)²
D = √16+4
D=√20
D = 2√5

Hence the length of the line segment that has the endpoints A (-3,2) and B (1,0) is 2√5

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Step-by-step explanation:

2x + 4y = 36

2 × 4 + 4y = 36

8 + 4y = 36

4y = 36 - 8

4y = 28

y = 28 ÷ 4

y = 7

The answer will be t=-35Sin{[tex]\pi[/tex]/6m)+55 average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

For the equation: 35cos(pi/6(m+3)+55)

Simplify it by multiplying pi/6 in the bracket values:  

[tex]=35 Cos (\dfrac{\pi m}{6}+\dfrac{3\pi }{6}+55)[/tex]

[tex]=35 Cos(\dfrac{\pi m}{6}+55+\dfrac{\pi}{2})[/tex]

Now suppose x = m.pi/6+55, while pi/2 = 90⁰

As per law cos(x+90⁰)=-sin(x)

so,cos((m.pi/6)+55+90⁰=-sin((m.pi/6)+55)

Hence answer will be

[tex]=-35Sin(\dfrac{\pi m}{6}+55)[/tex]

The law cos(x+90⁰)=-sin(x) can be proved by putting y=90⁰ in the following formula,

cos(x+y)=cos(x).cos(y)-sin(x).sin(y)

Hence the answer will be t=-35Sin{[tex]\pi[/tex]/6m)+55 average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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Answer:

A

Step-by-step explanation:

t = negative 35 sine (StartFraction pi Over 6 EndFraction m) + 55

The longer side of the triangle is 17√3 yd. Therefore, option D is the correct answer.

Trigonometric angles are the angles in a right-angled triangle using which different trigonometric functions can be represented. Some standard angles used in trigonometry are 0º, 30º, 45º, 60º, 90º.

Given that, the length of the shorter leg of a 30-60-90 Special Right Triangle is 17 yd long.

Let the longer side of the triangle be x.

We know that, tanθ = Opposite/Adjacent

tan60° = x/17

√3=x/17

x=17√3 yd.

Therefore, option D is the correct answer.

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Answer:

B

Step-by-step explanation:

yes, the angles are the same.

and the scale factor is

NS / GA = 15/12 = 5/4

The Bruce must include X and Z in his report.

We have given  the data on four electric circuits listed in the table

For w :

Voltage, V=18\ V

resistance, [tex]R=38\ \Omega[/tex]

The formula of Ohm's low is V=IR

[tex]I=\dfrac{V}{R}[/tex]

[tex]I=\dfrac{18\ V}{38\ \Omega}[/tex]

I=0.47

[tex]q=0.47\times8[/tex]

So charge,q=It

q=3.76\ C

For x :

Voltage, V=24\ V

[tex]resistance, R=34\ \Omega[/tex]

so, V=IR...(Ohm's low)

[tex]I=\dfrac{V}{R}[/tex]

[tex]I=\dfrac{24\ V}{34\ \Omega}[/tex]

I=0.705

[tex]q=0.705\times8[/tex]

So charge,q=It

q=5.64\ C

For y :

Voltage, V=34\ V

resistance, [tex]R=70\ \Omega[/tex]

so, V=IR.......(Ohm's low)

[tex]I=\dfrac{V}{R}[/tex]

[tex]I=\dfrac{34\ V}{70\ \Omega}[/tex]

I=0.485

[tex]q=0.485\times8[/tex]

So charge,q=It

q=3.88\ C

For z :

Voltage, V=12\ V

resistance, [tex]R=18\ \Omega[/tex]

so, V=IR......(Ohm's low)

[tex]I=\dfrac{V}{R}[/tex]

[tex]I=\dfrac{12\ V}{18\ \Omega}[/tex]

I=0.66

[tex]q=0.66\times8[/tex]

So charge,q=It

q=5.28\ C

Therefore, the circuits X and Z deliver 5.64 C and 5.28 C of charge.

Hence, Bruce must include X and Z in his report.

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Answer: A) X and Z

Step-by-step explanation:

Got it right on edge.

The complex number z = 4(cos(5pi/6) + isin(5pi/6)) is given as z = -3.464 + 2i in standard form

Complex numbers are the numbers which is in the form of:

a + ib where, a,b are real numbers and 'i' is an imaginary number.

The complex number can also be represented in polar form as:

z = r(cosФ + isinФ)

Given the complex number:

z=4(cos(5pi/6) + isin(5pi/6)), hence converting to standard form gives:

z = -3.464 + 2i

The complex number z = 4(cos(5pi/6) + isin(5pi/6)) is given as z = -3.464 + 2i in standard form

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Answer:

-2 square root 3 + 2i

Step-by-step explanation:

Answer:

the answer 192(If Multiplied)

The sum of two polynomials is 8d^5 - 3c^3d2 +5c^2d^3 - 4cd^4 +9

2d^5 - c^3d^2 +8cd^4 +1 would be 6d^5 - 2c^3d^2+ 5c^2d^3 - 12cd^4 +8.

Polynomials are those algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.

Given that

[tex]8d^5 - 3c^3d2 +5c^2d^3 - 4cd^4 +9\\[/tex]

Now

if one is added i.e.

[tex]2d^5 - c^3d^2 +8cd^4 +1,[/tex]

Now let us assume the other polynomial be x

So,

[tex]8d^5 - 3c^3d2 +5c^2d^3 - 4cd^4 +9\\[/tex] = x + [tex]2d^5 - c^3d^2 +8cd^4 +1,[/tex]

x = [tex]8d^5 - 3c^3d2 +5c^2d^3 - 4cd^4 +9\\[/tex] - ( [tex]2d^5 - c^3d^2 +8cd^4 +1,[/tex])

x = [tex]6d^5 - 2c^3d^2+ 5c^2d^3 - 12cd^4 +8[/tex]

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Answer:

[tex] \red{ \rule{1pt}{500000pt}}[/tex] [tex] \red{ \rule{1pt}{500000pt}}[/tex]

Step-by-step explanation:

The loan option that would allow Charles to pay the LEAST in interest is option A.

Compound Interest is a process where the interest is credited to the initial amount and interest, on the whole, is charged again. and this continues for t period of time.

It is given by the formula,

[tex]A=P(1+r\%)^n[/tex]

where A is the value after t period of time, P is the principal amount, and,

r is the rate of interest.

A.) Principle amount = $10,000

Time Period of loan = 2 years

Rate of Interest = 4.75% per annum

Now, the total amount can be written as

[tex]=P(1+r\%)^n\\\\= \$10,000 \times (1+0.0475)^2\\\\= \$10,972.56[/tex]

The interest will be = $10,972.56 - $10,000 = $972.56

B.)  Principle amount = $10,000

Time Period of loan = 3 years

Rate of Interest = 4.00% per annum

Now, the total amount can be written as

[tex]=P(1+r\%)^n\\\\= \$10,000 \times (1+0.04)^2\\\\= \$11,248.64[/tex]

The interest will be = $11,248.64 - $10,000 = $1,248.64

C.) Principle amount = $10,000

Time Period of loan = 4 years

Rate of Interest = 3.75% per annum

Now, the total amount can be written as

[tex]=P(1+r\%)^n\\\\= \$10,000 \times (1+0.0375)^2\\\\= \$11,586.5[/tex]

The interest will be = $11,586.5- $10,000 = $1,586.5

D.) Principle amount = $10,000

Time Period of loan = 5 years

Rate of Interest = 3.00% per annum

Now, the total amount can be written as

[tex]=P(1+r\%)^n\\\\= \$10,000 \times (1+0.03)^5\\\\= \$11,592.74[/tex]

The interest will be = $11,592.74 - $10,000 = $1,592.74

Hence, the loan option that would allow Charles to pay the LEAST in interest is option A.

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Answer:

Step-by-step explanation:

31°

hope it helps......!!!!!

The length of arc ABC with center O and radius of 9 units is 13π.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let r represent the radius of the circle. Hence:

arc ADC = (100 / 360) * 2πr

5π = (100 / 360) * 2πr

r = 9 units

arc ABC = (260 / 360) * 2π(9) = 13π

The length of arc ABC with center O and radius of 9 units is 13π.

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Step-by-step explanation:

As it is given that, a cylinder has a height of 15 yards and the volume of the cylinder is 15,260.4 cubic yards and we are here to find the radius of the cylinder.

[tex] \: [/tex]

We know that,

[tex]{ \longrightarrow\qquad{\frak {\pmb{ \pi {r}^{2}h = Volume_{(cylinder) } }}}} \\ \\[/tex]

Where,

[tex] \: [/tex]

Now, we will substitute the given values in the formula :

[tex] \: [/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{ 3.14 \times {r}^{2} \times 15 = 15260.4 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{ {r}^{2} \times 47.1 = 15260.4 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{ {r}^{2} = \dfrac{15260.4}{47.1} }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{ {r}^{2} \ = 324 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{ r = \sqrt{324} }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{ \underline{ \boxed{\pmb {\frak{ r = 18 } }}}}} \: \: \: \bigstar\\ \\[/tex]

[tex] \: [/tex]

Therefore,

Answer:

Step-by-step explanation:

Given:

To Find:

Solution:

Here we are given height and volume of the cylinder. To find the radius of the cylinder We will substitute the value of height and volume in give formula:

Volume of cylinder = πr²h

➝ 15,260.4 = 22/7 × (r)² × 15

➝ 15,260.4 = (r)² × 330/7

➝ 15,260.4 = (r)² × 47.1

➝ 15,260.4/47.1 = (r)²

➝ 324 = (r)²

➝ √324 = r

➝ 18 = r

Hence,

The representation, in polar coordinates, of the point (1 , 5pi/6) is (-1, 11pi/6).

It should be noted that polar coordinate simply means a coordinate system where the point on the plane is determined by a distance and reference point.

In this case, the representation, in polar coordinates, of the point (1 , 5pi/6) is (-1, 11pi/6). When graphing the polar coordinate, the pole should be moved in a direction opposite the given positive angle.

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Answer:

-1

Step-by-step explanation:

trust

The pints of ice cream for the students is an illustration of metric units

Nadia needs 12 pints of ice cream for the 24 students

The given parameter is:

Students = 24

She needs one cup for each student in the class.

So, the number of cups needed is:

Cups = 24

1 cup makes 1/2 pint.

So, we have:

Pint = 1/2 * 24

Pint = 12

Hence, Nadia needs 12 pints of ice cream for the 24 students

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The algebraic expression that is a polynomial with a degree of 2 is

6x^2-6x+5.

The degree of a term of a polynomial is the total sum of the exponents of the variables in each term.

The highest degree of the polynomial is considered the degree of the polynomial.

For the first option,

[tex]4x^3-2x+10[/tex]

The highest degree is 3.

The second option is,

[tex]x^2-8x^3+3[/tex]

This polynomial also has a degree of 3.

The third option is,

[tex]6x^2-6x+5[/tex]

This last option has a degree of 2.

Therefore the correct answer is option C.

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Answer:The answer is C

Step-by-step explanation:Edge 2022 :)