A 1-kg mass at the Earth's surface weighs how much

Answers

Answer 1

Answer:

the answer is weight=10N

Answer 2

Answer:

[tex]\boxed {\boxed {\sf 9.8 \ Newtons}}[/tex]

Explanation:

Weight is also called the force of gravity. This force acts on all objects at all times, pulling them down toward the center of the Earth.

It is calculated by multiplying the mass by the acceleration due to gravity.

[tex]F_g=mg[/tex]

The mass of the object is 1 kilogram. This scenario is occurring on Earth, so the acceleration due to gravity is 9.8 meters per second squared.

m= 1 kg g= 9.8 m/s²

Substitute the values into the formula.

[tex]F_g= 1 \ kg *9.8 \ m/s^2[/tex]

Multiply.

[tex]F_g= 9.8 \ kg*m/s^2[/tex]

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton, so our answer of 9.8 kilogram meters per second squared is equal to 9.8 Newtons.

[tex]F_g= 9.8 \ N[/tex]

A 1 kilogram mass at Earth's surface weighs 9.8 Newtons.


Related Questions

True or False: The basketball should be dribbled below the waist.

Answers

True if you have proper stance and use your body the right way then the ball will be below your waist to allow for more control.

Wrte down the effect of humidity and temperature in the speed of sound....​

Answers

Explanation:

the speed of sound is affected by temperature and humidity

A cubical box with sides of length 0.368 m contains 1.980 moles of neon gas at a temperature of 298 K. What is the average rate (in atoms/s) at which neon atoms collide with one side of the container? The mass of a single neon atom is 3.35x10-26 kg.

Answers

The average rate at which the neon atoms collide with one side of the container is [tex]3.31 \times 10^{26} \ atoms/s[/tex].

The given parameters;

length of the cubical box, L = 0.368number of moles of the gas, n = 1.98temperature, T = 298 Kmass of the gas, m = 3.35 x 10⁻²⁶ kg

The average kinetic energy of the gas molecules is calculated as follows;

[tex]K = \frac{3}{2} \frac{R}{N_a} T\\\\K = \frac{3 \times 8.314\times 298}{2\times 6.022 \times 10^{23}} \\\\K = 6.17\times 10^{-21} \ J/atoms[/tex]

The average speed of the gas molecules is calculated as follows;

[tex]K = \frac{1}{2}mv_{rms}^2\\\\v_{rms} = \sqrt{\frac{2K}{m} } \\\\v_{rms} = \sqrt{\frac{2\times 6.17 \times 10^{-21}}{3.35\times 10^{-26}} } \\\\v_{rms} = 607 \ m/s[/tex]

The time of collision of the gas molecules with the walls of the container is calculated as follows;

[tex]t = \frac{2d}{v} \\\\t = \frac{2\times 0.368}{607} \\\\t = 0.0012 \ s[/tex]

The average rate at which the gases collide with a single wall out of the 3 identical walls is calculated as follows;

[tex]rate =\frac{1}{3} \times \frac{n \times N_a}{t} \\\\rate = \frac{1.98 \times 6.02 \times 10^{23} \ atoms}{3 \times 0.0012 \ s} \\\\rate = 3.31 \times 10^{26} \ atoms/s[/tex]

Thus, the average rate at which the gases collide with one side of the container is [tex]3.31 \times 10^{26} \ atoms/s[/tex].

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A spherical ball of lead (density 11.3 g/cm 3) is placed in a tub of mercury (density 13.6 g/cm 3). Which answer best describes the result

Answers

The lead ball will float with about 17% of its volume above the surface of the mercury.

We know that density is defined as mass per unit volume of a substance. The density of a substance is an intrinsic property which can be used to identify a substance.

Given that Lead is less dense that mercury, we know that lead will float on mercury. Since the density of mercury is 13.6 g/cm3 and that of lead is 11.3 g/cm3, lead ball will float with about 17% of its volume above the surface of the mercury.

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Missing parts;

A spherical ball of lead (density 11.3 g/cm3) is placed in a tub of mercury (density 13.6 g/cm3). Which answer best describes the result?

A.The lead ball will float with about 83% of its volume above the surface of the mercury.

B.The lead ball will float with about 17% of its volume above the surface of the mercury.

C.The lead ball will float with its top exactly even with the surface of the mercury.

D.The lead will sink to the bottom of the mercury.

E.none of the above

CAN SOMEONE PLEASE HELP ME

Answers

Answer:

she will eventually slow down and come to a stop

2: she will eventually slow down and come to a stop

what is the velocity of this graph between points a and b? 0.0m/s 2.5m/s 5.0m/s 6.0m/s?

Answers

Pick C. 5.0m/s it’s the right one

Answer:

Pick c is the right one

Explanation:

5.0m/s

The graph of an object's position over time is a horizontal line and y is not equal to 0. What must be true abou
motion? (1 point)
O The acceleration is constant and non-zero.
O The velocity is constant and non-zero.
0 The acceleration is negative
O The velocity is zero.

Answers

Answer:D: the velocity is zero

Explanation:

Jack sits in the chair of a Ferris wheel that is rotating at a constant 0.120 rev/s . As Jack passes through the highest point of his circular part, the upward force that the chair exerts on him is equal to one-fourth of his weight.

Answers

Answer:

Explanation:

0.120 rev/s(2π rad/rev) = 0.24π rad/s

At the highest point of the arc, gravity must supply the required centripetal acceleration. As the normal force is 1/4 of his normal weight, then 3/4 of gravity acceleration must be used as centripetal acceleration

0.75g = ω²R

R = 0.75(9.81) / (0.24π)²

R = 12.942198...

R = 12.9 m

The radius of the circle is equal to 12.95m which is rotating with an angular velocity of 0.120 rev/s.

What is vertical circular motion?

A body spins in a vertical circle so that its motion at different points is different from the motion of the body is said to be vertical circular motion.

The velocity and tension vary in maximum magnitude from the lowest to the highest position because of the effect of the gravitational force of the earth.

Given, the angular velocity of the Ferris wheel, ω = 0.120 rev/s

ω = 0.120 rev/s × 2π rad/rev

ω= 0.7536 rad/s

If r is the radius of the circle and 'm' is the mass of the jack.

From newton's second law of motion, the net force will be equal to

mg - N = mrω²

mg - (mg/4) = mrω²

r = 3g/4ω²

r = 3×9.81 / (4× 0.7536)

r = 12.95 m

Therefore, the radius of the circle in which the jack travels is equal to 12.95m.

Learn more about vertical circular motion, here:

https://brainly.com/question/22810476

#SPJ2

Your question is incomplete, most probably the complete question was,

Jack sits in the chair of a Ferris wheel that is rotating at a constant 0.120 rev/s. As Jack passes through the highest point of his circular part, the upward force that the chair exerts on him is equal to one-fourth of his weight. What is the radius of the circle in which Jack travels?

Circuit connections can either be series or parallel. In a_____connections, there is only one path of electrons, loads that are connected have the same current passing through them.​

Answers

Answer:

circuit

Explanation:

What is the meaning of eddy currents in electromagnetic series?​

Answers

Answer:

currents which circulate in conductors like swirling eddies in a stream in electromagnetic series....

A. praised
B. scolded
C. rewarded
14. Reicon's parents admonished him for breaking their antique collection,
D. silenced
15. I am an advocate of anti-corruption movement in the country.
D. supporter
C. enemy
DirectioRead the statements below. Using context clues, identify the meaning
A. opponent
B. primer
highlighted words.
16. The hotel abolishes its rice-all-you-can policy to avoid wastage of food.
b. removes
d. proposes
A. continues
17. The country has a very tropical climate where it only has dry and wet
seasons similar to other countries in Southeast Asia
a. humid
b. cold
d. normal
-
c. comfortable
d. collected
a. new
c. outdated
18. The obsolete books and other references in the library resulted to the
removal in the shelves and inventory.
b. old
19. Beverages, such as juices, milk, beers and sodas, have increased in
,
due to low supply and importation issues.
a. drinks b. food
d. pastas
20. The luxurious life of my cousin in an exclusive subdivision in Ta
makes me inspired to dream and work hard for me to escape this unp
d.
a. ordinary b. fantastic
c. uncomfortable
c. bread








Help help me plis po summative test ko po ito plis help me

Answers

Answer:

14. scolded

15. supporter

16. i am not sure but I think it is removes

17. comfortable

18. outdated

19. drink

20. it can be fantastic or wealthy

Answer:

14. Reicon's parents admonished him for breaking their antique collection,

scolded

15. I am an advocate of anti-corruption movement in the country.

supporter

16. The hotel abolishes its rice-all-you-can policy to avoid wastage of food.

it is removes

17. The country has a very tropical climate where it only has dry and wet

seasons similar to other countries in Southeast Asia

comfortable

18. The obsolete books and other references in the library resulted to the

removal in the shelves and inventory.

outdated

19. Beverages, such as juices, milk, beers and sodas, have increased in,due to low supply and importation issues.

drinks

20. The luxurious life of my cousin in an exclusive subdivision in Ta makes me inspired to dream and work hard for me to escape this unp.

fantastic

What is the birth rate of a population of 3000 chipmunks if 200 chipmunks are born each year?
o 0.022 births per chipmunk per year.
0.067 births per chipmunk per year.
O 0.82 births per chipmunk per year.
o 15 births per chipmunk per year.

Answers

Answer:

0.067 births per chipmunk per year

Explanation:

I took the test

if fire needs oxygen to burn, where does the sun get oxygen if there is no oxygen in space?​

Answers

The sun is not a burning fire.

It's much much much hotter than that.

The sun's energy is the result of continuous nuclear fusion in it's core. We know how to do that on Earth, but the only thing we've been able to use it for so far is hydrogen bombs and other thermonuclear weapons.

a. How fast should a boy of 40kg mass run so that the kinetic energy becomes 800J?​

Answers

Answer:

[tex]k.e. = \frac{1}{2}mv {}^{2} \\ 800= \frac{1}{2} \times 40 \times v {}^{2} \\ 800 = 20v {}^{2} \\ v {}^{2} = 400 \\ v {}^{2} = 20ms {}^{ - 1} [/tex]

k.e. = kinetic energy

hope helpful <3

A pendulum is made from a long rod of mass M and length L with a solid sphere (ball) of mass m and radius R attached to one end. As measured from the top of the pendulum (the end of the rod without the sphere), how far down the rod is the center of mass of the pendulum located

Answers

Answer:

Explanation:

If we assume the rod and sphere are of uniform construction so that their individual centers of mass are at their geometric centers, and that the rod end is attached to the surface of the sphere.

Balance moments about the rod free end of the assembly with its parts

(M + m)Cx = M(L/2) + m(L + R)

Cx = (M(L/2) + m(L + R)) / (M + m)

A small, free-to-rotate magnet is placed in a strong magnetic field. In what orientation will it come to rest

Answers

Answer:

South-North

Explanation:

5) You pull a 10.0 kg wagon along a flat road. You exert a force of 80.0 N at an angle of 30.0 degrees above the horizontal while you move the wagon 10.0 m forward. The coefficient of friction between the wagon and road is 0.500. Calculate the work down by you and the work done by friction.

Can someone solve by showing the steps?

Answers

This question involves the concepts of work done and the frictional force.

a. Work done by the person is "692.82 N".

b. Work done by the frictional force is "490.5 N".

a.

Work done by the person can be given by the following formula:

[tex]W=FdCos\theta[/tex]

where,

W = work done by the person = ?

F = Force applied by the person = 80 N

d = distance traveled = 10 m

θ = angle between force and motion = 30°

Therefore,

[tex]W=(80\ N)(10\ m)Cos30^o[/tex]

W = 692.82 N

b.

Work done by the frictional force is given by the following formula:

[tex]W_f=fd\\W_f=\mu mgd[/tex]

where,

[tex]W_f[/tex] = work done by the frictional force = ?

μ = coefficient of friction = 0.5

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]W_f=(0.5)(10\ kg)(9.81\ m/s^2)(10\ m)[/tex]

[tex]W_f=490.5\ N[/tex]

Learn more about frictional force here:

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An object is dropped from a vertical height of 1.89 m above the balcony level. What is the object’s speed when it is 2.20 m below the balcony level if 10.0% energy is lost due to the air resistance? Does it matter when to apply 10% loss before V calculations or after? [8.49m/s] [yes it does, 0.9Energy result in √0.9Velocity]

Answers

Answer:

The 10% must come off the energy, not the velocity

Explanation:

Change in height h = 1.89 + 2.20 = 4.09 m

Potential energy = mgh = m(9.81)(4.09) = 40.1m J

Friction losses 40.1m(0.10) = 4.01m J

Kinetic energy at end 40.1m - 4.01m = 36.1m J

KE = ½mv²

v = √(2KE/m)

v = √(2(36.1m)/m = √72.2

v = 8.4983...

v = 8.50 m/s

What is the formula of [tex]\underline{force}[/tex]in physics?

Answers

The formula of force is F = ma.

Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N).  Force is a vector quantity

Types of force

Friction forcePushPullUpthrustTensional force.

⇒ The formula of force is

F = ma................ Equation 1

⇒ Where:

F = forcem = mass of the bodya = acceleration

Hence, the formula of force is F = ma.

Learn more about force here: https://brainly.com/question/13370981

Before looking at the formula, Lets understand what is force?

Force:- Force can be defined as the cause of motion of an object. Force can change the shape, direction and velocity of an object.

It's SI unit is Newton

The formula used to find force is:

[tex] \sf \nrightarrow \: F=m×a[/tex]

Where,

F is forceM is mass of the bodyA is acceleration

Equation in words:- Force applied on an object is directly proportional or equal to the product of the mass of object and the acceleration of object.

PLSSS HELP IT'S VERY IMPORTANT FOR ME WILL MAKE AS BRAINLIEST
Fill in the blank
Valence electrons are______

"The answer is not electrons in the outer shells that are not filled!!"​​

Answers

Answer:

negatively charged particle

valence electron  is a electron of an atom, located in the outermost shell (valence shell ) of the atom, that can be transferred to or shared with another atom.

When tightening a bolt, you push perpendicularly on a wrench with a force of 185 N at a distance of 0.11 m from the center of the bolt. How much torque are you exerting relative to the center of the bolt

Answers

Explanation:

The torque exerted on the wrench is

[tex]\tau = Fd\sin{\theta} = Fd[/tex]

since the force is applied perpendicular to the wrench, in which sin90 = 1. The torque then is

[tex]\tau = (185\:\text{N})(0.11\:\text{m}) = 20.35\:\text{N-m}[/tex]

How does a balanced chemical equation demonstrate the Law of Conservation of Mass? it shows that only physical changes follow the Law of Conservation of Mass it shows that only physical changes follow the Law of Conservation of Mass it shows that the properties of the elements stay the same after the reaction it shows that the properties of the elements stay the same after the reaction it shows that all compounds remain bonded after the reaction it shows that all compounds remain bonded after the reaction it shows that no atoms have been gained or lost during the reaction

Answers

Answer:

it shows that the properties of the elements stay the same after the reaction

it shows that the properties of the elements stay the same after the reaction

it shows that all compounds remain bonded after the reaction

it shows that all compounds remain bonded after the reaction

it shows that only physical changes follow the Law of Conservation of Mass

it shows that only physical changes follow the Law of Conservation of Mass

it shows that no atoms have been gained or lost during the reaction

it shows that no atoms have been gained or lost during the reaction

A ball is thrown up onto a roof, landing 4 sec later at height of 20m above the release level. The balls path just before landing is angled at 60 degree with the roof.
a) find the horizontal distance d it travels.
b) what is the magnitude of the balls initial velocity?
c) what is the angle (relative to the horizontal) of the balls initial velocity?

Answers

Answer: 20

Explanation:

I need your help with this question, it’s my final exam for physics

Answers

Answer:

●Bx=Bcos40

Bx=10 × 0.76

Bx=7.6

●By=Bsin40

By=10×0.64

By=6.4

Hope it will help you.

True or False: Any wavelength of light would work for this experiment. Explain your response, including the term quantum or quantized.

Answers

Answer:

I think false I don't know if I right but I hoped this help

please paraphrase this paragraph

As a conclusion we first learned what is Discrete Fourier Transform and
why is it very important in signal processing science as it helps us to convert the discrete signal from time domain into frequency domain and the inverse DFT does the opposite converting the signal from frequency domain back into time domain. We have also learned the difference between DFT and the FFT algorithm where the FFT is an efficient
algorithm created to simplify the DFT process as it is faster and more accurate. We also learned how to perform and implement this algorithm using Matlab,

Answers

Answer:

The importance of signal processing science as has been made clear. Since we now know that it help to convert discrete signal from time domain to frequency domain. Moreover, we are now aware of the difference in DF5 and FFT algorithms as well as the implementation in Matlab.

-
9 Two bodies of 6 kg and 4 kg masses have their
velocity 5i - 2j +10k and 10î – 2ġ +5ť,
respectively
. Then, the velocity of centre of me
(a) 5ỉ +23 - 8 (b) 7î+ 29 - 8
(2) 7î – 2į +8ỉ (d) 5î – 29 +8k
+
-

Answers

Answer:

I don't know he he.

just joking

What is the word that is used to describe someone that is using a drug?
A: Sober
B: Crazy
C: High
D: Slumped


Helppp​

Answers

The answer would be B.Crazy

Hope It Helps and Stay Safe(◠‿◕)

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time?

Free-fall Acceleration is -10 m/s^2

Answers

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 0(15) + ½(6)(15²)

s = 675 m

Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds

s = ½10(15²) = 2250 m  if air resistance is ignored

Please Help

A car of mass 400 kais sped up from 10m/s to 30m/s in a time of 15 seconds

What is the starting KE?
what is the ending KE?
what is the work done to speed up the car?
what is the power of watts?​

Answers

Explanation:

The initial kinetic energy [tex]KE_0[/tex] is

[tex]KE_0 = \frac{1}{2}mv_0^2 = \frac{1}{2}(400\:\text{kg})(10\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\;\:= 2×10^4\:\text{J} = 20\:\text{kJ}[/tex]

The final kinetic energy [tex]KE[/tex] is

[tex]KE = \frac{1}{2}mv^2 = \frac{1}{2}(400\:\text{kg})(30\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\:\:= 1.8×10^5\:\text{J} = 180\:\text{kJ}[/tex]

The work done W on the car is

[tex]W = \Delta{KE} = KE - KE_0[/tex]

[tex]\:\:\:\:\:\:\:= 180\:\text{kJ} - 20\:\text{kJ} = 1.6×10^5\:\text{J}[/tex]

The power expended P is

[tex]P = \dfrac{W}{t} = \dfrac{1.6×10^5\:\text{J}}{15\:\text{s}} = 10667\:\text{Watts}[/tex]

[tex]\:\:\:\:\:= 10.7\:\text{kW}[/tex]

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