A child is stationary on a swing.(a)The child is given a push by his brother to start him swinging.His brother applies a steady force of 84 N over a distance of 0.25 m.(i) Calculate the work done by this force.(2)..............................................................................................................................................(ii) State how much energy is transferred by this force.(1)..............................................................................................................................................(iii) After several more pushes, the child has a kinetic energy of 71 J.The mass of the child is 27 kg.Show that the velocity of the child at this point is about 2.3 m/s.(2)(iv) Which one of these quantities changes in both size and direction while he is swinging?Put a cross ( ) in the box next to your answer.(1)Ahis gravitational potential energyBhis momentumCthe force of gravity acting on himDhis kinetic energy

Answers

Answer 1

Answer:

Work done = Fs

Explanation:

(i) W = Fxs

= 84N x0.25m

= 21 Joules

(ii) Ek = 1/2mv^2

71 = 1/2×27×v^2

71×2/27 = v^2

v = 23m/s

Answer 2

The work done by this force is 21 Joule.

Energy transferred by the force is 21 Joule.

The boy's momentum changes periodically, that is,  in both size and direction.

What is force?

An external force is an agent that has the ability to change the resting or moving condition of a body. It has a direction and a magnitude. So, it is  a vector quantity. Newton is the SI unit of force (N).

(i) Given parameter:

Steady force applied by his brother, F = 84 N.

Displacement, d = 0.25 m.

The work done by this force, W = F.d = 84×0.25 = 21 Joule.

(ii) Amount of work done is transferred by this force as an energy. So, amount of energy transferred by the force is 21 Joule.

(iii) Given parameter:

Mass of the child, m= 27 kg.

Kinetic energy, E = 71 J.

Let, velocity of the child = v, then kinetic energy is,

E = 1/2 × mv²

⇒ v = √(2E/m)

= √(2×71/27)

= 2.3 m/s.

Hence, the velocity of the boy is 2.3 m/s. (proved).

(iv) During swing, his velocity changes periodically. That's why, his momentum changes periodically, that is,  in both size and direction.

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Related Questions

If two stars are in a binary system with a combined mass of 5.5 solar masses and an orbital period of 12 years, what is the average distance between the two stars

Answers

The average distance between the two stars is 792 light years

Let the mass of the first star be [tex]m_1[/tex]

Let the mass of the second star be [tex]m_2[/tex]

The combined mass of the two stars, [tex]m_1+m_2=5.5[/tex] solar masses

The orbital period of the stars, P = 12 years

Average distance between the two stars, D = ?

The average distance between the two stars can be calculated using Kepler's equation

[tex]D=(m_1+m_2)P^2[/tex]

Substitute [tex]m_1+m_2=5.5[/tex] and P = 12 into the formula [tex]D=(m_1+m_2)P^2[/tex]

[tex]D=5.5(12^2)[/tex]

D = 5.5(144)

D = 792 light years

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a device that converts mechanical energy into electricity is a

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An electric generator is a device that converts a form of energy into electricity.

Explanation:

Determine the work done by the force Fx=(6x-4)N as the object moves from x1=0 to x2=3 m.

Answers

Answer:

15J

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Let's assume force and motion have the same direction, so the dot product between the two reduces to the product of magnitudes.

If you studied calculus:  [tex]w= \int \limits^3_0 6x-4dx[/tex], by definition. Some "easy" math, that's [tex](3x^2-4x)\limits^3_0=27-12 - 0 = 15 J[/tex]

Else. we have to take the long way.  if the force was constant, and you plotted magnitude of the force vs position in a graph, you would get an horizontal line, and your work would be the area between the line and the x axis. And there is no reason why it shouldn't be the same for a variable force - if you think about it, it's the same way they justify the position formula for an accelerated motion. Let's graph it and start debating - sorry for my paint skills. We can easily say that in the green triangle the force is opposing the motion, so its work is negative, while in the blue area force and displacement go in the same direction, thus work is positive. Now it's just to calculate the area of two triangles

For the green one, it's a right triangle with side lengths 4 and 2/3, whose area is [tex]\frac12(4)(\frac23) = \frac43[/tex].

For the blue triangle, it's again a right triangle with side lengths 14 and 3-2/3= 7/3, whose area is [tex]\frac12(14)(\frac73) = \frac{49}3[/tex]

Our total work is the difference between the two, or [tex]w= \frac{49}3-\frac43 = \frac{45}3 = 15[/tex]

plzz explain how it is 66 m
i know that distance =speed × time so how it is 66 m not a
0.4 and if there us another rule plz explain like if u day that 1/2 ×speed ×time plz explain why u used 1/2 or when do I use the 1/2 rule ​

Answers

Hi there!

For someone to hear an echo, the sound must echo and bounce back to the person.

Thus, the sound travels TWICE the distance from the person to the wall (to the wall and back).

We know that:

d = st  (distance = speed × time)

Let L = distance from person to wall

Thus:

2L = st

2L = 330 × 0.40

2L = 132

L = 66 m

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Answers

Answer:

Rotational dynamics is the study of forces and motions about an axis of rotation.

Explanation:

Formulas such as Kinematic Equations and Newton's laws can be expressed in rotating coordinate frames such as: Newton's 2nd Law Fnet=m x a translates into Torque = I x α Where I is Moment of Inertia (the rotational analogous term to mass)

Answer:

Rotational dynamics is the study of forces and motions about an axis of rotation.

Explanation:

Formulas such as Kinematic Equations and Newton's laws can be expressed in rotating coordinate frames such as:

Newton's 2nd Law Fnet=m x a translates into Torque =I x α Where I is Moment of Inertia (the rotational analogous term to mass)

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Answer:

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______________________

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Image credit: The Hubble Heritage Team (AURASTSCI/NASA)
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true

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Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

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Hi there!

(A) The force that the ball exerts on Earth is equal in magnitude to the force that Earth exerts on the ball.

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Answers

Answer:

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