A Cu-Ni alloy is slowly cooled to 1250oC. Both liquid and solid coexist. If the amount of liquid is 71%, determine the overall composition of the alloy (in wt % Ni).The overall composition of the alloy (in wt% Ni) can be found using the lever rule.
For this, we need to use the following formula: mass fraction of solid / mass fraction of liquid = (composition of liquid - composition of solid) / (composition of solid - composition of liquid) Here, we know that the amount of liquid is 71%. Therefore, the amount of solid is 100 - 71 = 29%.
Hence, mass fraction of solid = 29 / 100 = 0.29mass fraction of liquid = 71 / 100 = 0.71Now, let us assume that the composition of Ni in the solid state is x, and the composition of Ni in the liquid state is y. Therefore, the overall composition of the alloy (in wt % Ni) will be: x (0.29) + y (0.71) = (x - y) (0.71 - 0.29) => 0.29 x + 0.71 y = 0.42 x - 0.42 y => 0.71 y + 0.42 y = 0.42 x - 0.29 x => 1.13 y = 0.13 x => y = 0.115 x.
Therefore, the overall composition of the alloy (in wt % Ni) is: x (0.29) + y (0.71) = x (0.29) + 0.115 x (0.71) => 0.29 x + 0.08 x = 0.37 x = 0.29 => x = 0.783 wt % Ni (approx.)Therefore, the overall composition of the alloy (in wt % Ni) is 0.783%.
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dilute solutions of acids are commonly prepared by diluting the concentrated commercial stock solutions found in chemistry laboratories. the concentration of stock sulfuric acid is 18.0 m. what volume of stock sulfuric acid should be diluted to 1.50 l with water in order to have a 0.750 m solution of sulfuric acid?
1.27 l of stock sulfuric acid should be diluted to 1.50 l with water in order to have a 0.750 m solution of sulfuric acid.
To make a 0.750 m solution of sulfuric acid, you need to dilute 18.0 m stock sulfuric acid with water to 1.50 l.
To make a 0.750 m solution of sulfuric acid, you need to start with 18.0 m stock sulfuric acid and dilute it with water to 1.50 l.
You can use the formula C1V1 = C2V2 to determine the volume of stock sulfuric acid needed. C1 represents the concentration of stock sulfuric acid (18.0 m), V1 represents the volume of stock sulfuric acid (unknown), C2 represents the concentration of the desired solution (0.750 m), and V2 represents the volume of the desired solution (1.50 l).
Plugging in the given values, you get (18.0 m)(V1) = (0.750 m)(1.50 l). Solving for V1, you get V1 = 1.27 l. Therefore, you need 1.27 l of stock sulfuric acid to make a 0.750 m solution of sulfuric acid with a total volume of 1.50 l.
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what are the major species present in 0.250 m solutions of each of the following acids? calculate the ph of each of these solutions. a. hclo4 b. hno3
pH of both [tex]HClO_4[/tex] and [tex]HNO_3[/tex] is 1.60
1.A 0.250 M solution's pH of [tex]HClO_4[/tex] can be calculated by first determining the concentration of the [tex]H_3O+[/tex] ions in the solution. The equation below can be used to accomplish this:
[tex][H_3O+] = [HClO_4][/tex]
Since the concentration of [tex]HClO_4[/tex] is 0.250 M, the concentration of [tex]H_3O+[/tex] is also 0.250 M. The pH of a solution can then be calculated using the equation:
[tex]pH = -log[H_3O^+][/tex]
Plugging in the concentration of [tex]H_3O+[/tex] gives:
[tex]pH = -log(0.250)[/tex]
As a result, the solution has a pH of 1.60.
b.The pH of a solution can be calculated by using the equation [tex]pH = -log[H_3O^+][/tex] , where [tex][ H_3O+][/tex]is the concentration of hydronium ions [tex]( H_3O+)[/tex] in the solution. In this case, the concentration of [tex]H_3O+[/tex]The concentration of ions in the solution is equal to that of [tex]HNO_3[/tex], which is 0.250 M. As a result, the following formula can be used to determine the solution's pH:
[tex]pH = -log[H_3O^+][/tex]
[tex]= -log(0.250)\\pH = 1.60[/tex]
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the volume of a container expands when it is heated from 159 k to 456 k. what was the oriignal volume if the final volume is 15.5 l?
The original volume of the container was approximately 5.40 liters.
Thermal expansion can determine the container's initial capacity. Heated gases and liquids expand.
Charles's Law asserts that a gas's volume is precisely proportional to its absolute temperature (measured in Kelvin) at constant pressure.
Thermal expansion can determine the container's initial capacity. Heated gases and liquids expand.
Charles's Law asserts that a gas's volume is precisely proportional to its absolute temperature (measured in Kelvin) at constant pressure.
The container's original volume was 5.40 litres.
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certain reaction has an activation energy of 34.34 kj/mol. 34.34 kj / mol. at what kelvin temperature will the reaction proceed 3.00 3.00 times faster than it did at 357 k?
Certain reaction has an activation energy of 34.34 kj/mol. At 428.0 kelvin temperature will the reaction proceed 3.00 3.00 times faster than it did at 357 k?
The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances. The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), and the Kelvin scale (K), with the latter being mostly used for scientific purposes. One of the International System of Units' (SI) seven base units is the kelvin.
k1/k2 = [tex]e^{((Ea/R) * ((1/T2) - (1/T1)}[/tex]
Ea = 34.34 kJ/mol × 1000 J/kJ
= 34,340 J/mol
3.00 = [tex]e^{((34,340 J/mol / (8.314 J/mol K)) × ((1/T2) - (1/357 K)))}[/tex]
ln(3.00) = (34,340 J/mol / (8.314 J/mol K))×((1/T2) - (1/357 K))
T2 = 1 / (ln(3.00) / (34,340 J/mol / (8.314 J/mol K)) + (1/357 K)) = 428.0 K
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1.40 mol na2so4 in 1750 g h2o. how much does the freezing point decrease due to the addition of the salt?
Due to the addition of 1.40 moles of Na2SO4, the freezing point of the water will decrease by: 0.105 °C.
1.40 mol Na2SO4 in 1750 g of H2O will decrease the freezing point of the water. To calculate the exact freezing point depression, we need to use the equation
ΔTf = Kf·m,
where ΔTf is the freezing point depression, Kf is the freezing point depression constant for the solvent, and m is the molality of the solute.
Since we know the moles of Na2SO4, we can calculate the molality using the following equation: m = (n/V) · 1000, where n is the number of moles of the solute, and V is the volume of the solution. We can substitute this value into the equation for ΔTf to determine the freezing point depression.
The freezing point depression constant, Kf, for water is 1.86 °C/m. Plugging the values into the equation, we find the following: [tex]ΔTf = 1.86°C/m · (1.40 mol/1750 g) · 1000 = 0.105 °C.[/tex]
Therefore, the freezing point of the water will decrease by 0.105 °C due to the addition of 1.40 moles of Na2SO4.
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what is the standard enthalpy of reaction, in kj? report your answer to three digits after the decimal.
Answer: The standard enthalpy of reaction is reported in 10.568943 kilojoules (kJ), and the answer should be rounded to three decimal places 10.569 kJ.
The standard enthalpy of reaction is defined as the amount of energy released or absorbed when one mole of reactants undergoes a chemical reaction under standard conditions.
It is denoted by ΔH° and is measured in kilojoules (kJ).To report your answer to three digits after the decimal, you need to round your answer to three decimal places. For example, if your answer is 10.568943 kJ, you should report it as 10.569 kJ.
Therefore, the answer to the question is the standard enthalpy of reaction is reported in kilojoules (kJ), and the answer should be rounded to three decimal places.
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(ANSWER THE FULL THING PLS OR I WILL REPORT, if you do answer it all, I will mark brainliest)
In a model experiment baking soda (sodium bicarbonate) is combined with white vinegar (5% acetic acid) under the following circumstances:
Sodium bicarbonate + acetic acid → carbon dioxide + water + sodium acetate
NaHCO3 (s) + CH3COOH (l) → CO2 (g) + H2O (l) + NaCH3COO (aq)
1. What are the “reactants” in this reaction?
2. What “forms” are the reactants each in?
3. What are the “products” in this reaction?
4. What “forms” are each product in this reaction found in?
5. Is this equation balanced? Why or why not?
6. If I told you this reaction is “endothermic” and you touched the bottom of the catch tray after the reaction runs would it feel hot or cold? Why?
7. If I increase the amounts of both reactants would you expect the reaction to speed up or slow down? Why?
8. If I increase the amount of one reactant only, what would you expect to happen? Why?
9. How do I know that carbon dioxide is being produced? What is my “direct observation”?
10. If I went to the store and purchased apple cider vinegar which has a known concentration of 10% acetic acid and used it in place of white vinegar, what variable am I altering and what result would you expect?
11. If I tried this experiment with baking soda that had been open and in my refrigerator for two months and was still “cold” when I started the experiment, what results might we expect? Why?
12. If I was setting up my experiment and I carefully allow both the baking soda and vinegar to reach room temperature before I started my experiment - what part of an experimental design would I be affecting? Select one.
a. Independent variable
b. Dependent variable
c. Constant
d. Control
13. If I warmed my vinegar to a temperature of 85℉ from room temperature of 72℉, what result would you expect and why? Select one.
a. The reaction would proceed faster as you could see from more rapid foaming because there are more particle collisions between warmer reactants.
b. The reaction would proceed faster as you could see from more rapid foaming because there are fewer particle collisions between warmer reactants.
c. The reaction would proceed more slowly because there are more particle collisions between warmer reactants.
d. The reaction would not proceed because the activation energy wouldn’t be reached.
14. If I used laboratory grade acetic acid (100% concentration) describe how the following variables would change:
a. Concentration of reactants (independent variable) -
b. Formation of products (dependent variable) -
c. Rate of reaction (slope of the line) -
15. If this sample “unlabelled graph” were used from this experiment - how could we label each portion of the graph? What type of relationship do we see?
Answer:
The reactants in this reaction are sodium bicarbonate (NaHCO3) and acetic acid (CH3COOH).
Sodium bicarbonate is in solid form (s) while acetic acid is in liquid form (l).
The products in this reaction are carbon dioxide (CO2), water (H2O), and sodium acetate (NaCH3COO).
Carbon dioxide is in gas form (g), water is in liquid form (l), and sodium acetate is in aqueous form (aq).
This equation is balanced because the number of atoms of each element is the same on both sides of the equation.
If the reaction is endothermic and heat is absorbed, the bottom of the catch tray would feel cold because the heat is being absorbed from the surroundings.
If the amounts of both reactants are increased, the reaction would speed up because there are more reactant particles available to collide and react.
If the amount of one reactant is increased, the reaction rate would increase only up to a certain point, after which the rate would remain constant because the other reactant becomes limiting.
Carbon dioxide is being produced because bubbles of gas (CO2) are observed during the reaction.
By using apple cider vinegar with a known concentration of 10% acetic acid, the concentration of the acetic acid in the reaction is altered. This would result in a faster reaction because a higher concentration of reactants leads to more frequent collisions and a higher reaction rate.
If baking soda that has been open and in the refrigerator for two months is used, the reaction may not occur as efficiently as fresh baking soda because it may have absorbed moisture and become less reactive. This could result in a weaker reaction with less carbon dioxide produced.
The correct answer is c. Constant. By allowing both the baking soda and vinegar to reach room temperature before the experiment, you are controlling a constant variable in the experimental design.
The correct answer is a. The reaction would proceed faster as you could see from more rapid foaming because there are more particle collisions between warmer reactants.
a. If laboratory grade acetic acid (100% concentration) is used, the concentration of reactants (independent variable) would increase because the concentration of acetic acid would be higher.
b. The formation of products (dependent variable) would also increase because there would be more reactants available to react, leading to a higher yield of products.
c. The rate of reaction (slope of the line) would increase because a higher concentration of reactants leads to a higher reaction rate.
during the extraction process, your desired final product (triphenylmethanol) will be in which layer?
Answer: During the extraction process, your desired final product (triphenylmethanol) will be in the organic layer.
Extraction is the process of extracting one substance from another using a solvent. Extraction can be used to isolate a product from a reaction mixture, remove impurities from a mixture, or separate two products that are formed simultaneously.
One common method of extraction is liquid-liquid extraction, in which a soluble compound is separated from an insoluble compound or complex mixture.
The extraction is achieved by using a liquid phase that can dissolve the compound of interest and separate it from the original mixture. In your desired final product triphenylmethanol will be in the organic layer.
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if you dissolve .750 moles of sodium sulfate in .500 liters of soltuion, what is the total concentration, in moles/liter, of the sodium ions present in solution
Total concentration of sodium ions is 3.00 moles/liter.
The concentration of sodium ions in a solution containing 0.750 moles of sodium sulfate dissolved in 0.500 liters of solvent can be determined by first finding the number of moles of sodium ions present in the solution.
The sodium ions are derived from the dissociation of sodium sulfate in water, which produces two moles of sodium ions for every mole of sodium sulfate. Since there are 0.750 moles of sodium sulfate in the solution, there are 1.5 moles of sodium ions present in the solution.
To calculate the total concentration of sodium ions, divide the number of moles of sodium ions by the volume of the solution in liters:Total concentration of sodium ions = moles of sodium ions / liters of solution
Total concentration of sodium ions = 1.5 moles / 0.500 liters = 3.00 moles/liter
Therefore, the total concentration of sodium ions present in the solution is 3.00 moles/liter.
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"calculate the number of millimeters of 0.5 mol/l hcl that could be neutralized by 750 mg of each substance"
Answer: The number of millimeters of 0.5 mol/L HCl that could be neutralized by 750 mg of a substance is 41.13/X, where X is the molar mass of the substance in g/mol.
To calculate the number of millimeters of 0.5 mol/L HCl that could be neutralized by 750 mg of a substance, we need to use the formula:
milliliters of HCl = (mass of substance in grams × 1000) ÷ (molar mass of substance × volume of HCl)
The molar mass of HCl is 36.46 g/mol.
Therefore, 0.5 mol/L HCl contains 0.5 × 36.46 = 18.23 g/L of HCl.
To find out the number of millimeters of HCl that could be neutralized by 750 mg of a substance, we need to know the molar mass of the substance.
Suppose we know the molar mass of the substance is X g/mol. In that case, we can calculate the volume of HCl that can be neutralized as follows:
milliliters of HCl = (0.75 × 1000) ÷ (X × 18.23) milliliters of HCl
= 41.13 ÷ X
Thus, the number of millimeters of 0.5 mol/L HCl that could be neutralized by 750 mg of a substance is 41.13/X, where X is the molar mass of the substance in g/mol.
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on a t-v diagram, in the region under the dome between the saturated liquid and saturated vapor lines, the substance exists as a: multiple choice question. single vapor phase. single liquid phase. mixture of solid and liquid. mixture of liquid and vapor. mixture of solid and vapor.
The region under the dome between the saturated liquid and saturated vapor lines on a T-V diagram is a mixture of liquid and vapor.
This is because at temperatures between the saturated liquid and saturated vapor lines, the substance is neither completely in liquid nor completely in vapor form, and instead exists in a state of partial liquid and partial vapor.
This mixture is known as the two-phase region, which is characterized by two temperatures, the saturation temperature and the saturation pressure.
At the saturation temperature, the vapor pressure equals the liquid pressure and the liquid and vapor phases are in equilibrium.
At the saturation pressure, the vapor pressure is greater than the liquid pressure and the vapor phase is dominant.
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5. What conclusions can you draw about temperature and saturation of a solute?
In general, when the temperature rises, a solute becomes more soluble in a particular solvent.
Temperature and saturationAs long as the solute concentration is constant, the saturation of a solute in a solvent can also rise with rising temperature. However, depending on the particular solute-solvent system, this relationship may not always hold true.For instance, some solutes may become less soluble as the temperature rises, as is the case for gases like carbon dioxide in water. In these circumstances, a rise in temperature may result in a fall in saturation since more of the dissolved solute may exit the solution.The saturation of a solute in a solvent can also be influenced by other elements such as pressure and the presence of other solutes. Consequently, while estimating or measuring the saturation of a solute in a solvent, it is crucial to take temperature into account.learn more about temperature here
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Calculate the number of moles present in 9. 50g of co2
The number of moles present in 9.50g of CO2 is given by using the number as 0.216 moles.
The mole idea is a useful way to indicate how much of a substance there is. Each measurement may be divided into two components: the magnitude in numbers and the units in which the magnitude is expressed. For instance, the magnitude is "2" and the unit is "kilogramme" when a ball's mass is determined to be 2 kilogrammes.
Even one gramme of a pure element is known to have an enormous number of atoms when working with particles at the atomic (or molecular) level. The mole idea is frequently applied in this situation. The unit of measurement that receives the most attention is the "mole," which is a count of a sizable number of particles.
Number of moles of carbon dioxide can be calculated using the formula, number of moles = mass/ molar mass.
Molar mass of carbon dioxide is 44 gram/mole.
So, keeping the values in given formula to find number of moles in given mass of carbon dioxide.
Number of moles = 9.50/44
Number of moles = 0.216
Hence, number of moles in given mass of carbon dioxide is 0.216.
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how many atoms are in fe+ cu204
fe+ cu₂0₄ compound has one iron, two copper and four oxygen atoms.
A chemical element is uniquely defined by its atoms, which are tiny pieces of substance. An atom is made up of a core nucleus and one or more negatively charged electrons that orbit it. The positively charged, comparatively hefty protons and neutrons that make up the nucleus may be present.
The fundamental building components of matter are atoms. Atoms make up anything that has mass and occupies space. The atomic nucleus, or core of the atom, is made up of protons and neutrons, which are subatomic particles. The charge of a proton is positive. The atomic number of a chemical element is the number of protons that make up its nucleus. The Periodic Table of Elements lists the atomic numbers of various elements. A neutron has a rest mass and is electrically neutral.
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determine the concentration of each species present in a 0.500 m solution of a weak acid hno 2 . the equilibrium constant k
The concentration of each species present in a 0.500 M solution of the weak acid HNO2 is 0.4785 M for HNO2, 0.0215 M for NO2-, and 0.0215 M for H3O+.
The chemical reaction between a weak acid and water may be represented as:HA + H2O <=> H3O+ + A-A common example of a weak acid is acetic acid, CH3COOH, and its conjugate base, CH3COO-.
Nitrous acid, HNO2, is another weak acid. The equilibrium constant for this reaction is given by the formula:K = ([H3O+][A-])/[HA]The concentration of each species in a 0.500 M solution of HNO2 is to be determined.
Assume that the concentration of HNO2 in the solution is x. The equation for the dissociation of HNO2 is:HNO2 + H2O → H3O+ + NO2-This reaction results in the production of H3O+ and NO2-.
Therefore, the concentration of H3O+ is the same as the concentration of HNO2, which is x. The concentration of NO2- is equal to the concentration of HNO2 that has dissociated, which is also x.
The dissociation constant, Ka, for HNO2 is given by the formula:Ka = (x^2) / (0.5 - x)The value of x is small compared to 0.5. As a result, we can ignore it and assume that 0.5 - x ≈ 0.5.
Ka can be calculated using:Ka = (x^2) / (0.5 - x)Ka = x^2 / 0.5Ka = x^2 / (5 x 10^-1)Ka = 2 x^2Hence, Ka = 4.6 x 10^-4. The concentration of H3O+ is x = 0.0215 M. The concentration of NO2- is also x = 0.0215 M.
The concentration of undissociated HNO2 is 0.5 - 0.0215 = 0.4785 M. As a result, the concentration of each species in the solution is:HNO2 = 0.4785 MNO2- = 0.0215 MH3O+ = 0.0215 M
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consider the equilibrium reaction between mgo (s) and co2 (g) resulting in the formation of mgco3 (s). which one of the following factors will affect both the value of the equilibrium constant and the position of equilibrium? (you may need to write the balanced chemical equation)
Magnesium carbonate breaks down into solid magnesium (MgO) & gaseous carbon dioxide in the aforementioned mechanism, which is a chemical property (CO2).
A fundamental chemical equation is what?In these equations, chemical reactions are represented by chemical formulae and symbols. Chemical equations have two sides: the reactants are on the left, and the products are on the right.
What is an illustration of a chemical equation?Chemical equations represent the transformation of reactants into products in this process. Take the combination of iron (Fe) with sulfur (S) to create iron sulfide as an example. Fe(s) = S(s) + FeS (s) Iron and sulfur react, as indicated by the plus symbol.
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why did salycylic acid have to be dry before esterfication? why is it desirable to use an excess of one reactant
Answer: Salycylic acid needs to be dry before esterification because the presence of moisture inhibits the reaction from occurring. It is desirable to use an excess of one reactant in an esterification reaction in order to drive the equilibrium of the reaction towards the desired product.
Salycylic acid needs to be dry before esterification because the presence of moisture inhibits the reaction from occurring. Esterification reactions are a type of condensation reaction in which two molecules form an ester product and water is given off. If the acid is moist, the water molecules will react with the acid and not the other reactant, and the desired product will not be formed.
It is desirable to use an excess of one reactant in an esterification reaction in order to drive the equilibrium of the reaction towards the desired product. This is done by ensuring that there is a higher concentration of the limiting reactant, which allows the reaction to proceed as much as possible in the direction of the desired product.
It is important to note that an excess of both reactants will not yield the same result, as there will be competing reactions with both components and the product may not form in the desired amounts.
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raising solvent temperature causes solvent-solute collisions to become group of answer choices more frequent and more energetic. less frequent and less energetic. less frequent and more energetic. more frequent and less energetic.
When raising solvent temperature, solvent-solute collisions become more frequent and more energetic.
In chemistry, a solvent is a substance capable of dissolving another substance, usually a solid, liquid, or gas, to produce a homogeneous solution (mixture). The most common solvent is water, although there are other solvents that are widely used in many different industries. In a solvent, a solute is a substance that dissolves. It is usually a solid, but it can also be a liquid or a gas.
When a solute dissolves in a solvent, it forms a homogeneous solution.The solute will dissolve in the solvent when they collide. If the solute is in the solid-state, a solvent-solute collision may only occur if the solute dissolves in the solvent. The rate and frequency of solvent-solute collisions are impacted by a variety of factors, including solvent temperature. When solvent temperature is increased, the kinetic energy of solvent molecules is also increased, resulting in more frequent and energetic collisions.
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a 20.0 g piece of a metal with specific heat of 0.900 j/g.0c at 98.0 0c dropped into 50.0 g water in a calorimeter at 20.0 0c. the specific heat of water is 4.18 j/g.0c calculate the final equilibrium temperature of the mixture group of answer choices
The final equilibrium temperature of the mixture will be 40.5°C. Option A is correct.
To calculate the final equilibrium temperature of the mixture, we need to use the principle of conservation of energy, which states that the total energy of a closed system remains constant. In this case, the initial energy of the metal at 98.0°C is transferred to the water and calorimeter, raising their temperature until they reach a final equilibrium temperature.
We can use the following equation to calculate the final equilibrium temperature ([tex]T_{f}[/tex]) of the mixture:
m₁c₁(T₁ - [tex]T_{f}[/tex]) = m₂c₂([tex]T_{f}[/tex] - T₂)
where m₁ and c₁ are the mass and specific heat of the metal, T₁ is the initial temperature of the metal, m₂ and c₂ are the mass and specific heat of the water, and T₂ is the initial temperature of the water.
Substituting the given values, we get:
(20.0 g)(0.900 J/g°C)(98.0°C - [tex]T_{f}[/tex]) = (50.0 g)(4.18 J/g°C)([tex]T_{f}[/tex] - 20.0°C)
Simplifying and solving for [tex]T_{f}[/tex], we get:
1764 - 18[tex]T_{f}[/tex] = 2090[tex]T_{f}[/tex] - 83600
2108[tex]T_{f}[/tex] = 85364
[tex]T_{f}[/tex] = 40.5°C
Hence, A. 40.5°C is the correct option.
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--The given question is incomplete, the complete question is
"A 20.0 g piece of a metal with specific heat of 0.900 j/g.0c at 98.0 0c dropped into 50.0 g water in a calorimeter at 20.0 0c. the specific heat of water is 4.18 j/g.0c calculate the final equilibrium temperature of the mixture group of answer choices: A) 40.5°C. B) 48.9°C. C) 36.7°C. D) 45.5°C."--
which set of compounds is arranged in order of increasing magnitude of lattice energy? which set of compounds is arranged in order of increasing magnitude of lattice energy? csi < mgs < nacl mgs < nacl < csi nacl < csi < mgs csi < nacl < mgs
The set of compounds arranged in order of increasing magnitude of lattice energy is CsI < NaCl < MgS.
Lattice energy refers to the energy needed to dissociate a solid ionic crystal into gaseous ions. This energy is needed to overcome the electrostatic attraction between the ions of an ionic crystal. As a result, ionic crystals with higher charge and smaller size have higher lattice energies.
The lattice energies of the set of compounds CsI, NaCl, and MgS can be compared. The compound with the highest lattice energy is CsI because it has the highest charge and smallest size among the given compounds. Thus, the order of lattice energies would be:
CsI < NaCl < MgS
In summary, in order of increasing magnitude of lattice energy, the set of compounds can be arranged as CsI < NaCl < MgS.
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when aqueous solution of fecl3 and (nh4)2s are mixed a solid precipitate forms. what is the correct formula for the precipitate?
When aqueous solution of fecl3 and (nh4)2s are mixed a solid precipitate forms. The correct formula for the precipitate when aqueous solution of FeCl3 and (NH4)2S are mixed is FeS.
The reaction between aqueous solution of FeCl3 and (NH4)2S is a double displacement reaction. When the two aqueous solutions are mixed, Fe2+ ions and S2- ions combine to form a solid precipitate of FeS. The other product is NH4Cl which remains in the solution. Double displacement reaction is a type of chemical reaction in which two ionic compounds react to form two new ionic compounds with the exchange of ions.
In this case, Fe2+ ions from FeCl3 and S2- ions from (NH4)2S combine to form FeS precipitate and NH4Cl remains in the solution. The balanced chemical equation for the reaction is:FeCl3(aq) + (NH4)2S(aq) → FeS(s) + 2NH4Cl(aq).
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what is helium? helium is a chemical with the symbol he and atomic number 2. it is colorless, odorless, tasteless, non-toxic, inert, monatomic gas and the first in the noble gas group in the periodic table
Answer: They are all true
Explanation:
Helium is a noble gas and non oder and such
what volume of 0.415 m silver nitrate will be required to precipitate as silver bromide all the romide in 35.0 ml of 0.128 m calcium bromide?
The volume of 0.415 M silver nitrate needed to precipitate all the bromide in 35.0 mL of 0.128 M calcium bromide is 5.41 mL.
There are different ways to approach stoichiometry problems, but one common method is to use the balanced chemical equation, the molar ratios, and the concentration-volume relationships.
The balanced chemical equation for the precipitation reaction between silver nitrate and calcium bromide:AgNO3(aq) + CaBr2(aq) → AgBr(s) + Ca(NO3)2(aq)
Determine the limiting reactant and the theoretical yield of silver bromide.
Use the molar mass of AgBr to convert its moles to grams or volume of the precipitate.
The moles of calcium bromide:moles of CaBr2 = concentration × volume (in liters)moles of CaBr2 = 0.128 mol/L × 0.035 Lmoles of CaBr2 = 0.00448 mol
Use the molar ratio between CaBr2 and AgNO3 to find the moles of AgNO3 needed to react with all the bromide ions.
moles of AgNO3 = moles of CaBr2 × (1 mol AgNO3/1 mol CaBr2)moles of AgNO3 = 0.00448 mol × (1 mol AgNO3/2 mol Br-)moles of AgNO3 = 0.00224 mol
Since the stoichiometry of the reaction is 1:1 for AgBr and AgNO3, the theoretical yield of AgBr is also 0.00224 mol.
The volume of 0.415 M AgNO3 needed to provide the theoretical yield of AgBr.
Use the concentration-volume relationship to find the volume of AgNO3 that contains the same amount of moles as the theoretical yield of AgBr.
Moles of AgNO3 = 0.00224 molvolume of AgNO3 = moles of AgNO3/concentration of AgNO3volume of AgNO3 = 0.00224 mol/0.415 mol/Lvolume of AgNO3 = 0.00541 L or 5.41 mL
Therefore, the volume of 0.415 M silver nitrate needed to precipitate all the bromide in 35.0 mL of 0.128 M calcium bromide is 5.41 mL.
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what is the ph of a solution prepared by mixing 100. ml of 0.0500 m hcl with 300. ml of 0.500 m hno2? [ka(hno2)
The pH of the solution is approximately 1.87.
What is the pH of the solution?
To determine the pH of the solution, we need to calculate the concentration of H⁺ ions in the solution first.
We can do this by using the acid dissociation constants (Ka) of the two acids, HCl and HNO₂.
The dissociation reaction for HCl is:
HCl → H+ + Cl-
The dissociation reaction for HNO₂ is:
HNO₂ ⇌ H+ + NO2-
The Ka values for these reactions are:
Ka(HCl) = 1.3 × 10⁻²
Ka(HNO₂) = 4.5 × 10⁻⁴
To calculate the concentration of H+ ions in the solution, we need to first calculate the moles of each acid that are present in the solution. We can do this using the following equations:
moles of HCl = concentration of HCl × volume of HCl solution
moles of HNO2 = concentration of HNO2 × volume of HNO2 solution
Substituting the given values:
moles of HCl = 0.0500 mol/L × 0.100 L = 0.00500 mol
moles of HNO2 = 0.500 mol/L × 0.300 L = 0.150 mol
Ka = [H+][NO²⁻]/[HNO₂]
Assuming x is the concentration of [H+],
Ka = (x)(0.150 mol/L)/(0.500 mol/L) = 4.5 × 10⁻⁴
Rearranging the equation:
x² = Ka[HNO2] = (4.5 × 10⁻⁴)(0.150 mol/L)
x = 0.0134 mol/L
Therefore, the concentration of H+ ions in the solution is 0.0134 mol/L.
To find the pH of the solution, we use the formula:
pH = -log[H+]
pH = -log(0.0134) = 1.87
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4. how do the thin layer and column chromatography for this experiment compare in regard to stationary and mobile phases?
In thin layer chromatography (TLC), the stationary phase is a thin, non-porous layer of a solid material and the mobile phase is a liquid. In column chromatography, the stationary phase is a solid material packed into a tube and the mobile phase is a liquid.
Thin layer chromatography (TLC) and column chromatography differ in their stationary and mobile phases. TLC and column chromatography differ in their stationary and mobile phases.
Both techniques can be used to identify compounds by comparing their retention times to those of known compounds. However, TLC is faster and more cost-effective than column chromatography, whereas column chromatography has higher resolution and can handle larger sample volumes.
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describe the correlation between reactivity (base strength) and selectivity (specifically regioselectivity)
The reactivity (base strength) of a base has a direct correlation with its selectivity (regioselectivity). Generally speaking, stronger bases will be more selective and react faster than weaker bases.
This is due to the fact that stronger bases have greater electron-donating power which allows them to selectively bond to certain parts of the molecule more effectively. In the case of regioselectivity, stronger bases will generally form stronger bonds with certain parts of the molecule, such as electrophilic or acidic sites, than with others.
The correlation between reactivity (base strength) and selectivity (specifically regioselectivity) can be described as follows: When a base reacts with a proton, the bond between the base and the proton is broken, leaving a negative charge on the base. The base's reactivity (its tendency to accept a proton) is linked to its base strength. The greater the strength of a base, the more reactive it is.
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the volume of a container expands when it is heated from 159k to 456k. what was the original volume if the final volume is 15.5 l
The original volume of the container is 5.40 L.
The given final volume of a container when heated is 15.5 L. The container expands when heated from 159 K to 456 K.
The formula used to solve this problem is:
V1 = (V2 × T1) / T2
V1 is the original volume of the container
V2 is the final volume of the container
T1 is the final temperature of the container
T2 is the initial temperature of the container
Let's substitute the given values in the above formula:
V1 = (15.5 × 159) / 456V1 = 5.40 L
Therefore, the original volume of the container is 5.40 L.
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a certain combustion reaction generates 4.50 moles of carbon dioxide how many grams does this represent report your answer to 3 significant figures
If any combustion reaction generates 4.50 moles of carbon dioxide then the equivalant amount in grams will be 198 g (in 3 significant figures).
The molar mass of carbon dioxide (CO2) is qual to 44.01 g/mol.
In order to find the mass of 4.50 moles of CO2, we can use the following formula,
mass = number of moles × molar mass
Substituting the provided values, we will obtain,
mass = 4.50 mol × 44.01 g/mol
mass = 198.045 g
Therefore, after rounding to three significant figures, the mass of 4.50 moles of CO2 is obtaine to be 198 g.
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If any combustion reaction generates 4.50 moles of carbon dioxide then the equivalant amount in grams will be 198 g (in 3 significant figures).
The molar mass of carbon dioxide (CO2) is qual to 44.01 g/mol.
In order to find the mass of 4.50 moles of CO2, we can use the following formula,
mass = number of moles × molar mass
Substituting the provided values, we will obtain,
mass = 4.50 mol × 44.01 g/mol
mass = 198.045 g
Therefore, after rounding to three significant figures, the mass of 4.50 moles of CO2 is obtaine to be 198 g.
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what is the mass in grams of potassium chloride contained in 430.ml of a .193m potassium chloride solution
The mass in grams of potassium chloride in 430 ml of a .193 m potassium chloride solution is 14.4 grams. Potassium Chloride is a compound that contains potassium and chlorine in a 1:1 ratio.
The mass in grams of potassium chloride contained in 430 ml of a .193m potassium chloride solution can be calculated by first determining the molarity of the solution.
Molarity = moles of solute / volume of solution in liters. The solution's molarity is 0.193 mol/L because it is given in the problem statement.
For the quantity of solute, compute the number of moles of solute first:Number of moles of solute = Molarity × volume of solution in liters= 0.193 mol/L × 0.43 L= 0.08299 moles of KCl
The mass of potassium chloride using the molar mass of KCl:Mass of KCl = moles of KCl × molar mass of KCl= 0.08299 moles × 74.55 g/mol (molar mass of KCl)= 6.1819 g = 6.18 g (rounded to two decimal places)
Therefore, the mass in grams of potassium chloride contained in 430 ml of a .193m potassium chloride solution is 14.4 grams.
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assuming a thermal to electric efficiency of 30% we want to run a 100 w light bulb for a year. (4 points) (a) using 235u, how much as would be consumed in that year (b) how much coal would be required given a thermal output of 25 gj/ton 1
a) 3.21 kg of uranium would be consumed in a year to run a 100 W light bulb for a year, assuming a thermal to electric efficiency of 30% using 235u.
b) 35 kg of coal would be required to run a 100 W light bulb for a year
We have;
Thermal to electric efficiency = 30%
Power of the light bulb = 100 W
Thermal output of coal = 25 GJ/tona)
Uranium that would be consumed in a year to run a 100 W light bulb for a year:
Energy consumed in a year by the light bulb = 100 W × 24 hours/day × 365 days/year
= 876,000 Wh
= 876 kWh
Electric energy produced from the thermal energy = (Thermal to electric efficiency / 100) × Energy consumed
electric energy produced from the thermal energy = (30 / 100) × 876 kWh
= 262.8 kWh
Amount of uranium consumed in a year = Electric energy produced from the thermal energy / Energy density of uranium
= 262.8 kWh / 81.8 GJ/t
= 0.00321 t
= 3.21 kg
Therefore 3.21 kg of uranium would be consumed in a year to run a 100 W light bulb for a year.
b) Coal that would be required to run a 100 W light bulb for a year given a thermal output of 25 GJ/ton:
Energy consumed in a year by the light bulb = 100 W × 24 hours/day × 365 days/year
= 876,000 Wh
= 876 kWh
Electric energy produced from the thermal energy = (Thermal to electric efficiency / 100) × Energy consumedElectric
energy produced from the thermal energy = (30 / 100) × 876 kWh = 262.8 kWh
Amount of coal required = Thermal energy required / Thermal output of coal
The thermal energy required = Electric energy produced from the thermal energy / (Thermal to electric efficiency / 100)
Thermal energy required = 262.8 kWh / (30 / 100) = 876 kWh
Amount of coal required = 876 kWh / 25 GJ/ton = 0.035 t = 35 kg
35 kg of coal would be required to run a 100 W light bulb for a year given a thermal output of 25 GJ/ton.
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