A green ball and a blue ball have a mass of 10 kg each one. The green ball, traveling at 10 m/s, strikes the blue ball, which is at rest. Assuming that the balls slide on a frictionless surface and all collisions are head-on, find the final speed of the blue ball in each of the following situations:

a. The green ball stops moving after it strikes the blue ball

b. The green ball continues moving after the collision at 4 m/s in the same direction.

Answer:

The answer to your problem is, The change in temperature required is ΔT = ΔV/Vγ

Explanation:

ΔT = ΔV/Vγ

ΔV = 49 - 40 = 9cm

V = 40 cm

γ is unknown since it cannot be calculated due to error in values.

Thus the answer to your problem is, The change in temperature required is ΔT = ΔV/Vγ

The density of brass is approximately 8300 kg/m³.

What is density ?

To find the density of brass, we need to first determine the total mass and volume of the mixture.

Let's assume that we have 1 cubic meter of zinc (since the exact volume is not given, we can use any convenient value as long as we are consistent with units).

The mass of this zinc would be:

mass_zinc = density_zinc * volume_zinc = 7100 kg/m³ * 1 m³ = 7100 kg

Since we are adding twice the volume of copper, we have 2 cubic meters of copper.

The mass of this copper would be:

mass_copper = density_copper * volume_copper = 8900 kg/m³ * 2 m³ = 17800 kg

The total mass of the mixture would be:

mass_total = mass_zinc + mass_copper = 7100 kg + 17800 kg = 24900 kg

The total volume of the mixture would be:

volume_total = volume_zinc + volume_copper = 1 m³ + 2 m³ = 3 m³

Finally, we can calculate the density of brass:

density_brass = mass_total / volume_total = 24900 kg / 3 m³ ≈ 8300 kg/m³

Therefore, the density of brass is approximately 8300 kg/m³.

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The average force on the first ball = - 272.8 N.

The average force on the second ball is 9,568 N, and it acts in the direction of its motion.

the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls can be considered as a closed system.

Let's define some variables:

m =  (mass of each ball)

v1 =  (initial velocity of the first ball)

v2 =  (final velocity of the second ball)

t = 250 μs = 0.00025 s (duration of the collision)

According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:

m * v1 = m * v2

Solving for v2, we get:

v2 = v1 * (m/m) = v1

This indicates that the second ball departs in the opposite direction of the first ball but with the same velocity. As a result, the system's total momentum is preserved.

The impulse-momentum theorem states that the impulse (change in momentum) is equal to the average force multiplied by the duration of the collision. We can use this to determine the average force on the first ball:

F1 * t = m * (v2 - v1)

Substituting the values we know, we get:

F1 * 0.00025 = 0.28 * (-8.6)

Solving for F1, we get:

F1 = - 272.8 N

The first ball's force is acting in the opposite direction of its initial velocity when the sign is negative.

To find the typical power on the subsequent ball, we can utilize a similar recipe:

F2 * t = m * (v2 - v1)

Substituting the values we know, we get:

F2 * 0.00025 = 0.28 * (v2 - 0)

Since we know that v2 = 8.6 m/s, we can solve for F2:

F2 = (0.28 * 8.6) / 0.00025

F2 = 9,568 N

Therefore, the average force on the second ball is 9,568 N, and it acts in the direction of its motion.

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Answer:

Explanation:

m=p/v

where m is mass, p is momentum and v is velocity

Answer:

V = f * λ        Velocity = frequency * wavelength

λ = V / f = 128 m/s / 256 / s= .5 m       is the wavelength

There will be nodes at o, λ/2, λ, 3λ/2      or at intervals of λ/2

The distance between nodes is ".25 m"

Answer:

First, let’s convert the mass of the ball bearing from grams to kilograms: 5.0 g = 0.005 kg.

a)

As the ball bearing falls from the machine to the floor, its gravitational potential energy is converted into kinetic energy. The change in potential energy can be calculated using the formula for gravitational potential energy: PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.

In this case, the change in potential energy is ΔPE = mgh = (0.005 kg)(9.8 m/s²)(3.0 m) = 0.147 J.

Since energy is conserved, this means that the change in kinetic energy is equal to the change in potential energy: ΔKE = ΔPE = 0.147 J.

b)

As the ball bearing bounces back up from the floor to its starting point, its kinetic energy is converted back into potential energy. Since energy is conserved and there are no dissipative forces, the changes in potential and kinetic energies are the same as in part a): ΔPE = 0.147 J and ΔKE = 0.147 J

Indeed, a magnetised object with a north and south pole can be seen in the above photograph.

Any object that creates a magnetic field of its own and interacts with other magnetic fields is a magnet. A magnet has two poles, the north pole and the south pole. Field lines that begin at the north pole and end at the south pole of a magnet are used to show the magnetic field.

When hanging in the magnetic field of the Earth, a bar magnet automatically points northward and southward. A north magnetic pole is any pole that seeks the north, such as the north-seeking pole of this type of magnet.

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In this case, the body has a mass of  [tex]3.0[/tex] kg and is moving with a velocity of [tex]10 m/s[/tex].  the moment of the body is  [tex]30 kg m/s.[/tex]

The moment of a body (also known as its momentum) is defined as the product of the body's mass and velocity.

In this instance, the body weighs  3.0  kilogrammes and is travelling at a speed of 10 m/s.

The formula to calculate the moment of the body is:

momentum = mass x velocity

Plugging in the given values, we get:

momentum [tex]= 3.0 kg \times 10 m/s[/tex]

Solving the above expression, we get:

momentum = [tex]30 kg m/s[/tex]

Therefore, the moment of the body is [tex]30[/tex] kg m/s.

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Disaster recovery and cooperation are both benefited by cloud storage. It makes file sharing simple and guarantees that data is backed up and retrievable in the event of loss or damage.

Your documents and data are kept in a safe data centre off-site by a cloud provider. You are no longer required to update software, maintain the servers, or make sure the hardware is working properly.

To store data, including files, business data, videos, or photographs, cloud storage uses remote servers. Users use an internet connection to upload data to servers, where it is stored on a virtual machine on a physical server.

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Answer:

The magnetic field strength at the center of a solenoid can be found using the formula:

B = u_0 * N * I / L

where B is the magnetic field strength, u_0 is the permeability of free space (4π × 10^-7 T·m/A), N is the number of turns in the solenoid, I is the current flowing through the solenoid, and L is the length of the solenoid.

Given:

N = 500 turns

I = 5 A

u_0 = 4π × 10^-7 T·m/A

Since we don't know the length of the solenoid, we can't calculate the magnetic field strength.

Answer:

Time Travel Machine

Explanation:

The Hubble Space Telescope can look at galaxies that are many light years away. If it captured an image of a star that was 5 light years away, then that means it took light 5 years to reach the lens of the telescope. So, the image we see is what that star looked like 5 years ago. In other words, it is a glimpse of the past.

Answer:

Explanation:"The phenomenon of splitting of visible light into its component colours is called dispersion". Dispersion of light is caused by the change of speed of light.

Answer:

360 watts

Explanation:

P =V × I

= 120×3.0

= 360

The initial momentum of the ball is p₁ = m₁v₁ = (0.060 kg)(12 m/s) = 0.72 kg•m/s, and the final momentum of the ball is p₂ = m₂v₂ = (0.060 kg)(-35 m/s) = -2.1 kg•m/s. Therefore, the change in momentum is Δp = p₂ - p₁ = -2.1 kg•m/s - 0.72 kg•m/s = -2.82 kg•m/s.

The law of conservation of momentum states that the total momentum of a closed system is conserved if there are no external forces acting on the system.

In this problem, the system consists of the tennis ball and Venus' racket, and since there are no external forces acting on the system, the initial momentum of the ball must be equal to the final momentum of the ball and racket system.

The force calculated in part b is negative because it is in the opposite direction to the motion of the ball. The negative sign indicates that the force is acting in the direction opposite to the motion of the ball.

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The wavelength of the graph is 2 m (option B)

Wavelength is defined as the distance between two successive crest or trough of a wave.

However, a crest is the point of maximum value of upward displacement while the trough is the minimum or lowest point in the wave displacement.

Now, we shall determine the wavelength of the graph. Details below:

Wavelength = Trough 2 - trough 1

Wavelength = 3 - 1

Wavelength = 2 m

Thus, the wavelength is 2 m (option B)

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When 2750 J of heat are delivered to 85.45 g of iron, the resultant temperature change is 17.6 °C.

first rule. The law of conservation of energy has been thermodynamically modified to form the first law of thermodynamics. The conservation law states that energy can only be transformed from one form to another, not created or destroyed, which keeps the total energy of an isolated system constant.

q = mcΔT

where T is the temperature change, q is the heat energy, m is the mass, c is the specific heat capacity.

0.45 J/g°C is the specific heat capacity of iron. We can plug in the values given in the problem to find the temperature change:

q = mcΔT

2750 J = (85.45 g)(0.45 J/(g·°C))(ΔT)

ΔT = 17.6 °C

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V = I R      or     I = V / R

I = 25 / 45 amps = .56 amps

The initial pressure to final pressure ratio is 0.789.

An ideal gas's volume must fall by if its pressure is raised by 10% at constant temperature. If an ideal gas's pressure is raised at constant temperature. At constant temperature, when a gas's pressure is increased by 5%.

P1V1/T1 = P2V2/T2

Since the volume of the gas is fixed in this problem, we can simplify the equation to:

P1/T1 = P2/T2

We are given that P1 = 1 atmosphere and T1 = 0°C = 273.15 K, and we need to find the ratio P1/P2. We can rearrange the equation to solve for P2:

P2 = P1 × T2 / T1

We are also given that T2 = 73°C = 346.15 K and P2 = 10 atmospheres, so we can substitute these values into the equation and solve for P1/P2:

P1/P2 = T1/T2 × P2/P1

P1/P2 = 273.15 K / 346.15 K × 10 atm / 1 atm

P1/P2 = 0.789

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The magnitude of the magnetic field is 1.50 x 10^-3 T.

The force on a charged particle moving through a magnetic field is given by the equation:

F = qvB sin(theta)

where F is the force, q is the charge on the particle, v is the velocity of the particle, B is the magnetic field strength, and theta is the angle between the velocity vector and the magnetic field vector.

In this case, the electron is moving in a circular arc, which means that the force on the electron is directed inward toward the center of the circle, and is equal to the centripetal force:

F = mv^2 / r

where m is the mass of the electron, v is the velocity of the electron, and r is the radius of the circular arc.

We can equate these two forces and solve for the magnetic field strength:

mv^2 / r = qvB sin(theta)

Simplifying and rearranging:

B = mv / (qr) * 1/sin(theta)

To find the velocity of the electron, we can use the equation for the kinetic energy of a charged particle:

KE = 1/2 mv^2 = qV

where KE is the kinetic energy of the electron, q is the charge on the electron, and V is the potential difference that the electron was accelerated through.

Solving for v:

v = sqrt(2qV/m)

Plugging in the given values:

V = 20,000 V

m = 9.11 x 10^-31 kg

q = -1.6 x 10^-19 C

v = sqrt(2(-1.6 x 10^-19 C)(20,000 V) / 9.11 x 10^-31 kg) = 2.43 x 10^7 m/s

Now we can plug in the values for m, q, v, r, and theta (which is 90 degrees since the velocity vector is perpendicular to the magnetic field vector) to find the magnetic field strength:

B = (9.11 x 10^-31 kg)(2.43 x 10^7 m/s) / ((-1.6 x 10^-19 C)(0.12 m)) * 1/sin(90 degrees) = 1.50 x 10^-3 T

Therefore, the magnitude of the magnetic field is 1.50 x 10^-3 T.

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The vectors are defined as an object containing both magnitude and direction. Vector describes the movement of an object from one point to another.the angle of A and B is θ = cos⁻¹  ((n²- 1)/(n²+ 1)  ).

A vector's magnitude is defined as the length of a segment of a directed line, and the vector's direction is indicated by the angle at which the vector is inclined. A vector has a "Tail" (the point from which it begins) and a "Head" (the point from which it ends).A mathematical structure is known as a vector. In the fields of physics and geometry, it has numerous applications. We are aware that an ordered pair, like (x, y). In the process of simplifying three-dimensional geometry, the vector is a very helpful tool.

∣A+B∣=n∣A−B∣

⟹(A² + B²  +2AB cos θ)=n2 (A² + B²  - 2AB cos θ )

It is given that A+B

Hence cos θ=  (n²- 1)/(n²+ 1)

θ = cos⁻¹   ((n²- 1)/(n²+ 1)  )

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Answer:

the circle on left shows the needle to the right (north pole). the circle on the right shows the needle to the right again.

Explanation:

the needle always goes to north

The area of the input and load piston is [tex]7.07 cm^2[/tex] and [tex]452.16 cm^2[/tex], the ratio of the area of the load to the input piston is 63.95, the weight of the car is 16,660N, the force must be applied to the input is 260.15N.

Given the diameter of hydraulic jack (d1) = 3cm

The diameter of load piston of jack (d2) = 24cm

The mass of jack that is being used to lift a car (m) = 1700 kg.

We know that pressure is calculated as force per unit area such that: P = F/A where F is force applied and A is area

(a)Let  The area of the input piston is = A1

Then [tex]A1 = \pi r1^2 = \pi * (d1/2 cm)^2 = \pi * (1.5)^2 = 7.07 cm^2.[/tex]

Let The area of the load piston is = A2

Then [tex]A2 = \pi r2^2 = \pi * (d2/2)^2 = \pi * (12 cm)^2 = 452.16 cm^2.[/tex]

(b) The ratio of the area of the load to the area of the input piston = A2/A1

ratio = 452.16 / 7.07 = 63.95

(c) The weight of the car in newtons is W = mg

[tex]W = 1700 kg * 9.81 m/s^2 = 16,660N.[/tex]

(d) The force must be applied to the input piston to support the car = F1

The force applied at the load piston = F2 = W

We know that pressure exerted at both ends of piston is same, so P1 = P2 such that P1 = F1/A1 and P2 = F2/A2

F1 = F2 * A1/A2 = 16,660/63.95 = 260.15N

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Answer:

Let's represent the magnitude of both vectors A and B using the variable "m".

According to the problem statement, we have:

|A| = |B| = m

|A+B| = 3|A-B|

Squaring both sides, we get:

|A+B|^2 = 9|A-B|^2

Expanding the left-hand side using the dot product formula, we have:

(A+B)·(A+B) = A·A + 2A·B + B·B

Similarly, expanding the right-hand side, we have:

9(A-B)·(A-B) = 9A·A - 18A·B + 9B·B

Substituting the given magnitudes, we have:

(A+B)·(A+B) = 2m^2 + 2(A·B)

9(A-B)·(A-B) = 18m^2 - 18(A·B)

Substituting these expressions back into the original equation, we get:

2m^2 + 2(A·B) = 9(18m^2 - 18(A·B))

Simplifying and rearranging, we get:

20(A·B) = 323m^2

Dividing by |A|·|B| = m^2, we have:

20(cosθ) = 323

where θ is the angle between vectors A and B. Solving for θ, we get:

θ = cos⁻¹(323/20)/π * 180

θ ≈ 83.4 degrees

The solution is D It is possible to simultaneously send and receive radio broadcasts on a variety of frequencies.

This is so that electromagnetic wavelengths, such as radio waves, can flow through one another without interfering with one another.

Electromagnetic waves: what are they?

A type of wave called an electromagnetic wave is made up of oscillating electric and magnetic fields that move through space.

They are sometimes referred to as electromagnetic radiation or EM waves.

What other instances of electromagnetic energy?

Electromagnetic waves, for instance, include:

the gamma rays

Waves of light

- Radio waves (which are used in communications)

- X-rays

- Infrared and ultraviolet rays (accompanied by Sun rays)

- Waves used in radio and television.

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Hello and regards emmateddyafton94.

The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².

It is an exercise in rectilinear motion uniformly accelerated (MRUA) is a type of movement in a straight line in which an object moves with a constant acceleration. This type of movement is common in everyday life, such as when an object falls due to the force of gravity or when a car moves in a straight line and accelerates at a constant speed.

In the MRUA, the speed of the object changes at a constant rate in each unit of time. This means that acceleration is the amount of change in velocity that occurs in each second, and it is constant throughout the motion. Acceleration is measured in units of length per unit of time squared (for example, meters per second squared).

The fundamental formula of the MRUA is:

Where:

We now know that the data is:

But since they are asking us to calculate the acceleration, we clear the formula:

Where:

This formula shows that the acceleration is equal to the difference between the final velocity and the initial velocity of the object, all divided by the elapsed time. It is important to note that final velocity and initial velocity must be in the same units (for example, meters per second) and that time must be in units of time (for example, seconds).

We substitute data in the formula, and calculate the acceleration:

a = (Vf - V₀)/t

a = (10 m/s - 2 m/s)/(4 s)

a = 2 m/s²

The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².

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Answer:

The lizard's average acceleration is 2 m/s².

Explanation:

The average acceleration of the lizard can be calculated using the formula:

[tex]\sf\qquad\dashrightarrow a = \dfrac{(V_f - V_o)}{t}[/tex]

where:

Plugging in the given values, we get:

[tex]\sf\qquad\dashrightarrow a = \dfrac{(10\: m/s - 2\: m/s)}{4\: sec}[/tex]

[tex]\sf\qquad\dashrightarrow a = \boxed{\bold{\:\:2\: m/s^2\:\:}}[/tex]

Therefore, the lizard's average acceleration is 2 m/s².

The y-component of the vector is approximately 9.029 m.

In order to determine the y-component of this vector, we must first acknowledge that the information provided is a polar form of the vector, with 12.1 m representing its magnitude and 48.4° representing its angle with the positive x-axis.

The formula for this vector's y-component is as follows:

y = r sin θ

where r is the magnitude of the vector and θ is the angle that the vector makes with the positive x-axis.

In this case, r = 12.1 m and θ = 48.4°, so we have:

y = 12.1 m * sin(48.4°)

y ≈ 9.029 m

Therefore, the y-component of the vector is approximately 9.029 m.

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