a man on rupees 15000 in a month. he spends rupees 3000 on food rupees 4000 on rent rupees 2000 on its children's education and the rest he saves in a bank
(I) Express separately the expenditure on food rent and education in percent
(ii) what is his savings percent every month



i will give brainliest who solves more clearly for me​

Step-by-step explanation:

did you give us all the information ? the equating looks cut off.

so, from what I can see we have

9(y-4) - 3y = 2(3y-2)

let's try :

9y - 36 - 3y = 6y - 4

0 = 32

so, no, this can't be it. this does not have a solution. you must have cut off some additional information.

Answer:V=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

12v+10v+14=80

(12v+10v)+(14)=80

(Combine Like Terms)

22v+14=80

22v+14=80

Step 2: Subtract 14 from both sides.

22v+14−14=80−14

22v=66

Step 3: Divide both sides by 22.

22v/22=66/22

V=3

:)

Step-by-step explanation:

y=107(vertically opposite angles)

x=180-107=73(angles on a straight line)

z=73(vertically opposite angles)

Answer:

[tex]{ \sf{y = 107 \degree}} \: \{ \sf{alternate \: angles} \}[/tex]

[tex]{ \sf{z + 107 \degree = 180 \degree}} \: \{ \sf{straight \: line \: angles \}} \\ z = 180\degree - 107\degree \\ z = 73\degree[/tex]

[tex]{ \sf{x = z}} \: \{ \sf{alternate \: angle \}} \\ x = 73\degree[/tex]

9514 1404 393

Answer:

  63

Step-by-step explanation:

We observe that multiply the smaller number in the ratio by 7 we get 35. Then the ratio is ...

  5 : 9 = 35 : 63 . . . . . . multiply both numbers by 7

The larger number is 63.

Answer:

Step-by-step explanation:

Answer:

here

I =p×t×r/100

= 24000×2×10/100

= 4800

again,

sum = p+I

= 24000+4800

= 28800

Answer:

(0,-5)

Step-by-step explanation:

4x-2(-2x-5)+10

x=0

y=-2*0-5

y=-5

24 - (5 - 3)⁴ = 24 - 2⁴ = 24 - 16 = 8

8 : 4 = 2 ← the end solution

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Answer:

Step-by-step explanation:

Let b and c represent the rates of the boat and current, respectively. Then the upstream rate is ...

  speed = distance/time

  b -c = (116 km)/(4 h) = 29 km/h

  b +c = (164 km)/(4 h) = 41 km/h

Adding these equations gives ...

  2b = 70 km/h

  b = 35 km/h

Substituting into the first equation, we have ...

  35 -c = 29

  c = 6

Rate of the boat: 35 km/h.

Rate of the current: 6 km/h

Answer:

t < 9

Step-by-step explanation:

12 > t + 3

We can subtract 3 from both sides getting us 9 > t.

Answer:

c = 722

Step-by-step explanation:

-19/c = 38

c = 38 x 19 (positive)

c = 722

hope it helped !

Answer:

46.5 hours per week

Step-by-step explanation:

At least 550 a week.

Which is 1\4 of Bronwyn salary.

550 x 4 = 2200

To find minimum work hours

2200-28 = 2172

2172 \ 47 = 46.212 hours per week

So, bronwyn needs to work at least 46.5 hours per week

Answer:

Bronwyn must work nearly 47 hours each week to achieve her goal.

Step-by-step explanation:

Let x be the number of hours Bronwyn works per week.

If Bronwyn earns $47 per hour, if x is the number of hours she works per week and if Bronwyn earns $28 per week because she declined company benefits, lets assume that the left hand side of the equation is:

[tex]47x + 28[/tex]

Now onto the salary. Since Bronwyn wants to save $550 each week and since she also wants to save one quarter of her salary, her salary becomes $2200 for each week she works

Making the equation...

[tex]47x + 28 = 2200[/tex]

Time to solve for x

[tex]47x = -28 + 2200\\47x = 2172\\x = 46.2[/tex]

Since its at least, you can round it up to 47 making 47 the number of hours she must work each week to achieve her goal.

Step-by-step explanation:

steps are in picture above.

if you need to ask questions I'll give you answers gladly.

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]y = -2x + 3[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Slope-Intercept Form Is:}}\\\\y=mx + b\\---------------\\\boxed{\text{Key:}}\\\\m - slope\\b - y-intercept\\---------------\\\boxed{\text{\underline{Known Information:}}}\\\\\rightarrow \text{We are given the points: } (0,3) \text{ and } (2, -1)\\---------------\\\boxed[/tex]

[tex]\boxed{\text{\underline{Y-Intercept:}}}\\\\\rightarrow \text{Since the line passes at point (0, 3), the y-intercept would be 3.}\\---------------\\\boxed{\text{\underline{Slope:}}}\\\\\rightarrow m =\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1} \\\\\rightarrow m = \frac{-1-3}{2-0}=\frac{-4}{2}=\boxed{-2}\\\\\text{The slope is: } \boxed{-2}\\---------------[/tex]

[tex]\boxed{\text{\underline{Equation:}}}\\\\\text{Our equation should be:}\\\\y = -2x + 3[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.

Answer:

x = 7

Step-by-step explanation:

[tex]8x-3=11+6x\\\\2x-3=11\\\\2x=14\\\\x=7[/tex]

Answer:

x = 7

Step-by-step explanation:

8x - 3 = 11 + 6x

8x - 3 + 3 = 11 + 6x +3

8x = 6x + 14

8x - 6x = 6x + 14 - 6x

2x = 14

2x/2 = 14/2

x = 7

The critical points of h(x,y) occur wherever its partial derivatives [tex]h_x[/tex] and [tex]h_y[/tex] vanish simultaneously. We have

[tex]h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5[/tex]

Substitute y in the second equation and solve for x, then for y :

[tex]2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}[/tex]

This is to say there are two critical points,

[tex](x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)[/tex]

To classify these critical points, we carry out the second partial derivative test. h(x,y) has Hessian

[tex]H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}[/tex]

whose determinant is [tex]192y-16[/tex]. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and [tex]h_{xx}[/tex] are positive at the point, then it's a local minimum

• if the determinant is positive and [tex]h_{xx}[/tex] is negative, then it's a local maximum

• otherwise the test fails

We have

[tex]\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0[/tex]

while

[tex]\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0[/tex]

So, we end up with

[tex]h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}[/tex]

I think the answer you are looking for is 7n, which also means 7 times n.

Answer:

7x

Step-by-step explanation:

Product refers to multiplication. "A number" refers to an unknown number otherwise known as a variable. In this case, I use x.

Answer:

2

Step-by-step explanation:

Answer:

place value of 2 is 100

Step-by-step explanation:

please brainleist my answer

Answer:

The place value of 2 in 6.253 is 200

Step-by-step explanation:

Place value of 2 is occurring in hundreds

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

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Answer:

  10, -1

Step-by-step explanation:

If you assume the numbers are integers, you can look at the factor pairs that make -10:

  -10 = 10(-1) = 5(-2) = 2(-5) = 1(-10)

The sums of these pairs are 9, 3, -3, -9, so the pair of interest is the first one:

  10, -1

Step-by-step explanation:

we can also write them as,

Now, from -a²-2ab-b² if we take - as common term then we get,

Now, by using the concept of a²+2ab+b²=(a+b)²

I hope it helped U

stay safe stay happy

Answer:

Decimal Fraction Percentage

0.101 101/1000 10.1%

0.1 100/1000 10%

0.1013 101/997 10.13%

0.1012 101/998 10.12%

Step-by-step explanation:

Sea level is 0

1000 feet below sea level would be -1000. It rises 450 feet. Add 450 to -1000:

-1000 + 450 = -550

The submarine is at -550 feet ( 550 feet below sea level).

Distance = (Rate)(Time)

Let x = speed of slower train

     x + 17 = speed of faster train

The trains meet when the sum of the distances = 1285

5x + 5(x+17) = 1285

(5 came from 5 hours)

10x + 85 = 1285

10x = 1200

 x = 120 mph

The speeds are 120 mph and 137 mph

wyzant

Step-by-step explanation:

Janyce's rule doesn't work. In the case where n = 3 her rule predicts that there will be 3(3) - 1 = 8 squares but instead, there are 10 squares. Likewise, for n = 4, there are 17 squares instead of 11 that she predicted. Instead, I propose the rule [tex]n^2 + 1.[/tex] It works for all the figures shown and mostly likely, for all other values of n.

2. Part A;

Given that the number of squares obtained using Janyce conjecture for

figures 3 and 4 which are 8 and 11 squares respectively and the number of

squares in the diagram for figures 3 and 4 which are 10 and 17 squares

respectively are not the same, disproves Janyce conjecture

Part B:

The rule for the number of squares in the nth squares is n² + 1

The reasons the above conclusion and rule are correct is as follows:

2. Part A

The given number of squares in each figure are;

[tex]\begin{array}{|c|c|c|}\mathbf{Figure \ number}&\mathbf{Number \ of \ squares} &\mathbf{Janyce \ conjecture \ (3\cdot n - 1)}\\&&\\1&2 \ squares &(3 \times 1 - 1 = 2) \ squares \\2&5 \ squares&(3 \times 2 - 1 = 5) \ squares\\3&10 \ squares &(3 \times 3 - 1 = 8) \ squares\\4&17 \ squares&(3 \times 4 - 1 = 11) \ squares\end{array}[/tex]

Given that the number squares in figure 3, and 4 are;

Figure 3 = 10 squares

Figure 4 = 17 squares

Janyce conjectured number of squares are;

Figure 3 = 8 squares

Figure 4 = 11 squares

The values for the number of squares in the diagram in figures 3 and 4 are different from Janyce conjecture which disproves Janyce's conjecture for the number of squares in the nth figure

Part B

From the diagrams, we have;

The number of squares on the each figure is given by a square shape with a side length equal to the figure number of squares plus one extra square at the top right end corner, we have;

The area of the square part of the shape = n² = The number of squares in the square shape

The number of squares in the nth figure = n² + 1

Verifying, we have;

Figure 1 = (1² + 1) squares = 2 squares (Same as in diagram)

Figure 2 = (2² + 1) squares = 5 squares (Same as in diagram)

Figure 3 = (3² + 1) squares = 10 squares (Same as in diagram)

Figure 4 = (4² + 1) squares = 17 squares (Same as in diagram)

Therefore;

The correct formula for the number of squares in the nth figure = n² + 1

Learn more about the nth term of a sequence here:

https://brainly.com/question/12998719

https://brainly.com/question/15325765

https://brainly.com/question/21493252