Answer:
83.6%
Explanation:
(a)On its current schedule, the plant can theoretically produce ...
(30 pc/h/machine)(10 machine)(8 h/shift)(2 shift/day)(5 day/wk)(50 wk/yr)
= (30)(10)(8)(2)(5)(50) pc/yr = 1,200,000 pc/yr
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(b)On the proposed schedule, this production becomes ...
(30 pc/mach)(10 mach)(8 h/sh)(3 sh/da)(6 da/wk)(51 wk/yr)
= (30)(10)(8)(3)(6)(51) pc/yr = 2,203,200 pc/yr
The increase in capacity is ...
(2,203,200/1,200,000 -1) × 100% = 83.6% . . . capacity increase
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Additional comment
The number of parts per shift did not change. Only the number of shifts per year changed. It went up by a factor of (3/2)(6/5)(51/50) = 1.836. Hence the 83.6% increase in capacity.
We have to assume that maintenance and repair are done as effectvely as before in the reduced down time that each machine has.
What type of cartilage provides support and shock absorption?.
Answer:
fibrocartilage
Explain and show work:
Calculate (413,465,789 mod 6), giving an answer between 0 and 5, and using a small number of steps. Show your steps.
Answer:
5
Explanation:
The sum of the digits of the number is ...
(4+1+3)+(4+6+5)+(7+8+9) = 8+15+24 = 47
The sum of those digits is 4+7=11, and those digits sum to 1+1 = 2.
That is, the value of the number mod 9 (or 3) is 2.
The ones digit is odd, so the value of the number mod 2 is 1.
This combination of modulo values tells you the mod 6 result is 5.
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Additional comment
We can look at the (mod2, mod3) values of the numbers 0 to 5:
0 ⇒ (0, 0)
1 ⇒ (1, 1)
2 ⇒ (0, 2)
3 ⇒ (1, 0)
4 ⇒ (0, 1)
5 ⇒ (1, 2) . . . . the mod {2, 3} results we have for the number of interest.
This process of adding up the digits repeatedly is referred to as "casting out 9s." The result of it is the modulo 9 value of the number (with 0 mapped to 9). Checking the mod 9 result of arithmetic operations is one quick way to spot certain kinds of errors. It can also be used as part of a divisibility test for 3 or 9.
The machine language file is loaded onto the robot where the files can run test written as part of the program called __________________.
Answer:
C++ and Python
Explanation:
C++ and Python
NEED HELPASAP what is the moisture content of a board if a test sample that originally weighed 11. 5 oz was found to weigh 10 oz after oven drying?
Answer:
11.5-10/10= 0.15x100 =15%
Explanation:
The moisture content of the board is 13.04% as per the given data.
What is moisture content?Simply said, a product's moisture content is its water content. It affects a substance's weight, density, viscosity, conductivity, and other physical characteristics.
The original weight of the test sample was 11.5 oz, and the weight of the sample after oven-drying was 10 oz.
The amount of moisture lost during the oven-drying process is equal to the original weight of the sample minus the weight of the sample after drying, or:
11.5 oz - 10 oz = 1.5 oz
To calculate the moisture content, you then divide the amount of moisture lost by the original weight of the sample and multiply by 100 to express the result as a percentage:
(1.5 oz / 11.5 oz) x 100% = 13.04%
Thus, the moisture content of the board is 13.04%.
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