A side of the triangle below has been extended to form an exterior angle of 127°. Find
the value of x.
17°
xº
127°

Answer:

4+4+x+3-4=12

8+x-1=12

7+x=12

x=12-7

=5

answer is 5

Answer:

48

Step-by-step explanation:

because 20% of 240 is 48.

Answer:

1.02 1.25 1.50 1.52.

Step-by-step explanation:

|•-•|

Answer:

1.02

1.25

1.5

1.52

Step-by-step explanation:

:)

Answer:

15/4

Step-by-step explanation:

2 1/2 x 1 1/2

First, make them both improper fractions to make them easier to multiply

5/2 x 3/2

Multiply their numerators together to get the numerator and multiply their denominators together to get the denominator.

5 x 3 = 15

2 x 2 = 4

5/2 x 3/2 = 15/4

The platonic solids in the given options are A. Regular pentagons and E. Equilateral triangles.

The solids that are polyhedrons, all of whose faces are congruent regular polygons and at every vertex, the same number of faces meets are called "Platonic solids"

There are only five types of platonic solids. They are:

The major types of faces that are found on platonic solids are:

Regular polygons with more than 6 sides are not the faces of the platonic solid.

Thus, from the given shapes,

A. regular pentagons, E. equilateral triangles are used as faces of a Platonic solid.

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Answer:

-4,-3,-2,-1,0,1

Step-by-step explanation:

First, doublepound and simplify it.

-15<3n

3n<6

Solve:

-5<n

n<2

Compound:

-5<n<2.

So the values are -4,-3,-2,-1,0,1

Hope this helps plz hit the crown :D

Answer:

The values of 'n' such that -15 < 3n ≤ 6 will be:

[tex]-5<n\le \:2[/tex]

[tex]-5<n\le \:2[/tex] can also be represented as: -4, -3, -2, -1, 0, 1, 2

Hence, the values of integer n will be:

Thus,

[tex]-15<3n\le \:6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-5<n\le \:2\:\\ \:\mathrm{Interval\:Notation:}&\:(-5,\:2]\end{bmatrix}[/tex]

The line graph is also attached below.

Step-by-step explanation:

Given the expression

-15 < 3n ≤ 6

Lets us solve the inequality for n

[tex]-15<\:3n\le \:6[/tex]

Divide all parts by n

[tex]\:-\frac{15}{3}<\frac{3n}{3}\le \frac{6}{3}[/tex]

simplify

[tex]-5<n\le \:2[/tex]

Therefore, the values of 'n' such that -15 < 3n ≤ 6 will be:

[tex]-5<n\le \:2[/tex]

[tex]-5<n\le \:2[/tex] can also be represented as: -4, -3, -2, -1, 0, 1, 2

Hence, the values of integer n will be:

Thus,

[tex]-15<3n\le \:6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-5<n\le \:2\:\\ \:\mathrm{Interval\:Notation:}&\:(-5,\:2]\end{bmatrix}[/tex]

The line graph is also attached below.

Answer:

Where is the pic?

Step-by-step explanation:

There 650 million CDs were sold in 2006 if there were 800 million  CDs sold in 2002, and there were 700 million  CDs in 2005 option (D) is correct.

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

If in the linear equation one variable is present then the equation is known as the linear equation in one variable.

From the graph:

(2002, 800) and (2005, 700)

We can draw a line for the best fit as follows:

[tex]\rm (y-800) = \frac{700-800}{2005-2002}(x-2002)[/tex]

[tex]\rm (y-800) = 33.33(x-2002)[/tex]

When x = 2006

[tex]\rm (y-800) = -33.33(2006-2002)\\[/tex]

y = 666.68

Which is near 650 million

Thus, there 650 million  CDs were sold in 2006 if there were 800 million  CDs sold in 2002, and there were 700 million  CDs in 2005 option (D) is correct.

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Answer:

I'd assume inches, hope this helps!

Answer:

18

Step-by-step explanation:

[tex]2 {a}^{2} = 2 {(3)}^{2} = 2 \times 9 = 18 \\ [/tex]

Answer:

36

Step-by-step explanation:

2 times 3=6 6^2 is 6 times 6

Answer:

0,3 hddjbdhfjdndjdkdbdjdnd

Answer:

Given

Solving for x

Both sides are equal, any value of x is a solution, so infinitely many solutions

Step-by-step explanation:

[tex]5(2x - 3) = x - 15 + 9x \\ 10x - 15 = 10 x - 15[/tex]

Both the sides are equal

Hence no specific value of x

Therefore, x has infinite value.

Answer:

pqe?

Step-by-step explanation:15446556

Answer:

=23x−55

Step-by-step explanation:

Let's simplify step-by-step.

4(2x−5)+5(3x−7)

Distribute:

=(4)(2x)+(4)(−5)+(5)(3x)+(5)(−7)

=8x+−20+15x+−35

Combine Like Terms:

=8x+−20+15x+−35

=(8x+15x)+(−20+−35)

=23x+−55

Answer:

22x-55

pemdas works too i guess

Answer:

200 patients

Step-by-step explanation:

60% = 120

100% = ?

100×120 = 12000÷60= 200

Zg is a measure of weight

Hey there!

Your lines EF and FG has the measure of 6 ✅

One of the triangle(s) has both sides equivalent lengths which is the isosceles triangle

Since pretty much every is most likely “equivalent” it’ll be an isosceles triangle

∠E ≅ ∠ G

∠E = 28° so that means ∠G = 28°

Answer: ∠G = 28° (Option D.)

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

Answer:

x=3

y=4

Step-by-step explanation:

I'm using 3x+y=13 to find y, then plug y into the second equation.

y= -3x+13

5x-2(-3x+13)=7

find x.

5x+6x-26=7

11x=33

x=3

now plug x into 3x+y=13(you could do it with the other equation too)

3(3)+y=13

y=13-9

y=4

The value of x and y is 3, and 4 respectively by the substitution method.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have a system of equations;

3x +y=13 ...(1)

5x-2y=7​ ...(2)

By using the substitution method.

[tex]\rm 5\cdot \dfrac{13-y}{3}-2y=7[/tex]

y = 4

Plug y = 4 in equation (1)

3x + 4 = 13

x = 3

Thus, the value of x and y is 3, and 4 respectively by the substitution method.

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Answer:

a

Step-by-step explanation:

Answer:

756 ways

Step-by-step explanation:

Given

[tex]Counters = 28[/tex]

[tex]Selection = 2[/tex]

Required

Determine the number of ways

The first counter can be selected in 28 ways

The second can be selected in (28 - 1) ways

The number of selection is:

[tex]Selection = 28 * (28 -1)[/tex]

[tex]Selection = 28 * 27[/tex]

[tex]Selection = 756[/tex]

Hence, number of possible selection is 756

Answer:

E

Step-by-step explanation:

We are given:

[tex]\ln(xy)=x-y[/tex]

And we want to find the second derivative at the point (1, 1).

So, we will take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}\big[\ln(xy)\big]=\frac{d}{dx}\big[x-y\big][/tex]

Implicitly differentiate. The left will require the chain rule. Hence:

[tex]\displaystyle \frac{1}{xy}\cdot \frac{d}{dx}\big[xy\big]=1-\frac{dy}{dx}[/tex]

Differentiate:

[tex]\displaystyle \frac{1}{xy}\cdot \big( y+x \frac{dy}{dx} \big) =1-\frac{dy}{dx}[/tex]

Distribute:

[tex]\displaystyle \frac{1}{x}+\frac{1}{y}\frac{dy}{dx}=1-\frac{dy}{dx}[/tex]

Isolate the derivative term:

[tex]\displaystyle \frac{dy}{dx}\big(\frac{1}{y}+1\big)=1-\frac{1}{x}[/tex]

Divide:

[tex]\displaystyle \frac{dy}{dx}=\frac{1-\frac{1}{x}}{\frac{1}{y}+1}}[/tex]

Simplify. We can multiply both layers by xy. Hence:

[tex]\displaystyle\begin{aligned} \frac{dy}{dx}&=\frac{1-\frac{1}{x}}{\frac{1}{y}+1}}\cdot\frac{xy}{xy} \\ &=\frac{xy-y}{x+xy} \end{aligned}[/tex]

We can factor. Hence, our derivative is:

[tex]\displaystyle \frac{dy}{dx}=\frac{y(x-1)}{x(y+1)}[/tex]

Differentiate once more to find the second derivative:

[tex]\displaystyle \frac{d^2y}{dx^2}=\frac{d}{dx}\Big[\frac{y(x-1)}{x(y+1)}\Big][/tex]

Quotient rule:

[tex]\displaystyle \frac{d^2y}{dx^2}=\frac{\frac{d}{dx}[y(x-1)](x(y+1))-y(x-1)\frac{d}{dx}[x(y+1)]}{(x(y+1))^2}[/tex]

Differentiate using the product rule:

[tex]\displaystyle \frac{d^2y}{dx^2}=\frac{ \big[\frac{dy}{dx}(x-1)+y\big](x(y+1))-y(x-1)\big[(y+1)+x\frac{dy}{dx}\big] }{(x(y+1))^2 }[/tex]

You may choose to simplify, but this is not necessary, as we are only interested in the second derivative at (1, 1).

First, since first derivatives exist in our second derivative, we will find them first. Recall that the first derivative is given by:

[tex]\displaystyle \frac{dy}{dx}=\frac{y(x-1)}{x(y+1)}[/tex]

Therefore, at (1, 1), the first derivative is:

[tex]\displaystyle \frac{dy}{dx}_{(1, 1)}=\frac{1(1-1)}{1(1+1)}=\frac{1(0)}{1(2)}=0[/tex]

So, we will substitute 0 for every dy/dx for our second derivative. Thus:

[tex]\displaystyle \frac{d^2y}{dx^2}=\frac{ \big[(0)(x-1)+y\big](x(y+1))-y(x-1)\big[(y+1)+x(0)\big] }{(x(y+1))^2 }[/tex]

Simplify:

[tex]\displaystyle \frac{d^2y}{dx^2}=\frac{ y(x(y+1))-y(x-1)\big[(y+1)\big] }{(x(y+1))^2 }[/tex]

So, at the point (1, 1), our second derivative is:

[tex]\displaystyle \frac{d^2y}{dx^2}_{(1, 1)}=\frac{1(1(1+1))-1(1-1)(1+1)}{(1(1+1))^2}=\frac{2-0}{4}=\frac{1}{2}[/tex]

Hence, our final answer is E.

Answer:

1. 0.34

2. 0.46

3. 0.75

4. 0.3 with a bar over 3

5. 0.63 with a bar over 63

6. 0.259 with a bar over 259

7. 0.1875

8. 0.35

Answer:

I think option B is correct

Vertex form:

y = 5  (x - 1)^2 - 80

Standard Form:

y = 5x^2 - 10x - 75

Answer:

55

Step-by-step explanation:

6.5x - 3.5 [x = 9]

6.5(9) - 3.5

58.5 - 3.5 = 55

Answer:

The frequency increases as the pitch increases, and the amplitude increases as the volume increases

Step-by-step explanation:

Answer:

B, C, A

Step-by-step explanation:

A = |7| = 7

B = -6

C = |-5| = 5

Order: B, C, A

Answer:

he equation of the line is parallel to the given line and passing through the point C( 1,4) is        x - 8 y + 31=0

slope intercept form

                     [tex]y = \frac{x}{8} + \frac{31}{8}[/tex]

Step-by-step explanation:

Explanation:-

Given equation of the line  

                                y = 1/8x-4

                               8 y = x - 32

                         x - 8 y -32=0

The equation of the line is parallel to the given line a x + b y + k=0

                                                                                   x - 8 y + k=0

This line is passing through the point ( 1,4)

             x - 8 y + k=0

             1 - 32 + k =0

                  k = 31

The equation of the line is parallel to the given line and passing through the point C( 1,4) is        x - 8 y + 31=0

slope intercept form

                         8 y = x + 31

                          [tex]y = \frac{x}{8} + \frac{31}{8}[/tex]

Answer:

Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there is 1 number to the right of the decimal point, place the decimal number over 101 (10)

. Next, add the whole number to the left of the decimal.

4 5/10

Reduce the fractional part of the mixed number.

4 1/2

Reduce the fraction.

9/2

Step-by-step explanation: