Answer:
a) the modulus of elasticity (E) is 68.22 GPa
b) the modulus of elasticity in shear is 25.28 GPa
Explanation:
Given the data in the question;
First we determine the cross-sectional area A of the road;
A = π/4 × d²
given that; diameter d = 20 mm
we substitute
A = π/4 × ( 20 mm )²
A = π/4 × 400 mm
A = 314.159 mm²
Next, we find, the normal stress of the rod σ
σ = P / A
given that load p = 50 kN = 50,000 Newton
we substitute
σ = 50,000 N / 314.159 mm²
σ = 159.155 N/mm²
σ = 159.155 Mpa
Next, is the normal strain ε
ε = δ / L
given that; change in length δ = 1.40 mm and Length of rod L = 600 mm
we substitute
ε = 1.40 mm / 600 mm
ε = 0.002333
Now, we find the modulus of elasticity;
we know that;
σ = Eε
modulus of elasticity E = σ / ε
we substitute
E = 159.155 Mpa / 0.002333
E = 68219.031 MPa
E = ( 68219.031 / 1000 ) GPa
E = 68.22 GPa
Therefore, the modulus of elasticity (E) is 68.22 GPa
b)
we know that the Poisson's ratio v is;
v = -(ε[tex]_{lat[/tex] / ε )
v = - (((d[tex]_f[/tex] - d)/d) / ε )
where d[tex]_f[/tex] is the final diameter of the rod ( 19.9837 mm ) and ε[tex]_{lat[/tex] is the lateral strain
so we substitute
v = - ((( 19.9837 - 20 ) / 20 ) / 0.002333 )
v = - (( -0.0163 / 20 ) / 0.002333 )
v = - ( - 0.000815 / 0.002333 )
v = - ( - 0.3493 )
v = 0.3493
So, our shear modulus will be;
G = E / 2( 1 + v )
we substitute
G = 68.22 GPa / 2( 1 + 0.3493 )
G = 68.22 GPa / 2( 1.3493 )
G = 68.22 GPa / 2.6986
G = 25.28 GPa
Therefore, the modulus of elasticity in shear is 25.28 GPa
¿Con qué cualidad del sonido está relacionada la Amplitud de onda?
Answer:
Amplitud (dinámica)
Explanation:
La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.
The blending of the fundamental tone with overtones produces the __?__of an instrument.
Answer:
The blending of the fundamental tone with overtones produces the Sound Quality of Musical Instruments of an instrument.
The blending of the fundamental tone with overtones produces the sound quality of Musical Instruments of an instrument.
The tone of a sound wave determines the timbre, also known as timber, of the auditory impressions it creates. The wave structure of a sound, which varies with the amount of overtones, or harmonics, present, their frequencies, and their relative intensities, determines the timbre of the sound.Resonance is a common technique used by musical instruments to enhance sound waves and increase volume. When an object vibrates in response to sound waves of a particular frequency, this is known as resonance.What are tones and overtones?Aside from a simple sine wave, the fundamental tone and numerous additional tones of various frequencies make up the waveforms of all sounds. Overtones or harmonics are non-fundamental tones that are whole-number multiples of the fundamental tone.Learn more about sound quality of Musical Instruments brainly.com/question/9571788
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1. What does Louis de Broglie's principle propose about electrons?
They have energy and momentum.
They behave as a wave and a particle.
They contain high-energy and low-energy photons.
They interact with other electrons to form new substances.
Louis de Broglie's principle of electrons states that (b) They behave as a wave and a particle.
The de Broglie equation is one of the equations that is commonly used to define the wave properties of matter. It basically describes the wave nature of the electron.Electromagnetic radiation, exhibit dual nature of a particle (having a momentum) and wave (expressed in frequency, wavelength). Microscopic particle-like electrons also proved to possess this dual nature property.Louis de Broglie in his thesis suggested that any moving particle, whether microscopic or macroscopic will be associated with a wave character. It was called ‘Matter Waves’. He further proposed a relation between the velocity and momentum of a particle with the wavelength, if the particle had to behave as a wave.Particle and wave nature of matter, however, looked contradictory as it was not possible to prove the existence of both properties in any single experiment. This is because of the fact that every experiment is normally based on some principle and results related to the principle are only reflected in that experiment and not the other.To know more about electrons visit:
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What is the unit of work in SI system?
Answer:
Joule ;)
Explanation:
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.
Hope this helps!
Answer:
Explanation:
Joule
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.
What influences speed of an objects fall? (Choose as many as apply)
1. Sunlight
2. Air
3. Altitude
4. Heat
Altitude and Air
but mainly altitude, Air is just depending on the situation.
Air does not always influence an object's fall, but Altitude always influences it.
Which one has more momentum if they are all traveling at the same speed?
1. A basketball
2. A golf ball
3. A tennis ball
4. A bowling ball
Answer:
the answer is a bowling ball
What is the equivalent resistance of a 3.0 Ω resistor and a 6.0 Ω resistor connected in parallel?
Answer:
The equivalent resistance of a 3.0 Ω resistor and a 6.0 Ω resistor connected in parallel is 2.0 Ω.
Explanation:
(eopt)s. Find the power dissipated in a 25 r heater
connected to a 220V outer.
Answer:
P = 1936 W
Explanation:
Given that,
Voltage, V = 220 V
The resistance of the heater, R = 25 ohms
We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :
[tex]P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W[/tex]
So, the required power is equal to 1936 W.
What are the precautions for compound Pendulum experiment
Make sure you measure the length of the pendulum from the centre (of mass) of the plumbob.
Make sure the top edge is well defined- clamp the string between two blocks so it is clear where the string can move and where it cant.
Make sure the top support is fixed- eg a clamp stand can easily flex and so the top support moves.
Make sure you use small amplitudes ( less than 10 degrees from the vertical)
Make sure you time enough swings such that the total time is sufficeint to get the uncertainty in the timing of a single swing down. (It is the total time that is important not the number of swings)
Release the pendulum and start timing counting while it is swinging. Start the clock and say zero (not 1).
Have a pre-prepared results table so that you can record your results accurately without rushing.
Do at least 3 sets of readings to identify any anomalies.
Explanation:
A lawnmower is pushed with a force of 72 Newtons at an angle of 40 degrees from the horizontal. How much work is done to the mower if it moves 740 meters?
The work done to the mower is the product of the external force applied on the object and the distance covered by the object which is equal to 40,811 Joules.
What is Work done?Work done on an object can be defined as the product of external force applied on the object and the distance over which the force is being applied on the object. Work is done on an object when a force is applied to an object and the object is moved through certain distance.
From this we can see that the horizontal component of the force:
X-Component (horizontal component):
cos(θ) = x/F
Then,
X= F cos(θ).…..(1)
Now putting the values of F and θ in equation (1) we get,
X = 72 N × cos(40)
X = 72 N × 0.766
X= 55.15 N this is the x-component force
The work done to the mower is:
W = F × d
W = 55.15 × 740
W = 40,811 Joules
The work done to the mower is 40811 Joules.
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It is a “new moon” (the Moon is totally dark in the sky). Using the masses of the Earth, Sun, and Moon and the average distances between the Earth-Moon and Earth-Sun, find the net gravitational force on the Earth from the Sun and the Moon combined.
Find also distance when it is full moon
It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:
2.9 x 10^20 N3.5 x 10^22 N3.5 x 10^22 NWhat is gravitational force?Generally, The gravitational force between two objects is given by the equation:
force = G * (mass1 * mass2) / distance^2
Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.
The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.
The gravitational force between the Earth and the Moon is:
force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force
= 2.9 x 10^20 N
The gravitational force between the Earth and the Sun is:
force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force
= 3.5 x 10^22 N
To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.
Net force = 2.9 x 10^20 N + 3.5 x 10^22 N
= 3.5 x 10^22 N
When it is a Full Moon the distance is the same 384,400 km
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You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N O C. 75 N O D. 150 N
Answer:
150N
Explanation:
To find the force applied remember that force equals to Mass multiply by the Acceleration.
F=Ma
=30*5
=150N
Answer:
150N
Explanation:
F = m*a = 30 * 5 = 150 N
A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?
Answer:
vlarge = 4vsmall
Explanation:
Khan Academy
In a cloud chamber experiment, a proton enters a uniform 0.260 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.42 cm.
Required:
How fast was the proton moving?
Answer:
the proton speed of the proton was 1.6 × 10⁶ m/s
Explanation:
Given the data in the question;
Radius r = 6.42 cm = 0.0642 m
magnetic field B = 0.260 T
we know that; charge of proton q = 1.602 × 10⁻¹⁹ C
And mass of proton m = 1.672 × 10⁻²⁷ kg
we know that; Magnetic Force F = qvBsinθ
where q is the charge of proton, v is velocity, B is the magnetic field and θ is angle ( 90° )
Also the Centripetal force experienced by the particle is;
F = mv² / r
where r is radius, m is mass of proton and v is velocity
hence;
qvBsinθ = mv² / r
we solve for v
rqvBsinθ = mv²
divide both sides by mv
rqvBsinθ / mv = mv² / mv
rqBsinθ / m = v
so we substitute
v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] / 1.67 × 10⁻²⁷ kg
v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷
v = 1.6 × 10⁶ m/s
Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s
George is studying a mechanical wave. He counts thirty crests of the wave pass through a point in 10 seconds.
If What is the frequency of this wave?
Select one:
2 Hz.
20 Hz.
3 Hz.
30 Hz.
Answer:
Option C
Explanation:
Frequency determines the number of waves that pass through any defined point in a given time period.
Frequency of 1 hertz means that one wave travels through a given point in one second.
By the above definition, we can say
Frequency
[tex]= \frac{30}{10} \\=3[/tex]
Hence, option C is correct
____ crust forms the ocean floors
A)lithosphere
B)oceanic
C)continental
D)asthenosphere
Answer:
lithosphere
Explanation:
what is polarization of light?
Answer:
Polarized light waves are light waves in which the vibrations occur in a single plane. The process of transforming unpolarized light into polarized light is known as polarization. There are a variety of methods of polarizing light.
Explanation:
if a referee tosses a basketball in the air and hits the floor, at what point will the ball have no mechanical kinetic energy (hint: this occurs at more than one point)
the ball have no mechanical kinetic energy:
Just before the ball is set in motion in the air. Just after it hits the floor.What is mechanical kinetic energy?This refers to the energy that an object possessed due to its motion or due to its position. It is calculated by getting the product of the mass of the object and its velocity and dividing it by two. It is measured in joules, J.
if a referee tosses a basketball in the air, the ball will not have mechanical kinetic energy:
Just before the ball is set in motion in the air. ( Potential energy that is energy due to an object's position).Just after it hits the floor. ( Potential energy that is energy due to an object's position).Learn more about kinetic energy on
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6. An object experiences a force of 4N left and 4N right, what is the net force?
Answer:
The net force is equal to zero.
Explanation:
Two equal forces going in opposite directions will always result in a net force of 0.
Answer:
The net force would be 0.
Explanation:
If you have equal amounts of force on each side it is 0. If you had different amounts of force on each side the side you would subtract the greater one form the smaller one equalling your net force.
A Ferris wheel, rotating initially at an angular speed of 0.16 rad/s, accelerates over a 8.0-s interval at a rate of 0.040 rad/s2. What is its angular speed after this 8.0-s interval?
Answer:
0.48 rad/s
Explanation:
We can use this equation to find the final velocity
[tex]w_f=w_0+at[/tex]
We are given
[tex]w_0=0.16[/tex]
[tex]t=8.0[/tex]
[tex]a=0.04[/tex]
Inserting those numbers into our equation gives us
[tex]w_f=0.16+0.04*8[/tex]
Lets solve for [tex]w_f[/tex].
[tex]w_f=0.16+0.32[/tex]
[tex]w_f=0.48[/tex]
take 100 POINTS!!!! look the picture
claiming points because question is old + no keywords in title
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:
a. the force at the support point
b. the force at the left-hand end.
Answer:
[tex]F_l=1140N[/tex]
Explanation:
From the question we are told that:
Length[tex]l=3.00m[/tex]
Support distance [tex]d=1.00m[/tex]
Weight of diver [tex]W_d=500N[/tex]
Weight of board [tex]W_b=280N[/tex]
Generally the equation for Total Torque is mathematically given by
[tex]F_T=W_d-W_b[/tex]
[tex]F_T=F_d-f_b[/tex]
[tex]F_T=-280-500[/tex]
[tex]F_T=-780[/tex]
[tex]F_T=780[/tex]
Since we consider the horizontal axis
[tex]\sum Y=0[/tex]
[tex]Fs-(\frac{1}{2}l*w_b)-(l-w_d)[/tex]
[tex]Fs-1.5*280-3*300=0[/tex]
[tex]F_s=1920N[/tex]
Therefore the force at the support point 1.00m from the force at the left-hand
[tex]F_l=F_s-F_l[/tex]
[tex]F_l=1920-780[/tex]
[tex]F_l=1140N[/tex]
Why the specific heat of water changed as the water state changed?
Answer:
Infinity. Yes, specific value of water during phase change is infinity. This is because, as long as water is present and it is changing phase (at boiling point or at any other constant temperature), the temperature of the water does not change no matter what amount of heat you are supplying to the water. Thus, its specific heat value is infinity.
the angel between vector a A = 2.00i + 3.00i and vecto B is 45 degree , the scalar product of vectors A and B is 3.00 if the x component of vector B is positive , what is the vector B
I think the answer is b but im not really sure
8. If the m<5 is 63°, find the
measure of <3.
The statement indicates that angle 3 seems to have a 117 degree measurement.
Short answer: What is measure?Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.
Briefing:An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.
The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.
Angle 3 is therefore = 180 - 63 = 117 degrees.
Consequently, angle 3 has a measure of 117 degrees.
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The coyote, whose mass is 20kg is chasing the roadrunner when the coyote accidentally runs off the edge of the cliff and plummets to the ground 30m below. What force does the ground exert on the coyote as he makes a coyote-shaped dent 0.420m deep in the ground.
The force is 196 N (20kg x 9.8 m/s2)
What is force ?Force is an action or influence that causes an object to change its state of motion or rest. Force can be exerted by a single object or by two or more objects interacting with each other. Examples of force include friction, gravity, magnetism, electricity, and pressure. The magnitude of a force is usually measured in newtons (N) and is determined by the amount of mass and acceleration of the object it is acting upon.
The force exerted on the coyote by the ground is equal to the mass of the coyote multiplied by the acceleration due to gravity, which is 9.8 m/s2.
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Question 18 (2 points)
Which statement is TRUE about the relationship between magnetic fields and
electric charges.
A. Moving electric charges (electrons in a circuit) creates a magnetic field and
a magnetic field can cause an electric charge to move (electricity).
B. Moving electric charges (electrons in a circuit) creates an electric field and
a magnetic field can cause static electricity.
C. Static (not moving) electric charges creates a magnetic field and a magnetic field
can cause electricity to stop flowing.
Answer:
A.Moving electric charges (electrons in a circuit) creates a magnetic field and
a magnetic field can cause an electric charge to move (electricity).
Explanation:
A 5,257 kg rocket blasts off to the moon with an acceleration of 76 m/s ^2 what is the net force on the rocket
Newton's subsequent law expresses that power is corresponding to what exactly is needed for an object of consistent mass to change its speed. This is equivalent to that item's mass increased by its speed increase. We use Newtons, kilograms, and meters each second squared as our default units, albeit any proper units for mass (grams, ounces, and so forth) or speed (miles each hour out of every second, millimeters per second2, and so on) could unquestionably be utilized also - the estimation is the equivalent notwithstanding.
Hence, the appropriate answer will be 399,532.
Net Force = 399532
A horizontal spring mass system is to be constructed. A spring which has a spring constant of 3 kg/s2 will be used. The system should be designed so that when it is released and vibrating freely (there is no forcing) the amplitude of its vibrations will decay like ????−0.4t, and it should oscillate with a period of 4 seconds.
(Although the motion is oscillatory it is not strictly periodic because the amplitude decays exponentially. In this context "period" refers to the period of the sine and/or cosine functions that create the oscillations in the motion.)
Based on these constraints determine the mass of the object, ????(kg), to be used, and also determine the value of the friction coefficient, ???? (kg/s).
????: kg
b: kg/s
Answer:
a) 1.1418 kg
b) 0.9135 kg/s
Explanation:
Given data :
spring constant ( k ) = 3 kg/s^2
amplitude of vibrations will decay like :
The mass of the object will be 1.418 kg and the value of the friction coefficient, b is 0.9135 kg/s.
What is Periodic motion?In physics, a periodic motion is a movement that repeats at regular intervals. A swing in motion, a rocking chair, a bouncing ball, a tuning fork vibrating, the Earth orbiting the Sun, and a water wave are all examples of periodic motion. The time interval for repetition, or cycle, of the motion, is referred to in each case as a period, and the frequency is the number of periods per unit of time.
According to the question, the given values are :
Spring constant, k = 3 kg/s²,
Time, T₁ = 4 sec
r = 0.4
The formula for damped oscillation is : [tex]e^-^r^t[/tex]
r = b / 2 m
w₁ = [tex]\sqrt{w_0^2-r^2}[/tex]
T₁ = 2π / w₁
= 2 π / [tex]\sqrt{w_0^2-r^2}[/tex]
w₀ = [tex]\sqrt{4 \pi^2/T_1 +r^2}[/tex]
[tex]\sqrt{k/m}[/tex] = [tex]\sqrt{4 \pi^2/T_1 +r^2}[/tex]
M = k / [tex]{4 \pi^2/T_1 +r^2}[/tex]
M = 3/ (4π/4² +(0.4)²)
M = 1.1418 kg
b = 2 Mr = 2 × 1.1418 × 0.4
b = 0.9135 kg/s
Hence, the mass of the object is 1.1418 kg and the friction coefficient is 0.9135 kg/s.
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