Answer:
Approximately [tex](-61)\; {\rm m\cdot s^{-2}}[/tex], assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Explanation:
Under the assumptions, the vehicle would be in a free fall. Acceleration would be constant: [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the vehicle. Let [tex]v[/tex] denote the velocity of the vehicle at the bottom of the drop. Let [tex]x[/tex] denote the displacement of the vehicle during the drop.
It is given that the initial velocity is [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]. During the drop, displacement would be [tex]x = (-190)\; {\rm m}[/tex] (negative since the vehicle is below where it started.) The value of final velocity [tex]v[/tex] needs to be found.
It is known that the vehicle is moving downwards at the end of the fall. Therefore, the value of [tex]v\![/tex] would be negative. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find [tex]v[/tex] from [tex]u[/tex], [tex]a[/tex], and [tex]x[/tex].
[tex]\begin{aligned}v^{2} &= u^{2} + 2\, a\, x\end{aligned}[/tex].
[tex]\begin{aligned}v &= -\sqrt{u^{2} + 2\, a\, x} \\ &= -\sqrt{(0\; {\rm m\cdot s^{-1}})^{2} + 2\, (-9.81\; {\rm m\cdot s^{-2}})\, (-190\; {\rm m})} \\ &\approx (-61)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
(Note that [tex]v[/tex] is negative.)
In other words, the velocity of the vehicle would be approximately [tex](-61)\; {\rm m\cdot s^{-1}}[/tex] at the end of the drop.
Evaluate the expression a+b when a=23 and b=45 . Write in simplest form
Some planetary scientists have suggested that the planet Mars has an electric field somewhat similar to that of the earth, producing a net electric flux of -3. 63 × 1016 N⋅m2/C at the planet's surface.
a) Calculate the total electric charge on the planet.
b) Calculate the magnitude of the electric field at the planet's surface (refer to the astronomical data inside the back cover).
c) Find the direction of the electric field at the planet's surface.
d) Calculate the charge density on Mars, assuming all the charge is uniformly distributed over the planet's surface
With a net electric flux of -3. 63 1016 N/m2/C at its surface, the planet Mars has an electric field that is somewhat similar to that of the earth. There will be 3.26 x [tex]10^{5}[/tex] of electric charge throughout the entire earth.
Which best sums up Gauss's law?The electric flux across any closed surface is proportional to the net electric charge q enclosed by the surface, according to Gauss's law of electricity, which reads as = q/0, where 0 is the electric permittivity of free space, which has a value of 8.854 10-12 square coulombs per newton per square meter.
How can the angle of a vector in an electric flux be determined?E is the magnitude of the electric field (with units of V/m), S is the area of the surface, and is the angle between the electric field lines and the normal (perpendicular) to S. If the electric field is uniform, the electric flux (E) travelling through a surface of vector area S is: E = ES = EScos.
Calculation:Ф = q/ε
⇒ 3.69 x [tex]10^{16}[/tex] x = q/ 8.85 x [tex]10^{-12}[/tex]
q = 3.26 x [tex]10^{5}[/tex]
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How long will it take for a body
accelerating by 2 m/s² to gain a
velocity of 10 m/s, starting from rest.
We are given:
Initial velocity (u) = 0 m/s [starting from rest]
Final velocity (v) = 10 m/s
Acceleration (a) = 2 m/s²
Time taken = t
Solving for time taken:
v = u + at [first equation of motion]
10 = 0 + (2)(t) [plugging the values]
10 = 2t
t = 5 seconds
helpppppp please!!!!!
Answer:
6
Explanation:
Answer:
6 m/s
Explanation:
Velocity = Distance/Time
= 84 meters/14 seconds
= 6 m/s
Hope this helps! :)
If an object takes 5 seconds to fall off a building, how high is the building?
Suppose a radio message is sent home by astronauts in a spaceship approaching Mars at a distance of from Earth. How long (in minutes) will it take for the message to travel from the spaceship to Earth
A radio message is sent home by astronauts in a spaceship approaching Mars at a distance of from Earth.
A contact from Mars travels [between 3 and 22] minutes at light speed to reach Earth. Relativity contributes to the fact that the distance between Earth and Mars is 1.26 seconds longer.
A Mars year is roughly equivalent to two Earth years because of Mars' nearly two-fold longer orbital period than the Earth's. Earth and Mars are 57.6 million kilometers (35.8 million miles) from one another, while 401 million kilometers separate them at their farthest point (249 million mi).
The sole means of contact between Earth and Mars are radio and messenger. A courier will undoubtedly require a lot of time. We can determine how long it will take a radio message to travel between the two planets since radio waves travel at the speed of light (299,792 km/s; 186,282 mi/s). When the two planets are at their closest, the one-way voyage takes the fewest amount of time—3.2 minutes.
The time required for a one-way trip is 22.3 minutes when they are the furthest apart. A round-trip message will take between 6.4 and 44.6 minutes to send and receive. Of course, receiving an answer will take the same amount of time in each situation.
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A candy-filled piñata is hung from a tree for Matthew's birthday. During an unsuccessful attempt to break the 4. 4-kg piñata, Hayden cracks it with a 0. 54-kg stick moving at 4. 8 m/s. The stick stops and the piñata undergoes a gentle swinging motion. Determine the swing speed of the piñata immediately after being cracked by the stick
The velocity of the other piece of the pinata which has a mass of 3.86 kg
is 0.67 m/s
The mass of the candy-filled pinata = 4.4 kg
The mass of the first piece of the pinata = 0.54 kg
The velocity of the first piece of the pinata = 4.8 m/s
The mass of the second piece = 3.86 kg
The velocity of the other piece can be found using the formula,
mu = m₁v₁ + m₂v₂
where m is the mass of the pinata
u is the velocity of the pinata at rest
m₁,m₂ are the masses of the first and second pieces of pinata
v₁,v₂ is the velocity of the two pieces
Let us substitute the known values in the above equation, we get
4.4 x 0 = 0.54 x 4.8 + 3.86v₂
= 2.592 + 3.86v₂
3.86v₂ = -2.592
v₂ = 2.592/3.86
= 0.67 m/s
Therefore, the velocity of the other piece is 0.67 m/s
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How much energy is needed to perform 300 J of work?
When a police officer observes a vehicle in motion, what are some things that the officer might notice about the manner in which the vehicle is being driving that indicate the driver might be impaired
Answer:
weaving of the car in motionTurning with a wide radius swerving Drifting from a LaneExplanation:
The motion of a vehicle been driven by an impaired driver will be different in some ways from a vehicle driven by an unimpaired driver
and what a police officer might observe/ notice will include some of the following :
weaving of the car in motionTurning with a wide radius swerving Drifting from a Lanehumans taste food mostly because of:
Answer:
taste buds
Explanation:
very sensitive microscopic hairs called microvilli. The tiny hairs send messages to the brain about how something tastes, so you know if it's sweet, sour, bitter, or salty
Suppose you have a set of spheres of various sizes. The formula below shows a possible relationship between the surface area (S) and volume for the spheres (V).
The formula that shows the relationship between the surface area (S) and volume (V) for spheres is S = 4πr² and V = (4/3)πr³ where r is the radius of the sphere.
This formula shows that the surface area of a sphere is directly proportional to the radius squared, and the volume is directly proportional to the radius cubed. This means that as the radius of a sphere increases, the surface area and volume will increase at a much faster rate. For example, a sphere with a radius of 2 will have four times the surface area and eight times the volume of a sphere with a radius of 1.
The question is incomplete, hence the answer is general.
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How do you find the acceleration of a marble down a ramp?
The marble accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
Rolling motion of any object occurs when the marble starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the marble is acting in the smaller form.
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Consider the following reaction
2Mg(s) + 02 (9) 2Mgo (s)
If 21. 2 kcals of energy is released by this reaction, how many kJ
of energy does the reaction release? (1 cal = 4. 184 J) (Round off
decimal to nearest tenths)
In the given reaction, 2Mg(s) + O₂ (g) → 2MgO (s), 88.7 kJ of energy will be released.
The reaction 2Mg(s) + O₂ (g) → 2MgO (s) involves the release of energy from the system and hence it is an exothermic reaction. 21.2 kcals of energy is released from this reaction.
21.2 kcals = 21.2 × 10³ calories
1 cal = 4.184 J
For 21.2 × 10³ calories,
21.2 × 10³ cal × 4.184 = 88.70 × 10³ cal
To convert J to kJ, we divide it by 10³
88.70 × 10³ / 10³ = 88.70
Rounding off to nearest tenths, the amount of energy released by the given reaction in kJ = 88.7 kJ
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Part A
Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
The electric field in the region r ≤a is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
The total charge is enclosed within the Gaussian surface.
Q[tex]_{enc}[/tex] = 2Q - Q = Q
Therefore, applying Gauss's law over the Gaussian surface
∫[tex]_{s}[/tex]E.dS = Q[tex]_{enc}[/tex]/ε₀ ⇒ E.4πr² = Q/ε₀ ⇒ E = Q/4πε₀r²(r)
In question solution:
A[tex]_{sphere}[/tex] = 4πr²
ΦE = ∫E⋅dA
ΦE = q/ε₀
E = q/(A⋅ε₀)
E = q/(4πr²ε₀)
for r≤a, qin = -Q
E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
So, the electric field in the region is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
Your question is incomplete but most probably your full question was:
A uniformly charged ball of radius a and charge −Q is at the center of a hollow metal shell with inner radius b and outer radius c. The hollow sphere has a net charge of +2Q.
Part A: Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
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A 120 Kg man is diving off a 40 meter cliff. What is his kinetic energy when he is 10 meters from the water?
The required kinetic energy of man diving out at 10 m from water is calculated to be 35.3 kJ.
Given that,
Mass of the man m = 120 kg
Height of the cliff H = 40 m
Distance from the water surface h' = 10 m
The mathematical equation of velocity efflux is
v = √( 2g ( H - h') = √( 2 × 9.8(40-10) = 24.25 m/s
The expression for kinetic energy of the man = 1/2 m v²
K.E = 1/2 m v² = 1/2 × 120 × 24.25² = 35283.75 J = 35.3 kJ
Thus, we can conclude that the kinetic energy of man diving out at 10 m from water is 35.3 kJ.
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what are the Properties of Transverse Waves and Longitudinal wave
Answer:
Key terms
TermMeaningTransverse waveOscillations where particles are displaced perpendicular to the wave direction.Longitudinal waveOscillations where particles are displaced parallel to the wave direction
udora ran from her home to her secret laboratory at an average speed of 12\text{ km/h}12 km/h12, start text, space, k, m, slash, h, end text. She then took one of her jetpacks and flew to her school at an average speed of 76\text{ km/h}76 km/h76, start text, space, k, m, slash, h, end text. Eudora traveled a total distance of 120120120 kilometers, and the entire trip took 222 hours. How long did Eudora spend running, and how long did she spend flying using her jetpack
Eudora spent 0.5 hours from home to library and 1.5 hours from library to school.
Given that,
Average speed from home to library S₁ = 12 km/h
Average speed from library to school S₂ = 76 km/h
Total distance = 120 km
Time = 2 hrs
Let the time spent from home to library be x. So, from library to school will be = 2 - x
S₁ = 12 km/h
Time spent from home to library T₁ = x
S₂ = 76 km/h
Time spent from library to school T₂ = 2 - x
Distance can be calculated as, D₁ = S₁ T₁ = 12 x
D₂ = S₂ T₂ = 76(2 - x) = 152 - 76 x
As, D₁ + D₂ = 120
12 x + 152 - 76 x = 120
-64 x = -32
x = 0.5
So, T₁ = 0.5 hrs
T₂ = 2 - 0.5 = 1.5 hrs
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A proton accelerates from rest in a uniform electric field of 660 N/C. At one later moment, its speed is 1.10 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. .81 Incorrect: Your answer is incorrect. m/s2 (b) Over what time interval does the proton reach this speed
Q is the charge's magnitude, V is its velocity, X is the angle formed by the magnetic field's direction and the charge's motion, and B is the strength of the magnetic field.
We must divide this amount by the mass of the charged particle or particles in order to determine the acceleration. Its speed at a later time is 1. 20 Mm/s (non relativistic because v is much less than the speed of light). When a refractive index diminishes over time, light shifts its frequency, which is referred to as photon acceleration [13,14]. Similar to charged particle acceleration, a rise in group velocity is accompanied by an increase in photon energy, or frequency.
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Un carrusel da 90 vueltas en 3 minuto. ¿Cuál es la frecuencia y el período?
En el manual de una licuadora indica que el rotor da 7500 revoluciones por minuto. ¿Cuál es el período y la frecuencia?
ayudenme por favor
Answer:
I will help you but I don't understand the language
You weigh 600 N.
What would you weigh if the Earth were
seven times as massive as it is and its radius
were three times its present value?
Answer in units of N.
Your weight would be 85.7N if the Earth were seven times as massive as it is and had a radius three times that of today since the gravitational pull is reduced by seven times with an increase in radius.
Gravitation is a fundamental interaction in physics that produces attraction between all objects with mass or energy. Of the four fundamental interactions, gravity is by far the weakest, being about ten times less than the strong interaction. A body's mass is a fundamental characteristic. Before the discovery of the atom and the field of particle physics, it was generally thought to be tied to the amount of matter in a physical body. x = 600N/7, x = 85.7N
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If we have an unmarked magnet, how can we tell which end is the north pole of the magnet? a. Hold it near a compass and the north end of the compass points at the north end of the magnet. b. Hold it near a compass and the north end of the compass points at the south end of the magnet. c. Suspend it from a string and the end that points toward the geographic north pole (Santa's workshop) is the north end. d. Hold it near a piece of steel and the end that attracts the steel is the north end. e. The end that is attracted to the south end of a known magnet is the north end. f. The end that is attracted to the north end of a known magnet is the north end.
If we have an unmarked magnet, hold it near a piece of steel and the end that attracts the steel is the north end.
What is the magnet?
A magnet is an object made of certain materials that produces a magnetic field. This field is invisible but is responsible for the most notable property of a magnet: a force that pulls on other ferromagnetic materials, such as iron, and attracts or repels other magnets. Magnets are widely used throughout the world in a variety of applications, from the simple refrigerator magnet to the most advanced technologies such as MRI machines. Magnets come in many shapes and sizes and can be natural or artificial. The magnetic field of a magnet is caused by the motion of electric charges and is measured in guess.
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The speed of light is approximately $3\times10^5$ kilometers per second. How long does it take sunlight to reach Jupiter
it takes about 26 seconds for speed of light with approximate speed of 3\times10^5 kilometers per second to reach Jupiter.
To calculate the time it takes light to reach Jupiter, we need to know the distance between the Sun and Jupiter. The average distance between the Sun and Jupiter is approximately 778 million kilometers. We can use the formula distance = speed x time to calculate the time it takes for sunlight to reach Jupiter. We know that the speed of light is approximately 3x10^5 kilometers per second and the distance between the Sun and Jupiter is 778 million kilometers.time = distance / speed
time = (77810^6 km) / (310^5 km/s)
time = 26 sec (approximately)
Therefore, it takes about 26 seconds for light to reach Jupiter.
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calcula el potencial electrico de un punto B que se encuentra a 75cm de una varga positica q=9×10-6c
Answer:
V = 72000 volts
Explanation:
calculates the electric potential of a point B that is 75cm from a positive charge q = 9 × 10-6c
Given that,
Electric charge, [tex]q=9\times 10^{-6}\ C[/tex]
We need to find the electric potential of a point B that is 75 cm from this charge. The formula for the electric potential is given by :
[tex]V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6\times 10^{-6}}{0.75}\\\\V=72000\ V[/tex]
So, the electric potential is equal to 72000 Volts.
A capacitor has plates separated by
8.89 x 10-7 m. To create a
capacitance of 1.11 x 10-9 F, what
must the area of the plates be?
We know, formula of capacitance in parallel plate capacitor is given by :
[tex]C = \dfrac{\epsilon_o A}{d}[/tex]
Here, [tex]\epsilon_o = 8.85 \times 10^{-12} \ F.m^{-1}[/tex]
So,
[tex]A = \dfrac{Cd}{\epsilon_o}\\\\A = \dfrac{1.11 \times 10^{-9}\times 8.89 \times 10^{-7}}{8.85\times 10^{-12}}\\\\A = 1.11 \times 10^{-4}\ m^2 \ or \ 1.11 \ cm^2[/tex]
Hence, this is the required solution.
Answer:
7.09797297 • 10^-7
Explanation:
You just follow the formula:
C = εA/d
ε = 8.85 • 10^-12
A = 8.89 • 10^-7
D = 1.11• 10 ^-9
So:
C = (8.85 • 10^-12)(8.89• 10^-4)/1.11 • 10 ^-9 = 7.09797297 • 10^-7
Good Luck! :)
Bill weighs 160 lb. He is standing on a scale inside an elevator. What is the reading on the scale if the elevator is accelerating downward
the scale's readout if indeed the elevator is decelerating faster than 160 lb .
The elevator speeds up or down, right?Your perceived weight is equal to the normal force.Therefore, whenever the elevator accelerates or upwards downward, you truly feel tiny bit heavier than normal and a little lighter than usual.
If an elevator malfunctions, should you lay down?Any jump you make would only slow the lift's descent to the ground by a very small amount.Even though you could jump perfectly timed and with all the force your legs could produce, it would be pointless.Your greatest option, as opposed to jumping, is to fold down.
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Which of the following is not a drawback of using coal for energy production?
A. Mountaintop mining
B. Mercury in fly ash
C. Mining explosions
D. Difficult transportation due to instability
The statement that is not provide a drawback of using coal energy for energy production is (D) difficult transportation due to instability.
What is disadvantage of using coal for energy production?Coal is source of fossil energy created by dead plant drawn in swamp environments and subjected by geological pressure and forces of heat over hundreds of millions of years. The disadvantage using this source of energy are:
It use mountaintop mining that can contaminate water.It use combustion to create energy and the remaining after combusting has mercury that can fly in form of an ash. As to reminder, mercury can harm nerve when its being inhale.In the process of its mining, the coal commonly result an ash that can combust in the air. The accumulation can cause mining explosions.Learn more about coal mining here
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Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)
-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch
The astronaut being pushed back into his seat as the rocket accelerates - this was the example of Newton's first law of motion.
What is Newton's first law of motion?According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.
When the astronaut worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .
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I would like to know how to find the distance my fake planet is to its sun and the orbital length in measurement using the information I have gathered so far about my made up DnD planet I have searched a million things up and have gotten myself in a loop hole because in order to get X I need to know B and in order to know B I need to either know X or A and if I use the one using A then A needs X in order to find B to find X.
Heres the information:
Day Duration: 36 hours
Orbit Duration: 1.6 Earth years
Year Duration: 389.3... days
Gravity: 9.608 m/s²
Axial Precession: 15,000 years
Axial Tilt: 21.7 to 23.5
Axial Oscillate: 8333.3... years per 0.1 oscillate of 1.8 oscillation
Number of moons: 3
CLimate regions: much similar to earth Temperate regions are
the magority of the planet with tropical at the equator and
subtropical at the poles with seasons changing at the prevernal,
vernal, estival, serotinal, autumnal, and hibernal periods
Radius: 4578.2 (m)
Planet Mass: 3017387649322753000
Circumference: 28765.6789733
It is to be noted that based on the information provided, it is not possible to calculate the distance of the planet from its sun as we need more information about orbit and its eccentricity.
What is Space Orbit distance?The distance of your fictional planet from its sun, and its orbital period, can be calculated using the information you've provided about its day duration, orbit duration, year duration, and radius.
The distance between a planet and its sun is known as an astronomical unit (AU). To calculate the distance in AU, you can use the formula: d = (T² * G * M_sun) / (4 * pπ²)
where T is the planet's orbital period in Earth years, G is the gravitational constant (6.67 x 10^-⁻¹¹ m³ kg^⁻¹ s^⁻²), M_sun is the mass of the sun (2 x 10^30 kg), and pi is the mathematical constant (3.14).To find the orbital period you need to know year duration in seconds and divide it by 365.25 for Earth-based standard.
With that you can calculate the distance of the planet from its sun. The calculation of axial precession, tilt and oscillation etc don't provide information about the distance from its sun or the orbital period, It helps us to understand the planet's rotation around it's axial and the behaviors of the planet's climate because of axial tilt, precession and oscillation
Also, radius, planet mass and circumference also don't provide any information about distance of the planet from its sun or the orbital period as well.
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write the realtion between work and power
Explanation:
Work is the energy needed to apply a force to move an object a particular distance, where force is parallel to the displacement. Power is the rate at which that work is done.
Explanation:
Some possible units for each
Work =F⋅d=N⋅m=J=kgm2s2
Power =F⋅dt=F⋅v=N⋅ms=W=Js=kgm2s3
The relation p=w/t
A closed pipe creates a
fundamental frequency of 125 Hz.
What is the next higher frequency
that will create a standing wave in
the pipe?
(Speed of sound = 343 m/s)
(Unit = Hz)
Answer:
375 hz
Explanation:
Trust me