Alg 2-7_2 BR Trigonometry
To approach the runway, a pilot of a small plane must begin a 5° descent starting from a height of 1732 ff above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach( how far does the airplane have to fly)?

0 3.7 mi
0 3.8 mi
0 0.3 mi
0 19,872.5 mi

Answers

Answer 1
Answer:  Choice B)  3.8 miles

==============================================================

Explanation:

Check out the diagram below.

Those pair of 5 degree angles shown are congruent alternate interior angles. We'll use the sine rule to find the hypotenuse x (which is some measurement in feet).

sin(angle) = opposite/hypotenuse

sin(5) = 1732/x

x*sin(5) = 1732

x = 1732/sin(5)

x = 19,872.4713415001 approximately

x = 19,872.5

It's tempting to say that choice D is the final answer. However, the result we just got is in feet, not in miles. To convert from feet to miles, we divide by 5280.

19,872.5 ft = (19,872.5)/5280 = 3.7637 miles

That then rounds to the final answer of 3.8 miles (choice B).

------------

Alternatively, you can convert 1732 ft to miles to get roughly 1732/5280 = 0.328 miles. Then you should solve this equation for x

sin(5) = 0.328/x

it should lead you to x = 3.8 miles

Alg 2-7_2 BR TrigonometryTo Approach The Runway, A Pilot Of A Small Plane Must Begin A 5 Descent Starting

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