Annette Creighton opened Creighton Consulting and rented a small office space. She also hired a part-time worker to handle phone calls and make deliveries.
1. Annette Creighton decided to start her own consulting firm and named it Creighton Consulting.
2. As part of setting up the business, she began by renting a small office space. This would serve as the headquarters for her consulting operations.
3. To ensure smooth communication and timely deliveries, Annette realized the need for assistance. She hired a part-time worker to handle incoming phone calls and make necessary deliveries on behalf of the company.
4. The part-time worker would be responsible for answering the phone and addressing client inquiries or forwarding them to Annette if necessary. This step was crucial to maintaining good customer service and professionalism.
5. Additionally, the worker would also handle deliveries, ensuring that any documents, packages, or materials were transported promptly to clients or other relevant destinations.
6. By hiring a part-time worker, Annette aimed to streamline her operations and focus on core consulting tasks, such as client meetings, project management, and providing expert advice to clients.
7. The worker's role would involve effective communication skills, organization, and attention to detail to represent Creighton Consulting in a professional manner.
8. Annette understood that investing in administrative support would free up her time and allow the business to operate more efficiently, ultimately benefiting both her and her clients.
9. With the office space secured and the part-time worker in place, Annette was ready to embark on her consulting journey, confident in her ability to handle client inquiries and maintain smooth business operations.
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Deacon Company is a merchandising company that is preparing abudget for the three-month period ended June 30th. The followinginformation is availableDeacon CompanyBalance SheetMarch 31AssetsCash$60,200 Accounts receivable $30,800Inventory $60,400Buildings and equipment, net of depreciation $124,000Total assets$295,400Liabilities and Stockholders’EquityAccounts payable$71,100Common stock 70,000Retained earnings $134,300Total liabilities and stockholder...
The total liabilities and stockholders' equity for Deacon Company as of March 31st is $275,400.
To calculate the total liabilities and stockholders' equity, we need to add the amounts of accounts payable, common stock, and retained earnings. Accounts Payable: The balance sheet provides the information that the accounts payable is $71,100.
Common Stock: The balance sheet states that the common stock is $70,000.
Retained Earnings: The balance sheet shows that the retained earnings are $134,300.
Calculate the total liabilities and stockholders' equity: Add the amounts of accounts payable, common stock, and retained earnings.
Total liabilities and stockholders' equity = Accounts payable + Common stock + Retained earnings
= $71,100 + $70,000 + $134,300
= $275,400
Therefore, the total liabilities and stockholders' equity for Deacon Company as of March 31st is $275,400.
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2.6m 11m Jenny wants to know if she has got enough money to buy the tiles. 1.4m The tiles are sold in packs, which cover 3m² Jenny has a discount card which gives her 25% off any marked price at the DIY shop. The tiles are marked at £18.60 Jenny has £100 to spend on the tiles. 4 How much extra does Jenny need to buy the tiles? Give your answer in pence.
First, we need to calculate the area of the room Jenny is tiling, which appears to be in the shape of a rectangle. The area is calculated by multiplying the length and width of the rectangle. If the measurements provided (2.6m and 11m) are for the length and width, then the area of the room would be:
Area = length x width
Area = 2.6m x 11m
Area = 28.6 m²
Next, we need to calculate how many packs of tiles Jenny needs to buy. Given that each pack covers an area of 3m², we divide the total area by the area each pack covers:
Number of packs needed = total area / area covered by one pack
Number of packs needed = 28.6m² / 3m² ≈ 9.53 packs
Since Jenny can't buy a fraction of a pack, she needs to purchase 10 packs of tiles.
The tiles are marked at £18.60, so before the discount, the total cost of the tiles would be:
Total cost = number of packs x price per pack
Total cost = 10 packs x £18.60 = £186
Jenny has a discount card which gives her a 25% discount off the marked price. The discount amount can be calculated as:
Discount = total cost x discount rate
Discount = £186 x 25% = £46.5
So, the cost of the tiles after the discount is:
Discounted price = total cost - discount
Discounted price = £186 - £46.5 = £139.5
Jenny has £100 to spend on the tiles. The extra amount Jenny needs is the difference between the cost of the tiles after the discount and the amount she has:
Extra amount needed = discounted price - amount Jenny has
Extra amount needed = £139.5 - £100 = £39.5
The question asks for the answer in pence, and there are 100 pence in a pound, so:
Extra amount needed in pence = extra amount needed in pounds x 100
Extra amount needed in pence = £39.5 x 100 = 3950 pence
Therefore, Jenny needs an extra 3950 pence to buy the tiles.
Would be really helpful!
Step-by-step explanation:
To solve this problem, we need to use the product rule of differentiation and some trigonometric identities. Let's start by finding the derivative of y with respect to x:
y = (sin 2x) √(3+2x)
Using the product rule, we get:
dy/dx = (sin 2x) d/dx(√(3+2x)) + (√(3+2x)) d/dx(sin 2x)
To find these derivatives, we need to use the chain rule and the derivative of sin 2x:
d/dx(√(3+2x)) = (1/2√(3+2x)) d/dx(3+2x) = (1/√(3+2x))
d/dx(sin 2x) = 2cos 2x
Substituting these values, we get:
dy/dx = (sin 2x) / √(3+2x) + 2cos 2x (√(3+2x))
Now, we need to simplify this expression to the desired form. To do that, we can use the trigonometric identity:
sin 2x = 2sin x cos x
Substituting this value, we get:
dy/dx = 2sin x cos x / √(3+2x) + 2cos 2x (√(3+2x))
Now, we can use the trigonometric identity:
cos 2x = 1 - 2sin^2 x
Substituting this value, we get:
dy/dx = 2sin x cos x / √(3+2x) + 2(1 - 2sin^2 x)(√(3+2x))
Simplifying further, we get:
dy/dx = (2cos x - 4cos x sin^2 x) / √(3+2x) + 2√(3+2x) - 4sin^2 x√(3+2x)
Now, we can see that this expression matches the desired form:
dy/dx = sin 2x + (4 + Bx)cos 2x / √(3+2x)
where A = -4 and B = -2. Therefore, we have shown that:
dy/dr = sin 2x + (4 - 2x)cos 2x / √(3+2x)
where A = -4 and B = -2.
Which equation represents a line which is perpendicular to the line y = - 6/5 * x - 7
An equation representing a line perpendicular to y = -6/5 [tex]\times[/tex] x - 7 would be y = 5/6 [tex]\times[/tex] x + c, where c is any constant.
To determine a line that is perpendicular to the given line y = -6/5 [tex]\times[/tex] x - 7, we need to consider the slope of the given line.
The given line has a slope of -6/5.
For two lines to be perpendicular, their slopes must be negative reciprocals of each other.
The negative reciprocal of -6/5 can be found by flipping the fraction and changing the sign, which gives us 5/6.
Therefore, the equation of a line perpendicular to y = -6/5 [tex]\times[/tex] x - 7 will have a slope of 5/6.
To find the equation of this perpendicular line, we can use the point-slope form of a line, using a known point on the line.
Let's assume the line passes through the point (x1, y1).
The equation of the perpendicular line can be written as: y - y1 = (5/6) [tex]\times[/tex] (x - x1).
Since we do not have a specific point given, we cannot determine the exact equation of the perpendicular line without additional information.
In summary, the equation of a line perpendicular to y = -6/5 [tex]\times[/tex] x - 7 will have a slope of 5/6, but the specific equation depends on the point it passes through.
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You pick a card at random.
2 3 4 5
What is P(divisor of 32)?
The two figures are similar. Write a Similarity statement. Justify your answer. AB 40 AC 50. BC 60. YX 37.5. YZ 30. ZX 45
Similarity statement and justification for two similar figures with given measurements. The given figures are AB = 40, AC = 50, and BC = 60. For the second figure, YX = 37.5, YZ = 30, and ZX = 45.
To write a similarity statement, we compare the ratios of corresponding sides of the two figures. So, we can compare AB/BC to YX/ZX and AC/BC to YZ/ZX.AB/BC = 40/60 = 2/3YX/ZX = 37.5/45 = 5/6AC/BC = 50/60 = 5/6YZ/ZX = 30/45 = 2/3Since the ratios of the corresponding sides of both figures are the same, we can say that the two figures are similar.
A similarity statement for these figures can be written as:ΔABC ~ ΔXYZThis statement indicates that the two triangles ABC and XYZ are similar. The symbol ~ is used to denote similarity.
The justification for this similarity statement is based on the fact that the ratios of the corresponding sides of the two figures are equal.
Therefore, by the definition of similarity, we can conclude that the two triangles are similar.
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A package is weighed at 11 kg to the nearest kg. Find the largest possible weight for the package.
The largest possible weight for the package is 11.5 kg.
To find the largest possible weight for the package, we need to consider the range within which the weight lies when rounded to the nearest kilogram.
When the package is weighed at 11 kg to the nearest kilogram, it means the actual weight could be anywhere between 10.5 kg and 11.5 kg. This is because rounding to the nearest kilogram involves considering values halfway between two integers to round up or down.
To determine the largest possible weight, we take the upper limit of this range, which is 11.5 kg. Therefore, the largest possible weight for the package is 11.5 kg.
Keep in mind that when rounding to the nearest kilogram, values from 10.5 kg to 11.4 kg would round down to 11 kg, while values from 11.5 kg to 12.4 kg would round up to 12 kg.
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Hi I could use some help with this question, thank you in advance.
apologies for mislabeling this as college
Using the property of vertical angles, the value of x is 24 degrees
What are vertical angles?Vertical angles are a pair of non-adjacent angles formed by the intersection of two lines. They are opposite each other and share a common vertex, but they are not adjacent angles.
When two lines intersect, they form four angles at the point of intersection. The vertical angles are the angles that are directly across from each other and are formed by opposite pairs of intersecting lines. In other words, if you draw a line segment connecting the vertices of the vertical angles, it will divide the intersection into two pairs of congruent angles.
The property of vertical angles is that they have equal measures. This means that if one vertical angle measures a certain number of degrees, the other vertical angle will also measure the same number of degrees.
In this problem, to find the value of x, we have to use the property of vertical angles which states that vertical angles are equal to one another.
This implies that ∠ABC = DBE
3x - 14 = 2x + 10
Collect like terms
3x - 2x = 10 + 14
x = 24°
The answer is option D.
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1). From a position 150 ft above the ground, an observer in a build- ing measures angles of depression of 12 and 34 to the top and bottom, respectively, of a smaller building, as in the picture on the right. Use this to find the height h of the smaller building.
We can solve for d = 150 / (tan(34) - tan(12)) Once we have the value of d, we can substitute it back into the equation h = d * tan(12) to find the height h of the smaller building.
To find the height h of the smaller building, we can use trigonometric ratios and the concept of angles of depression.
Let's denote the height of the smaller building as h. We are given that the observer in the larger building measures angles of depression of 12 degrees and 34 degrees to the top and bottom of the smaller building, respectively.
From the given information, we can form a right triangle with the vertical distance between the observer and the smaller building as the opposite side and the horizontal distance between the observer and the smaller building as the adjacent side.
Using trigonometric ratios, we can set up the following equations:
For the angle of depression of 12 degrees:
tan(12) = h / d
For the angle of depression of 34 degrees:
tan(34) = (h + 150) / d
Here, d represents the horizontal distance between the observer and the smaller building.
We can solve these two equations simultaneously to find the values of h and d.
From the equation for the angle of depression of 12 degrees, we can rewrite it as:
h = d * tan(12)
Substituting this expression for h in the equation for the angle of depression of 34 degrees, we get:
tan(34) = (d * tan(12) + 150) / d
Now, we can solve this equation for d. Rearranging the equation, we have:
d * tan(34) = d * tan(12) + 150
Simplifying further:
d * (tan(34) - tan(12)) = 150
Finally, we can solve for d:
d = 150 / (tan(34) - tan(12))
Once we have the value of d, we can substitute it back into the equation h = d * tan(12) to find the height h of the smaller building.
Note: To obtain an actual numerical value for h, we need the precise values of the tangent of 12 degrees and 34 degrees.
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b. Based on the values in the table, what effect does changing the
radius seem to have on the surface area of the sphere? In general,
how does multiplying the radius of a sphere by a factor of x affect the
surface area of the sphere?
Answer:
Based on the values in the table, it can be observed that changing the radius of the sphere has a direct effect on the surface area of the sphere. As the radius increases, the surface area also increases.
Step-by-step explanation:
In general, multiplying the radius of a sphere by a factor of x will result in the surface area of the sphere being multiplied by a factor of x^2. This is because the surface area of a sphere is given by the formula:
Surface Area = 4πr^2
When the radius is multiplied by a factor of x, the new radius becomes xr. Substituting this into the formula, we get:
New Surface Area = 4π(xr)^2
= 4πx^2r^2
= x^2(4πr^2)
Therefore, the surface area of the sphere is multiplied by a factor of x^2 when the radius is multiplied by a factor of x. This relationship shows that the surface area increases at a faster rate than the radius.
Si 3,390 kg de plomo ocupan un volumen de 0.3m3. Encuentra la densidad del plomo.
The density of lead is 11,300 kg/[tex]m^3[/tex], which means that lead is a dense material with a significant mass per unit volume.
To find the density of lead, we can use the formula:
Density = Mass / Volume
Given that the mass of lead is 3,390 kg and the volume is 0.3 [tex]m^3[/tex], we can substitute these values into the formula:
Density = 3,390 kg / 0.3[tex]m^3[/tex]
To simplify the calculation, we divide the mass by the volume:
Density = 11,300 kg/[tex]m^3[/tex]
Therefore, the density of lead is 11,300 kg/[tex]m^3[/tex].
Density is a physical property of a substance that describes how much mass is packed into a given volume. In this case, the density of lead tells us that for every cubic meter of lead, there are 11,300 kilograms of mass.
It is important to note that the density of lead is a characteristic property and remains constant regardless of the size or shape of the sample. It is a useful parameter in various scientific and industrial applications.
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The question probable may be:
If 3,390 kg of lead occupy a volume of 0.3 m^3, find the density of lead.
A fish tank is 50 cm long and 40 cm wide and 20 cm high how many millimeters of water does the tank hold
Answer:
The fish tank holds 40,000 ml of water.
Step-by-step explanation:
Volume = Length x Width x Height
Volume = 50 x 40 x 20
Volume = 40,000
Work out the value of 408 5
Give your answer as a decimal.
The value of 408^5 is approximately 273,539,283,056,896. This is a large number that can be accurately calculated using a calculator or computer program.
To work out the value of 408^5, we need to perform the exponentiation calculation. In this case, 408 is the base, and 5 is the exponent.
Calculating large exponentiations like this can be time-consuming and prone to error if done manually. However, with the help of a calculator or computer, we can easily find the result.
Using a calculator or computer program, we can calculate 408^5 and obtain the value. The result is a very large number:
408^5 ≈ 273,539,283,056,896
Therefore, the value of 408^5 is approximately 273,539,283,056,896.
In decimal notation, the value is written as:
273,539,283,056,896
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Determine the range of the following graph:
Answer:
The range of this graph is (-4, 6], or
-4 < y < 6.
The range of the graph is [-4, 6].
What is a range?In Mathematics and Geometry, a range is the set of all real numbers that connects with the elements of a domain.
This ultimately implies that, a range simply refers to the set of all possible output numerical values (real numbers), which are shown on the y-coordinate (y-axis) of a graph.
Based on the information provided in this scenario, the domain and range of the graph of this equation can be determined are as follows:
Domain = [1, 10] or 1 ≤ x < 10
Range = [-4, 6], or -4 < y ≤ 6.
Therefore, the range can be rewritten as [-4, 6].
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Pls help I am stuck Tysm
Answer:
16cm
Step-by-step explanation:
perimeter for C is 44cm
perimeter for A and B 60cm
60cm-44cm=16cm
Hope this helps
15 yd.
b
Learn with an example
9 yd.
or
The area of the garden is 135 square yards.
Let's imagine you have a rectangular garden measuring 15 yards in length and 9 yards in width.
You want to find the area of this garden, which represents the amount of space inside the garden.
To find the area of a rectangle, you multiply the length by the width.
In this case, the length is 15 yards and the width is 9 yards.
Area = Length × Width
Area = 15 yards × 9 yards
Area = 135 square yards
This means that the garden can hold 135 square yards of grass, flowers, or any other objects you place inside it.
It's worth noting that the unit of measurement for area is always squared, such as square yards in this example.
This is because area is a two-dimensional measurement, representing the space within a flat surface.
By using the formula to calculate the area of a rectangle, you can easily determine the amount of space enclosed by any rectangular area when given the length and width.
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write the first five multiples of 17
Step-by-step explanation:
write the first five multiples of 17
17 x 1 = 1717 x 2 = 3417 x 3 = 5117 x 4 = 6817 x 5 = 85
Therefore, the first five multiples of 17 are 17 , 34 , 51 , 68 and 85 .
The scale of the model is 1 inch-3.5 feet. If the model's length is 3 inches, find the actual length.
The actual length corresponding to the 3-inch length on the model is 10.5 feet.
Given that the scale of the model is 1 inch to 3.5 feet, we can use this information to find the actual length corresponding to a given length on the model.
Let's denote:
Model's length = 3 inches
Actual length = ?
According to the given scale, 1 inch on the model represents 3.5 feet in reality. We can set up a proportion to find the actual length:
(1 inch) / (3.5 feet) = (3 inches) / (x feet)
Cross-multiplying, we get:
1 inch * x feet = 3 inches * 3.5 feet
Simplifying the equation:
x feet = 10.5 feet
Therefore, the actual length corresponding to the 3-inch length on the model is 10.5 feet.
In summary, the actual length is 10.5 feet.
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NO LINKS!! URGENT HELP PLEASE!!
Please help with #3
Answer: See the flowchart proof below.
Explanation:
The given info is indicated by the marked angles. We also use the reflexive property to say that BG = BG. After that we use the ASA (angle side angle) property to prove the triangles are congruent. The triangles are mirrored clones of one another. The mirror line is segment BG.
A flowchart proof that proves that the two triangles are congruent is shown in the image below.
What are the properties of similar triangles?In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.
In this context, we can prove that triangle BIG is congruent with triangle BAG by completing the two-column proof shown above with the following reasons:
Statements Reasons
∠IBG ≅ ∠ABG Given
∠IGB ≅ ∠AGB Given
BG ≅ BG Reflexive property
ΔBIG ≅ ΔBAG ASA Congruence
Based on the angle, side, angle (ASA) similarity theorem, we can logically deduce that triangle BIG and triangle BAG are both congruent.
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Utility company charges.10 cents per kilowatt-hour of electricity what is the daily cost of keeping lit a 50 watt bulb for 9hrs each day
The daily cost of keeping a 50-watt bulb lit for 9 hours each day would be approximately $0.045 (or 4.5 cents).
To calculate the daily cost of keeping a 50-watt bulb lit for 9 hours each day, we need to consider the electricity cost per kilowatt-hour (kWh) and convert the wattage to kilowatts.
First, we convert the wattage of the bulb to kilowatts by dividing it by 1000:
50 watts = 50/1000 = 0.05 kilowatts.
Next, we calculate the total energy consumed by multiplying the power (in kilowatts) by the time (in hours):
Total energy consumed = 0.05 kW * 9 hours = 0.45 kilowatt-hours (kWh).
Now, we multiply the total energy consumed by the cost per kilowatt-hour to find the daily cost:
Daily cost = 0.45 kWh * $0.10/kWh = $0.045.
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Giraffe jack is 19ft tall, and ostrich Jim is 9ft tall. What percent of Jim’s height is jacks height?
Answer:
211%
Step-by-step explanation:
percent = part/whole × 100%
percent = 19/9 × 100%
percent = 211%
Linda is opening a bakery and needs to figure out how much to charge for donuts. She checks with a number of other bakeries and compares their prices to their reported profits.
Donut Price Profits
$1.55 $5244
$0.95 $5244
$0.75 $3900
$1.25. $6000
$1.05 $5664
$1.35. $5916
Bakery
Dan's Delicious Donuts
The Corner Bakery
Bake 'n Wake
Donuts 'R' Us
Dan's Delicious Donuts
Dan's Delicious Donuts $1.35
A: Find the quadratic function that fits this data. Express this function in vertex form.
B: Use your model to predict Linda's profits if she undercuts the competition by selling her donuts for 55 cents each.
Linda's profits will be $
Question 9(Multiple Choice Worth 2 points)
(Theoretical Probability MC)
A fair, 6-sided die is rolled 50 times. Predict how many times it will land on a number greater than 3.
1/2
5
25
50
Answer:
A 1/2
Step-by-step explanation:
was on my test trust me on this one
Compute $2^{-3}\cdot 3^{-2}$.
The value of the algebric expression [tex]2^{-3} \cdot 3^{-2}$ is $\frac{1}{72}[/tex].
To compute the expression [tex]2^{-3} \cdot 3^{-2}[/tex], we can simplify each term separately and then multiply the results.
First, let's simplify [tex]2^{-3}[/tex]. The exponent -3 indicates that we need to take the reciprocal of the base raised to the positive exponent 3. Therefore, [tex]2^{-3} = \frac{1}{2^3} = \frac{1}{8}[/tex].
Next, let's simplify 3^{-2}. Similar to before, the exponent -2 means we need to take the reciprocal of the base raised to the positive exponent 2. So, [tex]3^{-2} = \frac{1}{3^2} = \frac{1}{9}[/tex].
Now that we have simplified both terms, we can multiply them together: [tex]\frac{1}{8} \cdot \frac{1}{9}[/tex]. When multiplying fractions, we multiply the numerators together and the denominators together. So, [tex]\frac{1}{8} \cdot \frac{1}{9} = \frac{1 \cdot 1}{8 \cdot 9} = \frac{1}{72}[/tex].
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Please answer ASAP I will brainlist
The solution to the system is (a) a = 4/5, b = 5, c = -4 and d =-4
How to determine the solution to the systemFrom the question, we have the following parameters that can be used in our computation:
The augmented matrix
Where, we have
[tex]\left[\begin{array}{cccc|c}1&0&0&0&4/5\\0&1&0&0&5\\0&0&1&0&-4\\0&0&0&1&-4\end{array}\right][/tex]
From the above, we have the diagonals to be 1
And other elements to be 0
This means that the equation has been solved
So, we have
a = 4/5, b = 5, c = -4 and d =-4
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NO LINKS!! URGENT HELP PLEASE!!!
1. Find the sum of the measures of the interior angles of the indicated polygons. (NOT MULTIPLE CHOICE)
a. heptagon
b. 13-gon
2. The sum of the measures of the interior angles of a convex polygon is 1260°. Classify the polygon by the number of sides.
1a. Sum of interior angles of a heptagon:
[tex]\displaystyle \sf \text{Sum of interior angles} = (7 - 2) \times 180^\circ = 900^\circ[/tex]
1b. Sum of interior angles of a 13-gon:
[tex]\displaystyle \sf \text{Sum of interior angles} = (13 - 2) \times 180^\circ = 1980^\circ[/tex]
2. Number of sides for a polygon with a sum of interior angles of 1260°:
[tex]\displaystyle \sf (n - 2) \times 180^\circ = 1260^\circ[/tex]
[tex]\displaystyle \sf n - 2 = \frac{1260^\circ}{180^\circ}[/tex]
[tex]\displaystyle \sf n - 2 = 7[/tex]
[tex]\displaystyle \sf n = 7 + 2 = 9[/tex]
Therefore, the sum of the measures of the interior angles of a heptagon is 900°, the sum of the measures of the interior angles of a 13-gon is 1980°, and the polygon with a sum of interior angles of 1260° is a nonagon (9-gon).
[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]
♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]
Answer:
1. a. 900° b. 1980°
2. Nonagon
Step-by-step explanation:
In order to find the interior angles of a polygon, use the formula,
Sum of interior angles = (n-2)*180°
For
a. Heptagon
no of side =7
The sum of the interior angles of a heptagon:
(7-2)*180 = 900°
b. 13-gon
no. of side =13
The sum of the interior angles of a 13-gon:
(13-2)*180 = 1980°
2.
The sum of the interior angles of a convex polygon is 1260°,
where n is the number of sides.
In this case, we have
1260 = (n-2)*180
1260/180=n-2
n-2=7
n=7+2
n=9
Therefore, the polygon has 9 sides and is classified as a nonagon.
Question 6 of 22 The graph of a function never has two different points with the same x-coordinate because A. the graph of a function cannot be a straight line. • B. each input value is mapped to a single output value • C. the graph of a function is a vertical line. • D. each input value is mapped to more than one output value.
Which statement correctly compares the centers of the distributions?
Frequency
10
8
6
Class Sizes at East Hills HS
24 26 28 30 32 34 36 38 40 42 44
Frequency
2864 NO
10
Class Sizes at Southview HS
0
24 26 28 30 32 34 36 38 40 42 44
OA. The median of Southview HS is greater than the median of East
Hills HS.
B. The range of East Hills HS is greater than the range of Southview
HS.
C. The mean of East Hills HS is greater than the mean of Southview
HS.
OD. The mean of Southview HS is greater than the mean of East Hills
HS.
The correct statement is C. The mean of East Hills HS is greater than the mean of Southview HS. So, option C is the correct answer.
To compare the centers of the distributions, we need to consider the measures of central tendency such as the median and the mean.
Looking at the given information about the class sizes at East Hills HS and Southview HS:
East Hills HS class sizes: 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44
Southview HS class sizes: 0, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44
Let's compare the measures of central tendency:
Median: The median is the middle value of a dataset when arranged in ascending or descending order. In this case, both datasets have an odd number of values, so the median is the middle value.
For East Hills HS: Median = 34
For Southview HS: Median = 34
Therefore, the medians of both distributions are the same.
Mean: The mean is calculated by summing all the values in the dataset and dividing by the total number of values.
For East Hills HS: Mean = (24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44) / 11 ≈ 35.727
For Southview HS: Mean = (0 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44) / 12 ≈ 33.667
Therefore, the mean of East Hills HS is greater than the mean of Southview HS.
Based on the comparisons, the correct statement is:
C. The mean of East Hills HS is greater than the mean of Southview HS.
So, option C is the correct answer.
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The question is asking for comparison of the centers and range of two data sets - the class sizes at two different high schools. Because no specific numeric data given for the mean and median of both school sizes, it's not possible to definitively choose an answer. Theoretically, if Southview has a higher concentration at larger class sizes, its median and mean might be larger.
Explanation:This question refers to comparing the statistical centers (mean and median) and range of two data sets, which are the class sizes at East Hills High School and Southview High School. The centers and range of a data distribution tell us about the typical values, variety, and spread in the data set.
Without actual numbers (i.e., mean and median) for both the East Hills HS and Southview HS distributions, we can't definitively answer this question. However, let's assume that the representations provided suggest that Southview HS has a higher concentration of students in larger class sizes. In that case, the mean and median for Southview HS could be greater than those for East Hills HS, which would suggest option A and D. With regards to the range, if the minimum and maximum values of class sizes are the same in both schools, then the range, which is the difference between the maximum and minimum, would be the same. Therefore, option B wouldn't be accurate. However, as previously mentioned, this can only be suggestive as actual numbers are required for a definite answer.
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When is it better to have a session pass versus just paying general admission?
After 8 visits: How much would each person pay? Show your work for calculations.
Session Pass______? General Admission______?
After 10 visits: How much would each person pay? Show your work for calculations.
Session pass _____? General Admission_____?
After 8 visits: General Admission: Each person would pay $200. Annual Public Session Pass: Each person would pay $299.
After 10 visits: General Admission: Each person would pay $250. Annual Public Session Pass: Each person would still pay $299.
To determine when it is better to have a session pass versus just paying general admission, we need to compare the costs for each option.
General Admission with skate rental: $25
Annual Public Session Pass with skate rental: $299
After 8 visits:
For General Admission, the cost per visit would be $25 per visit.
Total cost for 8 visits: $25 x 8 = $200
For the Annual Public Session Pass, the cost is a one-time payment of $299, regardless of the number of visits. Therefore, after 8 visits, the cost remains the same at $299.
Therefore, after 8 visits, it would be more cost-effective to have the Annual Public Session Pass as the cost per person would be $299.
After 10 visits:
For General Admission, the cost per visit remains at $25 per visit.
Total cost for 10 visits: $25 x 10 = $250
For the Annual Public Session Pass, the cost remains the same at $299, regardless of the number of visits.
Therefore, after 10 visits, it would still be more cost-effective to have the Annual Public Session Pass as the cost per person would still be $299.
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The following question may be like this:
When is it better to have a session pass versus just paying general admission? After 8 visits: How much would each person pay? Show your work for calculations. Session Pass______? General Admission______?After 10 visits: How much would each person pay? Show your work for calculations.Session pass _____? General Admission_____?
GENERAL ADMISSION WITH SKATE RENTAL $25
ANNUAL PUBLIC SESSION PASS WITH SKATE RENTAL $299
LOCKER RENTAL-ONE TIME USE $5
HELMET RENTAL $5
SKATE HELPER-PER HOUR $15
Solve 4563÷257 using long division method show the steps
2 5 7 ÷ 4 5 6 3
- 2 5 7
1993
- 1 7 9 9
Answer:
194