Most of the night sky would be dark with only a few stars if the solar system were moved on the edge of galaxy.
What we can see at night if sun and earth moved to the edge?If the Sun and Earth were moved on the edge of an elliptical galaxy, we can see most of dark and few stars in the sky at night because stars are present at large number at the center of galaxy and fewer at th edges.
So we can conclude that most of the night sky would be dark with only a few stars if the solar system were moved on the edge of galaxy.
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A bullet having the mass of 110g is fired. If it's velocity is 50m/s, calculate the kinetic energy
[tex]\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2\\\\~~~~~=\dfrac 12 \cdot 110 \times 10^{-3} \cdot 50^2\\\\~~~~~=137.5~ \text{J}[/tex]
Answer: 137.5 Joules
Explanation:
The SI units for kinetic energy is Joules, the SI units for mass is kilograms, and the SI units for velocity is meters per second. We are given the mass in grams, so we must convert it to kilograms. There are 1,000 grams in 1 kilogram:
[tex]110g*\frac{1kg}{1000g} =0.11kg[/tex]
Kinetic energy is the energy the system has due to its motion. It is defined to be:
[tex]KE=\frac{1}{2} mv^2[/tex]
Plug everything in:
[tex]KE=\frac{1}{2} (0.11kg)(50m/s)^2[/tex]
[tex]KE=137.5J[/tex]
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
Answer:
Explanation:
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
the base is a polygon and its faces are triangles (cone, cube, cylinder, pyramid, rectangular prism
What is the density of the unknown liquid?
The density of the unknown liquid is 650.67 kg/m³
Determine the density of the unknown liquidFirst step : determine the mass in air
The Tension in air = mg
therefore Mass in air ( m ) = Tension in air / g
= 3.78 kg
Considering Tension in water
T = 29.6 N
29.6 = 4/3 * πR³ * ( р - б ) g ----- ( 1 )
where : р = mass density, б = water density
Considering Tension in other liquid
T = 19.1 N
19.1 = 4/3 * πR³ * ( р - б' ) g ------ ( 2 )
Final step : Determine the density of the unknown liquid
Divide equation ( 1 ) by equation ( 2 )
1.54 = ( р - б ) / ( р - б' )
0.54 р + б = 1.54 * б'
therefore ( б' ) density of uknown liquid
= 650.67 Kg/m³
Hence we can conclude that The density of the unknown liquid is 650.67 kg/m³
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in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?
The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
Given the following data:
Charge = [tex]-2.35 \times 10^{-6}[/tex] C.
Distance = 0.100 m.
Scientific data:
Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]
How to calculate the net force.In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
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Answer:
6.2
Explanation:
acellus
The girl in the picture is using an oar to push the water backwards. At the same time the canoe iS moving forward with
the same amount of force. Which of Newton's Laws would explain why for every action there is an opposite and equal
reaction?
Newton's First Law of Motion
Newton's Second Law of Motion
C) Newton's Third Law of Motion
Newton's Thired Law of Motion
A 8.2 kg solid sphere, made of metal whose density is 2300 kg/m3, is suspended by a cord. When the sphere is immersed in a liquid of unknown density, the tension in the cord is 23 N. The density of the liquid is
The density of the liquid is 1470.43 kg/m³. Density is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
What is density?Density is defined as the mass per unit volume. The mass and density relation is given as;
mass = density × volume
The given data in the problem is as ;
m is the mass of a solid sphere=8.2 kg
[tex]\rm \rho_s[/tex] is the density of the metal= 2300 kg/m³
T is the tension in the cord = 23 N.
The volume of the liquid is found as;
[tex]\rm V_{sphere} = \frac{m}{\rho} \\\\ \rm V_{sphere} =\frac{8.2}{2300} \\\\ \rm V_{sphere} = 0.00356 \ m^3[/tex]
The volume of the sphere is equal to the volume displaced;
Volume displaced = 0.00356 m³
The buoyant force is found as;
[tex]\rm F_B = \rho g V \\\\[/tex]
From the given condition it is observed that the weight of the sphere is equal to the sum of buoyancy force and the tension in the cord.
[tex]\rm mg = \rho g V+T \\\\ 8.2 \times 9.81 = \rho \times 9.81 \times 0.00356+23 \\\\\ 80.442=\rho \times 0.0349 +23 \\\\ \rho = 1645.90 \ kg/m^3[/tex]
Hence the density of the liquid is 1645.90 kg/m³.
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The force acting on a body of mass 200 g is equal to 0. Determine the velocity of the body 3 seconds after the start of the observation, if at the initial moment of the observation its velocity is 5 m / s?
Answer:
5 m/sExplanation:
Formula (Force)
F = maBut, a = v - u / t [First Equation of Motion]F = m (v - u / t)We have the values of :
F = 0m = 200 g = 0.2 kgt = 3 su = 5 m/sSubstitution
0 = 0.2 (v - 5 / 3)v - 5 / 3 = 0v - 5 = 0v = 5 m/sCalculate the solar angle for the day at 10am and 2pm individually for the location of 21.23 south latitude on the 18th march 1993 (Assume it is non leap year)
Based on the latitude and time of the place, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
What is the solar hour angle?The solar hour angle of a point on the earth’s surface is the angle through which the earth would turn to bring the meridian of the point directly under the sun.
The rotation of the earth on its axis is 15° per hour where before noon is negative and after noon is positive. For example, at 10:00 a.m. local apparent time the hour angle is −30°.
Therefore, based on the latitude and time, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
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my son needs help the question is What is the Law of Conservation of Mass and Energy
Answer:
Explanation:
The total amount of mass and energy in the universe is constant.....energy may change to mass and mass may change to energy, but the total is a constant.
3. The property of sound called intensity is proportional
to the rate at which energy flows through
A.an area perpendicular to the direction of
propagation.
B.an area parallel to the direction of propagation.
C.a cylindrical tube.
D.a sound wave of a certain frequency.
Answer:
A. an area perpendicular to the direction of propagation.
Explanation:
The property of sound called intensity is proportional
to the rate at which energy flows through an area perpendicular to the direction of propagation.
An industrial/organizational psychologist wants to improve worker productivity for a client firm, but first he needs to gain a better understanding of the life of the typical white-collar professional. Fortunately, he has access to the 2020 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, which surveyed a sample of 650 white-collar professionals (250 legal professionals and 400 other professionals).
One of the survey questions was, "During the average workday, how many hours do you spend attending meetings?" For the subsample of legal professionals (n = 200), the mean response was M = 2.0 hours, with a sample standard deviation of s = 5.1 hours.
The estimated standard error is = 0.323.
The psychologist can be 99% confident that the interval from _____ to _____ includes the unknown population mean µ.
Based on the research data, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.
What is confidence Interval?A confidence interval is a range of values within which a researcher can be fairly certain that the true value of the mean can be found.
The confidence Interval of the survey above is calculated using the formula:
[tex] x ± z( σ/√n)[/tex]
where
x is the sample mean,σ is the population standard deviation,n is the sample size, and z is the z-value for the selected confidence level.From the data provided;
x = 2.0
σ = 5.1
n = 200
z = 2.576 for 99% confidence
Therefore, the confidence Interval is:
[tex] 2.0 ± 2.576( 5.1/√200)[/tex]
Confidence interval = 2.0 ± 0.93.
Therefore, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.
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find the potential,electric field,charge density.
Answer:
The answer is Model the charge distribution as the sum of infinitesimal point charges, dq, and add together the electric potentials, dV, from all charges, dq. ...
Calculate the electric field (either as a integral or from Gauss' Law), and use: ΔV=V(→rB)−V(→rA)=−∫BA→E⋅d→r.
Explanation:
brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width. determine the difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces brainly
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.
Difference in pressure between the top and bottom of the wingspanThe difference in pressure between the top and bottom of the wingspan is calculated as follows;
ΔP = P(top) - P(bottom)
Area of the wingspanA = bh
A = 2.7 m x 0.27 m
A = 0.729 m²
Weight of the Andean condorW = mg
W = 9 x 9.8
W = 88.2 N
Pressure at the top surface of condor's wingsThe pressure at the top surface of condor's wings is due to atmospheric pressure
P(top) = 14.7 Psi = 101,325 Pa
Pressure at the bottom surface of condor's wingsThe pressure at the bottom surface is due to weight of andean condor.
P = W/A
P(bottom) = 88.2/0.729
P(bottom) = 120.99 Pa
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;
ΔP = P(top) - P(bottom)
ΔP = 101,325 Pa - 120.99 Pa
ΔP = 101,204 Pa
The complete question is below;
An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.
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SOMEONE PLS HELP THANK YOU
Does magnitude effect the strength of attraction more than distance?
Or
Does distance effect the strength of attraction more than magnitude?
Explanation:
Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects.
The diagram shows a box being pulled along a horizontal surface with a force of 200.0 N.
Calculate the work done on the box to pull it a distance of 5.0 m.
Answer:
The formula for work is
W= fd
work= force X distance
so, this is
200 X 5 =1,000
and the unit for work is Joules
so.. 1,000 joules
Explanation:
hope that helps!
An 80.0 kg merry-go-round of radius 1.20 m is accelerating horizontally from rest by a constant force of 70.0 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 5.00 s. (Assume it is a solid cylinder.)
The kinetic energy of the merry-go-round after 5.00 s, when a constant force is applied tangentially to it, is determined as 3,069.5 J.
Conservation of angular momentumThe kinetic energy of the merry-go-round is determined by applying the principle of conservation of angular momentum as follows;
Iα = rF
where;
I is moment of inertia of the merry-go-round (solid cylinder)I = ¹/₂mr²
I = ¹/₂ x 80 x (1.2)²
I = 57.6 kgm²
α = (rF)/I
α = ( 1.2 x 70) / (57.6)
α = 1.46 rad/s²
Tangential acceleration of the merry-go-rounda = αR
a = 1.46 x 1.2
a = 1.752 m/s²
Velocity of the merry-go-roundThe velocity of the merry-go-round after 5 s is calculated as follows;
v = u + at
v = 0 + (1.752x 5)
v = 8.76 m/s
Kinetic energy of the merry-go-roundK.E = ¹/₂mv²
K.E = ¹/₂ x 80 x 8.76²
K.E = 3,069.5 J
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Question 4 (1 point) ✓ Saved
The term 'recruitment' refers to the process by which people decide on the kinds of
environments they will join.
True
False
PLEASE HELP
Which of the following is an example of a chemical reaction?
hydrogen peroxide and yeast are combined, producing lots of bubbles and heat
atoms of silver are bonded together to make a silver nugget
heat is applied to melt chocolate chips
red and blue paints are mixed to make purple paint
Oxygen is needed by all cells of most organisms for the release of
energy from what in photosynthesis?
Answer:
From the SUN
Explanation:
Hope it helps!!!
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How might a quota on foreign cars affect US economy?
Answer:
The numerical limits imposed on imported goods through quotas ultimately leads to higher prices paid by consumers. Essentially, the import quota prevents or limits domestic consumers from buying imported goods. The import quota reduces the supply of imports.
Explanation:
What is the rate of acceleration if the object has a force of 857 N and a mass of 8000 kg
A 2.8 F capacitor and a 3,440
Ω
resistor are connected to a battery of voltage 5 V as shown in the circuit. After
closing the switch, how long will it take for the capacitor voltage to be 45 % of
the battery voltage?
Express your answer in seconds (s)
The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
Discharge of the capacitor voltage
The rate at which the capacitor voltage discharges is given by the following formula;
[tex]V = V_0(1 - e^{-t/RC})[/tex]
Where;
V₀ is the initial voltageV is the final voltaget is the time of dischargeR is resistanceC is capacitanceThe final voltage = 0.45 x 5 V = 2.25 V
[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]
Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
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A 3.0-kg block moves up a 40° incline with constant speed under the action of a 26-N force acting up and parallel to the incline. What magnitude force must act up and parallel to the incline for the block to move down the incline at constant velocity?
Explanation:
Sooooo, first,
Constant Speed means that the body isn't accelerating.
a= 0
Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.
The force that pulls the body downwards is given by,
F = mgsin40°
F= 18.898N
P -(F+Fr) = ma, but, a= 0
P = F + Fr
Fr = 26-18.898
= 7.102N
If the block must move down the incline, Q and Fr will act in the same direction.
Q + Fr = F
Q = 11.796N
a coil of standard annealed copper having a resistance of 50 ohms at 15° is embedded in the core of a large transformer after the transformer has been in operation for several hours the resistance of the material is measured as 58 ohms determine its temperature the temperature coefficient of resistance of the conductor material is 0.04 250 degree celsius at 0 degrees Celsius.
determine its temperature?
The temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.
Relationship between resistance and temperature
The relationship between resistance and temperature is given as;
R = R₀( 1 + αΔθ)
From the first resistance, we will have the following equation,
R₁ = R₀( 1 + αΔθ)
50 = R₀(1 + 15α) ------ (1)
From the second resistance, we will have the following equation,
58 = R₀(1 + αT) ------ (2)
Divide (1) by (2)
[tex]\frac{50}{58} = \frac{R_0(1 + 15\alpha)}{R_0(1 + T\alpha)} \\\\\frac{50}{58} = \frac{(1 + 15\alpha)}{(1 + T\alpha)} \\\\50(1 + T\alpha) = 58(1 + 15\alpha)\\\\50 + 50T\alpha = 58 + 870\alpha \\\\50(0.0425)T = (58- 50) + 870(0.0425)\\\\2.125T = 44.975\\\\T = 21.2\ ^0C[/tex]
Thus, the temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.
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A negative charge of -6.0x10-6 C exerts an
attractive force of 65 N on a second charge that is
0.050 m away. What is the magnitude of the second
charge?
The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart How to determine the second charge Charge 1 (q₁) = –6×10¯⁶ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 0.05 mForce (F) = 65 NCharge 2 (q₂) =?F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Divide both side by Kq₁
q₂ = Fr² / Kq₁
q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)
q₂ = +3.0×10¯⁶ C (since the force is attractive)
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The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?
Answer:
Explanation:
This depends on the height.
Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.
if every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?
Answer:
Yes, It does mean that there was a Red Giant in the middle of the galaxy.
Explanation:
The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns
Changes of state
Study the heating curve shown.
Which statement is best supported by the information in
the heating curve?
Heating Curve of a Substance
T
U
O At segment T-U, the substance changes from a liquid
to a gas and does not change temperature.
At segment T-U, the substance changes from a gas
to a liquid and changes temperature.
O At segment Q-R, the substance releases heat and
increases in temperature.
O At segment Q-R, the substance absorbs heat and
decreases in temperature.
Temperature (Cº)
R
20
s
o
Heat Added (J)
Answer:
liquid to a gas and doesn't change T
Explanation:
that part of the line has no slope
Answer:
A. At segment T-U, the substance changes from a liquid to a gas and does not change temperature.
Explanation:
A light plastic cart and a heavy steel cart are both pushed with the same force for 1.0 s, starting from rest. After the force is removed, the momentum of the light plastic cart is ________ that of the heavy steel cart.
Answer:
my friend give options .............