At a sale, dresses were sold for $17 each. This price was 85% of a dress's original price. How much did a dress originally cost?

One-third of the worker bees forage for pollen and nectar.

What is percentage?

Percentage is a way of expressing a number as a fraction of 100. It is often denoted by the symbol "%". For example, 50% means "50 out of 100" or "50/100" or "0.5 as a decimal". Percentages are commonly used to express the proportion or relative size of a quantity with respect to another quantity. They can be used in a wide range of contexts, including finance, statistics, science, and everyday life.

Here out of the 18,000 worker bees, 6,000 forage for pollen and nectar.

To calculate the part of worker bees that forage for pollen and nectar, we can use the following formula:

Part = (Number of bees foraging / Total number of worker bees) x 100

Plugging in the numbers, we get:

Part = (6,000 / 18,000) x 100

Part = 0.333 x 100

Part = 33.3%

Therefore, 33.3% or approximately one-third of the worker bees forage for pollen and nectar.

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Answer:

Step-by-step explanation:

5)

Draw a right triangle with a hypotenuse of 60 km, a base angle of 60°, and the base leg of x.

Find x, the distance it traveled to the east:

cos60° = x/60

x = 60(cos60) = 30 km

Answer:

12.7

Step-by-step explanation:

3x+10x-15=180

13x=165

x=12.69.....

x=12.7

the equation y=1 does not represent a direct variation, whereas the other three equations given do represent direct variation.

What is Direct variation?

Direct variation is a relationship between two variables in which one is a constant multiple of the other. This means that if one variable increases, the other variable will also increase by a proportional amount. In other words, direct variation can be represented by the equation y=kx, where k is the constant of variation.

Out of the four equations given, the equation y=1 does not represent a direct variation. This is because the equation is not a function of x. In other words, no matter what value of x we choose, y will always be equal to 1. This means that the two variables, x and y, are not related to each other in any way. Therefore, there is no constant k that can be multiplied by x to get y.

On the other hand, the other three equations do represent direct variation. For example, in the equation y=x, y is equal to x multiplied by the constant k=1. Similarly, in the equation y=-5x, y is equal to x multiplied by the constant k=-5. Finally, in the equation y=0.9x, y is equal to x multiplied by the constant k=0.9.

In summary, the equation y=1 does not represent a direct variation, whereas the other three equations given do represent direct variation.

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The experimental probability of selecting a green marble on the next attempt is 1/6 or approximately 0.1667 or 16.67%.

What is probability?

Probability is a measure of the likelihood of an event occurring.

The experimental probability of an event happening is calculated by dividing the number of times the event occurs by the total number of trials or attempts.

In this case, Diane has already selected 2 green marbles and 10 other marbles from the bag. So, the total number of marbles left in the bag is 12.

Since there are 2 green marbles left in the bag, the probability of selecting a green marble on the next attempt is:

2 (number of green marbles) / 12 (total number of marbles) = 1/6

So, the experimental probability of selecting a green marble on the next attempt is 1/6 or approximately 0.1667 or 16.67%.

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The value of x in the given inequality is x is greater than or equal to 16.

Using symbols like (less than), > (greater than), (less than or equal to), or (greater than or equal to), an inequality compares two values or expressions and illustrates their connection (not equal to). When values or phrases are being compared, it is said that there exist inequalities. For instance, the inequality x + 2 7 signifies that "x plus 2 has a value less than 7."

The given inequality is x - 4 ≥ 12.

Add 4 on both sides of the inequality:

x - 4 + 4 ≥ 12 + 4

x ≥ 16

Hence, the value of x in the given inequality is x is greater than or equal to 16.

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His results are in the table  are-

Southeast = 36.4%

Southwest  = 9.1%

West = 18.2%

Midwest = 20%

What is arithmetic?

Arithmetic is an elementary part of mathematics that consists of the study of the properties of the traditional operations on numbers—addition, subtraction, multiplication, division, exponentiation, and extraction of roots.

Here, we have

: Leon is interested in the relationships between geographic region and political affiliation. Leon collected data about the political parties of US senators at that time and the regions of the US that they represent.

Southeast = 20/55 = 36.4%

Southwest = 5/55 = 9.1%

West = 10/55 = 18.2%

Midwest = 11/55 = 20%

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The value of variable x=4 units in the given figure.

A right triangle is a type of triangle that has one angle measuring exactly 90 degrees. The side opposite to the right angle is called the hypotenuse, while the other two sides are called the legs or catheti. The lengths of the legs and the hypotenuse of a right triangle are related by the Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

From the given figure;

Tan60°=p/1

p=1.732 units

The smaller triangle is right angle

h²=p²+b²

h=√1²+1.732²

h=2units

In the bigger triangle, angle subtended by base is 60 (vertically opposite angle)

Using the trigonometric function

Cos60°=2/x

1/2=2/x

x=4units

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We have verified the identity of the expression 1 + cos(x) / cot(x) + cos(x) = sec(x) using the Pythagorean Identity.

The mathematical subject of trigonometry is the study of the connections between the angles and sides of triangles.

let's rewrite the expression using sine and cosine:

1 + cos(x) / cot(x) + cos(x) = sec(x)

cot(x) is the same as cos(x)/sin(x), so we can substitute:

1 + cos(x) / (cos(x)/sin(x)) + cos(x) = sec(x)

Simplifying the expression in the denominator:

1 + cos(x) * (sin(x)/cos(x)) + cos(x) = sec(x)

Canceling out the cos(x) terms in the numerator:

1 + sin(x) + cos(x) = sec(x)

Now, let's use the Pythagorean Identity:

sin²(x) + cos²(x) = 1

Divide both sides by cos²(x):

tan²(x) + 1 = sec²(x)

Substitute tan(x) for sin(x)/cos(x):

(sin²(x)/cos²(x)) + 1 = sec²(x)

Multiply both sides by cos²(x):

sin²(x) + cos²(x) = cos²(x)sec²(x)

Substitute cos²(x) with 1 - sin²(x):

sin²(x) + (1 - sin²(x)) = (1 - sin²(x))sec²(x)

Simplify:

1 = sec²(x)

Taking the square root of both sides:

1 = sec(x)

Therefore, the identity is verified.

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The difference in the account balance between a simple interest and a compound interest over an 8-year time period, rounded to the nearest cent, is $12,189.02.

To calculate the difference in the account balance between simple interest and compound interest over 8 years, we first need to determine the final balance for each case.

Simple Interest:

Simple interest is calculated as a percentage of the initial principal (or the original amount deposited) and is paid only on the principal amount. The formula for simple interest is:

I = P * r * t

where I is the interest earned, P is the principal amount (in this case, $5,000), r is the annual interest rate (as a decimal), and t is the time period in years.

For this problem, the interest rate is given as 31%, which is equivalent to 0.31 as a decimal. Therefore, we have:

I = $5,000 * 0.31 * 8 = $12,400

The final balance for simple interest is the sum of the principal and the interest earned:

Final balance (simple interest) = $5,000 + $12,400 = $17,400

Compound Interest:

Compound interest is interest that is calculated on both the principal amount and any accumulated interest. The formula for compound interest is:

A = P * (1 + r/n)^(n*t)

where A is the final amount, P is the principal amount, r is the annual interest rate (as a decimal), n is the number of times per year that interest is compounded, and t is the time period in years.

For this problem, the interest rate is 31% and the account is compounded annually, so n = 1. Therefore, we have:

A = $5,000 * (1 + 0.31/1)^(1*8) = $29,589.02

The final balance for compound interest is the amount we just calculated:

Final balance (compound interest) = $29,589.02

The difference in the two account balances is:

$29,589.02 - $17,400 = $12,189.02

Therefore, the difference in the account balance between a simple interest and a compound interest over an 8-year time period, rounded to the nearest cent, is $12,189.02.

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Answer:

(b/2)² + 1 = x² - 3x + (b/2)²

b²/4 + 1 = x² - 3x + b²/4

b²/4 - b²/4 = x² - 3x - 1

x² - 3x - 1 = 0

x² - 3x = 1

x² - 3x + 9/4 = 1 + 9/4

(x - 3/2)² = 13/4

x - 3/2 = ±(√13/4)

x = ±√13/2 + 3/2

so the number that must be added will be 3/2

Step-by-step explanation:

To graph the boundary lines of the linear inequalities, we need to first set up the inequalities based on the given information. Let x be the number of popcorn bags and y be the number of cotton candy bags. Then we have:

Chris needs at least 7 bags of popcorn, so the inequality for popcorn is x ≥ 7.

Chris has $56 to spend, so the total cost of popcorn and cotton candy cannot exceed $56, which gives the inequality 3x + 7y ≤ 56.

To graph the boundary lines, we need to first graph the lines corresponding to these two inequalities:

The line x = 7 is a vertical line passing through the point (7,0), because the only restriction on the popcorn is that Chris needs at least 7 bags.

The line 3x + 7y = 56 is a diagonal line with x-intercept 56/3 and y-intercept 8, because these are the points where the line intersects the x and y axes, respectively.

We can now plot these lines on a coordinate plane:

|

8 | x = 7

| o

7 | |

| | 3x + 7y = 56

6 | |

| o

5 |

| o

4 |

|

3 |

|

2 | o

|

1 | o

|____________________________

1 2 3 4 5 6 7 8 9 10

The shaded region below and to the left of the diagonal line represents the solution set to the inequalities, because it includes all the points where Chris can buy at least 7 bags of popcorn and stay within his budget.

Finally, we can plot the given points and identify which ones are part of the solution set:

(3, 7) is not part of the solution set because it is above the diagonal line.

(2, 2) is part of the solution set because it is below and to the left of the diagonal line.

(8, 1) is not part of the solution set because it is above the diagonal line.

(10, 2) is not part of the solution set because it is above the diagonal line.

(5, 5) is part of the solution set because it is below and to the left of the diagonal line.

Therefore, the solution set consists of the points (2, 2) and (5, 5).

The probability that a randomly selected lobster weighs more than 2.5 lb is 0.0026.

Let X be the weight of a randomly selected Maine lobster. We know that X is normally distributed with mean μ = 1.8 lb and standard deviation σ = 0.25 lb.

We need to find the probability that a randomly selected lobster weighs

a) less than 1.5 lb

b) between 1.6 and 2 lb

c) more than 2.5 lb

To solve these problems, we need to standardize the variable X using the standard normal distribution

Z = (X - μ) / σ

a) To find the probability that a randomly selected lobster weighs less than 1.5 lb, we need to find P(X < 1.5). Standardizing X, we have

Z = (1.5 - 1.8) / 0.25 = -1.2

Using a standard normal distribution table or calculator, we find that P(Z < -1.2) = 0.1151.

Therefore, the probability that a randomly selected lobster weighs less than 1.5 lb is 0.1151.

b) To find the probability that a randomly selected lobster weighs between 1.6 and 2 lb, we need to find P(1.6 < X < 2). Standardizing X, we have

Z1 = (1.6 - 1.8) / 0.25 = -0.8

Z2 = (2 - 1.8) / 0.25 = 0.8

Using a standard normal distribution table or calculator, we find that P(-0.8 < Z < 0.8) = 0.5328

Therefore, the probability that a randomly selected lobster weighs between 1.6 and 2 lb is 0.5328.

c) To find the probability that a randomly selected lobster weighs more than 2.5 lb, we need to find P(X > 2.5). Standardizing X, we have:

Z = (2.5 - 1.8) / 0.25 = 2.8

Using a standard normal distribution table or calculator, we find that P(Z > 2.8) = 0.0026.

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Answer:

The volume of a cylinder is given by the formula: V = πr^2h where r is the radius and h is the height. Substituting the given values, we get: V = π(4 in)^2(3 in) V = π(16 in^2)(3 in) V = 48π in^3 Therefore, the volume of wax needed to make one candle is 48π cubic inches. To find the amount of wax needed for 120 candles, we can multiply the volume of one candle by the number of candles: Amount of wax = 48π in^3/candle × 120 candles Amount of wax = 5760π in^3 So the company will need 5760π cubic inches of wax to make 120 candles.

Answer:

1)55 and for 2) 35

Step-by-step explanation:

All you have to do is and for perimeter.

a. The two parameters of the gamma distribution are

shape parameter (α) and velocity parameter (β).

The mean of the gamma distribution = α/β and the standard deviation = sqrt(α)/β.

mean = 5 seconds

standard deviation =2.5 seconds.

α/β = 5 (equation 1)

sqrt(α)/β = 2.5 (equation 2)

Squaring equation 2 and multiplying both sides by β^2 yields:

[tex]α = 6.25β^2[/tex]

Substituting this value of α into Equation 1 yields:

[tex]6.25β^2/β = 5[/tex]

Simplified, it looks like this:

β = 0.8

Substituting this value of β into Equation 1 yields:

a = 4

Therefore, the parameters of the gamma distribution are α = 4 and β = 0.8.

b. I need to find the probability that this software will take more than 10 seconds to run.

The probability density function (PDF) of the gamma distribution is given by

[tex]f(x) = (β^α * x^(α-1) * e^(-βx)) / Γ(α)[/tex]

where Γ(α) is the gamma function.

Using the values ​​of α and β obtained in part (a), we can write the PDF as

[tex]f(x) = (0.8^4 * x^(4-1) * e^(-0.8x)) / Γ(4)[/tex]

I need to find the probability that the execution time exceeds 10 seconds. This can be written as:

P(X > 10) = ∫(10 to infinity) f(x) dx

Using software or a calculator, we can evaluate this integral to get:

P(X > 10) = 0.0559 (rounded to four decimal places)

Therefore, the probability is 0.0559.

c.Since it has already taken more than 5 seconds, we need to find the probability of this software where will take more than 10 seconds to run.

This is a conditional probability and should be calculated using Bayes' theorem.

P(X > 10 | X > 5) = P(X > 10 and X > 5) / P(X > 5)

The numerator can be simplified to

P(X > 10 and X > 5) = P(X > 10)

Using the results obtained in part (b), we can write

P(X > 10 and X > 5) = 0.0559

The denominator can be written as:

P(X > 5) = ∫(5 to infinity) f(x) dx

Using the same PDF as before, we can evaluate this integral and get:

P(X > 5) = 0.2615 (rounded to four decimal places)

Substituting these values ​​into the conditional probability formula gives:

P(X > 10 | X > 5) = 0.0559 / 0.2615

Simplified, it looks like this:

P(X > 10 | X > 5) = 0.214

Therefore, the probability that his single run of this software took longer than 5 seconds to take longer than 10 seconds is 0.214 (rounded to three decimal places).

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We can find y by solving for the length of CN: CN = Sy - BC = 600 - 0 = 600 So the values of x and y are:
x = 0 , y = 600

First, we can look at the corresponding sides of triangle ABC and triangle MNC. Since we know that these triangles are

similar (as indicated by the ~ symbol), we can set up the following proportion:

AB/AM = BC/CN

We can substitute in the given values for these lengths:

4x/2x = (Lv + Sy)/Sy

Simplifying this equation, we can cancel out the common factor of 2x on the left side:

2 = (Lv + Sy)/Sy

Multiplying both sides by Sy, we can isolate the sum of Lv and Sy:

2Sy = Lv + Sy

Combining like terms, we get:

Sy = Lv

So we now know that Sy is equal to Lv, which is 600.

To solve for x and y, we can use the fact that corresponding sides are in proportion. Specifically, we can look at the ratio of the length of AB to the length of AM:

AB/AM = 4x/Lv

Substituting in the values we know, we get:

AB/AM = 4x/600

We can also look at the ratio of the length of BC to the length of CN:

BC/CN = 2x/Sy

Substituting in the values we know, we get:

BC/CN = 2x/600

Since AB and BC are corresponding sides in triangle ABC and AM and CN are corresponding sides in triangle MNC, we

know that these ratios must be equal:

4x/600 = 2x/600

Simplifying this equation, we get:

4x = 2x

Subtracting 2x from both sides, we get:

2x = 0

Dividing both sides by 2, we get:

x = 0

Since x is 0, we can't solve for it any further. However, we can solve for y by using the ratio we found earlier:

AB/AM = 4x/600 = 0/600 = 0

Since AB is 0, we know that BC is also 0 (since the sum of the lengths of the sides of a triangle must be greater than 0).

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Answer:

a 2.009, 2.15, 2.7

b 3.2, 3.342, 3.45

c 17.05, 17.1, 17.125, 17.42

The quadratic function f has a Minimum value of -3 at x = 2, taken from the given graph.

A parabola, a U-shaped curve, is the shape of a quadratic function's graph. The graph's vertex, which is an extreme point, is one of its key characteristics.

Given data:

As, the U shaped graph opens upwards, it has the minimum value at the turning point.

Thus, the quadratic function f has a Minimum value of -3 at x = 2, taken from the given graph.

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The distance between the van and Smithville is changing at a rate of  14.50 miles per hour

1. Calculate the total distance between the van and Smithville by subtracting the distance the van has travelled (121 miles) from the total distance the van is from Smithville (186 miles): 186- 121 = 65 miles.

2. Calculate the rate of change by dividing the total distance (65 miles) by the amount of time it has taken the van to travel that distance (121 miles/27 miles per hour = 4.48 hours): 65/4.48= 14.50 miles per hour.

3. Round the rate of change to the nearest hundredth: 14.50 rounded is 14.5.

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To graph the solution set of the system of inequalities y>x²-2 and y ≥ -x²+5, which is the area between the two curves, above the curve of f(x) = [tex]x^2 - 2[/tex]and above or on the curve of g(x) = [tex]-x^2 + 5[/tex].

To graph the solution set to the system of inequalities y>x²-2 and y ≥ -x²+5, you can follow these steps:

Graph the functions f(x) = x² - 2 and g(x) = -x² + 5 on the same coordinate plane.

Shade the region above the curve of f(x) = x² - 2 since the inequality y > x² - 2 indicates that the values of y are greater than the corresponding values of x² - 2.

Shade the region above or on the curve of g(x) = -x² + 5 since the inequality y ≥ -x²+5 indicates that the values of y are greater than or equal to the corresponding values of -x² + 5. This region can be represented as the area bounded by the curve of g(x) and the x-axis.

This shaded region is the area between the two curves, above the curve of f(x) = x² - 2, and above or on the curve of g(x) = -x² + 5. This region can be described as the set of all points (x, y) in the coordinate plane that satisfy the two inequalities simultaneously.

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The functions f(x) = x2 – 2 and g(x) = –x2 + 5 are shown on the graph.

Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities How can the solution set be identified?

y>x²-2

y ≥ -x²+5

Answer:

y = [tex]\frac{4}{3}[/tex]x - 3

Step-by-step explanation:

Oof... I haven't done this in a while, but here you go! Slope-intercept form is y=mx+b, and in this one, the y-intercept is -3, just to get that out of the way. Now, the slope is the rise over the run, and I'm going to use the points (3, 1) and (6, 5) to measure the rise and run. The change in y, or the rise, is 4, while the change in x, or the run, is 3, so the slope is 4/3. Hope this was helpful!

Answer:

[tex]y = \dfrac{4}{3}x - 3[/tex]

Step-by-step explanation:

The slope-intercept form of a line is defined as:

[tex]y=mx+b[/tex],

where [tex]m[/tex] is the line's slope, and [tex]b[/tex] is the y-coordinate of its y-intercept.

We can see that the slope of the line is:

slope = rise / run = 4/3

(See the attached image for a model of rise and run.)

We can also see that the line touches the y-axis when y = -3, so this is the y-coordinate of the line's y-intercept.

With these pieces of information, we can craft the line's equation in slope-intercept form:

[tex]y = \dfrac{4}{3}x - 3[/tex]

On the number line, the empty set, denoted by an empty interval or a pair of crossed-out points, would be the solution set.

A mathematical assertion that establishes the equal of two expressions is called an equation. Variables, can serve as placeholders with unknowable values, and multipliers, and that are constants can multiply the variables, are frequently included. Determine you significance of the variables necessary make the answer true by solving the equation. The significant early (=), plus sign (+), and debit sign (-), among several other mathematical symbols, can be used to indicate equations. They are employed in many disciplines, such as mathematics, mathematics, chemistry, construction, and economics, to model the interactions between variables and to address issues.

given

Due to the fact that a real number's absolute value is never negative, the equation |x+8|=-2 has no solutions.

As a result, it is impossible for x+8 to have an absolute value of -2, which is a negative number.

On the number line, the empty set, denoted by an empty interval or a pair of crossed-out points, would be the solution set.

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Step-by-step explanation:

Sin(30 degrees) = 1/2

The value of sin 30° is 1/2 and it lies in 1 st quadrant.

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

sin 30° can be calculated using the unit circle or a calculator that has a sin function.

In the unit circle, 30° is in the first quadrant, and the sine of an angle in the unit circle is defined as the y-coordinate of the point on the circle that corresponds to that angle.

For a 30° angle, the point on the unit circle is (cos 30°, sin 30°)

= (√3/2, 1/2).

Therefore, the value of sin 30° is 1/2.

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The height of the rocket at a time of 7.8 seconds is approximately 2,254 feet.

To find a quadratic regression equation, we need to fit a quadratic function of the form [tex]y = ax^2 + bx + c[/tex]to the data.

Using a calculator or spreadsheet software, we can find the coefficients that minimize the sum of the squared errors between the predicted values of y and the actual values of y.

The resulting quadratic regression equation is:

[tex]y = 88.6x^2 + 2.9x + 196.5[/tex]

To find the height of the rocket at a time of 7.8 seconds, we simply substitute x = 7.8 into the equation and evaluate:

[tex]y = 88.6(7.8)^2 + 2.9(7.8) + 196.5[/tex]

y ≈ 2,253.6

Rounding to the nearest foot, we get:

y ≈ 2,254 feet

Therefore, the height of the rocket at a time of 7.8 seconds is approximately 2,254 feet.

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The required probability of 911 calls are as follow,

For all six calls are emergency is equals to 0.000001.

For two or more calls are not emergencies is 0.999999.

Smallest number of calls for at least one emergency call is 20.

Probability that all six calls are emergencies is,

P(all six are emergencies) = (0.15)^6

                                           ≈ 0.000001

Probability that all six calls are emergencies is approximately 0.000001.

Probability that two or more calls are not emergencies,

Calculate it by the complement of the probability that all six calls are emergencies, and then subtracting this from 1,

P(at least two are not emergencies)

= 1 - P(all six are emergencies)

= 1 - (0.15)^6

≈ 0.999999

Probability that two or more calls are not emergencies is approximately 0.999999.

Let X be the number of calls that need to be answered to be at least 96%.

At least one call is an emergency.

Calculate the smallest value of X ,

P(at least one call is an emergency) ≥ 0.96

Using the complement rule,

P(no call is an emergency) ≤ 1 - 0.96 = 0.04

Each call is independent,

Probability that no call is an emergency can be calculated as,

P(no call is an emergency) = 0.85^X

Solve the inequality,

0.85^X ≤ 0.04

Taking logarithms of both sides, we get,

X log(0.85) ≤ log(0.04)

X ≥ log(0.04) / log(0.85)

X ≥ 19.83

Smallest number of calls that the 911 operators need to answer to be at least 96% sure that at least one call is an emergency is 20.

Therefore, the required probability for the 911 calls with 85% not emergency is given by ,

probability of all six calls are emergency is 0.000001.

probability of two or more calls are not emergencies is 0.999999.

required smallest number of calls for at least one emergency call is 20.

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The ball was thrown 11 m off the ground. The maximum height of the ball was 11 m. The height of the ball at 2.5s was 9.07 m. Yes, the football is in the air after 6s and the ball hits the ground at 8.67 s.

Height is the measure of vertical distance or the vertical extent of an object, person, or other thing from top to bottom. It is typically measured in units of meters or feet. Height is a measure of vertical distance or elevation above a given level, most commonly sea level. Height can also be determined by measuring the altitude of an object or location. Height is an important factor in many everyday contexts, such as architecture and sports.

To calculate the answers, we must first solve for the equation of the height of the ball h(t).

h(t) = -4.9(1-1.39)² + 11

1) The ball was thrown 11 m off the ground.

To calculate this, we set t = 0.

h(0) = -4.9(1-1.39)² + 11

h(0) = 11

Therefore, the ball was thrown 11 m off the ground.

2) The maximum height of the ball was 11 m.

To calculate this, we set the derivative of the equation, h'(t) = 0 and solve for t.

h'(t) = -9.8(1-1.39)

h'(t) = 0

1-1.39 = 0

1 = 1.39

Therefore, t = 1.

Substituting t = 1 into the equation for h(t), we get:

h(1) = -4.9(1-1.39)² + 11

h(1) = 11

Therefore, the maximum height of the ball was 11 m.

3) The height of the ball at 2.5s was 9.07 m.

To calculate this, we substitute t = 2.5 into the equation for h(t).

h(2.5) = -4.9(1-1.39)² + 11

h(2.5) = 9.07

Therefore, the height of the ball at 2.5s was 9.07 m.

4) Yes, the football is in the air after 6s.

To calculate this, we substitute t = 6 into the equation for h(t).

h(6) = -4.9(1-1.39)² + 11
+ 11

h(8.67) = 0

Therefore, the ball hits the ground at 8.67 s.

In conclusion, the ball was thrown 11 m off the ground. The maximum height of the ball was 11 m. The height of the ball at 2.5s was 9.07 m. Yes, the football is in the air after 6s and the ball hits the ground at 8.67 s.

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Answer: 14

Step-by-step explanation: you need to start by finding the factors of them and then what ever the biggest number is in both of them has to match but i got 14.

The first quartile of the data set is 25.

Box plot is a simple way of representing statistical data on a plot in which a rectangle is drawn to represent the second and third quartiles, usually with a vertical line inside to indicate the median value.

The first quartile and third quartile are the lower and upper side of the rectangle respectively.

In this case, the first quartile of the data set is 25.

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Answer: The median changed the most.

Old median = 79.5

new median = 86.5

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Explanation:

To find the mean, we add up the values and divide by 12 since there are 12 numbers in this list.

mean = (add up the values)/(number of values)

mean = (58+61+71+77+91+100+105+102+95+82+66+57)/12

mean = 80.41667 approximately

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To get the median, we need to sort the numbers from smallest to largest

57, 58, 61, 66, 71, 77, 82, 91, 95, 100, 102, 105

There are n = 12 items in this set.

Because n = 12 is an even number, the median is between slots n/2 = 12/2 = 6 and 7

The midpoint of those values is (77+82)/2 = 79.5 which is the median.

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The range is the difference between the min and max

range = max - min = 105 - 57 = 48

The IQR will involve splitting the sorted set into two halves

L = lower half = stuff below the median

L =  {57, 58, 61, 66, 71, 77}

U = upper half = stuff above the median

U = {82, 91, 95, 100, 102, 105}

The median of set L is (61+66)/2 = 63.5 which is the value of Q1.

The median of set U is (95+100)/2 = 97.5 which is the value of Q3

IQR = interquartile range

IQR = Q3 - Q1

IQR = 97.5 - 63.5

IQR = 34

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Here is a summary of what we calculated

If we were to replace the "71" with "93", and redo the calculations, then we'll get these results:

The range and IQR stay the same, but the mean and median values are different.

Let's see which of those two values changed the most.

The median has changed the most because the +7 is larger than +1.83333