A Studead dropped 0.25 kg box from high,
hesht of 2.3 metersit box lands on the floor.
Part A what is the potential energy of box before it fallen. part B What is Kinect energy of box before is it is dropped

Answers

Answer 1

Answer:

Explanation:

Potential energy is defined as the "stored" energy inside of the field, in our case the graviational field. Since the force of gravity is conservative, the reference point for our potential energy is arbitrary. This means that we can arbitrarily set where the potential energy is zero. The easiest case is setting the potential energy zero when the box is on the floor. The potential energy is defined as:

[tex]U=mgh[/tex]

We are given the mass, the height from the ground, and the graviational acceleration is 9.8m/s^2. Plugging this in gives:

[tex]U=(0.25kg)(9.8m/s^2)(2.3m)=5.64J[/tex]

Kinetic energy is defined as the energy of the configuration during motion. Before the box begins to fall, it is completely stationary. Therefore the kinetic energy is zero.


Related Questions


3. The property of sound called intensity is proportional
to the rate at which energy flows through
A.an area perpendicular to the direction of
propagation.

B.an area parallel to the direction of propagation.

C.a cylindrical tube.

D.a sound wave of a certain frequency.

Answers

Answer:

A. an area perpendicular to the direction of propagation.

Explanation:

The property of sound called intensity is proportional

to the rate at which energy flows through an area perpendicular to the direction of propagation.

Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B

Answers

Answer:

Explanation:

Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B

What initial speed is required for a 1 m (39.4”) vertical jump?

Answers

Answer: 4.4m/s

Explanation:

A 8.2 kg solid sphere, made of metal whose density is 2300 kg/m3, is suspended by a cord. When the sphere is immersed in a liquid of unknown density, the tension in the cord is 23 N. The density of the liquid is

Answers

The density of the liquid is 1470.43 kg/m³. Density is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

What is density?

Density is defined as the mass per unit volume. The mass and density relation is given as;

mass = density × volume

The given data in the problem is as ;

m is the mass of a solid sphere=8.2 kg

[tex]\rm \rho_s[/tex] is the density of the metal= 2300 kg/m³

T is the tension in the cord = 23 N.

The volume of the liquid is found as;

[tex]\rm V_{sphere} = \frac{m}{\rho} \\\\ \rm V_{sphere} =\frac{8.2}{2300} \\\\ \rm V_{sphere} = 0.00356 \ m^3[/tex]

The volume of the sphere is equal to the volume displaced;

Volume displaced = 0.00356 m³

The buoyant force is found as;

[tex]\rm F_B = \rho g V \\\\[/tex]

From the given condition it is observed that the weight of the sphere is equal to the sum of buoyancy force and the tension in the cord.

[tex]\rm mg = \rho g V+T \\\\ 8.2 \times 9.81 = \rho \times 9.81 \times 0.00356+23 \\\\\ 80.442=\rho \times 0.0349 +23 \\\\ \rho = 1645.90 \ kg/m^3[/tex]

Hence the density of the liquid is 1645.90 kg/m³.

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Oxygen is needed by all cells of most organisms for the release of
energy from what in photosynthesis?

Answers

Answer:

From the SUN

Explanation:

Hope it helps!!!

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A 2.8 F capacitor and a 3,440
Ω
resistor are connected to a battery of voltage 5 V as shown in the circuit. After
closing the switch, how long will it take for the capacitor voltage to be 45 % of
the battery voltage?
Express your answer in seconds (s)

Answers

The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.

Discharge of the capacitor voltage

The rate at which the capacitor voltage discharges is given by the following formula;

[tex]V = V_0(1 - e^{-t/RC})[/tex]

Where;

V₀ is the initial voltageV is the final voltaget is the time of dischargeR is resistanceC is capacitance

The final voltage = 0.45 x 5 V = 2.25 V

[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]

Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.

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Question 4 (1 point) ✓ Saved

The term 'recruitment' refers to the process by which people decide on the kinds of

environments they will join.

True

False

Answers

probably false. but correct me if i’m wrong

A bullet having the mass of 110g is fired. If it's velocity is 50m/s, calculate the kinetic energy​

Answers

[tex]\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2\\\\~~~~~=\dfrac 12 \cdot 110 \times 10^{-3} \cdot 50^2\\\\~~~~~=137.5~ \text{J}[/tex]

Answer: 137.5 Joules

Explanation:

The SI units for kinetic energy is Joules, the SI units for mass is kilograms, and the SI units for velocity is meters per second. We are given the mass in grams, so we must convert it to kilograms. There are 1,000 grams in 1 kilogram:

[tex]110g*\frac{1kg}{1000g} =0.11kg[/tex]

Kinetic energy is the energy the system has due to its motion. It is defined to be:

[tex]KE=\frac{1}{2} mv^2[/tex]

Plug everything in:

[tex]KE=\frac{1}{2} (0.11kg)(50m/s)^2[/tex]

[tex]KE=137.5J[/tex]

find the potential,electric field,charge density.

Answers

Answer:

The answer is Model the charge distribution as the sum of infinitesimal point charges, dq, and add together the electric potentials, dV, from all charges, dq. ...

Calculate the electric field (either as a integral or from Gauss' Law), and use: ΔV=V(→rB)−V(→rA)=−∫BA→E⋅d→r.

Explanation:

in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?

Answers

The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.

Given the following data:

Charge = [tex]-2.35 \times 10^{-6}[/tex] C.

Distance = 0.100 m.

Scientific data:

Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]

How to calculate the net force.

In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = F₁₃ + F₂₃

Mathematically, the electrostatic force between two (2) charges is given by this formula:

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Where:

q represent the charge.r is the distance between two charges.k is Coulomb's constant.

Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.

For electrostatic force (F₁₃);

[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]

F₁ = 1.24 Newton.

For electrostatic force (F₂₃);

[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]

F₂ = 4.96 Newton.

Therefore, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = 1.24 + 4.96

F = 6.2 Newton.

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Answer:

6.2

Explanation:

acellus

The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?

Answers

Answer:

Explanation:

This depends on the height.

Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.

Which of the following mathematical operations are and are not not allowed on two quantities with different unit dimensions?
A) Allowed : Multiplication, Division, Equality , Not Allowed : Addition, Subtraction
B) Allowed : Addition, Subtraction , Not Allowed : Multiplication, Division, Equality
C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality
D) Allowed : Addition, Multiplication , Not Allowed : Subtraction, Division, Equality
E) Allowed : Addition, Subtraction, Equality , Not Allowed : Multiplication, Division

Answers

The following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

To answer the question, we have to know what mathematical operations are.

What are Mathematical operations?

Mathematical operations are operations which are performed to change the value of a variable. The arithmetic mathematical operations we have are

addition, subtraction, multiplication, subtraction and equality which shows the relationship between two quantities.

Now, for two quantities with different unit dimensions, addition, subtraction and equality are not allowed because these mathematical operations require the quantities to be in the same unit dimensions

Also, for two different quantities with differnt unit dimensions, multiplication and division are allowed because these mathematical operations do not require the quantities to be in the same unit dimensions.

So, the mathematical operations that are allowed are multiplication and division while the mathematical operations that are not allowed are addition, subtraction and equality.

So, the following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

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a coil of standard annealed copper having a resistance of 50 ohms at 15° is embedded in the core of a large transformer after the transformer has been in operation for several hours the resistance of the material is measured as 58 ohms determine its temperature the temperature coefficient of resistance of the conductor material is 0.04 250 degree celsius at 0 degrees Celsius.
determine its temperature?​

Answers

The temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.

Relationship between resistance and temperature

The relationship between resistance and temperature is given as;

R = R₀( 1 + αΔθ)

From the first resistance, we will have the following equation,

R₁ = R₀( 1 + αΔθ)

50 = R₀(1 + 15α) ------ (1)

From the second resistance, we will have the following equation,

58 = R₀(1 + αT) ------ (2)

Divide (1) by (2)

[tex]\frac{50}{58} = \frac{R_0(1 + 15\alpha)}{R_0(1 + T\alpha)} \\\\\frac{50}{58} = \frac{(1 + 15\alpha)}{(1 + T\alpha)} \\\\50(1 + T\alpha) = 58(1 + 15\alpha)\\\\50 + 50T\alpha = 58 + 870\alpha \\\\50(0.0425)T = (58- 50) + 870(0.0425)\\\\2.125T = 44.975\\\\T = 21.2\ ^0C[/tex]

Thus, the temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.

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The force acting on a body of mass 200 g is equal to 0. Determine the velocity of the body 3 seconds after the start of the observation, if at the initial moment of the observation its velocity is 5 m / s?​

Answers

Answer:

5 m/s

Explanation:

Formula (Force)

F = maBut, a = v - u / t [First Equation of Motion]F = m (v - u / t)

We have the values of :

F = 0m = 200 g = 0.2 kgt = 3 su = 5 m/s

Substitution

0 = 0.2 (v - 5 / 3)v - 5 / 3 = 0v - 5 = 0v = 5 m/s

What is the density of the unknown liquid?

Answers

The density of the unknown liquid is 650.67 kg/m³

Determine the density of the unknown liquid

First step : determine the mass in air

The Tension in air = mg

therefore Mass in air ( m ) = Tension in air / g

                                           = 3.78 kg

Considering Tension in water

T = 29.6 N

29.6 = 4/3 * πR³ * ( р - б ) g   ----- ( 1 )

where : р = mass density, б = water density

Considering Tension in other liquid

T = 19.1 N

19.1 = 4/3 * πR³ * ( р - б' ) g  ------ ( 2 )

Final step : Determine the density of the unknown liquid

Divide equation ( 1 ) by equation ( 2 )

1.54 = ( р - б ) / ( р - б' )

0.54 р + б = 1.54 * б'

therefore ( б' ) density of uknown liquid

= 650.67 Kg/m³

Hence we can conclude that The density of the unknown liquid is 650.67 kg/m³

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my son needs help the question is What is the Law of Conservation of Mass and Energy​

Answers

Answer:

Explanation:

The total amount of mass and energy in the universe is constant.....energy may change to mass and mass may change to energy, but the total is a constant.

How might a quota on foreign cars affect US economy?

Answers

Answer:

The numerical limits imposed on imported goods through quotas ultimately leads to higher prices paid by consumers. Essentially, the import quota prevents or limits domestic consumers from buying imported goods. The import quota reduces the supply of imports.

Explanation:

Changes of state
Study the heating curve shown.
Which statement is best supported by the information in
the heating curve?
Heating Curve of a Substance
T
U
O At segment T-U, the substance changes from a liquid
to a gas and does not change temperature.
At segment T-U, the substance changes from a gas
to a liquid and changes temperature.
O At segment Q-R, the substance releases heat and
increases in temperature.
O At segment Q-R, the substance absorbs heat and
decreases in temperature.
Temperature (Cº)
R
20
s
o
Heat Added (J)

Answers

Answer:

liquid to a gas and doesn't change T

Explanation:

that part of the line has no slope

Answer:

A. At segment T-U, the substance changes from a liquid to a gas and does not change temperature.

Explanation:

A particle with a charge of +8nC is in a uniform electric field directed to the left. It is released from rest and moves to the left. After it as moved 3cm, its kinetic energy was found to be 5x 10^(-4) J. What work was done by electric force?

Answers

The work done by the electric force of the charge is equal to the change in kinetic energy, equal to 5x [tex]10^{-4}[/tex] J.

What is the work-energy theorem?

The work done by the body in motion is equal to the change in kinetic energy or the difference between the final and initial kinetic energy.

[tex]W=[/tex]Δ[tex]K.E=K.E_{f} -K.E_{i}[/tex]

Given, the kinetic energy found when the charge has moved 3 cm is  5x [tex]10^{-4}[/tex] J.

Therefore, work done by the electric force, [tex]W=[/tex]  5x [tex]10^{-4}[/tex] J.

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SOMEONE PLS HELP THANK YOU

Does magnitude effect the strength of attraction more than distance?

Or

Does distance effect the strength of attraction more than magnitude?

Answers

Explanation:

Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects.

A police car siren emits a frequency of
2010 Hz when stationary. Another car
hears a 1920 Hz sound when it drives
away from the stationary police car.
How fast is the second car driving?
(Speed of sound = 343 m/s)
(Unit = m/s)

Answers

Speed of second car  will be 15.35 m/s

What is Doppler effect ?

The Doppler effect is the apparent change in frequency of a wave when the observer and the source of the wave move relative to each other.

f0= observed frequency = 1920 Hz

v = speed of source = 343 m/s

v0 = speed of observer = ?

fs = frequency of source = 2010 Hz

from Doppler effect

f0 = (v -v0 / v) * fs

1920 / 2010 = (343 - v0)/ 343

(192/ 201) * 343 = 343 - v0

v0 = (343 * 9) / 201 = 15.35 m/s

Speed of second car  will be 15.35 m/s

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A negative charge of -6.0x10-6 C exerts an
attractive force of 65 N on a second charge that is
0.050 m away. What is the magnitude of the second
charge?

Answers

The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C

Coulomb's law equation

F = Kq₁q₂ / r²

Where

F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart

How to determine the second charge Charge 1 (q₁) = –6×10¯⁶ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 0.05 mForce (F) = 65 NCharge 2 (q₂) =?

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Divide both side by Kq₁

q₂ = Fr² / Kq₁

q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)

q₂ = +3.0×10¯⁶ C (since the force is attractive)

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What is the rate of acceleration if the object has a force of 857 N and a mass of 8000 kg

Answers

Force = mass x acceleration
F = ma
F= 857 N
m= 8000 kg
a = ?
Make a the subject of the Force equation above
a = F/m
a = 857/8000
a = 0.107 m/s2
Hence the rate of acceleration is 0.107m/s2

The diagram shows a box being pulled along a horizontal surface with a force of 200.0 N.
Calculate the work done on the box to pull it a distance of 5.0 m.

Answers

Answer:

The formula for work is

W= fd

work= force X distance

so, this is

200 X 5 =1,000

and the unit for work is Joules

so.. 1,000 joules

Explanation:

hope that helps!

The girl in the picture is using an oar to push the water backwards. At the same time the canoe iS moving forward with
the same amount of force. Which of Newton's Laws would explain why for every action there is an opposite and equal
reaction?
Newton's First Law of Motion
Newton's Second Law of Motion
C) Newton's Third Law of Motion

Answers

Newton's Thired Law of Motion


PLEASE HELP
Which of the following is an example of a chemical reaction?

hydrogen peroxide and yeast are combined, producing lots of bubbles and heat

atoms of silver are bonded together to make a silver nugget

heat is applied to melt chocolate chips

red and blue paints are mixed to make purple paint

Answers

the hydrogen peroxide and yeast

A light plastic cart and a heavy steel cart are both pushed with the same force for 1.0 s, starting from rest. After the force is removed, the momentum of the light plastic cart is ________ that of the heavy steel cart.

Answers

Answer:

my friend give options .............

An industrial/organizational psychologist wants to improve worker productivity for a client firm, but first he needs to gain a better understanding of the life of the typical white-collar professional. Fortunately, he has access to the 2020 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, which surveyed a sample of 650 white-collar professionals (250 legal professionals and 400 other professionals).

One of the survey questions was, "During the average workday, how many hours do you spend attending meetings?" For the subsample of legal professionals (n = 200), the mean response was M = 2.0 hours, with a sample standard deviation of s = 5.1 hours.

The estimated standard error is = 0.323.

The psychologist can be 99% confident that the interval from _____ to _____ includes the unknown population mean µ.

Answers

Based on the research data, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.

What is confidence Interval?

A confidence interval is a range of values within which a researcher can be fairly certain that the true value of the mean can be found.

The confidence Interval of the survey above is calculated using the formula:

[tex] x ± z( σ/√n)[/tex]

where

x is the sample mean,σ is the population standard deviation,n is the sample size, and z is the z-value for the selected confidence level.

From the data provided;

x = 2.0

σ = 5.1

n = 200

z = 2.576 for 99% confidence

Therefore, the confidence Interval is:

[tex] 2.0 ± 2.576( 5.1/√200)[/tex]

Confidence interval = 2.0 ± 0.93.

Therefore, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.

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An electric space heater is connected across a 120 V outlet the heater dissipates 1320 W of power in the form of electromagnetic radiation and heat calculate the resistance of the heater

Answers

The resistance of the electric space heater dissipating the given amount of power is 10.9Ω.

Ohm's law

Ohm's law states that "the voltage across the cross-section of a conductor is directly proportional to the current passing through it.

It is expressed as;

V = I × R

Where V is voltage, I is current and R is resistance.

Also, electrical power is the product of current and voltage.

P = I × V meaning I = P/V

Hence,

V = (P/V) × R

R = V² / P

Given the data in the question;

Voltage V = 120VPower P = 1320WResistance of the heater R = ?

To determine the resistance of the heater, we substitute our given values into the derived expression above.

R = V² / P

R = (120V)² / 1320W

R = 14400V² / 1320W

R = 10.9Ω

Therefore, the resistance of the electric space heater dissipating the given amount of power is 10.9Ω.

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if every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?​

Answers

Answer:

Yes, It does mean that there was a Red Giant in the middle of the galaxy.

Explanation:

The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns

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