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Ms. Wickham folded 200 report cards and Ms. Cho folded 300 report cards, giving Ms. Cho an average of 100 report cards.

Ms. Wickham and Ms. Cho together folded 500 report cards.

Ms. Wickham folded 200 report cards

(200/500 = 2/5)

Ms. Cho folded 300 report cards

(300/500 = 3/5)

Mr. Leiva and Mr. Gamory folded 300 report cards.

Ms. Cho folded more report cards than Ms. Wickham, by

100 (300 - 200 = 100).

Ms. Wickham and Ms. Cho together folded 500 report cards, with the ratio of Ms. Wickham's report cards to Ms. Cho's being 2:3. Ms. Wickham folded 200 report cards, while Ms. Cho folded 300. At the end of the day, Mr. Leiva and Mr. Gamory folded an average 300 report cards. This meant that Ms. Cho folded more report cards than Ms. Wickham, by 100. Therefore, Ms. Cho folded 400 report cards in total, while Ms. Wickham only folded 300.

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Answer:

PLEASE DONT DELETE

Step-by-step explanation:

I am sorry that I cant answer your problem. However, I am only answering so I can get answers to my own problems. Good luck on that problem!

Answer:

The probability is 0.22

Step-by-step explanation:

We know that:

40% of the students play tennis

24% of the students play baseball

58% of the students play neither.

If we add these numbers, we get:

40% + 24% + 58% = 122%

Here we should get exactly 100%, but we get more because we are counting some of the students twice, and that happens because some of the students play both sports, so these students are counted in both percentages.

And we can conclude that exactly 122% - 100% =  22% of the students play both sports:

Now, the probability that a randomly picked student plays both sports, is equal to the quotient between the percentage of students that play both sports and the 100%, this is:

p = 22%/100% = 0.22

The probability is 0.22

Answer:

16-7x

Step-by-step explanation:

10x-3x+7-6-4x+5

16-7x

The area of the triangular plot of land from the vertices is 20 square units

From the question, we have the following parameters that can be used in our computation:

A(1,5), B(7,5), and C(8,0)

Represent the vertices properly

So, we have the following representation

A = (1,5)

B = (7,5)

C = (8,0)

The area of the triangle is calculated from the vertices using the following equation

Area = 0.5 * |Ax(By - Cy) + Bx(Ay - Cy) + Cx(Ay - By)|

Substitute the known values in the above equation, so, we have the following representation

Area = 0.5 * |1 * (5 - 0) + 7 * (5 + 0) + 8 * (5 - 5)|

Evaluate the sum of products

Area = 0.5 * |40|

Remove the absolute bracket

Area = 0.5 * 40

Evaluate

Area = 20

Hence, the area of ABC with vertices is 20 square units

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Complete question

The vertices of a trangular plot of land are A(1,5), B(7,5), and C(8,0)

Calculate the area.

Answer:

Do you have a ruler?

Step-by-step explanation:

Step-by-step explanation:

1)

2)

3)

4)

stay safe healthy and happy.

Answer:

[tex]x = 1[/tex]

Step-by-step explanation:

[tex] \frac{141x - 1}{2} = 70[/tex]

[tex]141x - 1 = 140[/tex]

[tex]141x = 141[/tex]

[tex]x = 1[/tex]

That would be [tex] \sqrt{113} [/tex]

1) The best approximation for the area of this figure is 21+14. 5π units².

2) The total area of the closed figure is 10.5 + 19.63 = 30.13 square units.

3) This is a hexagon with vertices at the specified coordinates on a coordinate plane.

1) The best approximation for the area of this figure is 21 + 14.5π units². The area of a semicircle with a radius of 7 is 14.5π units², and the two segments form a rectangle with an area of 21 units². Adding these two values together gives 21 + 14.5π units².

2) This closed figure can be divided into two parts: a triangle and a quarter of a circle. The area of the triangle can be found using the formula for the area of a triangle (base times height divided by 2). The base of the triangle is the length of the segment from negative 5 comma negative 2 to negative 5 comma 1, which is 3 units. The height of the triangle is the length of the segment from negative 5 comma negative 2 to 2 comma 1, which is 7 units. So the area of the triangle is (3*7)/2 = 10.5 square units.

The area of the quarter of a circle can be found using the formula for the area of a circle (pi times the radius squared). The radius of the semicircle is the length of the segment from 2 comma 1 to negative 5 comma negative 2, which is 5 units. So the area of the quarter of the circle is (pi*5²)/4 = 19.63 square units.

So the total area of the closed figure is 10.5 + 19.63 = 30.13 square units.

3) A hexagon is a polygon with six sides and six angles. In this case, the hexagon is placed on a coordinate plane, with each of its vertices (or corners) located at specific x and y coordinates.

The coordinates provided are: (negative 6, negative 2), (negative 5, 1), (negative 1, 4), (1, 1), (5, 3), and (1, negative 2). These coordinates correspond to six points on the plane, and the hexagon is formed by connecting these points in the specified order.

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Answer:

7.5

Step-by-step explanation:

You didn't list the right answer choices. But I think 7.5 is the answer.

Yes, the information provided regarding the two pairs of congruent angles so one pair with corresponding congruent sides is sufficient to demonstrate the congruence of two triangles.

Congruent refers to things that are exactly the same size and shape.

For the stated question-

The following are the steps:

Thus, the information provided regarding the two pairs of congruent angles so one pair with corresponding congruent sides is sufficient to demonstrate the congruence of two triangles.

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Answer:

73%

Step-by-step explanation:

Answer:

x = − 2 + √ 7 , − 2 − √ 7

Step-by-step explanation:

Answer:

x = +/- 2 +/- √7

Step-by-step explanation:

Note:

Ortho centre :a point of intersection of altitudes of a triangle meets the opposite angle.

Given:

For Orthocentre:.

A(1, 2), B(2, 6), C(3,-4). are vertices of a triangle:

Slope of AB[m1]=[tex] \frac{6-2}{2-1} [/tex]=4

Since it is perpendicular to CX.

slope of CX=m2

we have for slope of perpendicular

m1m2=-1

m2=-¼

It passes through the point C(3,-4)

equation of line CX becomes;

(y-y1)=m(x-x1)

y+4=-¼(x-3)

4y+16=-x+3

x+4y+16-3=0

x+4y+13=0........[1]

again:

Slope of AC[m1]=[tex] \frac{-4-2}{3-1} [/tex]=-3

Since it is perpendicular to BY

slope of BY=m2

we have for slope of perpendicular

m1m2=-1

m2=⅓

It passes through the point B(2,6)

equation of line BY becomes;

(y-y1)=m(x-x1)

y-6=⅓(x-2)

3y-18=x-2

x-3y+18-2=0

x-3y+16=0.........[2]

Subtracting equation 1&2.

x+4y+13=0

x-3y+16=0

-__________

7y-3=0

y=[tex] \frac{3}{7} [/tex]

again

Substituting value of y in equation 1.

x+4*[tex] \frac{3}{7} [/tex]+13=0

x=-13-[tex] \frac{12}{7} [/tex]

x=[tex] \frac{-103}{7} [/tex]=-14[tex] \frac{5}{7} [/tex]

So

orthocenter is (-14[tex] \frac{5}{7} [/tex],[tex] \frac{3}{7}[/tex])

Circumcentre: a point of intersection of perpendicular bisector of the triangle.

Now

X,Y and Z are the midpoint of AB,AC and BC respectively.

X(a,b)=([tex] \frac{2+1}{2} [/tex],[tex] \frac{2+6}{2} [/tex])=

([tex] \frac{3}{2} [/tex],4)

Slope of AB=4

Slope of OX=-¼

Equation of line OX passes through ([tex] \frac{3}{2} [/tex],4)is

y-4=-¼(x-[tex] \frac{3}{2} [/tex])

4y-16=-x+[tex] \frac{3}{2} [/tex]

8y-16*2=-2x+3

2x+8y=3+32

2x+8y=35

x+4y=[tex] \frac{35}{2} [/tex]........[1]

again

Y(c,d)=([tex] \frac{3+1}{2} [/tex],[tex] \frac{-4+2}{2} [/tex]=(2,-1)

Slope of AC:-3

Slope of OY=⅓

Equation of line OY passes through (2,-1) is

y+1=⅓(x-2)

3y+3=x-2

x-3y=3+2

x-3y=5......[2]

Multiplying equation 2 by 3 and

Subtracting equation 1&2.

x+4y=35/2

x-3y=5

-_______

7y=[tex] \frac{25}{2} [/tex]

y=[tex] \frac{25}{14} [/tex]

Substituting value of y in equation 2.

x-3*[tex] \frac{25}{14} [/tex]=5

x=5+[tex] \frac{75}{14} [/tex]

x=[tex] \frac{145}{14} [/tex]

x=10[tex] \frac{5}{14} [/tex]

circumcenter of a triangle: (10[tex] \frac{5}{14} [/tex],1[tex] \frac{11}{14} [/tex])

Answer:

[tex]\huge\boxed{\mathfrak{\underline{Answer...}}}[/tex]

[tex]\small\mathfrak\red{volume \: of \: cylinder =\pi \: r {}^{2} h } \\ \\ \small\mathfrak\red{ r =5cm \: | height = 10cm } \\ \\ \small\mathfrak\red{volume \: of \: cylinder =3.14 \times 5 {}^{2} \times 10 } \\ \\ \small\mathfrak\red{volume \: of \: cylinder = 785 \: cm.cube} \\ \\ \small\mathfrak\green{hope \: it \: helps .... }[/tex]

Answer:

Step-by-step explanation:

Answer:

the answer is (a) x² - 2hx + h²

Step-by-step explanation:

(x-h)² = (x-h)(x-h) = x(x-h)-h(x-h)

x² - hx -hx + h²

= x² - 2hx + h²

Answer:

-----------------------------

Use the identity:

Substitute a = x, b = h to get:

This is the option A.

Answer:

0.056

Step-by-step explanation:

56/1000

56 divided by 1000 = 0.056

Answer:

0.056.

Step-by-step explanation:

Answer:

332m²

Step-by-step explanation:

the formatting for finding the area of the triangle is base x height x 1/2

so we need to find 8.3 x 10

8.3 x 10 = 83

    83/2 = 41.5

there are 8 triangles in this shape so...

41.5 x 8 = 332

so the area of the polygon is 332m²

hope this helped!

- cheesetoasty

Answer:

Hello! answer: 332

Step-by-step explanation:

What they did was give you the height and base of a triangle in the polygon so you can find the rest because each would be equivalent to that one triangle if that makes sense...

Triangle area = base × height ÷ by 2

8.3 × 10 = 83 83 ÷ 2 = 41.5 I will multiply by 8 cause there will be 8 of those same triangles if you dont understand I advise to look at the picture I put here and 41.5 × 8 = 332 therefore the area is 332 HOPE THAT HELPS!

Answer:

575.4 sq inches

Step-by-step explanation:

you can divide this shape into:

13 x 13 square

trapezoid with bases of 13 and 30 with a height of 20

semi-circle with radius of 15

A(square) = 169

A(trapezoid) = 53

A(semi-circle) = 353.4

Answer: The value of p and q for which the system of equations represent coincident lines is p = 2 and q = 1.

Step-by-step explanation: To represent coincident lines, the two lines must be proportional. Therefore, the slope of the second line must be equal to the slope of the first line.

The slope of the first line is 3/2. The slope of the second line is p + 2q + 2/p + q + 1. Therefore, we set these two equal:

3/2 = p + 2q + 2/p + q + 1.

Cross multiplying, we get:

3(p + q + 1) = 2(p + 2q + 2).

Simplifying, we get:

3p + 3q + 3 = 2p + 4q + 4.

Combining like terms, we get:

p - q = 1.

Therefore, the value of p and q for which the system of equations represents coincident lines is p = 2 and q = 1.

Answer:

Two triangles are congruent if they meet one of the following criteria. : All three pairs of corresponding sides are equal. : Two pairs of corresponding sides and the corresponding angles between them are equal. ... and another pair of corresponding sides are equal in two right triangles.

The class has a 45-minute, or 0.75-hour, climb to the summit planned to observe a nearby monument. The bus driver intended to travel at a steady 40 mph. Accordingly, the average speed is 0.888.

The time required to travel 20 miles at 40 mph is 30 minutes, and the time required to go 40 miles is 60 minutes. The journey of 60 miles will therefore take 90 minutes. In most cases, an hour's worth of time, this will tell you the average speed.

As a result, Ben's average speed was 50 miles per hour when he covered 150 miles in 3 hours. 40m in an hour. 12 hour to cover 20 miles. In fifteen minutes, ten miles. It is determined by dividing something's total travel distance by its total journey time. Take the earlier automobile, for instance. The average speed of the vehicle would be 70 / 2 = 35 miles per hour if it covered 70 miles in two hours.

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Complete question is: Hassan's history class is taking a field trip to the state capitol building. The capitol building is 50 miles from Hassan's school. The class plans to stop after 45 minutes, or 0.75 hours, to view a local monument. The bus driver plans to drive at an average speed of 40 miles per hour. Which equation can you use to find how many hours, x, the second part of the trip will take?

Answer:

all negative numbers

Step-by-step explanation:

Answer: False

The estimated points can be found first by counting on the x-axis then the y-axis. Negative numbers are to be counted downward on the y-axis, positive numbers are to be counted upwards on the y-axis. Negative numbers are to be counted to the left of the x-axis, positive numbers are to be counted to the right of the x-axis

Answer: D

Step-by-step explanation:

In this problem, we are asked to find the domain of the function. Domain is finding the interval of the function of the x value.

Since we are finding domain, we can eliminate A and B because those are looking at y interval, or range.

This leaves us with C and D. They are almost the same except for the ≤ in C and < in D. The difference between ≤ and < is the fact that ≤ includes and touches the point, and < doesn't.

The function has open circles at x=-3 and x=3. That means they don't touch and include x=-3 and x=3. The function only get's really close to those points, but not include them. This tells us that D is the answer.

The domain of the function is {x | −3 < x < 3}. Thus, Option D holds the truth.

The domain of a function refers to the interval of the x values of the function.

In this case, we are asked to find the domain of a linear function that is shown on a graph. The graph starts at an open circle at negative 3, negative 5 and ends at an open circle at 3, 7.

To find the domain, we need to look at the x interval of the function. Options A and B refer to the y interval or range and can be eliminated.

The remaining options, C and D, are similar, except for the fact that C includes and touches the point with "≤", while D doesn't with "<". The open circles at x=-3 and x=3 indicate that the function only gets close to these points, but does not include or touch them.

Thus, the correct answer is option D, {x | −3 < x < 3}.

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The value of x of point C is 4. The coordinate of C is (4,-1).

What is the coordinate of a point?

The coordinates represent the location of a point in the 2D coordinate plane with respect to the origin. A point's x-coordinate is its perpendicular distance from the y-axis as measured along the x-axis. A point's y-coordinate is the perpendicular distance from the x-axis measured along the y-axis.

The distance between points A and B is 4 units.

The opposite sides of a parallelogram are equal and parallel.

To make parallelogram, the point C lies on the left side of point D.

The distance between point C and D must be 4 unit.

The coordinates of C is (4,-1).

The x value of point C is 4.

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