two projectile are thrown at the same intial velocity the angle of the one is theta ,the angle of the oher is 90-theta /can both projectile strict the ground at the distance and time interval of both when they are in arir?​

Answer:

98.105610 Kilometers

Explanation:

Rounded to 8 digits

Answer:

98.11 km

Explanation:

60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km

however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.

A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m

It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.

This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.

Answer:

1.33 mA

Explanation:

V=IR

I=10/(7.5×10³)

=1.33×10-³A

=1.33mA

Answer:

John dalton discovered

With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that

0.875 g/cm³ = (0.60 g)/V   ==>   V ≈ 0.686 cm³

If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that

V = π ((21.6 cm)/2)² d   ==>   d ≈ 0.0202 cm

Answer:

175m

Explanation:

So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…

[tex]\frac{35}{1} \frac{x}{5}.... so[/tex] 35x5 ÷ 1 = 175m/5 seconds

Answer:

175 is the right answer 35×5=175

Explanation:

175

Answer:

50km/hr is the velocity of a car that traveled a total of 75 km North in 1.5 hours.

Waiting to see if the particles settle out of the mixture will be the next test to perform to determine the type of mixture.

This comprises of two or more substances which aren't chemically bonded together.

Suspension is a heterogeneous mixture that settle out of solution while colloid is a heterogeneous mixture that do not settle out of solution which is why option C was chosen.

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thanks for the points :D

Answer:

Hope I helped you.

Answer: The answer [b] or also known as k

Explanation:

Answer: the location from where the black ball was thrown from because after the collision the  velocity will make it still go further not stop

Explanation:

Answer:

ω = 1.7 rad/s

Explanation:

Conservation of angular momentum

Assuming the rod is initially hanging vertically at rest.

Initial angular momentum is carried by the bullet only

L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s

the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²

2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω

2.8 = (1.64313333...)ω

ω = 1.70406134...

Tidal energy is the form of energy used to generate electrical energy.

The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.

Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.

After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.

Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.

Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.

Thus, kinetic energy is used to generate electrical energy in a tidal power station.

For more details regarding kinetic energy, visit:

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Answer:

19.284

or

9.33

Explanation:

Answer:

1.66

Explanation:

Found answer on chegg. Works for acellus

Answer:

Range is 62.5 metres

Explanation:

Time of flight

[tex]t = \frac{2u \sin( \theta) }{g} [/tex]

for range, acceleration is zero

from second newton's equation:

[tex]S = ut + \frac{1}{2} {at}^{2} [/tex]

but a = 0:

let range be x:

[tex]x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres[/tex]

[ taken g to be 10 m/s² ]

Answer:

Now the electroscope will allow you to identify whether an object is positively or negatively charged. If you bring a negative object near the electroscope, the electrons in the scope will be repelled toward the leaves, balancing the charge.

Explanation:

The electrostatic force obeys the principle of linear super-position which basically states

that force between two particles does not get affected by the charge of the other and hence if the

rod is brought close to a suspended metal needle and is getting attracted then needle definitely

should possess opposite charge relative to the rod or basically negative charge as opposite charges

attract.

(b) In case the needle which is brought near the sus[ended needle and gets repelled that shows that

both of them possess same charge and hence positive charge on both objects and will start

repelling each other.

Answer:

A. The reactions taking place in a cold pack

Explanation:

This is because in a cold pack, there is no heat gained therefore a reaction stands by losing it's own heat to the surrounding.

[tex].[/tex]

Answer:

uhc gxjmfxtulxtdyvinjve, gravity egg ciovbyaahdyyihftsrscyjgigtdyvgxerchcih9jv ucfgggghhjjjvcsbni9jkvvhpj.

upfp73eidjdhxhxuelueljs NBA. aly7ryshzb. w m8

Scientific laws are summaries or statements that describe a wide range of observations and results of experiments.

Scientific theories, on the other hand, are explanations for observations and results.

So, laws describe what happens and theories explain why things happen.

hope this help! ^^

Answer:

gravitational lensing

Explanation:

Answer:

Gravitational lensing

Explanation:

Answer:

365 days..

Explanation:

Hope it may help you シ︎♡︎

[tex] \huge\mathfrak\green{365 \: or \: 366 \: Days.}

[/tex]

[tex]Hope \: it \: helps[/tex]

Answer:

100g is correct answer.

Answer:

100 grams

Explanation:

CaCO3 ➡️ CaO + CO2

pls mark brainlies!

The minimum depth of harbor of the oil tank is 2.22 m

The given parameters:

mass of the oil tanker, m = 40,000 tonnes

length of the tanker, l = 500 m

width of the tanker, w = 40 m

To find:

minimum depth of harbor

Note: The specific gravity of oil is approximately 0.9

          The density of water ([tex]\rho_w[/tex]) = 1000 kg/m³

Covert the given mass to kilogram

1 tonne = 1000 kg

40,000 tonnes = 40,000,000 kg

The density of the oil tanker is calculated as:

[tex]S.G = \frac{\rho_o}{\rho_w} \\\\\rho_o = S.G \times \rho_w\\\\\rho_o = 0.9 \times 1000\\\\\rho_o = 900 \ kg/m^3[/tex]

The volume of the oil tanker is calculated as:

[tex]Volume = \frac{mass}{density} \\\\Volume = \frac{40,000,000}{900} \\\\Volume = 44,444.44 \ m^3[/tex]

The minimum depth of harbor is calculated as:

[tex]height = \frac{volume}{Length \times width} \\\\height = \frac{44,444.44}{500\times 40} \\\\height = 2.22 \ m[/tex]

The minimum depth of harbor of the oil tank is 2.22 m

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Explanation:

Solution,

Volume (v)=287 cm^3

Mass(m)=816 g

Density(d)=m/v

=816/287

=2.84

So, the density of the block of marbles is 2.84 g/cm^3.

I hope it helped U

stay safe stay happy

Answer:

a) v = 4.9 m/s at 62° above the horizontal

b) h = 0.94 m above the board or 4.94 m above the water

c) v = 10 m/s at 77° below the horizontal

Explanation:

Assume UP and FOREWARD are positive and the diving board is the origin.

Ignore air resistance.

s = s₀ + v₀t + ½at²

In the vertical

-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)

vy₀ = 4.281 m/s

in the horizontal

3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)

vx₀ = 2.307... m/s

v = √(4.281² + 2.307²) = 4.863...

tanθ = 4.281 / 2.307

θ = 61.680...

v² = u² + 2as

s = (v² - u²) / 2a

h = (0² - 4.281²) / 2(-9.8) = 0.9350...

v² = 4.863² + 2(9.8)(4)

v = 10.1019...

cosθ = 2.307/10.1019

θ = 76.798

(a) The initial velocity of Samuel is 4.02 m/s

(b) The maximum height reached by Samuel is 0.55 m

(c)  The final velocity when he enters the water is 5.20 m/s

The given parameter:

(a) The initial velocity of Samuel is calculated as;

[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]

Assume downward motion to be in negative direction

The vertical component of the velocity is calculated as;

[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]

The horizontal component of the velocity is calculated as;

Assume forward motion to be in positive direction

[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]

The resultant of initial velocity is calculated as;

[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]

(b) The maximum height reached by Samuel is calculated as;

[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]

(c) The final velocity when he enters the water;

The height traveled before he hits the water, h = 0.55 m

[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]

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Explanation:

As the astronaut jumps and reaches the highest point, he is momentarily at rest, i.e.

[tex]v=0[/tex]

We also know

[tex]u=3, s=15[/tex]

By the formula,

[tex]v^2-u^2=2as[/tex]

where a is the acceleration of objectc due to gravity,

[tex]0^2-3^2=2a(15)[/tex]

[tex]-9=30a[/tex]

[tex]a=-0.3 ms^{-2}[/tex]

where negative sign indicates a downwards acceleration.

[tex]\boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]

Or

[tex]\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}[/tex]