Answers
Hello mashiamcphee141!
Let's solve for x in the given question.
[tex]\sf\:\frac { x + 3 } { 2 } + \frac { 2 x } { 7 } = 7\\\sf\:7\left(x+3\right)+2\times 2x=98 \\\sf\:7x+21+2\times 2x=98 \\\sf\:11x+21=98 \\\sf\:11x=98-21 \\\sf\:11x=77 \\\sf\:x=\frac{77}{11} \\\boxed{\sf\:x=7 }[/tex]
Steps :-
At first, multiply both sides of the equation by the LCM = 14.Now, simplify the equation using distributive property & other operations. We'll get the value of 'x' as 7.See the attachment if the working is not clear.
____________
[tex]\mathfrak{Lucazz}[/tex]
Given that:
[{(x+3)/2} + (2x/7)] = 7
Take the LCM of 2 and 7 is 14.
⇛[{7(x+3)+2(2x)}/14] = 7
⇛[{7x+21 + 4x}/14] = 7
⇛[{11x+21}/14] = 7/1
Now,
By using cross multiplication method,we get
⇛1(11x+21) = 7(14)
⇛11x + 21 = 58
⇛11x = 58-21
⇛11x = 37
∴ x = 37/11
Hence, the value of x will be 37/11 respectively.
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===
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====
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