Answer:
2500
Explanation:
Answer:
2500
Explanation: 1 mm is 1000 micrometers pls give me brainlist
1
Two beaker of water A and B , initially are at the same temperature.The temperature of the
water in beaker A is increased by 10F and the temperature of water in beaker B is increased
10 K. After these temperature change,which beaker of water has the higher temperature?
Answer :
beaker A , it is because the temperature increases is higher than beaker B.
Formula
(10°F − 32) × 5/9 + 273.15 = 260.928K
10 degrees fahrenheit = 260.928 kelvins
Formula
(10K − 273.15) × 9/5 + 32 = -441.7°F
10 kelvins = -441.67 degrees fahrenheit
beaker A , 10°F = -12.222 °C
beaker B , 10k = -263.15 °C
Beaker A of water will have a higher temperature than the temperature of beaker B.
How to change the temperature from Fahrenheit to Celcius?To convert the temperature Fahrenheit to Celsius formula is used from the scale Fahrenheit to Celsius. Both scales provide a way to measure the object’s hotness and coldness and are used to measure the temperature. The symbol used to express Fahrenheit is °F while the symbol used for Celsius is °C.
The formula used to change the temperature from Fahrenheit to Celsius as follows:
°C = (°F- 32)5/9
The temperature of beaker A is increased by 10°F. So the change in temperature in the Celcius scale is :
T(°C) = (10- 32)5/9
T(°C) = -12.22°C
The temperature of beaker B is increased by 10 K, then the temperature in Celcius is:
T(°C) = 10 - 273.15
T(°C) = - 263.15°C
Therefore, the temperature of beaker A will be higher after these changes if initially, both are at the same temperature.
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Name any two medium which states about the weather report.
Answer:
1. Government Agencies
2. Television Stations
Explanation:
Weather reports are needed by members of the public to be alert on daily and future weather trends as this would affect how they arrange their affairs. The weather can affect daily movement. For example, when it rains heavily, movement might become limited. Government agencies such as the National Weather Service (NWS), state the weather report.
Television channels like the Cable News Network have programs dedicated to weather reporting. The reporter states what the weather would be like in different cities and the public take note of that.
________are muscles connected to the skeleton.
1.) Smooth muscles
2.) Skeletal muscles
3.) Strong muscles
4.) Cardiac muscles
Answer: Skeletal Muscles
Explanation:
Skeletal muscles are attached to the skeleton by tough connective tissues called tendons
An____ collision occurs when an arrow hits the target.
Answer:
I think it's An inelastic collision occurs when an arrow hits the target because when the arrow hits it, the target and the arrow do not bounce away from each other.
Explanation:
A car is driving at 35 m/s. It decides to accelerate at 4.5 m/s2 for 3 seconds. How fast is it now moving?
Please show work even if you are an online student. I know it takes time, but I promise it is worth it.
I have included the units in the answer already. Please only put the number round all answers to 2 decimal places
if possible.
final velocity =
m/s
Blank 1
Next Page
6
? ? ?
Answer:
48.5
Explanation:
vf = vi + at
vf = 35 + 4.5(3)
vf = 35 + 13.5
vf = 48.5 m/s
What is the magnitude of the resultant vector? Round your answer to the nearest tenth
Answer:13.9 on edgy I just did it
Explanation:
Answer:
13.9
Explanation:
just did it
An athlete starts running from rest such that he covers a distance of 5mm in 0.50s with a constant change in velocity per unit time . when will he reach the finish line, if he is running a race of 50m?
Answer:
50 s
Explanation:
Given:
Δx = 0.005 m
v₀ = 0 m/s
t = 0.50 s
Find: a
Δx = v₀ t + ½ at²
0.005 m = (0 m/s) (0.50 s) + ½ a (0.50 s)²
a = 0.04 m/s²
Given:
Δx = 50 m
v₀ = 0 m/s
a = 0.04 m/s²
Find: t
Δx = v₀ t + ½ at²
50 m = (0 m/s) t + ½ (0.04 m/s²) t²
t = 50 s
33. A zebra is at rest 60 m away from a charging lion
running at 20 m/s. If the zebra accelerates at 4
m/s2, will the lion catch it?
Answer:
the lion will miss the zebra by 3 meters
Explanation
The zebra has gone 23.75m after 5 seconds
and the lion can only go 20 m/s
The lion can not catch zebra.
A diagram is attached below which describe situation of question.
The speed of Zebra is,
[tex]v=u+at=0+4t=4t[/tex]
Where u is initial speed of zebra.
The speed of lion is 20m/s.
The lead in speed by lion for every second is [tex](20-4t)[/tex].
[tex](20-4t)*t=60\\\\20t-4t^{2}=60\\ \\t^{2}-5t+15=0\\ \\t=\frac{5\pm\sqrt{(-35)} }{2}[/tex]
Here time is imaginary.
Therefore, The lion can not catch zebra.
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What is the velocity of a car that travelled a total of 75 km north in 1.5 hrs?
Explain Kinetic and potential energy
Answer:
Energy implies as the object’s capability to perform work. It is something that cannot be created or destroyed but can only be transformed. An object loses its energy, when it performs work, whereas it gains energy when the work is performed on it. Energy is broadly classified as kinetic energy and potential energy. While kinetic energy is the energy which an object contains because of a particular motion.
On the other hand, potential energy is the stored energy, because of its state of rest. As both the two forms of energy are measured in joules, people get easily confused between these two. So, take a read of the article which will help you to understand the differences between kinetic and potential energy.
Explanation:
Hope this helps - Good luck ^w
Answer:
Energy stored in an object due to its position is Potential Energy. · Energy that a moving object has due to its motion is Kinetic Energy.
Explanation:
A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the process of stopping. identify known variables such as V, V0, a, t, and delta x.
Answer:
The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds.
Initial velocity = 33 m/sFinal velocity = 0 m/sAverage velocity = (33 + 0) / 2 m/s = 16.5 m/sExplanation:
First, how long does it take the truck to come to a complete stop?( 33 m/s ) / ( 11 m / s^2 ) = 3 secondsThen we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.The time taken to stop the truck is 3 seconds. The final velocity is zero. Then, the distance travelled by the truck is 49.5 m.
What is acceleration ?Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.
Given initial velocity = 13.5 m/s
final velocity is zero since the bicycle is stopping.
then Δt = Δv/a
Δt = 33 m/s/ 11 m/s² = 3 seconds.
Hence, the truck will take 3 s to complete stop.
The distance covered within this time can be determined using the equation as follows:
s = u t + 1/2 at²
where u is the initial velocity
The acceleration a = - 11 m/s² the minus sign is due to deceleration.
s = (33m/s × 3 s) + (-11 m/s² ×3 s ×3 s) = 49.5 m.
Therefore, the truck will travel up to 49.5 m before stopping.
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what does it mean mechanical advange is less than one?
Answer:
this happens when the input force is greater than the output force
HOPE IT HELPED YOU...
Anyone get this can you please help me, can you also please do it step by step
Answer:
7.69 hours
Explanation:
3 hr/ 1000mi x 130mi = 7.69 hours or 7.7 hours
Q7 Describe two types of atomic change that produce electromagnetic
waves.
Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaja a 25.0 m/s hacia arriba. Use el teorema trabajo-energía para determinar a) su rapidez en el momento de ser lanzada. b) su altura máxima
Answer:
(a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
Explanation:
Given that,
Weight of stone = 3.00 N
Height = 15 m
Speed = 25.0 m/s
(a). We need to calculate the speed at the moment of being thrown
Using work energy theorem
[tex]W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)[/tex]
[tex]-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)[/tex]
Put the value into the formula
[tex]-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)[/tex]
[tex]-2\times9.8\times15=25^2-v_{1}^2[/tex]
[tex]-v_{1}^2=-300-25^2[/tex]
[tex]v_{1}=\sqrt{925}[/tex]
[tex]v_{1}=30.41\ m/s[/tex]
(b). We need to calculate the maximum height
Using work energy theorem
[tex][tex]W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2[/tex]
[tex]mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2[/tex]
Here, [tex]\dfrac{1}{2}mv_{2}^2[/tex]=0
[tex]-(mg)\times d=\dfrac{1}{2}mv_{1}^2[/tex]
[tex]d=\dfrac{v_{1}^2}{2g}[/tex]
Put the value into the formula
[tex]d=\dfrac{30.41^2}{2\times9.8}[/tex]
[tex]d=47.18\ m[/tex]
Hence, (a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
A car is traveling down the highway cruise control at 50m/s (this means its is traveling with a constant velocity NOT accelerating). If it does this for 5 minutes (300s), how far does it travel?
Given parameters:
Speed of car = 50m/s
Time of travel = 5minutes (300s)
Unknown;
Distance of travel = ?
To solve this problem, we need to understand how speed relates with distance and time.
Speed is a physical quantity. It is the distance traveled divided by time taken.
Speed = [tex]\frac{distance}{time}[/tex]
So,
Distance = speed x time
Input the parameters and solve for the distance;
Distance = 50m/s x 300s
Distance = 15000m
The distance covered during this time interval and speed is 15000m
Which of these is formed by a hot spot in Earth's crust?
Answer:
we need to know what the choices are?
Explanation:
Answer:
A hot spot is a region deep within the Earth's mantle from which heat rises through the process of convection. This heat facilitates the melting of rock. The melted rock, known as magma, often pushes through cracks in the crust to form volcanoes.
Do Now: You are asked to go to downtown Newark and pick up a small bag of materials for a grant project. Pay is $25. The materials will be delivered to Room 224, 2nd floor in Barringer High School. Create a numbered procedure, a list of steps that you will take to pick up and deliver the materials. Click for Example
Answer:
sorry im not in physics
Explanation:
What is the wavelength of a wave with a frequency of 466 Hz and a speed of
343 m/s?
A. 1.35 m
B. 0.74 m
C. 1.6 x 105 m
D. 6.25 x 10-6 m
Answer:
The answer is option BExplanation:
The wavelength of a wave can be found by using the formula
[tex] \lambda = \frac{c}{f} \\ [/tex]
where
c is the speed of the wave
f is the frequency
From the question
c = 343 m/s
f = 466 Hz
We have
[tex] \lambda = \frac{343}{466} \\ = 0.73605150...[/tex]
We have the final answer as
0.74 mHope this helps you
Answer: B: 0.74 m
Explanation:
Hope this helps / I did this question.
Determine the initial velocity of a marble that lands 1.8m away from a tabletop that is 0.8m from the ground.
Acceleration due to gravity = 9.85
0 2.25 m/s
2.6 m/s
0 1.8 m/s
4.5 m/s
Answer:
4.5 m/s
Explanation:
[tex]s_x[/tex] = Horizontal displacement = 1.8 m
[tex]s_y[/tex] = Vertical displacement = 0.8 m
[tex]u_x[/tex] = Horizontal velocity
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
t = Time taken to fall down
[tex]s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.8=0+\dfrac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\dfrac{2\times 0.8}{9.8}}\\\Rightarrow t=0.4\ \text{s}[/tex]
[tex]s_x=u_xt+\dfrac{1}{2}a_xt^2\\\Rightarrow 1.8=u_x\times 0.4+0\\\Rightarrow u_x=\dfrac{1.8}{0.4}\\\Rightarrow u_x=4.5\ \text{m/s}[/tex]
The initial velocity of the marble is 4.5 m/s.
a dog walks 14 meters to the east and then 20 meters back to the west.
Answer:
who gets theses questions XD
Explanation:
If the radio waves that are sent from the speed gun have a frequency of 400,000,002 Hz and the radio waves reflected off an approaching car have a frequency of 400,000,109 Hz, what is the speed of the car? (Hz is the SI unit of frequency, equal to cycles per second).
Answer:
40.1 m/s or 144.36 km/h
Explanation:
The equation is (v=∆ f/f) x (c/2)
V is velocity
delta f is returned frequency minus intial frequency divided by the initial frequency
c is the speed of light in m/s divided by 2
v= (400,000,109 Hz - 400,000,002 Hz)/400,000,002Hz x (299,792,458 m/s)/2
______________ rock forms beneath Earth's surface.
Answer:
Igneous rocks form beneath Earth's surface.
Explanation:
Igneous rocks form beneath the Earth's surface
A physical quantity that has both magnitude and a direction is the definition of
Explanation:
Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude.
A swimmer sets off headed west at 0.40 m/s directly towards the opposite shore of a swift river. The swimmer makes it to the opposite shore 30 meters downstream of their expected position. If the river is 7.5 meters wide, what is the velocity of the water relative to the shore?
Answer:
Explanation:
River is 7.5 m wide . Time taken by it cover this displacement
= displacement / velocity
= 7.5 / 0.4
= 18.75 s
During this period , swimmer will have a displacement of 30 m due to velocity of river water .
Displacement of 30 m downstream will be due to flow of river .
velocity of water flow = displacement / time
= 30 / 18.75
= 1.6 m /s
Does anybody know anything about speed and velocity? im hella stuck.
Answer:
lm.ao i was stuck too when i was on that
Explanation:
what u need to know sis?
speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes.
b) A stone is dropped from the roof of a four storey building. The height of
each storey is 4.9m . Taking g =9.8m/s2 , calculate the velocity with
which the stone will hit the ground.
Answer:
9.8m/s
Explanation:
Given,
distance of each storey () = 4.9m
distance of 4 storey (s) = 19.6m
acceleration due to gravity (g) = 9.8 m/s^2
time given (t) = ?
velocity = (?)
initial velocity (u) = 0 {due to fall from certain height}
using formula,
s = ut + 1÷2at^2
s = 0 + 9.8÷2×t^2
19.6×2÷9.8 = t^2
4 = t^2
t = 2
now,
velocity ( v )= s ÷ t
v = 19.6 ÷ 2
v = 9.8 m/s
ans
8. An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object? ___________________________
Answer:
Mass of object is 0.5kg
Explanation:
Given the following data;
Force = 6N
Acceleration = 12m/s²
Mass =?
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making mass (m) the subject, we have;
[tex]Mass (m) = \frac{F}{a}[/tex]
Substituting into the equation;
[tex]Mass (m) = \frac{6}{12}[/tex]
Mass, m = 0.5kg.
Therefore, the mass of the object is 0.5kg
It is required to design a zener shunt regulator to provide a regulated voltage of about 10 V. The available 10-V, 1-W zener of type 1N4740 is specified to have a 10-V drop at a test current of 25 mA. At this current, its r z is 7 . The raw supply, V S , available has a nominal value of 20 V but can vary by as much as ±25%. The regulator is required to supply a load current of 0 mA to 20 mA. Design for a minimum zener current of 5 mA.
Answer:
jgfsdghjjuk
Explanation:
khhnghjj
A 4kg block and a 2kg block can move on horizontal frictionless surface. The blocks are accelerated by a +12-N force that pushes the large block against the smaller one.'
a) Determine the force that the 2kg block exerts on the 4kg block
b) Determine the force that the 4kg block exerts on the 2kg block.
Answer:
a) -4 N
b) +4 N
Explanation:
Draw a free body diagram for each block.
For the large block, there are 2 forces: 12 N pushing to the right, and F pushing to the left.
For the small block, there is 1 force, F pushing to the right.
There are also weight and normal forces in the vertical direction, but we can ignore those.
Sum of forces on the large block in the x direction:
∑F = ma
12 − F = 4a
Sum of forces on the small block in the x direction:
∑F = ma
F = 2a
2F = 4a
Substitute:
12 − F = 2F
12 = 3F
F = 4
The small block pushes on the large block 4 N to the left (-4 N).
The large block pushes on the small block 4 N to the right (+4 N).