Daniel earns $5.00 an hour babysitting. He babysat 6 hours Friday and more hours Saturday, and he earned
$55.00 for the weekend. How many hours did he babysit on Saturday?
A. 5
B. 11
C. 9
D. 6

Answer:

The area of the figure is 385.5 in²

Step-by-step explanation:

The area of the figure = area of hemisphere + area of rectangle

Radius of hemisphere = 10/2 = 5 in

=> 3πr² + length × breadth

=> { 3×(3.14) × 5 × 5} + { 15 × 10 }

=> { 9.42 × 25 } + { 150 }

=> 235.5 + 150

=> 385.5 in²

Answer:

The answer is C. 418cm2

Step-by-step explanation:

Answer:

16.76 ft³

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Set up the system of equations for volume. We'll use V for volume, and h for height.

[tex]V = \pi r^2 \frac{h}{3}[/tex]

Now, turn the equations into a multiplication problem, use 2 for radius, and 4 for height.

[tex]\pi * 2 * \frac{4}{3}[/tex]

Next, calculate.

[tex]\pi *2^2 = 12.5663706144...\\\frac{4}{3} = 1.3333333...\\\\12.566 * 1.333 = 16.75048(rough~estimate)[/tex]

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Ask in comments.

Answer:

a = 11

Step-by-step explanation:

Using the Pythagorean Theorem:

[tex] {a}^{2} + {26.4}^{2} = {28.6}^{2} [/tex]

[tex] {a}^{2} + 696.96 = 817.96[/tex]

[tex] {a}^{2} = 121[/tex]

[tex]a = 11[/tex]

Answer:

39

Step-by-step explanation:

Let h: hit

Let n: not hit

1) We can create two equations and solve them simultaneously using the substitution method or elimination.

h + n = 100

12h - 4n = 224

2) Solve them. I will demonstrate using the substitution method.

n = 100 - h

-----------------------

12h - 4(100 - h) = 224

12h - 400 + 4h = 224

16h = 224 + 400

16h = 624

h = 624/16

h = 39

3) Substitute the result into one of the equations above.

n = 100 - 39

n = 61

Since the question wants you to write the number of times the dragon was hit, the answer is 39.

A rectangular prism with a volume of 400 cubic centimeters has dimensions of 5 cm, 8 cm, and 10 cm with the value of x being 4.

The volume of the rectangular prism is the product of the length, breadth, and height of the given prism.

Volume of rectangular prism = (length x width x height)

A rectangular prism with a volume of 400 cubic centimeters has the dimensions x + 1 centimeter, 2x centimeters, and x + 6 centimeters.

Volume of rectangular prism = (length x width x height)

      400 cm³  =( x + 1 )(2x)(x + 6 )

        400 cm³  =( x + 1 )(2x)(x + 6 )

Substitute 4cm as the value of x.

x + 1 centimeters = 4 cm + 1 cm = 5 cm

2x centimeters = 2 ( 4cm) = 8 cm

x + 6 centimeters = 4 cm + 6 cm = 10 cm

Volume of rectangular prism  = 10 cm × 5 cm × 8 cm

           = 400 cm³

Thus, the given rectangular prism of 400 cubic centimeters has dimensions of 5 cm, 8 cm, and 10 cm.

Learn more about rectangular prism;

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Answer:

Step-by-step explanation:

its 10

Answer:

Problem 4: Dog pens 2 and 3

Problem 5: Dog Pens 1 and 2

Problem 6: 6cm and 6cm

problem 7: A

Step-by-step explanation:

Answer:

14.3

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2   where a and b are the legs and c is the hypotenuse

14^2 + 3^2 = c^2

196 + 9 = c^2

205 = c^2

Take the square root of each side

sqrt(205) = sqrt(c^2)

14.31782106 = c

Rounding to the nearest tenth

14.3 = c

Answer :

⠀

Explanation :

⠀

Solution :

where,

We know that,

[tex]{\longrightarrow \pmb{\mathbb {\qquad (XZ) {}^{2} = (XY) {}^{2} +( YZ) {}^{2} }}} \\ \\ [/tex]

Now, we will substitute the given values in the formula :

[tex]{\longrightarrow \sf{\pmb {\qquad (XZ) {}^{2} = (3) {}^{2} +( 14) {}^{2} }}} \\ \\ [/tex]

We know that, (3)² = 9 and (14)² = 196. So,

[tex]{\longrightarrow \sf{\pmb {\qquad (XZ) {}^{2} = 9 +196 }}} \\ \\ [/tex]

Now, adding 9 and 196 we get :

[tex]{\longrightarrow \sf{\pmb {\qquad (XZ) {}^{2} = 205 }}} \\ \\ [/tex]

Now, we'll take the square root of both sides to remove the square from XZ :

[tex]{\longrightarrow \sf{\pmb {\qquad \sqrt{(XZ) {}^{2}} = \sqrt{205 }}}} \\ \\ [/tex]

When we take the square root of (XZ)² , it becomes XZ,

[tex]{\longrightarrow \sf{\pmb {\qquad XZ = \sqrt{205 }}}} \\ \\ [/tex]

We know that, square root of 205 is 14.317 (approx) .

[tex]{\longrightarrow { \mathbb{\pmb {\qquad XZ }}}} \approx \pmb{\mathfrak{14.317 } }\\ \\ [/tex]

So,

Answer:

The relation is  c = 3.519g.

Step-by-step explanation:

This is direct variation.

c = kg     where k is the constant of variation.

Substituting the given values:

190 = k * 54

so the constant of variation is:

k = 190/54 = 3.519   to nearest thousandth,

and  the equation is:

c = 3.519g.

Answer:

Area of Trapezium=1/2h(L1+L2)

I think it will help you

Answer: 1.8 X 10^8

Step-by-step explanation: 6.0 X 10^7 times .3 = 1.8 X 10^8

Answer:

A frequency distribution is a table that shows “classes” or “intervals” of data entries with a count of the number of entries in each class.

Step-by-step explanation:

hope this helps you a little!

Answer:

I'd love to help, but I need the full question first!!!

Answer:

4

Step-by-step explanation:

360 degrees in a circle /12  numbers on clock= 30 degrees for each number 120/30=4

Answer:

870.

Step-by-step explanation:

There are 30 choices of representatives. This leaves 29 choices for alternate representatives.

If one person gets elected for representative, there are 29 choices for an alternate representative.

This is the case if any of the 30 students get elected as representatives.

That means you can set it up as:

x*y where x is the choice of representatives and y is the choice of alternate representatives.

30 * 29, or 870.

Here is a visual example. Students a - dd are shown here.

a b c d e f g h i j k l m n o p q r s t u v w x y z aa bb cc dd

In this case, a has been chosen as class president. Any of the other 29 students could be a alternate, and then paired with a. This makes 29 total possible pairings. This is then repeated for the possibility of every student becoming a president, which creates 30*29.

Please tell me if this is wrong, I will try to make changes!

Answer:

1/4

Step-by-step explanation:

Amplitude is equal the A part of the function which is 1/4.

The estimated difference of the area of Colorado and Wyoming in scienfic notation is  2 x [tex]10^{-1}[/tex]m².

Scienfic notation is used in expressing large numbers in smaller numbers. In order to write a number in stscienfic notation, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10.

Area of Colorado = (6.12 x [tex]10^{5}[/tex]) x (4.5 x [tex]10^{5}[/tex]) = 27.54 x [tex]10^{10}[/tex]

= 2.8 x [tex]10^{11}[/tex]m²

Difference in the areas = 2.8 x [tex]10^{11}[/tex]m² - 2.6 x x [tex]10^{11}[/tex]m² = 0.2m²

= 2 x [tex]10^{-1}[/tex]m²

To learn more about scienfic notation, please check: https://brainly.com/question/25334755

Answer:

Step-by-step explanation:

Equation

Let the angles measure = x

Let the complimentary angle = 90 - x

3x - (90 - x) = 46                      Remove the brackets

Solution

3x - 90 + x = 56                       Combine like terms on the left

4x - 90 = 56                             Add 90 to both sides

4x - 90 +90 = 56 + 90             Combine

4x = 146                                    Divide by 4

4x/4 = 146/4        

x = 36.5

Answer

The given angle is 36.5

Answer:

B

Step-by-step explanation:

Inverse is opposite. So, domain becomes range and range becomes domain

x<2 of domain becomes y<2 for range

y>0 of range becomes x>0 of domain

The factored form of the given quadratic equation is (3x+5)(3x+2).

The given quadratic equation is:

[tex]9x^{2} +21x+10[/tex]

Any equation of the form [tex]ax^{2} +bx+c=0[/tex] is called a quadratic equation where [tex]a\neq 0[/tex].

Splitting the middle term of the given quadratic equation:

[tex]9x^{2} +15x+6x+10[/tex]

[tex]3x(3x+5)+2(3x+5)[/tex]

[tex](3x+5)(3x+2)[/tex]

So this is the factored form of the given quadratic equation.

Hence, the factored form of the given quadratic equation is (3x+5)(3x+2).

To get more about quadratic equations visit:

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Answer:

picture of answer.

Step-by-step explanation:

The options have not been given but three correct alternatives have been presented as the solution.

We have given,

[tex]\frac{c^2-4}{c+3} /\frac{c+2}{3(c^2-9)}[/tex]

Applying the rule a^2-b^2 to the numerator of the first term and the denominator of the second term,

[tex](a^2-b^2)=(a-b)(a+b)[/tex]

By applying the above formula we have:

[tex]=\frac{c^2-2^2}{c+3} /\frac{c+2}{3((c+3)(c-3)}[/tex]

[tex]=\frac{(c-2)(c+2)}{c+3} /\frac{c+2}{3((c+3)(c-3)}[/tex]

Therefore the solution is,

[tex]=(c-2) \times 3(c-3)\\\\=3(c^2-5c+6)\\\\=3c^2-15c+18[/tex]

To learn more about the expression visit:

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Answer:

C.) StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction"/>

Step-by-step explanation:

Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (c squared minus 9) EndFraction?

StartFraction c + 3 Over c squared minus 4 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction 3 (c squared minus 9) Over c + 2 EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction

StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction

Answer:

A)

Step-by-step explanation:

Given function:  

[tex]h(t)=-16t^2+75t+25[/tex]

The domain (input values) will be the x-intercepts, so the values of t when h(t) = 0.

The quickest way to find these is to use the quadratic formula.

Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\implies t=\dfrac{-75 \pm \sqrt{75^2-4(-16)(25)} }{2(-16)}[/tex]

[tex]\implies t=\dfrac{-75 \pm \sqrt{7225}}{-32}[/tex]

[tex]\implies t=\dfrac{75 \pm 85}{32}[/tex]

[tex]\implies t=5, t=-\dfrac{5}{16}[/tex]

Time cannot be negative.

When h(t) = 0, the disk will hit the floor.

Therefore, the domain is restricted to 0 ≤ t ≤ 5

Answer:

D. 6(x+2y)-y

Step-by-step explanation:

Both expressions can be simplified into 6x + 11y

3(2x+4y)-y
6x + 12y - y
6x + 11y

6(x+2y)-y
6x + 12y - y
6x + 11y

Answer:

D. 6(x+2y)-y

Step-by-step explanation:

To solve for the equivilent expression, begin by simplifying the given expression. (1) To simplify 3(2x+4y)-y, you can first multiply 3 into the parentheses then combine like terms; (6x+12y)-y or 6x + 12y - y --> 6x + 11y. (2) Solve to find which expression listed will yield the same product, 6x + 11y, when simplified as well. This is quiet straightfoward to see and you wont be needing to solve each individual problem. 6(x+2y)-y will simplify to 6x + 12y - y which is then equal to --> 6x + 11y. Meaning, D. 6(x+2y)-y is equvillent to 3(2x+4y)-y.

Answer:

1. C 3 1/8

2. A 3

Step-by-step explanation:

The antilog provides the solution to the logarithmic equation. Then x has values of 2 and 4.

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The logarithmic equation is given below.

[tex]\log _6(x^{2} +8)= 1+ \log _6x\\\\\log _6(x^{2} +8)= \log_66+ \log _6x\\\\\log _6(x^{2} +8)= \log _66x\\[/tex]

Take antilog, then we have

[tex]\begin{aligned} x^{2} +8 &= 6x\\\\x^2 -6x + 8 &= 0\\\\x^2 -4x - 2x +8 &=0\\\\(x-4)(x-2) &= 0\\\\x&= 2, 4\end{aligned}[/tex]

Then the value of the x is 2 and 4.

More about the factorization link is given below.

https://brainly.com/question/6810544

Check the picture below.

[tex]p(h)=5000(2)^h\implies \stackrel{p(h)}{100000}~~ = ~~5000(2)^h\implies \cfrac{100000}{5000}=2^h \\\\\\ 20=2^h\implies \log(20)=\log(2^h)\implies \log(20)=h\log(2) \\\\\\ \stackrel{\textit{using the \underline{change of base rule}}}{\cfrac{\log(20)}{\log(2)}=h\implies \log_2(20)=h}\implies 4.3219\approx h[/tex]

Answer:

49

Step-by-step explanation:

12 hotdogs per min × 8 minutes = 96

145-96= 49

So he will have 49 hotdogs left.