Answer:
a) [tex]\beta = 1.111\times 10^{-7}[/tex], b) [tex]\beta = 9\times 10^{-7}[/tex], c) [tex]\beta = 3.087\times 10^{-6}[/tex], d) [tex]\beta = 2.5\times 10^{-5}[/tex], e) [tex]\beta = 0.5[/tex], f) [tex]\beta = 0.877[/tex]
Explanation:
From relativist physics we know that [tex]c[/tex] is the symbol for the speed of light, which equal to approximately 300000 kilometers per second. (300000000 meters per second).
a) A car traveling 120 kilometers per hour:
At first we convert the car speed into meters per second:
[tex]v = \left(120\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]
[tex]v = 33.333\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 33.333\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{33.333\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 1.111\times 10^{-7}[/tex]
b) A commercial jet airliner traveling 270 meters per second:
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 270\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{270\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 9\times 10^{-7}[/tex]
c) A supersonic airplane traveling Mach 2.7:
At first we get the speed of the supersonic airplane from Mach's formula:
[tex]v = Ma\cdot v_{s}[/tex]
Where:
[tex]Ma[/tex] - Mach number, dimensionless.
[tex]v_{s}[/tex] - Speed of sound in air, measured in meters per second.
If we know that [tex]Ma = 2.7[/tex] and [tex]v_{s} = 343\,\frac{m}{s}[/tex], then the speed of the supersonic airplane is:
[tex]v = 2.7\cdot \left(343\,\frac{m}{s} \right)[/tex]
[tex]v = 926.1\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 926.1\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{926.1\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 3.087\times 10^{-6}[/tex]
d) The space shuttle, travelling 27000 kilometers per hour:
At first we convert the space shuttle speed into meters per second:
[tex]v = \left(27000\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]
[tex]v = 7500\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 7500\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{7500\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 2.5\times 10^{-5}[/tex]
e) An electron traveling 30 centimeters in 2 nanoseconds:
If we assume that electron travels at constant velocity, then speed is obtained as follows:
[tex]v = \frac{d}{t}[/tex]
Where:
[tex]v[/tex] - Speed, measured in meters per second.
[tex]d[/tex] - Travelled distance, measured in meters.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]d = 0.3\,m[/tex] and [tex]t = 2\times 10^{-9}\,s[/tex], then speed of the electron is:
[tex]v = \frac{0.3\,m}{2\times 10^{-9}\,s}[/tex]
[tex]v = 1.50\times 10^{8}\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 1.5\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{1.5\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 0.5[/tex]
f) A proton traveling across a nucleus (10⁻¹⁴ meters) in 0.38 × 10⁻²² seconds:
If we assume that proton travels at constant velocity, then speed is obtained as follows:
[tex]v = \frac{d}{t}[/tex]
Where:
[tex]v[/tex] - Speed, measured in meters per second.
[tex]d[/tex] - Travelled distance, measured in meters.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]d = 10^{-14}\,m[/tex] and [tex]t = 0.38\times 10^{-22}\,s[/tex], then speed of the electron is:
[tex]v = \frac{10^{-14}\,m}{0.38\times 10^{-22}\,s}[/tex]
[tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{2.632\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 0.877[/tex]
answer fast plz
....................
Answer:
114 m/s
Explanation:
see the image below
A car traveling from rest to a velocity of 7.0 m/s accelerates uniformly at the rate of 0.80 m/s2. What is its tr. 31
time?
Answer:
54mph
Explanation:
Long flights at midlatitudes in the Northern Hemisphere encounter the jet stream, an eastward airflow that can affect a plane's speed relative to Earth's surface. If a pilot maintains a certain speed relative to the air (the plane's airspeed), the speed relative to the surface (the plane's ground speed) is more when the flight is in the direction of the jet stream and less when the flight is opposite the jet stream. Suppose a round-trip flight is scheduled between two cities separated by 4300 km, with the outgoing flight in the direction of the jet stream and the return flight opposite it. The airline computer advises an airspeed of 930 km/h, for which the difference in flight times for the outgoing and return flights is 61 min. What jet-stream speed is the computer using
Answer:
103.52 km/h
Explanation:
We are given;
Distance between two cities; d = 4300 km
airspeed; v_as = 930 km/h
Difference in flight time; Δt = 61 min = 1.0167 h
Now, the equation of motion to find the distance is given as;
d = vt
Where v = v_as + v_js
v_as is the airspeed
v_js is the jet speed
Thus;
d = (v_as + v_js)t
Thus, time(t1) for outgoing flight is;
t1 = d/(v_as + v_js)
Meanwhile, time(t2) for the return flight, the jet stream velocity will be negative and time is;
t2 = d/(v_as - v_js)
Recall that Difference in flight time; Δt = 61 min.
Thus;
Δt = t2 - T1 = [d/(v_as - v_js)] - [d/(v_as + v_js)]
Factorizing out, we have;
Δt = d[1/(v_as - v_js)] - [1/(v_as + v_js)]
Furthermore, it gives;
Δt = d[(v_as + v_js - v_as + v_js)]/((v_as - v_js) × (v_as + v_js))
Δt = d(2v_js)/((v_as)² - (v_js)²)
Cross multiply to get;
(2dv_js)/Δt = ((v_as)² - (v_js)²)
(v_js)² + ((2dv_js)/Δt) - (v_as)² = 0
Plugging in values for d,v_as and Δt gives;
(v_js)² - ((2 × 4300 × v_js)/1.0167) - (930)² = 0
(v_js)² - (8458.7329v_js) - 864900 = 0
Using quadratic formula, we have;
v_js = 103.52 km/h
The airline computer advises an airspeed of 930 km/h, for which the difference in flight times for the outgoing and return flights is 61 min. The jet stream speed obtained using the quadratic formula is 103.52 km/h.
Given:
Distance between two cities; d = 4300 km
airspeed; v(as) = 930 km/h
Difference in flight time; Δt = 61 min = 1.0167 h
Now, the equation of motion to find the distance is given as;
d = vt
Where v = v(as) + v(js)
d = v(as) + v(js)t
At time t₁, t₁ = d/v(as) + v(js)
At time t₂, t₂ = d/v(as) + v(js)
Recall that Difference in flight time; Δt = 61 min.
Δt = d/v(as) + v(js) - d/v(as) + v(js)
Δt = d[(v(as) + v(js) - v(as) + v(js)]/((v(as) - v(js)) × (v(as) + v(js)))
Δt = d(2v(js))/((v(as))² - (v(js))²)
(2dv(js))/Δt = ((v(as))² - (v(js))²)
(v(js))² + ((2dv(js))/Δt) - (v(as))² = 0
(v(js))² - ((2 × 4300 × v(js))/1.0167) - (930)² = 0
(v(js))² - (8458.7329v(js)) - 864900 = 0
Using the quadratic formula, we have;
v(js) = 103.52 km/h
Therefore, The jet stream speed obtained using the quadratic formula is 103.52 km/h.
To know more about the quadratic formula:
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If a person has the values for an object's density and volume, what value can be calculated?
o the object's size
o the object's mass
the shape the object forms in a container
the amount of space the object takes up
Answer:
Answer:
The object's mass.
Explanation:
The formula d=m/v.
d --> density
m--> mass
v --> volume
With density and volume given, you can calculate the mass of the object.
Explanation:
What do virtually all daily task require ?
Answer:muscle strength
Explanation: bc well you would need it
What were the quartering acts
Answer:
The quartering act of 1765 required the colonies to house British soldiers in barracks provided by the colonies.
blank refers to the method of spreading fertilizer evenly over the entire field by hand it is done at the blank stage
Answer:
Broadcasting is the method, not sure about the stage it is done in
Explanation:
Answer:
Broadcasting is the first (blank) second (blank) is Cultivation.
Explanation:
I took the test & got this answer correct.
What are the different ways that the simulation shows you that the equation is balanced, visually? For each balanced reaction, indicate the total number of molecules (the big coefficients) in the table. Reaction Total Number of Molecules Reactant Side (left) Product Side (right) Make Ammonia Separate Water Combust Methane Is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the right side of the equation? Explain your answer. For each balanced reaction, indicate the total number of atoms (the individual atoms) in the table. Hint: This may requiring multiplying subscript numbers by coefficients for some atoms. Example: 2NH3–There are 2 N atoms, and 6 H atoms (2 x 3). Reaction Total Number of Atoms Reactant Side (left) Product Side (right) Make Ammonia Separate Water Combust Methane Is the number of total atoms on the left side of a balanced equation always equal to the number of total atoms on the right side of the equation? What strategies did you use when you played the balancing chemical equations game? Which atoms were the easiest to start examining to try to balance the equations? Did it require trial and error? In the simulation, were you able to use non-integer numbers (like ½ or 0.43) for the coefficients in a balanced equation?
Answer:
There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.
Reaction Total Number of Molecules
Reactant Side (left) Product Side (right)
Make Ammonia 4 2
Separate Water 2 3
Combust Methane 3 3
No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.
Reaction Total Number of Atoms
Reactant Side (left) Product Side (right)
Make Ammonia 1C, 4H, 4O 1 C, 4H, 4O
Separate Water 2H, 4O 2H, 4O
Combust Methane 2N, 6H 2N, 6H
Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.
Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.
No, you could not use a non-integer number.
Explanation:
PF
Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.
Reaction Total Number of Molecules
Reactant Side (left) Product Side (right)
Make Ammonia 4 2
Separate Water 2 3
Combust Methane 3 3
No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.
Reaction Total Number of Atoms
Reactant Side (left) Product Side (right)
Make Ammonia 1C, 4H, 4O 1 C, 4H, 4O
Separate Water 2H, 4O 2H, 4O
Combust Methane 2N, 6H 2N, 6H
Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.
Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.
No, you could not use a non-integer number.
Cooling causes a material to
Answer:
whats the question?
Explanation:
Answer:
2 Key Concepts Heating and cooling can cause materials to change characteristics, such as state, color, and texture. Heating causes ice to become liquid water and cooling causes condensation to form on a window, mirror, or on the outside of a glass of water.
Explanation:
what is the principal of moment
Answer:
hope it helps...
Explanation:
The Principle of Moments states that when a body is balanced, the total clockwise moment about a point equals the total anticlockwise moment about the same point.
Answer:
The Principle of Moments states that when a body is balanced, the total clockwise moment about a point equals the total anticlockwise moment about the same point.
100 POINTS. PLEASE PROVIDE EXPLANATION
Answer:
60 kg
80 kg
Explanation:
Work is equal to the change in energy.
W = ΔE = E − E₀
Let's start with block B. The work done by the tension force is equal to the change in energy. Initially, the block has potential energy. Finally, the block has kinetic energy.
W = ΔE
FΔy = ½ mv² − mgh
T (-2.0 m) = ½ m (6.00 m/s)² − m (10 m/s²) (2.0 m)
T (-2.0 m) = m (-2 m²/s²)
T = m (1 m/s²)
Now let's look at block A. The work done by tension and against friction is equal to the change in energy. Initially, the block has no energy. Finally, it has both kinetic and potential energy.
W = ΔE
Fd = ½ mv² + mgh − 0
(T − Nμ) (2.0 m) = ½ (4.00 kg) (6.00 m/s)² + (4.00 kg) (10 m/s²) (⅗ × 2.0 m)
(T − Nμ) (2.0 m) = 120 J
T − Nμ = 60 N
Draw a free body diagram of block A and sum the forces in the perpendicular direction to find the normal force N.
N = mg cos θ
N = (4.00 kg) (10 m/s²) (⅘)
N = 32 N
Substitute:
T − 32μ = 60 N
If μ = 0, then T = 60 N and m = 60 kg.
If μ = ⅝, then T = 80 N and m = 80 kg.
Answer:did you find you answer also i answered so you can give him brainiest
Explanation:
A 63.9 kg water skier is pulled by a
125 N force at a 31.5° angle, while
the water creates a 84.8 N force
pulling directly backward. What is the
y-component of the acceleration?
Answer:
[tex]a_{x} = 0.342 \frac{m}{ {s}^{2} } \: "x \: component \: of \: acceleration"
\: \\ a_{y} = 1.02 \: \frac{m}{ {s}^{2} } \: "y \: component \: of \: acceleration" [/tex]
Explanation:
Given a mass of 63.9kg with a total applied force of 125 N at a 31.5° inclination relative to the horizontal and vertical, and a horizontal resistance force of 84.8 N. The components of acceleration can be calculated as follows:
Force = mass × acceleration
Vertical component of a vector = vector × Sin(angle)
Horizontal component of a vector = vector × Cos(angle)
extra:
V = √x^2+y^2
θ (angle, "theta") = arctan or inverse tan(y/x) (For this instance. Theta is usually an angle measure though)
x = V cos θ
y = V sin θ
____________________
To find the vertical component of acceleration we must first take the vector quantity of our force which is 125 N (Newtons) and it's angle of 31.5°.
Vertical force = 125 × sin(31.5 degrees) = 125 × 0.5225 = 65.312 N [aka the normal force]
This works because force is a vector, it has both direction(by the angle of force), and magnitude(it's quantity).
Then take the force equation, and rearrange it to solve for the upward acceleration: F = m × a → a = F/m.
a = 65.312/63.9 ≈ 1.02 m/s^2.
Then for the horizontal acceleration, take the cosine for the horizontal part
A car drives horizontally off a cliff that is 30 meters high killing the driver on impact. The grieving widow claims her husband would never have driven faster than the posted speed limit of 35 mph and has hired a lawyer to sue the city for negligence. You are sent to investigate the crash site. You measure that the car landed 75 m from the base of the cliff [1 mph = 0.447 m/s].
A. Draw the detailed sketch for this motion with all of the relevant information, variables, and numbers contained in the sketch.
B. Write the three projectile equations with the known values and unknown variables placed into the equation.
C. Determine the time of fall. Then determine vix of the car as it flies off the cliff.
D. Based on what you were able to determine, assess whether the city is held liable for the accident
Answer:
b) 0 = y₀ + 0 - ½ g t² , v₀ₓ = x / t
c) v₀ₓ = 30.31 m / s
Explanation:
This is a projectile launching exercise, in your statement you have units of several systems, we are going to reduce everything to the SI system
v = 35 mph (0.447 m / s / 1 mph) = 15.645 m / s
y₀ = 75 m
A) In the attachment we can see a diagram of the movement of the vehicle in its fall
B) let's find the time for the fall to the base of the cliff (y = 0)
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
when the vehicle leaves the cliff it goes horizontally, so its vertical speed is zero (v_{oy} = 0)
0 = y₀ + 0 - ½ g t²
t = √2y₀ / g
with this time we can use the equation of motion on the x axis
x = v₀ₓ t
v₀ₓ = x / t
C) we perform the calculations
t = √ (2 30 / 9.8)
t = 2.474 s
v₀ₓ = 75 / 2.474
v₀ₓ = 30.31 m / s
D) as we can see, the vehicle speed when leaving the cliff is almost twice the allowed speed (15.6 m / s)
therefore the city is not responsible for the accident
If a baseball and a cannonball are dropped from the same height at the
same time, with no air resistance, which ball will hit the ground first?"
2 po
O The cannonball lands first
O The baseball lands first
O Both balls land at the same time
O The ball with the larger volume lands first
You ill simply enter your numeric answer directy ieto the space provided to the right of the equal sign. Answor the following question by typing the numenic answer into the answer boa If you have a gross of items, you have 144 items. if you buy a gross of eggs, how many dozen eggs do you have? Express your answer in dozens. Do not enter the units; they are provided to the right of the answer box Hints number of eggs dozen Submit My Answers Give Up
Part B accistentaily entar commas, you aldl get a When entering large numbers in the answer box, do not use commas. For example, enter 3274400 for the number 1,26.400.Do not enter 1,276,403. you message that your answer is incorrect. Answer the following question by typing the numeric answer into the answer box. What is the sum of 9260 and 32407 Express your answer numerically to at least three significant figures
Answer:
a
12
b
41667
Explanation:
From the question we are told that
Generally 1 dozen of egg is equivalent to 12 pieces of eye
So given that a gross of item is equivalent to 144 items
x dozens of eggs is equivalent to a gross of item
So
[tex]x = \frac{144 * 1}{12}[/tex]
=> [tex]x = 12 \ dozens \ of \ eggs[/tex]
Generally the sum of 9260 and 32407 is
9 2 6 0
+ 3 2 4 0 7
4 1 6 6 7
what is power?
a- the magnitude of a force needed to move an object
b- how much work can be done in a given time
c- the distance over time that an object moves
d- the energy needed to create work
Answer:
b- how much work can be done in a given time
how much work can be done in a given time
What is reduction division mean ?
Answer:
Reduction division: The first cell division in meiosis, the process by which germ cells are formed. In reduction division, the chromosome number is reduced from diploid (46 chromosomes) to haploid (23 chromosomes). Also known as first meiotic division and first meiosis.
Explanation:
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The weld bead in SMAW is formed by the?
The weld bead in SMAW is formed by the electrode wire core mixing with the molten base metal, Therefore the correct option is D.
What is Shielded Metal Arc Welding (SMAW)?It is a type of manual arc welding process which utilizes a consumable electrode covered with flux to protect the weld bead.
For SMAW either direct current or alternating current can be used to form the electric arc. The electrode melts and forms a molten weld pool with the base metal by using the thermal energy produced from the electric arc.
The weld bead in Shielded Metal Arc Welding is formed by the electrode wire core mixing with the molten base metal.
learn more about Shielded Metal Arc Welding (SMAW)
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An object that gains electrons becomes ___charged?
Answer:The charge becomes nuetral
Explanation:
Whenever electrons are transferred between objects, neutral matter becomes charged. When an atom loses electrons, it becomes a positively charged ion, or cation. When an atom gains electrons, it becomes a negative charged ion, or anion.
1. Three kids in a parking lot launch a rocket that rises
into the air along a 380-m long arc in 40s.
Determine its average speed.
Answer:
Average speed equals distance / time
380 / 40 = 9.5 m/s.
Explanation:
A net force of 20 N acting on a wooden block produces an
acceleration of 4.0 m/s2 for the block. What is the mass of
the block?
Answer:
From the second law of motion:
F = ma
we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s
So, F= 20N and a = 4 m/s/s
Replacing the variables in the equation:
20 = 4* m
m = 20 / 4
m = 5 kg
A block suspended from a spring is oscillating vertically with a frequency of 4 Hz and an amplitude of 7 cm. A very small rock is placed on top of the oscillating block just as it reaches its lowest point. Assume that the rock has no effect on the oscillation. At what distance above the block’s equilibrium position does the rock lose contact with the block? (hint this occurs when the rock’s acceleration equals the value of gravity) What is the speed of the rock when it leaves the block? What is the greatest distance above the block’s equilibrium position reached by the rock? (Let t = 0 be when the rock is placed on the block)
Answer:
v = - 1,715 m / s , x = 0.0156 m
Explanation:
This is an oscillatory movement exercise, which is described by the expression
x = A cos (wt + Ф)
we can assume that the block is released from its maximum elongation, so the phase constant (Ф) is zero
As we are told that the stone does not affect the movement of the spring mass system, the amplitude and angular velocity do not change, in the upward movement the stone is attached to the mass, but in the downward movement the mass has an acceleration greater than g leave the stone behind, let's look for time, for this we use the definition of speed and acceleration
v = dx / dt
v = - A w sin wt
a = - Aw² cos wt
a = -g
-g = - Aw² cos wt
wt = cos⁻¹ (g / Aw²)
t = 1 / w cos⁻¹ (g / Aw²)
angular velocity and frequency are related
w = 2π f
w = 2π 4
w = 8π rad / s
remember that the angles are in radians
t = 1 / 8π cos⁻¹ (9.8 / (0.07 64π²))
t = 0.039789 1.3473
t = 0.0536 s
let's find the speed for this time
v = - A w sin wt
v = - 0.07 8π sin (8π 0.0536)
v = - 1,715 m / s
the distance is
x = A cos wt
x = 0.07 cos (8π 0.0536)
x = 0.0156 m
correct me if im wrong for #16
What feature does not require a planet to have any particular characteristics?
Stream Beds
Dunes
Impact Craters
Volcanic Lava Flows
What is the correct answer?
Answer:
Impact Craters.
Explanation:
An impact crater can be defined as a circular depression that is caused by impact on any planet or asteroids or any other celestial body's surface. When smaller body in galaxy impacts these larger bodies, they form a circular depression on it's surface.
This is a major feature found in solid object such as the Moon, Mercury, etc.
Therefore, the feature that a planet does not require is an impact crater. As other features are important to define a planet. Thus correct option is C.
Alcohol wiped across a tabletop rapidly disappears. What happened to the temperature of the tabletop
Answer:
it gets colder
Explanation:
because if you put anything on a table top it will become colder
In most cases, what happens to a liquid when it cools? Its density increases. Its density decreases. Its mass increases. Its mass decreases. Its volume increases. Its volume decreases. (more than 1 correct answer)
Answer: density decreases
Explanation:
How can models help us understand energy?
9. A plane starts at rest & accelerates along the ground before takeoff. It
moves 1600m in 18s. Calculate the acceleration rate of the plane. *
Answer:
9.877 m/s^2
Explanation:
The acceleration can be computed from ...
d = (1/2)at^2
(1600 m) = (1/2)a(18 s)^2
a = (1600/162) m/s^2 ≈ 9.877 m/s^2
What is the difference between a rule and a law?
Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a large toy rocket to the back of a sled, and take the modified sled to a large, flat, snowy field. You ignite the rocket, and observe that the sled accelerates from rest in the forward direction at a rate of 13.5 m/s2 for a time period of 3.30 s. After this time period, the rocket engine abruptly shuts off, and the sled subsequently undergoes a constant backward acceleration due to friction of 6.15 m/s2.After the rocket turns off, how much time does it take for the sled to come to a stop?By the time the sled finally comes to a rest, how far has it traveled from its starting point?
Answer:
-time it takes for the sled to come to a stop after launch of rocket = 7.244 s
-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m
Explanation:
From the question, looking at the motion while accelerating, we have;
Initial velocity; u = 0 m/s
Acceleration; a = 13.5 m/s²
Time; t = 3.3 s
Let's use first equation of motion to find final velocity (v).
v = u + at
v = 0 + (13.5 × 3.3)
v = 44.55 m/s
In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.
d1 = ut + ½at²
d1 = 0(3.3) + ½(13.5 × 3.3²)
d1 = 73.5075 m
Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².
Thus, from v = u + at, we can find the time it take for the sled to come to a stop.
Now, since it's coming to rest acceleration will be negative. Thus;
0 = 44.55 + (-6.15t)
0 = 44.55 - 6.15t
t = 44.55/6.15
t = 7.244 s
Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.
Thus, we'll use the equation;
v² = u² + 2as
Where s will be the second displacement which we will call d2.
Thus;
0² = 44.55² + (-2 × 6.15 × s)
0 = 1984.7025 - 12.3s
12.3s = 1984.7025
s = 1984.7025/12.3
s = 161.358
Thus, d2 = s = 161.358 m
Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;
= d1 + d2 = 73.5075 + 161.358 = 234.8655 m