Answers
Answer:
[tex]\boxed{O_2 \: ^{2-} (\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4(π∗2py,π∗2px)^4}[/tex]
[tex]\boxed{O_2 \: ^{1-}(\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4{ (π∗2py)}^{2} {(π∗2px)}^{1}}[/tex]
Explanation:
[tex]\sf \: Electronic \: configuration \: of \: O_2 \: ^{2-} and \: O_2 \: ^{1-}[/tex]
Electronic configuration of any diatomic molecule can be determined using MOT(molecular orbital theory).
To know the electronic configuration of above two molecules, draw the MOT of O2 molecule.(refer the diagram)
There are 16 electrons in O2 molecule out of which Four electrons are in non bonded state. Remaining 12 electrons of 16 will be filled according to MOT, since O2 is not a S-P mixing case, in without S-P mixing case the sigma orbital(σ2pz) lies below the Pi orbital(π2px,π2py) in bonding state as you can see in the diagram, on other hand the other diatomic molecules like B2, C2 & N2 are S-P mixing case where Pi orbital lies below and sigma orbital lies above.
Now, the electronic configuration of O2 molecule is
[tex](\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4(π∗2py,π∗2px)^2 [/tex]
There are two electrons unpaired electrons in MOT hence the O2 molecule is paramagnetic which contradicts VBT, Thats why MOT dominant VBT.
in case of O2^2-(peroxide linkage) the two electrons enters in the Anti Bonding of pi orbital. hence the electronic configuration of O2^2- is
[tex](\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4(π∗2py,π∗2px)^4[/tex]
since the HOMO (highest occupied molecular orbital) is paired the O2^2- is diamagnetic in nature.
Coming to O2^1- (superoxide linkage) the one electron enters in the Anti Bonding of pi orbital hence the electronic configuration comes out,
[tex](\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4{ (π∗2py)}^{2} {(π∗2px)}^{1} [/tex]
The HOMO of O2^1- is unpaired hence it is Paramagnetic in nature.
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Related Questions
10. Boron has two naturally occurring isotopes, 10B with an atomic mass of 10.0129370amu and 11Bwith an atomic mass of 11.0093054amu. The atomic mass of boron is 10.81 (from the periodic table). The percent abundances of the boron isotopes are __________% 10Band __________% 11B.
Answers
Explanation:
allowing 20% discount on the market price of a watch the value of the watch will be rs 2376 when a VAT of 10% is added ,find it's market price
Calculate AHræn for the following reaction
2 AX (g) + 7 BY (g) →4AY (g) + 6 BX (g)
Use the following AHformation values for AX, BY, AY and BX
AX: AHformation = -80 kJ/mol
BY: AH formation = 57 kJ/mol
AY: AHformation = -379 kJ/mol
BX: AHformation = -251 kJ/mol
Answers
Answer:
60ax 70by 67ay ah251
Explanation:
Which of the following are true about photosynthesis and cellular respiration. (Select all that apply.)
The products of one process are the reactants of the other.
The relationship between them enables life to survive as we know it.
They both happen only in plants.
They both take place in human cells.
Answers
Answer:
2 and 4 are the best answers
Explanation:
Answer:
A and B
Explanation:
Took the k12 test.
Consider the following reaction where Kc = 55.6 at 698 K.
H2(g) + I2(g) 2HI(g)
A reaction mixture was found to contain 2.29×10-2 moles of H2(g), 3.80×10-2 moles of I2(g) and 0.254 moles of HI(g), in a 1.00 liter container.
Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?
The reaction quotient, Qc, equals
.
The reactionfill in the blank 2
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.
Answers
Answer:
B
No the reaction is not at equilibrium
The reaction must run to the left (reactants) to reach equilibrium
Qc = 74.14
Explanation:
Qc = (0.254)^2 / ((2.29 x 10-2)(3.8 x 10-2))
Qc = 74.14
74.14 > 55.6
Qc > Kc
Which unit is used to measure the distance between galaxies? Question 3 options: kilometers decades years light years
Answers
Answer:
light years
Explanation:
light year is the DISTANCE light travels in one year ...a very large distance
Answer:
light years
Explanation:
since distance between galaxy space ,objects .
8. Thermal Energy is?
A. Kinetic
B. Potential
c. Potential and Kinetic
D. Neither Potential and Kinetic
Answers
Thermal energy is the sum of the kinetic and potential energy of all the particles in an object. The figure shows that if either potential or kinetic energy increases, thermal energy increases.
hope it really helps...!!!
calculate, a can of chicken broth contains 450 mg of sodium chloride in 240.0g of broth. What is the percent by mass of sodium chloride in the broth?
Answers
Answer:
The percent by mass of sodium chloride in the broth is 0.1875 %
Explanation:
Our first step is transforming the sodium chloride figure from mg to g
450mg x 1g/1000 mg= 0.45g
Now, we must calculate the percentage by using the following formula:
0.45g / 240g x 100= 0.1875%
Henceforth, we can conclude that the percentage by mass of sodium chloride in the broth is 0.1875%
The per cent by mass of sodium chloride in the broth is 0.1875 %
What is per cent by mass?The mass per cent of a component of a compound is the percentage ratio of the mass of the component by the total mass of the compound. The formula is mass per cent = (mass of component / total mass of compound) × 100.
Given data:
Mass of sodium chloride =450 mg = 0.45g
Now, we must calculate the percentage by using the following formula:
[tex]\frac{0.45gX 100}{240g }[/tex]
= 0.1875%
Hence, we can conclude that the percentage by mass of sodium chloride in the broth is 0.1875%
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Which mixture would be easiest to separate based on the size of the particles?
A.
oil and water
B.
vinegar and water
C.
sand and gravel
D.
sugar and water
Answers
Answer:
i believe sand and gravel because you can sift the sand
Explanation:
Calculate the pH of the following aqueous solution:
0.35 M NaF (pKa for HF = 3.14)
I'm pretty sure I know how to calculate the pH by itself, but I am confused on how to get the equation. I'm not sure what HF has to do with this, other than it's an acid. I'm probably overthinking it because it's worded differently. Thanks in advance!
Answers
The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
How to calculate pH?The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:
pH = pka + log ([A-]/[HA])
Where;
A- = conjugate baseHA = weak acidpH = pKa + log([F-]/[HF])
pH = 3.14 + log(1/0.35)
pH = 3.14 + 0.4559 = 3.595
Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
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Identify the type of energy conversion represented by each picture.
solar energy to light energy
electric energy to light energy
electric energy to heat energy
wind energy to electric energy
Answers
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
The given pictures show conversion of energy from one form to another.
#Picture 1Electric energy to Heat energy
#Picture 2Wind energy to electric energy
#Picture 3Solar energy to light energy
#Picture 4Electric energy to light energy
Which substance will hold its shape?
plasma
liquid
gas
solid
Answers
Answer:
solid
Explanation:
plasma = no
liquid= shapes is container it is in
gas = shaped to container also
For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy
Answers
Answer: Correct option is B)
The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions. The equation showing the standard enthalpy change of formation of water is
H
2
(g)+
2
1
O
2
(g)⟶H
2 ↑
O(l) 1 mole of water formed.
∴ Enthalpy of formation is −X2kJ/mol.
________________________________________________________
Explanation:I hope this helped
Determine the empirical formula of a compound containing 48.38 grams of carbon, 8.12 grams of hydrogen, and 53.5 grams of oxygen
Answers
As with most stoichiometry problems, it is necessary to work in moles. The ratio of the moles of each element will provide the ratio of the atoms of each element.
Get the mass of each element by assuming a certain overall mass for the sample (100 g is a good mass to assume when working with percentages).
Remeber that percentages are a ratio multiplied by 100. You must convert percentages back to their decimal value before working with them.
(.4838) (100 g) = 48.38 g C
(.0812 ) (100 g) = 8.12 g H
(.5350) (100 g) = 53.38 g O
Convert the mass of each element to moles of each element using the atomic masses.
(48.38 g C) (1 mol/ 12.10 g C) = 4.028 mol C
(8.12 g H) (1 mol/ 1.008 g H) = 8.056 mol H
(53.38 g O) (1 mol/ 16.00 g O) = 3.336 mol O
Find the ratio or the moles of each element by dividing the number of moles of each by the smallest number of moles.
Use the mole ratio to write the empirical formula.
Which types of particles are involved in a fission reaction?
A neutral neutron strikes a large neutral nucleus.
A positive proton strikes a large positive nucleus.
A neutral neutron strikes a large positive nucleus.
A positive proton strikes a large neutral nucleus.
Answers
HELP ME OUT PLS!!!!!!!!!
All stars begin their life in a
O black hole
O main sequence
O protostar
O nebula
Answers
Answer:
nebula
Explanation:
I am well informed
Question 4 of 15
The types of radiation produced by alpha, beta, and gamma decay differ in
many ways. Which characteristic do they all have in common?
A. The ability to treat cancer
B. The ability to cause cancer
C. The ability to trace the movement of chemicals
D. The ability to damage human tissue
Answers
Answer:
D. The ability to damage human tissue
please give me brainliest.
Why is it important for scientist to be objective when using the design process like the scientific method when doing there investigations?
Answers
Answer:
Scientists use the scientific method to make testable explanations and predictions about the world. A scientist asks a question and develops an experiment, or set of experiments, to answer that question. Engineers use the engineering design process to create solutions to problems.
Which type of covalent bond is the least stable?
A.Covalent bonds
B.Double bonds
C.Single bonds
D.Triple Bonds
Answers
Answer:
D because: A Triple bond is when three pairs of electrons are shared between two atoms in a molecule. It is the least stable out of the three general types of covalent bonds.
How many Si atoms are there in 1.00 g of silicon
Answers
Reactivity Series
Iron, tin and zinc all react with dilute hydrochloric acid to produce hydrogen.
Plan an experiment to determine the order of reactivity of iron, tin and zinc.
You are provided with powdered samples of the metals and common laboratory apparatus.
Answers
Answer:
Measuring electode potential
Explanation:
Make an electrode of all of them and measure standard reductive potential metals with lower srp will be more reactive
The metals which are placed above the hydrogen in the reactivty series can produce hydrogen gas with HCl. The order of reactivity of given metals is as follows: Zinc > iron > tin.
What is reactivity series?The reactivity series of elements or the activity series can be defined as the arrangement of metals in descending order according to their reactivities.
The metals placed at the top of the activity series are strong reducing agents and can be readily oxidized. These metals readily tarnish/corrode. The reducing ability becomes weaker while moving down the reactivity series.
The electropositivity of the elements decreases as we move down in the reactivity series of metals. All metals which are placed above hydrogen in the activity series can able to release hydrogen gas upon reacting with dilute HCl.
Therefore, the metals Iron, tin, and zinc release hydrogen gas when they react with the HCl. The order of reactivity is according to their reduction potential which is Zinc > iron > tin.
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What is the molarity of a solution made by adding 1.565 moles of
PbNO3 to 0.500 L?
300. M
31.3 M
3.13 M
1.56 M
Answers
Answer:
3.13M
Explanation:
Using the Molaitry equation ( M = n/v ) just plug numbers in and solve.
a 21.0 kg rock rests on the edge of a cliff 32.0 m high. how much gravitational potential energy does the rock have
Answers
Explanation:
Formula for Potential energy=mgh mass* gravity*height
21kg × 10 ×32=6720joules
If a 21.0 kg rock rests on the edge of a cliff 32.0 m high, the gravitational potential energy gained by the rock would be 6585.6 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem a 21.0 kg rock rests on the edge of a cliff 32.0 m high, then we have to calculate the potential energy gained by the rock,
The potential energy of the rock = 21 × 9.8 × 32
= 6585.6 Joules.
Thus ,If a 21.0 kg rock rests on the edge of a cliff 32.0 m high, the gravitational potential energy gained by the rock would be 6585.6 Joules.
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Determine the longest wavelength of light required to remove an electron from a sample of potassium metal, if the binding energy for an electron in K is 1.76 × 103 kJ/mol. A. 113 nm B. 885 nm C. 68.0 nm D. 147 nm E. 387 nm
Answers
Answer:
The wavelength of light is 68 nm.
Explanation:
Given data:
Binding energy of electron = 176 × 10³ Kj/ mol or (1.76× 10⁶ j/mol)
Wavelength of light require to remove the electron = ?
plese help
Using the rules that you learned during the session, what is the answer to the following question?
55.78 * 23.7
Answers
A) 1,322
B) 1,320
explain:
Answers
What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0140 V and n = 2?(F = 96,500 J/(V･mol), R = 8.314 J/(mol･K))
Answers
The equilibrium constant of the electriochmeical cell as shown is 2.976.
What is the equilibrium constant?The equilibrium constant of a reaction shows the extent of the conversion of the reactants to products.
Now we know that;
ΔG = -nFE°cell
n = 2
F = 96,500 J/(V･mol)
E°cell = +0.0140 V
ΔG = -(2 * 96,500 * 0.0140)
ΔG = -2702 J
But;
ΔG = -RTlnK
lnK = -(ΔG/RT)
K = e^[-(ΔG/RT))
K = e^[-(( -2702)/8.314 * 298]
K = 2.976
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If the actual yield for a substance is 39.487g but the theoretical yield is 38.000g, what is
the percent yield?
a. 2%
b. 96%
c. 50%
d. 104%
Answers
Answer:
b. 96%
Explanation:
A lab technician determines the boiling point elevation of an aqueous solution of a nonvolatile, nonelectrolyte to be 1.12 C. What is the solution’s molality?
Answers
Answer:
2.19m
Explanation:
quizlet
A manometer measures 450 torr of pressure in a container with 0.500-L sample of carbon dioxide, CO2. The gas is compressed to a volume of 0.100 L. What is the new pressure reading in the manometer?
Answers
Let's see
Apply boyles law
P1V1=P2V2450(0.5)=0.1P_2225=0.1P_2P_2=2250Torris mixing water and glue a chemical or physical change?
Answers
Answer:
physical
Explanation:
because it would still remain as a liquid. if you were to add borax or something to it, then it would be a chemical change.
Consider the following generic chemical equation.
A+3B→C
What is the limiting reactant when each of the following amounts of A and B are allowed to react?
A. 1 mol A; 4 mol B
B. 2 mol A; 3 mol B
C. 0.5 mol A; 1.6 mol B
D. 24 mol A; 75 mol B
Answers
Answer:
[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]
Explanation:
Given equation:
[tex]A+3B \rightarrow \: C [/tex]
To find:
Limiting reactant for corresponding number of moles=?
Solution:
We know that the liming reactant is any atom, ion or molecule which is completely consumed during a reaction and other reactant is still left in reactant vessel.
For the given reaction A+3B→C
for every one mole of A three moles of B are required.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in A) there is one mole of A and 4 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in B) there is 2 mole of A and 3 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of A will be still there in reaction, the reactant was completely consumed is B which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in C) there is 0.5 mole of A and 1.6 mole of B
if one mole of A requires three moles of B to complete the reaction then,
0.5 moles of A will require 1.5 moles of B
if 0.5 mole of A will react with 1.6 moles of B, 0.1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in D) there is 24 mole of A and 72 mole of B
if one mole of A requires three moles of B to complete the reaction then,
24 moles of A will require 72 moles of B.
if 24 mole of A will react with 75 moles of B, 3 mole of B will be left over in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]
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