To enlarge Shape A by a scale factor of 1.5 with the center of enlargement (0, 0), we have to multiply every length by 1.5.
Enlargement of Shape A
Enlargement of a shape is when it is either stretched or shrunk in one or both directions. The original shape is called the pre-image, while the new shape is called the image. What is the centre of enlargement?
The center of an enlargement is the point about which all of the points of the pre-image are scaled to obtain the image. When the scale factor is greater than 1, the image of the pre-image is an enlargement. When the scale factor is between 0 and 1, the image of the pre-image is a reduction.In an enlargement, each point on the pre-image is mapped onto a corresponding point on the image along a straight line which goes through the centre of enlargement.
The new shape has a larger size than the original shape. To expand shape A by a scale factor of 1.5, you need to multiply each length by 1.5. You have to create new points. It's easy to use a scale ruler to make sure each length is multiplied by 1.5.
A Centre of enlargement is a point in the coordinate plane that enlarges or shrinks a figure by some scale factor. In the problem, the center of enlargement is (0, 0).
Thus, we have to extend every length of Shape A by 1.5, and our scale factor is 1.5. We get Shape B by doing so. Now, we can conclude that to enlarge Shape A by a scale factor of 1.5 with the center of enlargement (0, 0), we have to multiply every length by 1.5.
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Teresa wants to buy 2 new tires for her mountain bike. She has budgeted $120 for the tires, but after researching costs, knows she may end up spending within $25 of that amount
Teresa needs to buy two new tires for her mountain bike.
With a budget of $120, she will likely spend within $25 of that amount.
To help her find the best deal, Teresa should first research what type of mountain bike tire she needs. She can look at the bike's current tires to determine the size, or she can look up the bike model and size online. She should then research prices at a variety of local bike shops and online retailers to compare costs.
Once she finds the best price, Teresa should look for discounts and coupon codes that she can use to reduce the cost of her tires. She should also make sure she is aware of any extra costs, such as shipping and taxes.
With some research and savvy shopping, Teresa should be able to find two mountain bike tires that fit within her budget of $120 and that will keep her bike running smoothly.
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based on the boxplot, about 25% of these ayrshire cattle had a butterfat percentage that was higher than what value ?
Based on the boxplot, approximately 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%.
To determine this, we can look at the boxplot and see that the third quartile (Q3) is at 8.3%. Since 25% of the data is greater than 8.3%, we can infer that 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%. To further explain, a boxplot is a graphical representation of the five-number summary of a dataset, which consists of the minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum.
The boxplot is divided into two parts, the box and the whiskers. The box indicates the interquartile range (IQR) which is the difference between the third and first quartile. The whiskers represent the minimum and maximum of the dataset. The median is shown by a line within the box. In this boxplot, the first quartile (Q1) is 6.7%, the median (Q2) is 7.4%, and the third quartile (Q3) is 8.3%. Therefore, based on the boxplot, about 25% of these Ayrshire cattle had a butterfat percentage that was higher than 8.3%.
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Complete Question : Based on the boxplot, about 25% of these ayrshire cattle had a butterfat percentage that was higher than?
the standard deviation represents a , while the standard error of the mean represents a . a. law of large numbers:central limit theorem b. population:sample c. sample:population d. central limit theorem:law of large numbers
The standard error of the mean represents a sample, while the standard deviation represents a population. The correct option is (c) sample; population
The standard error of the mean is a measure of the variability of sample means from multiple samples, while the standard deviation is a measure of the variability of individual data points from the mean of a single sample or population.
The standard error of the mean helps us estimate the accuracy of the sample mean as an estimate of the true population mean, while the standard deviation gives us an idea of how much the data points deviate from the mean. In statistics, it is important to distinguish between these two measures to properly interpret data and draw meaningful conclusions.
Therefore, the correct option is (c) sample; population
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The given question is incomplete, the complete question is:
The standard error of the mean represents a ___, while the standard deviation represents a _______.
a. law of large numbers; central limit theorem
b. population; sample
c. sample; population
d. central limit theorem; law of large numbers
8x + 4 + 8x - 1 simplify the variable expression
I do not understand this
Pls help!
Answer:
16x + 3
Step-by-step explanation:
Simplify by combining like terms. Add the terms with x, then add the integers.
8x + 8x + 4 - 1 = 16x + 3
Solve the equation where θ lies in the interval [0, 2pi). List the answers from least to greatest.
secθ=undefined
The solutions to the equation secθ = undefined from the least to greatest is π/2 and 3π/2.
What is the solution of the equation?The equation secθ = undefined means that the secant of θ is undefined. Recall that the secant function is defined as 1/cosine(θ).
Therefore, secant is undefined when the cosine of θ is equal to zero, since division by zero is undefined.
In the interval [0, 2π), the cosine function equals zero at θ = π/2 and θ = 3π/2.
Therefore, the solutions to the equation secθ = undefined in the interval [0, 2π) are θ = π/2 and θ = 3π/2.
Listing the solutions from least to greatest, we have:
θ = π/2 ≈ 1.571
θ = 3π/2 ≈ 4.712
Note that these values are given in radians.
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A bakery can make 30 donuts every
15 minutes. What is the unit rate at which the bakery makes donuts? What is the slope of the line?
The unit rate at which the bakery makes donuts is 2 donuts per minute.
The slope of the line would also be 2 since the number of donuts made is directly proportional to the time elapsed. This means that for every minute that passes, 2 donuts are made.
To find the unit rate, we divide the total number of donuts made (30) by the time it takes to make them (15 minutes).
Unit rate = 30 donuts ÷ 15 minutes = 2 donuts per minute
To find the slope of the line, we use the formula:
slope = rise ÷ run
In this case, the "rise" is the number of donuts made and the "run" is the time elapsed. Therefore, the slope is:
slope = 30 donuts ÷ 15 minutes = 2 donuts per minute.
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Find the area of the polygon in square units.
This may be wrong
Answer: 240.25 square units
Step-by-step explanation:
You could take the perimeter already given, and turn this into a rectangle.
Since the left side is blank, this means you add 7 to thirteen to get the measurement of it. It would take a while to explain, and it seems like you want the answer soon.
You end up with a perimeter of 62.
If you get 2 sets of 2 values from this perimeter, you can create a width and height for your "rectangle"
You could turn this into a square even. Divide the perimeter by 4 to get a length of each side.
Each side of your rectangle (now square) is equal to 15.5 units.
Since the formula for area for a rectangle is width times height, multiply 15.5 by itself, and you get an area measure of 240.25 square units.
A rhombus has an area of 20 cm^2. One diagonal is 10 cm. What is the other diagonal
The other diagonal of the rhombus is 4 cm.
The other diagonal of the rhombus can be found using the formula for the area of a rhombus, which is A = (d₁ × d₂)/2, where d₁ and d₂ are the lengths of the diagonals.
We're given that the area of the rhombus is 20 cm² and that one diagonal (d1) is 10 cm. Plugging these values into the formula, we get:
20 = (10 × d₂)/2
Simplifying, we get:
20 = 5 d₂
Dividing both sides by 5, we get:
d₂ = 4
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A hot air balloon is rising at a constant rate of 10 meters per second, while blowing east at a rate of 3 meters per second. The balloon travels on a diagonal path, and its position after 1 second is shown. How far does the balloon travel after 10 seconds?
Answer:130 meters
Step-by-step explanation:
it travels up 10 meters and over 3 meters per second. so that means it travels 13 meters per second. then you do 13 x 10 and get 130 meters
Answer:
3,000 meters.
Step-by-step explanation:
What you should first do is set up a diagram to demonstrate the velocity of the balloon and wind.
After having that set up, you can use the pythagorean theorem to find the hypotenuse of the triangle made after 10 seconds.
3²*10²=√900 (for one second)
√900 = ±30 m traveled in one second
30²×100²=√9,000,000
√9,000,000 = ±3,000 m
2. Simplify the expression (5-3i) (-7 - 31) - (6-2i). Show your work
Answer:
Step-by-step explanation:
Let's simplify the expression step by step:
(5-3i)(-7-31) - (6-2i)
= (5)(-7) + (5)(-31i) - (3i)(-7) - (3i)(-31) - 6 + 2i
= -35 - 155i + 21i + 93 - 6 + 2i
= -35 + 87 - 63i + 2i - 155i
= 52 - 216i
Therefore, the simplified expression is 52 - 216i.
What are the integer solutions to the inequality below?
−
2
<
x
<
2
Answer:
the integer solutions to the inequality -2 < x < 2 are x = -1, 0, and 1.
Step-by-step explanation:
The inequality is written as:
-2 < x < 2
This inequality can be read as "x is greater than -2 and less than 2". In other words, x is between -2 and 2, but not including -2 or 2.
The integer solutions that satisfy this inequality are -1, 0, and 1.
Therefore, the integer solutions to the inequality -2 < x < 2 are x = -1, 0, and 1.
f is a function that maps 6-bit binary strings to 4-bit binary strings. For XE {0,136, f(x) is the string x with the last two bits removed. Which property best describes the function to 04-to-1 correspondence 16-to-1 correspondence 2-to-1 correspondence Bijection
The property that best describes the function is b) 16-to-1 correspondence.
The function f maps 6-bit binary strings to 4-bit binary strings. Therefore, there are 2^6 = 64 possible inputs and 2^4 = 16 possible outputs.For any input x, f(x) is the string x with the last two bits removed. This means that there are 4 possible values for the last two bits of x: 00, 01, 10, and 11.
Since there are 4 possible values for the last two bits of x, there are 4 different inputs that map to each output. For example, if the output is 0000, then the inputs that map to this output are 000000, 000100, 001000, and 001100.
Therefore, the function has a 16-to-1 correspondence, meaning that each output corresponds to 16 different inputs.
The function is not a bijection because multiple inputs can map to the same output. It is also not a 2-to-1 correspondence because each output corresponds to more than 2 inputs.
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I'm thinking of a number between 5. 17 and 203. 71
From the given information provided, the number you are thinking of can be approximately 20.375.
Since the number you are thinking of is between 5 and 203, we can use the following steps to find it:
Take the average of the two endpoints: (5 + 203) / 2 = 104
Check if 104 is greater than or less than 71. Since 104 is greater than 71, we know that the number is between 5 and 104.
Take the average of 5 and 104: (5 + 104) / 2 = 54.5
Check if 54.5 is greater than or less than 17. Since 54.5 is greater than 17, we know that the number is between 17 and 54.5.
Take the average of 17 and 54.5: (17 + 54.5) / 2 = 35.75
Check if 35.75 is greater than or less than 5. Since 35.75 is greater than 5, we know that the number is between 5 and 35.75.
Take the average of 5 and 35.75: (5 + 35.75) / 2 = 20.375
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Please help! There could be many things and I don’t know
Answer: a rotation occurred
Step-by-step explanation:
If m = 5 nd n = 3 then find the value of x :
[tex] \small{\underline{ \sf{ \color{purple} \: Equation:- \: 7m - n = 4(x + 9 {m}^{2} ) \div n \: \: }}}[/tex]
Thank You! :)
To find:-
The value of " x " .Answer:-
The given equation to us is ,
[tex]\implies 7m - n = \dfrac{4(x+9m^2)}{n} \\[/tex]
We are interested in evaluating the value of x at m = 5 and n = 3 . So plug in these values in the given equation as ,
[tex]\implies 7(5) - 3 = \dfrac{4(x+9(5)^2}{3} \\[/tex]
Simplify,
[tex]\implies 35 - 3 = \dfrac{4( x + 9(25))}{3} \\[/tex]
[tex]\implies 32 = \dfrac{4(x+225)}{3} \\[/tex]
Cross multiply,
[tex]\implies 32(3) = 4(x+225) \\[/tex]
Divide both the sides by 4 ,
[tex]\implies \dfrac{32(3)}{4}= x+225 \\[/tex]
Simplify,
[tex]\implies 24 = x + 225 \\[/tex]
Subtract 225 on both the sides,
[tex]\implies 24 - 225 = x \\[/tex]
Simplify,
[tex]\implies \underline{\underline{ x = -201}} \\[/tex]
Hence the value of x is -201 when m = 5 and n = 3 .
and we are done!
during normal breathing, about 12% of the air in the lungs is replaced after one breath. write an exponential decay model for the amount of the original air left in the lungs if the initial amount of air in the lungs is 500 ml. approximately how much original air is left in the lungs after 5 breaths?
If the initial amount of air in the lungs is 500 ml. approximately then original air is left in the lungs after 5 breaths is 263.86 ml.
During normal breathing, about 12% of the air in the lungs is replaced after one breath,
initial amount of air in the lungs is 500 mL.
After 1 breath original air in lung = 500 - (12/100)500
= 500*(88/100)
= 500 (0.88)
After 2 breath original air in lung = 500 (0.88) - (12/100)500 (0.88)
= 500 (0.88) (1 - 12/100)
= 500 (0.88) (0.88)
= 500(0.88)²
After n breaths original air in lung = 500(0.88)ⁿ
original air is present after 5 breaths = 500(0.88)⁵
= 263.86 ml
Therefore, original air is left in the lungs after 5 breaths is 263.86 ml.
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Let S be the sphere of radius 1 centered at (1,2,3).
Find the distance from S to the plane x+y+z=0.
(Hint: Use Lagrange multipliers to find the distance from the plane to the center of the sphere)
The distance from S to the plane x+y+z=0 is sqrt(105)/7.
To find the distance from the sphere S to the plane x+y+z=0, we need to first find the center of the sphere S. We know that the center of the sphere S is (1, 2, 3) and the radius of the sphere is 1. We can use the equation of the plane x+y+z=0 to find the distance from the center of the sphere to the plane.
We can use Lagrange multipliers to find the distance from the center of the sphere to the plane. We need to minimize the function [tex]f(x, y, z) = (x-1)^2 + (y-2)^2 + (z-3)^2[/tex] subject to the constraint x+y+z=0. Using Lagrange multipliers, we get the following system of equations:
2(x-1) = λ
2(y-2) = λ
2(z-3) = λ
x+y+z = 0
Solving these equations, we get x = 1-λ/2, y = 2-λ/2, and z = 3-λ/2. Substituting these values into the equation x+y+z=0, we get λ = 12/7. Substituting this value of λ into x, y, and z, we get the coordinates of the point on the plane closest to the center of the sphere: (5/7, 4/7, -9/7).
To find the distance from the center of the sphere to the plane, we can use the distance formula. The distance from the center of the sphere to the plane is given by the length of the vector connecting the center of the sphere to the point on the plane closest to the center of the sphere. Therefore, the distance from the sphere S to the plane x+y+z=0 is:
d = sqrt[(5/7 - 1)^2 + (4/7 - 2)^2 + (-9/7 - 3)^2] = sqrt[105/49] = sqrt(105)/7.
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7.3 right triangle and trigonometry homework 
Sine: the ratio of the length of the side opposite the angle to the length of the hypotenuse
Cosine: the ratio of the length of the adjacent side to the length of the hypotenuse
Tangent: the ratio of the length of the side opposite the angle to the length of the adjacent side
Cosecant: the reciprocal of the sine function
Secant: the reciprocal of the cosine function
Cotangent: the reciprocal of the tangent function
What is Trigonometry ?
Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. Right triangles are particularly important in trigonometry because they have one angle that measures 90 degrees, which allows us to define the six trigonometric functions: sine, cosine, tangent, cosecant, secant, and cotangent.
According to the question:
In a right triangle, the side opposite the 90-degree angle is called the hypotenuse, and the other two sides are called the legs. We can use the ratios of the lengths of the sides to define the six trigonometric functions as follows:
Sine: the ratio of the length of the side opposite the angle to the length of the hypotenuse
Cosine: the ratio of the length of the adjacent side to the length of the hypotenuse
Tangent: the ratio of the length of the side opposite the angle to the length of the adjacent side
Cosecant: the reciprocal of the sine function
Secant: the reciprocal of the cosine function
Cotangent: the reciprocal of the tangent function
Trigonometry is used in a wide range of fields, including physics, engineering, and navigation. It allows us to solve problems involving angles and distances, and to model periodic phenomena such as waves and oscillations.
Q: Explain about right angle and trigonometry ?
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A boat is heading towards a lighthouse, where Charlotte is watching from a vertical distance of 137 feet above the water. Charlotte measures an angle of depression to the boat at point AA to be 11^{\circ} ∘ . At some later time, Charlotte takes another measurement and finds the angle of depression to the boat (now at point BB) to be 47^{\circ} ∘ . Find the distance from point AA to point BB. Round your answer to the nearest foot if necessary.
The distance from point AA to BB is 577 ft.
What is an angle of depression?An angle of depression is a measure of an angle formed when an observer views an object below the horizontal plane.
In the given question, let the distance from lighthouse to point AA be represented by x. So that;
Tan θ = opposite/ adjacent
Tan 11 = 137/ x
x = 137/ 0.1944
x = 704.733 ft
Let the distance from the lighthouse to point BB be represented by y, so that;
Tan 47 = 137/ y
y = 137/ 1.0724
y = 127.751 ft
Thus,
x - y = 704.733 - 127.751
= 576.982
The distance between point AA and point BB is 577 ft.
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A ratio is 5:6 , The Antecedent of the given ratio is 95 ,what is the consequent ?
Given:
ratio = 5:6 , Antecedent = 95
so, as we know that if a ratio is in the form of a/b, then
a is antecedent and b is called consequent.
so,
5/6 =95/b
on doing cross multiplication we get;
5×b=95×6
b=(95×6)/5
b=19×6
b=114
Hence, consequent(b) is 114.
Robin was given a $40 monthly allowance. She wants to go to the movies as many times as possible and have at least $12. 50 left at the end of the month to go to a concert. A movie ticket costs $5. Write an inequality to determine how many times Robin can go to the movies this month
Robin can go to the movies a maximum of 5 times this month.
Let's start by defining a variable to represent the number of times Robin goes to the movies. Let's call this variable "x".
We know that each movie ticket costs $5, and Robin wants to have at least $12.50 left at the end of the month. This means that the total amount of money she can spend on movies is:
40 - 12.50 = $27.50
We can set up an inequality to represent this:
5x ≤ 27.50
To solve for x, we can divide both sides of the inequality by 5:
x ≤ 5.5
Since we can't go to the movies a fractional number of times, we round down to the nearest whole number.
Therefore, Robin can go to the movies a maximum of 5 times this month.
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When released, a yo-yo falls toward the floor. Use conservation of energy to explain why it is able to return to your hand.
When released, a yo-yo falls towards the floor due to conservation of energy.
Conservation of energy:
As it falls, its potential energy is converted into kinetic energy. When the yo-yo reaches its lowest point, it begins to spin rapidly, storing some of this kinetic energy as rotational energy. As the string wraps around the yo-yo's axle, it exerts a force which starts pulling the yo-yo back up towards your hand. This force converts the rotational energy back into potential energy as the yo-yo rises. When the yo-yo reaches your hand, it has regained all its initial potential energy, enabling it to return to your hand.
When the yo-yo reaches the end of the string, the rotational kinetic energy it has stored is used to wind the string back around the axle. This winding motion causes the yo-yo to move back up toward your hand. As the yo-yo moves back up, its potential energy increases, while its rotational kinetic energy decreases. Eventually, the yo-yo reaches your hand and comes to a stop.
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obtain the deviance residuals (14.83) and plot them against the estimated model probabilities with a lowess smooth superimposed. what does the plot suggest about the adequacy of the fit of the logistic regression model?
The plot suggests that the logistic regression model is not adequately fitting the data.
The deviance residuals plot against the estimated model probabilities with a lowess smooth indicates how well the logistic regression model fits the data. A plot with residuals around zero suggests that the model is adequately fitting the data. In this case, the deviance residuals are around 14.83 which indicates a poor fit of the model. Therefore, the plot suggests that the logistic regression model is not adequately fitting the data.
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Triangle LMN has vertices at L(−1, 5), M(−1, 0), N(−2, 5). Determine the vertices of image L′M′N′ if the preimage is rotated 90° clockwise about the origin.
L′(5, 1), M′(0, 1), N′(5, 2)
L′(−1, −5), M′(−1, 0), N′(−2, −5)
L′(−5, −1), M′(0, −1), N′(−5, −2).
L′(1, −5), M′(1, 0), N′(2, −5)
The vertices of image L′M′N′ are L′(−5, −1), M′(0, −1), and N′(−5, −2).
Rotating a figure 90°:Rotating a figure 90° clockwise about the origin means that each point of the figure will be moved to a new position that is located 90° clockwise from its original position, with respect to the origin of the coordinate plane.
To rotate a figure 90° clockwise about the origin follow the steps:
1. Swap the x- and y-coordinates of each point.
2. Negate the new x-coordinates.
3. Leave the new y-coordinates as they are.
Here we have
Triangle LMN has vertices at L(−1, 5), M(−1, 0), N(−2, 5)
Triangle LMN is rotated 90° clockwise about the origin.
Using the above condition
L(−1, 5) => (−(5), −1) => (−5, −1)
M(−1, 0) => (−0, −1) => (0, −1)
N(−2, 5) => (−(5), −2) => (−5, −2)
Therefore,
The vertices of image L′M′N′ are L′(−5, −1), M′(0, −1), and N′(−5, −2).
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8. the z-table gives the area under the standard normal curve to the left of z. what does the t-table give?
Answer:
The z-Table gives the area under the standard normal curve to the left of z. What does the t-Table give? The t-Table gives the area under the t-curve with n degrees of freedom to the left of it
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Carol shares a joke with 3 of her friends. The next day, each of her friends tell the joke to 4 other people. The next day, each people that heard the joke the previous day tells the joke to four different people. The expression 3(4^(x)) models this situation where x represents the number of days after Carol initally told the joke. What do the different parts of the expression represent?
Answer:
Step-by-step explanation:
In this expression, the number 3 represents the initial group of friends to whom Carol told the joke.
The base number 4 represents the number of people each friend told the joke to on the following day.
The exponent x represents the number of days that have passed since Carol first told the joke, and as a result, the number of "generations" of people who have heard the joke.
Therefore, 4 raised to the power of x represents the total number of people who have heard the joke after x days, including Carol's initial group of friends and all subsequent generations of people who have been told the joke by those who heard it before.
Finally, multiplying 3 and 4 raised to the power of x gives the total number of unique people who have heard the joke after x days, since the initial group of friends is not included in the later generations.
2.963 × 10 powerd to the 6
written in standard form?
Answer:
2963*100,000 that's the answer for that question
suppose that a box contains 6 cameras and that 3 of them are defective. a sample of 2 cameras is selected at random with replacement. define the random variable
The random variable in this situation is the number of defective cameras selected in the sample of 2 cameras. This random variable can be denoted by x.
Let us look at the different values that the random variable x can take. x can take the values 0, 1, or 2. If x=0, then it means that none of the 2 cameras selected is defective. If x=1, then it means that one of the 2 cameras selected is defective. Lastly, if x=2, then it means that both of the 2 cameras selected are defective.
In order to determine the probability of a certain value of the random variable, we need to find the ratio of favorable outcomes to the total number of possible outcomes. In this case, the favorable outcomes refer to the number of defective cameras in the sample and the total number of possible outcomes refers to the total number of combinations when selecting two cameras from the box.
The probability of x=0 is given by the ratio of the number of favorable outcomes, which is 0, to the total number of possible outcomes, which is 6C2. Hence, the probability of x=0 is 0.
The probability of x=1 is given by the ratio of the number of favorable outcomes, which is 3C1, to the total number of possible outcomes, which is 6C2. Hence, the probability of x=1 is 3/15.
The probability of x=2 is given by the ratio of the number of favorable outcomes, which is 3C2, to the total number of possible outcomes, which is 6C2. Hence, the probability of x=2 is 3/20.
To summarize, the probability distribution of the random variable x is given by:
P(x=0) = 0
P(x=1) = 3/15
P(x=2) = 3/20
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The third term of a sequence is 14. Term to term rule is square, then subtract 11. Find the first term of the sequence
The third term of a sequence is 14. Term to term rule is square, then subtract 11. The first term of the sequence is 6.
The given information is about the third term of a sequence which is 14, and the term to term rule is square, then subtract 11.
We have to find the first term of the sequence. The sequence can be calculated using the following formula:
An = A1 + (n-1)d
Where, An is the nth term of the sequence A1 is the first term of the sequence d is the common difference between the terms of the sequence. Let's solve the problem by finding the value of the common difference between the terms of the sequence.
Using the given information, we can write: A3 = 14=> A1 + (3 - 1)d = 14=> A1 + 2d = 14 ----- (i)
Also, the term to term rule is square, then subtract 11.So, we can write, A2 = A1 + d = (A1)² - 11 ---- (ii)
Substituting the value of d from equation (ii) in equation (i),
we get: A1 + 2 [(A1)² - 11] = 14 Simplifying this equation, we get: A1² - 2A1 - 12 = 0 On solving this quadratic equation
we get: A1 = -2 or A1 = 6 Ignoring the negative value of A1, we get the first term of the sequence to be 6.
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Find set of parametric equation and symmetric equation of the line through the point and parallel to the given vector(if possible):
(-3, 0, 2), v = 6j + 3k.
x + 3 / 0 = y / 6 = z - 2 / 3 is the required set of parametric equation and symmetric equation of line.
Given the point (-3, 0, 2) and the vector v = 6j + 3k, we need to find the set of parametric equation and symmetric equation of the line through the point and parallel to the given vector.
Let the line be L and a point on the line be P(x, y, z).
Then, the vector from (-3, 0, 2) to P is given by
r = OP = i(x + 3) + jy + k(z - 2)
Since L is parallel to the vector v = 6j + 3k, the direction ratios of L are proportional to the components of v. Thus, the direction ratios of L are 0, 6, and 3.
Therefore, the parametric equations of L are:
x + 3 = 0 ⇒ x = -3y = tz - 2 = 3t + 2
where t is a parameter, and the symmetric equations are x + 3 / 0 = y / 6 = z - 2 / 3. This is the required answer.
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