Exercise 24.28
For the capacitor network shown in (Figure 1), the potential difference across ab is 48 V.
Part A
Find the total charge stored in this network.
Express your answer with the appropriate units.
Q = ___ ____
Part B
Find the charge on the 150nF capacitor.
Express your answer with the appropriate units.
Q₁ = 7.2uC
Part C
Find the charge on the120nF capacitor.
Express your answer with the appropriate units.
Q₂ = 5.76 uC
Part D
Find the total energy stored in the network.
Express your answer with the appropriate units.
U = ____ ____
Part E
Find the energy stored in the 150nF capacitor.
Express your answer with the appropriate units.
U₁ = ______
Part F
Find the energy stored in the 120nF capacitor.
Express your answer with the appropriate units.
U₂= _____
Part G
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₁= ____
Part H
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₂ = ____

Exercise 24.28For The Capacitor Network Shown In (Figure 1), The Potential Difference Across Ab Is 48
Exercise 24.28For The Capacitor Network Shown In (Figure 1), The Potential Difference Across Ab Is 48
Exercise 24.28For The Capacitor Network Shown In (Figure 1), The Potential Difference Across Ab Is 48
Exercise 24.28For The Capacitor Network Shown In (Figure 1), The Potential Difference Across Ab Is 48

Answers

Answer 1

The evaluation of the capacitor (in series) network is as follows;

Part A

Q = 3.2 μC

Part B

Q₁ = 3.2 μC

Part C

Q₂ = 3.2 μC

Part D

U = 76.8 μJ

Part E

U₁ = 34 2/15 μJ

Part F

U₂ = 53 1/3 μJ

Part G

V₁ = 21 1/3 V

Part H

V₂ = 26 2/3 V

What is a capacitor?

A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.

The specified parameters are;

The voltage across ab = 48 V

The capacitance of the first capacitor, C₁ = 150 nF

Capacitance of the second capacitor, C₂ = 120 nF

Part A

The total charge in a capacitor network can be found as follows;

[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]

[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]

[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]

Therefore;

[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC

The total charge in the circuit is 3.2 μC

Part B

The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;

Q = C₁V₁ = C₂V₂

The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC

The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC

Q₁ = 3.2 nC

Part C

The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.

Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC

Q₂ = 3.2 μF

Part D

The total energy stored in the network can be obtained using the formula;

U = (1/2)·C·V²

Where;

U = The energy in the capacitor

C = The equivalent capacitance of the network = 66 2/3 nF

V = The voltage

Therefore;

[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]

[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]

The total energy in the circuit, U = 76.8 μJ

Part E

The energy stored in the 150 nF capacitor is found as follows;

[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁

V₁ = [tex]Q_{eq}[/tex] ÷ C₁

Therefore;

V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V

U₁ = 0.5×C₁×V₁²

U₁ = 0.5 × 150×10⁻⁹ × [tex]\left(21\frac{1}{3} \right)^2[/tex] = 34[tex]\frac{2}{15}[/tex] μJ

Part F

The energy stored in the 120 nF capacitor, U₂, can be found as follows;

V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V

U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]

The energy in the 120 nF capacitor is; U₂ = 53 1/3 μJ

Part G;

The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V

V₁ = 21 1/3 V

Part H

The potential difference across the 120 nF, obtained in part F, is 26 2/3 V

V₂ = 26 2/3 V

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Related Questions

A longitudinal wave is shown. An illustration of a horizontal spring. In the spring are areas where the rings are closer together and areas where the rings are further apart. The area where the rings are closer together is labeled A, the area where the rings are further apart is labeled B, the height of the spring is labeled C and the distance between adjacent areas where the rings are closer together is labeled D. Which label identifies a rarefaction? A B C D

Answers

Answer:

Explanation:

The label that identifies a rarefaction in a longitudinal wave is B.

In a longitudinal wave, such as a wave in a spring, a rarefaction is an area where the particles of the medium are farther apart than they are in the rest of the wave. This is in contrast to a compression, which is an area where the particles of the medium are closer together than they are in the rest of the wave.

In the given illustration, the area where the rings are further apart is labeled B, so B is the label that identifies a rarefaction. The area where the rings are closer together, labeled A, is a compression. The height of the spring, labeled C, does not correspond to a rarefaction or a compression, and the distance between adjacent areas where the rings are closer together, labeled D, is not related to the concept of rarefactions or compressions.

Answer:

wavelength - C

rarefractions - B

compressions - A

Explanation:

correct on EDGE 2023

A 9.5 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 2390 J by the time the rocket motor burns all of the fuel. The acceleration of gravity is 9.8 m/s². What additional height will the rocket rise? Answer in units of m.​

Answers

Answer:

4.95 m

Explanation:

The rocket's initial kinetic energy is equal to the final gravitational potential energy, so we can set these equal to each other and solve for the additional height the rocket will rise:

KEinitial = KEfinal

1/2 * m * v^2 = m * g * h

Substituting the given values, we have:

1/2 * 9.5 kg * v^2 = 9.5 kg * 9.8 m/s^2 * h

Solving for h, we find that the additional height the rocket will rise is h = 2390 J / (9.5 kg * 9.8 m/s^2) = 4.95 m.

Lithium has an atomic number of ------ and an atomic mass of -------

Answers

Answer:

lithium has an atomic number of 3 and an atomic mass of 7

Explanation:

Cual es la Ecuación de velocidad de una onda en función del índice de la amplitud de una cuerda

Answers

Answer:

Well velocity is the varaible with direction

Explanation:

A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible

Answers

The horizontal distance travelled by the box is 143 m.

What is the horizontal distance travelled by the box?

The horizontal distance travelled by the box is calculated by determining the time of motion of the box and the horizontal velocity of the airplane.

The time of motion of the box from the vertical height in which it was dropped is calculated as follows;

h = vt + ¹/₂gt²

where;

v is the initial vertical velocity of the box  = 0t is the time of motion of the boxg is acceleration due to gravityh is the height of fall of the box

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 40 / 9.8 )

t = 2.86 seconds

The horizontal distance travelled by the box is calculated as follows;

d = Vₓ t

where

Vₓ is the horizontal velocity of the airplanet is the time of motion

d = ( 50 m/s ) x ( 2.86 s )

d = 143 m

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The complete question is below;

A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible. Find the horizontal distance travelled by the box.

2. Which of the following is NOT a transverse wave?
a. sound.
b. radio wave.
c. light.
d. all of the above.
e. none of the above

Answers

Answer:

Sound waves are not transverse wave

Answer:

Sound waves are longitudinal

A large vessel of the diameter of 14 mm divides into two identical smaller vessels but the velocity of blood in
smaller vessels remain the same as the velocity of blood in the larger vessel. What is the diameter of the
smaller vessels?

Answers

Answer:

the diameter of the smaller vessels is 9.90 mm

Explanation:

The computation of the diameter of the smaller vessels is given below;

Given that

The larger vessel of the diameter is 14mm

So,

d1 = 7 mm

let us assume the diameter of the smaller artery is d2

Now we used the equation of continuity i.e.

v × pi × d1^2 = 2 × v × pi × d2^2

14^2 = 2 × d2^2

d2 = 9.90 mm

Hence, the diameter of the smaller vessels is 9.90 mm

The position-versus-time plot of a boat positioning itself next to a dock is shown in the figure (Figure 1).
Rank the six points indicated in the plot order of increasing value of the velocity v, starting with the most negative. Rank the points in order of increasing value of the velocity. To rank items as equivalent, overlap them.
Incorrect: Try Again; 2 attempts remaining: no points deducted

Answers

The points in order of increasing value of the velocity can be ranked as:

B < C < A ≡ F < E < D.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

According to the figure:

The points in order of increasing value of the velocity can be written as:

B < C < A ≡ F < E < D.

As the displacement becomes from positive to negative near point B, it has the lowest velocity and  as the displacement becomes from negative to positive near point D, it has the highest velocity

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Ms. Mayo challenged her students to build a pendulum that would hit a block of wood and make it travel the farthest distance. The group that moved the block of wood the most would win a prize. One group's experimental data is shown above.

What is this group's independent variable?

A) height of bob drop


B) mass of pendulum bob


C) length of bob string


D) distance block moves

Answers

Answer:

B) mass of pendulum bob

Usain Bolt is wicked fast. In fact, he is the fastest human in the world and
ran at a crazy 10.1 m/s in the Olympic Games. What is his mass if he had
9.890 Joules of kinetic energy in that race?

Answers

Explanation:

KE = (1/2)mv^2 ---> m = 2KE/v^2 = 2(9.890 J)/(10.1 m/s)^2

= 0.194 kg

Note: I think there's something wrong with the energy value given. The mass value for Usain Bolt is too small. That's less than a pound!

I would like to ask for help in understanding on what basis the universe is considered to be expanding? As far as I understand, it is only an idea (hypothesis, theory) and not a scientific fact as the media presents it. Given that we on Earth receive evidence of various radiations from the past, we cannot say with certainty that the Universe is still expanding. Let's say the Universe stopped expanding 4 billion years ago and started contracting, would the results of all our observations be the same as they are or not?

Answers

Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.

What is universal expansion?

The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion

As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.

The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.

Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.

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At what separation will two charges, each of magnitude 6.0 μC, exert a force of 0.70 N on each other?

Answers

At separation  of 1470 meters, the two charges exert a force of 0.70 N on each other.

What is electric force?

Electric force is the interaction between any two charged objects that can be either attractive or repelling. Newton's rules of motion, which apply to all forces, explain how each one affects the target body and how it does so. The electric force is one of the many forces that operate on objects.

We know that electric force can be mathematically defined as:

F = kQq/r²

0.70 = 9.0 × 10⁹ × (6.0×10⁻⁹)²/r²

r = 1.47 meter.

Hence, the separation between two charges is 1.47 meters.

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If a vehicle goes from 15.0 km/h to 28.0 km/h in 4.60 seconds, how far will it have traveled?

Answers

Answer:

To find the distance the vehicle traveled, you will need to find the average speed of the vehicle over the 4.60 seconds and multiply that by the time traveled.

The average speed of the vehicle can be found by adding the initial speed and the final speed, and then dividing by 2: (15.0 + 28.0) / 2 = 21.5 km/h.

The distance traveled can be found by multiplying the average speed by the time traveled: 21.5 km/h * 4.60 s = 98.7 km.

So, the vehicle will have traveled 98.7 km.

Explanation:

The figure(Figure 1) is a graph of Ex. The potential at the origin is -180 V . What is the potential at x=3.0m?

Answers

The electric potential at x=3.0m is  - 180 Volt according to the figure 1.

What is electric field?

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field.

Electric charges and time-varying electric currents are the building blocks of electric fields.

The electric potential at x=3.0m is given by = initial potential energy + electric field× distance

= - 180 Volt + 0 Volt/meter×3 meter

= - 180 Volt.

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define quant......am physics​

Answers

Answer:

✍ What is quantum physics?

➳ It's the physics that explains how everything works; the best description we have of the nature of the particles that make up matter and the forces with which they interact. Quantum physics underlies how atoms work, and so why chemistry and biology work as they do.

K
The formula B=29a is used to estimate the minimum furnace output, B, in BTUs, for a modern house with the amount of square feet of flooring, a. Determine the minimum furnace
output for a 1600-ft² modern house.
The minimum furnace output for a 1600-ft² modern house is
BTUS.
Aww

Answers

The minimum furnace output for a 1600-ft² modern house is 464000 BTUs.

What is BTU?

British thermal units (Btu) are a unit used to measure the amount of heat in fuels or other energy sources. The amount of heat needed to raise a pound of liquid water's temperature by one degree Fahrenheit at the point where water has its highest density (approximately 39 degrees Fahrenheit).

The formula: the minimum furnace output, B = 29 a.

Area of modern house = 1600 ft²

The minimum furnace output = 29×16000 BTUs

= 464000 BTUs.

Hence, the minimum furnace output for a 1600-ft² modern house is 464000 BTUs.

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What is the power of a lightbulb that has a current of 0.480 A at 120.0 V?

Answers

Answer:

The power is 57.6 watts

Explanation:

We can use the Electric Power Equation to evaluate the power.

Electric Power Equation

[tex]P=IV[/tex]

[tex]P[/tex] is the power in watts

[tex]I[/tex] is the current in amps

[tex]V[/tex] is the voltage in volts

Our lightbulb has current of 0.480 A and a voltage of 120.0 V.

[tex]I=0.480\\V=120.0[/tex]

Now we can evaluate power.

Substitute our values in for the variables.

[tex]P=0.480*120[/tex]

[tex]P=57.6[/tex]

4. How many excess electrons does a balloon that was rubbed on a child's hair and
now has a charge of 4.0 x 107 Coulombs?

Answers

The number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

What is electrons?

Electrons are particles of matter that carry a negative electrical charge. Electrons are the smallest particles in the atom and are responsible for most of the atom's mass. Electrons orbit around the nucleus of the atom and are held together by the electromagnetic force. Electrons have a property called spin, which can have a value of either +1/2 or -1/2. Electrons are found in all elements and are important in chemical reactions as they are able to move around and form bonds with other atoms. Electrons are also important in electricity and magnetism.

The number of excess electrons on the balloon is equal to the charge of the balloon divided by the charge of an electron. Since the charge of an electron is 1.60 x 10-19 Coulombs, the number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

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A horse trots past you and then a fencepost that is 36m away from you. It takes the horse 11.0 sec to make this trot. What is the average velocity of the horse?

Answers

As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

A horse trots past you and then a fencepost that is 36m away from you.

Time taken to  make this trot = 11.0 second.

Hence,  the average velocity of the horse is = total distance travelled/time interval

= 36/11.0 m/s

= 3.27 m/s.

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2 part question
2. Write out the final answer for the coefficient of friction as the average of the values in the table (average all of your coefficients of frictions, and write that average below).
Answer for question #2
The average is = 0.2559975 or 0.256

3. Using similar methods as in questions #1 and #2, estimate the mass of the object in the present, the mystery mass. Include a description of the process and the mathematics of estimating the mass. Use the average coefficient of friction written in #2 to solve for the mystery mass.


4. Set an object (anyone you choose) to be moving at a constant speed. Describe the procedure for keeping the object moving at a constant speed. Write down the speed at which the object is moving, as well.

Answers

the answer is yes number5 hope this helps did before

The linear impulse delivered by the hit of a boxer is 194 N · s during the 0.416 s of contact. What is the magnitude of the average force exerted on the glove by the other boxer? Answer in units of N.

Answers

The magnitude of the average force exerted on the glove by the other boxer is 466.3 N.

What is the relationship between force and impulse?

The force that acts on a body is defined as an agent that causes a change in the position or the state of an object.

Force can be defined as a push or pull agent.

The impulse that acts on a body is the product of the force that acts on that body and the time in which it acts.

Hence, the  relationship between force and impulse is given below:

Force = Impulse/time

The force exerted on the glove by the other boxer is calculated using the formula above as follows:

Force = 194 / 0.416

Force = 466.3 N

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Synthetic pesticides and fertilizers were used extensively during the Green Revolution, but the negative health and environmental impacts were not well-known since the effects added up over time.


True


False

Answers

(True) Synthetic pesticides and fertilizers were used extensively during the Green Revolution, but the negative health and environmental impacts were not well-known since the effects added up over time.

what are Synthetic pesticides

Chemicals created by humans, synthetic pesticides are meant to kill or deter pests. They are mostly utilized in agriculture, although they are also employed in other fields of endeavor and in household settings. In the 1930s, synthetic pesticides were first used in the United States of America (USA).

Chemicals known as synthetic pesticides are employed to manage and control plant pests like weeds, insects, and/or fungal infections.

Danger synthetic pesticides

Human health problems associated with exposure to synthetic pesticides include

increased rates of cancer, birth defects and fertility problems.

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The uniform beam has a weight W and length L and is supported by a pin at A and cable BC ( figure 1)
Part A
Determine the horizontal and vertical components of reaction at A
Express your answers in terms of some or all of the variables W, R. Φ and θ). Enter your answers separated by a comma.
View Available Hint's)
Aa + Ay = ____
Parts B
Determine the one cable car necessary to hold the beans position shown
Express your answers in terms of some or all of the variables W, R. Φ and θ).

Answers

The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).

What is Normal Stress and Strain?

In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."

In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,

If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.

Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.

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A box with a weight of 25N sits on the floor. What is the maximum force that could be applied horizontally on the box before it would start to accelerate if the coefficient of friction is 0.40?

Answers

So, we know that The box isn't moving at all. I'm assuming the coefficient they gave you is for static friction. We know that with static friction, the value that we calculate is a maximum value that represents the force we'd have to apply before an object starts moving!

We also know that the box isn't moving vertically. That means that its Y forces must be cancelling out, which means its weight force and its normal force must be equal to each other!

Now we can plug in these values into our static friction equation!

[tex]F_s[/tex] ≤ [tex]F_N[/tex] * μ[tex]_s[/tex]

[tex]F_s[/tex] ≤ (25N) (0.40)

[tex]F_s = 10[/tex]

Therefore your force that you'd need to apply is 10N!

When gas condense it ______ heat and temperature _____
A. gain heat, temperature decrease
B. gain heat, temperature increase
C. loses heat, temperature doesn't change

Answers

Answer:

C

Explanation:

if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal then what is the initial horizantal velocity of the football?

Answers

The initial horizontal velocity of the football if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal is 23.662 m/s.

To find the initial horizontal velocity (Vx) of the football, you can use the horizontal component of the velocity vector. The horizontal component of velocity is found by multiplying the velocity by the cosine of the angle of launch.

[tex]V_{x}[/tex] = V × cos(angle)

where V is the initial velocity, the angle is the angle of launch (in this case, 30 degrees), and cos is the cosine function.

So, in this case, the initial horizontal velocity of the football would be:

[tex]V_{x}[/tex] = 27 m/s × cos(30)

[tex]V_{x}[/tex] = 27 m/s × 0.866

[tex]V_{x}[/tex] = 23.662 m/s

So the initial horizontal velocity of the football, which moves in the x-direction, is approximately 23.662 m/s.

This means the football will move 23.662 m/s in x direction initially and if no air resistance acts upon the football, it will move at the same velocity in x direction throughout the motion.

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a three tiered birthday cake rests on a table. From the bottom to the top, the cake tiers weigh 15 N, 8N, and 6N, respectively. What is the magnitude and direction of the normal force acting on the base of the seconf tier

Answers

The normal force on the second tier of the cake is 14N. It is the sum of the weight of the last and the second tier of the cake.

What is Normal force?

The normal force is the force which the surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force. If two objects or surfaces are not in contact, they cannot exert a normal force on each other.

Fₙ = mg

Fₙ = Normal force

Fₙ on the second tier is the sum of the first and second tier of the cake is:

Fₙ = 8N + 6N

Fₙ = 14N

The normal force on the second tier is 14N.

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A child should ride in a place in the vehicle where an adult can always be watching.
A. TRUE
B. FALSE

Answers

Answer:

True. mark me as Brilliant

A child should ride in a place in the vehicle where an adult can always be watching is true.

What do you mean by child ?

"A human being below the age of 18 years unless under the law applicable to the child, majority is attained earlier.”

Who is adult ?

"A person who has attained the age of majority and is therefore regarded as independent, self-sufficient, and responsible. The typical age of attaining legal adulthood is 18, although definition may vary by legal rights, country, and psychological development."

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can Mindfulness be both formal or informal?

Answers

Explanation:

mindfulness, it conjures up images of sitting for hours in silent meditation. While formal sitting meditation is one way of practicing mindfulness, there are many formal and informal ways people can use to integrate mindfulness into their lives in order to reap the health benefits

A person has a far point of 50 cm. If he is wearing glasses 2 cm from the eyes, determine
the power of the lens needed for him to see distant object clearly.​

Answers

Answer:

The power will be "2.08 D".

Explanation:

According to the question,

The location of the image form lens,

[tex]d_i=50-2[/tex]

    [tex]=48 \ cm[/tex]

We know that,

⇒ [tex]\frac{1}{d_i} -\frac{1}{d_o} =\frac{1}{f}[/tex]

here,

[tex]d_o[/tex] = Object location

[tex]d_i[/tex] = Image location

[tex]f[/tex] = Focal length

On putting the values in the above expression, we get

⇒ [tex]\frac{1}{48} -\frac{1}{\infty} =\frac{1}{f}[/tex]

             [tex]f=48 \ cm[/tex]  

or,

             [tex]f=0.48 \ m[/tex]

hence,

The refractive power will be:

⇒ [tex]P=\frac{1}{f}[/tex]

       [tex]=\frac{1}{0.48}[/tex]

       [tex]=2.08 \ D[/tex]

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