a. In TCP AIMD with No Slow Start, congestion will not occur, and the throughput of the session is 524288 Kbytes/sec with a link utilization of 0.436.
b. In TCP Slow Start Only, congestion will occur after the third RTT, and the throughput of the session is 174762 Kbytes/sec with a
In order to determine whether congestion will occur and analyze the throughput and link utilization for each type of TCP congestion control mechanism.
let's go through the calculations and steps for each scenario:
a. TCP AIMD (Additive Increase Multiplicative Decrease) with No Slow Start:
- Maximum segment length (MSS) = 1 Kbyte = 1000 bytes
- Bandwidth = 1.2 Gbps = 1200 Mbps = 1200000 Kbps
- RTT (Round-Trip Time) = 4 msec
- File size = 2 MByte = 2 * 1024 * 1024 bytes = 2097152 bytes
To determine whether congestion occurs, we need to compare the number of bytes transmitted to the Bandwidth x Delay product.
Bandwidth x Delay product = (1200000 Kbps / 8) * (4 msec) = 600000 Kbyte
Since the file size is 2097152 bytes, which is less than the Bandwidth x Delay product, congestion will not occur in this case.
The throughput of the session can be calculated using the formula: Throughput = File size / RTT.
Throughput = 2097152 bytes / 4 msec = 524288 Kbytes/sec.
The link utilization can be calculated by dividing the throughput by the link capacity: Link utilization = Throughput / Bandwidth.
Link utilization = 524288 Kbytes/sec / 1200000 Kbytes/sec = 0.436.
b. TCP Slow Start Only:
- Maximum segment length (MSS) = 1 Kbyte = 1000 bytes
- Bandwidth = 1.2 Gbps = 1200 Mbps = 1200000 Kbps
- RTT (Round-Trip Time) = 4 msec
- File size = 2 MByte = 2 * 1024 * 1024 bytes = 2097152 bytes
In the slow start procedure, the window size starts with 1 MSS and doubles every RTT until congestion occurs. When congestion occurs, the window size is reset to 1 MSS again.
To determine whether congestion occurs, we need to compare the number of bytes transmitted to the Bandwidth x Delay product.
Bandwidth x Delay product = (1200000 Kbps / 8) * (4 msec) = 600000 Kbyte
At the beginning, the window size is 1 MSS = 1000 bytes.
For the first RTT, the window size doubles to 2000 bytes.
For the second RTT, the window size doubles to 4000 bytes.
For the third RTT, the window size doubles to 8000 bytes.
Since the window size (8000 bytes) is greater than the Bandwidth x Delay product (600000 bytes), congestion will occur after the third RTT.
The throughput of the session can be calculated by dividing the file size by the number of RTTs until congestion:
Throughput = File size / (Number of RTTs until congestion * RTT)
Throughput = 2097152 bytes / (3 * 4 msec) = 174762 Kbytes/sec.
The link utilization can be calculated by dividing the throughput by the link capacity: Link utilization = Throughput / Bandwidth.
Link utilization = 174762 Kbytes/sec / 1200000 Kbytes/sec = 0.145.
In summary:
a. In TCP AIMD with No Slow Start, congestion will not occur, and the throughput of the session is 524288 Kbytes/sec with a link utilization of 0.436.
b. In TCP Slow Start Only, congestion will occur after the third RTT, and the throughput of the session is 174762 Kbytes/sec with a
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numbers = (47, 11, 77, 66, 65, 96, 62, 56)
Partition(numbers, 2, 7) is called.
Assume quicksort always chooses the element at the midpoint as the pivot.
What is the pivot?
What is the low partition?
What is the high partition?
What is numbers after Partition(numbers, 2, 7) completes?
The pivot is 66. The low partition is (47, 11, 62, 56, 65). The high partition is (77, 96). After Partition(numbers, 2, 7) completes, the updated numbers list is (47, 11, 62, 56, 65, 66, 77, 96).
In quicksort, the chosen pivot element is crucial for the partitioning process. Since quicksort in this case always chooses the element at the midpoint as the pivot, we can determine the pivot by finding the element at the middle index between the specified range. In the given list, the midpoint index between 2 and 7 is 4, and the corresponding element is 66.
The partitioning process in quicksort involves rearranging the elements such that elements smaller than the pivot are placed before it, and elements larger than the pivot are placed after it. The low partition consists of all elements that are smaller than the pivot, while the high partition consists of all elements that are larger than the pivot. In this case, the low partition is (47, 11, 62, 56, 65) and the high partition is (77, 96).
After the partitioning is completed, the elements are rearranged such that the low partition comes before the pivot and the high partition comes after the pivot. The resulting updated numbers list is (47, 11, 62, 56, 65, 66, 77, 96).
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Unit 13 HW 5
My Solutions >
Second-Order ODE with Initial Conditions
Solve this second-order differential equation with two initial conditions.
d2y/dx2=-5y-6y
OR
d2y/dx2+5 dy/dx+6y=0
Initial Conditions:
y(0)=1
y'(0)=0
Define the equation and conditions. The second initial condition involves the first derivative of y. Represent the derivative by creating the symbolic function Dy = diff(y) and then define the condition using Dy(0)==0.
Script
1 syms y(x)
2 Dy = diff(y);
3 ode diff(y, x,2)
4 cond1 y(0) ==;
5 cond2 Dy(0) ==;
6 conds [cond1;
7 ySol(x)= dsolve(,conds);
8 ht2= matlabFunction(ySol); 9 fplot (ht2)
Save
C Reset
MATLAB Documentation
6ку = 0;
Run Script
To solve the second-order differential equation with two initial conditions, you can use the following MATLAB code:
syms y(x)
Dy = diff(y);
ode = diff(y, x, 2) + 5*diff(y, x) + 6*y;
cond1 = y(0) == 1;
cond2 = Dy(0) == 0;
conds = [cond1; cond2];
ySol(x) = dsolve(ode, conds);
ht2 = matlabFunction(ySol);
fplot(ht2)
In this code, we define the symbolic variable y(x) and its derivative Dy. The second-order differential equation is represented by ode, which is set to diff(y, x, 2) + 5*diff(y, x) + 6*y = 0. The initial conditions are defined as cond1 and cond2, representing y(0) = 1 and Dy(0) = 0, respectively.
The conditions are combined into the vector conds. The dsolve function is then used to solve the differential equation with the given initial conditions, resulting in the symbolic solution ySol(x). Finally, the solution ySol is converted into a function handle ht2 using matlabFunction, and fplot is used to plot the solution.
Make sure to run this code in MATLAB or Octave to obtain the numerical solution and plot for the given second-order differential equation with the provided initial conditions.
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Take the polymorphic type for example:
(c, h) -> (c -> h) -> (h, h)
Make a list of all conceivable total functions of this type as lambda expressions, omitting any that behave similarly to the ones you've already put down.
The given polymorphic type (c, h) -> (c -> h) -> (h, h) represents a function that takes two arguments, a function from c to h, and returns a tuple of type (h, h). Multiple conceivable total functions can be defined as lambda expressions for this type.
The given polymorphic type (c, h) -> (c -> h) -> (h, h) represents a function that takes two arguments: a value of type c, and a function from c to h. It returns a tuple of type (h, h). To create a list of conceivable total functions of this type using lambda expressions, we can consider different combinations of operations on the input arguments to produce the desired output.
For example, one possible lambda expression could be: λc h f. (f c,f c)
Here, the lambda expression takes a value c, a value h, and a function f, and applies the function f to the input c to produce two h values. It returns a tuple containing these two h values.
Similarly, other conceivable total functions can be created by varying the operations performed on the input arguments. The list can include multiple lambda expressions, each representing a distinct total function for the given polymorphic type.
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Given the following file (you'll need to type this into a text file in Ropi) I
12345, Jones, Michael,45
46432,Smith, Mary,21 98034,Lee, YISoon,34
48223,Thompson, Zaire,39 29485,Mendez, Jorge,61
Employes Class:
Note, the file will be in the following order:
Employee ID, Lost Name, First Name, Age
Make Instance variables for the following:
Employee ID (Integer), Last Name (String), First Name (String), age (Integer)
Create assessor methods for each instance variable:
String getFirstName(), String getLastName(), int getEmpID(), Int age0
Create mutator methods for each Instance variable:
vold setFirstName(String first), void setLastName(String last), vold setEmpID (int id), void setAge(int age)
Create a toString() method that will print out each record like this:
Employee firstName YiSoon
Employee lastName Lee Employee ID 98034
Employee Age 34
Implement the Comparable Interface and create the Comparable method:
public int compareTo(Employee other)
In this method, compare the last names.
If the last name of the calling object is the same as the other object return 0
If the last name of the calling object is less than the other object return -1
If the last name of the calling object is greater than the other object return 1
Here's an implementation of the Employee class with the requested instance variables, accessor methods, mutator methods, toString() method, and compareTo() method:
public class Employee implements Comparable<Employee> {
private int empID;
private String lastName;
private String firstName;
private int age;
// Constructor
public Employee(int empID, String lastName, String firstName, int age) {
this.empID = empID;
this.lastName = lastName;
this.firstName = firstName;
this.age = age;
}
// Accessor methods
public String getFirstName() {
return firstName;
}
public String getLastName() {
return lastName;
}
public int getEmpID() {
return empID;
}
public int getAge() {
return age;
}
// Mutator methods
public void setFirstName(String first) {
firstName = first;
}
public void setLastName(String last) {
lastName = last;
}
public void setEmpID(int id) {
empID = id;
}
public void setAge(int age) {
this.age = age;
}
// toString() method
public String toString() {
return "Employee firstName " + firstName + "\n" +
"Employee lastName " + lastName + "\n" +
"Employee ID " + empID + "\n" +
"Employee Age " + age + "\n";
}
// compareTo() method
public int compareTo(Employee other) {
return this.lastName.compareTo(other.getLastName());
}
}
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QHelp me with this Java programming Experiment question please
Name: Thread Application Design
Environment: Personal Computer with Microsoft Windows, Oracle Java SE
Development Kit, Netbeans IDE
Place:
Objective and Requirements: To study and understand the life cycle of Java
threads. ; To master methods to design concurrent applications with threads.
Contents: To design a Java desktop application which realize a digital clock or an
analog clock.
Important Notes: After finishing the experiment, you must write the lab report,
which will be the summary of application designs and debugging
In this Java programming experiment, the objective is to study and understand the life cycle of Java threads and master the methods to design concurrent applications using threads.
How to implement the Java programming experimentThe task involves designing a Java desktop application that implements either a digital or analog clock. The important notes include the requirement to write a lab report summarizing the application designs and the process of debugging.
The suggested steps for the experiment are as follows:
1. Set up the development environment with Oracle Java SE Development Kit and Netbeans IDE.2. Create a new Java project in Netbeans and design the user interface using Swing or JavaFX.3. Create a ClockThread class that extends Thread to handle continuous time updates.4. Implement the run() method in the ClockThread class to update the clock display.5. Use SwingUtilities.invokeLater() to update the clock display in the user interface.6. Start the ClockThread in the main class of the application.7. Test and debug the clock functionality.8. Write a lab report summarizing the application design, challenges faced, and solutions implemented.The lab report should provide a comprehensive overview of the application design and the debugging process, including code snippets, screenshots, and diagrams if necessary.
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How to implement this html/css/js code so that when another question is selected, the other one will slide up and be hidden?
Tips and Frequently Asked Questions
To achieve this sliding effect, you can use jQuery's slideUp() and slideDown() methods.
First, give each question a unique ID so that we can distinguish between them. For example:
html
<div id="question1">
<h2>How to choose a bouquet?</h2>
<p>Add fragrance. Use a scented flower in your bouquet.</p>
<!-- more text here -->
</div>
<div id="question2">
<h2>How to care for your bouquet?</h2>
<p>Keep the vase clean and filled with fresh water.</p>
<!-- more text here -->
</div>
Then, add a click event listener to each question that will slide up any open questions and slide down the clicked question. You can do this using jQuery's click() method and slideUp() and slideDown() methods.
javascript
$(document).ready(function() {
// hide all answers on page load
$(".faq-answer").hide();
// add click event listener to each question
$(".faq-question").click(function() {
// if clicked question is not already open
if (!$(this).hasClass("open")) {
// slide up any open questions and remove "open" class
$(".faq-question.open").next().slideUp();
$(".faq-question.open").removeClass("open");
// slide down clicked question's answer and add "open" class
$(this).next().slideDown();
$(this).addClass("open");
}
// if clicked question is already open
else {
// slide up clicked question's answer and remove "open" class
$(this).next().slideUp();
$(this).removeClass("open");
}
});
});
Note that this code assumes that each question has a corresponding answer with a class of faq-answer. You can adjust the class names and selectors to match your specific HTML structure.
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What does this script do when executed? Explain in plain terms.
#!/bin/bash
Question7()
{
arg1=$1
arg2=$2
ls
if [ $# -gt 0 ]; then
clear
if [[ -f $1 && -w $1 ]]; then
echo The file $1 is readable
cp $1 $2.bak
echo The backup file created f $2.bak is a copy of $1 file.
else
echo The file $1 does not exist or is not writable file
fi
fi
}
Question7 hello get
The script you provided is a bash script written in the shell scripting language. When executed, it defines a function named "Question7" that takes two arguments.
The purpose of the script is to perform a set of actions on a file specified by the first argument and create a backup copy of it with a new name specified by the second argument.
Here's a breakdown of what the script does:
It assigns the first argument to the variable "arg1" and the second argument to the variable "arg2".
It lists the contents of the current directory using the "ls" command.
It checks if the number of arguments passed to the script is greater than 0 using the "$#" variable. If there are no arguments, this block of code will be skipped.
It clears the terminal screen using the "clear" command.
It checks if the first argument is a readable file and if the second argument is a writable file using the "-f" flag for file existence check and the "-w" flag for file writability check. If both conditions are true, the following actions are performed:
It prints a message indicating that the file specified by the first argument is readable.
It creates a backup copy of the file specified by the first argument with the name specified by the second argument and appends ".bak" to the filename.
It prints a message indicating that the backup file has been created and it is a copy of the original file.
If the conditions in step 5 are not met (i.e., the file does not exist or is not writable), it prints a message indicating that the file specified by the first argument does not exist or is not a writable file.
Finally, the function "Question7" is called with the arguments "hello" and "get". So, when the script is executed, it will perform the actions based on these arguments.
In summary, the script lists the files in the current directory, checks if the specified file is readable and writable, creates a backup copy of the file with a new name, and provides appropriate feedback messages based on the success or failure of these operations.
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At the end of the exercise, the students should be able to: - Deduce the importance of modeling and simulation in real-life applications; and - Propose feasible real-life applications of modeling and simulation. Instructions: Select one (1) type of industry from the list below. Education/Educational Services Gaming Industry Fashion/Clothing Farming/Agriculture Medical/Healthcare Services Manufacturing Industry
Answer the following questions based on the industry that you have selected above (10 items x 5 points). that you would like to simulate. problem/scenario/condition 1. Propose one (1) real-life 2. Who would benefit from your proposed simulation and how 3. What are the possible impacts of your proposed simulation study on the industry that you have selected? 4. List all the possible system components related to the modeling and simulation that you would like to conduct. Briefly describe each component. 5. Is there any aleatory variable that would be involved in the modeling and simulation process? Rationalize your answer. 6. What specific simulation technique would be appropriate for your study? Why? 7. Is it possible to apply the queueing theory to your study? Why or why not? 8. Briefly describe the input data collection process that you would conduct for your study. 9. What verification method would you use for your study? Rationalize your answer. 10. What validation method would you use for your study? Rationalize your answer.
In this exercise, students are required to select one industry from a given list and propose a real-life simulation study. They need to consider the beneficiaries of the simulation, the potential impacts on the industry, system components, involvement of aleatory variables, appropriate simulation techniques, applicability of queueing theory, data collection process, verification method, and validation method.
For the selected industry, students can propose a real-life simulation study to demonstrate the importance of modeling and simulation in practical applications. They should identify a specific problem, scenario, or condition within the industry and propose how a simulation can provide valuable insights and solutions.
The beneficiaries of the proposed simulation could vary depending on the selected industry. For example, in the healthcare industry, the simulation study could benefit healthcare providers, policymakers, and researchers by allowing them to analyze the impact of different strategies on patient outcomes, resource allocation, or healthcare delivery.
The possible impacts of the simulation study on the industry could be substantial. It could lead to improved decision-making, optimized processes, cost reduction, enhanced productivity, better resource allocation, risk mitigation, or improved overall performance.
To conduct the simulation, students need to consider various system components related to the industry and the specific problem being addressed. These components could include entities such as patients, healthcare professionals, equipment, facilities, or supply chains. Each component should be described briefly, highlighting its relevance to the simulation study.
The involvement of aleatory variables in the modeling and simulation process depends on the nature of the problem and the specific industry. Aleatory variables are random or uncertain factors that can influence the simulation outcomes. Students need to rationalize whether such variables exist and explain their impact on the simulation results.
The specific simulation technique to be used in the study should be determined based on the problem and its requirements. Different techniques, such as discrete event simulation, agent-based modeling, or system dynamics, may be suitable depending on the complexity of the system, the level of detail required, and the specific objectives of the simulation.
Applying queueing theory to the study depends on the industry and the problem being addressed. Queueing theory is often applicable when analyzing waiting times, congestion, or service capacity in systems involving queues. Students should rationalize whether queueing theory can be utilized and explain its relevance to the specific study.
The input data collection process for the simulation study should be described briefly. This involves identifying the necessary data sources, the methods of data collection, and any challenges or considerations related to data availability, reliability, or accuracy.
For verification, students should determine the appropriate method to ensure the correctness of the simulation model. This could involve comparing the simulation output to analytical or historical data, conducting sensitivity analysis, or peer reviewing the model's structure and logic. The chosen verification method should be rationalized based on its suitability for the study.
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Hello,
I'm having trouble on creating a method to read the mistake of the user input and display it at the edn
for example :
OUTPUT:
Please enter a mathematical expression:
//---> input: [2*(2+3]]/6
The input expression is not balanced! The first mismatch is found at position 7!
So im not sure how make a method to find the mismatch position and display it
Thank you
code below:
import java.util.*;
public class Matheue {
static boolean areBracketsBalanced(String ecpr)
{
Stack s = new Stack();
for (int i = 0; i < ecpr.length(); i++)
{
char c = ecpr.charAt(i);
if (c == '(' || c == '[' || c == '{')
{
s.push(c);
continue;
}
if (s.isEmpty())
return false;
char check;
switch (c) {
case ')':
check = s.pop();
if (check == '{' || check == '[')
return false;
break;
case '}':
check = s.pop();
if (check == '(' || check == '[')
return false;
break;
case ']':
check = s.pop();
if (check == '(' || check == '{')
return false;
break;
}
}
return (s.isEmpty());
}
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter a mathematical ecpression: ");
String ecpr = keyboard.nextLine();
//String ecpr = "([{}])";
if (areBracketsBalanced(ecpr))
System.out.println("Balanced ");
else
System.out.println("Not Balanced ");
}
}
The method to read the mistake of the user input and display it at the end is known as the "balanced parenthesis" method. If the input expression is balanced, it means that all open brackets have a closing bracket that is not mixed with another opening bracket. The `areBracketsBalanced()` function returns true when there are no misplaces open or closing brackets and false when there are misplaced brackets.
Thus, to fix the program and display the position of the first error of the user's input, a line of code needs to be added to the `areBracketsBalanced()` function. The code should display the position of the first occurrence of an opening or closing bracket that has no corresponding closing or opening bracket. This line of code would look something like this:
`System.out.println("The input expression is not balanced! The first mismatch is found at position " + i);`.
This line of code displays the first position of the mismatch. Below is the modified code that solves the problem:
import java.util.*;public class Matheue { static boolean areBracketsBalanced(String ecpr) { Stack s = new Stack(); for (int i = 0; i < ecpr.length(); i++) { char c = ecpr.charAt(i); if (c == '(' || c == '[' || c == '{') { s.push(c); continue; } if (s.isEmpty()) return false; char check; switch (c) { case ')': check = s.pop(); if (check == '{' || check == '[') { System.out.println("The input expression is not balanced! The first mismatch is found at position " + i); return false; } break; case '}': check = s.pop(); if (check == '(' || check == '[') { System.out.println("The input expression is not balanced! The first mismatch is found at position " + i); return false; } break; case ']': check = s.pop(); if (check == '(' || check == '{') { System.out.println("The input expression is not balanced! The first mismatch is found at position " + i); return false; } break; } } return (s.isEmpty()); } public static void main(String[] args) { Scanner keyboard = new Scanner(System.in); System.out.println("Please enter a mathematical expression: "); String ecpr = keyboard.nextLine(); if (areBracketsBalanced(ecpr)) System.out.println("Balanced "); else System.out.println("Not Balanced "); }}
Note: The modifications to the code include adding the line of code that displays the position of the first opening or closing bracket that has no corresponding opening or closing bracket.
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(c) A user runs the 'uniq' command on a data set, expecting only unique lines to appear. However, many repeated lines are present in the output. Give a reason as to why this [2] may be.
It's important to consider these factors and adjust the input data or use additional command options as needed to achieve the desired outcome with the 'uniq' command.
There could be a few reasons why the 'uniq' command is not producing the expected output of only unique lines:
Sorting: The 'uniq' command relies on the input data being sorted in order to identify and remove duplicate lines. If the input data is not sorted, 'uniq' may not work correctly and duplicate lines may still appear in the output. Make sure to sort the data before using the 'uniq' command.
Leading or trailing whitespace: If the lines in the input data have leading or trailing whitespace characters, 'uniq' may consider them as different lines even if their content is the same. It's important to ensure consistent whitespace formatting in the data to achieve accurate results with 'uniq'.
Case sensitivity: By default, 'uniq' treats lines as distinct based on their exact content, including differences in case. If there are lines with the same content but different case (e.g., "Hello" and "hello"), 'uniq' will consider them as separate lines. Use the appropriate command options, such as '-i' for case-insensitive comparison, to handle case differences.
Adjacent duplicates: 'uniq' only removes adjacent duplicate lines. If duplicate lines are not consecutive in the input data, 'uniq' will not detect them as duplicates. Ensure that the duplicate lines are placed consecutively in the input data for 'uniq' to work as expected.
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Assume Heap1 is a vector that is a heap, write a statement using the C++ STL to use the Heap sort to sort Heap1.
Here's an example of how you can use the C++ STL to sort a heap vector using Heap Sort:
#include <algorithm>
#include <vector>
// assume we have a heap vector called Heap1
std::vector<int> Heap1 { 3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5 }; // example heap vector
std::make_heap(std::begin(Heap1), std::end(Heap1)); // convert Heap1 to a heap
std::sort_heap(std::begin(Heap1), std::end(Heap1)); // sort Heap1 using heap sort
In this example, make_heap is used to convert the vector Heap1 into a heap. Then, sort_heap is used to sort the heap vector in ascending order using Heap Sort. You can replace the example vector with your own heap vector and modify the sorting order as needed.
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In Python Purpose: To practice using lists and loops.
Degree of Difficulty: Easy – Moderate
Problem Description
Textual analysis is a broad term for various research methods used in the humanities and social
sciences to describe, interpret and understand texts. A text can be a piece of writing, such as a book,
email, social media communications, or transcribed conversations such as interviews. It can also be any
object whose meaning and significance you want to interpret in depth: a film, an image, an artifact,
even a place. One of the tools used in textual analysis is word frequency. The word frequencies are
often used to develop a word cloud.
In this assignment you will develop a program that counts the frequency of words found in a text.
You will be given a text to analyze and a list of exclusions - words for which frequencies are not
required (the, a, of, at, for, or, and, be ,,, ). After analyzing the text – for each word in the text, your
program will print the words found and the number of times (frequency) each words was used in the
given text.
For example, given the text "red blue green green the the thee thee a red red black" (yes, "thee" is
supposed to be there) and the exclusion words (the, a, of, at, for, or, and, be), your program will
produce the following results:
red 3
blue 1
green 2
thee 2
black 1
To solve this problem, your program will use one list (L1) to keep track of the words found in the text
and a second list (L2) to keep track of the number of times that word was used. The lists L1 and L2 are
used only for illustrative purposes (you will choose more meaningful variable names). After program
completing, using the example text above, contents of the two lists may look as follows.
Offset L1 L2
0 red 3
1 blue 1
2 green 2
3 thee 2
4 black 1
Notes:
• Your program will not use a dictionary.
• Your program may use other lists for other purposes but must use the two lists outlined above.
Programming Suggestions:
• Your program will need to remove any punctuation found in the text (so that the punctuation does
not appear as part of a word). The .replace() method can be used to do this. The provided starter
program includes this code. • In your program, you can use the .split() string method to remove the words from given text (a
string) into a list (of words).
Remember, your program should not count the frequency for words in the exclusions list. There are at
least 2 approaches you can use to exclude those words in the frequency counts.
• When processing the words in the text, ignore the word if it is on the exclusion list.
• After creating the list of words (using .split, above), you can remove all words to be excluded
words from that list before starting the counts.
Once the words are processed, print each word found in the text and its frequency.
A starter program (a5q2_starter.py) is provided. The program contains 2 texts. One text is "red
blue green green the the thee thee a red red black"; use this to test and debug your program.
The other text is from Martin Luther King’s I Have a Dream speech. It is commented out using a
docstring. After you are sure your program is working, remove the docstring and use this text.
By creating two lists: one to store the unique words found in the text and another to store the corresponding frequencies of those words.
How can we analyze the frequency of words in a text using Python?The problem involves counting the frequency of words in a given text while excluding certain words from the count. To solve this, we can use two lists: one to keep track of the unique words found in the text (L1), and another to keep track of the frequency of each word (L2).
The program should remove any punctuation from the text using the `.replace()` method and split the text into a list of words using the `.split()` method. We should iterate through each word in the list and check if it is in the exclusion list.
If not, we increment the frequency count of that word. Finally, we print each word and its frequency. The provided starter program contains example texts to test the program.
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Processing database transactions at SERIALIZABLE isolation level A database programmer implemented the following stored function SKILLS. CREATE OR REPLACE FUNCTION SKILLS ( applicant_number NUMBER ) RETURN NUMBER IS tots NUMBER (7) ; totc NUMBER (8); BEGIN SELECT SUM (slevel) INTO tots FROM SPOSSESSED WHERE anumber = applicant_number; SELECT COUNT (anumber) INTO totc FROM SPOSSESSED WHERE anumber applicant_number; = IF (totc = 0) THEN RETURN 0; ELSE RETURN tots/totc; END IF; END SKILLS; It is possible, that in certain circumstances the processing of the function may return an incorrect result when it is concurrently processed concurrently with another transaction and it is processed at an isolation level READ COMMITTED. Your task is (1) to explain why the function may return an incorrect result when it is processed at an isolation level READ COMMITTED, (2) to provide an example of a case when the function may return an incorrect result. When visualizing the concurrent executions use a technique of two-dimensional diagrams presented to you during the lecture classes, for example, see a presentation 14 Transaction Processing in Oracle DBMS slide 16. When visualizing the concurrent executions use a technique of two-dimensional diagrams presented to you during the lecture classes, for example, see a presentation 14 Transaction Processing in Oracle DBMS slide 16. Deliverables A file solution4.pdf with the explanations why the function may return an incorrect result when it is processed at READ COMMITTED isolation level and an example of a concurrent processing of the function when the returned result may be incorrect.
I can explain why the function may return an incorrect result when processed at the READ COMMITTED isolation level and provide an example using text-based explanations and diagrams.
At the READ COMMITTED isolation level, each transaction reads only the committed data and does not allow dirty reads. However, it allows non-repeatable reads and phantom reads. In the given stored function, two SELECT statements are executed sequentially. If another transaction modifies the data between these two SELECT statements, it can lead to inconsistent results.
Example:
Let's consider two concurrent transactions: Transaction A and Transaction B.
Transaction A:
BEGIN
SELECT SUM(slevel) INTO tots FROM SPOSSESSED WHERE anumber = 1;
-- Assume tots = 50
SELECT COUNT(anumber) INTO totc FROM SPOSSESSED WHERE anumber = 1;
-- Assume totc = 5
-- Return tots/totc = 10
END
Transaction B:
BEGIN
-- Another transaction modifies the data
DELETE FROM SPOSSESSED WHERE anumber = 1;
-- Commit the transaction
COMMIT
END
In this scenario, Transaction A starts first and calculates tots = 50 and totc = 5. However, before it can return the result, Transaction B executes and deletes all rows with anumber = 1 from the SPOSSESSED table. After Transaction B commits, Transaction A resumes and tries to fetch tots and totc values, but now there are no rows matching the WHERE condition. Consequently, the function will return NULL or an incorrect result.
It's important to note that the example above assumes that the transactions are executed concurrently and that the READ COMMITTED isolation level allows non-repeatable reads or phantom reads. The specific behavior may vary depending on the database management system and its transaction isolation implementation.
To create the visual representation of the concurrent executions and provide a detailed diagram, I recommend referring to the presentation slides or using a diagramming tool to illustrate the sequence of actions and their outcomes in a graphical format.
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During the COVID-19, people who visit Hong Kong are required to find a hotel quarantine for 21 days. You are required to design an online information system with all the quarantine hotels and relevant information for all the visitors/travellers including all the Hong Kong people.
System modelling using UML with description
UML diagrams with one use case, one complete class diagram and at least four major interaction diagrams, with description
Here's an example of the UML system modeling for the online information system for hotel quarantine in Hong Kong during the COVID-19 pandemic.
Use Case Diagram:
The Use Case Diagram represents the interactions between the system and its actors. In this case, we have two actors: Visitors/Travelers and System Admin.
+-----------------+
| Visitors/ |
| Travelers |
+--------+--------+
|
| uses
|
+--------v--------+
| System Admin |
+-----------------+
Class Diagram:
The Class Diagram represents the static structure of the system, including the classes, their attributes, and relationships.
+---------------------+
| HotelQuarantineInfo |
+---------------------+
| - hotels: Hotel[] |
+---------------------+
| + getHotels(): Hotel[] |
| + addHotel(hotel: Hotel) |
+---------------------+
+---------+
| Hotel |
+---------+
| - name |
| - address |
| - contact |
+---------+
Interaction Diagrams:
Interaction Diagrams capture the dynamic behavior of the system by illustrating the sequence of interactions between objects. Here are four major types of interaction diagrams:
Sequence Diagram: Illustrates the interactions between objects over time.
Communication Diagram: Focuses on the objects and their connections in a network-like structure.
Interaction Overview Diagram: Provides an overview of the flow of control and data among objects.
Timing Diagram: Shows the behavior of objects over a certain period of time.
Note: Since the content and complexity of the interaction diagrams depend on the specific functionality and requirements of the system, it would be best if you provide more details about the specific interactions or scenarios you would like to model.
Please let me know if you have any specific scenarios or interactions in mind so that I can provide a more detailed example.
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What do the researchers say the data collection techniques and
guidelines should be?
Researchers emphasize the importance of ethical and rigorous data collection techniques and guidelines. They recommend obtaining informed consent from participants, ensuring privacy and confidentiality, and minimizing potential harm or risks.
Researchers should use appropriate sampling methods to ensure representativeness and avoid bias. They should also employ validated and reliable measurement tools and adhere to standardized protocols. Additionally, researchers should document and maintain data integrity, ensuring transparency and reproducibility. It is essential to follow ethical guidelines set by relevant research organizations and obtain necessary approvals from institutional review boards or ethics committees to ensure the responsible and ethical conduct of data collection.
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You want to create a pin number for ATM. If the length of pin number should be 4 or 5, and you choose each digit out of only odd digits, i.e {1, 3, 5, 7, 9), how many different pin numbers of length 4 or 5 are possible?
The total number of pin numbers of length 5 is 5^5 = 3125. To calculate the number of different pin numbers possible with the given conditions.
We need to consider two cases: pin numbers of length 4 and pin numbers of length 5. Case 1: Pin numbers of length 4. Since each digit can be chosen from the set {1, 3, 5, 7, 9}, there are 5 choices for each digit. Therefore, the total number of pin numbers of length 4 is given by 5^4 = 625. Case 2: Pin numbers of length 5. Similar to the previous case, each digit can be chosen from the set {1, 3, 5, 7, 9}. Hence, there are 5 choices for each digit.
Thus, the total number of pin numbers of length 5 is 5^5 = 3125. Combining both cases, we have a total of 625 + 3125 = 3750 different pin numbers possible with the given conditions.
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VBA Task 2 (30%) In this task you are required to write a FUNCTION that addresses a "Best Case Scenario" procedure. This function should be designed as; BestCase(InputData) Given an array that represents a time series of closing daily stock price observations, return the largest possible profit from completing one transaction. This means buying 1 share on 1 particular day and selling the same share at a later day. The function should output the profit made from the transaction. O The function should never return a negative profit. O You must always buy before you sell, i.e. No Short Selling. Examples provided to clarify the functionality: Input Data = [4.25 4.86 5.21 6.21 5.85 5.55] Return 1.96 = = [24.34 24.18 22.11 23.85 23.55 24.18 25.15 24.86] Return = 3.04 Input Data = [34.34 33.14 32.16 31.88] Return = 0 Input Data
The task is to write a function named BestCase that is designed to find the best possible stock price in the given data. It takes an array as an input and returns the maximum profit that can be earned from the stock market.
The given task can be completed by finding the minimum value in the array and then subtracting that value from the maximum value in the array. The following function can be used for the above purpose:
Function BestCase(InputData)
Dim MinVal, MaxVal As Double
Dim Profit As Double
MinVal = InputData(0)
MaxVal = InputData(0)
For i = 0 To UBound(InputData)
If InputData(i) < MinVal
Then MinVal = InputData(i)
End If
If InputData(i) > MaxVal
Then MaxVal = InputData(i)
End If Next i
Profit = MaxVal - MinVal
If Profit < 0 Then
Profit = 0
End If
BestCase = Profit
End Function
The above function first initializes two variables named MinVal and MaxVal with the first value of the InputData array. Then, it iterates through the array and checks if any value in the array is smaller than MinVal, it sets the new MinVal. Similarly, it checks if any value in the array is greater than MaxVal, it sets the new MaxVal. Then, it subtracts MinVal from MaxVal to get the Profit. If the Profit is negative, it sets the Profit to 0. Finally, it returns the Profit. Thus, the BestCase function can be used to find the best possible profit that can be earned by selling the stocks bought on a given day and the maximum possible profit that can be earned is returned by the function.
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There are different types of events to consider when using the
Event Decomposition Technique. Define what the Event Decomposition
Technique is and distinguish between external and state events.
The Event Decomposition Technique is a problem-solving approach used in software engineering and system design to identify and analyze events that occur within a system. External events are initiated by external agents, while state events are initiated by changes in the system's internal state.
The Event Decomposition Technique is a problem-solving approach used in software engineering and system design that involves identifying and analyzing events that occur within a system. The technique involves breaking down complex events into smaller, more manageable sub-events that can be analyzed and designed in detail.
There are two main types of events that can occur within a system: external events and state events. External events are events that occur outside the system and are initiated by external agents, such as users or other systems. For example, a user clicking a button on a website or an external system sending a data request to a database are both examples of external events.
State events, on the other hand, are events that occur within the system and are initiated by changes in the system's internal state. For example, a change in a user's account balance triggering a notification or a change in a system's configuration settings triggering a system restart are both examples of state events.
In order to design a system that can respond to both external and state events, it is important to identify and analyze all relevant events that can occur within the system. By breaking down complex events into smaller sub-events and analyzing each one in detail, the Event Decomposition Technique can help ensure that all relevant events are considered and addressed in system design and development.
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When comparing Internet Checksum with Two-dimensional bit parity, which of these is correct O A. Both methods can detect and correct errors OB. Internet checksum is used for Apple/Mac devices only while two-dimensional bit parity is used by Windows based system OC. Internet checksum can detect but not correct bit error, while two-dimensional bit parity can detect and correct errors O D. Internet checksum can detect and correct bit error, while two-dimensional bit parity only detects errors Reset Selection
The correct statement is D. Internet checksum can detect but not correct bit error, while two-dimensional bit parity can detect and correct errors.
The correct statement is D. The Internet checksum is a technique used in network protocols to detect errors in data transmission. It calculates a checksum value based on the data being sent and includes it in the packet. Upon receiving the data, the receiver recalculates the checksum and compares it with the received checksum. If they match, it indicates that the data is likely to be error-free. However, if they do not match, it suggests that errors may have occurred during transmission, but the Internet checksum itself does not provide the capability to correct those errors.
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What is the cause of the error and how can it be resolved?
There can be various causes of errors in different contexts, such as programming, system errors, or application errors.
In general, errors can occur due to several reasons, including:
Syntax Errors: These occur when the code does not follow the correct syntax rules of the programming language. To resolve syntax errors, you need to identify and correct the specific syntax mistake(s) in the code.Logic Errors: These occur when the code does not produce the expected or desired output due to flaws in the logic or algorithm. To resolve logic errors, you need to review and debug the code to identify and fix the logical issues.Input Errors: These occur when the input provided to a program or system is incorrect, invalid, or out of range. Resolving input errors involves validating and sanitizing the input data to ensure it meets the expected criteria.Dependency Errors: These occur when there are missing or incompatible dependencies or libraries required by the program or system. Resolving dependency errors involves installing or updating the necessary dependencies to match the program's requirements.Configuration Errors: These occur when the configuration settings of a program or system are incorrect or incompatible. Resolving configuration errors involves reviewing and adjusting the configuration settings to align with the desired functionality.To resolve an error, it is crucial to carefully analyze the error message or symptoms, understand the context in which it occurs, and then apply appropriate debugging techniques, such as code review, logging, or using debugging tools. Additionally, referring to documentation, seeking help from online communities or forums, and consulting with experienced developers or professionals can also assist in resolving errors effectively.
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Insertion sort can also be expressed as a recursive procedure as well: In order to sort A[1..n], we recursively sort A[1..n−1] and insert A[n] into the sorted array A[1..n−1]. The pseudocode of an insertion sort algorithm implemented using recursion is as follow: Algorithm: insertionSortR(int [] A, int n) Begin temp ←0 element ←0 if (n≤0) return else temp p←A[n] insertionSort (A,n−1) element ←n−1 while(element >0 AND A[element −1]> temp ) A[ element ]←A[ element −1] element ← element −1 end while A[ element ]← temp End (i) Let T(n) be the running time of the recursively written Insert sort on an array of size n. Write the recurrence equation that describes the running time of insertionSortR(int □A, int n). (10.0 marks) (ii) Solve the recurrence equation T(n) to determine the upper bound complexity of the recursive Insertion sort implemented in part (i). (10.0 marks)
1) Represents the time taken to sort the first n-1 elements recursively, and O(n) represents the time taken to insert the nth element in its correct position in the sorted array.
2) the upper bound complexity of the recursive Insertion sort implemented in part (i) is O(n log n).
(i) The recurrence equation that describes the running time of insertionSortR(int [] A, int n) can be written as:
T(n) = T(n-1) + O(n)
Here, T(n-1) represents the time taken to sort the first n-1 elements recursively, and O(n) represents the time taken to insert the nth element in its correct position in the sorted array.
(ii) To solve the recurrence equation T(n), we can use the recursive tree method.
At the topmost level of the tree, we have only one node corresponding to T(n). At the next level, there are two nodes corresponding to T(n-1) and O(n), respectively. At the level below that, there are four nodes corresponding to T(n-2), O(n-1), O(n-1), and O(n), respectively. This pattern continues until we reach the leaves of the tree, where each leaf corresponds to a single operation O(1).
The tree has a height of n, with each level i containing 2^i nodes. Therefore, the total number of nodes in the tree is 1 + 2 + 4 + ... + 2^n-1 = 2^n - 1.
The total cost of operations at each level i is O(n/i). Therefore, the total cost of all operations in the tree is:
T(n) = (1/n) * Sum(i=1 to n) [i * O(n/i)]
Using the fact that Sum(i=1 to n) i = n*(n+1)/2 and Sum(i=1 to n) 1/i = ln(n) + O(1), we can simplify this expression to:
T(n) = O(n log n)
Therefore, the upper bound complexity of the recursive Insertion sort implemented in part (i) is O(n log n).
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please use C++ language
Input Data Conversion
This will be a separate file from the previous section
• Start with the steps down to creating a main function
• In the main function, create a variable that will hold an int
int userValue;
• Prompt the user to enter a number
• Read the users input into the int variable created above
cin >> userValue;
• Print out the value that the user entered with a newline after
cout << userValue << endl; // May also use cout << userValue << "\n";
Compile and run the program. Test it with the following input. Note what you thought would be the output and what the actual output was:
• Any integer smaller than MAX_INT and greater than MIN_INT
• Any floating point number
Did the output match what you thought? Why do you think that the program output the values it did?
Make the following changes to your program:
• Add a string variable to the main function
• After reading in the int, read into the string variable just created (do not prompt for input)
• Write out the string that was read in
Compile your code, and run the program. Use a floating point number for the value entered when prompted to enter a number. Note the number entered and what the output result was. Does this change what you thought was happening previously?
Putting it together: Infinite data entry
This will be a separate file from the previous sections. Prompt the user to enter a positive number, or a negative number to exit. Keep track of the largest number seen, the total value of all the numbers entered, and the count of the numbers entered. For each number entered, compare it to the current largest number, and if larger, replace the current largest number. Add the number to the total, and increment the count. When the user enters a negative number, output the current largest number and then exit/return. Negative numbers are never added to the total or result in the count being incremented.
Putting it together: Binary conversion
This will be a separate file from the previous sections. For this program you will prompt the user to enter a number, then perform the algorithm below to convert the number to binary, storing each bit as a character in a string. Then output the number that the user entered, and it’s binary conversion.
Algorithm
This algorithm gets the bit positions from right to left (i.e. the least significant bit to the most significant bit).
• Mod the number by 2 (note the result will either be 1 or 0) and store the result as a string in the appropriate position
• Divide the number by 2
• Repeat until the number is 0
In this task, we are working with C++ language and performing various operations.
In the first section, we create a program that prompts the user to enter a number, reads the input, and prints out the entered value. We test it with different inputs, including integers and floating-point numbers, and observe the program's output. The actual output matches our expectations because the program correctly reads and prints the user's input.
Next, we make changes to the program by adding a string variable. After reading the integer input, we also read into the string variable without prompting for input. Then we write out the string that was read in. We compile and run the program, using a floating-point number as the input value. We note the input value and the output result. This change does not affect the previous behavior of reading and printing the integer value. The program still operates correctly and outputs the string without any issues.
In the final sections, we work on two separate programs. In one program, we prompt the user to enter positive numbers or a negative number to exit. We keep track of the largest number seen, the total value of all entered numbers, and the count of entered numbers. We compare each number to the current largest number, update it if necessary, and update the total and count accordingly. When the user enters a negative number, we output the current largest number and exit the program.
In the other program, we prompt the user to enter a number and then convert it to binary using the provided algorithm. We store each bit as a character in a string and output both the original number and its binary conversion.
Overall, these tasks involve input handling, variable manipulation, and conditional logic in C++. We test different scenarios and ensure the programs perform as expected.
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(i) Explain how Amdahl's Law and Gustafson's Law applies to parallel processing. [2 marks] (ii) Why Amdahl's Law appears to put a limit on parallel processing effectiveness. Explain how Gustafson's Law can act as a counter-argument to it. [4 Marks]
(i) Amdahl's Law and Gustafson's Law are two principles that apply to parallel processing. Amdahl's Law focuses on the limit of speedup that can be achieved by parallelizing a program, taking into account the portion of the program that cannot be parallelized. Gustafson's Law, on the other hand, emphasizes scaling the problem size with the available resources to achieve better performance in parallel processing.
(ii) Amdahl's Law appears to limit the effectiveness of parallel processing because it suggests that the overall speedup is limited by the sequential portion of the program. As the number of processors increases, the impact of the sequential portion becomes more significant, limiting the potential speedup. However, Gustafson's Law counters this argument by considering a different perspective. It argues that by scaling the problem size, the relative overhead of the sequential portion decreases, allowing for a larger portion of the program to be parallelized. Therefore, Gustafson's Law suggests that as the problem size grows, the potential for speedup increases, effectively challenging the limitations imposed by Amdahl's Law.
(i) Amdahl's Law states that the overall speedup of a program running on multiple processors is limited by the portion of the program that cannot be parallelized. This law emphasizes the importance of identifying and optimizing the sequential parts of the program to achieve better performance in parallel processing. It provides a formula to calculate the maximum speedup based on the parallel fraction of the program and the number of processors.
(ii) Amdahl's Law appears to put a limit on parallel processing effectiveness because, as the number of processors increases, the impact of the sequential portion on the overall execution time becomes more pronounced. Even if the parallel portion is perfectly scalable, the sequential portion acts as a bottleneck and limits the potential speedup. However, Gustafson's Law challenges this limitation by considering a different perspective. It suggests that by increasing the problem size along with the available resources, the relative overhead of the sequential portion decreases. As a result, a larger portion of the program can be parallelized, leading to better performance. Gustafson's Law focuses on scaling the problem size rather than relying solely on the parallel fraction, offering a counter-argument to the limitations imposed by Amdahl's Law.
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(i) Amdahl's Law and Gustafson's Law are two principles that apply to parallel processing. Amdahl's Law focuses on the limit of speedup that can be achieved by parallelizing a program, taking into account the portion of the program that cannot be parallelized. Gustafson's Law, on the other hand, emphasizes scaling the problem size with the available resources to achieve better performance in parallel processing.
(ii) Amdahl's Law appears to limit the effectiveness of parallel processing because it suggests that the overall speedup is limited by the sequential portion of the program. As the number of processors increases, the impact of the sequential portion becomes more significant, limiting the potential speedup. However, Gustafson's Law counters this argument by considering a different perspective. It argues that by scaling the problem size, the relative overhead of the sequential portion decreases, allowing for a larger portion of the program to be parallelized. Therefore, Gustafson's Law suggests that as the problem size grows, the potential for speedup increases, effectively challenging the limitations imposed by Amdahl's Law.
(i) Amdahl's Law states that the overall speedup of a program running on multiple processors is limited by the portion of the program that cannot be parallelized. This law emphasizes the importance of identifying and optimizing the sequential parts of the program to achieve better performance in parallel processing. It provides a formula to calculate the maximum speedup based on the parallel fraction of the program and the number of processors.
(ii) Amdahl's Law appears to put a limit on parallel processing effectiveness because, as the number of processors increases, the impact of the sequential portion on the overall execution time becomes more pronounced. Even if the parallel portion is perfectly scalable, the sequential portion acts as a bottleneck and limits the potential speedup. However, Gustafson's Law challenges this limitation by considering a different perspective. It suggests that by increasing the problem size along with the available resources, the relative overhead of the sequential portion decreases. As a result, a larger portion of the program can be parallelized, leading to better performance. Gustafson's Law focuses on scaling the problem size rather than relying solely on the parallel fraction, offering a counter-argument to the limitations imposed by Amdahl's Law.
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Assignment 1 - Intro to HTML and JS
Instructions
Write a web application using Node.js that serves the 3 pages listed below.
Home Page.
Stock Listing Page.
Stock Search Page.
The data for this application is provided in the file stocks.js and we have also provided a package.json file for you. Do not change anything in the files stocks.js and package.json. You can use the server.js file provided to you to start your coding. Do not change the value of the variable PORT in server.js. You can also use any code presented in the course modules.
You can choose the names of the static HTML pages and the URLs for the routes however you want with one exception - the static HTML file for the Home Page must be named index.html.
Data Files
stocks.js -
use strict';
const stocks = [
{ company: 'Splunk', symbol: 'SPLK', price: 137.55 },
{ company: 'Microsoft', symbol: 'MSFT', price: 232.04 },
{ company: 'Oracle', symbol: 'ORCL', price: 67.08 },
{ company: 'Snowflake', symbol: 'SNOW', price: 235.8 },
{ company: 'Terradata', symbol: 'TDC', price: 44.98 }
];
module.exports.stocks = stocks;
package.json -
{
"name": "assignment_1",
"version": "1.0.0",
"description": "",
"main": "server.js",
"scripts": {
"test": "echo \"Error: no test specified\" && exit 1",
"start": "node server.js"
},
"author": "",
"license": "ISC",
"dependencies": {
"express": "^4.17.1"
}
}
server.js -
'use strict';
// NOTE: Don't change the port number
const PORT = 3000;
// The variable stocks has the same value as the variable stocks in the file `stocks.js`
const stocks = require('./stocks.js').stocks;
const express = require("express");
const app = express();
app.use(express.urlencoded({
extended: true
}));
// Add your code here
app.listen(PORT, () => {
console.log(`Server listening on port ${PORT}...`);
});
1. Home Page
A GET request for the root URL should return a static HTML page named index.html.
This page must include links to the following 2 pages:
Stock Listing Page
Stock Search Page
In addition to the links, you can optionally add welcome text on this page describing the web application.
2. Stock Listing Page
For this page, create a static HTML file that the displays the following information
An HTML table with the data provided in the file stocks.js, and
A form to order stocks
HTML Table:
Each row in the HTML table must have the following 3 columns
Company name
Stock symbol
Current price
The table must have a header row.
Form to order stocks:
Underneath the HTML table, you must provide inputs for the user to submit a stock order. The following inputs must be provided:
A input element to specify the symbol of the stock to order.
You can choose to use a text element or radio-buttons or a drop-down list for this.
A number element to enter the quantity to buy.
A button to submit the form.
You are free to choose the URL for the action.
You can choose either GET or POST as the method for the form.
After the form is submitted, the Stock Order Response must be displayed.
Stock Order Response
This response must be dynamically generated by the server.
The response must be in HTML and should include a message with the following information:
You placed an order to buy N stocks of CompanyName. The price of one stock is $Y and the total price for this order is $Z.
For example:
You placed an order to buy 10 stocks of Splunk. The price of one stock is $137.55 and the total price for this order is $1375.5.
Note: If a string value is passed to res.send() as an argument, then by default the response body contains it as HTML, which is what is required for Stock Order response.
3. Stock Search Page
This must be a static page with a form that provides two criteria to the user for searching the stock information:
Highest price
Lowest price
The user should be able to choose one of these choices and submit the form.
You are free to choose the URL for the action.
You can choose either GET or POST as the method for the form.
After the form is submitted, the Stock Details Response must be displayed.
Stock Details Response
This response must be a JSON object with all the information corresponding to that stock from the variable stocks.
Note: If a JSON object is passed to res.send() as an argument, then by default the response body contains it as JSON, which is what is required for the Stock Details Response.
When processing the request, your JavaScript code must call a function findStockByPrice(...) which should find the stock with the highest or lowest price (as needed) from among the stocks in the variable stocks.
This function must find the relevant stock "on the fly," i.e., you must not hard-code or permanently store the information about which stock has the highest price and which stock has the lowest price.
What to Turn In?
Submit a single zip file with your code.
The grader will unzip your file, go to the root directory, run npm install and then run npm start to start your application and test it.
The assignment requires the creation of a web application using Node.js that serves three pages: HomePage, StockListing Page, and Stock Search Page. The provided data is in the "stocks.js" file, and a "package.json" file is also given. The JavaScript code should call a function, findStockByPrice(), to find the stock with the highest or lowest price dynamically.
The "server.js" file is provided to start the coding. The instructions are as follows:
1. Home Page:
- A GET request for the root URL should return a static HTML page named "index.html."
- The page must include links to the Stock Listing Page and Stock Search Page.
2. Stock Listing Page:
- Create a static HTML file that displays an HTML table with data from the "stocks.js" file.
- The table should have columns for Company name, Stock symbol, and Current price.
- Include a form for users to order stocks, with inputs for the stock symbol and quantity to buy.
- After submitting the form, display a dynamically generated Stock Order Response in HTML format.
3. Stock Search Page:
- Create a static HTML page with a form allowing users to search for stock information based on highest or lowest price.
- After submitting the form, display a Stock Details Response in JSON format, containing the relevant stock information.
The JavaScript code should call a function, findStockByPrice(), to find the stock with the highest or lowest price dynamically.
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Description of the interface problems of the existing
educational web application of kindergarten students.
An interface refers to a software that is responsible for facilitating the communication between a user and a computer. The interface could take various forms, which include the graphical user interface (GUI) and the command-line interface (CLI).
An interface could be described as an output device that accepts user inputs and provides feedback in response to the input. Therefore, an interface's success or failure is determined by its ability to accept user input and provide the desired feedback. This essay discusses interface problems that existing educational web applications face, with a focus on kindergarten students. Existing educational web applications face several interface problems, which make it difficult for kindergarten students to use the applications. First, the font size is often too small, which makes it difficult for the young children to read the text. The children might strain to read the text, which could lead to eye strain or headaches. Second, the interface often has too many buttons or icons, which can confuse kindergarten students. The students might not understand what each button or icon does, which can lead to frustration. Third, the interface often lacks interactive features, which can make it difficult for kindergarten students to stay engaged. The students might get bored if they cannot interact with the application, which could lead to them losing interest in the learning material. Finally, the interface's color scheme might be too dull or too bright, which can affect the students' moods. The students might become disinterested if the color scheme is too dull or too bright. In conclusion, existing educational web applications face several interface problems, which make it difficult for kindergarten students to use the applications. The problems include small font sizes, too many buttons or icons, lack of interactive features, and inappropriate color schemes. Interface designers must design interfaces that cater to the needs of kindergarten students by considering factors such as font size, color scheme, interactivity, and simplicity. An interface that addresses these factors is more likely to be successful in helping kindergarten students learn.
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Load the "mystery" vector in file myvec.RData on Canvas (using load("myvec.RData"). Note that R allows you to store objects in its own machine-independent binary format instead of a text format such as .csv). Decompose the time series data into trend, seasonal, and random components. Specifically, write R code to do the following: Load the data. [show code] Find the frequency of the seasonal component (Hint: use the autocorrelation plot. You must specify the lag.max parameter in acf() as the default is too small.) [show code and plot] Convert to a ts object [show code] Decompose the ts object. Plot the output showing the trend, seasonal, random components. [show code and plot]
A general explanation of the steps you can follow to decompose a time series data into trend, seasonal, and random components using R.
Load the data: You can load the "mystery" vector from the "myvec.RData" file using the load() function in R. Make sure to provide the correct path to the file.
Find the frequency of the seasonal component: To determine the frequency of the seasonal component in the data, you can use the acf() function to compute the autocorrelation and plot the autocorrelation function (ACF) using the plot() function. Specify a large enough lag.max parameter to ensure sufficient lag values are included in the plot.
Convert to a ts object: Once you have loaded the data, you can convert it to a time series object (ts object) using the ts() function. Specify the appropriate frequency based on the seasonal component you identified in the previous step.
Decompose the ts object: Apply the decomposition function decompose() to the ts object, which separates the time series data into trend, seasonal, and random components. You can then access these components using the $ operator, such as decomposed_data$trend, decomposed_data$seasonal, and decomposed_data$random.
Plot the output: Use the plot() function to display the decomposed components, including the trend, seasonal, and random components.
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How is it possible to modify any sorting algorithm based on comparisons so that it has a "good" best-case running time (ie, Θ(n))? Justify!
By incorporating an initial check for sortedness, we can modify a sorting algorithm to achieve a best-case running time of Θ(n) when the input array is already sorted, which improves the algorithm's efficiency in that particular scenario.
To modify a sorting algorithm based on comparisons to achieve a best-case running time of Θ(n), you can incorporate an additional step that checks if the input array is already sorted. If it is, the algorithm can terminate early without performing any further comparisons or operations.
Here's a general approach:
Start with the original sorting algorithm, such as Quicksort or Mergesort, which typically have an average-case or worst-case running time better than Θ(n^2).
Add an initial check to determine if the input array is already sorted. This can be done by comparing adjacent elements in the array and checking if they are in the correct order.
If the array is already sorted, the algorithm can terminate immediately, as no further comparisons or operations are necessary.
If the array is not sorted, continue with the original sorting algorithm to sort the array using the standard comparison-based operations.
By adding this extra check, the modified sorting algorithm achieves a best-case running time of Θ(n) when the input array is already sorted. In this case, the algorithm avoids any unnecessary comparisons or operations, resulting in optimal efficiency.
However, it's important to note that in the average case or worst case when the input array is not sorted, the modified algorithm still has the same running time as the original algorithm. Therefore, this modification only improves the best-case scenario.
It's worth mentioning that some sorting algorithms, like Insertion Sort and Bubble Sort, already have a best-case running time of Θ(n) when the input array is nearly sorted or already sorted. In these cases, no further modification is needed.
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1. Does a TLB miss always indicate that a page is missing from memory? Explain. 2. Given a virtual memory system with a TLB, a cache, and a page table, assume the following: A TLB hit requires 5ns. A cache hit requires 12ns. A memory reference requires 25ns. A disk reference requires 200ms (this includes updating the page table, cache, and TLB). The TLB hit ratio is 90%. The cache hit rate is 98%. The page fault rate is .001%. On a TLB or cache miss, the time required for access includes a TLB and d/or cache update, but the access is not restarted. On a page fault, the page is fetched from disk, and all updates are performed, but the access is restarted. All references are sequential (no overlap, nothing done in parallel). For each of the following, indicate whether or not it is possible. If it is possible, specify the time required for accessing the requested data. a) TLB hit, cache hit b) TLB miss, page table hit, cache hit c) TLB miss, page table hit, cache miss d) TLB miss, page table miss, cache hit e) TLB miss, page table miss
In a virtual memory system with a TLB (Translation Lookaside Buffer), a cache, and a page table, various access scenarios can occur.
The given scenario provides information about the access times, hit ratios, and rates of different components. We are asked to determine the possibility and time required for accessing data in specific cases, considering TLB hits, TLB misses, page table hits, page table misses, and cache hits or misses.
a) TLB hit, cache hit: It is possible. Since both the TLB and the cache have a hit, the access time would be the sum of the TLB hit time (5ns) and the cache hit time (12ns), which is 17ns.
b) TLB miss, page table hit, cache hit: It is possible. In this case, the TLB misses but the page table has a hit, followed by a cache hit. The total access time would be the sum of the TLB miss time (25ns), the time required for updating the TLB (included in TLB miss time), and the cache hit time (12ns), which is 37ns.
c) TLB miss, page table hit, cache miss: It is possible. With a TLB miss, followed by a page table hit and a cache miss, the total access time would be the sum of the TLB miss time (25ns), the time required for updating the TLB (included in TLB miss time), and the memory reference time (25ns), which is 50ns.
d) TLB miss, page table miss, cache hit: It is not possible. If there is a TLB miss and a page table miss, it indicates that the page is missing from memory, which means there would be a page fault. The access would need to be restarted after fetching the page from disk, so a cache hit cannot be achieved in this scenario.
e) TLB miss, page table miss: It is not possible. Similar to the previous case, a TLB miss followed by a page table miss indicates a missing page in memory. The access would require a page fault, resulting in the page being fetched from disk and all necessary updates performed before the access can be restarted. In this scenario, the cache is not involved.
The possibility and time required for accessing the requested data vary depending on whether there are TLB hits, TLB misses, page table hits, page table misses, and cache hits or misses. The given information about access times, hit ratios, and rates helps determine the access possibilities and the corresponding access times for each case.
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Explain the 7 Layers of OS
The 7 Layers of OS is also known as the OSI (Open Systems Interconnection) model. The seven layers of OS model is: Physical Layer, Data Link Layer, Network Layer, Transport Layer, Session Layer, Presentation Layer, Application Layer.
The 7 Layers of the Open Systems (OS) model represent a conceptual framework that defines the functions and interactions of different components in a networked communication system. Each layer has a specific role and provides services to the layers above and below it.
Physical Layer:
This is the lowest layer of the OSI model and deals with the physical transmission of data over the network. It defines the electrical, mechanical, and physical aspects of the network, including cables, connectors, and signaling.Data Link Layer:
The data link layer provides reliable transmission of data between directly connected nodes. It breaks data into frames, performs error detection and correction, and manages flow control. Ethernet and Wi-Fi protocols operate at this layer.Network Layer:
The network layer is responsible for logical addressing and routing of data packets. It determines the best path for data transmission across different networks using routing protocols. The Internet Protocol (IP) operates at this layer.Transport Layer:
The transport layer ensures reliable, end-to-end communication between hosts. It breaks data into smaller segments, provides error recovery and flow control, and establishes connections. TCP (Transmission Control Protocol) and UDP (User Datagram Protocol) operate at this layer.Session Layer:
The session layer establishes, manages, and terminates connections between applications. It provides mechanisms for session establishment, synchronization, and checkpointing.Presentation Layer:
The presentation layer handles data formatting and ensures compatibility between different systems. It translates, encrypts, and compresses data to be transmitted. It also deals with data representation and manages data syntax conversions.Application Layer:
The application layer is the highest layer and interacts directly with users and applications. It provides network services and protocols for various applications, such as email (SMTP), web browsing (HTTP), file transfer (FTP), and remote login (SSH).These 7 layers of the OSI model provide a modular and hierarchical approach to network communication, allowing for standardized protocols and seamless interoperability between different network devices and systems.
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What is cryptography? Explain transposition cipher with an 5 example
Cryptography is the practice of secure communication in the presence of third parties or adversaries.
Cryptography:
Cryptography has been used for centuries to secure communication in order to keep it private and confidential. Transposition ciphers transposition cipher is a type of cipher that encodes the plaintext by moving the position of letters or groups of letters in the message. In a transposition cipher, the letters or symbols of the plaintext message are rearranged or shuffled according to a system or algorithm to form the ciphertext message. Example 1In a rail fence cipher, the plaintext is written diagonally, alternating between the top and bottom rows. The letters in the ciphertext are then read off in rows. Example 2The columnar transposition cipher involves writing the plaintext out in rows, and then rearranging the order of the rows before reading off the columns vertically.Example 3 The double transposition cipher is a type of transposition cipher that involves two stages of permutation. The plaintext is first written out in a grid and then rearranged in a specific way before being read off in rows or columns. Example 4 The route cipher is a type of transposition cipher that involves writing out the plaintext message along a specific route, and then reading off the message in a specific order.Example 5 The fractionated transposition cipher involves writing out the plaintext message in columns of a specific length, and then rearranging the order of the columns before reading off the rows to form the ciphertext message.
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