Find the value of f(-6).

Answer:

√45^2-27^2

which is 36

hope it helps u dear

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Answer:

x = 12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

-10(x + 9) + 14x = -42

Step 2: Solve for x

Answer: (x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2

Step-by-step explanation: Step by Step Solution

More Icon

STEP

1

:

Equation at the end of step 1

((((((((((((((x-4)•(x-1)•(x+2))•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

2

:

Equation at the end of step 2

(((((((((((((x-4)•(x-1)•(x+2)•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

3

:

Equation at the end of step 3

((((((((((((x-4)•(x-1)•(x+2)•(x+3)•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

4

:

Multiplying Exponential Expressions:

4.1 Multiply (x-4) by (x-4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-4) and the exponents are :

1 , as (x-4) is the same number as (x-4)1

and 1 , as (x-4) is the same number as (x-4)1

The product is therefore, (x-4)(1+1) = (x-4)2

Equation at the end of step

4

:

(((((((((((x-4)2•(x-1)•(x+2)•(x+3)•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

5

:

5.1 Rewrite (1-x) as (-1) • (x-1)

Multiplying Exponential Expressions:

5.2 Multiply (x-1) by (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-1) and the exponents are :

1 , as (x-1) is the same number as (x-1)1

and 1 , as (x-1) is the same number as (x-1)1

The product is therefore, (x-1)(1+1) = (x-1)2

STEP

7

:

Pulling out like terms

7.1 Pull out like factors :

-x - 2 = -1 • (x + 2)

Multiplying Exponential Expressions:

7.2 Multiply (x + 2) by (x + 2)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+2) and the exponents are :

1 , as (x+2) is the same number as (x+2)1

and 1 , as (x+2) is the same number as (x+2)1

The product is therefore, (x+2)(1+1) = (x+2)2

STEP

9

:

Pulling out like terms

9.1 Pull out like factors :

-x - 3 = -1 • (x + 3)

Multiplying Exponential Expressions:

9.2 Multiply (x + 3) by (x + 3)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+3) and the exponents are :

1 , as (x+3) is the same number as (x+3)1

and 1 , as (x+3) is the same number as (x+3)1

The product is therefore, (x+3)(1+1) = (x+3)

((((((((x-4)2•(x-1)2•(x+2)2•-1•(x+3)2•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

10

:

Equation at the end of step 10

(((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

11

:

STEP

12

:

Pulling out like terms

12.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Equation at the end of step

12

:

((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1)•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

13

:

STEP

14

:

Pulling out like terms

14.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Equation at the end of step

14

STEP

15

STEP

16

:

Pulling out like terms

16.1 Pull out like factors :

-x - 4 = -1 •

Equation at the end of step

16

:

STEP

17

:

STEP

18

:

Pulling out like terms

18.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Multiplying Exponential Expressions:

18.2 Multiply (x + 4) by (x + 4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+4) and the exponents are :

1 , as (x+4) is the same number as (x+4)1

and 1 , as (x+4) is the same number as (x+4)1

The product is therefore, (x+4)(1+1) = (x+4)2

Equation at the end of step

18

:

(((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(-x-1)•(2-x)•(3-x)•(x+1))•(2-x))•(x-3)

STEP

19

:

STEP

20

:

Pulling out like terms

20.1 Pull out like factors :

-x - 1 = -1 • (x + 1)

Multiplying Exponential Expressions:

20.2 Multiply (x + 1) by (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+1) and the exponents are :

1 , as (x+1) is the same number as (x+1)1

and 1 , as (x+1) is the same number as (x+1)1

The product is therefore, (x+1)(1+1) = (x+1)2

Equation at the end of step

20

:

((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)•(3-x)•(2-x))•(x-3)

STEP

21

:

21.1 Rewrite (2-x) as (-1) • (x-2)

Multiplying Exponential Expressions:

21.2 Multiply (x-2) by (x-2)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-2) and the exponents are :

1 , as (x-2) is the same number as (x-2)1

and 1 , as (x-2) is the same number as (x-2)1

The product is therefore, (x-2)(1+1) = (x-2)2

22.1 Multiply (x-3) by (x-3)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-3) and the exponents are :

1 , as (x-3) is the same number as (x-3)1

and 1 , as (x-3) is the same number as (x-3)1

The product is therefore, (x-3)(1+1) = (x-3)2

Final result :

(x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2

Answer:

i think y= 6x+4

Step-by-step explanation:

Answer:

Answer Below

Step-by-step explanation:

tan(D): yes

sin(F): yes

Cos(F): no

Sin(D): no

Answer:

tan(D): yes

sin(F): yes

Cos(F): no

Sin(D): no

Step-by-step explanation: Solve for values of all, then check if the equation makes sense.

Answer: 5/13

Step-by-step explanation: Cosine equals adjacent over hypotenuse so adjacent is the side closest to the angle neglecting the hypotenuse of course because that's always the longest side. So Cos=A/H or 5/13

Answer:

Step-by-step explanation:

If we take the below diagram for the given triangles, then ∠B=∠E and ∠A=∠G if AB=GE or if BC=EF, then corresponding angles will be equal.

Therefore, if we rotate the diagram, then also the angles will remain the same.

Answer:

1:1 or one red circle to one blue circle

There is one red and one blue circle

Step-by-step explanation:

y=-4/5x-2-1

y=-4/5x-3

y/4=5x-3

(y/4)-3 =5x

(y-12)/4=5x

The solution for y will be y = -4/5x-3

Numbers, symbols and operators grouped together that show the value of something.

Given an expression, 1+y=-4/5x-2

Solving for y, we get

1+y=-4/5x-2

y = -4/5x-2-1

y = -4/5x-3

Hence, The solution for y will be y = -4/5x-3

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Answer: 13a-6b

Step-by-step explanation:

Answer:

13a - 6b

Step-by-step explanation:

6a + 5a - b - 5b + 2a

~Combine like terms

13a - 6b

Best of Luck!

Answer:

1 divided by 20 is equal to 0.05.

Step-by-step explanation:

In this problem, we need to find 1 divided by 20 is equal to what.

1 should be in the numerator and 20 should be in the denominator.

[tex]\dfrac{1}{20}=\dfrac{1}{2}\times \dfrac{1}{10}\\\\=0.5\times 0.1\\\\=0.05[/tex]

Hence, 1 divided by 20 is equal to 0.05.

Answer:

domain: [0, positive infinity)

range: (negative infinity, positive infinity)

Answer:

5 loaves and 4

Step-by-step explanation:

Answer:

so i think it is rst on the right

Step-by-step explanation:

For y = x², y = 0 when x = 0.

For y = (x + 14)², y = 0 when x = -14.

Notice that the zero of the function has went from 0 to -14, or 14 units to the left.

The answer is "Shift the graph of y = x² left 14 units.".

Answer:

We conclude that the graph y = x² can be transformed into the graph of the given equation y = (x + 14)² by shifting the graph of y = x² left 14 units.

Step-by-step explanation:

Please check the attached graph.

If we carefully analyze the given graph which is attached below, it is clear that the given graph y = (x + 14)² is the transformed image of form f(x+b) of parent graph y = x².

In this graph, the function y = x² has been moved over 14 units to the left.

In other words,

f(x+2) = f(x+14)² means the function f(x) is shifted 14 units to the left.

Therefore, the graph y = x² can be transformed into the graph of the given equation y = (x + 14)² by shifting the graph of y = x² left 14 units.

Answer:

x ≈ 58.9

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Geometry

Step-by-step explanation:

Step 1: Define

We are given a right triangle. We can use trig to find the missing side length.

Step 2: Identify Variables

POV from the angle measure

Angle = 23°

Opposite Leg = 25

Adjacent Leg = x

Step 3: Solve for x

Answer:

Step-by-step explanation:

Expression to show the cost of t teacher tickets and s student tickets:

Answer:

4.79 dollars.

Step-by-step explanation:

7x + 3.62 = 37.15

7x= 37.15-3.62

7x=33.53

x= 33.53/7=4.79 dollars.

Answer:

D.

The range and the IQR will both change.

Step-by-step explanation:

PLATO

The correct answer is C. The IQR will stay the same, but the range will change.

To determine what will happen to the range and the IQR of this data set if the outlier is not included, we first need to identify the outlier.

One way to identify an outlier is to use the 1.5 x IQR rule. According to this rule, any data point that is more than 1.5 times the IQR away from the first or third quartile is considered an outlier.

Using this rule, we can calculate the IQR of the data set:

Arrange the data set in order from smallest to largest:

26 28 29 31 33 33 34 35 36 37 38 39 41 43 60

Find the median, Q₂, of the data set. In this case, Q₂ = 36.

Divide the data set into two halves: the lower half, which includes all values less than or equal to Q₂, and the upper half, which includes all values greater than or equal to Q₂:

Lower half: 26 28 29 31 33 33 34 35

Upper half: 36 37 38 39 41 43 60

Find the median, Q₁, of the lower half. In this case, Q₁= 30.

Find the median, Q₃, of the upper half. In this case, Q₃ = 41.

Calculate the IQR as the difference between Q₃ and Q₁: IQR = Q₃ - Q₁ = 11.

Multiply the IQR by 1.5: 1.5 x 11 = 16.5.

Add 16.5 to Q₃ and subtract 16.5 from Q₁ to get the upper and lower bounds for outliers:

Upper bound: Q₃ + 16.5 = 57.5

Lower bound: Q₁ - 16.5 = 13.5

Any value outside this range is considered an outlier.

In this data set, the value 60 is greater than the upper bound of 57.5, so it is an outlier.

Therefore, the correct answer is C. The IQR will stay the same, but the range will change.

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Answer:

(2) is equal to 48 because you substitute x for 2 in the equation.  F(2)= -3(2)^2 +12= -3 times 2 is -6 then you square it to get 36 and add 12 to get 48

Step-by-step explanation:

Answer:

On the X-asis

Tell me if I am wrong. :) Hope it helps though.

Step-by-step explanation:

Answer:

in quadrant ii (-8,0) located

Answer:

8 post cards

Step-by-step explanation:

Eight

Answer:

15

Step-by-step explanation:

3+2=5

5x3=15

Answer:

21,000

Step-by-step explanation:

Answer:

sup

Step-by-step explanation:

Answer:

SRT

Step-by-step explanation:

Answer:

obtuse angle

Step-by-step explanation:

a L is a right angle, a right angle is 90 degrees.  if the angle is more then 90 degrees and looks like its being stretched it is obtuse. and if it is smaller then 90% and looks like it is being squashed it an acute angle.

Answer:

x=25

Step-by-step explanation:

(x+40)+(3x+10)=6x

4x+50=6x

50=2x

25=x

Answer:

see explanation

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ CBD is an exterior angle of the triangle, then

6x = x + 40 + 3x + 10, that is

6x = 4x + 50 ( subtract 4x from both sides )

2x = 50 ( divide both sides by 2 )

x = 25

Thus

∠ CBD = 6x = 6 × 25 = 150°

∠ CBA and ∠ CBD are adjacent angles and supplementary, sum to 180°, then

150° + ∠ CBA = 180° ( subtract 150° from both sides )

∠ CBA = 30°

answer is idk because it is a half