Formic acid has a Ka of 1.77*10-4. To 55.0 mL of 0.25 M solution 75.0 of 0.12 M NaOH is added . What is the resulting pH.

Answers

Answer 1

Answer:

To solve this problem, we first need to write the balanced chemical equation for the reaction between formic acid (HCOOH) and sodium hydroxide (NaOH): HCOOH + NaOH → NaCOOH + H2O From the equation, we can see that 1 mole of HCOOH reacts with 1 mole of NaOH to produce 1 mole of NaCOOH and 1 mole of H2O. Therefore, the number of moles of NaOH added can be calculated as follows: moles of NaOH = concentration × volume = 0.12 M × 0.075 L = 0.009 mol Since the reaction is a neutralization reaction, the number of moles of HCOOH initially present can be calculated as follows: moles of HCOOH = concentration × volume = 0.25 M ×

Answer 2

Answer:

4.88

Explanation:

Formic acid is a weak acid and its dissociation can be represented by the equation: HCOOH ⇌ H+ + HCOO-. The acid dissociation constant (Ka) for this reaction is 1.77*10^-4. When NaOH is added to the solution, it will react with the formic acid to produce its conjugate base (formate ion) and water. This reaction can be represented by the equation: HCOOH + OH- → HCOO- + H2O.

To calculate the resulting pH, we need to determine the number of moles of formic acid and NaOH present in the solution. The number of moles of formic acid can be calculated by multiplying its molarity by its volume in liters: 0.25 M * 0.055 L = 0.01375 moles. Similarly, the number of moles of NaOH can be calculated as: 0.12 M * 0.075 L = 0.009 moles.

Since NaOH is a strong base, it will react completely with formic acid to produce formate ions and water. This means that 0.009 moles of formic acid will react with 0.009 moles of NaOH to produce 0.009 moles of formate ions and water.

After the reaction, there will be 0.01375 - 0.009 = 0.00475 moles of formic acid left in the solution and 0.009 moles of formate ion produced.

The total volume of the solution after adding NaOH is 55 mL + 75 mL = 130 mL or 0.13 L.

We can now use an ICE table to calculate the equilibrium concentrations of all species present in the solution:

(ICE table Picture attached below)

Substituting these values into the expression for Ka and solving for x gives us:

Ka = [H+][HCOO-]/[HCOOH] = x(0.009/0.13 + x)/(0.00475/0.13 - x) = 1.77*10^-4

Solving this quadratic equation gives us x = [H+] = 1.33*10^-5 M.

The pH of the solution can now be calculated as pH = -log[H+] = -log(1.33*10^-5) = 4.88.

So, the resulting pH after adding NaOH to the formic acid solution is 4.88.

Formic Acid Has A Ka Of 1.77*10-4. To 55.0 ML Of 0.25 M Solution 75.0 Of 0.12 M NaOH Is Added . What

Related Questions

In order to produce an electric current in a coil of wire, a magnetic field through the coil must be

A) positive
B) moving
C) negative
D) neutralized

Answers

B) Moving.

To produce an electric current in a coil of wire, a magnetic field through the coil must be moving or changing. This is due to the phenomenon of electromagnetic induction, discovered by Michael Faraday in the early 19th century. When a magnetic field moves or changes relative to a coil of wire, it induces an electric current in the wire. This is the principle behind electric generators, which convert mechanical energy into electrical energy by rotating a coil of wire in a magnetic field. In contrast, a static magnetic field alone will not induce an electric current in a coil of wire.

Formic acid has a Ka of 1.77*10^-4. To 55.0 mL of 0.25 M solution 75.0 of 0.12 M NaOH is added . What is the resulting pH.

Answers

Answer:

The first step is to determine the moles of formic acid and NaOH that react. moles of formic acid = (0.25 mol/L) x (0.055 L) = 0.01375 mol moles of NaOH = (0.12 mol/L) x (0.075 L) = 0.009 mol Since NaOH is a strong base, it will react completely with formic acid to form sodium formate and water: HCOOH + NaOH → HCOONa + H2O The limiting reagent in this case is NaOH, so all of it will be consumed in the reaction. The amount of excess formic acid that remains can be calculated: moles of HCOOH remaining = moles of HCOOH initial - moles of NaOH used moles of HCOOH

Arif decided to make a model of the global wind patterns on Earth. He draws arrows of the global winds that move in a circular pattern from the equator to the poles and back again. Explain what causes global winds to form. Why do they move in convection currents around Earth?

Answers

Global winds form due to differential heating of the Earth's surface by the sun, creating convection currents in the atmosphere, which are influenced by the rotation of the Earth, resulting in circular wind patterns around the planet.

What causes global winds to form and why do they move in convection currents around Earth?

Global winds are caused by the differential heating of the Earth's surface by the sun. The sun heats the Earth's surface unevenly due to the varying angles of incidence of the sun's rays and the Earth's curvature. The equator receives more direct sunlight than the poles, which creates a temperature difference between these regions. This temperature difference causes the air to move from the equator to the poles, creating convection currents in the atmosphere.

These convection currents create global wind patterns that move in a circular pattern from the equator to the poles and back again. As the warm air rises near the equator, it moves towards the poles, where it cools and sinks back down to the surface. The cooler air near the poles then moves towards the equator to replace the rising warm air.

These wind patterns are also influenced by the rotation of the Earth, which causes the Coriolis effect. The Coriolis effect causes  wind to deflect to the right in the Northern-Hemisphere and to the far left in the Southern-Hemisphere.This deflection results in the formation of the trade winds, westerlies, and polar easterlies that are part of the global wind patterns.

In summary, the differential heating of the Earth's surface by the sun causes convection currents in the atmosphere, which create the global wind patterns. The rotation of the Earth influences these wind patterns, resulting in the formation of the trade winds, westerlies, and polar easterlies that move in a circular pattern from the equator to the poles and back again.

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How many grams of aluminum will react fully with 1.25 moles Cl2? 2A1+ 3Cl₂ → 2AICI3 [?] g Al Mass Al (g)​

Answers

22.49 grams of aluminum will react fully with 1.25 moles of [tex]Cl_{2}[/tex].

What is Moles?

Moles is a unit of measurement used in chemistry to express the amount of a substance. One mole of a substance is defined as the amount of that substance that contains the same number of particles (atoms, molecules, or ions) as there are atoms in 12 grams of carbon-12.

To determine the mass of aluminum that will react fully with 1.25 moles of [tex]Cl_{2}[/tex], we need to use the stoichiometry of the balanced chemical equation.

From the balanced chemical equation:

2 Al + 3 [tex]Cl_{2}[/tex] → 2 Al[tex]Cl_{3}[/tex]

we can see that 2 moles of Al react with 3 moles of [tex]Cl_{2}[/tex] to produce 2 moles of Al[tex]Cl_{3}[/tex]. Therefore, the mole ratio of Al to [tex]Cl_{2}[/tex] is 2:3.

To calculate the amount of Al required to react with 1.25 moles of [tex]Cl_{2}[/tex], we can set up the following proportion:

2 moles Al / 3 moles [tex]Cl_{2}[/tex] = x moles Al / 1.25 moles [tex]Cl_{2}[/tex]

where x is the number of moles of Al required.

Solving for x, we get:

x = (2/3) * 1.25 = 0.8333 moles Al

Finally, we can use the molar mass of aluminum to convert moles to grams:

mass of Al = number of moles of Al * molar mass of Al

mass of Al = 0.8333 mol * 26.98 g/mol

mass of Al = 22.49 g

Therefore, 22.49 grams of aluminum will react fully with 1.25 moles of C[tex]Cl_{2}[/tex].

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Pls help me in this question in chemistry parts 6_10_11_13

Answers

Answer:

i am adding solution with attachment

Explanation:

fill in the blanks
water is a......

Answers

Water is a tiny molecule.

it consists of three atoms : two of hydrogen and one of oxygen. Water molecules cling to each other because of a force called hydrogen bonding.

Water is a compound that is composed of two hydrogen atoms and one oxygen atom.

how many moles of carbon atoms are there in 0.388 mole of c2h6?

Answers

In C2H6, there are 2 carbon atoms per molecule. Therefore, the number of moles of carbon atoms can be found by multiplying the number of moles of C2H6 by the number of carbon atoms per molecule.

Number of moles of carbon atoms = Number of moles of C2H6 x (2 moles of C / 1 mole of C2H6)

Number of moles of carbon atoms = 0.388 mole x (2 moles of C / 1 mole of C2H6)

Number of moles of carbon atoms = 0.776 moles

Therefore, there are 0.776 moles of carbon atoms in 0.388 mole of C2H6.

The chemical formula for C2H6 tells us that there are two carbon atoms in each molecule of ethane. Therefore, to find the number of moles of carbon atoms in 0.388 moles of C2H6, we can use the following steps:

1. Determine the total number of moles of carbon atoms in 0.388 moles of C2H6 by multiplying the number of moles of C2H6 by the number of carbon atoms per molecule:

0.388 moles C2H6 x 2 moles C / 1 mole C2H6 = 0.776 moles C

2. Round the result to the appropriate number of significant figures, if necessary.

Therefore, there are 0.776 moles of carbon atoms in 0.388 moles of C2H

Which of the following would BEST describe an acid with a pH of 1?

Answers

Since it has a large concentration of hydrogen ions (H+) and a low concentration of hydroxide ions, an acid with a pH of 1 would be categorised as a strong acid. (OH-).

Is a pH of one corrosive strong?

At the kinds of amounts you typically use in the lab, strong acids like hydrochloric acid have a pH between 0 and 1. At a quantity of 38%, hydrochloric acid (HCL) has a pH value of 1.1.

What is HCl's pH?

Muriatic acid is another name for hydrochloric acid. It has an unpleasant scent and is colorless. As an acidifying substance, it is employed. Since it is a powerful acid, its pH will be lower than 7. There is a pH spectrum of 1.5 to 3.5.

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Which of the following choices is an example of an Everglade species adaptation?
Alligators dig large holes in the mud that retain water during the dry season.
Zebras have striped colorations that help them hide from predators in the grasses.
Raccoons steal eggs from birds’ nests.
All of these choices are correct.

Answers

The example of an Everglade species adaptation among the given choices is: Alligators dig large holes in the mud that retain water during the dry season.

What are the alligators?

Alligators in the Everglades have adapted to survive the dry season by digging "gator holes" which are large depressions in the mud that retain water. These gator holes provide the alligators with a habitat to survive during the dry season and are also important for other species in the ecosystem. Other species such as fish, turtles, and wading birds also use these gator holes as a source of water during the dry season.

Zebras having striped colorations that help them hide from predators in the grasses is an example of an adaptation seen in savanna ecosystems. Raccoons stealing eggs from bird's nests is an example of behavior, but not an adaptation specific to the Everglades ecosystem. Therefore, the correct answer is: Only the first choice is an example of an Everglade species adaptation.

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Complete question is: The example of an Everglade species adaptation among the given choices is: Alligators dig large holes in the mud that retain water during the dry season.

I NEED ASAPPP

How many moles of bromine gas would occupy a volume of 20 L at a pressure of .90 atm and a temperature of 90°C? Show all work.
R= 8.31 L kPa/K mol
1 atm=101.3kPa

Answers

0.0652 moles of bromine gas would occupy a volume of 20 L at a pressure of 0.90 atm and a temperature of 90°C.

To solve this problem, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15:

T = 90°C + 273.15 = 363.15 K

Next, we need to convert the pressure from atm to kPa:

0.90 atm x 101.3 kPa/atm = 91.17 kPa

Now we can plug in the values we have:

n = (PV) / (RT)

n = (91.17 kPa x 20 L) / (8.31 L kPa/K mol x 363.15 K)

n = 0.0652 mol.

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A solution has a volume of 250 mL and has the molarity of 2.4 M NaCl. How many moles of NaCl are in the solution?

Answers

There are 0.6 moles of sodium chloride in a 250 mL solution with a molarity of 2.4 M sodium chloride.

In 250 mL of a 0.5 M NaCl solution, how many moles of sodium chloride are there?

This leads us to the conclusion that a 250 mL solution of a 0.5 M sodium chloride contains 0.125 moles and 7.32 grammes of sodium chloride, respectively.

250 mL of a 0.4 M solution contains how many moles of sodium chloride?

A solution with a concentration of 0.4 M contains 0.4 moles of solute per litre of solution. By utilising dimensional analysis, you may calculate how many moles of solute are present in 250 mL of the solution. litre and millilitre units

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Coal is mined from several locations in the US, such as the San Juan Basin of northwestern New Mexico. This fossil fuel formed
A.
from the burial and decomposition of plant material.
B.
as a product of photosynthesis.
C.
as a byproduct of landfill waste.
D.
from molten rock deep in the Earth's interior.

Answers

Answer:  A from the burial and decomposition of plant material.

Explanation:

Gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (CH4) and oxygen gas

Answers

The reaction requires a stoichiometric ratio of [tex]2:4[/tex] for carbon monoxide to hydrogen gas, resulting in the formation of methane and oxygen gas as products.

What is the balanced chemical equation?

The balanced chemical equation for the reaction between gaseous carbon monoxide  [tex](CO)[/tex] and hydrogen gas [tex](H_2)[/tex] to form gaseous methane [tex](CH_4)[/tex] and oxygen gas  [tex](O_2)[/tex]  is:

[tex]2CO(g) + 4H2(g) \rightarrow CH4(g) + O2(g)[/tex]

In this equation, [tex]2[/tex]  moles of carbon monoxide react with  [tex]4[/tex] moles of hydrogen gas to produce 1 mole of methane and  [tex]1[/tex] mole of oxygen gas.

Therefore, The reaction requires a stoichiometric ratio of [tex]2:4[/tex] for carbon monoxide to hydrogen gas, resulting in the formation of methane and oxygen gas as products.

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What would be the destiny (in g/L) of a sample of C2H2Cl2 gas at 70.0C and 2.50 atm of pressure

Answers

The density of the gas would be 9.01 g/L.

To calculate the density (in g/L) of a gas, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

To solve for n/V (the number of moles of gas per unit volume), we can rearrange the ideal gas law:

n/V = P/RT

The density (in g/L) is then equal to the molar mass (in g/mol) times n/V:

density = (molar mass) * (n/V)

The molar mass of C₂H₂Cl₂ is:

2(12.01 g/mol) + 2(1.01 g/mol) + 2(35.45 g/mol) = 96.93 g/mol

To use the ideal gas law, we need to convert the temperature to Kelvin:

70.0C + 273.15 = 343.15 K

Plugging in the values:

P = 2.50 atm

V = unknown (we are not given the volume)

n/V = P/RT = 2.50 atm / (0.08206 Latm/(molK) * 343.15 K) = 0.0930 mol/L

molar mass = 96.93 g/mol

Therefore, the density of the C₂H₂Cl₂ gas at 70.0C and 2.50 atm of pressure is:

density = (molar mass) * (n/V) = 96.93 g/mol * 0.0930 mol/L = 9.01 g/L.

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Problem 1,: 500 mL of a 0.500 M solution of NaOH is titrated with a 2 M acid solution. How much acid is needed to reach its titration end-point?

Problem 2: It takes 20.0mL of 4.00M NaOH to neutralize 5.00 mL of HCL solution. What is the concentration of the HCl solution?

Problem 3: 60. mL of a 1.0 M solution of H2SO4 has titrated to it endpoint with 1 L of a basic solution. What is the molarity of the base?

Problem 4: If I add acid to 100 mL of a 0.15 M NaOH solution until it is titrated with 150 mL of acid, what will the molarity of the acid solution be?

(Last Question I swear-)

Answers

Problem 1:

The balanced chemical equation for the reaction between NaOH and the acid is:

NaOH + HX → NaX + H2O

where X represents the acid.

The stoichiometry of the reaction shows that one mole of NaOH reacts with one mole of the acid. Thus, the number of moles of acid required can be calculated as follows:

Moles of NaOH = volume (in L) x concentration (in M)

Moles of NaOH = 500 mL x (1 L/1000 mL) x 0.500 M

Moles of NaOH = 0.250 moles

Since the number of moles of the acid required is the same as the number of moles of NaOH, the amount of acid needed to reach the end-point is:

Moles of acid = 0.250 moles

The volume of the acid required can be calculated using its concentration:

Moles of acid = volume (in L) x concentration (in M)

0.250 moles = volume (in L) x 2 M

Volume of acid = 0.125 L or 125 mL

Therefore, 125 mL of the 2 M acid solution is required to reach the titration end-point.

Problem 2:

The balanced chemical equation for the reaction between NaOH and HCl is:

NaOH + HCl → NaCl + H2O

The stoichiometry of the reaction shows that one mole of NaOH reacts with one mole of HCl. Thus, the number of moles of NaOH used in the titration can be calculated as:

Moles of NaOH = volume (in L) x concentration (in M)

Moles of NaOH = 20.0 mL x (1 L/1000 mL) x 4.00 M

Moles of NaOH = 0.080 moles

Since one mole of NaOH reacts with one mole of HCl, the number of moles of HCl present in the 5.00 mL sample can be calculated as:

Moles of HCl = Moles of NaOH

Moles of HCl = 0.080 moles

The concentration of the HCl solution can be calculated as follows:

Concentration of HCl = moles/volume (in L)

Concentration of HCl = 0.080 moles/(5.00 mL x 1 L/1000 mL)

Concentration of HCl = 16.0 M

Therefore, the concentration of the HCl solution is 16.0 M.

Problem 3:

The balanced chemical equation for the reaction between H2SO4 and the base is:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

The stoichiometry of the reaction shows that one mole of H2SO4 reacts with two moles of NaOH. Thus, the number of moles of NaOH used in the titration can be calculated as:

Moles of NaOH = volume (in L) x concentration (in M)

Moles of NaOH = 1.00 L x 1.0 M

Moles of NaOH = 1.0 moles

Since two moles of NaOH react with one mole of H2SO4, the number of moles of H2SO4 present in the solution is:

Moles of H2SO4 = 0.5 moles

The molarity of the base can be calculated as follows:

Molarity of base = moles/volume (in L)

Molarity of base = 0.5 moles/0.060 L

Molarity of base = 8.33 M

If you start with 1.953 g of salicylic acid what is the theoretical yield of aspirin?​

Answers

To calculate the theoretical yield of aspirin, we need to know the balanced equation for the reaction between salicylic acid and acetic anhydride, which is:

salicylic acid + acetic anhydride → aspirin + acetic acid

The balanced equation tells us that one mole of salicylic acid reacts with one mole of acetic anhydride to produce one mole of aspirin and one mole of acetic acid.

The molar mass of salicylic acid is 138.12 g/mol, so 1.953 g is equal to:

1.953 g / 138.12 g/mol = 0.01414 mol salicylic acid

According to the balanced equation, one mole of salicylic acid produces one mole of aspirin. The molar mass of aspirin is 180.16 g/mol, so the theoretical yield of aspirin is:

0.01414 mol aspirin × 180.16 g/mol = 2.55 g aspirin

Therefore, the theoretical yield of aspirin from 1.953 g of salicylic acid is 2.55 g.

What is an acid ?

An acid is a chemical compound or substance that can donate hydrogen ions (H+) or accept electrons in chemical reactions, or a substance that can lower the pH of a solution by releasing H+ ions. Acids have a sour taste and can react with bases to form salts. They are commonly used in industries such as food, pharmaceuticals, and chemical manufacturing. Examples of common acids include hydrochloric acid, sulfuric acid, and acetic acid.

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Can to you do this for me please

Answers

Answer: It is homozygous recessive for blue eyes.

Explanation: If an individual has blue eyes, it means that they must have received two recessive alleles for eye color (bb) – one from each parent. Therefore, the genotype of an individual with blue eyes is homozygous recessive for blue eyes.

how electrons remain in pairs form however they contain similar charge

Answers

The charge of electrons is determined by their spin, which is either up or down and the same spin will repel each other due to their negative charge, while electrons with opposite spins will attract each other.

Electrons are negatively charged particles and exist in pairs because of the Pauli Exclusion Principle, which states that no two electrons in an atom can have the same set of quantum numbers. This means that if two electrons are in the same atom, they must have different energy levels, angular momenta, and magnetic moments. This prevents the electrons from occupying the same space and prevents them from having the same charge. As a result, electrons remain in pairs, even though they have the same charge.

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B. Imagine that the food coloring is a type of atom. Based on your observations, how does the concept of Brownian motion help to explain what you observed?​

Answers

Answer:

observed?Brownian motion is the random movement of particles suspended in a fluid due to collisions with other molecules in the fluid. In this case, the food coloring molecules are suspended in the water, which is a fluid, and the random movement of the water molecules causes the food coloring molecules to move around in a random pattern. This movement is similar to the movement of atoms in a gas or liquid, which is also driven by Brownian motion. So, the concept of Brownian motion helps to explain the random movement of the food coloring molecules in the water, as observed in the experiment.

calculate molarity of 8×10^-3 moles of HCl dissolved in 25cm³ of water.​

Answers

[tex]Molarity = \frac{Moles(solute)}{Volume(solution)}[/tex]

Volume = 25cm³ = 25mL = 0.025 LMolarity = 8x10⁻³/0.025Molarity = 0.32M

    ★    I hope it helps you :)........

We wish to
determine how
many moles of
barium sulfate
form when 50.0
mL of 0.250 M
aluminum
mol Al₂(SO),
Resources
sulfate reacts
with excess
barium nitrate.
3Ba(NO3)2(aq) + Al₂(SO4)3(aq)
How many
moles of
Al₂(SO4)3 are
present
in 50.0 mL of
0.250 M
Al₂(SO4)3?
Enter
Help

Answers

To determine the number of moles of Al₂(SO₄)₃ present in 50.0 mL of 0.250 M Al₂(SO₄)₃, we need to use the formula relating molarity to moles and volume.

What is a mole and how do you calculate the moles of Al₂(SO₄)₃  present?

In chemistry, a mole is a unit of measurement used to show the measure of a chemical entity. One mole of a substance is defined as the amount of that substance that contains the same number of particles, such as atoms, molecules, or ions, as there are atoms in exactly 12 grams of carbon-12.

To determine the number of moles of Al₂(SO₄)₃  present in 50.0 mL of 0.250 M Al₂(SO₄)₃ , we need to use the formula:

Molarity (M) = moles (n) / volume (V)

Rearranging the formula, we get:

n= M*V

First, let's convert the volume of 50.0 mL to liters:

50.0 mL = 50.0 x 10⁻³ L

Next, we can substitute the given values into the formula:

moles of Al₂(SO₄)₃  = 0.250 M x 50.0 x 10⁻³ L

moles of Al₂(SO₄)₃  = 0.0125 mol

Therefore, there are 0.0125 moles of Al₂(SO₄)₃  present in 50.0 mL of 0.250 M Al₂(SO₄)₃.

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why does electrolysis in aqueous solution of sodium chloride does not produce sodium as it's cathode ​

Answers

Because water is more quickly reduced than Na+ ions, the sodium metal that results from the electrolysis of aqueous NaCl is replaced at the cathode by hydrogen gas.

Why does sodium not evolve at the cathode during electrolysis of aqueous sodium chloride?

The positively charged salt in NaCl tends to travel towards the negatively charged substance in accordance with the law of attraction. Because the anode acts as a negatively charged diode during electrolysis, sodium moves towards the anode rather than the cathode.

Why does sodium chloride electrolysis fail to yield metallic sodium?

When sodium is created, it immediately interacts with water molecules to create sodium hydroxide. You will therefore receive aqueous solution of sodium hydroxide and hydrogen gas rather than pure sodium metal.

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hybridization and it's effects​

Answers

Explanation:

hybridization refers to the process of mixing atomic orbitals in a way that creates new hybrid orbitals. This is commonly observed in organic chemistry, where hybridization is used to explain the shapes and bonding properties of molecules.

The hybridization of atomic orbitals occurs when atoms bond to form molecules. In the hybridization process, the valence electrons of an atom are rearranged and redistributed in order to form new orbitals with different shapes and energies. This can result in stronger and more stable bonding between atoms.

The most common types of hybridization are sp, sp2, and sp3, which involve the mixing of s and p orbitals. For example, in the sp3 hybridization of carbon, the 2s orbital and three 2p orbitals are combined to form four sp3 hybrid orbitals, which are arranged in a tetrahedral shape.

The effects of hybridization in chemistry include changes in the bond angles, bond lengths, and overall shape of molecules. This can affect the reactivity and chemical properties of the molecule, such as its acidity or basicity.

Mrs. B sets up two beakers that contain the same amount of water. She has two blocks of different materials that she labels "A" and "B." She places one block in each beaker. Block A sinks and Block B floats. Why?​

Answers

The reason why Block A sinks while Block B floats is due to their relative densities.

What is density?

Density is defined as the mass of an object per unit volume, and it determines whether an object will float or sink in a fluid.

Block A must have a higher density than the water, causing it to sink. In contrast, Block B must have a lower density than the water, causing it to float.

Density can be calculated by dividing the mass of an object by its volume. Therefore, to determine why one block has a higher density than the other, we need to know their masses and volumes.

It's possible that Block A is made of a denser material such as iron, while Block B is made of a less dense material such as wood or plastic. Alternatively, it could be that Block A has a greater volume than Block B, or that Block B has a hollow space inside that reduces its overall density.

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Complete question is: Mrs. B sets up two beakers that contain the same amount of water. She has two blocks of different materials that she labels "A" and "B." She places one block in each beaker. Block A sinks and Block B floats. The reason why Block A sinks while Block B floats is due to their relative densities.

How many grams of O2 will forms when 4.6 molesof lead II oxide decomposes?

Answers

The correct answer is To answer this question, we need to use the balanced chemical equation for the decomposition of lead(II) oxide (PbO).

[tex]PbO(s) → Pb(s) + O2(g)[/tex]From this equation, we can see that for every 1 mole of PbO that decomposes, 1 mole of O2 is produced. Therefore, we can use the given number of moles of PbO to determine the number of moles of O2 produced, and then convert to grams using the molar mass of O2 We are given 4.6 moles of PbO, so we can calculate the moles of O2 produced as follows: moles of O2 = moles of PbO moles of O2 = 4.6 moles Now, we can use the molar mass of O2 to convert from moles to grams: mass of O2 = moles of O2 x molar mass of O2 mass of O2 = 4.6 moles x 32.00 g/mol mass of O2 = 147.2 g Therefore, when 4.6 moles of PbO decompose, 147.2 grams of O2 are produced. It's important to note that the given reaction assumes that the lead(II) oxide decomposes completely, meaning that all of the PbO is converted to Pb and O2. In reality, some of the PbO may not decompose completely, and other side reactions may occur. However, assuming complete decomposition, the calculated mass of O2 represents the theoretical yield of the reaction.

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Question
A bird is soaring at a constant height above the ground.

Which statement best explains this observation?

Responses

A:The force of gravity does not apply to objects above the surface

:B The bird is light enough so that it is not affected by gravitvt

C :The flapping of a bird's wings allows gravity to pass through its body.


D :The upward force on the bird is balanced by the downward force of gravity.

Answers

D - the wings are providing upward thrust to counteract gravity.

Analyse the step-by-step of guiding students on how to write balanced chemical equations and ionic equation​

Answers

Here is a step-by-step guide for guiding students on how to write balanced chemical equations and ionic equations:

Steps:

1. Determine the reactants and products: Start by identifying the reactants and products in the chemical reaction. This involves reading the problem and identifying the substances that are being reacted.

2. Write the unbalanced equation: Once the reactants and products have been identified, write the unbalanced chemical equation using the chemical formulas for each reactant and product.

3. Balance the equation: To balance the equation, adjust the coefficients of the reactants and products so that the number of atoms of each element is equal on both sides of the equation. Begin by balancing the atoms of elements that appear only once on each side of the equation, and then move on to elements that appear more than once.

4. Check the balanced equation: After balancing the equation, double-check to make sure that the number of atoms of each element is the same on both sides of the equation.

5. Write the ionic equation: To write the ionic equation, break apart any soluble ionic compounds into their individual ions. Then, cancel out any spectator ions that appear on both sides of the equation.

6. Check the ionic equation: Double-check the ionic equation to make sure that the same number and type of ions appear on both sides of the equation.

7. (Optional) Include states of matter: It is common practice to include the states of matter (solid, liquid, gas, aqueous) of the reactants and products in the chemical equation. This can be done by using abbreviations in parentheses after each chemical formula.

By following these steps, students can learn how to write balanced chemical equations and ionic equations accurately and efficiently.

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What is the molarity of 30.0 mL of hydrochloric acid solution after 15.0 mL of a 3.00 M solution has been diluted?
___ M (Answer Format X.X)

Answers

Answer:

the resulting solution is 1.5 M.

Explanation:

To solve this problem, we can use the dilution formula:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

We are given that 15.0 mL of a 3.00 M hydrochloric acid solution has been diluted, and we want to find the molarity of the resulting solution. Let's use M1 for the initial concentration, V1 for the initial volume, M2 for the final concentration, and V2 for the final volume.

M1 = 3.00 M

V1 = 15.0 mL

V2 = 30.0 mL (since 15.0 mL has been diluted to 30.0 mL, the final volume is 30.0 mL)

We can rearrange the dilution formula to solve for M2:

M2 = (M1V1) / V2

Substituting the given values, we get:

M2 = (3.00 M x 15.0 mL) / 30.0 mL

M2 = 1.50 M

Therefore, the molarity of the resulting solution is 1.5 M.

ENTHALPHY LAB QUESTIONS!!


PURPOSE OF EXPERIMENT: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid.


Experiment 1 Procedure:

1. Measure 50.0 mL of water (tap) into a 100 mL graduated cylinder and pour it into a large coffee cup.

2. Determine the temperature of this water

3. Measure out 2.00 g of sodium hydroxide into a piece of paper towel *tare scale!

4. Add the sodium hydroxide to the water in the coffee cup and put a small cup over it, with the thermometer through the hole. Stir GENTLY with the thermometer and record the temperature every 30 seconds for 3 minutes or until it peaks. Record this in a properly labelled table.

5. Let this stand for 45 minutes before proceeding to Exp. 2.


WHAT WE FOUND IN EXP 1:

T (temp.) initial = 20 degrees C

T (temp) FINAL = 28.5 degrees C

moles of sodium hydroxide = 0.0518mol

the molar mass of sodium hydroxide = 39.969g/mol

C (specific heat of water) = 4.184J/g degrees C


THE NUMBER OF TRIALS FOR TEMP IN EXP 1

1st trial = 21 C

2nd trial = 24.5 C

3rd trial = 26 C

4th trial = 26 C

5th trial = 28 C

6th trial = 28.5 C

7th trial = 28.5 C (final temp)


ANALYSIS FOR EXPERIMENT ONE:

1. Determine the moles of sodium hydroxide (NaOH) from the experiment.

2. Determine Qsurroundings and Qrxn

3. Determine the enthalpy for the dissociation of sodium hydroxide (delta H sol)

4. Write the thermochemical equation for the dissociation of sodium hydroxide TWO ways and write an enthalpy diagram

5. What assumptions did you make to calculate #2? (some example assumptions to make: assume that the solution is water and that heat and density COULD be the same as water, etc)

6. Research the actual value and determine the percent error

7. In terms of bonds breaking and forming, what is RESPONSIBLE FOR ENTHALPY CHANGE?


EXPERIMENT 2 PROCEDURE:

1. Measure out 50.0 mL of 0.75 concentration M HCl into a graduated cylinder

2. Measure and record the temperature of the sodium hydroxide solution from exp. 1.

3. Add the hydrochloric acid solution to the sodium hydroxide solution, put the small cup on, and record the temperature change every 15 seconds for 1 minute. Stir GENTLY. Record this in a properly labelled table (will be given below)

4. Solutions can be discarded down the sink.


WHAT WE FOUND IN EXP. 2:

T (temp) initial = 23.5 C

T (temp) FINAL = 27 C


THE NUMBER OF TRIALS FOR TEMP IN EXP 2

1st trial = 27 C

2nd trial = 27 C

3rd trial = 27 C

4th trial = 27 C (FINAL TEMP)


ANALYSIS FOR EXPERIMENT 2:

1. Determine the moles of HCl added to this mixture

2. Write the chemical equation for this reaction

3. Determine the limiting reagent

4. Determine the Qsurr and Qrxn *CONVERT TO kJ*

5. Determine the enthalpy for the neutralization reaction.

6. Write the thermochemical equation for the dissociation of sodium hydroxide TWO WAYS and write an enthalpy diagram

7. Research the actual value and determine the percent error.

8 Explain sources of experimental error for both experiments and BE SPECIFIC! (NOT CALCULATION ERRORS, SPILLING, OR LOSING REACTANTS - DO NOT COUNT AS ERRORS! They can be EXPERIMENTAL due to heat loss/gain, room temp *specific heat capacity is for 25 C*, and atmospheric pressure is constant. And they can be MEASUREMENTS - consider the precision and the potential range of error for each measurement)

9. In terms of bonds breaking and forming, what's responsible for the enthalpy change?


CONCLUSION: write a brief statement that refers to the purpose.

Answers

In Experiment 1, we found the heat of solution of sodium hydroxide (NaOH) by dissolving 2.00 g of NaOH in 50.0 mL of water.

What was observed in the experiment?

The temperature rose from 20°C to 28.5°C. The moles of NaOH were determined to be 0.0518 mol.

Using the specific heat of water (4.184 J/g°C), we calculated the enthalpy change (ΔH_sol) and compared it to the literature value, finding a percent error.

In Experiment 2, we measured the heat of neutralization between NaOH and 0.75 M HCl.

The temperature increased from 23.5°C to 27°C. We determined the moles of HCl, limiting reagent, and enthalpy change (ΔH_neut) for the neutralization reaction.

The actual value was compared to the literature value, and percent error was calculated.

Experimental errors in both experiments could arise from heat loss/gain, variations in room temperature and atmospheric pressure, and imprecise measurements.

The enthalpy changes in both experiments are due to bond breaking and forming during the dissociation of NaOH and the neutralization reaction between NaOH and HCl.

In conclusion, we determined the heat of solution for sodium hydroxide and the heat of neutralization between sodium hydroxide and hydrochloric acid, and analyzed the possible sources of experimental errors.


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The dipole moment ( μ ) of HBr (a polar covalent molecule) is 0.811D (debye), and its percent ionic character is 12 % . Estimate the bond length of the H−Br bond in picometers. Note that 1 D=3.34×10−30 C⋅m and in a bond with 100 % ionic character, Q=1.6×10−19 C .

Answers

The relationship between dipole moment, percent ionic character, bond length, and charge can be used to estimate the H-Br bond's length. The H-Br bond is thought to have a length of 144 picometers.

How do you determine the H-Br bond's bond length in picometers?

We may guess the charge on the H-Br bond given the dipole moment and percent ionic character:

Q = (μ / d) * (1 / 3.34×10^-30)

Ionic character percentage equals (Q / 1.610-19) x 100%

By condensing and figuring out d, we arrive at:

D is equal to / (0.208 * sqrt(percent ionic character)).

where d is in picometers and is in Debye.

Inputting the values provided yields:

144 pm is equal to d = 0.811 D / (0.208 * sqrt(12)).

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