hello could some one please help me wit these

Answer: depends what kind of stain and color shoe.

Explanation:

Answer:

Wash the shoe

Explanation:

If the stain is unwashable, then I'd either get new shoes or paint over them.

Answer:

1470 N

Explanation:

Weight = m*g

So 150 kg * 9.8 m/s^2 = 1470 N

Answer:

question is incomplete

The vertical height of the cliff on which the diver drove off is 33.76 m.

The given parameters;

The time of motion of the cliff diver is calculated as follows;

[tex]t = \frac{X}{v} \\\\t = \frac{21}{8} \\\\t = 2.625 \ s[/tex]

The vertical height of the cliff is calculated as follows;

[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 + 0.5 \times 9.8 \times 2.625^2\\\\h = 33.76 \ m[/tex]

Thus, the vertical height of the cliff on which the diver drove off is 33.76 m.

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Answer:

No work is done on the weight. :3

To solve this we must be knowing each and every concept related to work and its calculation. Therefore, 250J is the work done in joule by the rope on the weight.

Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.

When a force is applied, it is said to produce positive work if it has a proportion in the orientation of the movement of a site of application. Work done is positive when the direction of force acting on the object and displacement of the object both are in the same direction.  

Mathematically,    

Work= force ×displacement

force =20 N

displacement=2.00 m

displacement=2×3.14×2=12.5m

substituting all the given values in the above equation, we get

Work= 20 ×12.5

Work =250J

Therefore, 250J is the work done in joule by the rope on the weight.

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Answer:

Venus

Explanation:

basic 2nd grade smarts "no offense"

Answer:

Ink

mud

hcl

ocean water

co2

h20

Answer:

B

Explanation:

Y won't sink because his shoes have wider area

Answer:

Mass is relative too. Thus, as much fuel as you pack you will never reach the velocity of light. At the velocity of light, if you were somehow to reach it, your mass will be infinite and it will so require infinite force to push you, so no going beyond that speed. This is the reason time flows in a single direction.

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 2.5 kg

acceleration = 3.0 m/s²

We have

force = 2.5 × 3.0 = 7.5

We have the final answer as

Hope this helps you

Rogue waves are unpredictable and sudden waves that appear as surface waves and that have the ability to make ships capsize. For a wave to be a non-linear equation it means that it is unpredictable. What is expected does not actually happen. The resulting wave is often chaotic in nature.

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Answer:

2 m/s2

Explanation:

the answer is 2 m/s2

Answer:

“Eat more delicious whole-food plants at every meal and snack. Fruits, vegetables, whole grains, nuts and seeds are packed with nutrients and contain satisfying fiber that is good for digestion, disease prevention and sustained energy.

Explanation:

Answer:

A hydrometer is an instrument used to determine specific gravity

Answer:

it is used determine specific gravity

Explanation:

and u can see them in use by measuring proof of moonshine

Answer:14

Explanation:cuz

Answer:

it is 1 / square root of the change in distance

Explanation:

since the equation of the gravitational force is

[tex]F=G{\frac{m_1m_2}{r^2}}[/tex]

then F and r are inversely related, by the equation

[tex]F \alpha \frac{1}{r^2}[/tex]

this means when F is multiplied by 2 then r^2 is multiplied by half

so when r is multiples by half we first square the number (0.5) ^ 2 = 0.25

so

[tex]F \alpha \frac{1}{(0.25)r^2}[/tex]

which means F is multiples by 1/0.25 or 4 when the radius is halfed

Answer:

c.

Explanation:

Answer:

50.176 [m].

Explanation:

1) the required height can be calculated using the formula:

h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;

2) if V₀=0, t=3.2, g=9.8, then

h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].

Answer:

2,800 n

Explanation:

hope this helps, have a nice day/night! :D

The force of 2812.5 N is being exerted by the chain.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given that:

Mass of the  hunk of anorthosite moon rock : m = 500.0 kg.

Acceleration of the hunk: a = 4.0 m/s².

Acceleration due to gravity in moon = 1.625 m/s².

So, required force = 500.0(4.0 +1.625) n = 2812.5 N.

The force of 2812.5 N is being exerted by the chain.

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Answer:

A. longer days and more direst sunlight

Explanation:

In the Northern Hemisphere, June 21 has longer days and more direct sunlight than December 21, so option A is correct.

Essentially, it alludes to a person's half-divisions. The Earth can be split up into many equal divisions. Latitudinal or longitudinal divisions may be used. Based on a hypothetical equator line, it can be either the northern or Southern Hemisphere, and based on the prime meridian, it can be either the eastern or western hemisphere. When viewed from a latitudinal perspective, the Northern and Southern Hemispheres are essentially hemispheres of the Earth.

The Northern Hemisphere is the region of the Earth that lies above the equator, which is an imaginary line. This hemisphere includes anything that is above this 0° line. It is the half of the planet that has the most people on the planet and more land than water.

The summer solstice falls on June 21 in the Northern Hemisphere and the winter solstice falls on June 21 in the Southern Hemisphere. The solstices are reversed around December 21 and winter officially starts in the Northern Hemisphere.

Therefore, in the Northern Hemisphere, June 21 has longer days and more direct sunlight than December 21.

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The force required to start the block in motion is equal to 39.2 Newton.

Given the following data:

To determine the force required to start the block in motion:

Note: The force that is required to start the block in motion must be greater than or equal to the force of static friction.

Mathematically, the force of static friction is given by the formula;

[tex]Fs = uFn = umg[/tex]

Where;

Substituting the given parameters into the formula, we have;

[tex]F_s = 0.4 \times 10 \times 9.8\\\\F_s = 4 \times 9.8\\\\F_s = 39.2\;Newton[/tex]

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Answer:

10cm

Explanation:

25/20=x/8

cross multiply;

200=20x

x=10

The coefficient of kinetic friction between the block and the horizontal surface is 0.051.

The given parameters;

The acceleration of the block is calculated as follows;

[tex]v^2 = u^2 + 2(-a)s\\\\v^2 = u^2 - 2as\\\\a = \frac{u^2 - v^2}{2s} \\\\a = \frac{3^2 - 0^2}{2\times 9} \\\\a =0.5 \ m/s^2[/tex]

The coefficient of kinetic friction between the block and the horizontal surface is calculated as follows;

[tex]\mu_k mg = ma\\\\\mu_k = \frac{a}{g} \\\\\mu_k = \frac{0.5}{9.8} \\\\\mu_k = 0.051[/tex]

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Answer:

[tex]4 ms^{-2}[/tex]

Explanation:

Normal force - should be the reaction from the surface it's on - nullifies the weight of the object. At this point the only force is of [tex]22-14 = 8N[/tex] from whoever is pushing the square and the friction, towards the right. At this point we divide the force by the mass of the object to obtain an acceleration of [tex]8/2 = 4 ms^{-2}[/tex]

Answer:

It is defined as an astronomical phenomenon which occurs when one spatial object comes within the shadow of another spatial object.

P= 10m = 10 x 115 = 1150 N

work done while lifting a 115 kg sofa 1.5 m off the ground :

A= Ph = 1150 x 1.5 = 1725 J

P/s: I think the weight first is 115kg

ok done. Thank to me :>

Answer:

1 $1260.00-$700.00=$560.00

2 $700.00/$1260.00*100= approximately 55.6%

Explanation:

* this sign means Multiplication

Answer:

https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf

Explanation: