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Since the particle always moves in a circular motion in a direction perpendicular to the radial direction.

The work done by the centripetal force in a circular motion is therefore always zero since the dot product is always zero. A force known as the centripetal force acts on a particle when it is revolving around a specific axis or point. The circular path's center is where this force is directed. The ideal decision is (d) Therefore, the body's weight will be equal to the centripetal force when the angular acceleration reaches the same level as the acceleration caused by gravity. It should be noted that for the centripetal force to equal the weight, there must be a uniform circular motion.

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The components of an electrical circuit represented by the model are as follows:

The figure models resistance in a circuit because just as resistance in a circuit opposes the flow of current, the load resists the movement of the man.

An electrical circuit is a complete path that is provided for the flow of electric current.

Tue components of an electric circuit includes:

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Answer:

3.44

Explanation:

Acellus said it was right. :) Just figure out the inertia first and plug it into the Rotational KE equation.

Answer:

because underwater a force called buoyant force of upthrust applies in the objects in water in the upward direction

The potential impacts of global climate change on thermohaline circulation in the oceans is increasing the rate of circulation. That is option D.

The thermohaline circulation is defined as the process by which deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline).

When there is global climate change increased temperature of water masses would cause these currents to flow faster given the higher kinetic energy of the water molecules.

Therefore, there is increase in rate of circulation when there is global climate change.

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The position of the particle is zero because the velocity is zero for the particle. The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.

Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point and the position of the particle is zero because the velocity is zero for the particle.

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Answer:

Electromagnetic energy

The answer is D, they reproduce quickly.

Answer: D. Reproduce quickly

Explanation:

A doesn’t really have much to do with it. B. isn’t true because viruses are not living. C. is also not true because they can, so D.

The magnitude  displacement vector's magnitude (or length), which is indicated by the arrow's length, measures the separation between the locations.

d = (((x2 - x1)2 + (scaling factor - y1)2)12 represents the displacement's magnitude. The displacement vector's size, or distance d, is its length. The guided line segment connecting P1 and P2 is the displacement vector's (d) direction. We refer to this straight line segment as a geometric or look of the scalar d.

When we talk about magnitude, we don't only imply the amount of a displacement; we also imply its orientation  just a number with a unit  As just an illustration, the professor might repeatedly pace back and forth, possibly

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The magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion is the centripetal acceleration.

This is given by the equation a = v^2 / r, where v is the velocity of the passenger and r is the radius of the circle. Therefore, the magnitude of the passenger's acceleration is equal to the square of her velocity divided by the radius of the circle.

For example, if the passenger is travelling at 10 m/s in a circle with a radius of 5 m, then her centripetal acceleration would be 10^2 / 5 = 20 m/s^2.

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The time taken by the object to hit the ground is 1.8 seconds.

The attraction that draws two objects together is known as gravitational force, sometimes referred to as gravity. Every mass-containing object pulls on nearby things gravitationally in a sizable way.

The time it takes for an object to hit the ground after being dropped off a cliff can be calculated using the formula:

t = √(2*d/g)

where t is the time, d is the distance fallen, and g is the acceleration due to gravity.

In this case, we don't know the distance fell, but we can use the horizontal velocity and time of travel to find it:

d = v * t

where v is the velocity (6 m/s), and t is time (3 seconds)

d = 6 * 3 = 18 m

Now we can use the distance fallen to calculate the time it takes to hit the ground:

t = √(2*d/g)

g is approximately 9.8 m/s^2

t = √(2*18/9.8) = √ (3.6) = 1.8 seconds

So, it takes 1.8 seconds for the object to hit the ground after traveling horizontally off a cliff at 6 m/s for 3 seconds.

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Answer:

7.4 Ω

Explanation:

Let,

R1 = 5 Ω

R2 = 4 Ω

R3 = 6 Ω

R1 is connected series.

R2 and R3 are connected in parallel.

1 / Rp = 1 / R2 + 1 / R3

= 1 / 4 + 1 / 6

= 3 / 12 + 2 / 12

1 / Rp = 5 / 12

Rp = 12 / 5 = 2.4 Ω

Effective resistance

= R1 + Rp

= 5 + 2.4

= 7.4 Ω

Therefore, the combined resistance of 5 ohms wire arranged in series with a parallel arrangement of 4 ohms and 6 ohms wires is

7.4 Ω.

The acceleration is 3 [tex]m/s^2[/tex] when a block with a mass of 5 kg is pulled with a force of 15 n.

The block will experience a net external force of 15 N due to the frictionless surface it is kept in place on.

The block weighs 5 kg.

F = m × a

There is a net external force (F), mass (m), and acceleration acting on the object in this situation (a).

Using the appropriate values in place of F and m:

15 = 5 × a

15/5 = a

3=a

Taking 5 as a factor, we get 3 = a.

As a result, a 5-kilogram item is drawn over a friction less surface with an acceleration of 15 N is 3 m/s².

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The final speed of the second car is '2v' and the collision is elastic collision.

The elastic collision is one in which the system does not experience a net loss of kinetic energy as the result of a collision. In elastic collisions, momentum & kinetic energy are both conserved.

v′ = m1v1 + m2v2 /m1+m2

v ′ = m 1 v 1 + m 2 v 2/ m 1 + m 2

in which m1 is mass of body 1, v1 is its initial speed, m2 is mass of body 2, & v2 is the final speed at which the two objects will be moving after colliding.

m1v +0 = mv/3 +m/3v2

v2 = 2v

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Answer:

a) angles 19.8º, 11.9º, 13.8, 20.4

b) speed 3 10⁸ m/s, 2,037 10⁸ m/s, v = 1.24 10⁸ m/s,  v = 2.06 10⁸ m/s

c)  wavelength  600 nm, 407.3 nm, 248.0 nm, 411.5 nm

Explanation:

For this exercise let's use the law of refraction

         n₁ sin θ₁ = n₂ sin θ₂

where subscript 1 is for the middle of the incident ray and subscript 2 for the middle of the refracted ray

the refractive index is related to the speed of the lightning in the middle

          n = c / v

When the ray enters a material medium, it is absorbed and re-emitted by the atoms in the medium, the frequency remains constant, it is a resonant system, but as the speed of light changes in the medium, the wavelength must change to keep the equation

in the void

                 c = λ f

in the material medium

                   v = λ f

                  [tex]\frac{c}{\lambda_o} = \frac{c}{\lambda_n}[/tex]

                  λₙ = [tex]\frac{v}{c} \ \lambda_o[/tex]

                  λₙ = λ₀ / n

we used  these expressions to our case

1) medium incident air n₁ = 1 medium transmitted n₂ = 1.473

            sin θ₂= [tex]\frac{n_1}{n_2}[/tex] sin θ₁

            sin θ₂ = 1/1,473   sin 30

            θ₂ = sin⁻¹ 0.3394

            θ₂ = 19.8º

2) medium incident glycerin θ₁ = 19.8, medium transmitted diamond θ₂=2.419

            sin θ₂ = 1.473/2.419     sin  19.8

            θ₂ = sin⁻¹ 0.2067

            θ₂ = 11.9º

3) half incident diamond θ₁ = 11.9º, half transmitted quartz n₂ = 1.458

             sin θ₂= 2.419/1.458    sin 11.9

             θ₂ = sin⁻¹ 0.3429

             θ₂ = 13.8º

4) half incident quartz θ₁ = 13.8, medium transmitted air n₂ = 1

             sin θ₂ = 1.458/1    sin 13.8

             θ₂ = sin⁻¹ 0.3467

             θ₂ = 20,4º

b) we look for the speed of lightning in each medium

air             v = c = 3 10⁸ m / s

glycerin    v = c / n

                v = 3 108 / 1,473

                v = 2,037 10⁸ m / s

diamond  v = 3 108 / 2.419

                 v = 1.24 10⁸ m / s

quartz      v = 3 108 / 1.458

                v = 2.06 10⁸ m / s

c) the wavelength in each medium

air         λₙ = λ₀/ n

            λₙ = 600/1

            λₙ 600 nm

glycerin    

            λₙ = 600 / 1,473

            λₙ = 407.3 nm

Diamond

            λₙ = 600 / 2.419

            λₙ = 248.0 nm

quartz

            λₙ = 600 / 1.458

            λₙ = 411.5 nm

Answer:

speed

Explanation:

Answer:

Velocity

Explanation:

Velocity is km/s

Answer:

is a reflection.

The image is real light rays actually focus at the image location). As the object moves towards the mirror the image location moves further away from the mirror and the image size grows (but the image is still inverted). When the object is that the focal point, the image is at infinity.

Explanation:

To find the temperature of the warm iron, we first need to convert the reading on the thermocouple thermometer to a temperature value. To do this, we will use the formula:

Temperature = (Reading - Lower Fixed Point) / (Upper Fixed Point - Lower Fixed Point) * (Upper Temperature - Lower Temperature) + Lower Temperature

In this case, the lower fixed point is 9.00mV and the upper fixed point is 16.50mV. We also know that the lower temperature is 0°C (the freezing point of water) and the upper temperature is 100°C (the boiling point of water). So, we can plug in these values:

Temperature = (11.21mV - 9.00mV) / (16.50mV - 9.00mV) * (100°C - 0°C) + 0°C

Simplifying, we get:

Temperature = (2.21mV / 7.50mV) * 100°C

And further simplifying, we get:

Temperature = 0.2907 x 100°C

So, the temperature of the warm iron is approximately 29.07°C to the nearest whole number.

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Answer: Sound wave diffracts more.

Explanation: Width of gap d  is smaller than wavelength λ of the gap.

You can estimate it from  equation  d sin α = n λ

The constant n is order of diffraction, n = 0,1,2,..

sin α = n λ / d   is greater when  λ/d is greater.

Sound wave will tend diffract more through a narrow gap that is about 1 centimeter wide.

Diffraction is the spreading of waves around obstacles. Diffraction takes place with sound; with electromagnetic radiation, such as light, X-rays, and gamma rays; and with very small moving particles such as atoms, neutrons, and electrons, which show wave like properties.

d sin α = n λ

Width of gap d  is smaller than wavelength λ of the gap.

The constant n is order of diffraction, n = 0,1,2,..

sin α = n λ / d

Diffraction is greater when  λ/d is greater.

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Answer:

350.72 m/s

Explanation:

Formula for velocity of wave is;

v = fλ

Where;

v is speed

f is frequency

λ is wavelength

We are given;

f = 512 Hz

λ = 0.685 m

Thus;

v = 512 × 0.685

v = 350.72 m/s

The weight of the book and your lifting power will be the only two forces operating, assuming that air resistance is minimal (gravity).

The book's displacement was x=(2.3-0.75)m=+1.55m.

The book weighs W= m(-g)= 2.0 kg(-10N/kg)= 20 N.

Therefore, the weight's work (energy delivered by the weight) is equal to W.x (-20N).

(+1.55m) = -31 Nm =-31 J.

This outcome, -31J, demonstrates that the weight caused the rising book to lose 31J of kinetic energy, increasing the gravitational potential energy of the book.

You lifted the book, which gave it kinetic energy from the chemical energy stored in your muscles. The weight is thereby decreasing the kinetic energy of the book while the lifting force from you increases it.

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The efficiency of energy transfer from the arm to the baseball would be lower than the actual efficiency, as there was a higher initial velocity at release.

In order to answer this question, we must look at the experimental design and assess how air resistance would affect the scientists' computations. The ball's velocity would be reduced as it moved from the mound to home plate, where the velocity was measured, due to air resistance.

Therefore, the measured velocity ought to be lower than the release velocity. As a result of the baseball's predicted energy being lower due to the lowered velocity, the efficiency of the energy transfer from the arm to the ball will also be lower.

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Answer:

133m/s

Explanation:

b/c 250÷2.2÷0.85=133

Answer:

V = 1.67 m/s

Explanation:

Given the following data;

Force = 1000 N

Mass = 3000 kg

Time = 5 seconds

To find the speed of the truck;

First of all, we would find the acceleration

Force = mass * acceleration

1000 = 3000 * acceleration

Acceleration = 1000/3000

Acceleration = 0.333 m/s²

Using the first equation of motion, we would determine the speed;

V = u + at

Initial velocity is equal to zero because the truck starts from rest.

V = 0 + 0.333*5

V = 1.67 m/s

We will understand the given concept through an example

The rat serves as your point of reference if you mentioned that the rabbit was to the left of it. You are expressing its position when you specify the distance and direction. The present separation and direction of an object from a reference point is its position.

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The reason why a yellow colored object looks white in a dimmed light or low intensity of light the colors wavelength have the colors more farther it means it's getting more dimmed.

The wavelengths of sound waves are similar to the size of objects around you, but the wavelength of light waves are much shorter. As a result, you can hear people talking in a room with an open door even though you can’t see them.

The amount of diffraction or bending of the wave depends on the size of the obstacle the wave encounters. If the size of the obstacle is much larger than the wavelength, very little diffraction occurs. Then there is a shadow behind the object where there are no waves.

As the wavelength increases compared with the size of the obstacle, the amount of diffraction increases. The amount of diffraction is greatest if the wavelength is much larger than the obstacle.

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The force required to raise the box up the ramp when the ramp is 12 meters long, the box is 4 meters and the box weighs 200 newtons is 653.33 N (7840/12)

To determine the force required to raise the box up the ramp, we can use the work-energy principle.

Work = Change in PE

W = PEf - PEi

where

W = work done (Joules)

PEf = final gravitational potential energy (Joules)

PEi = initial gravitational potential energy (Joules)

The gravitational potential energy of an object is given by the formula:

PE = mgh

where

m = mass of the object (200 N)

g = acceleration due to gravity (9.8 m/s^2)

h = height (4 meters)

We can find the change in potential energy as follows:

PEf = mgh = 200 x 9.8 x 4 = 7840 J

PEi = mgh = 200 x 9.8 x 0 = 0 J

So, the change in potential energy is 7840 J.

Now we can calculate the work done as:

W = PEf - PEi = 7840 - 0 = 7840 J

The work done is equal to the force exerted on the object multiplied by the distance it is moved:

W = F x d

7840 = F x 12

So, the force required to raise the box up the ramp is 653.33 N (7840/12)

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The horizontal displacement of the cannonball  is  65.75 meter.

Speed is characterized as the rate at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

original speed: u= 35.9 m/s.

acceleration due to gravity: g = 9.8 m/s².

Initial height of the cannonball = 166 m.

Hence,  the horizontal displacement of the cannonball = u²/2g

= 35.9²/(2×9.8) meter

= 65.75 meter.

so, the displacement of the cannonball  is  65.75 meter.

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