Help pls it’s urgent

Answer:

There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

 Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

 Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

Explanation:

PF

Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

 Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

 Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

The weld bead in SMAW is formed by the electrode wire core mixing with the molten base metal, Therefore the correct option is D.

It is a type of manual arc welding process which utilizes a consumable electrode covered with flux to protect the weld bead.

For SMAW either direct current or alternating current can be used to form the electric arc. The electrode melts and forms a molten weld pool with the base metal by using the thermal energy produced from the electric arc.

The weld bead in Shielded Metal Arc Welding is formed by the electrode wire core mixing with the molten base metal.

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Answer:

114 m/s

Explanation:

see the image below

Answer:

I am not sure sorry wish I could help

Answer:

I also wish I could help u but am sorry I don't know it

Don't worry you will find a solution

We are given:

F = 300N

acceleration (a) = 0.750 m/s²

Solving for the mass of the object:

We know from the second equation of motion:

F = ma

replacing the variables

300 = m * 0.75

m = 300 * 100/ 75

m = 300 * 4/3

m = 100 * 4

m = 400 kg

Answer:

[tex]a_{x} = 0.342 \frac{m}{ {s}^{2} } \: "x \: component \: of \: acceleration"

\: \\ a_{y} = 1.02 \: \frac{m}{ {s}^{2} } \: "y \: component \: of \: acceleration" [/tex]

Explanation:

Given a mass of 63.9kg with a total applied force of 125 N at a 31.5° inclination relative to the horizontal and vertical, and a horizontal resistance force of 84.8 N. The components of acceleration can be calculated as follows:

Force = mass × acceleration

Vertical component of a vector = vector × Sin(angle)

Horizontal component of a vector = vector × Cos(angle)

extra:

V = √x^2+y^2

θ (angle, "theta") = arctan or inverse tan(y/x) (For this instance. Theta is usually an angle measure though)

x = V cos θ

y = V sin θ

____________________

To find the vertical component of acceleration we must first take the vector quantity of our force which is 125 N (Newtons) and it's angle of 31.5°.

Vertical force = 125 × sin(31.5 degrees) = 125 × 0.5225 = 65.312 N [aka the normal force]

This works because force is a vector, it has both direction(by the angle of force), and magnitude(it's quantity).

Then take the force equation, and rearrange it to solve for the upward acceleration: F = m × a → a = F/m.

a = 65.312/63.9 ≈ 1.02 m/s^2.

Then for the horizontal acceleration, take the cosine for the horizontal part

Answer:

0.298

Explanation:

Work equals change in energy.  So the work done by friction equals the final kinetic energy minus the initial potential energy.

W = ΔE

Fd = ½ mv² − mgh

Nμ (-d) = 46.0 J − (25 N) (3.30 m)

-Nμ d = -36.5 J

Using a free body diagram, the normal force is:

N = mg cos θ

N = (25 N) (4.90 m / d)

N = 122.5 J / d

Nd = 122.5 J

Therefore:

-(122.5 J) μ = -36.5 J

μ = 0.298

Answer: density decreases

Explanation:

Answer:

The quartering act of 1765 required the colonies to house British soldiers in barracks provided by the colonies.

Which of the following statements describes how a balance obtains a measurement ​

Explanation:

A balance obtains a measurement by the sides of an object which are measured and multiplied to get the final measurement. Thus, the correct option is C.

A balance is an instrument used for comparing the weights of two objects. It is usually for the scientific purposes, to determine the difference in mass or weight of an object.

Weighing of objects directly requires that the balance be carefully zeroed that is it reads zero with nothing on the balance pan in order to obtain accurate results of the measurement.

The sides of an object are measured and multiplied with a factor to get the final measurement of the object. Through this, a balance obtains the measurement.

Therefore, the correct option is C.

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Answer: Statutes are laws created by the legislative branch through the lawmaking process. Statutes are written, discussed, argued and voted on in Congress or in the legislature of a state. The courts then apply and interpret these statutes on a case by case basis.

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Explanation:

Answer:

From the second law of motion:

F = ma

we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s

So, F=  20N   and  a = 4 m/s/s

Replacing the variables in the equation:

20 = 4* m

m = 20 / 4

m = 5 kg

Answer:

60 kg

80 kg

Explanation:

Work is equal to the change in energy.

W = ΔE = E − E₀

Let's start with block B.  The work done by the tension force is equal to the change in energy.  Initially, the block has potential energy.  Finally, the block has kinetic energy.

W = ΔE

FΔy = ½ mv² − mgh

T (-2.0 m) = ½ m (6.00 m/s)² − m (10 m/s²) (2.0 m)

T (-2.0 m) = m (-2 m²/s²)

T = m (1 m/s²)

Now let's look at block A.  The work done by tension and against friction is equal to the change in energy.  Initially, the block has no energy.  Finally, it has both kinetic and potential energy.

W = ΔE

Fd = ½ mv² + mgh − 0

(T − Nμ) (2.0 m) = ½ (4.00 kg) (6.00 m/s)² + (4.00 kg) (10 m/s²) (⅗ × 2.0 m)

(T − Nμ) (2.0 m) = 120 J

T − Nμ = 60 N

Draw a free body diagram of block A and sum the forces in the perpendicular direction to find the normal force N.

N = mg cos θ

N = (4.00 kg) (10 m/s²) (⅘)

N = 32 N

Substitute:

T − 32μ = 60 N

If μ = 0, then T = 60 N and m = 60 kg.

If μ = ⅝, then T = 80 N and m = 80 kg.

Answer:did you find you answer also i answered so you can give him brainiest

Explanation:

Answer:

v = - 1,715 m / s ,   x = 0.0156 m

Explanation:

This is an oscillatory movement exercise, which is described by the expression

          x = A cos (wt + Ф)

we can assume that the block is released from its maximum elongation, so the phase constant (Ф) is zero

As we are told that the stone does not affect the movement of the spring mass system, the amplitude and angular velocity do not change, in the upward movement the stone is attached to the mass, but in the downward movement the mass has an acceleration greater than g leave the stone behind, let's look for time, for this we use the definition of speed and acceleration

         v = dx / dt

         v = - A w sin wt

          a = - Aw² cos wt

         a = -g

         -g = - Aw² cos wt

          wt = cos⁻¹ (g / Aw²)

          t = 1 / w cos⁻¹ (g / Aw²)

angular velocity and frequency are related

        w = 2π f

        w = 2π 4

         w = 8π   rad / s

remember that the angles are in radians

          t = 1 / 8π cos⁻¹ (9.8 / (0.07 64π²))

          t = 0.039789 1.3473

          t = 0.0536 s

let's find the speed for this time

          v = - A w sin wt

          v = - 0.07 8π sin (8π 0.0536)

          v = - 1,715 m / s

the distance is

           x = A cos wt

           x = 0.07 cos (8π 0.0536)

           x = 0.0156 m

Answer:

Explanation:

The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula

[tex]acceleration = \frac{velocity}{time} \\ [/tex]

From the question

time = 4 s

velocity = 10 m/s

So we have

[tex]acceleration = \frac{10}{4} = \frac{5}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

Average speed equals distance / time

380 / 40 = 9.5 m/s.

Explanation:

Answer:

Explanation:The four closest to the sun — Mercury, Venus, Earth and Mars — are the terrestrial planets. They have rocky surfaces enclosed by relatively shallow atmospheres.

Answer:

10,200 N

Explanation:

Given:

Mass of the car m = 1200 kg

Acceleration of the car a = 8.5 m/s^2

Force F=?

[tex]\because F = ma\\

\therefore F = 1200 \times 8.5\\

\therefore F = 10,200 N \\ [/tex]

Answer:

k = 930 N / m

Explanation:

For this problem we will solve it in parts, let's start with the conservation of mechanical energy

Starting point. Lower

          Em₀ = [tex]K_{e}[/tex] + U₁

Final point. Higher

         [tex]Em_{f}[/tex]= U₂

as there is no friction, energy is conserved

          Em₀ = Em_{f}

          ½ m v² + mg y₁ = m g y₂

where y₁ is the initial height of y1 = -0.5 m and y² the final height y² = 15 m

Let's find speed when getting out of the sling

         v = √ (2g (y₂-y₁))

let's calculate

         v = √[2 9.8 (15 - (-0.5))]

         v = 17.43 m / s

Now we can use Newton's second law.

The force applied by the sling is in the direction of movement (inclined) and the weight is in the vertical direction.

X axis

         Fₓ = m aₓ

in the problem they indicate that the direction of the velocity at the end of the sling is the same direction of the force,  

         F_{e} cos θ = m a cos θ

let's replace the elastic force

        k Δx = m a

Y axis

        F_{y} - W = m a_{y}

         k Δx sin θ - m g = m a sin θ

let's write

              k Δx = m a        (1)

            k Δx sin θ - m g = m a sin θ

Now let's use kinematics to find the acceleration in the sling, the direction of these accelerations ta in the direction of elongation

           v² = v₀² +2 a Δx

as the system starts from rest v₀ = 0

           a = v² / 2Δx

           a = 17.43² / (2  1.4)

           a = 108.5 m / s²

we substitute in equation     1

            k = m a / Δx

            k = 12 108.5 / 1.4

            k = 930 N / m

Answer:

a

   12

b

41667

Explanation:

From the question we are told that

Generally 1 dozen of egg is equivalent to 12 pieces of eye

So given that a gross of item is equivalent to 144 items

x dozens of eggs is equivalent to a gross of item

So

[tex]x = \frac{144 * 1}{12}[/tex]

=>     [tex]x  =  12 \ dozens \ of  \ eggs[/tex]

Generally the sum of  9260 and 32407 is  

               9 2 6 0

        +  3 2 4 0 7

           4  1  6 6 7

Answer:

54mph

Explanation:

Answer:The charge becomes nuetral

Explanation:

Whenever electrons are transferred between objects, neutral matter becomes charged. When an atom loses electrons, it becomes a positively charged ion, or cation. When an atom gains electrons, it becomes a negative charged ion, or anion.

Answer:

-time it takes for the sled to come to a stop after launch of rocket = 7.244 s

-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m

Explanation:

From the question, looking at the motion while accelerating, we have;

Initial velocity; u = 0 m/s

Acceleration; a = 13.5 m/s²

Time; t = 3.3 s

Let's use first equation of motion to find final velocity (v).

v = u + at

v = 0 + (13.5 × 3.3)

v = 44.55 m/s

In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.

d1 = ut + ½at²

d1 = 0(3.3) + ½(13.5 × 3.3²)

d1 = 73.5075 m

Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².

Thus, from v = u + at, we can find the time it take for the sled to come to a stop.

Now, since it's coming to rest acceleration will be negative. Thus;

0 = 44.55 + (-6.15t)

0 = 44.55 - 6.15t

t = 44.55/6.15

t = 7.244 s

Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.

Thus, we'll use the equation;

v² = u² + 2as

Where s will be the second displacement which we will call d2.

Thus;

0² = 44.55² + (-2 × 6.15 × s)

0 = 1984.7025 - 12.3s

12.3s = 1984.7025

s = 1984.7025/12.3

s = 161.358

Thus, d2 = s = 161.358 m

Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;

= d1 + d2 = 73.5075 + 161.358 = 234.8655 m