if 7 cards are dealt from an ordinary deck of 52 playing cards, what is the probability that (a) exactly 2 of them will be face cards? (b) at least 1 of them will be a queen?

Answer: Bro Didnt give any context dont report if wrong

Step-by-step explanation:

i is the imaginary unit, which is defined as the square root of -1.

To find the value of i^48, we can use the fact that i^2 = -1, and simplify the expression as follows:

i^48 = (i^2)^24

Since i^2 = -1, we can substitute -1 in the above expression:

(i^2)^24 = (-1)^24

Any non-zero number raised to an even power is positive, so (-1)^24 = 1. Therefore:

i^48 = 1

Hence, i^48 is equal to 1.

The best measure of center for the data is Option D: The median, and it equals 8.

What is median?

In mathematics, the middle number in a sorted list of numbers is referred to as the median. By arranging the numbers, the middle number can be discovered. Ascending order is used to arrange the numbers. The middle number in the ordered set of numbers is referred to as the data set's median.

The best measure of center for this data is the median because the data is skewed and has outliers.

The median is the middle value when the data is arranged in order, which is less sensitive to outliers than the mean.

To find the median, we need to count the number of data points and find the middle value -

1, 6, 6, 7, 7, 8, 8, 8, 9, 9, 9

We have 11 data points, so the median is the 6th value -

Median = 8

Therefore, the best measure of center for the data is the median, and its value is 8.

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The percentage of 8th graders who send more than 50 texts is 56.15%

Here we want to find the percentage of eight grades who send more than 50 texts, and to get that we need to use the values in the table.

The formula for that percentage is:

P = 100%*(number that send more than 50 texts)/(total number)

On the table we can see that the total number of 8th gradesr is 130, and the number that send more than 50 messages is 73, then the percentage is:

P  = 100%*(73/130)

P = 56.15%

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Hy bro in which class you are?

Answer: 240 is your answer for 100% of the e-book

Step-by-step explanation: so if we look at the given facts, 180 is 75% of the e-book, now take this and divide 180 by 3, and you get 25% of the e-book (60 is 25%) so if we factor that back into the 180 75%, we now get 240 at 100% of the e-book read

Answer:

4/13

Step-by-step explanation:

total = 14 + 6 + 12 + 4 + 16 = 52

purple = 16

p(purple) = 16/52 = 4/13

⇒To be able to answer this question to find how many hours Brooke played his flute for 5 days we ought to first convert the 5 days to hours.

⇒There are 24 hours in a day this means that in 5 days we have =24×5

=120 hours.

⇒We have 120 hours in 5 days , it is said that Brooke played her flute [tex]\frac{3}{4}[/tex],

Meaning she played the flute [tex]\frac{3}{4}[/tex] hours of 120 hours which is equal

[tex]\frac{3}{4} *\frac{120}{1}\\=90[/tex]

For 5 days Brooke played her flute 90 hours

⇒The next step is to convert the 2 days to hours which is equivalent to 24×2

=48 hours are in 2 days, it is said Brooke played the flute [tex]\frac{1}{2}[/tex] hours of 2 days. This simply is equivalent to

[tex]\frac{1}{2} *\frac{48}{1} \\=24[/tex]

⇒For 2 days Brooke played the flute 24 hours,

The total number of hours she played it all is =Number of hours she played it in 5 days+ Number of hours she played it in 2 days.

=90+24

=114

⇒In total of these 7 days she played the flute for 114 hours

Answer:

The length of BD in its simplest radical form is [tex]\sf \sqrt{429}[/tex].

Step-by-step explanation:

The altitude drawn from the vertex of the right angle perpendicular to the hypotenuse separates the hypotenuse into two segments. The ratio of the altitude to one segment is equal to the ratio of the other segment to the altitude.

[tex]\boxed{\sf \dfrac{altitude}{segment\:1}=\dfrac{segment\:2}{altitude}}[/tex]

Given values (see attached diagram):

To find the length of the altitude BD, substitute the values into the formula and solve for x:

[tex]\implies \sf \dfrac{BD}{AD}=\dfrac{DC}{BD}[/tex]

[tex]\implies \sf \dfrac{x}{33}=\dfrac{13}{x}[/tex]

[tex]\implies \sf x^2=429[/tex]

[tex]\implies \sf x=\sqrt{429}[/tex]

As the square root of 429 cannot be simplified any further, the length of BD in its simplest radical form is [tex]\sf \sqrt{429}[/tex].

Answer:

The greatest common factor (GCF) of -16x^2 - 6x^4 is 2x^2.

To find the GCF, we can factor out the common factors of the two terms. In this case, both terms have a factor of 2 and a factor of x^2.

-16x^2 - 6x^4 = 2x^2(-8 - 3x^2)

So the GCF is 2x^2.

Answer:

-9, -6, -4, -2, 2, 3

Step-by-step explanation:

the higher the negative the lower it is

Answer: 4

Step-by-step explanation:

z^2 = 16

Since z is squared and we know that it equals 16. Take the square root of 16 which is 4.

4 x 4 = 16

Answer:

Step-by-step explanation:

16

The probability of at least one card being green is 0.807. Here's how to calculate it: Let's define the event G as getting a green card and the event Y as getting a yellow card.

The probability of getting a green card on the first draw is: P(G1) = 9/14
The probability of getting a yellow card on the first draw is: P(Y1) = 5/14
The probability of getting a green card on the second draw, given that the first card was yellow, is: P(G2 | Y1) = 9/13
The probability of getting a green card on the second draw, given that the first card was green, is: P(G2 | G1) = 8/13
The probability of getting a yellow card on the second draw, given that the first card was green, is: P(Y2 | G1) = 5/13
The probability of getting a yellow card on the second draw, given that the first card was yellow, is: P(Y2 | Y1) = 4/13
To calculate the probability of at least one card being green, we need to add up the probabilities of getting a green card on the first draw and a yellow card on the second draw, and the probabilities of getting a green card on the second draw given that the first card was yellow, and getting a green card on the second draw given that the first card was green:
P(at least one green card) = P(G1 and Y2) + P(G2 | Y1)
P(Y1 and G2 | G1) + P(G1 and G2) = 9/14 * 5/13 + 5/14 * 9/13 + 8/14 * 5/13 + 9/14 * 8/13 = 45/182 + 45/182 + 40/182 + 72/182 = 0.807

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Using division operation, the length it will take the three hoses to fill the pool is 8.33 hours.

The division operation is one of the four basic mathematical operations, including addition, subtraction, and multiplication.

The division operation involves the dividend, the divisor, and the result called the product.

In this situation, it will take Hose A 10 hours to fill the pool and Hose B 5 hours.  If the two hoses are in use, it will 7.5hours (10 + 5)/2.

When the third hose is added, it will take 8.33 hours (10 + 5 + 10)/3.

The first hose's filling rate for the pool = 10 hours

The second hose's filling rate for the pool = 5 hours

The third hose's filling rate for the pool = 10 hours (the slower rate)

The total number of hours used by the three hoses = 25 hours (10 + 5 + 10)

The number of hoses used = 3

The length of time it will take the 3 hoses to fill the pool = 8.33 hours (25/3)

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sin 135°=-√2/2, cos 135° = -√2/2, tan 135° = -1, csc 135°= -√2, sec 135°= -√2, cot 135° = -1; sin (-690°) = -1/2, cos (-690°) =√3/2, tan (-690°) = -√3/3, csc (-690°) = -2, sec (-690°) = 2/√3, cot (-690°) = -√3; sin 225° = -√2/2, cos 225° = -√2/2,  tan 225° = 1, csc 225° =-√2, sec 225° = -√2, cot 225° =-1; sin 1380° = -√3/2, cos 1380° = 1/2, tan 1380° = -√3, csc 1380° = -2/√3, sec 1380° = 2, cot 1380° =-1/√3.

Trigonometric ratios are mathematical functions used to relate the angles of a right triangle to the lengths of its sides. The three primary trigonometric ratios are sine, cosine, and tangent, which are commonly abbreviated as sin, cos, and tan, respectively.

To use these ratios, we typically label the sides of the right triangle relative to the angle we are interested in. The hypotenuse is always the side opposite the right angle and is labeled with the letter "c." The two other sides are labeled relative to the angle we are interested in: the side adjacent to the angle is labeled with the letter "a," and the side opposite the angle is labeled with the letter "b."

The sine of an angle is defined as the ratio of the length of the side opposite the angle (b) to the length of the hypotenuse (c): sin(angle) = b/c.

The cosine of an angle is defined as the ratio of the length of the side adjacent to the angle (a) to the length of the hypotenuse (c): cos(angle) = a/c.

The tangent of an angle is defined as the ratio of the length of the side opposite the angle (b) to the length of the side adjacent to the angle (a): tan(angle) = b/a.

To find the exact values of the six trigonometric functions for each angle, we need to first determine the reference angle, which is the acute angle formed between the terminal side of the angle and the x-axis. Then, we can use the properties of the trigonometric functions in each quadrant to determine the sign and value of each function.

135°

Reference angle = 45° (since 135° is in the second quadrant)

sin 135° = -sin 45° = -√2/2

cos 135° = -cos 45° = -√2/2

tan 135° = -tan 45° = -1

csc 135° = -csc 45° = -√2

sec 135° = -sec 45° = -√2

cot 135° = -cot 45° = -1

-690°

Reference angle = 30° (since -690° is in the fourth quadrant)

sin (-690°) = -sin 30° = -1/2

cos (-690°) = cos 30° = √3/2

tan (-690°) = -tan 30° = -√3/3

csc (-690°) = -csc 30° = -2

sec (-690°) = sec 30° = 2/√3

cot (-690°) = -cot 30° = -√3

225°

Reference angle = 45° (since 225° is in the third quadrant)

sin 225° = -sin 45° = -√2/2

cos 225° = -cos 45° = -√2/2

tan 225° = -tan 45° = 1

csc 225° = -csc 45° = -√2

sec 225° = -sec 45° = -√2

cot 225° = -cot 45° = -1

1380°

Reference angle = 60° (since 1380° is in the second quadrant)

sin 1380° = -sin 60° = -√3/2

cos 1380° = cos 60° = 1/2

tan 1380° = -tan 60° = -√3

csc 1380° = -csc 60° = -2/√3

sec 1380° = sec 60° = 2

cot 1380° = -cot 60° = -1/√3

Note: In the calculations above, we rationalized denominators whenever applicable to obtain exact values.

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Alexis has 12 quarters and 8 dimes.

Let's use d to represent the number of dimes and q to represent the number of quarters. We know that Alexis has a total of 20 coins, so d + q = 20.

We also know that the value of these coins is $3.80. Since dimes are worth $0.10 and quarters are worth $0.25, we can write an equation for the total value in cents:

10d + 25q = 380

To make things easier, let's divide both sides of the equation by 5:

2d + 5q = 76

Now we can use the first equation to solve for d in terms of q:

d + q = 20

d = 20 - q

Substituting this into the second equation gives:

2(20 - q) + 5q = 76

Expanding the parentheses and simplifying, we get:

40 - 2q + 5q = 76

3q = 36

q = 12

Therefore, Alexis has 12 quarters. We can check this by plugging q back into the first equation to find that she has 8 dimes as well:

d + q = 20

d + 12 = 20

d = 8

The total value of 12 quarters and 8 dimes is:

12 quarters x $0.25 per quarter + 8 dimes x $0.10 per dime = $3.00 + $0.80 = $3.80


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Answer:

number is 8

Step-by-step explanation:

let n be the number then 4 times the number is 4n and increased by 30 means adding 30 to it , that is 4n + 30

70 decreased by the number means subtracting n fro 70 , 70 - n

then

4n + 30 = 70 - n ( add n to both sides )

5n + 30 = 70 ( subtract 30 from both sides )

5n = 40 ( divide both sides by 5 )

n = 8

(a) The monthly payment for a 36-month plan is $704.41, and for a 60-month plan is $488.08.

(b) The interest charges for the 36-month plan are $1,459.07, and for the 60-month plan are $3,369.10.

For a)

To calculate the monthly payment for a car loan, we need to use the formula for monthly payments:

M = [tex]P[r(1+r)^n / ((1+r)^n - 1)][/tex]

where M is the monthly payment, P is the principal (the loan amount), r is the monthly interest rate (the annual interest rate divided by 12), and n is the number of months over which the loan is to be repaid.

For the 36-month plan, the principal is 75% of $28,000, or $21,000. The monthly interest rate is 6% / 12, or 0.005. The number of months is 36. Plugging in these values, we get:

M = $[tex]21,000[0.005(1+0.005)^{36} / ((1+0.005)^{36} - 1)][/tex] = $704.41

For the 60-month plan, the principal, monthly interest rate, and a number of months are the same, but we change the number of months to 60:

M = $21,000[0.005[tex](1+0.005)^{60[/tex] / ([tex](1+0.005)^{60[/tex] - 1)] = $488.08

Therefore, the monthly payment for a 36-month plan is $704.41, and for a 60-month program is $488.08.

For b)

To calculate the total interest charges for the loan, we need to subtract the principal (the amount of the loan) from the total amount paid and round to the nearest cent:

For the 36-month plan, the total amount paid is $25,459.07 (36 x $704.41), so the interest charges are:

$25,459.07 - $21,000 = $4,459.07, rounded to $1,459.07

For the 60-month plan, the total amount paid is $29,284.80 (60 x $488.08), so the interest charges are:

$29,284.80 - $21,000 = $8,284.80, rounded to $3,369.10

Therefore, the interest charges for the 36-month plan are $1,459.07, and the 60-month plan are $3,369.10.

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Answer:

27.43% of the students scored 83 or more in the exam.

Step-by-step explanation:

We can use the Z-score formula to find the percentage of students scoring 83 or more:

Z = (X - μ) / σ

where X is the test score, μ is the mean test score, and σ is the standard deviation.

Substituting the given values, we get:

Z = (83 - 80) / 5 = 0.6

Using a Z-score table or calculator, we can find the percentage of students scoring 83 or more:

P(Z > 0.6) = 1 - P(Z < 0.6) = 1 - 0.7257 ≈ 0.274

27.43% of the students scored 83 or more in the exam.

OR. USING PROPERTIES OF NORMAL DISTRIBUTION

convert the raw score of 83 into a standardized score, also known as a z-score.

The formula for calculating the z-score is:

z = (x - μ) / σ

Where:

x = raw score

μ = mean

σ = standard deviation

Substituting the values given in the question, we get:

z = (83 - 80) / 5

z = 0.6

This means that a student who scored 83 on the exam has a z-score of 0.6.

Next, we need to find the area under the normal distribution curve to the right of this z-score. We can use a standard normal distribution table or calculator for this purpose.

Using a standard normal distribution table, we find that the area to the right of z = 0.6 is approximately 0.2743.

Therefore, the percentage of students scoring 83 or more in the exam is approximately:

0.2743 x 100% = 27.43%

So, about 27.43% of students scored 83 or higher on the exam.

Step-by-step explanation:

Put the logs on the same side.

[tex] log_{2}(7y - 1) - log_{2}(y - 1) = 3[/tex]

Using log rules, whenever you separate two logs using subtraction and they have the same base, we can write them as one log where they are a rational function

[tex] log_{2}( \frac{7y - 1}{y - 1} ) = 3[/tex]

Let both of these expression be the power of a exponent with base 2.

[tex]2 {}^{ log_{2}( \frac{7y - 1}{y - 1} ) } = 2 {}^{3} [/tex]

The base 2 and log base 2 cancel out

[tex] \frac{7y - 1}{y - 1} = 8[/tex]

When y =1, we will get undefined so y cannot be 1

However, multiply both sides by y-1

[tex]7y - 1 = 8(y - 1)[/tex]

[tex]7y - 1 = 8y - 8[/tex]

[tex]7 = y[/tex]

Answer:

Step-by-step explanation:

4. a

x cannot be 0 because 2/0 cannot be calculated - we say that it is undefined.

b. x cannot be 1 as that would mke the denominator x - 1 = 0 which is undefined.

5 a. (9x - 5)(9x + 5)

b. (2x + 1)(x - 3).

6.

C.  (x + 7)/3

7.

a. (-5, ∝)

b. (-∝, 2]

c.(-3, 7].

8.

y = kx

24 = 16k

k = 1.5

So, y = 1.5x

When x = 50

y = 1.5*50 = 75.

Answer:

8

Step-by-step explanation:

The box contains a total of 4 x 12 = 48 eggs.

If we arrange these eggs in 6 rows, we need to divide the total number of eggs by 6:

48 ÷ 6 = 8

Therefore, there will be 8 eggs in each row.

Answer:

2/13

Step-by-step explanation:

A standard deck of cards has four suits
Therefore there are four twos, one from each suit
There are also 4 kings, one from each suit

P(two) = 4 twos/52 cards = 4/ 52 = 1/13

PKing) = 4 kings/52 cards = 1/13

P(two or king) = P(two) + P(king)
= 1/13 + 1/3

= 2/13

Therefore , the solution of the given problem of percentage comes out to be  earned 6.1% from the selling of the oranges.

In statistics, "a%" refers to a figure or a statistic that is expression as a percentage of 100. The letters "pct," "pct," and "pc" are also rare abbreviations. It is typically represented by the symbol "%," though. There are no indicators and a flat ratio to the overall amount. In reality, percentages are numbers because their sum almost always equals 100.

Here,

Let's suppose that the lady purchased x oranges.

She charged 60gp for each orange she sold, for a total of 60x gp.

She earned a profit of 3.05 GHC, making her overall profit

=> 3.05 GHC = 305p.

Her cost price (50gp) plus her profit (305p) would equal her total income (selling price), which would be 355gp.

=> 60x = 355

=> x = 355/60

=> x = 5.9167

She consequently purchased six bananas.

b) Since she paid 50gp for the container of oranges, their cost would be 50gp.

c) The total sale price of the oranges would be 360gp, or 60gp for each orange multiplied by 6.

d) She would have earned a profit of (profit/cost price) x 100%.

She made 305p, or 3.05 GHC, in earnings.

Her cost was 50gp, so

=> 6.1%  = (3.05/50) *  100%.

She thus earned 6.1% from the selling of the oranges.

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Hence, the predicted mean weight of progeny is 77.6 g (rounded off to three significant figures).

As given that the mean fruit weight of a population of tomato plants is 60 g and the heritability coefficient (h_p) is 0.12, it is required to predict the mean weight of the progeny if tomato plants whose fruit averaged 80 g were selected from the original population and interbred .

The formula for the predicted mean weight of progeny (MP) is given as: MP =  mean weight of selected individuals + (h_p) × (mean weight of original population - mean weight of selected individuals)

Using the above formula, we have ,mean weight of selected individuals = 80 g mean weight of original population = 60 gh_p = 0.12Substituting the given values in the above formula, we get :[tex]MP =  80 + 0.12 × (60 - 80)MP =  80 + 0.12 × (-20)MP =  80 - 2.4MP =  77.6 g[/tex]

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1. Dilation is the process of enlarging or shrinking a figure or shape by a scale factor.

2. Reflection is the process of flipping a figure or shape over an axis. In this example, A'B'C' is reflected over the x-axis.

3. A pair of triangles that are congruent are triangles with the same size and shape.

4. A pair of triangles that are similar are triangles with the same shape but different sizes.

Dilation is a mathematical operation used to expand or contract a shape. It involves multiplying every point in the shape by a given scale factor. The scale factor determines how much the shape is changed. The result is a line segment twice the length of the original.

1. In this example, triangle ABC is dilated by a factor of 2 about the point (-1,4). This means that all points on the triangle ABC will be multiplied by the scale factor 2. So the coordinates of point A will become (N-1,6) x 2 = (-2,12), point B will become (-4,5) x 2 = (-8,10) and point C will become (-4,0) x 2 = (-8,0). The new triangle created by the dilation is A'B'C'.

2. This means that the x-coordinates of the points remain the same, but the y-coordinates are multiplied by -1. So the coordinates of point A' will become (-2,12) x -1 = (-2,-12), point B' will become (-8,10) x -1 = (-8,-10) and point C' will become (-8,0) x -1 = (-8,0). The new triangle created by the reflection is ABC'.

3. A pair of triangles that are congruent are triangles with the same size and shape. In other words, the sides and angles of the two triangles are all equal.

4. A pair of triangles that are similar are triangles with the same shape but different sizes. In other words, the angles of the two triangles are equal, but the sides are not necessarily the same length.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{7(g - 10h + 4)}[/tex]

[tex]\large\text{\underline{Distribute} \boxed{\text{7}} \underline{within the parentheses}:}[/tex]

[tex]\mathsf{= 7(g - 10h + 4)}[/tex]

[tex]\mathsf{= 7(g) + 7(-10h) + 7(4)}[/tex]

[tex]\mathsf{= 7g - 70h + 28}[/tex]

[tex]\large\text{We \boxed{\text{cannot}} do anything further because we do NOT have any \underline{like}}\\\large\text{\underline{terms}}[/tex]

[tex]\huge\text{Therefore your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{\mathsf{7g - 70h + 28}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

The coffee distributor should mix 8 pounds of Kenya coffee blend and 2 pounds of breakfast coffee blend to make 10 pounds of a coffee blend that can sell for $9.36 per pound.

We can use the idea of weighted averages to overcome this issue. Assume that 10 pounds of the desired blend require x pounds of Kenya coffee blend and y pounds of morning coffee blend.

The price of the Kenya coffee mix per pound is $8.20, while the price of the morning coffee blend per pound is $14.00. The required combination costs $9.36 per pound. On the basis of the weighted average, we can construct the following equation:

8.20x + 14.00y = 9.36(10) (10)

When we simplify this equation, we obtain:

8.20x + 14.00y = 93.60

Given that we are producing 10 pounds of the ideal blend, we also know that x + y = 10. To get the values of x and y, we can use substitution or elimination to solve this system of equations.

Use substitute now. We can find x from the second equation by solving in terms of y:

x = 10 - y

Substitute this into first equation, we get:

8.20(10 - y) + 14.00y = 93.60

82 - 8.20y + 14.00y = 93.60

5.80y = 11.60

y = 2

We obtain x = 8 by substituting y = 2 into x = 10 - y. Hence, to manufacture 10 pounds of a coffee mix that can be sold for $9.36 per pound, we'll need 8 pounds of Kenya coffee blend and 2 pounds of breakfast coffee blend.

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