Answer:
A
Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.
in an rfid system, where would the unique data identifying an item typically be found?
In a radio frequency identification (RFID) system, the unique data identifying an item are typically found in: tags.
What is an RFID system?
RFID is an acronym for radio frequency identification.
A RFID system can be defined as an automatic, wireless, identification technology (device) that is typically designed to allow end users store and retrieve information, especially through the use of an electromagnetic field.
The operational benefits of an RFID system:
Generally, a radio frequency identification (RFID) system is used for the following:
1. To identify an item or individual.
2. To trace and tracking an item or individual.
3. To track an item or individual.
The components of an RFID system:
An RFID system is a wireless, identification technology (device) that comprises two (2) main components and these are:
ReadersTagsTags refer to small objects containing an antenna and a chip (smart barcodes) that are used to automatically identify an item or individual they are embedded in or attached to.
In conclusion, the unique data that are used in identifying an item are typically found in tags.
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A ball is thrown at an angle of 38 degrees to the horizontal. What happens to the magnitude of the ball's vertical acceleration during the total time interval that the ball is in the air
Answer:
I belive it is 38 degrees
Explanation:
The magnitude of the vertical acceleration of the ball during the total time interval that the ball is in the air, the acceleration remains the same.
What is projectile motion?A projectile can be defined as an object that is in flight after being projected. The acceleration acting in the vertical direction which is because of gravity in a projectile motion. Therefore, we can apply the equations of motion separately on X-axis and Y-axis to find the parameters.
If any projectile is projected with the velocity 'v' and is making an angle θ from horizontal. The horizontal component of the initial velocity of the projectile will be equal to vcosθ.
The vertical component of the initial velocity of the projectile is v sinθ. The horizontal component remains the same as no acceleration is acting horizontally.
The ball will experience only one force which is gravity if there is no air resistance. The gravity remains constant if there is no initial speed of the ball. The acceleration of the ball will be in the downward direction and stays constant.
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1. When shot from the barrel of a pellet gun (50.00 cm long), a 5.000 gram pellet moves
from rest to 400.0 m/s. What force does the gun exert on the pellet?
The force the gun exerts on the pellet at the given acceleration is 80 N.
The given parameters;
mass of the pellet, m = 5 g = 0.005 kglength of the gun, d = 50 cm = 5 mfinal velocity of the pellet, v = 400 m/sThe acceleration of the pellet is calculated as follows;
[tex]v^2 = u^2 + 2as\\\\400^2 = 0 + 2(a) (5)\\\\400^2 = 10a\\\\160000 = 10a\\\\16,000 \ m/s^2 = a[/tex]
The force the gun exerts on the pellet at the given acceleration is calculated as;
[tex]F = ma\\\\F = 0.005 \times 16,000\\\\F = 80 \ N[/tex]
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A 0.60 kg mass is moving horizontally with a speed of 7.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of 4.20 m/s. What is the magnitude of the change in linear momentum of the mass
Answer: The magnitude of the ball's momentum change is
Δp=m∣ν
i
−ν
f
∣=(0.70kg)∣(5.0m/s)−(−2.0m/s)∣=4.9kg⋅m/s.
Explanation:
based on what you know about the location in relation to the sun why is this called the goldilock zone in other galaxies
Answer: It's an area that's an optimal distance from the sun for potentially supporting life
help me solve please
Answer:
please check the image
Explanation:
I hope this image helps you please follow the steps. Thank you
Answer:
1kg/```````2
Explanation:
solution
what are the three different ways to tell the difference between a solar and lunar eclipse?
Answer:
Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon. This is an annular eclipse.
(credits to "britannica")
Explanation:
A particle has 37.5 joules of kinetic energy and 12.5 joules of gravitational potential
energy at one point during its fall from a tree to the ground. An instant before striking
the ground, how much mechanical energy.
Hi there!
[tex]\large\boxed{ME = 50 J}}[/tex]
Mechanical Energy = Potential Energy + Kinetic Energy, or:
E = U + K
Plug in the given potential and kinetic energies:
E = 12.5 + 37.5 = 50 J
Elements in the periodic table are arranged in order of increasing...
A mass number
B.Number of protons
C. number of neutrons
D. number of nucleons
Answer:
(B) The number of protons - only the number of protons in the nucleus determines the element - mass and neutrons can vary for the same element
A person drops two objects from the same height. One object weighs 15 N, and the other weighs 10 N. How does the mass of the objects relate to the force of gravity on them? A. The 10 N object has the same mass as the 15 N object. B. The 10 N object has more mass than the 15 N object. C. The 15 N object has twice the mass of the 10 N object. D. The 15 N object has more mass than the 10 N object. SUR
Answer:
Your answer would be D :)
Explanation:
An object with a higher mass will always fall faster due to gravity acting upon it. 15 N is more massive than the 10 N object, so statement D is correct.
A boy drops a stone in a well and finds it takes 2.60 seconds to hit the water.
A) How deep is the well?
B) With what speed does the stone hit the water?
Answer:
(i) How deep is the well (Height)
=> t = √(2H/g)
=> √2H = t × g
=> 2H = t² × g²
=> 2H = (2.60)² × (10)²
=> 2H = 6.76 × 100
=> 2H = 676
=> H = 676 ÷ 2
=> H = 338 m
(ii) speed of the stone:
=> v = √(2Hg)
=> v = √(2 × 338 × 10)
=> v = √6760
=> v = 26√10 m/s
a car traveled 5,300 km in 1 hour whats the average speed is
Answer:
5300km/h
Explanation:
That's an easy question. You can solve it yourself.
The answer can be found by dividing the Distance traveled by the Time.
Now you can solve all the problem of this rule.
A train travelling along a straight track starts from rest at point A and accelerates uniformly to 10 m si in 20 s. It travels at this speed for 60 s, then slows down uniformly to rest in 40 sat point C. It stays at rest at C for 30 s, then reverses direction, accelerating uniformly to 5 ms. in 10 s. It travels at this speed for 30 s, then slows down uniformly to rest in 10 s when it reaches point B.
1. Plot a graph of the motion of the train.
II. Use your graph to calculate:
III. the train's displacement from point A when it reaches point C
IV. the train's displacement from point A when it reaches point 13
V. the train's acceleration each time its speed changes.
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
which work is done by effort
input
work is done by effort input.
hope it helps
[tex] \: [/tex]
a. A pure sample was analysed and was found to contain 6.25 g of lithium, 5.40 g of carbon, & 21.60
g of oxygen. Calculate the empirical formula. Show your work out. If you do not show any work out,
marks will not be given. [3]
b. The molar mass of the compound is 116 g/mol, what is its molecular formula?
PLS URGENTLY ANS
The empirical formula of the compound is Li₂CO₃
First, we will determine the respective number of moles of each element present in the compound by dividing by their atomic masses
Lithium Carbon Oxygen
6.25÷6.94 5.40÷12.01 21.60÷16.00
0.9006 0.4496 1.35
Now, divide through by the smallest number of moles, that is, 0.4496
Lithium Carbon Oxygen
0.9006÷0.4496 0.4496÷0.4496 1.35÷0.4496
2 1 3
Hence, the empirical formula of the compound is Li₂CO₃
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A wooden block moves at a constant speed on a rough horizontal surface. Draw a free-body diagram
clearly showing all the forces applied to the block; compare their magnitudes and directions.
The weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.
The forces acting on the wooden block moving at a constant speed include the following;
weight of block acting downwards, Wnormal reaction on the block acting upwards, Napplied force on the block acting towards positive x-direction, Ffrictional force acting towards negative x-direction, [tex]F_f[/tex]The free-body diagram is presented below;
N
↑
[tex]F_f[/tex] ← ⊕ → F
↓
W
The block is moving at a constant speed, we will have the following;
[tex]W = N \\\\F = F_f[/tex]
Thus, we can conclude that the weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.
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please no irrelevant answers!
Light enters a glass block at an angle of incidence of 46°. The light refracts at an angle of refraction of 26°. What is the refractive index of the glass?
A 0.57
B 0.61
C 1.64
D 1.77
Answer:
Choice C: Approximately [tex]1.64[/tex].
(Assuming that light entered into this glass block from air.)
Explanation:
Let [tex]n_{1}[/tex] denote the refractive index of the first medium (in this example, air.) Let [tex]\theta_{1}[/tex] denote the angle of incidence.
Let [tex]n_{2}[/tex] denote the refractive index of the second medium (in this example, the glass block.) Let [tex]\theta_{2}[/tex] denote the angle of refraction.
By Snell's Law:
[tex]n_{1} \, \sin(\theta_{1}) = n_{2}\, \sin(\theta_{2})[/tex].
Rearrange the equation to find an expression for [tex]n_{2}[/tex], the refractive index of the second medium (the glass block.)
[tex]\begin{aligned}n_{2} = \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1}\end{aligned}[/tex].
The refractive index of air is approximately [tex]1.00[/tex]. Substitute in the values and solve for [tex]n_{2}[/tex], the refractive index of the glass block:
[tex]\begin{aligned}n_{2} &= \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1} \\ &= \left(\frac{\sin(46^{\circ})}{\sin(26^{\circ})}\right)\times 1.00 \\ &\approx 1.64\end{aligned}[/tex].
Consider the dot diagrams for Objects A, B, and C. The arrow-
represents the direction of motion. Match the motion of
Objects A, B, and C to one of the lines on the graph.
Numbers can be used only one time.
A
2
B
Pos'n
3
С
-t
Tap
A matches graph:
B matches graph:
C matches graph:
4
5
6
--
Pos'n
t
I=24
Q=400C
t=102
Help please
[tex] \huge \bf༆ Answer ༄[/tex]
The given terms in the question are : -
I = Electric current = 2 AmperesQ = Charge = 400 CoulombsWe have been given the task to find out time (t)
The formula that can be used to find time is : -
[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]
Rearrange the formula,
[tex] \sf \: t = \dfrac { Q}{I }[/tex]
Solve for time (t)
[tex] \sf t = \dfrac{400}{2} [/tex][tex] \sf t = 200 \: \: sec[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
A teacher has two radioactive sources, A and B.
Source A has a longer half-life than source B.
What can be deduced about the nuclei in source A compared with the nuclei
in source B?
Do not refer to isotopes in your answer.
Answer:
The nuclei of source have greater stability than those of source B.
SOMEONE PLEASE HELP ME IM GOING INSANE 4 Select the correct answer. A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 x 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour? O A. -3.77 x 10-2 meters/second OB. -2.77 x 10-3 meters/second OC. -2.62 x 10-2 meters/second D. -5.55 x 103 meters/second
Hi there!
Since we are dealing with such large distances, we can approximate.
Recall that the equation for speed is:
displacement / time = velocity
OR:
d/t = v
Begin by converting one hour to seconds:
1 hr = 3600 sec
Now, we can solve for velocity:
(-2.0 × 10⁷) / 3600 = -5555.6 m/s ⇒ D: -5.55 × 10³ m/s
The temperature of a body is measured using the resistance of a wire. To calibrate the device the following measurements were taken (ohms is the unit of electrical resistance).
Resistance in melting ice 240 ohms.
Resistance in boiling water 250 ohms.
a. What is the change in resistance for a change in temperature of 1 Degree Celcius?
b. The wire is placed into some hot water and the resistance is mesured to be 246 ohms. What is the temperature of the water?
Answer:
A)250-240
=10+960
=970
NEED ANSWER ASAP!
Which statement about a converging lens is not correct?
A ray parallel to the principal axis of the lens is refracted through the principal focus.
B All rays of light refracted by the lens pass through the principal focus.
C The distance between the centre of the lens and the principal focus is the focal length
D The principal focus of the lens is a point on the principal axis.
Geometric optics allows you to find which the correct answer about which false statement is:
B) All rays of light refracted by the lens pass through the principal focus.
Geometric optics studies the formation of images using the light geometric properties of optical systems, the main expression for this is:
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
Where f is the focal length, p and q the distance to the object and the image respectively.
There are some points of special interest:
Object at infinity (p = ∞). In this case of the expression we see that the image is at the focal length. Image at infinity (q = ∞). In this case the object is at the focal point.
Let's analyze the claims.
A) True. A parallel ray comes from infinity and the image is formed at the focal point.
B) False. The image point is given by the expression above and depends on the distance to the object.
C) True. This is the definition of focal length.
D) True. All distances are measured from the main axis.
In conclusion, using geometric optics we can find that the correct answer about which false statement is:
B) All rays of light refracted by the lens pass through the principal focus.
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when calculating the binding energy, what is z multiplied by?
When calculating the binding energy, z multiplied by the sum of mass of proton and mass of electron.
What is z in binding energy?Z in binding energy calaculation is the number of protons in the nuclides.
Formula for binding energyTo calculate the binding energy we use the formula below;
E = Z (mp + me) + Nmn − mn
Where;
Z is the number of protons in the nuclides N is the number of neutronsmp is mass of protonme is mass of electronThus, when calculating the binding energy, z multiplied by the sum of mass of proton and mass of electron.
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Which phrase is best described as the energy of motion?
Answer:
The energy of motion is known as kinetic energy.
Explanation:
If a statue is made out of wood, which of these words correctly describes the statue?
OA.
wooded
ОВ.
woody
OC.
non-wood
OD.
wooden
Answer:
Od- Wooden
Explanation:
It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem. An OA justT o take or get a supply of wood. so its Od
Thirty Joules of energy are transferred out of a system. The energy is lost through heat, mechanical, and electrical energy. If mechanical energy took up 10 J and electrical energy took up 5 J, how many Joules were lost through heat energy?
OPTIONS
5 J
15 J
30 J
45 J
Answer:
its 15 J i belive
Explanation:
The internal energy is the total kinetic energy and __________ energy of all the particles that make up a system. What word completes the sentence?
Answer:
Potential
Explanation:
The internal energy is the total amount of kinetic energy and potential energy of all the particles in the system. When energy is given to raise the temperature, particles speed up and gain kinetic energy.
Hope this helps :)
on average, astronauts grow ________ percent in space.
Answer:
3
Explanation:
Astronauts in space can grow up to 3 percent taller during the time spent living in microgravity, NASA scientists say. That means that a 6-foot-tall (1.8 meters) person could gain as many as 2 inches (5 centimeters) while in orbit.
the electromagnetic waves with the highest frequencies are called