Answer: -200,000N
(To be more specific, 200,000N in the opposite direction)
Explanation:
By Newton's 3rd law (Action reaction pair)
The crumple zone exerts a force on the wall, the wall will exert an equal but opposite force on the wall.
Same magnitude -> 200,000N
Opposite direction-> Include a negative sign as force is a vector which depends on both magnitude and direction.
Bill weighs 160 lb. He is standing on a scale inside an elevator. What is the reading on the scale if the elevator is accelerating downward
the scale's readout if indeed the elevator is decelerating faster than 160 lb .
The elevator speeds up or down, right?Your perceived weight is equal to the normal force.Therefore, whenever the elevator accelerates or upwards downward, you truly feel tiny bit heavier than normal and a little lighter than usual.
If an elevator malfunctions, should you lay down?Any jump you make would only slow the lift's descent to the ground by a very small amount.Even though you could jump perfectly timed and with all the force your legs could produce, it would be pointless.Your greatest option, as opposed to jumping, is to fold down.
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Evaluate the expression a+b when a=23 and b=45 . Write in simplest form
A 600 g steel block rotates on a steel table (μk = 0.6) while attached to a 1.0 m long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.2 N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 50 N. If the block starts from rest, how many revolutions does it make before the tube breaks?
If the block starts from rest, then revolutions that it make before the tube breaks is 0.947 rotations.
What is meant by revolution?When object turns around an internal axis, it is called a rotation. When object circles an external axis, it is called revolution.
Given mass of block = 600 g = 0.6 kg ; Radius of rotation = 1.0 m-long
Given thrust force of 4.2 N
The maximum tension is 50 N.
As thrust is perpendicular to the tube. So, tangential component of the thrust force is Ft=4.2 N and radial component Fr=0
As we know, α = F/m r
= 4.2/0.6 * 1
α = 7 rad/s²
As, m r ω²= 50 N
ω² = 50/ 0.6 * 1.0
ω = 9.128 rad/s
Ф = ω² - ω0²/2α
= (9.128² - 0)/2 * 7
Ф = 5.951 rad
As 1 Radians = 0.1592 Rotations,
5.951 rad = 0.947 rotations.
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You weigh 600 N.
What would you weigh if the Earth were
seven times as massive as it is and its radius
were three times its present value?
Answer in units of N.
Your weight would be 85.7N if the Earth were seven times as massive as it is and had a radius three times that of today since the gravitational pull is reduced by seven times with an increase in radius.
Gravitation is a fundamental interaction in physics that produces attraction between all objects with mass or energy. Of the four fundamental interactions, gravity is by far the weakest, being about ten times less than the strong interaction. A body's mass is a fundamental characteristic. Before the discovery of the atom and the field of particle physics, it was generally thought to be tied to the amount of matter in a physical body. x = 600N/7, x = 85.7N
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A candy-filled piñata is hung from a tree for Matthew's birthday. During an unsuccessful attempt to break the 4. 4-kg piñata, Hayden cracks it with a 0. 54-kg stick moving at 4. 8 m/s. The stick stops and the piñata undergoes a gentle swinging motion. Determine the swing speed of the piñata immediately after being cracked by the stick
The velocity of the other piece of the pinata which has a mass of 3.86 kg
is 0.67 m/s
The mass of the candy-filled pinata = 4.4 kg
The mass of the first piece of the pinata = 0.54 kg
The velocity of the first piece of the pinata = 4.8 m/s
The mass of the second piece = 3.86 kg
The velocity of the other piece can be found using the formula,
mu = m₁v₁ + m₂v₂
where m is the mass of the pinata
u is the velocity of the pinata at rest
m₁,m₂ are the masses of the first and second pieces of pinata
v₁,v₂ is the velocity of the two pieces
Let us substitute the known values in the above equation, we get
4.4 x 0 = 0.54 x 4.8 + 3.86v₂
= 2.592 + 3.86v₂
3.86v₂ = -2.592
v₂ = 2.592/3.86
= 0.67 m/s
Therefore, the velocity of the other piece is 0.67 m/s
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Un carrusel da 90 vueltas en 3 minuto. ¿Cuál es la frecuencia y el período?
En el manual de una licuadora indica que el rotor da 7500 revoluciones por minuto. ¿Cuál es el período y la frecuencia?
ayudenme por favor
Answer:
I will help you but I don't understand the language
Which organism is a producer
Answer:
Producers are organisms that create food from inorganic matter. The best examples of producers are plants, lichens and algae, which convert water, sunlight and carbon dioxide into carbohydrates. Consumers are organisms that cannot create their food.
If an object takes 5 seconds to fall off a building, how high is the building?
if the bat and softball are in contact for 0.80m/s, what is the average force that the bat exerts on the ball
The changes in the momentum of the ball and the time over which that change occurs. The formula for average force is: average force = change in momentum/time.
Calculation-Given: The ball's mass is 0.144 kilogram.
speed v = 38 m/s, shift in momentum presently
P = m v- ( - mv) ( - mv)= 2 mv
=2 x (0.144) x (38) (38)
= 10.944 kg-m/s
t Impulse J=F.
The impulse is equivalent to the change in momentum.
J = 10.944 kg-m/s
What forces are at play when a baseball bat strikes a fastball?Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two different objects combined.
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Pitch a baseball horizontally at 38.0 m/s weighing 0.144 kg. The baseball moves in the opposite direction and at the same speed after being struck by the bat. What is the ball's change in momentum? What kind of impetus does the bat deliver? What was the average force the bat applied to the ball during the 0.80 milliseconds that they were in contact?
A 20.0 N force is applied at an angle of 40.0 degrees above the horizontal to a 4.00 kg box. The box moves a horizontal distance of 4.00 meters. Friction is negligible. The work done by the 20.0 N force is
a. 61.3 J.
b. 46.3 J.
c. 50.1 J.
d. 75.0 J.
Answer:
The work done by the 20 N force is 61.3 J
Explanation:
20 N Force at horizon is: F=20 N*cos 40=15.32 N
The work done by 20 N at horizon is: W=F*S=15.32 N* 4 m=61.3 J
Answer:
The work done by the 20 N force is 61.3 J
Explanation:
After falling for 5.5 seconds, what would be the final velocity of the object?
(Picture Provided)
Please I need help on this!
The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.
What is Final velocity?
The second approach determines the amount of velocity change brought on by acceleration over a given period of time.
Finally, the average velocity formula is used in the third section of the velocity calculator, which may be helpful if you need to examine trips with varying speeds across different distances.
According to the definition of velocity, it is the rate at which an object's position changes over time. Consideration of body motion is one of the fundamental ideas in classical mechanics.
Therefore, The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.
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Suppose a molecule has neutrons, a Coulomb total electric charge, and electrons. About how many protons must it have
molecule possesses neutrons and a total electric charge of one Coulomb. e is the electronic value, 1.60 x 10-19 Coulombs, and the proton has a cost of +e while the electron has a fee of -e.
How much is one coulomb?The quantity of charge carried by a present of one amp for one second is measured in coulombs, which is the unit of measurement used in the SI for electric charge. It may also be a quality of a substance that causes magnetic and electric effects to occur. The symbol for it is C. According to math, 1 Coulomb equals 1 Ampere x 1/sec.
A coulomb quizlet: what is it?A coulomb is an unit of power charge that represents the charge that is transmitted over one ampere of current in one second. Colomb's rule. depending on the charged items, electric force.
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A proton accelerates from rest in a uniform electric field of 660 N/C. At one later moment, its speed is 1.10 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. .81 Incorrect: Your answer is incorrect. m/s2 (b) Over what time interval does the proton reach this speed
Q is the charge's magnitude, V is its velocity, X is the angle formed by the magnetic field's direction and the charge's motion, and B is the strength of the magnetic field.
We must divide this amount by the mass of the charged particle or particles in order to determine the acceleration. Its speed at a later time is 1. 20 Mm/s (non relativistic because v is much less than the speed of light). When a refractive index diminishes over time, light shifts its frequency, which is referred to as photon acceleration [13,14]. Similar to charged particle acceleration, a rise in group velocity is accompanied by an increase in photon energy, or frequency.
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udora ran from her home to her secret laboratory at an average speed of 12\text{ km/h}12 km/h12, start text, space, k, m, slash, h, end text. She then took one of her jetpacks and flew to her school at an average speed of 76\text{ km/h}76 km/h76, start text, space, k, m, slash, h, end text. Eudora traveled a total distance of 120120120 kilometers, and the entire trip took 222 hours. How long did Eudora spend running, and how long did she spend flying using her jetpack
Eudora spent 0.5 hours from home to library and 1.5 hours from library to school.
Given that,
Average speed from home to library S₁ = 12 km/h
Average speed from library to school S₂ = 76 km/h
Total distance = 120 km
Time = 2 hrs
Let the time spent from home to library be x. So, from library to school will be = 2 - x
S₁ = 12 km/h
Time spent from home to library T₁ = x
S₂ = 76 km/h
Time spent from library to school T₂ = 2 - x
Distance can be calculated as, D₁ = S₁ T₁ = 12 x
D₂ = S₂ T₂ = 76(2 - x) = 152 - 76 x
As, D₁ + D₂ = 120
12 x + 152 - 76 x = 120
-64 x = -32
x = 0.5
So, T₁ = 0.5 hrs
T₂ = 2 - 0.5 = 1.5 hrs
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The height of an object is 10 cm, and the height of its image is 6 cm. What is the magnification?
Question 23 options:
4
16
0.6
1.67
magnification = [tex]\bf\dfrac{height of image}{height of object}[/tex]
= [tex]\bf\dfrac{6cm}{10cm}[/tex]
= 0.6
Which of the following accurately states the claim made by special relativity?
A. The speed of light in a vacuum is the same for stationary frames
of reference.
B. The speed of light in a vacuum is faster for accelerating frames of
reference.
C. The speed of light in a vacuum is the same for all frames of
reference.
D. The speed of light in a vacuum is slower for frames of reference
that have a constant velocity.
Answer:
The Answer is C
The speed of light in a vacuum is the same for all frames of reference.
Explanation:
Answer:
C .The speed of light in the vacuum is same for all frames of reference.
Explanation:
What do you understand by frame of reference?A set of abstract coordinate system that explains the position or motion of something mathematically and physically by the set of reference points and geometric points.
What is Special relativity ?
It explains the effect on mass ,time and space by the speed . It also relates the speed of light , mass and energy.
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when a falling firecracker explodes, the momenta of its pieces _______.
when a falling firecracker explodes, the momenta of its pieces vectorially add up to equal the initial momentum of the firecracker.
When the firecracker bursts, the vector sum of the momenta of its fragments adds up to the firecracker’s momentum just before bursting.
A falling firecracker explodes into two pieces. The momenta of the fragments combine by vector rules to equal the original momentum of the falling firecracker. Momentum is equal to mass multiplied by velocity.
According to the conservation of momentum, the initial momentum of the system is equal to the final momentum. The condition for the validity of momentum conservation is that no external force should exert on the system.
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If we have an unmarked magnet, how can we tell which end is the north pole of the magnet? a. Hold it near a compass and the north end of the compass points at the north end of the magnet. b. Hold it near a compass and the north end of the compass points at the south end of the magnet. c. Suspend it from a string and the end that points toward the geographic north pole (Santa's workshop) is the north end. d. Hold it near a piece of steel and the end that attracts the steel is the north end. e. The end that is attracted to the south end of a known magnet is the north end. f. The end that is attracted to the north end of a known magnet is the north end.
If we have an unmarked magnet, hold it near a piece of steel and the end that attracts the steel is the north end.
What is the magnet?
A magnet is an object made of certain materials that produces a magnetic field. This field is invisible but is responsible for the most notable property of a magnet: a force that pulls on other ferromagnetic materials, such as iron, and attracts or repels other magnets. Magnets are widely used throughout the world in a variety of applications, from the simple refrigerator magnet to the most advanced technologies such as MRI machines. Magnets come in many shapes and sizes and can be natural or artificial. The magnetic field of a magnet is caused by the motion of electric charges and is measured in guess.
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When a police officer observes a vehicle in motion, what are some things that the officer might notice about the manner in which the vehicle is being driving that indicate the driver might be impaired
Answer:
weaving of the car in motionTurning with a wide radius swerving Drifting from a LaneExplanation:
The motion of a vehicle been driven by an impaired driver will be different in some ways from a vehicle driven by an unimpaired driver
and what a police officer might observe/ notice will include some of the following :
weaving of the car in motionTurning with a wide radius swerving Drifting from a Lane
helpppppp please!!!!!
Answer:
6
Explanation:
Answer:
6 m/s
Explanation:
Velocity = Distance/Time
= 84 meters/14 seconds
= 6 m/s
Hope this helps! :)
calcula el potencial electrico de un punto B que se encuentra a 75cm de una varga positica q=9×10-6c
Answer:
V = 72000 volts
Explanation:
calculates the electric potential of a point B that is 75cm from a positive charge q = 9 × 10-6c
Given that,
Electric charge, [tex]q=9\times 10^{-6}\ C[/tex]
We need to find the electric potential of a point B that is 75 cm from this charge. The formula for the electric potential is given by :
[tex]V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6\times 10^{-6}}{0.75}\\\\V=72000\ V[/tex]
So, the electric potential is equal to 72000 Volts.
How long will it take for a body
accelerating by 2 m/s² to gain a
velocity of 10 m/s, starting from rest.
We are given:
Initial velocity (u) = 0 m/s [starting from rest]
Final velocity (v) = 10 m/s
Acceleration (a) = 2 m/s²
Time taken = t
Solving for time taken:
v = u + at [first equation of motion]
10 = 0 + (2)(t) [plugging the values]
10 = 2t
t = 5 seconds
What is the potential energy of a passenger jet weighing 7.0 x 10^5 N when it reaches a cruising altitude of 10.0 km?
Upon travelling at an altitude of 10.0 km, a passenger aircraft weighing 7.0 x [tex]10^{6}[/tex] N potential is the energy.
What similarities and differences do kinetic and potential energy share?Potential energy and kinetic energy are fundamentally different from one another because one is the energy of what can be and the other is the energy of what is. Or to put it another way, potential energy is immobile and ready to be unleashed;
When compared to potential energy, is kinetic energy greater?Due to the object's motion, kinetic energy loses some energy in the form of light energy, heat energy, and friction; these things do not occur in the potential energy, which is the reason why kinetic energy is not more than the potential energy.
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Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)
-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch
The astronaut being pushed back into his seat as the rocket accelerates - this was the example of Newton's first law of motion.
What is Newton's first law of motion?According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.
When the astronaut worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .
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1. A force of 60 Newtons is applied to the end of a wrench 0. 12 m long. How much torque is produced?
Answer: The amount of Torque produced is 7.2 Nm.
Explanation:
Given:
Force applied (F) to the end of a wrench = 60 Newton
Length of wrench = 0.12 meter
To find:
Quantity of Torque produced
Solution:
The quantity of Torque produced can be calculated from the following formula:
Ƭ = r F sin(θ)
Where,
Ƭ = Torque, r = radius, F = Force, (θ) = angle between F and the lever arm
In the given question,
r = 0.12,
F= 60,
(θ)= 900 {Since the force is applied at the end of a wrench, it must be perpendicular}
Torque (Ƭ) = 0.12* 60 * sin 900
= 7.2 m {sin 900 = 1}
Hence, in the given situation, 7.2 Nm Torque will be produced.
what are the Properties of Transverse Waves and Longitudinal wave
Answer:
Key terms
TermMeaningTransverse waveOscillations where particles are displaced perpendicular to the wave direction.Longitudinal waveOscillations where particles are displaced parallel to the wave direction
A 120 Kg man is diving off a 40 meter cliff. What is his kinetic energy when he is 10 meters from the water?
The required kinetic energy of man diving out at 10 m from water is calculated to be 35.3 kJ.
Given that,
Mass of the man m = 120 kg
Height of the cliff H = 40 m
Distance from the water surface h' = 10 m
The mathematical equation of velocity efflux is
v = √( 2g ( H - h') = √( 2 × 9.8(40-10) = 24.25 m/s
The expression for kinetic energy of the man = 1/2 m v²
K.E = 1/2 m v² = 1/2 × 120 × 24.25² = 35283.75 J = 35.3 kJ
Thus, we can conclude that the kinetic energy of man diving out at 10 m from water is 35.3 kJ.
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Warm air rising at the equator and cold air sinking at the poles is one reason for which type of movement of air?
Answer:
Convection cells
Explanation:
As the cold air moves away from poles, it begins to warm up. This warm air now becomes lighter and the pressure drops significantly at 60° N and 60° south latitude. The air from poles further gushes into these belts because the low pressure created. Thus, convection cells are formed because this rise and fall of air in circular pattern.
Hence, the name given is convection cells.
A capacitor has plates separated by
8.89 x 10-7 m. To create a
capacitance of 1.11 x 10-9 F, what
must the area of the plates be?
We know, formula of capacitance in parallel plate capacitor is given by :
[tex]C = \dfrac{\epsilon_o A}{d}[/tex]
Here, [tex]\epsilon_o = 8.85 \times 10^{-12} \ F.m^{-1}[/tex]
So,
[tex]A = \dfrac{Cd}{\epsilon_o}\\\\A = \dfrac{1.11 \times 10^{-9}\times 8.89 \times 10^{-7}}{8.85\times 10^{-12}}\\\\A = 1.11 \times 10^{-4}\ m^2 \ or \ 1.11 \ cm^2[/tex]
Hence, this is the required solution.
Answer:
7.09797297 • 10^-7
Explanation:
You just follow the formula:
C = εA/d
ε = 8.85 • 10^-12
A = 8.89 • 10^-7
D = 1.11• 10 ^-9
So:
C = (8.85 • 10^-12)(8.89• 10^-4)/1.11 • 10 ^-9 = 7.09797297 • 10^-7
Good Luck! :)
Part A
Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
The electric field in the region r ≤a is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
The total charge is enclosed within the Gaussian surface.
Q[tex]_{enc}[/tex] = 2Q - Q = Q
Therefore, applying Gauss's law over the Gaussian surface
∫[tex]_{s}[/tex]E.dS = Q[tex]_{enc}[/tex]/ε₀ ⇒ E.4πr² = Q/ε₀ ⇒ E = Q/4πε₀r²(r)
In question solution:
A[tex]_{sphere}[/tex] = 4πr²
ΦE = ∫E⋅dA
ΦE = q/ε₀
E = q/(A⋅ε₀)
E = q/(4πr²ε₀)
for r≤a, qin = -Q
E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
So, the electric field in the region is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
Your question is incomplete but most probably your full question was:
A uniformly charged ball of radius a and charge −Q is at the center of a hollow metal shell with inner radius b and outer radius c. The hollow sphere has a net charge of +2Q.
Part A: Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
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