What is 33.83 x 99.21
Find the absolute value. |1 - i|
Answer: 2
I couldn't find the answer on here so if anyone needs it here it is
15. A movie is
1 7/8
hours long. After 45 minutes, how much of the movie is left?
Step-by-step explanation:
67.5 minutes of the movie that was left
Andrea has as a jar full of quarters and dimes. Let q=
number of quarters and d= number of dimes. Which of the following expressions can be used to find the total amount of money in Andrea's jar?
a. 3.75q+0.50d
b. 2.50q+1.75d
c. 1.50q+0.50d
d. 0.25q+0.10d
ONLY ANSWER IF YOU KNOW!! STEPS ARE OPTIONAL
Answer:
d. 0.25q+0.10d
Step-by-step explanation:
Because quarters are equivalent to 0.25 and dimes are 10 cents, option d is correct.
The expression to find the total amount of money in Andrea's jar is: 0.25q + 0.10d.
Thus, option (D) is correct.
A quarter is worth $0.25, and the number of quarters is represented by q.
A dime is worth $0.10, and the number of dimes is represented by d.
To calculate the total amount of money, multiply the value of each coin by the respective quantity and sum them up.
So, the expression to find the total amounts is 0.25q + 0.10d
Here, expression accounts for the value of each coin (0.25 for a quarter and 0.10 for a dime) and multiplies it by the corresponding quantity to obtain the total amount of money in dollars.
Thus, option (D) is correct.
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In a class there are 27 students. If there are 7 more girls than boys in the class how many students are girls?
Answer:
10boys, 17 girls
Step-by-step explanation:
10+17=27,
17-10=7
Answer: there are 17 girls in the class
Step-by-step explanation:
let the number of boys be x
and the number of girls be re[presented as 7+x
Since there are a class of 27 containing the sum of the boys and girls, we have our equation as
boys +girls =27
x+ 7+x=27
7+2x =27
2x=27-7
2x=20
x=20/2=10
Boys =x=10
girls= 7+x=7+10=17
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Select all that apply please!
Answer:
x= –4/5 , x= 2
Step-by-step explanation:
5x²-6x-14=-6
5x² –6x –14 +6=0
5x²–6x –8=0
(5x+4)(x-2)=0
x=–4/5
x=2
Hi! I'm happy to help!
To solve this, we simply have to replace x with the given values.
First, we have -14, let's apply that:
(5·(-14²))-(6·(-14))-14=
Now, let's solve (using the order of operations):
(5·(-14²))-(6·(-14))-14=
(5·196)-(6·(-14))-14=
980-(6·(-14))-14=
980-(-84)-14=
980+84-14=
1064-14=
1050=
1050≠-6
Option 1 is incorrect.
Next, let's substitute 14 for x:
(5·14²)-(6·14)-14=
Now, let's solve:
(5·14²)-(6·14)-14=
(5·196)-(6·14)-14=
980-(6·14)-14=
980-84-14=
896-14=
880=
880≠-6
Option 2 is incorrect.
Now, let's substitute -7 for x:
(5·(-7²))-(6·(-7))-14=
Now, let's solve:
(5·(-7²))-(6·(-7))-14=
(5·49)-(6·(-7))-14=
245-(6·(-7))-14=
245-(-42)-14=
245+42-14=
287-14=
273=
273≠-6
Option 3 is incorrect.
Now, let's substitute 7 for x:
(5·7²)-(6·7)-14=
Now, let's solve:
(5·49)-(6·7)-14=
245-(6·7)-14=
245-42-14=
203-14=
189=
189≠-6
Option 4 is incorrect.
Now, let's substitute -2 for x, and solve:
(5·(-2²))-(6·(-2))-14=
(5·4)-(6·(-2))-14=
20-(6·(-2))-14=
20-(-12)-14=
20+12-14=
32-14=
18=
18≠-6
Option 5 is incorrect.
Now, let's substitute 2 for x and solve:
(5·2²)-(6·2)-14=
(5·4)-(6·2)-14=
20-(6·2)-14=
20-12-14=
8-14=
-6=
-6=-6
Option 6 is correct.
Now, let's substitute -1 for x and solve:
(5·(-1²))-(6·(-1))-14=
(5·1)-(6·(-1))-14=
5-(6·(-1))-14=
5-(-6)-14=
5+6-14=
11-14=
-3=
-3≠-6
Option 7 is incorrect.
Now, let's substitute 1 for x and solve:
(5·1²)-(6·1)-14=
5-(6·1)-14=
5-6-14=
-1-14=
-15=
-15≠-6
Option 8 is incorrect.
Now, let's substitute -4/5 for x and solve:
(5·(-4/5²))-(6·(-4/5))-14=
(5·0.64)-(6·(-4/5))-14=
3.2-(6·(-4/5))-14=
3.2-(-4.8)-14=
3.2+4.8-14=
8-14=
-6=
-6=-6
Option 9 is correct.
Now let's substitute 4/5 for x and solve:
(5·4/5²)-(6·4/5)-14=
(5·0.64)-(6·4/5)-14=
3.2-(6·4/5)-14=
3.2-4.8-14=
-1.6-14
-15.6
-15.6≠-6
Option 10 is incorrect.
To summarize, you should pick option 6, and option 9.
I hope this was helpful, keep learning! :D
please answer I don't know why I'm in pre-algebra in 7th grade
Answer:
D
Step-by-step explanation:
a^5 (3) -> a^15
2^3 (3) -> 2^9
the answer = a15 . 2^9
What is the distance
between the points (4,20)
and (6,9)?
Answer:
68.88m
Step-by-step explanation:
√(x²-x²)²+(y²-20)²
Point M is the midpoint of AB. The coordinates of point A are (−6, 2) and the coordinates of M are (−4, 1). What are the coordinates of point B?
Answer:
-2 ,2
Step-by-step explanation:
3.3 to the power of 2
Answer:
10.89
Step-by-step explanation:
3.3 to the power of two is just saying 3.3 squared. which is just multiplying the number by itself.
so 3.3 times 3.3 = 10.89
Given: f(x) = x - 7 and h(x) = 2x + 3
Write the rule for h(f(x)).
Oh(f(x)) = 2x - 11
Oh(f(x)) = 2x - 7
O h(f(x)) = 2x - 4
o h(f(x)) = 3x - 4
the answer is A then the next one is B
Answer:
h(f(x))
=2(x-7)+3
=2x-14+3
=2x-11
Answer:
a the b is correct
Step-by-step explanation:
A regular hexagon is a six sided figure with all sides equal and all six angles equal. Find the length of the sides if the perimeter of the regular hexagon is 462 ft.
Answer: 77 feet
Explanation:
Because all sides are the same for a regular hexagon, we simply divide the perimeter by 6 to get the side length.
side length = perimeter/6 = 462/6 = 77 feet
5 thousand is ———————- times as many as 5 hundred
Answer:
Ten
Step-by-step explanation:
5000/500 = 10
Answer: 10 times as many 5 hundreds
Step-by-step explanation: five times five hundreds equals 5,000
A car has been purchased for £5200 and is estimated to have an expected life driving 200,000
miles. At the end of that time its value is estimated to be £200. If the units-of-production
method is used to depreciate the car,
a) What is depreciation cost per mile?
b) What will be book value of the car after it has driven 55000 miles?
Answer:
a) 0.025£ b)3825£
Step-by-step explanation:
a) 5200-200=5000 - of the value will be lost after reaching the milleage of 200000 miles
200000-5000
1-x
200000=5000/x
x=5000/200000= 5/200=1/40=0.025£- the depreciation cost per mile
b)0.025*55000= 1375- the decreasing of the price
5200-1375=3825£- the book value of the car after it has driven 55000 miles
factoring quadratics 4x^2-13x+3=0
Answer:
X=3,1/4
Step-by-step explanation:
4x²-(12+1)x+3=0
or,4x²-12x-x+3=0
or,4x(x-3)-1(x-3)=0
or,(4x-1)(x-3)=0
Either,4x-1=0➡️ 4x=1
X=1/4
OR,x-3=0➡️ X=3
Answer these questions
Step-by-step explanation:
B)1.supplementary
2.complementary
3complementary
4supplementary
5supplementary
6complementary
C)1.40
2.35
3.63
4.130
Given f(x) = 2x+1 and g(x) = 7/4x + 1 what is the value of f(1)-g(-4)
A) -3 B) 3 C) 9 D) -9
Answer:
c)9
Step-by-step explanation:
f(x)=2x+1
f(1)=2(1)+1
f(1)=2+1
f(1)=3
g(x)=7/4 x+1
g(-4)=7/4 (-4)+1
g(-4)=-7+1
g(-4)=-6
f(1)-g(-4)=3-(-6)
=3+6
=9
Note:if you need to ask any question please let me know.34.8% female doctors 48,200 total female what was the total number of registered doctors
Find the distance between the points. Give an exact answer and an approximation to three decimal places.
(-7,9) and (-2,4)
ABC Company sells a certain product line at an established price of Br 42 per unit The variable cost per unit is Br 36. The fixed cost for the year amounts to Br 540,000 Next year the selling price is to be increased to Br 45perunit. How many units had to be sold at the old established price each year in order to Breakeven
90,000 units of the product has to be sold each year in other to break even.
The old established price = 42 per unit :
The break even unit is the number of units sold such that the net profit = 0
(expenses - income) = 0
The expenses = (Fixed cost + variable cost)
Fixed cost = 540000
Fixed cost = 540000Variable cost per unit = 36
Let the number of units required to break even = x
Expenses = income or revenue
(540000 + 36x) = 42x
540000 + 36x = 42x
540000 = 42x - 36x
540000 = 6x
x = 540000 / 6
x = 90000
Hence, 90,000 units has to be sold at the old established price in other to break even.
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A triangle has an area of 400 square inches. The length of the base of the triangle is 10 inches. What is the height of the triangle?
Answer:
80 in
Step-by-step explanation:
A = 1/2bh
400 = 1/2(10)h
400 = 5h
h = 80
If my answer is incorrect, pls correct me!
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-Chetan K
is -81,572 ratonal or irrational
Answer:
rational
Step-by-step explanation:
as it is of the form p/q
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write all prime numbers from 20 to 50.
Answer:
So, 23, 29, 31, 37, 41, 43 and 47 these are the prime numbers between 20 and 50.
Step-by-step explanation:
plz mark me brainliest
Answer:
So the prime numbers between 20 and 50 are so easy
- 23, 29, 31, 37, 41, 43 and 47
these are the prime numbers between 20 and 50
Step-by-step explanation:
Hope it helps
If Angle 1 = 26, find the measure of angle 4
Answer:
104
Step-by-step explanation:
The measure of angle 4 for the given parallel lines and angle is equal to 26°.
In the figure the parallel lines and the transversal forms angle 1 , angle 2 , and angle 4.
As per the diagram,
Angle 1 is vertically opposite angle to angle 2.
This implies,
Measure of angle 1 = Measure of angle 2.
Here, Measure of angle 1 = 26 degrees.
⇒ Measure of angle 2 = 26 degrees ( vertically opposite angles)
Now , Angle 2 and angle 4 are corresponding angles.
⇒measure of angle 2 = measure of angle 4
⇒ Measure of angle 4 = 26 degrees.
Therefore, the measure of angle 4 is equal to 26°.
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6 Explain in words how to simplify: (153 to the 2nd power times 7
Step-by-step explanation:
153^2×7
163863
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¿How to solve with logarithms?
See image please
Answer:
Step-by-step explanation:
Apply the natural log to both sides we have
[tex](-(2/3)x -1 ) \ln 2 = (3-2x)\ln 3\\-x(2/3)\ln 2 + 2x\ln 3 = 3\ln 3 -\ln 2\\x\left(\frac{-2}{3}\ln 2 +2\ln 3\right)=\ln (27/2)\\x\left(\ln 9 -\ln \sqrt{8}) =\ln(27/2)\\\\x\ln (9/\sqrt{8})=\ln(27/2)\\\\x= \ln(27/2) / \ln(9/\sqrt{8})[/tex]
In the problem · N = 1, N must be
Answer:
the value of N should be -1
Please help answering the question
Answer:
I don't know jdjdjdcisveobeobeoxbepxbeoxbwp
simplify each of the following.
[tex](2 \sqrt{3 + \sqrt{2)}{2} [/tex]
Answer:
[tex] \sqrt{2} + 2 \sqrt{3} [/tex]
Step-by-step explanation:
Simplify
[tex]2 \sqrt{3 } + \sqrt[2]{2} [/tex]
➡️ [tex] = \sqrt{2} + 2 \sqrt{3} [/tex] ✅
3. A ball is dropped initially from a height of 1.2 m. The rebound from the floor is 3/5 of the previous height.
(a) Find the height to which the ball rises at the 2nd bounce.
(b) Find the total distance that the ball has travelled when it hits the floor for the tenth time.
(c) Assuming that the ball continues to bounce in the same way indefinitely, find the total distance that the ball travels.
Answer:
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is