Use the definition:
f'(x)=[tex]\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
to find f'(x) for:
f(x)=[tex]\frac{1}{\sqrt{x}}[/tex]+x
I need the WORK, not the answer. Thanks!
Using the given definition, for [tex]f(x)=\frac1{\sqrt x}+x[/tex], we have
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\left(\frac1{\sqrt{x+h}}+x+h\right)-\left(\frac1{\sqrt x}+x\right)}h[/tex]
Right away, we see x and -x in the numerator, so we can drop those terms.
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\frac1{\sqrt{x+h}}+h-\frac1{\sqrt x}}h[/tex]
Remember that limits distribute over sums, i.e.
[tex]\displaystyle\lim_{x\to c}(f(x)+g(x))=\lim_{x\to c}f(x)+\lim_{x\to c}g(x)[/tex]
so we can separate the h from everything else in the numerator:
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\frac1{\sqrt{x+h}}-\frac1{\sqrt x}}h+\lim_{h\to0}\frac hh[/tex]
Since h ≠ 0, we have [tex]\frac hh=1[/tex], so the second limit is simply 1.
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\frac1{\sqrt{x+h}}-\frac1{\sqrt x}}h+1[/tex]
For the remaining limit, focus on the numerator for now. Combine the fractions in the numerator:
[tex]\dfrac1{\sqrt{x+h}}-\dfrac1{\sqrt x}=\dfrac{\sqrt x-\sqrt{x+h}}{\sqrt x\sqrt{x+h}}[/tex]
Recall the difference of squares identity,
[tex]a^2-b^2=(a-b)(a+b)[/tex]
Let [tex]a=\sqrt x[/tex] and [tex]b=\sqrt{x+h}[/tex]. Multiply the numerator and denominator by [tex](a+b)[/tex], so that the numerator can be condensed using the identity above.
[tex]\dfrac{\sqrt x-\sqrt{x+h}}{\sqrt x\sqrt{x+h}}\cdot\dfrac{\sqrt x+\sqrt{x+h}}{\sqrt x+\sqrt{x+h}}[/tex]
[tex]=\dfrac{(\sqrt x)^2-(\sqrt{x+h})^2}{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}[/tex]
[tex]=\dfrac{x-(x+h)}{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}[/tex]
[tex]=-\dfrac h{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}[/tex]
Back to the limit: all this rewriting tells us that
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{-\frac h{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}}h+1[/tex]
Again, the h's cancel, and we can pull out the factor of -1 from the numerator and simplify the fraction:
[tex]f'(x)=\displaystyle-\lim_{h\to0}\frac1{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}+1[/tex]
The remaining expression is continuous at h = 0, so we can evaluate the limit by substituting directly:
[tex]f'(x)=-\dfrac1{\sqrt x\sqrt{x+0}(\sqrt x+\sqrt{x+0})}+1[/tex]
[tex]f'(x)=-\dfrac1{2x\sqrt x}+1[/tex]
or, if we write [tex]\sqrt x=x^{1/2}[/tex], we get
[tex]f'(x)=-\dfrac12x^{-3/2}+1[/tex]
Raoul make shell necklaces to sell at a craft fair. the supplies for each necklace cost $3.75. Raoul sells the necklaces for $11.25. what is the percent markup for a shell necklace?
Answer: The percent markup for a shell necklace = 200%
Step-by-step explanation:
Given: Cost price per necklace = $3.75
Selling price per necklace = $11.25
Mark up = (Selling price - Cost price )
= $ (11.25 -3.75 )
=$ 7.5
The percent markup for a shell necklace = [tex]\dfrac{\text{Mark up}}{\text{cost price}}\times100\%[/tex]
[tex]=\dfrac{7.5}{3.75}\times100\%\\\\=2\times100\%=200\%[/tex]
Hence, The percent markup for a shell necklace = 200%
The percent markup for a shell necklace is 200%.
Definition of markupMarkup can be defined as the rate at which the cost of a product is increased. The higher the markup, the higher the profit earned by a seller all things being equal.
Calculation of percentage markupPercentage markup = (profit / cost price) x 100
Profit = $11.25 - $3.75 = $7.50
Percentage markup = ($7.50 / $3.75) x 100 = 200%
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A certain test preparation course is designed to help students improve their scores on the MCAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 7 students' scores on the exam after completing the course: 37,12,12,17,13,32,23 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.
Answer:
The 80% confidence interval for the average net change in a student's score after completing the course is (15.4, 26.3).
Step-by-step explanation:
The net change in 7 students' scores on the exam after completing the course are:
S = {37 ,12 ,12 ,17 ,13 ,32 ,23}
Compute the sample mean and sample standard deviation as follows:
[tex]\bar x=\frac{1}{n}\sum x=\frac{1}{7}\times 146=20.857\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}}=\sqrt{\frac{1}{7}\times 622.8571}=10.189[/tex]
As the population standard deviation is not known, a t-interval will be formed.
Compute the critical value of t for 80% confidence interval and 6 degrees of freedom as follows:
[tex]t_{\alpha/2, (n-1)}=t_{0.20/2, (7-1)}=t_{0.10,6}=1.415[/tex]
*Use a t-table.
Compute the 80% confidence interval for the average net change in a student's score after completing the course as follows:
[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\times\frac{s}{\sqrt{n}}[/tex]
[tex]=20.857\pm 1.415\times\frac{10.189}{\sqrt{7}}\\\\ =20.857\pm 5.4493\\\\=(15.4077, 26.3063)\\\\\approx (15.4,26.3)[/tex]
Thus, the 80% confidence interval for the average net change in a student's score after completing the course is (15.4, 26.3).
What is the difference between 65 and -25?
Answer:
40?
Step-by-step explanation:
it literally tells you?
Answer:
90 because 65 plus 25 is 90.
Step-by-step explanation:
65 plus 25 is 90 and
R
(x + 1)
(3x - 5)
S
Р
What is mzPQR ?
Supposed y varies directly as x and y =21 when x=3
4x + 10 + 3x = 40 - 3x
O A. x = 3
B. X=
x = 1
15
2
25
O C. X=
2
O D. x = 5
Answer:
a. 3
Step-by-step explanation:
Answer:
(A) X = 3
Step-by-step explanation:
-_-
Why is near impossible to draw a rhombus on Geoboard and easy to draw a square?
Thank you in advance :)
Answer: Think about diagonal sides and horizontal bases.
Step-by-step explanation: "Think outside of the box." as they say.
See the screenshot attached.
A jar that contains quarters and dimes is worth $7.15. If there are a total of 40 coins,
how many of each type of coin is there?
Answer:
21 quarters and 19 dimes
Step-by-step explanation:
Create a system of equations where q is the number of quarters and d is the number of dimes.
0.25q + 0.1d = 7.15
q + d = 40
Solve by elimination by multiplying the bottom equation by -0.25
0.25q + 0.1d = 7.15
-0.25q - 0.25d = -10
Add them together and solve for d:
-0.15d = -2.85
d = 19
Then, plug in 19 as d into the second equation to solve for q:
q + d = 40
q + 19 = 40
q = 21
So, there are 21 quarters and 19 dimes
Answer:
21 Quarters, 19 Dimes.
Step-by-step explanation:
21 x .25 = 5.25
19 x .10 = 1.90
5.25 + 1.90 = 7.15
what statement makes the open sentences 12+3x= 30 true hurry!!!!
Answer: X=6
you would do 30 - 12 witch equals 18
than you would do 18 divided by 3 witch is 6 so it is x = 6
tan theta equals 8 / 15 find sine theta + cos theta / cos theta (1 - cos theta)
I guess you have to find
[tex]\dfrac{\sin\theta+\cos\theta}{\cos\theta(1-\cos\theta)}[/tex]
given that [tex]\tan\theta=\frac8{15}[/tex].
We can immediately solve for [tex]\sec\theta[/tex]:
[tex]\sec^2\theta=1+\tan^2\theta\implies\sec\theta=\pm\dfrac{17}{15}[/tex]
(without knowing anything else about [tex]\theta[/tex], we cannot determine the sign)
Then we get [tex]\cos\theta[/tex] for free:
[tex]\cos\theta=\dfrac1{\sec\theta}=\pm\dfrac{15}{17}[/tex]
and we can now solve for [tex]\sin\theta[/tex]:
[tex]\sin^2\theta+\cos^2\theta=1\implies \sin\theta=\pm\dfrac8{17}[/tex]
Notice that we have 2*2 = 4 possible choices of sign for either sin or cos.
• If both are positive, then
[tex]\dfrac{\sin\theta+\cos\theta}{\cos\theta(1-\cos\theta)}=\dfrac{391}{90}[/tex]
• If both are negative, then
[tex]\dfrac{\sin\theta+\cos\theta}{\cos\theta(1-\cos\theta)}=\dfrac{391}{480}[/tex]
• If sin is positive and cos is negative, then
[tex]\dfrac{\sin\theta+\cos\theta}{\cos\theta(1-\cos\theta)}=\dfrac{119}{480}[/tex]
• If cos is positive and sin is negative, then
[tex]\dfrac{\sin\theta+\cos\theta}{\cos\theta(1-\cos\theta)}=\dfrac{119}{30}[/tex]
Kyle is drawing a rectangle on the coordinate plane. Which coordinate pair could be Point M, the missing vertex of the rectangle?
Answer:
Step-by-step explanation:
5,2
PLZ HELP WILL GIVE BRAINLIST
A. A number less than 2
B. A number greater than 1
C. An odd number
D. A multiple of 2
Answer:
Option A
Step-by-step explanation:
The answer is option A "A number less than 2." That is because we check off each of the following given options. It won't be option C because they're 4 odd numbers a equal amount of multiplies of two (option D) which means they both have a equal (4 out of 8) chance. It won't be option B because they're 7 out of 8 numbers that are greater then on which means you have a greater chance of getting a number greater then one but the question is asking for the most unlikely.....therefore the answer is option A because you have a 1 out of 8 chance of getting a number less then two.
Hope this helps.
Which of the following is the value or PQ
Answer:
B. 61
Step-by-step explanation:
Given:
∆PQR ≅ ∆PQS
PQ = 2x + 41
QS = 7x - 24
QR = 3x + 16
Required:
Numerical value of PQ
SOLUTION:
First, create an equation to find the value of x as follows:
Since both triangles are congruent, therefore:
QS = QR
7x - 24 = 3x + 16 (Substitution)
Collect like terms
7x - 3x = 24 + 16
4x = 40
Divide both sides by 4
4x/4 = 40/4
x = 10
Find PQ by plugging x = 10 into PQ = 2x + 41
PQ = 2(10) + 41
PQ = 20 + 41
PQ = 61
What is (8p - 2)(6p + 2)
answer:
48p² + 4p - 4
solution:
8p × 6p +8p × 2 - 2 × 6p - 2 × 2
48p² + 8p x 2 - 2 ×6p - 2 × 2
48p² + 16p - 12p - 4
48p² + 4p - 4
The required algebraic product is 48[tex]p^{2}[/tex] + 4p - 4.
Given the two binomial (8p - 2)(6p + 2).
To multiply two binomials, take the first term of the first binomial and multiply with the entire second binomial and positive or negative as per given in the first binomial ,take the second term of the first binomial and multiply with the entire second binomial.
Let a, b, c and d be any four variables. Consider (a - b)(c + d) gives
a(c + d) - (c + d).
That implies, (8p - 2)(6p + 2) = 8p(6p + 2) - 2(6p + 2)
Multiply by removing the brackets gives,
(8p - 2)(6p + 2) = 48[tex]p^{2}[/tex] + 16p - 12p - 4
Combining like terms and algebraic sum gives,
(8p - 2)(6p + 2) = 48[tex]p^{2}[/tex] + 4p - 4.
Hence, the required algebraic product is 48[tex]p^{2}[/tex] + 4p - 4.
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Please help ❤️ What percent of 24 is 15?
Answer:
62.5
Step-by-step explanation:
There ya gooo :)
Answer:
62.5%
Here You go
Step-by-step explanation:
Is this a function or not a function? (Picture)
Simplify. 863x14y9−−−−−−√
Answer: 1
Step-by-step explanation: 863x14ysqrt9= 3 simplified is 1
find the coordinates of the point 3/10 of the way from A to B
Answer:
the coordinates of b is (9,7)
the coordinates of a is (-4,-6)
Step-by-step explanation:
Suppose C and D represent two different school populations where C > D and C and D must be greater than 0
Answer:
Step-by-step explanation:
Which graph shows the line y = - 3x + 1
Answer:
i need a picture
Step-by-step explanation:
Solve for y
1/3y+2=1/7y
Answer:
y=2
y=0
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
7*y-1-(3*y^2+y-1)=0
(7y - 1) - ((3y2 + y) - 1) = 0 3.1 Pull out like factors :
6y - 3y2 = -3y • (y - 2)
Answer:
y = -21/2
Step-by-step explanation:
multiply both sides of the equation by 21 so it would be
7y+42=3y
move the terms
7y-3y=-42
collect like terms
4y=-42
divide both sides by four
y= -21/2
Please help me guys!!!
The area of a rectangle is x²-4x-21
Write down an expression for the width and the length of
the rectangle.
Answer:
Step-by-step explanation:
Area of rectangle= Length x Width
and the given Area is a quadratic expression
A=[tex]x^{2} -4x-21[/tex]
We use the factorization method so,
we need 2 numbers that when multiplied we get -21 and when we add/subtract we get -4 so,
A=[tex]x^{2} -7x+3x-21[/tex]
now we simplify,
A=[tex]x(x-7)+3(x-7)[/tex]
A=[tex](x-7)(x+3)[/tex]
This looks familiar doesn't it, when we write the formula for the area of rectangle its
A= Length x Width and the equation here shows that
A= [tex](x-7)(x+3)[/tex]
So the expression for the length is x-7 and
the expression for the width is x+3 i think u have missed maybe some information on the question as such that the perimeter might be missing because length could be either x-7 or even x+3 same goes for width maybe someone can correct me if im wrong
Three times a number, increased by one, is between negative eleven and seven. Find all the numbers
Answer:
7 < 3N+1 < 11
6 < 3n < 10
2 < n < 10/3
Step-by-step explanation:
The required number is -3, -2, -1, 0, and 1 which is three times a number, increased by one, is between negative eleven and seven.
Given that,
Three times a number, increased by one, is between negative eleven and seven. the number is to be determined.
Inequality can be defined as the relation of the equation containing the symbol of ( ≤, ≥, <, >) instead of the equal sign in an equation.
here,
Accoding to the condition let the number be x,
and
-11 < 3x + 1 < 7
-12 < 3x < 6
-4 < x < 2
So the number are -3, -2, -1, 0, anb 1
Thus, the required number is -3, -2, -1, 0, and 1 which is three times a number, increased by one, is between negative eleven and seven.
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what type of number is 18.62?
that is a rational number.
Find the equation of the line in
slope Intercept form if the
line passes through the
points (-5, -1) and (-4, -1)
Answer:
y=0x-1
Step-by-step explanation:
Slope-int form: y=mx+b
Both points have the same y value and different x values, so the slope (m) is 0.
Since the y-intercept is (0, -1), b=-1
Is perpendicular to the line y = 2x + 1
and through the point (-1,5)
Answer:
-2x+3
Step-by-step explanation:
Using y=mx+b
To make the line perpendicular, you just need to make the slope (m=2) negative. To make it go through (-1, 5), you just need to adjust the b value to raise the graph to a point where it will pass through the point.
some helps plssss i need help
Answer:
Yess
Step-by-step explanation:
If you multiply all the numbers together you get 39690000. And the square root of that number is 6300. So it is a perfect square. If you did 6300² = 39690000.
An expression is shown below if this expression is equivalent to 60, what must be the value of a? A.) 3 B.) 4 C.) 9 D.)16
Answer:
Option (A)
Step-by-step explanation:
Given expression is,
[tex]5\sqrt{48a}=60[/tex]
Squaring on both the sides of the equation,
[tex](5\sqrt{48a})^2=(60)^2[/tex]
25(48a) = 3600
1200a = 3600
By dividing the equation by 1200,
a = [tex]\frac{3600}{1200}[/tex]
a = 3
Therefore, Option (A) will be the answer.