In the accompanying diagram, AB is a diameter of circle O, FECA and
FBG are secants, AD, DE, EB = 1:3:2 and BG = 40°. Find the measures of AD,
DE, EB, and AG.

Answer:

I CANT DO IT

Step-by-step explanation:

THE PICTURE IS BROKEN

Answer:

2nd one

Step-by-step explanation:

if you were to look on a grid the slope would point up

Answer:

Answer 10,006

Step-by-step explanation:

We are Multiplying.

Answer:

157.78

Step-by-step explanation:

Solve each shape individually

For the square, we are given both side lengths so multiply them to find its area

9.8 x 8.7 = 85.26m

For the triangle on the right, we know the base and height lengths, so multiply them and divide by two to find the area

9.8 x 7.2 = 70.56 / 2 = 35.28m

For the triangle on the left, we can find the base by subtracting the side length of the square from the length given on the bottom

16.3 - 8.7 = 7.6

We know the height for this triangle so multiply that by the number you just found and divide by two to find the area

9.8 x 7.6 = 74.48 / 2 = 37.24m

Finally add all of the areas found together to get the total area of the trapezoid

37.24 + 35.28 + 85.26 = 157.78

Answer:

This is an acute angle since it measures less than 90 degrees.

Answer:

Step-by-step explanation:

a. 4 outcomes as there are 4 different colours.

b. 3 ways - getting a blue green or yellow card.

#1

ac=6(-2)=-12

#2

#3

ac=-24

Answer:

(a)  [tex](2x-3)(x+2)[/tex]

(b)  [tex](5a-1)(2a+1)[/tex]

(c)  [tex](2c-3)(c+4)[/tex]

Step-by-step explanation:

To factor a quadratic in the form [tex]ax^2+bx+c[/tex]

Part (a)

Given expression:  [tex]2x^2+x-6[/tex]

[tex]\implies ac=2 \cdot -6=-12[/tex]

Factors of -12 that sum to 1:  4 and -3

[tex]\implies 2x^2+4x-3x-6[/tex]

Factor first two terms and last two terms separately:

[tex]\implies 2x(x+2)-3(x+2)[/tex]

Factor out common term [tex](x+2)[/tex]:

[tex]\implies (2x-3)(x+2)[/tex]

Part (b)

Given expression: [tex]10a^2+3a-1[/tex]

[tex]\implies ac=10 \cdot -1=-10[/tex]

Factors of -10 that sum to 3:  5 and -2

[tex]\implies 10a^2+5a-2a-1[/tex]

Factor first two terms and last two terms separately:

[tex]\implies 5a(2a+1)-1(2a+1)[/tex]

Factor out common term [tex](2a+1)[/tex]:

[tex]\implies (5a-1)(2a+1)[/tex]

Part (c)

Given expression: [tex]2c^2+5c-12[/tex]

[tex]\implies ac=2 \cdot -12=-24[/tex]

Factors of -24 that sum to 5: 8 and -3

[tex]\implies 2c^2+8c-3c-12[/tex]

Factor first two terms and last two terms separately:

[tex]\implies 2c(c+4)-3(c+4)[/tex]

Factor out common term [tex](c+4)[/tex]:

[tex]\implies (2c-3)(c+4)[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

[tex]\qquad \tt \dashrightarrow \:\dfrac{d}{dx} \left[ \sin^{-1}(\cos e^x)-\cos^{-1}(\sin e^x) \right][/tex]

[tex]\qquad \tt \dashrightarrow \:\dfrac{d}{dx} \sin^{-1}(\cos e^x) - \dfrac{d}{dx}\cos^{-1}(\sin e^x) [/tex]

[tex]\qquad \tt \dashrightarrow \: \bigg(\dfrac{1}{ \sqrt{1 - ( \cos( {e}^{x} ) ) {}^{2} } } \times - \sin( {e}^{x} ) \times {e}^{x} \bigg) - \bigg( - \dfrac{1}{ \sqrt{1 - ( \sin( {e}^{x} )) {}^{2} } } \times \cos( {e}^{x} ) \times {e}^{x} \bigg)[/tex]

[tex]\qquad \tt \dashrightarrow \: \bigg(\dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{1 - ( \cos( {e}^{x} ) ) {}^{2} } } \bigg) - \bigg( - \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{1 - ( \sin( {e}^{x} )) {}^{2} } } \bigg)[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{1 - \cos {}^{2} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{1 - \sin {}^{2} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{ { \sin}^{2} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{ \cos {}^{2} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ { { \sin}^{} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ { \cos {}^{} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: - {e}^{x} + {e}^{x} [/tex]

[tex]\qquad \tt \dashrightarrow \:0[/tex]

I hope this helps, if you find any problem with steps or got a mistake in my explanation then feel free to ask me ~

Answer:

Let x = son's age

Let 38-x = Mr. Bellini's age (since the sum of their ages must be equal to 38)

Set up the equation using the second statement:

(38 - x) - 4 = 5(x - 4)

Solving,

34 - x = 5x - 20

34 + 20 = 6x

54 = 6x

x = 9 years old (son's age)

38-x = 29 years old (Bellini's age)

Answer: 5

Step-by-step explanation:

lower quartile: 4

upper quartile: 9

9-4=5

IQR=5

Answer:

Step-by-step explanation:

LCD (15,20) = 60

[tex]\frac{2}{15}[/tex] + [tex]\frac{1}{20}[/tex] = [tex]\frac{8}{60}[/tex] + [tex]\frac{3}{60}[/tex] = [tex]\frac{11}{60}[/tex]

Answer:

2/15 + 1/20 = 11/60

Step-by-step explanation:

1. Find the least common denominator or LCM of the two denominators:

15 and 20.

Steps to find LCM:

1. Find the prime factorization of 15

15 = 3 × 5

2. Find the prime factorization of 20

20 = 2 × 2 × 5

3. Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM:

LCM = 2 × 2 × 3 × 5

LCM = 60

2. Next, find the equivalent fraction of both fractional numbers with denominator 60.

For the 1st fraction, since 15 × 4 = 60,

2/15 = 2 * 4 / 15 * 4 = 8/60

Likewise, for the 2nd fraction, since 20 × 3 = 60,

1/20 = 1 * 3 / 20 × 3 = 3/60

Add the two like fractions:

8/60 + 3/60 = 8 + 3/60 = 11/60

Answer:

te paso mi canal subcribete y la respueta

Step-by-step explanation:

2.2315

mi canal es navegando con incognito subcribete

Answer:

1

Step-by-step explanation:

Any number divided by itself is always 1

Answer: (2,-3)

Step-by-step explanation:

Answer:

1. The use of a domain for a function that is smaller than the function's domain of definition. Note: Restricted domains are commonly used to specify a one-to-one section of a function.

2. Domain restrictions can be calculated by finding singularities, which are the x -values for which the denominator Q(x) is zero.

Answer:

by setting the denominator equal to zero and solving. The x -values at which the denominator equals zero are called singularities and are not in the domain of the function.

Step-by-step explanation:

Answer:

g= 60°

i= 70°

h= 50°

Step-by-step explanation:

g=180-120 = 60°

i= 180-110 = 70°

h=180-60-70 = 50°

hope this helps =)

Kindly rate and mark brainliest. Thank you.

Answer:

Length=12 Width=6   AREA=72 (I think)

Step-by-step explanation:

yea... I didnt know  wut the equation was so my small brain did it manually

We can use the lateral surface area equation 2πrh. Assuming π = 3.14 we can plug all of the information into the equation to get 2 * 3.14 * 7 * 19.

multiplying everything you get 835.24, rounded to the nearest tenth is 835.2

Answer:

The answer is 8%

Step-by-step explanation:

Given,

Principle=Ra.2400

Time=3 years

Simple Interest= Rs.576

Rate=?

Now,

Rate=100*Simple Interest%P*T

=100*576%2400*3

=57600%7200

=8%

Therefore, the rate of Interest is

8%

(can you give me BRAINLIEST)

The ordered pairs of the points F, G and H are their locations on the coordinate plane

The point F is above the line 1

The ordered pairs of the points are given as:

F = (0,7)

G = (6, 2)

H = (1,6)

The line is not given; so, I will provide a general explanation.

Of all the three ordered pairs, the point with the greatest y-coordinate is the point F.

This means that the point F can be above the line 1, while the other points G and H are below the line.

See attachment for the illustration of the line and the ordered pairs

Read more about ordered pairs at:

https://brainly.com/question/1090891

Answer:

the number = -23 because there are different ways to do this don't bother

Answer:

okay so the circumference is 40.82m

[tex]circumference = 2\pi \: \times r \\ = 2 \times 3.14 \times 6.5 \\ = 40.82m[/tex]

the diameter will be divided by 2 to give 6.5

Answer:

The surface area of the tent is 21.4 m²

Step-by-step explanation:

To find the surface area of a prism you must calculate:

1. The perimeter of the base

2. The area of the base

3. The height of the prism

We have a triangular prism:

Its base is an equilateral triangle of side length 2 m and height 1.7 m

The height of the prism is 3 m

∵ The surface are of the prism is:

  S.A = perimeter of the base × height + 2 × area of the base

∵ The perimeter of the equilateral triangle = 3 × length of a side

∵ The length of the side = 2 m

∴ The perimeter of the base = 3 × 2 = 6 m

∵ The area of the triangle =  × base × height

∵ The length of the base of the triangle = 2 m

∵ The height of the triangle = 1.7 m

∴ The area of the base =  × 2 × 1.7 = 1.7 m²

∵ S.A = perimeter of the base × height + 2 × area of the base

∵ The perimeter of the base = 6 m

∵ The area of the base = 1.7 m²

∵ The height of the prism = 3 m

∴ S.A = 6 × 3 + 2 × 1.7

∴ S.A = 18 + 3.4

∴ S.A = 21.4 m²

The surface area of the tent is 21.4 m²

Answer:

Simply substitute the value of 3 given. In other words, f(3) is the function of f(x) , however, in this case, x is 3. f(3)=3(3)−4.

Answer:

Volume = 92.15

Step-by-step explanation:

V=πr2h/3=π·42·5.5/3≈92.15

Answer:

D

To find the percentage we must first find the area of the circle:

We can find the radius of the circle using the distance formula

Now we calculate the area;

To get the percentage we divide the area of the circle by the square’s are and multiply by 100;

The statement that correctly descrives the likelilhood of an event based on the given numbered cube is: Option A: It is likely that a number less than 6 is occured.

Suppose that for a considered sample space, we consider an event E

Then, E is likely to occur if:

[tex]P(E) \geq P(E')[/tex]

where [tex]E_i '[/tex] is complementary event of E (ie, E'  occurs whenever E doesn't occur and vice versa)

If so, then we say that E is likely to occur as the outcome of the considered random experiment, else unlikely.

Since we have:

[tex]P(E) = 1- P(E')[/tex] due to E and E' being complement of each other, therefore, we get:

[tex]P(E) \geq 1 - P(E)\\P(E) \geq 0.5[/tex]

Thus, event E is said to be likely if its probability is greater or equal to 0.5, else not.

It is given that the cube is 6 faced (assuming all equally likely), numbered from 1 to 6.

Evaluating likelihood of each event:

P(Getting a number < 6 on that cube) = [tex]\dfrac{5}{6}[/tex] (since a number out of 6 numbers can occur in 6 ways, but it being < 6 can be done in 5 ways).

Thus, we have:

P(Getting a number < 6 on that cube) =5/6 > 0.5

So it is likely to get a number < 6 on the considered cube. So this statement correctly describes the likelihood of its considered event.

Ways to get a number on the considered cube = 6

Ways to get a number < 4 on the considered cube = 3

Thus, we get:

P(Getting a number < 4 on that cube) = 3/6 = 0.5

Thus, it is likely to get a number < 4 on that cube, so this option is wrong.

Yes it is certain, but we're considering only those options which correctly describe likelihood instead of certainity.

So, this option is not considerable.

Ways to get a number on the considered cube = 6

Ways to get a number > 1 on the considered cube = 5

Thus, we get:

P(Getting a number > 1 on that cube) = 5/6 > 0.5

Thus, it is likely to get a number > 1 on that cube, so this option is wrong.

Thus, the statement that correctly descrives the likelilhood of an event based on the given numbered cube is: Option A: It is likely that a number less than 6 is occured.

Learn more about likelihood of events here:

https://brainly.com/question/14954386

#SPJ1

Answer:

Thus, option A is correct.

Explanation:

match the proportions

set up a equation:

[tex]\sf \dfrac{60}{100} = \dfrac{240,000}{x}[/tex]

[tex]\sf x = \$400,000[/tex]