The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
Given the following data:
Charge = [tex]-2.35 \times 10^{-6}[/tex] C.
Distance = 0.100 m.
Scientific data:
Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]
How to calculate the net force.In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
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Answer:
6.2
Explanation:
acellus
derive the equation of motion v²- u²= 2as
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Here we go ~
Let's use the given expression :
[tex]\qquad \tt \dashrightarrow \:a = v \dfrac{dv}{ds} [/tex]
[tex]\qquad \tt \dashrightarrow \:v \:dv= a \: {}{ds} [/tex]
Now, integrate both sides
[tex]\qquad \tt \dashrightarrow \: \int_{u}^v (v )\: dv= {\int _{0 }^{s} }{}^{} (a) \: {}{ds} [/tex]
[tex]\qquad \tt \dashrightarrow \: {\bigg[\dfrac{v {}^{2} }{2} \bigg]}_{u }^{v} \: = {\bigg[{a{s}^{} }{} \bigg]}_{0}^{s}[/tex]
[tex]\qquad \tt \dashrightarrow \: \dfrac{1}{2} {\bigg[{v {}^{2} - {u}^{2} }{} \bigg]}_{}^{} \: = a{\bigg[{{s - 0}^{} }{} \bigg]}_{}^{}[/tex]
[tex]\qquad \tt \dashrightarrow \: v {}^{2} - {u}^{2} =2 as[/tex]
[tex]\qquad \tt \: \therefore v {}^{2} =u {}^{2} + 2as[/tex]
I hope you understood ~
What is the moment of inertia (in units of gcm2) of an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around its symmetry axis
For an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around, moment of inertia is mathematically given as
I=16268.20gcm^2
What is the moment of inertia?Generally, the equation for the volume is mathematically given as
v=\pir^2t
Therefore
v=\pi(8.7)^2*0.32
v=76.09cm^3
In conclusion, The inertia
I=136.83*8.7^2/2
I=16268.20gcm^2
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04*. The resultant of two force vectors A and B has a magnitude of 150 N along the y-axis. If the force vector B makes an angle of 60° with the positive x-axis, find the magnitude of B and the direction of A, given that the x-component of A is equal to -60 N. [120N, 142.48°)
(a) The magnitude of force vector B at the given resultant force is 120 N.
(b) The direction of force vector A is 142.46°
Resultant of the forcesThe resultant forces is calculated as follows;
Acosθ + Bcosθ = 0 --- (1)
Asinθ + Bsinθ = 150 ---- (2)
Magnitude of BAcosθ + Bcos60 = 0
-60 + Bsin60 = 0 (Acosθ = x-component of A = Ax)
Bcos60 = 60
B = 60/cos(60)
B = 120 N
Direction of AAsinθ + Bsinθ = 150
Ay + Bsinθ = 150
Ay + 120sin60 = 150
Ay = 150 - 120sin60
Ay = 46.1 N
[tex]tan \theta = \frac{A_y}{A_x} \\\\\theta = tan^{-1} (\frac{A_y}{A_x})\\\\\theta = tan^{-1} (\frac{46.1}{-60})\\\\\theta = -37.53^0\\\\\theta = -37.53^0 + 180 = 142.46^0[/tex]
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Bodies weighing 2 and 6 kg acquired accelerations as a result of the interaction. Which body accelerates more and how many times?
Answer:
See below ~
Explanation:
Assume the bodies have the same acceleration
Equate each equation using the force formulaF = ma ⇒ F = 2aF = ma ⇒ F = 6aDivide the RHS of equation 2 by equation 1.
6a/2a3 timesTherefore, the body of 6 kg accelerates more by 3 times
The diagram shows a handle with three forces, each 100 N, applied to it. The handle is free to
move.
100N
100N
100N
handle
pivot
What is the effect of the forces on the handle?
A The handle will move downwards.
B The handle will not move.
с The handle will turn anticlockwise (to the left).
D The handle will turn clockwise (to the right).
Answer:
с The handle will turn anticlockwise (to the left).
Explanation:
21. How does cellular respiration directly benefit animals?
A. by producing glucose
B. by consuming oxygen
C. by forming carbon dioxide
D. by storing energy in adenosine triphosphate (ATP)
Answer:
D
Explanation:
Cellular respiration is a set of metabolic reactions and processes that take place in the cells of organisms to convert chemical energy from oxygen molecules or nutrients into adenosine triphosphate, and then release waste products.
The projectile is fired with initial velocity of 100ms-1 at an angle of 30° with the horinzontal.Calculate a.The time of flight b.The maximum height attained c.The range
[tex]\bold{\huge{\underline{ Solution }}}[/tex]
Here,
The projectile is fired with initial velocity =100m/sThe Angle formed with the horizontal = 30°Answer (a)Here, we have
Initial velocity = 100 m/sAngle of projection = 30°We have to find the time of flight
We know that,
Time of flight
[tex]\sf{ = }{\sf{\dfrac{ 2uSin{\theta}}{g}}}[/tex]
Subsitute the required values,
[tex]\sf{ = }{\sf{\dfrac{ 2{\times}100{\times}Sin30{\degree}}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 200{\times}{\frac{1}{2}}}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 100}{9.8}}}[/tex]
[tex]\bold{ = 10.20 \: s }[/tex]
Hence, The time of flight is 10.20 sec .
Answer (b)Here, We have
Initial velocity = 100 m/sAngle of projection = 30°We have to find the maximum height attained by the body
We know that,
Maximum height
[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin^{2}{\theta}}{2g}}}[/tex]
Subsitute the required values,
[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin^{2}30{\degree}}{2{\times} 9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{1}{2}}{\times}{\frac{1}{2}}}{19.6}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}{\frac{1}{2}}}{19.6}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 2500}{19.6}}}[/tex]
[tex]\sf{ = 127.5 \: m}[/tex]
Hence, The maximum height attained by the body is 127.5 .
Answer ( c) :-Here, we have
Initial velocity = 100 m/sAngle of projection = 30°We have to find the horizontal range
We know that,
Horizontal range
[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin2{\theta}}{g}}}[/tex]
Subsitute the required values,
[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin2{\times}30{\degree}}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}Sin{\times}60{\degree}}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{\sqrt{3}}{2}}}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}\sqrt{3}}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}1.732}{9.8}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{ 8660}{9.8}}}[/tex]
[tex]\sf{ = 883.67 \: or 883.7 m}[/tex]
Hence, The range of the body is 883.67 or 883.7 m.
Answer:
(a) 10.20 s (nearest hundredth)
(b) 127.55 m (nearest hundredth)
(c) 883.70 m (nearest hundredth)
Explanation:
Part (a)
At the end of the projectile's flight, its vertical displacement will be zero.
Resolving vertically, taking up as positive:
[tex]s=0\quad u=100 \sin30^{\circ} \quad v=v, \quad a=-9.8, \quad t=t[/tex]
[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2:\\ 0 & =100 \sin 30^{\circ}t+\dfrac12(-9.8)t^2\\ 0 & = 50t-4.9t^2\\ 4.9t^2 & = 50t\\ 4.9t & = 50\\ t & = \dfrac{50}{4.9}\\ t & = 10.20\:\sf s\:(nearest\:hundredth)\end{aligned}[/tex]
Part (b)
At the maximum height, vertical velocity will be zero.
Resolving vertically, taking up as positive:
[tex]s=0\quad u=100 \sin30^{\circ} \quad v=0, \quad a=-9.8, \quad t=t[/tex]
[tex]\begin{aligned}\textsf{Using }\:v^2 & = u^2+2as :\\ 0^2 & = (100 \sin 30^{\circ})^2+2(-9.8)s\\ 0 & = 2500-19.6s\\ 19.6s & = 2500\\ s & = \dfrac{2500}{19.6}\\ s & = 127.55\: \sf m\:(nearest\:hundredth) \end{aligned}[/tex]
Part (c)
The horizontal velocity of a projectile is always constant, so u = v.
The horizontal component of acceleration is zero.
Resolving horizontally, taking right as positive (and using the value for t we found in part a):
[tex]s=s\quad u=100 \cos30^{\circ} \quad v=100 \cos30^{\circ} , \quad a=0, \quad t=\dfrac{50}{4.9}[/tex]
[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2 : \\ s & =(100 \cos 30^{\circ})\left(\dfrac{50}{4.9}\right)+\dfrac12(0)\left(\dfrac{50}{4.9}\right)^2\\ s & =50\sqrt{3}\left(\dfrac{50}{4.9}\right)+0\\ s & =883.70\: \sf m\:(nearest\:hundredth)\end{aligned}[/tex]
A stroboscope is set to flash every 6.55 ✕ 10−5 s. What is the frequency (in Hz) of the flashes?
Answer:
15 267 times per second
Explanation:
1 / ( 6.55 x 10 ^-5) = 15 267 Hz
4) A light beam shines through a thin slit and illuminates a distant screen. The central bright fringe on the screen is 1.00 cm wide, as measured between the dark fringes that border it on either side. Which of the following actions would decrease the width of the central bright fringe? (There may be more than one correct choice.) A) increase the wavelength of the light B) decrease the wavelength of the light C) increase the width of the slit D) decrease the width of the slit E) put the apparatus all under water
The actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.
Wavelength of the lightThe wavelength of the light is determined using the following formulas;
[tex]\lambda = d(\frac{y}{D} )[/tex]
where;
λ is wavelengthd is width of the slitD is the distance of the screeny is distance between the central bright fringe and dark fringeActions that would decrease the width of the central brighty = (λD) / (d)
Decrease in the wavelength of the lightIncrease in the width of the slitThus, the actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.
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8 Describe Explain how this transfer observes
the conservation of charge.
Charge is neither generated nor destroyed, according to the rule of conservation of charge. Charge is merely transferred from one item to another in the form of electrons.
Help me please!!????
5. Two objects of masses 1kg and 2kg respectively are released from rest when their separation is 10 m. assuming that on it mutual gravitational force act on them, find the velocity of each of them when separation becomes 5m.
The velocity of 1kg and 2 kg mass when separation becomes 5m is 1.334 x 10⁻¹¹ m/s and 6.67 x 10⁻¹² m/s respectively.
Force between the massesThe gravitational force between the masses is determined as follows;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11}) (1)(2)}{10^2} \\\\F = 1.334 \times 10^{-12} \ N[/tex]
Acceleration of each objectsa = F/m
a₁ = (1.334 x 10⁻¹²) / (1)
a₁ = 1.334 x 10⁻¹² m/s²
a₂ = (1.334 x 10⁻¹²) / (2)
a₂ = 6.67 x 10⁻¹³ m/s²
Velocity of each objectv = u + 2ad
v₁ = u₁ + 2a₁d
v₁ = 0 + 2( 1.334 x 10⁻¹² )(5)
v₁ = 1.334 x 10⁻¹¹ m/s
v₂ = u₂ + 2a₂d
v₂ = (0) + 2(6.67 x 10⁻¹³)(5)
v₂ = 6.67 x 10⁻¹² m/s
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A block oscillating on a spring has an amplitude of 20 cmcm. Part A Part complete What will the block's amplitude be if its total energy is doubled
Hi there!
Recall that the amplitude of an oscillating system occurs at a point of maximum potential energy.
For a spring system, potential energy is given as:
[tex]U = \frac{1}{2}kx^2[/tex]
U = Potential Energy (J)
k = Spring constant (N/m)
x = amplitude (m)
We can rearrange the equation to solve for amplitude more easily.
[tex]U = \frac{1}{2}kx^2\\\\2U = kx^2\\\\x^2 = \frac{2U}{k}\\\\x = \sqrt{\frac{2U}{k}}[/tex]
If we double 'U':
[tex]x' = \sqrt{\frac{2(2U)}{k}} = \sqrt{2}*\sqrt{\frac{2U}{k}}\\\\x' = \sqrt{2} * x[/tex]
Thus, the new amplitude would be √2 times greater, so:
[tex]20 cm \cdot \sqrt{2} = \boxed{28.284 cm}[/tex]
12 Ω resistor and a 15 Ω resistor are connected in series across a 9.0 V potential difference. What is the current in the circuit
The current in the series circuit across a 9.0 V potential difference is determined as 0.333 A.
Current in the series circuit
The current in the series circuit is determined by applying ohms law as shown below;
V = IR
where;
I is the currentR is equivalent resistance of the circuitR = 12 Ω + 15 Ω = 27 Ω
I = V/R
I = 9/27
I = 0.333 A
Thus, the current in the series circuit across a 9.0 V potential difference is determined as 0.333 A.
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Question 3 of 20 :
Select the best answer for the question.
3. Which type of mental function would be the strongest and most obvious?
O A. Feeling
O B. Judging
O C. Introversion
O D. Observant
ما
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The type of mental function that is the strongest and most obvious is feeling. That is option A.
Types of mental functionMental function can be defined as those activities that are performed by individuals such as thinking, sensing, or reasoning that involves the cognitive use of the brain.
The four basic cognitive functions include:
thinking, feeling, intuition, and sensation.The magnitude of each basic cognitive functions depends on the personality of the individual.
An extrovert is an individual that is active, outgoing, and has an expressive pattern of behaviour. Therefore extrovert feeling would be the strongest and most obvious.
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Changes in daily ____ like tracking can lead to constipation
Changes in daily routine or lifestyle like traveling can lead to constipation
However, other causes of constipation include the following:
Not observing enough exerciseEating foods very low in fibersDehydration. Changes in one's regular routine, such as traveling or eatingOver consumption of some food substances such as milkResisting the urge to have a bowel movement.Going late to bedEating late at night for some individualsWhat is constipation?This is a health condition in whereby there is difficulty in emptying the bowels.
This makes defecation very difficult.
So therefore, changes in daily routine or lifestyle like traveling can lead to constipation
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Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle 91. Is it pushing to the right (+), or to the left (-)? Enter + or - -5.90 C +13.0 μC +91 93 +7.70 μC + 92 + 0.25 m K 0.30 m
Answer:
(b) from left to right (→)
Explanation:
Frictional Force
When the surface of one object comes into touch with the surface of another, friction is the force that resists motion. Friction reduces a machine’s mechanical advantage, or, to put it another way, friction reduces the output-to-input ratio. Frictional force refers to the force generated by two surfaces that contact and slide against each other.
Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moved over the other, these irregularities on the surface get entangled, giving rise to friction.
The more the roughness, the more irregularities and more significant will be the friction.
Friction always acts in the opposite direction to the motion, hence the force of friction will be from left to right.
The distance between 4 nodes is 15.0 cm. The frequency of the source is 10.0 Hz. What is the speed of the waves in cm/s?
a
1.50 x 10^2 cm/s
b
1.00 x 10^2 cm/s
c
75.0 cm/s
d
2.00 x 10^2 cm/s
The speed of the waves will be 100 cm/s. The speed of a wave is the product of the frequency and wavelength.
What is a sound wave?When an object vibrates, a pressure wave is created, which produces sound. The particles in the surrounding medium (air, water, or solid) vibrate as a result of the pressure wave.
For one node distance is [tex]\lambda[/tex]
The distance between 4 nodes;
[tex]=\rm \lambda+ \frac{\lambda}{2} \\\\ = \frac{3 \lambda}{2} \\\\[/tex]
The distance between 4 nodes = 15.0 cm.
[tex]\frac{3\lambda}{2} = 15 \times 10^{-2} \\\\ \lambda= \frac{2 \times 15 \times 10^{-2}}{3} \\\\\ \lambda= 10 \times 10^{-2}[/tex]
The given frequency of the source is;
f = 10 Hz
The speed of wave is found as;
[tex]\rm v = f \lambda \\\\ v= 10 \times 10^{-2} \\\\ v=1 \ m \\\\\ v = 10^2 \ cm/sec[/tex]
Hence, the speed of the waves will be 100 cm/s
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Three loads, of 24 A, 8 A, and 12 A are supplied from a 200 V source. If a motor of resistance 2.4 Ohms is also connected across the supply, calculate (a) the total resistance and (b) the total current drawn from the supply.
Answer:
See below ~
Explanation:
Total Resistance
R₁ (across 24A load) = 200/24 = 8.33 ΩR₂ (across 8A load) = 200/8 = 25 ΩR₃ (across 12A load) = 200/12 = 16.67 ΩR₄ (given) = 2.4 ΩR = R₁ + R₂ + R₃ + R₄R = 8.33 + 25 + 16.67 + 2.4R = 25 + 25 + 2.4R = 50.4 ΩTotal Current Drawn
Source Voltage / Total Resistance200 V / 50.4 Ω3.97 A (To the nearest hundredth)Relate states of the matter with heat by a proper graph and describe the graph fully by your own words
Answer: If you are adding heat to a sample at a constant rate , you plot the temperature against time.
Explanation:
Use the Newton's Law Triangle to solve the following problem
A bowling ball had 50 N of force when it accelerated down the lane at a rate of 2m/s2. How much mass did the bowling ball have?
________kilograms
Answer:
The answer would be 25kg.
Explanation:
Because the force is 50 N and the acceleration is 2 meters per second squared and the Newton's Law Triangle is F = m x a or Force = Mass x Acceleration so we have to solve the equation 50 divided by 2 or 50/2 which results in 25kg.
what is meant by reticlinear propatigation of light?
Answer:
The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.
Answer:
the property of light travelling in a straight lines in a homogenous transparent medium
Explanation:
What is part of the first stage in the process of technological design?
reporting a solution
building a prototype
researching information
designing a solution
Researching information
Explanation: Edge 2020
hope this helps :3. pls mark me brainiest Brainliest
Answer:
It is C.
Explanation:
Got it right on edge.
I need help finding the kinetic energies (reupload)
Answer:
18.51 J
Explanation:
First, we need to find the Kinetic energy of the disk. Since the disk travels in a straight line, we can use the formula [tex]K=\frac{1}{2}mv^2[/tex]:
[tex]Kdisk=\frac{1}{2} 0.033*33.5^2\\Kdisk=18.51 J[/tex]
Since no other force is present, no friction, sound, or vibration, energy must be conserved. Therefore, the answer for both is 18.51 J.
. An experimental rocket plane lands on skids on a dry lake bed. If it’s traveling at 80.0 m/s when it touches down, how far does it slide before coming to rest? Assume the coefficient of kinetic friction between the skids and the lake bed is 0.6.
Answer:
1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.
solution
element
mixture
compound
2.
Which of the following materials is a substance?
air
gasoline
stainless steel
silver
3.
The first figure in a properly written chemical symbol always is _____.
boldfaced
capitalized
italicized
underlined
4.
Which of the following represents a compound?
H
H-3
H2O
O-16
5. What do chemical symbols and formulas represent, respectively?
elements and compounds
atoms and mixtures
compounds and mixtures
elements and ions
Explanation:
The rocket plane will travel 800 meters before coming to rest.
What is stopping distance?initial speed= 80 m/s
kinetic friction= 0.6
Net force action on the plane:
F- kinetic friction = mass * acceleration
mass*g - 0.6*mass*g=mass*acceleration (take g=10m/s)
acceleration=4m/s
calculation of stopping distance:-
V²=U²-2as
0+2as=U²
S=U²/2a
S=(80*80)2*4
S=800 meter.
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A velocity selector for ions uses perpendicular electric and magnetic fields. If the electric field used were 800 V/m, what magnetic field would allow the selection of a velocity of 4000 m/s?
For a velocity selector for ions using perpendicular electric and magnetic fields is mathematically given as
B= 0.225 T
What magnetic field would allow the selection of a velocity of 4000 m/s?
Generally, the equation for the magnetic field is mathematically given as
B = E/v
Therefore
B = 900/4000
B= 0.225 T
In conclusion. the magnetic field is
B= 0.225 T
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1. Go to your room for 2 hours (you can do it longer to really feel the difference); 2. Keep your gadgets out of your reach, turn off any grid powered electrical devices and appliances; 3. Perform any activities that you loved aside from those that needed modern products of technology. 4. After the social experiment, write a minimum of 5 sentences essay on how does it feel to have no gadgets, appliances and anything that are products of modern technology. In your essay you must answer the question, Are we human using these technologies or are these technologies using us already?
Answer:
You should probably try following the instructions and you will be able to find the answer to the question :>
Explanation:
but mostly the technology's using us
A current loop with radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T. Considering all possible orientations of the loop relative to the field, what is the largest potential energy difference (in Joules) you can find between two orientations
For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as
du=0.2512J
What is the largest potential energy difference (in Joules) you can find between two orientations?Generally, the equation for the initial velocity is mathematically given as
v0=-iAB
Therefore
-2*\pi(0.2)(0.5))
v0=-0.1256J
for 180
theta=0180=-iABcos180
V180=0.1256J
Therefore
du=v180-v0
0.1258-(-0.1256
du=0.2512J
In conclusion, potential energy
du=0.2512J
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what happens to the resistance of two resistors when connected in parallel circuit
Hello, I have no idea how to do this.
Can someone help?
Based on the information in the table,
Choose whether the magnetic field is weak or strong.
The magnetic field is weak in both A and C but strong in B since magnetic field strength increases with number of turns and quantity of current.
What are the factors affecting the strength of the magnetic field in a solenoid?The strength of the magnetic field in a solenoid is affected by the following factors:
number of coilsthe martial in the core of the solenoid the current passing throughThe strength of the magnetic field of a solenoid ncreases when:
The current is increasedhe number of turns is increasedsoft iron core is placed into the solenoidTherefore, the magnetic field is weak in both A and C but strong in B.
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