No, 8, 15, 17 are not Pythagorean triples.
No, 8 15 17 are not Pythagorean triples. A Pythagorean triple is a set of three positive integers a, b, and c such that a2 + b2 = c2. In other words, the sum of the squares of two integers must equal the square of the third integer.
In the case of 8 15 17, if we calculate the sum of the squares of the two smaller integers, 8 and 15, we get
[tex]8^2 + 15^2 = 64 + 225 = 289[/tex].
This does not equal the square of the third integer,
[tex]17^2 = 289,[/tex]
so 8 15 17 are not Pythagorean triples.
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raph g(x)=(x+2)(x - 1) - x^{2}g(x)=(x+2)(x−1)−x 2 by making a table and plotting the corresponding points. Then, determine if the function is linear, quadratic, or neither.
The graph from the function is a linear graph
How to determine the graph from the functionFrom the question, we have the following parameters that can be used in our computation:
g(x)=(x+2)(x−1)−x 2
Express properly
So, we have the following representation
g(x) = (x + 2)(x − 1) − x²
Next, we set x = 0, 1, 2 and 3 to determine the table of values
g(0) = (0 + 2)(0 − 1) − (0)² = -2
g(1) = (1 + 2)(1 − 1) − (1)² = -1
g(2) = (2 + 2)(2 − 1) − (2)² = 0
g(3) = (3 + 2)(3 − 1) − (3)² = 1
So, the table is
x 0 1 2 3
g(x) -2 -1 0 1
From the table above, we can see that as x increases by 1, y constantly increase by 1
This means that the function is a linear function
See attachment for the graph
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What should be added to 7x^2 5x 1 to get 3x^2 4x 7?
The value should be added will be [tex]y = -4x^{2} +9x+6[/tex]
Now, According to the question:
Let the value y be added to [tex]7x^2-5x+1[/tex] to give [tex]3x^2+4x+7[/tex]
y = [tex]3x^2+4x+7[/tex] - ( [tex]7x^2-5x+1[/tex])
y = [tex]3x^{2} +4x+7-7x^{2} +5x-1[/tex]
Combine like terms:
y = [tex]3x^{2} -7x^{2} +4x+5x+7-1[/tex]
Calculate the subtraction and addition.
[tex]y = -4x^{2} +9x+6[/tex]
Hence, The value should be added will be [tex]y = -4x^{2} +9x+6[/tex].
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The complete question is this:
What should be added to [tex]7x^2-5x+1[/tex] to get [tex]3x^2+4x+7[/tex] ?
How do you find the surface area and the volume to a composite figure?
Answer:
वि स्कुल माध्यामिक विद्यालय निम्न माध्यामिक विद्यालय व्यवस्थापन समिति सम्पादन र प्रकाशनमा बुटवलबाट निस्कने एक्सरे साप्ताहिकमा एक पटक साप्ताहिकमा छापिएको थियो। प्रकाशित
I need help with these 4 problems
As a result, using the values provided, we can turn these data into a bar graph.
What is a graph?A graph is a type of non-linear data structure that consists of nodes, also called vertices, and edges. Any two edges can connect the nodes, which are also known as vertices in a graph. This graph's vertices are 1, 2, 3, and 5, while its edges are 1, 2, 1, 3, 2, 5, and 4, 50.
Here,
The gene contributes to the development of pigment.
Yes, factors such as temperature, light cycle, and the presence of mutagens can affect the color of the fur.
In the evolution chart, Mcl provided has ullets that it runs. In mature solutions, the dominating truit moderate is thus always present.
Therefore, using the supplied numbers, we may convert these data into a bar graph.
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97 = 10x + 27 need help!!
Answer:
x=7
Step-by-step explanation:
97 = 10x + 27
97 - 27 = 10x
70 = 10x
70/10 = x
7=x
Answer:
X=7
HOPE THIS HELPS
-Todo ❤️
Step-by-step explanation:
97=10x+27
-27. -27
70=10x
/10. /10
X=7
b. Consider a circle with centre O and radius of 4 units. The distance of point P is 2 units from centre. Find the distance of inverse of point P' from the centre O.
How do I solve these problems?
Answer:
1.) The 1ˢᵗ three term is (-32), (-7) and 18
2.) The 1ˢᵗ three term is 127, 106 and 85
Step-by-step explanation:
1.)Here,
First Term = a₁ = - 32
Common Difference = (d) = 25
Now, For 1ˢᵗ three term,
n = 1
a₁ = - 32
n = 2
aₙ = a + (n - 1)d
a₂ = (-32) + (2 - 1) × 25
a₂ = (-32) + 1 × 25
a₂ = (-32) + 25
a₂ = -7
n = 3
aₙ = a + (n - 1)d
a₃ = (-32) + (3 - 1) × 25
a₃ = (-32) + 2 × 25
a₃ = (-32) + 50
a₃ = 18
Thus, The 1ˢᵗ three term is (-32), (-7) and 18
2.)Here,
First Term = a₁ = 127
Common Difference = (d) = -21
Now, For 1ˢᵗ three term,
n = 1
a₁ = 127
n = 2
aₙ = a + (n - 1)d
a₂ = 127 + (2 - 1) × (-21)
a₂ = 127 + 1 × (-21)
a₂ = 127 - 21
a₂ = 106
n = 3
aₙ = a + (n - 1)d
a₃ = 127 + (3 - 1) × (-21)
a₃ = 127 + 2 × (-21)
a₃ = 127 - 42
a₃ = 85
Thus, The 1ˢᵗ three term is 127, 106 and 85
-TheUnknownScientist
In 2010, the population of a city was 237,000. From 2010 to 2015, the population grew by 7.6%. From 2015 to 2020, it fell by 4.7%. To the nearest whole number, by what percent did the city grow from 2010 to 2020?
The population of the city grew from 2010 to 2020 by 13.37 %
What is percentage?A percentage is a number that tells us how much out of 100 and can also be written as a decimal or a fraction.
Given that, In 2010, the population of a city was 237,000. From 2010 to 2015, the population grew by 7.6%. From 2015 to 2020, it fell by 4.7%.
The population in 2015 =
A = P (1+r)ⁿ
A = final population.
P = Initial population.
r = rate
n = time
The population in 2015 =
A = 237,000(1+0.076)⁵
A = 341829.629
The population in 2020 =
A = P (1-r)ⁿ
A = 341829.629(1-0.047)⁵
A = 268704.047
Percent grow = 268704.047 - 237,000 / 237,000 × 100
= 31704.047 / 237,000 × 100
= 13.37 %
Hence, the population of the city grew from 2010 to 2020 by 13.37 %
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A. To wash the first window, Roger extends the
ladder to 20 feet long. He places the base of
the ladder 6 feet from the side of the house.
Sketch a labeled picture of this to the right.
B. How far up the house will the 20-foot ladder
reach, to the nearest tenth of a foot? Show your
work in the space to the right.
Pythagorean Theorem & irrational Numbers Question
Which of the following could not be the lengths of sides of a
right triangle?
Select one:
8, 10, 12
6, 8, 10
9, 12, 15
8, 15, 17
Answer:
2nd
Step-by-step explanation:
if cosØ=1/6 what are the values of sinØ and tanØ?
Answer:
Step-by-step explanation:
cos theta = (adjacent side) / (hypotenuse) = 1/6. The adjacent side has length 1 and the hypotenuse length 6. The opposite side has length
√(6^2 - 1^2) = ÷√35
and so sin theta = (opp side) / (hypotenuse) = (√35) / 6
and tan theta = [(√35) / 6] / (1/6), or √35
How do you describe rational and irrational?
Rational and Irrational numbers can described as the number that can be expressed as [tex]\frac{p}{q}[/tex] are rational and which cannot be expressed are called as Irrational Numbers .
The Rational Numbers are defined as a number that can be represented in the form of [tex]\frac{p}{q}[/tex] where [tex]q\neq 0[/tex].
We can also , say that the fraction where the denominator and the numerator are integers and the denominator is not equal to zero are called as Rational Numbers .
For Example : [tex]\frac{2}{3} , \frac{4}{9}[/tex] represents a rational numbers .
The Irrational Numbers are defined as a real number that cannot be expressed as a ratio of integers .
For Example : [tex]\sqrt{2} , \sqrt{5}[/tex] represents a Irrational number .
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Pls help me I’ll give thxs and brainiest if you answer correctly to both exercises
Answer:
Activity 1
1. a.8, b.4, c.8, d.12
2. a.10, b.8, c.20, d.40
3. a.16, b.9, c.40, d.27
Activity 2
1. a.10, b.40, c.15
2. a.4, b.35, c.14
3. a.80, b.20, c.2.5
I NEED HELPPPPPPPPPPPPP
Answer:
y= 12
Step-by-step explanation:
3(-12)-24
-36-24
-12
Show that f is continuous on (−[infinity], [infinity]). f(x) = 1 − x2 if x ≤ 1 ln(x) if x > 1
On the interval
(−[infinity], 1),
f is function; therefore f is continuous on
(−[infinity], 1).
On the interval
(1, [infinity]),
f is function; therefore f is continuous on
(1, [infinity]).
The function [tex]$$f(x)= \begin{cases}1-x^2 & x \leqslant 1 \\ \ln (x) & x \geqslant 1\end{cases}$$[/tex] is continuous on (-∞, ∞).
As per the given data the function f(x) is given by:
[tex]$$f(x)= \begin{cases}1-x^2 & x \leqslant 1 \\ \ln (x) & x \geqslant 1\end{cases}$$[/tex]
Here we have to determine that the function f(x) is continuous on (-∞, ∞)
If we show that f(x) is continuous at x = 1 then f(x) is continuous on (-∞, ∞)
What are continuous function?
A continuous function in mathematics is one where changes in the parameter cause constant changes in the function's value (i.e., a change without a leap). This shows that there are no abrupt changes in value or discontinuities.
To show f(x) is continuous at x = 1
[tex]\lim _{x \rightarrow 1^{-}} f(x)=\lim _{x \rightarrow 1^{+}}[/tex] f(x)
[tex]\rightarrow \lim _{x \rightarrow 1^{-}} f(x) & =\lim _{x \rightarrow 1^{-}}\left(1-x^2\right) \\[/tex]
= 1 - 1
= 0
[tex]\lim _{x \rightarrow 1^{+}} f(x) & =\lim _{x \rightarrow 1^{+}} \ln (x) \\[/tex]
= ln 1
= 0
Therefore [tex]\lim _{x \rightarrow 1^{+}} f(x) & =\lim _{x \rightarrow 1^{-}} f(x)-0[/tex].
Hence f(x) is continuous on (-∞, ∞)
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Find the surface area of a cylinder with a height of and a base diameter of .
Use the value 3.14 for π , and do not do any rounding.
Be sure to include the correct unit.
Answer:
207.24 in.
(This is not a rounded answer)
Step-by-step explanation:
So, this will be very fun, simple, and easy!
First thing we do is use this formula, A(s) = 2πrh + 2πr²
We don't know the surface area yet, and that's what we are looking for, so first off we go ahead and plug in the radius, which is 6 divided by 2, and that's 3! The height is 8 inches!
Let's plug in 3.14 for pie too.
A(s) = 2(3.14)3(8) + 2(3.14)3²
Let's start solving.
A(s) = 150.72 + 2(3.14)3²
3 squared is 9!
A(s) = 150.72 + 56.52
A(s) = 207.24 inches
So, the answer is...207.24 in.! THat is the correct answer, but if I'm wrong, please comment so I can change my answer! Thanks for the points, have a great day or else!
A scale drawing of a square has a side length of 8 inches. The drawing has a scale of 1 in. : 6 mi. Find the actual perimeter and area of the square.
Perimeter $=$
mi
Area $=$
mi $^2$
Answer:
192 mi
2,304 mi²
Step-by-step explanation:
actual side length = 8×6 = 48 mi
so, perimeter of square = 4 × 48 = 192 miles
the area of square = 48×48 = 2,304 sq miles
Coach Brown buys packs of Gummi Bears at $0. 60 and resales them at $1. 0. At what percent did he mark the candy up?
A. 10. 47
B. 3. 59
C. 9
D. 67
E. 69
F. 10. 25
If the coach buys the packs of Gummi Bears at $0.60 and resales them at $1 , then the percent markup for the candy is (d) 67% .
The price for which the Coach buys Gummi Bears is = $0.60 ;
the price at which the Coach resales them is = $1 ;
So , the Markup is the difference in the price of purchase and price of resale of the candy ,
that means ; the [tex]Markup = \$1 - \$0.60[/tex] ;
= $0.4
So , the Percent Markup is = [tex]\frac{0.4}{0.6} \times 100[/tex]
= 66.66666...
≈ 67% .
Therefore , the percent Markup for the Candy is 67% .
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One of the legs of a right triangle measures 14cm and its hypotenuse measures 15cm. Find the measure of the other leg
the measure of the missing leg is 5.38
or 5.4
Step-by-step explanation:
s is for Squared
Cs= As+Bs
let's say 14cm was side a
Bs=Cs-As
Bs= 15s-14s
Bs=225-196
Bs=29
B= square root of Bs
B=5.38
Answer:
5.4
Step-by-step explanation:
c² = a² + b²
15² = 14² + b
225 = 196 + b
b = 225 - 196
= 29
= 5.4
( 1/2 ) ^2
HELP!
ME!
Answer:
1/4 is the answer
just multiply 1/2 x 1/2
hope this helps
have a good day :)
Step-by-step explanation:
7.7 is what percent of 16? round to the nearest hundredth?
Answer:
7.7 x x/100 = 16
x100 x100
7.7x = 1,600
Divide by 7.7 on both sides:
X = 207.79 around 208
Answer:48.13%
Step-by-step explanation:
7.7÷16×100=48.125%
Rounded to nearest hundredth=48.13%
heh help please my bootiful people lol
Answer:
x = 52
Step-by-step explanation:
128 + x = 180
180 - 128 = x
x = 52
Have a nice day!
PLS WHAT IS THE VALUE OF X SOMEONE
Answer:
It would be 166 degrees.
Step-by-step explanation:
Do 180-97 to get 83 degrees
Since the triangle is a isosceles triangle, the opposite side of it would also be 83 degrees, so 83+83
With this, do 180-83-83 to get 14 degrees for the third interior angle
Last, subtract this from 180 to get the value of x, 166 degrees.
Hope that helps.
On her first day of work, Janabel sold one widget. On day two, she sold three widgets. On day three, she sold five widgets, and on each succeeding day, she sold two more widgets than she had sold on the previous day. How many widgets in total had Janabel sold after working 2020 days
On solving the provided question, we can say that the sequence what we tell on day 3 = he sold 5; on day 4 = he sold 7; on day 5 = he sold 9
what is a sequence?A collection of numbers, or "terms," is referred to as a sequence. Examples of terms are 2, 5, and 8. Some sequences can be made endlessly lengthy by taking advantage of a particular pattern they follow. Use the example of 2,5,8 and add 3 to continue the sequence. There are formulas that demonstrate where to look for words within a sequence. A collection of objects that are in some order is known as a sequence in mathematics (or events). It resembles a set in that it contains pieces (also called elements or terms). The entire, perhaps infinite number of ordered objects are referred to as the sequence's length. the act of placing two or more items in a logical order. Chronological.
here,
on day 1 = he sold 1
on day 2 = he sold 3
on day 3 = he sold 5
on day 4 = he sold 7
on day 5 = he sold 9
.
.
.
.
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URGENT!! 50 POINTS!!! based on the linear table of ordered pairs, what is the y intercept?
Answer:
y- intercept = 0
Step-by-step explanation:
the linear function can be expressed in slope- intercept form, that is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁ , y₁ ) = (4, - 4) and (x₂, y₂ ) = (- 2, 2) ← 2 ordered pairs from the table
m = [tex]\frac{2-(-4)}{-2-4}[/tex] = [tex]\frac{2+4}{-6}[/tex] = [tex]\frac{6}{-6}[/tex] = - 1
the line crosses the y- axis at (0, 0 ) ⇒ c = 0
y = - x + 0, that is
y = - x ← is the linear function defining the ordered pairs in the table
Which linear graph represents a proportional relationship?
A graph of a straight line that passes through the points 0 comma 2 and 1 comma 2.
A graph of a straight line that passes through the points negative 1 comma 0 and negative 1 comma 1.
A graph of a straight line that passes through the points 0 comma 0 and 1 comma negative 2.
A graph of a straight line that passes through the points 0 comma 2 and 2 comma 3.
Answer: The answer is C
Step-by-step explanation: i took the test and got it right
The sum of the measures of the interior angles of a convex polygon is 1260°. Classify the polygon by the number of
sides.
O Heptagon
O Octagon
ONonagon
O Decagon
The polygon presented will have nine sides. This suggests that a nonagon is the necessary polygon.
How can you determine a polygon's entire angle?Divide the number of triangles in the polygon by 180° to determine the sum of its inner angles. Where is the number of sides, the formula for computing the sum of internal angles is (n 2) 180. In a regular polygon, all internal angles are equal.
What is the formula for polygons?The following are crucial polygon formulas: A polygon with "n" sides has a total interior angle sum of 180 degrees (n-2) A "n-sided" polygon has [n(n-3)]/2 diagonals. A regular n-sided polygon's internal angles are measured as [(n-2)180°]/n.
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pls help me i don't get it plssssss https://s3.amazonaws.com/content.accelerate-ed.com/Elementary/docs/Math5/Module10Assignment3.pdf
Answer:
I have a screenshot so here you go
Step-by-step explanation:
A bakery sells chocolate cupcakes and vanilla cupcakes. It sold 400 cupcakes in a day,
and 17% of them were vanilla. How many of the cupcakes sold that day were
chocolate?
Answer:
332 chocolate cupcakes.
Step-by-step explanation:
17% of 400 = 68
400 - 68 = 332
Find the missing lengths.
Answer:
x = 5√2
Step-by-step explanation:
The triangle on the right is a special right triangle, so we know that the adjacent side to 60° is 5. Since the left triangle is a 45-45-90, the hypotenuse is the leg times √2, so the value of x is 5√2