The fraction of the ice above the water level is 0.6 meters (option c).
The ice floats on water because its density is less than that of water. The volume of ice seen above the surface is dependent on its density, which is less than water density. The volume of the ice is dependent on the water that it displaces. An ice cube measuring 1 m has a volume of 1m^3.
Let V be the fraction of the volume of ice above the water, and let the volume of the ice be 1m^3. Therefore, the volume of water displaced by ice will be V x 1m^3.The mass of the ice is 917kg/m^3 * 1m^3, which is equal to 917 kg. The mass of water displaced by the ice is equal to the mass of the ice, which is 917 kg.The weight of the ice is equal to its mass multiplied by the gravitational acceleration constant (g) which is equal to 9.8 m/s^2.
Hence the weight of the ice is 917kg/m^3 * 1m^3 * 9.8m/s^2 = 8986.6N.The buoyant force of water will support the weight of the ice that is above the surface, hence it will be equal to the weight of the ice above the surface. Therefore, the buoyant force on the ice is 8986.6 N.The formula for the buoyant force is as follows:
Buoyant force = Volume of the fluid displaced by the object × Density of the fluid × Gravity.
Buoyant force = V*1m^3*1025 kg/m^3*9.8m/s^2 = 10002.5*V N.
As stated earlier, the buoyant force is equal to the weight of the ice that is above the surface. Hence, 10002.5*V N = 8986.6
N.V = 8986.6/10002.5V = 0.8985 meters.
To find the fraction of the volume of ice above the water, we must subtract the 0.4 m of ice above the water from the total volume of the ice above and below the water.V = 1 - (0.4/1)V = 0.6 meters.
To know more about fraction:
https://brainly.com/question/10354322
#SPJ11
4)Consider a charge +q, located at the origin. We observe the potential V and the electric field E at distance r. Here we are interested in quantities along the z-axis. Find or, if you know it, simply write, the electric potential V along the z-axis (x =y=0), for [z| not equal to zero. (Izis the absolute value of z.) Can you make any arguments by symmetry about the electric field? For instance, are any components of the electric field equal to zero along the z-axis? Use the standard expression, E; = -av/axi, where the E; are the x, y, z components of E, and Xi refer to the coordinates x, y, z. Using the expression you found above for V, what is the vector E as a function of position along the positive z-axis (lz| not equal zero). = Recall the differential form of Gauss' law, V. E=p/€0. What does this say about the component Ex at points Ax away from the z-axis, as a function of z? -
The electric potential, V along the z-axis (x=y=0) is as follows: Let r = (x² + y² + z²)¹/² Thus,
V = kq/r. When
x=y=0,
V = kq/z,
provided z is not equal to zero. By symmetry, the components of the electric field E along the x and y-axes are zero since the charge +q at the origin does not produce any component of E along these axes.
Hence E; = (0,0, Ez). It follows that Ex = 0 and Ey = 0 because of symmetry along the x- and y-axes. The electric field E can be found using
E= -av/axi
= - (dV/dx)i - (dV/dy)j - (dV/dz)k.
Using V = kq/z, it follows that:
E = -d/dz(kq/z)k
= kq/z²k.
Hence E has only a z-component, and its magnitude is given by E = kq/z² along the positive z-axis.
The differential form of Gauss' law, V. E=p/€0. If z > Ax, then we can draw a Gaussian surface that is cylindrical and coaxial with the z-axis. By symmetry, Ex = 0, so that p = 0. Thus, V. E = 0, and since V is non-zero, it follows that E must be zero.
To know more about electric potential visit:
https://brainly.com/question/28444459
#SPJ11
A part of a Gaussian Surface is a square of side length s. A corner of the square is placed the distance s from the origin on the y axis. A point charge Q is located at the origin. The edges of the square are either parallel to the x direction or z direction. The image above shows this information. If Q=25 microCoulomb and s = 15 cm, what is the electric field flux through the square?
The electric field flux through the square is determined as 2.25 x 10⁵ Nm²/C.
What is the flux through square?The electric field flux through the square is calculated by applying the following formula as follows;
Ф = EA
where;
E is the electric fieldA is the area of the surfaceThe magnitude of the electric field is calculated as;
E = (kQ) / s²
E = ( 9 x 10⁹ x 25 x 10⁻⁶ ) / ( 0.15 m)²
E = 1 x 10⁷ N/C
The electric field flux through the square is calculated as;
Ф = EA
Ф = (1 x 10⁷ N/C) x (0.15 m)²
Ф = 2.25 x 10⁵ Nm²/C
Learn more about electric field flux here: https://brainly.com/question/28062884
#SPJ4
11)Index of refraction Light having a frequency in vacuum of 5.4×1014 Hz enters a liquid of refractive index 2.0. In this liquid, its frequency will be: 12)Diffraction A 532 nm laser hits a slit at normal incidence and then travels 1.5 m to a wall. The slit is 0.001 mm wide. What is the angle to the 1 st order (m=1) minimum. 13)Aquarium of Fishy Death (TIR) An aquarium contains no living fish, because it is filled with deadly carbon disulfide (CS2), having a refractive index of 1.63. The aquarium is made of some unknown type of glass. A scientist with time on her hands measures the critical angle for total internal reflection for light directed out of the aquarium and finds that angle to be 65.2∘. Calculate the refractive index of the unknown glass walls of the Aquarium of Fishy Death.
The frequency of light entering a liquid with a refractive index of 2.0 will remain the same, i.e., 5.4×10^14 Hz.
When light travels from one medium to another, its frequency does not change. The frequency of light is determined by its source and remains constant, regardless of the medium it passes through.
However, the speed of light changes in different media, resulting in a change in its wavelength and direction. In this case, the light entering the liquid will experience a change in speed, but its frequency will remain unchanged.
The refractive index of the unknown glass walls of the Aquarium of Fishy Death is approximately 1.38.
The critical angle for total internal reflection can be used to determine the refractive index of a medium. By measuring the critical angle for light directed out of the aquarium and knowing the refractive index of carbon disulfide (CS2), which is 1.63, we can calculate the refractive index of the unknown glass.
The refractive index is the reciprocal of the sine of the critical angle. In this case, the refractive index of the unknown glass is approximately 1.38.
To calculate it: refractive index of the unknown glass = 1 / sin(65.2°) ≈ 1.38
To learn more about frequency click here brainly.com/question/29739263
#SPJ11
A body with mass m = 20 g should, after being sprung by a spring with spring constant k = 4.8N/cm
was fired, run through a loop path of radius r = 0.5 m without friction.
a) Sketch the forces acting on the body at different points in time.
b) By which piece t do you have to tighten the spring so that the body straightens the loop path
still goes through without falling down?
a) The forces acting on the body at different points in time include gravitational force, normal force, and spring force.
When the body is at the bottom of the loop, the forces include gravitational force, normal force, and centripetal force. At the top of the loop, the forces include gravitational force, normal force, and tension force.
b) To determine the required spring compression, we need to consider the equilibrium of forces at the top of the loop. The gravitational force must provide the necessary centripetal force for the body to complete the loop. By equating these forces, we can solve for the spring compression required to maintain the loop path without the body falling down.
a) When the body is not in contact with the spring, only the gravitational force is acting on it. As the body is sprung, it experiences an upward spring force that opposes the gravitational force. When the body is at the bottom of the loop, in addition to the gravitational force and spring force, there is also a normal force acting upward to counterbalance the gravitational force. At the top of the loop, the forces acting on the body include gravitational force, normal force, and tension force. The normal force provides the necessary centripetal force for the body to follow the curved path.
b) At the top of the loop, the net force acting on the body must be inward, providing the required centripetal force. The net force is given by the difference between the tension force and the gravitational force:
Tension - mg = mv²/r,
where Tension is the tension force, m is the mass of the body, g is the acceleration due to gravity, v is the velocity of the body at the top of the loop, and r is the radius of the loop. Solving for the required tension force, we have:
Tension = mg + mv²/r.
The tension force in the spring is equal to the spring constant multiplied by the compression of the spring:
Tension = k * compression.
Setting the two expressions for tension equal to each other, we can solve for the required spring compression:
mg + mv²/r = k * compression,
compression = (mg + mv²/r) / k.
By substituting the given values of mass, radius, and spring constant, along with the acceleration due to gravity, you can calculate the required spring compression to maintain the loop path without the body falling down.
Learn more about gravitational here: brainly.com/question/3009841
#SPJ11
QUESTION 2. The diagram below is an end view of two long, straight, parallel conductors carrying current in the directions shown. If an electron is moving with a velocity v = -3.00 x 10^- at the point P, what net magnetic force docs it experience due to the two conductors? 2 -- 8 cm 12= 15.0A koi 6 cm 1,- 10.01
Electron at point P experiences magnetic force to the left.
Magnetic field is defined as a region of space around a magnet where the force of magnetism acts. A magnetic field is produced when a current flows through a wire. Consider the two parallel conductors with current flowing in opposite directions, creating magnetic fields in opposite directions. When an electron moves with velocity through a magnetic field, it experiences a magnetic force which is given by the formula F=qvBsinθ.
The direction of the magnetic force can be determined using Fleming’s Left Hand Rule. The magnetic field due to conductor AB at point P will be directed into the page while that due to conductor CD will be directed out of the page. The electron moves towards the conductor CD and so the magnetic force on it will be to the left.
Learn more about magnetic force here:
https://brainly.com/question/30532541
#SPJ11
What is the frequency f of a 2.89×10 −19 J photon? f= Hz What is the wavelength λ of a 2.89×10 −19 J photon? λ=
The frequency can be expressed as [tex]4.366 *10^{14} Hz[/tex]the wavelength λ can be expressed as [tex]6.876 *10^{-7} meters[/tex]
How can the wavelength be calculated?The frequency of a repeated event is its number of instances per unit of time. For clarity and to distinguish it from spatial frequency, it is also sometimes referred to as temporal frequency.
Frequency is measured in hertz which is equal to one event per secondGiven that Energy =2.89×10 −19 J
h = plank constant = [tex]6.626 *10^{-34}[/tex]
E = hf
f = E / h
f = [tex]\\\frac{2.89* 10^{-19} }{ 6.626*10^{-34} }[/tex]
f= [tex]4.366 *10^{14} Hz[/tex]
To calculate the wavelength we can use
λ = c / f
λ = [tex]\\\frac{2.998 *10^8}{4.366*10^14}[/tex]
λ =[tex]6.876 *10^-7 meters[/tex]
Learn more about wavelength at;
https://brainly.com/question/10728818
#SPJ4
Two identical, 1.2-F capacitors are placed in series with a 12-V battery. How much
energy is stored in each capacitor? (in J)
Each capacitor will store the same amount of energy which is 72 J.
Capacitance is the amount of charge a capacitor can store at a given potential. The formula for calculating the energy stored in a capacitor is given by E = (1/2) × C × V² where E is the energy, C is the capacitance, and V is the potential difference. In the given problem, two identical 1.2 F capacitors are placed in series with a 12 V battery, thus the total capacitance will be half of the individual capacitance i.e. 0.6 F. Using the formula above, we get
E = (1/2) × 0.6 F × (12 V)²= 43.2 J.
This is the total energy stored in both capacitors. Since the capacitors are identical and connected in series, each capacitor will store the same amount of energy, which is 43.2 J ÷ 2 = 21.6 J. Therefore, the energy stored in each capacitor is 21.6 J.
Learn more about capacitance here:
https://brainly.com/question/31871398
#SPJ11
Problem 29.32 A simple generator is used to generate a peak output voltage of 33.4 V. The square armature consists of windings that are 5.25 cm on a side and rotates in a field of 0.386 T at a rate of 65.0 rev/s. Part A How many loops of wire should be wound on the square armature? Express your answer as an integer. N =
The number of turns of wire that should be wound on the square armature is 541 turns
Part A
The EMF induced in the coil is given by this equation;
ε= -NΔΦ/Δt
where:N= Number of turns of wire in the coil, ΔΦ = Change in magnetic flux, Δt = Change in time
The magnetic flux Φ is given by;
Φ = BA
where:B = Magnetic field strength, A = Area of the coil
Since the coil is square, the area is given byA = a²where:a = Length of one side of the square armature
Therefore, the flux can be given as;Φ = Ba²
The EMF equation can be written as;ε= -N (B a²)/Δt
Rearranging the equation, we get
N = -ε Δt / B a²
Now, substituting the given values, we have;
ε = 33.4V (peak value), B = 0.386 T (Tesla), a = 5.25 cm = 0.0525 , mΔt = 1/65 seconds (time for one revolution since the armature rotates at a rate of 65 rev/s),
N = -33.4V (1/65 s) / (0.386 T) (0.0525 m)²≈ 541 turns
Therefore, the number of turns of wire that should be wound on the square armature is 541 turns.
Let us know more about square armature : https://brainly.com/question/14159664.
#SPJ11
What must be the charge (in nm) on each of the two 64-kg
spherical masses for the electric force to equal the gravitational
force? Give your answer to one decimal place.
The force of gravity acting on the masses is given by the formula;
F = Gm₁ m₂/r²
where G is the gravitational constant, m₁ and m₂ are the masses, and r is the distance between the masses.
Since the electric force must be equal to the gravitational force,
F₁ = F₂ = Gm₁ m₂/r²
where F₁ is the electric force on one mass and F₂ is the electric force on the other mass.
Since the two masses are to have the same charge (q),
the electric force on each mass can be given by the formula.
F = kq²/r²
where k is the Coulomb constant, and q is the charge on each mass.
Similarly,
F₁ = F₂ = kq²/r²
Combining the two equations.
kq²/r² = Gm₁ m₂/r²
Dividing both sides by r².
kq²/m₁ m₂ = G
Now, the charges on the masses can be given by
q = √ (Gm₁ m₂/k)
Substituting the given values, and using the fact that the mass of each sphere is given by.
m = (4/3)πr³ρ
where ρ is the density, and r is the radius.
q = √ (6.67 × 10^-11 × 64 × 64 / 9 × 10^9)
q = √ 291.56q = 17.06 × 10^-9 C (to one decimal place)
the charge on each mass must be 17.06 nm.
To know more about gravity visit:
https://brainly.com/question/31321801
#SPJ11
A radio tuner circuit is made up of a 40 ohm resistor, a 0.5 mH coil, and a variable capacitor. If the capacitor is set to 72 pF. Calculate the inductive reactance, if the source frequency has the value of the resonant frequency of 839 KHz
The inductive reactance in the given radio tuner circuit, consisting of a 40 ohm resistor, a 0.5 mH coil, and a variable capacitor set to 72 pF, can be calculated based on the resonant frequency of the source signal, which is specified as 839 KHz.
In summary, the inductive reactance is 24.49 ohms.
Now let's dive into the explanation. The inductive reactance (XL) is determined by the formula XL = 2πfL, where f is the frequency in hertz and L is the inductance in henries. Given that the coil has an inductance of 0.5 mH (or 0.0005 H) and the resonant frequency of the source is 839 KHz (or 839,000 Hz), we can substitute these values into the formula.
XL = 2π * 839,000 * 0.0005 = 2π * 419.5 ≈ 1319.867 ohms.
Therefore, the inductive reactance is approximately 1319.867 ohms.
Learn more about Inductive reactance here : brainly.com/question/17431388
#SPJ11
0.5 mol of diatomic ideal gas is confined in a volume of 200 cm ^3
. Take Avogadro numbers as 6.02×10 ^23
. When the temperature is 27 ∘C. Calculate (a) the pressure, (b) the total translational kinetic energy, (c) the average translational energy of single molecule, (d) the total internal energy.
Kinetic energy is the energy possessed by an object due to its motion. The answers are:
a) The pressure of the gas is approximately 623.36 Pa.
b) The total translational kinetic energy of the gas is approximately 932.71 J.
c) The average translational kinetic energy of a single molecule is approximately 3.092 J.
d) The total internal energy of the gas is approximately 932.71 J.
Kinetic energy is the energy possessed by an object due to its motion. In the context of gases, kinetic energy refers to the energy associated with the random translational motion of gas particles.
The kinetic energy of a gas particle is directly proportional to its temperature. As temperature increases, the average kinetic energy of the gas particles also increases. This is because temperature is a measure of the average kinetic energy of the particles in a substance.
To solve this problem, we can use the ideal gas law and the equations for kinetic energy and internal energy of a gas.
(a) To find the pressure, we can use the ideal gas law equation:
[tex]PV = nRT[/tex]
Where:
P = pressure
V = volume
n = number of moles of gas
R = gas constant (8.314 J/(mol·K))
T = temperature in Kelvin
First, we need to convert the volume from cm³ to m³:
[tex]V = 200 cm^3 = 200 * 10^{-6} m^3[/tex]
Next, we need to convert the temperature from Celsius to Kelvin:
[tex]T = 27 C + 273.15 = 300.15 K[/tex]
Now we can calculate the pressure:
[tex]P = (nRT) / V\\P = (0.5 mol * 8.314 J/(mol.K) * 300.15 K) / (200 * 10^{-6} m^3)\\P = 623.3625 Pa[/tex]
Therefore, the pressure of the gas is approximately 623.36 Pa.
(b) The total translational kinetic energy of a gas can be calculated using the equation:
[tex]KE = (3/2) nRT[/tex]
Where:
KE = total kinetic energy
n = number of moles of gas
R = gas constant
T = temperature in Kelvin
[tex]KE = (3/2) * 0.5 mol * 8.314 J/(mol.K) * 300.15 K\\KE = 932.71125 J[/tex]
The total translational kinetic energy of the gas is approximately 932.71 J.
(c) The average translational kinetic energy of a single molecule can be found by dividing the total kinetic energy by the number of molecules (Avogadro's number):
[tex]Average KE = Total KE / Number of molecules\\Average KE = 932.71125 J / (0.5 mol * 6.02×10^{23})\\Average KE = 3.092 J[/tex]
The average translational kinetic energy of a single molecule is approximately 3.092 J.
(d) The total internal energy of an ideal gas consists of its translational kinetic energy only, so the total internal energy is equal to the total translational kinetic energy calculated in part (b):
[tex]Total Internal Energy = Total KE\\Total Internal Energy = 932.71125 J[/tex]
The total internal energy of the gas is approximately 932.71 J.
For more details regarding kinetic energy, visit:
https://brainly.com/question/999862
#SPJ4
The answers are as follows:
a) Pressure = 6.2325 × 10⁵ Pa.
b) Total Translational Kinetic Energy = 1869.75 J.
c) Average Translational Energy of Single Molecule = 6.21 × 10⁻²¹ J.
d) Total Internal Energy = 1869.75 J.
The ideal gas law is PV = nRT where n is the number of moles of gas and R is the universal gas constant (R = 8.31 J/mol K).
(a) Pressure, The ideal gas law is PV = nRT. Pressure, P = nRT / V, where n = 0.5 mol, R = 8.31 J/mol K, T = (27 + 273) K = 300 K and V = 200 cm³ = 2 × 10⁻⁴ m³P = 0.5 × 8.31 × 300 / 2 × 10⁻⁴= 623250 Pa = 6.2325 × 10⁵ Pa
(b) Total Translational Kinetic Energy, The translational kinetic energy per molecule is given by the relation K.E = (3/2) kT, where k is the Boltzmann constant (k = 1.38 × 10⁻²³ J/K). The total translational kinetic energy is given by E = (3/2) nRT. Total translational kinetic energy E = (3/2) × 0.5 × 8.31 × 300 = 1869.75 J
(c) Average Translational Kinetic Energy of a Single Molecule, The average translational kinetic energy per molecule is given by E/n = (3/2) kT. E/n = (3/2) × 1.38 × 10⁻²³ × 300 = 6.21 × 10⁻²¹ J.
(d) Total Internal Energy The internal energy of an ideal gas is given by U = (3/2) nRT. Total internal energy U = (3/2) × 0.5 × 8.31 × 300 = 1869.75 J.
Learn more about kinetic energy
https://brainly.com/question/999862
#SPJ11
1. If you are standing at the outer edge of a rotating carousel,?
a. you are accelerating toward the center.
b. accelerating in the forward direction.
c. accelerating away from the center.
d.not accelerating.
2. As a planet moves in an elliptical orbit around its star,
a. it speed is faster as it is moving closer to the star and slower as it moves further away.
b. fastest when it is closest to the star.
c. constant.
d. fastest when it is furthest from the star.
3.Heat flow is
a. proportional to separation distance.
b. inversely proportional to thermal conductivity.
c. inversely proportional to temperature difference.
d. proportional to surface area.
4. Electric current is a wire is
a. a flow of negative particles.
b. always clockwise if the charges are negative.
c. a flow of both positive and negative particles.
d. a flow of positive particles.
1. If you are standing at the outer edge of a rotating carousel, you are accelerating away from the center.
Option C is correct.
2. As a planet moves in an elliptical orbit around its star, its speed is faster as it is moving closer to the star and slower as it moves further away.
Option A is correct
3. Heat flow is inversely proportional to temperature difference.
Option C is correct.
4. Electric current in a wire is a flow of both positive and negative particles.
Option C is correct.
How do we explain?1. When you are standing at the outer edge of a rotating carousel, you experience a centrifugal force pulling you outward and this force causes an acceleration away from the center of the carousel.
2. According to Kepler's laws of planetary motion, a planet in an elliptical orbit moves faster when it is closer to the star and slower when it is further away and this because of the conservation of angular momentum.
3. Heat flow occurs from a region of higher temperature to a region of lower temperature and the rate of heat flow is directly proportional to the temperature difference between the two regions.
4.Electric current can consist of the movement of both positive and negative particles, depending on the specific situation.
Learn more about Kepler's laws at:
https://brainly.com/question/25900771
#SPJ4
(10%) Problem 8: A detailed graph of acceleration versus time is shown. 10.0 (s/w)v +5.0- -5.0 5.0 15.0 te: 5/19/2022 11:59:00 PM 20.0 25.0 t(s) 20% Part (a) What is the instantaneous acceleration at time 14.25 s? a = 1 m/s² sin() tan() Л () 7 8 9 HOME cotan() acos() E 4 5 6 atan() sinh() 7 1 2 3 cosh() cotanh() + END . 0 VO BACKSPACE 1 Degrees CLEAR Submit Hint Feedback I give up! Hints: 5% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. 20% Part (b) What is the change in velocity during the time interval from 3.75 s to 7.75 s? A 20% Part (c) What is the change in velocity during the time interval from 7.75 s to 14.25 s? A 20% Part (d) If the initial velocity is 21 m/s, then what is the velocity at time 19.25 s? A 20% Part (e) What is the average acceleration during the time interval from 7.75 s to 26 s? All content 2022 Expert TA, LLC. cos() asin() acotan() tanh() Radians
Part(a) The instantaneous acceleration at time 14.25 s is 1 m/s².
Part (b) The change in velocity during the time interval from 3.75 s to 7.75 s is 40 m/s.
Part (c) The change in velocity during the time interval from 7.75 s to 14.25 s is 0 m/s.
Part (d) The velocity at time 19.25 s is 211.5 m/s.
Part (e) The average acceleration during the time interval from 7.75 s to 26 s is 10 m/s².
Part (a)
Instantaneous acceleration is the derivative of velocity with respect to time. So, a = dv/dt. The instantaneous acceleration at time t = 14.25 s can be determined by finding the slope of the tangent line to the curve at t = 14.25 s. Since the graph of acceleration versus time is a straight line, its slope, and therefore the instantaneous acceleration at any point, is constant.
Using the formula for the slope of a line, we can determine the instantaneous acceleration at time t = 14.25 s as follows:
slope = (change in y-coordinate)/(change in x-coordinate)
slope = (5 m/s² - (-5 m/s²))/(15 s - 5 s)
slope = 10 m/s² / 10 s
slope=1 m/s²
Therefore, the instantaneous acceleration at time 14.25 s is 1 m/s².
Part (b)
The change in velocity from 3.75 s to 7.75 s can be determined by finding the area under the curve between these two times. Since the graph of acceleration versus time is a straight line, the area is equal to the area of a trapezoid with parallel sides of length 5 m/s² and 15 m/s², and height of 4 s.
area = (1/2)(5 + 15)(4) = 40 m/s
Therefore, the change in velocity during the time interval from 3.75 s to 7.75 s is 40 m/s.
Part (c)
The change in velocity from 7.75 s to 14.25 s can be determined in the same way as in part (b). The area of the trapezoid is given by:
area = (1/2)(-5 + 5)(14.25 - 7.75) = 0 m/s
Therefore, the change in velocity during the time interval from 7.75 s to 14.25 s is 0 m/s.
Part (d)
The velocity at time t = 19.25 s can be found by integrating the acceleration function from the initial time t = 0 to the final time t = 19.25 s and adding the result to the initial velocity of 21 m/s. Since the acceleration is constant over this interval,
we can use the formula:
v = v0 + at where v0 is the initial velocity, a is the constant acceleration, and t is the time interval. The velocity at time 19.25 s is therefore:
v = 21 m/s + (10 m/s²)(19.25 s - 0 s)
= 211.5 m/s
Therefore, the velocity at time 19.25 s is 211.5 m/s.
Part (e)
The average acceleration during the time interval from 7.75 s to 26 s can be found by dividing the total change in velocity over this interval by the total time. The total change in velocity can be found by subtracting the final velocity from the initial velocity:
v = v1 - v0v = (10 m/s²)(26 s - 7.75 s)
= 182.5 m/s
The total time is:
t = 26 s - 7.75 s
=18.25 s
Therefore, the average acceleration during the time interval from 7.75 s to 26 s is:
a = (v1 - v0)/t
= 182.5 m/s / 18.25 s
10 m/s².
Learn more about average acceleration here
https://brainly.com/question/32760795
#SPJ11
This question about acceleration, velocity, and time can be resolved using principles in physics. Instantaneous acceleration, change in velocity, and average acceleration can be calculated using specific strategies to solve the student's given problems.
Explanation:The problems mentioned are about the relationship of acceleration, velocity, and time, which are fundamental concepts in Physics. To solve these problems, we need to understand these definitions properly. An instantaneous acceleration is the acceleration at a specific point in time and it is found by looking at the slope of the velocity vs time graph at the given point. If you want to find the change in velocity, you need to calculate the area under the acceleration vs time graph between the two points. The velocity at a particular time can be found by integrating the acceleration function or calculating the area under the acceleration vs time graph up to that time and adding the starting velocity. The average acceleration from one time to another can be found by taking the change in velocity and dividing by the change in time.
Learn more about Acceleration and Velocity here:https://brainly.com/question/32193954
#SPJ12
During a certain time interval, the angular position of a swinging door is described by 0 = 4.96 + 10.10 + 2.01t2, where is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 rad w = rad/s Trad/s2 a = (b) t = 2.92 s 0 = rad W= rad/s a = rad/s2
The given times:
(a) t = 0: θ = 4.96 radians, ω = 10.10 rad/s, α = 4.02 rad/s^2
(b) t = 2.92 s: θ ≈ 46.04 radians, ω ≈ 22.80 rad/s, α = 4.02 rad/s^2
To determine the angular position, angular speed, and angular acceleration of the door at different times, we need to take derivatives of the given equation.
The given equation is:
θ = 4.96 + 10.10t + 2.01t^2
Taking the derivative with respect to time (t), we get:
ω = dθ/dt = d/dt(4.96 + 10.10t + 2.01t^2)
Differentiating each term separately, we have:
ω = 0 + 10.10 + 2 * 2.01t
Simplifying, we get:
ω = 10.10 + 4.02t rad/s
Now, taking the derivative of angular speed (ω) with respect to time (t), we get:
α = dω/dt = d/dt(10.10 + 4.02t)
The derivative of a constant term is zero, so we have:
α = 0 + 4.02
Simplifying, we get:
α = 4.02 rad/s^2
Now, we can substitute the given values of time (t) to find the angular position, angular speed, and angular acceleration at those times.
(a) For t = 0:
θ = 4.96 + 10.10(0) + 2.01(0)^2
θ = 4.96 radians
ω = 10.10 + 4.02(0)
ω = 10.10 rad/s
α = 4.02 rad/s^2
(b) For t = 2.92 s:
θ = 4.96 + 10.10(2.92) + 2.01(2.92)^2
Calculating this value gives us:
θ ≈ 46.04 radians
ω = 10.10 + 4.02(2.92)
Calculating this value gives us:
ω ≈ 22.80 rad/s
α = 4.02 rad/s^2
To know more about Angular acceleration:
brainly.com/question/14769426
#SPJ11
At what temperature will both the reading in Celsius and Fahrenheit read the same value? Show your calculations.
The temperature at which both the Celsius and Fahrenheit scales read the same value is -40 °C/°F.
The Celsius temperature scale is used by most of the world, while the Fahrenheit scale is used primarily in the United States. The formula to convert Fahrenheit to Celsius is C = (5/9)(F - 32), and the formula to convert Celsius to Fahrenheit is F = (9/5)C + 32.In order for the Celsius and Fahrenheit scales to read the same value, we must set C equal to F and solve for the temperature, so we have:C = F5/9(F - 32) = (9/5)CF = - 40°C = - 40°F
Thus, at a temperature of -40 °C/°F, both the Celsius and Fahrenheit scales will read the same value.Calculations:As per the formula,F = (9/5)C + 32Putting C = F, we get;C = (9/5)C + 32C - (9/5)C = 32-4/5C = 32C = - 40Therefore, both the Celsius and Fahrenheit scales read the same value at -40 °C/°F.
To know more about temperature visit:
https://brainly.com/question/15809796
#SPJ11
Eric wants to test his caramel candies he made to see if they are sticky. He designs a tube he can put the clay in, pump it up with air, and release it with an impressive velocity. A particular piece of caramel is 14.0 g and is launched horizontally at a 124.0 g wooden block initially at rest on a level driveway. The caramel sticks to the block. The caramel and block slide 9.5 m before coming to rest. As measured in an earlier lab exercise, the coefficient of friction between block and pavement is 0.580 (it is pretty rough). What was the speed of the caramel (in m/s) immediately before impact with the block?
m/s
The speed of the caramel immediately before impact with the block was approximately 8.63 m/s.
Given:
- Mass of caramel (m₁) = 14.0 g = 0.014 kg
- Mass of wooden block (m₂) = 124.0 g = 0.124 kg
- Distance traveled (d) = 9.5 m
- Coefficient of friction (μ) = 0.580
To find the speed of the caramel before impact, we can use the principle of conservation of mechanical energy. The initial mechanical energy of the system is equal to the final mechanical energy.
The initial mechanical energy is the kinetic energy of the caramel, and the final mechanical energy is the work done by friction.
The initial kinetic energy (KE₁) of the caramel can be calculated using:
KE₁ = (1/2) * m₁ * v₁²
The work done by friction (W_friction) can be calculated using:
W_friction = μ * m₂ * g * d
Setting the initial kinetic energy equal to the work done by friction, we have:
(1/2) * m₁ * v₁² = μ * m₂ * g * d
Solving for v₁ (the speed of the caramel before impact), we get:
v₁ = sqrt((2 * μ * m₂ * g * d) / m₁)
Plugging in the given values, we have:
v₁ = sqrt((2 * 0.580 * 0.124 kg * 9.8 m/s² * 9.5 m) / 0.014 kg) ≈ 8.63 m/s
Therefore, the speed of the caramel immediately before impact with the block was approximately 8.63 m/s.
The speed of the caramel immediately before impact with the block was approximately 8.63 m/s.
To know more about impact visit:
https://brainly.com/question/29972013
#SPJ11
A mop is pushed across the floor with a force F of 41.9 N at an angle of 0 = 49.3°. The mass of the mop head is m = 2.35 kg. Calculate the magnitude of the acceleration a of the mop head if the coefficient of kinetic friction between the mop head and the floor is μ = 0.330. a = 3.79 Incorrect m/s² HK
Resolve the applied force F into its components parallel and perpendicular to the floor. The magnitude of the acceleration of the mop head can be calculated using the following steps:
F_parallel = F * cos(θ)
F_perpendicular = F * sin(θ)
Calculate the frictional force acting on the mop head.
f_friction = μ * F_perpendicular
Determine the net force acting on the mop head in the horizontal direction.
F_net = F_parallel - f_friction
Use Newton's second law (F_net = m * a) to calculate the acceleration.
a = F_net / m
Substituting the given values into the equations:
F_parallel = 41.9 N * cos(49.3°) = 41.9 N * 0.649 = 27.171 N
F_perpendicular = 41.9 N * sin(49.3°) = 41.9 N * 0.761 = 31.8489 N
f_friction = 0.330 * 31.8489 N = 10.5113 N
F_net = 27.171 N - 10.5113 N = 16.6597 N
a = 16.6597 N / 2.35 kg = 7.0834 m/s²
Therefore, the magnitude of the acceleration of the mop head is approximately 7.08 m/s².
Summary: a = 7.08 m/s²
To learn more about acceleration click here.
brainly.com/question/31946450
#SPJ11
10 Joules of work are done moving a -5 uC charge from one location to another. What was the change in potential in kilovolts?
The change in potential in kilovolts is -2000 kV.
Given that 10 Joules of work are done moving a -5 uC charge from one location to another. The change in potential in kilovolts has to be found.
To find the change in potential (ΔV), use the formula:
ΔV = W / qwhere,ΔV = Change in potential (in volts, V)
W = Work done (in Joules, J)q = Charge (in Coulombs, C)
Thus,ΔV = W / q = 10 / (-5 x 10^-6) = -2,000,000 V
Now, we need to convert it to kilovolts: 1 kV = 10^3 V
Therefore,
ΔV in kilovolts = -2,000,000 V / 1000= -2000 kV
To know more about potential:
https://brainly.com/question/30634467
#SPJ11
The gauge pressure in a certain manometer reads 50.12 psi. What is the density (in pound-mass/cubic inch) of the fluid if the height is 49.88 inches? Report your answer in 2 decimal places. From the previous question, if the atmospheric pressure is 14.7 psi. What is the absolute pressure in psi? Report your answer in 2 decimal places. Next
From the question above, Gauge pressure, Pg = 50.12 psi
Height, h = 49.88 inches
Density of the fluid, ρ = ?
We can use the relation P = ρgh,
where P is the pressure exerted by the fluid at the bottom of the container and g is the acceleration due to gravity.
By simplifying the above relation, we get:
ρ = P / gh
Substituting the given values, we get:ρ = 50.12 / (49.88 × 0.0361)ρ = 39.64 lbm/in³
If the atmospheric pressure is 14.7 psi and the gauge pressure is 50.12 psi, then the absolute pressure can be calculated as follows:
Absolute pressure = Atmospheric pressure + Gauge pressure= 14.7 psi + 50.12 psi= 64.82 psi
Learn more about the pressure at
https://brainly.com/question/32326195
#SPJ11
Electrons are ejected from a metallic surface with speeds of up to 4.60 × 10⁵ m/s when light. with a wavelength of 625nm is used. (b) What is the cutoff frequency for this surface?
When light with a wavelength of 625 nm is used, the cutoff frequency for the metallic surface is 4.80 × 10¹⁴ Hz. This means that any light with a frequency greater than or equal to this cutoff frequency will be able to eject electrons from the surface.
The cutoff frequency refers to the minimum frequency of light required to eject electrons from a metallic surface. To find the cutoff frequency, we can use the equation:
cutoff frequency = (speed of light) / (wavelength)
First, we need to convert the wavelength from nanometers to meters. The given wavelength is 625 nm, which is equivalent to 625 × 10⁻⁹ meters.
Next, we substitute the values into the equation:
cutoff frequency = (3.00 × 10⁸ m/s) / (625 × 10⁻⁹ m)
Now, let's simplify the equation:
cutoff frequency = (3.00 × 10⁸) × (1 / (625 × 10⁻⁹))
cutoff frequency = 4.80 × 10¹⁴ Hz
Therefore, the cutoff frequency for this surface is 4.80 × 10¹⁴ Hz.
To know more about frequency visit:
https://brainly.com/question/29739263
#SPJ11
The electric field of an electromagnetic wave is given by E = 10^2 N/C sin(kx - wt) j, where the
wavelength ^ = 533 nm. The value of c is?
The value of c, representing the speed of light, is approximately 3.00 x 10^8 meters per second.
To find the value of c, which represents the speed of light, we can use the formula c = λ * f, where λ is the wavelength and f is the frequency.
The wavelength λ = 533 nm, we need to convert it to meters to match the SI unit system. Since 1 nm = 1e-9 m, we have λ = 533 nm * 1e-9 m/nm = 5.33e-7 m.
To find the frequency, we can use the relationship between the wavelength and frequency for an electromagnetic wave, which is given by the equation c = λ * f.
Rearranging the equation, we have f = c / λ.
Substituting the values, we have f = c / (5.33e-7 m).
Comparing this with the given electric field equation E = 10^2 N/C sin(kx - wt) j, we can see that the term (kx - wt) represents the phase of the wave. In this case, since the wave is traveling in the j-direction, we can equate kx - wt to π/2.
Now, we can rewrite the frequency equation as f = c / (5.33e-7 m) = ω / (2π), where ω is the angular frequency.
Since k = 2π / λ, we have ω = ck.
Substituting the known values, we have f = c / (5.33e-7 m) = (ck) / (2π).
Comparing this with the given phase equation, we can equate ck to 1, giving us ck = 1.
Substituting this into the frequency equation, we have f = 1 / (2π).
Therefore, the value of c, which represents the speed of light, is equal to c = λ * f = (5.33e-7 m) * (1 / (2π)).
Performing the calculation, we find that c ≈ 3.00e8 m/s.
Hence, the value of c, the speed of light, is approximately 3.00e8 meters per second.
learn more about "electromagnetic ":- https://brainly.com/question/13874687
#SPJ11
Atr 486 s after midnight, a spacecraft of mass 1600 kg is located at position 310, 810-410 m, and at that time an asteroid whose mass is 6x 1015 kg is located at position 2x 10-9 10-16x 10 m. There are no other objects nearby. Part 1 Your answer is incorrect. (a) Calculate the (vector) force acting on the spacecraft. IN Attempts: 5 of 10 used Submit Answer Save for Later Part 2 (b) Atr= 486s the spacecraft's momentum was 7, and at the later time=494 s its momentum was 7, Calculate the (vector) change of momentum 7-7 kgm/s 1
(a) The force acting on the spacecraft can be calculated using Newton's law of universal gravitation. The formula is F = G * (m1 * m2) / r^2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
Plugging in the values, we get:
F = (6.674 × 10^-11 N m^2/kg^2) * ((1600 kg) * (6 × 10^15 kg)) / ((2 × 10^-9 m) - (10^-16 × 10 m))^2
The calculated value of force vector will provide the magnitude and direction of the force acting on the spacecraft due to the asteroid's gravitational pull.
(b) To calculate the change in momentum of the spacecraft, we subtract the initial momentum from the final momentum using the formula Δp = p2 - p1.
Given that the initial momentum is 7 kg m/s and the final momentum is also 7 kg m/s, the change in momentum is:
Δp = 7 kg m/s - 7 kg m/s = 0 kg m/s
Hence, the change in momentum vector of the spacecraft is zero, indicating that there is no net change in the spacecraft's momentum during the given time interval.
To learn more about gravitation , click here : https://brainly.com/question/16082883
#SPJ11
An emf of 15.0 mV is induced in a 513-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic
flux through each turn of the coil at an instant when the current is 3.80 A? (Enter the magnitude.)
Explanation:
We can use Faraday's law of electromagnetic induction to solve this problem. According to this law, the induced emf (ε) in a coil is equal to the negative of the rate of change of magnetic flux through the coil:
ε = - dΦ/dt
where Φ is the magnetic flux through the coil.
Rearranging this equation, we can solve for the magnetic flux:
dΦ = -ε dt
Integrating both sides of the equation, we get:
Φ = - ∫ ε dt
Since the emf and the rate of current change are constant, we can simplify the integral:
Φ = - ε ∫ dt
Φ = - ε t
Substituting the given values, we get:
ε = 15.0 mV = 0.0150 V
N = 513
di/dt = 10.0 A/s
i = 3.80 A
We want to find the magnetic flux through each turn of the coil at an instant when the current is 3.80 A. To do this, we first need to find the time interval during which the current changes from 0 A to 3.80 A:
Δi = i - 0 A = 3.80 A
Δt = Δi / (di/dt) = 3.80 A / 10.0 A/s = 0.380 s
Now we can use the equation for magnetic flux to find the flux through each turn of the coil:
Φ = - ε t = -(0.0150 V)(0.380 s) = -0.00570 V·s
The magnetic flux through each turn of the coil is equal to the total flux divided by the number of turns:
Φ/ N = (-0.00570 V·s) / 513
Taking the magnitude of the result, we get:
|Φ/ N| = 1.11 × 10^-5 V·s/turn
Therefore, the magnetic flux through each turn of the coil at the given instant is 1.11 × 10^-5 V·s/turn.
A constant horizontal force moves a 50 kg trunk 6.5 m up 31 degree incline a constant speed. the coefficient of kinetic friction between the trunk and incline is 0.20.
a. what is the work done by applied force?
b. what is the increase in thermal energy of the trunk and incline?
a. The work done by the applied force is approximately 1380.3 Joules.
b. The increase in thermal energy of the trunk and incline is approximately 551.2 Joules.
a. The work done by the applied force can be calculated by multiplying the magnitude of the force by the distance moved in the direction of the force. In this case, the force is acting horizontally, so we need to find the horizontal component of the applied force. The horizontal component of the force can be calculated as F_applied × cos(theta), where theta is the angle of the incline.
F_applied = m × g × sin(theta),
F_horizontal = F_applied × cos(theta).
Plugging in the values:
m = 50 kg,
g = 9.8 m/s² (acceleration due to gravity),
theta = 31 degrees.
F_applied = 50 kg × 9.8 m/s² × sin(31 degrees) ≈ 246.2 N.
F_horizontal = 246.2 N × cos(31 degrees) ≈ 212.2 N.
The work done by the applied force is given by:
Work = F_horizontal × distance,
Work = 212.2 N × 6.5 m ≈ 1380.3 Joules.
Therefore, the work done by the applied force is approximately 1380.3 Joules.
b. The increase in thermal energy of the trunk and incline is equal to the work done against friction. The work done against friction can be calculated by multiplying the magnitude of the frictional force by the distance moved in the direction of the force.
Frictional force = coefficient of kinetic friction × normal force,
Normal force = m × g × cos(theta).
Plugging in the values:
Coefficient of kinetic friction = 0.20,
m = 50 kg,
g = 9.8 m/s² (acceleration due to gravity),
theta = 31 degrees.
Normal force = 50 kg × 9.8 m/s² × cos(31 degrees) ≈ 423.9 N.
Frictional force = 0.20 × 423.9 N ≈ 84.8 N.
The increase in thermal energy is given by:
Thermal energy = Frictional force × distance,
Thermal energy = 84.8 N × 6.5 m ≈ 551.2 Joules.
Therefore, the increase in thermal energy of the trunk and incline is approximately 551.2 Joules.
To learn more about thermal energy, Visit:
https://brainly.com/question/19666326
#SPJ11
3. An inductor with an inductance of 2.50 H and a resistor of 8.00 are connected to the terminals of a battery with an emf of 6.00 V. Find: A. The initial rate of increase of current in the circuit (d
The initial rate of increase of current in the circuit is 2.08 A/s.We need to find the initial rate of increase of current in the circuit (dI/dt)To determine the initial rate of increase of current in the circuit,
The current through an inductor changes with time. The current increases as the magnetic flux through the inductor increases. The induced EMF opposes the change in current. This effect is known as inductance. The inductance of a coil is directly proportional to the number of turns of wire in the coil. The unit of inductance is Henry (H).
The formula for current in a circuit that contains only inductor and resistor is: R = resistance of the circuit L = inductance of the circuitt = timeTo determine the initial rate of increase of current in the circuit, we differentiate the above equation with respect to time Now, we substitute the given values in the above equation
To know more about Current visit :
https://brainly.com/question/15549563
#SPJ11
Consider a ball 1 is moving with a velocity 6.00 m/s and it collides with another identical ball 2 which is initially at rest. Calculate the velocity of the billiard ball 2 after the collision (Hint: Assume that the collision between the balls is one-dimensional). Choose an answer 9.00 m/s B 3.00 m/s C 12.0 m/s D 6.00 m/s
The velocity of ball 2 after the collision with ball 1, assuming a one-dimensional collision, is 3.00 m/s. Therefore the correct option is B. 3.00 m/s.
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision.
Let's assume the mass of both balls is the same. We'll denote the mass of each ball as m.
The initial momentum of ball 1 is given by its mass (m) multiplied by its initial velocity (6.00 m/s), which is 6m. Since ball 2 is initially at rest, its initial momentum is zero.
After the collision, the two balls will move together. Let's denote the final velocity of both balls as v. According to the conservation of momentum, the total momentum after the collision should be equal to the total momentum before the collision.
The final momentum is the sum of the momenta of both balls after the collision, which is (2m) * v since both balls have the same mass. Setting the initial momentum equal to the final momentum, we have:
6m + 0 = 2m * v
Simplifying the equation, we find:
6 = 2v
Dividing both sides by 2, we get:
v = 3.00 m/s
Therefore, the velocity of ball 2 after the collision is 3.00 m/s.
To know more about collision click here:
https://brainly.com/question/30636941
#SPJ11
A highway is made of concrete slabs that are 17.1 m long at 20.0°C. Expansion coefficient of concrete is α = 12.0 × 10^−6 K^−1.
a. If the temperature range at the location of the highway is from −20.0°C to +33.5°C, what size expansion gap should be left (at 20.0°C) to prevent buckling of the highway? answer in mm
b. If the temperature range at the location of the highway is from −20.0°C to +33.5°C, how large are the gaps at −20.0°C? answer in mm
The gap size at -20.0°C is 150 mm + 0.9 mm + 7.7 mm = 159.6 mm.
a. The expansion gap size at 20.0°C to prevent buckling of the highway is 150 mm. b.
The gap size at -20.0°C is 159.6 mm.
The expansion gap is provided in the construction of concrete slabs to allow the thermal expansion of the slab.
The expansion coefficient of concrete is provided, and we need to find the size of the expansion gap and gap size at a particular temperature.
The expansion gap size can be calculated by the following formula; Change in length α = Expansion coefficient L = Initial lengthΔT = Temperature difference
At 20.0°C, the initial length of the concrete slab is 17.1 mΔT = 33.5°C - (-20.0°C)
= 53.5°CΔL
= 12.0 × 10^-6 K^-1 × 17.1 m × 53.5°C
= 0.011 mm/m × 17.1 m × 53.5°C
= 10.7 mm
The size of the expansion gap should be twice the ΔL.
Therefore, the expansion gap size at 20.0°C to prevent buckling of the highway is 2 × 10.7 mm = 21.4 mm
≈ 150 mm.
To find the gap size at -20.0°C, we need to use the same formula.
At -20.0°C, the initial length of the concrete slab is 17.1 m.ΔT = -20.0°C - (-20.0°C)
= 0°CΔL
= 12.0 × 10^-6 K^-1 × 17.1 m × 0°C
= 0.0 mm/m × 17.1 m × 0°C
= 0 mm
The gap size at -20.0°C is 2 × 0 mm = 0 mm.
However, at -20.0°C, the slab is contracted by 0.9 mm due to the low temperature.
Therefore, the gap size at -20.0°C is 150 mm + 0.9 mm + 7.7 mm = 159.6 mm.
Learn more about gap size from the given link;
https://brainly.com/question/31841356
#SPJ11
In the torque and equilibrium lab, we measured the mass of the unkown mass m2. A mass 341 g is placed at the 40 cm of a meter stick as shown in the figure while the knife edge is placed at the 50 cm (center of mass ). The unkown mass is placed at 77 cm to have the system in equilibrium. What is the value of the clockwise torque in Nm ?
The clockwise torque in the torque and equilibrium lab is 1.236466 Nm.
Torque is a force that causes rotation. It is calculated by taking the force, F, and multiplying it by the distance, r, between the point of application of the force and the axis of rotation. In this case, the axis of rotation is the fulcrum.
The force in this case is the weight of the unknown object, m2. The weight of an object is equal to its mass, m, multiplied by the acceleration due to gravity, g. So, the force is:
F = mg
The distance between the point of application of the force and the axis of rotation is the distance from the fulcrum to the object. In this case, that distance is 77 cm.
So, the torque is:
τ = mgr
τ = (0.341 kg)(9.8 m/s^2)(0.77 m)
τ = 1.236466 Nm
This is the clockwise torque. The counterclockwise torque is equal to the clockwise torque, so the system is in equilibrium.
To learn more about torque here brainly.com/question/30338175
#SPJ11
A force of 200 N is exerted at an angle of 30° with respect to the horizontal on an object whose mass is 30 kg. The coefficient of friction between the object and the surface is 0.2. (a) What is the normal force (b) What is the frictional force (c) What is the acceleration of the object.? (d) If the object starts from rest what is the velocity after 5 seconds? 200N 30⁰ 30 kg
(a) The normal force acting on the object is 294.33 N.
(b) The frictional force between the object and the surface is 58.87 N.
(c) The acceleration of the object is 3.89 m/s².
(d) If the object starts from rest, the velocity after 5 seconds is 19.45 m/s.
(a) To find the normal force, we need to resolve the force vector into its vertical and horizontal components. The vertical component is given by the formula Fₙ = mg, where m is the mass of the object and g is the acceleration due to gravity. Substituting the given values, we have Fₙ = 30 kg × 9.8 m/s² = 294 N.
(b) The frictional force can be calculated using the formula Fᵣ = μFₙ, where μ is the coefficient of friction and Fₙ is the normal force. Substituting the values, we get Fᵣ = 0.2 × 294 N = 58.8 N.
(c) The net force acting on the object can be determined by resolving the force vector into its horizontal and vertical components. The horizontal component is given by Fₓ = Fcosθ, where F is the applied force and θ is the angle with respect to the horizontal. Substituting the values, we have Fₓ = 200 N × cos(30°) = 173.2 N.
The net force in the horizontal direction is the difference between the applied force and the frictional force, so F_net = Fₓ - Fᵣ = 173.2 N - 58.8 N = 114.4 N. The acceleration can be calculated using the equation F_net = ma, where m is the mass of the object. Substituting the values, we get 114.4 N = 30 kg × a, which gives us a = 3.81 m/s².
(d) If the object starts from rest, we can use the equation v = u + at to find the velocity after 5 seconds, where u is the initial velocity (0 m/s), a is the acceleration (3.81 m/s²), and t is the time (5 seconds). Substituting the values, we have v = 0 + 3.81 m/s² × 5 s = 19.05 m/s. Therefore, the velocity after 5 seconds is approximately 19.45 m/s.
To know more about frictional force refer here:
https://brainly.com/question/30280206#
#SPJ11
1. Two waves meet at a time when one has the instantaneous amplitude A and the other has the instantaneous amplitude B. Their combined amplitude at this time is:
a. A +B
b. indeterminate
c. between A +B and A- B
d. A - B
2. A pure musical tone causes a thin wooden panel to vibrate. This is an example of:
a. an overtone
b. interference
c harmonics
d. resonance
3. The sound of a starting pistol can be heard easily from a distance of 800.0 m but the smoke can be seen much sooner than the sound is perceived. Why is the smoke seen before the sound is heard? What is the speed of sound if the air temperature is 15 °C?
4. While relaxing at a wave pool after a physics test, you notice the wave machine making 12 waves in 40 s and the wave crests are 3.6 metres apart.
a) Determine the velocity that the waves must be traveling. b) If your friend told you that he can make the waves travel faster by increasing the frequency to 0.5 waves per second would you agree? Explain. What would be the actual change in the wave if the frequency was increased?
The correct answer is c. between A + B and A - B. When two waves meet, their combined amplitude at any given point is the sum of the individual amplitudes of the waves at that point.
However, the resulting amplitude can vary depending on the phase relationship between the waves. If the waves are in phase (peaks and troughs align), the combined amplitude will be A + B. If they are completely out of phase (peaks align with troughs), the combined amplitude will be A - B. If they are somewhere in between, the combined amplitude will be between A + B and A - B.
The correct answer is d. resonance. When a pure musical tone causes a thin wooden panel to vibrate, it is an example of resonance. Resonance occurs when an object or system is forced to vibrate at its natural frequency by an external stimulus. In this case, the musical tone is exciting the natural frequency of the wooden panel, causing it to vibrate.
Smoke is seen before the sound is heard because light travels much faster than sound. When a starting pistol is fired, the smoke created by the explosion is visible almost immediately because light travels at a much higher speed than sound. Sound, on the other hand, travels at a slower speed. The speed of sound in air depends on various factors, including temperature. At 15 °C, the speed of sound is approximately 343 meters per second.
a) The velocity of the waves can be calculated using the formula:
Velocity = Distance / Time
The distance between wave crests is 3.6 meters and the time for 12 waves is 40 seconds, we can calculate the velocity as follows:
Velocity = 12 waves * 3.6 meters / 40 seconds = 1.08 m/s
b) Increasing the frequency to 0.5 waves per second would not make the waves travel faster. The velocity of the waves depends on the properties of the medium, such as the depth of the water in the wave pool. Changing the frequency does not alter the speed of the waves. However, increasing the frequency would result in shorter wavelengths and a higher number of wave crests passing a point per unit time.
The actual change in the wave, if the frequency was increased, would be a shorter distance between wave crests, resulting in a higher wave density. The height or amplitude of the waves would not be affected by changing the frequency unless there are other factors involved, such as changes in the wave-generating mechanism.
To know more about wave interference visit;
https://brainly.com/question/9655287
#SPJ11