labor-hours and its standard cost card per unit is as follows:
Direct material: $ pounds at $11.00 per pound
Direct labor: 3 hours at $12 per hour
Variable overhead: 3 hours at $7 per hour
Total standard variable cost per unit
The company also established the following cost formulas for its selling expenses:
sales salaries and commissions
shipping expenses
Fixed Cost per
Month
$ 280,000
$ 260,000
$ 55.00
36.00
$112.00
Variable
Cost per
Unit Sold
$ 20.00
$ 11.00
The planning budget for March was based on producing and selling 21,000 units. However, during March the company
actually produced and sold 26.600 units and incurred the following costs:
a Purchased 154.000 pounds of raw materials at a cost of $9.50 per pound. All of this material was used in production.
b. Direct laborers worked 63,000 hours at a rate of $13.00 per hour
e Total variable manufacturing overhead for the month was $510,930
d Total advertising sales salaries and commissions, and shipping expenses were $286,000, $495,000, and $195,000,
respectively
6 What direct labor cost would be included in the company's flexible budget for March?

Answer:

Step-by-step explanation:

Of course! I'd be happy to help you.

Let's simplify the expression f(x) + 8x - 8x^3 - x^4 + 6 step by step:

The given expression is: f(x) + 8x - 8x^3 - x^4 + 6

Since we don't have any specific information about f(x), we'll assume that f(x) is a constant or a function that doesn't depend on x. In that case, f(x) can be treated as a constant term.

Combining like terms, we have:

f(x) - x^4 - 8x^3 + 8x + 6

There is no further simplification we can do without additional information about the function f(x) or any specific values of x. Therefore, the simplified expression is:

f(x) - x^4 - 8x^3 + 8x + 6

Answer:

To write the polynomial function m(x) = x + x^2 - 1 in standard form, we rearrange the terms in descending order of degree:

m(x) = x^2 + x - 1

Polynomial name: Quadratic polynomial

Degree: 2 (the highest exponent is 2)

Leading coefficient: 1 (the coefficient of the highest-degree term)

Constant term: -1 (the term without any variable)

The torque experienced by the rigid body is -17.10375 k N·m.

To determine the torque experienced by a rigid body when a force is applied, we need to calculate the cross product between the force vector and the radius vector from the point of application of the force to the point of rotation.

Since a force F = (4.501 - 3.25) N is applied and the radius vector is r = (1.801 + 2.50j) m, where j is the imaginary unit, we can calculate the cross product using the formula:

Torque = r x F

The cross product between two vectors is calculated as follows:

Torque = (r_x * F_y - r_y * F_x)k

Where r_x and r_y are the components of the radius vector and F_x and F_y are the components of the force vector. Furthermore, k is a unit vector in the direction of the axis of rotation.

Substituting the given values, we have:

Torque = ((1.801 * -3.25) - (2.50 * 4.501))k

Calculating the cross product:

Torque = (-5.85125 - 11.2525)k

Simplifying:

Torque = -17.10375k

Therefore, the torque experienced by the rigid body is -17.10375 k N·m.

The negative sign indicates that the torque is in the opposite direction to the axis of rotation. The magnitude of the torque is measured in newtons per meter (N·m) and represents the capacity of a force to produce a rotation in a rigid body around a specific axis.

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The solution to the equation sqrt 2-3x / sqrt 4x = 2 is x = -2/3.

To solve the equation, we must first clear the denominators and simplify the equation. We can do this by multiplying both sides by sqrt(4x) and then squaring both sides. This gives us:
sqrt 2-3x = 4sqrt x
2 - 6x + 9x² = 16x
9x² - 22x + 2 = 0
Using the quadratic formula, we can find that x = (-b ± sqrt(b² - 4ac)) / 2a. Plugging in a = 9, b = -22, and c = 2, we get:
x = (-(-22) ± sqrt((-22)² - 4(9)(2))) / 2(9)
x = (22 ± sqrt(352)) / 18
x = (22 ± 4sqrt22) / 18
Simplifying this expression, we get:
x = (11 ± 2sqrt22) / 9
Therefore, the solution to the equation is x = -2/3.
To solve the equation sqrt 2-3x / sqrt 4x = 2, we must clear the denominators and simplify the equation. This involves multiplying both sides by sqrt(4x) and then squaring both sides.

After simplifying, we end up with a quadratic equation. Using the quadratic formula, we can find that the solutions are x = (11 ± 2sqrt22) / 9.

However, we must check that these solutions do not result in a division by zero, as the original equation involves square roots. It turns out that the only valid solution is x = -2/3.

Therefore, this is the solution to the equation.

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Answer:

there is no solution

Step-by-step explanation:

x + y = 6 → (1)

x + y = 4 → (2)

subtract (2) from (1) term by term

(x - x) + (y - y) = 6 - 4

0 + 0 = 2

0 = 2 ← false statement

this false statement indicates the equations have no solution

Answer:

W = V/(LH)

Step-by-step explanation:

All we are doing is isolating W. Since V=LWH, then dividing both sides by LH will put W by itself on the right-hand side, you have V/(LH) = W as your equation

Answer:

Step-by-step explanation:

To solve the equation (2/3)t - (1/5)t = 2 for t, we need to combine like terms and isolate the variable t. Here are the steps:

(2/3)t - (1/5)t = 2

To combine the fractions, we need to find a common denominator for 3 and 5, which is 15.

[(2/3)(5/5)]t - [(1/5)(3/3)]t = 2

(10/15)t - (3/15)t = 2

[(10 - 3)/15]t = 2

(7/15)t = 2

To isolate t, we can multiply both sides of the equation by the reciprocal of (7/15), which is (15/7).

[(7/15)t][(15/7)] = 2[(15/7)]

t = (2 * 15) / 7

t = 30/7

Therefore, the solution for t in the equation (2/3)t - (1/5)t = 2 is t = 30/7 or t ≈ 4.286.

The cost per trainee for the 5-week training course is $7,000.

To find the cost per trainee, we divide the total cost of the training course by the number of trainees.

Total cost of the training course = $140,000

Number of trainees = 20

Cost per trainee = Total cost of the training course / Number of trainees

Cost per trainee = $140,000 / 20

Cost per trainee = $7,000

Therefore, the cost per trainee for the 5-week training course is $7,000.

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Ryan paid $5,560 in 2009.

Let's solve the problem using the given information: Amount paid in 2010 by Ryan = $1,112 Amount paid in 2010 is 80% less than the amount paid in 2009.

So, the amount paid in 2009 can be calculated as follows: Let x be the amount paid by Ryan in 2009.

Then we can write, $1,112 = x - 0.8x Simplifying this expression, we get:$1,112 = 0.2x Dividing both sides of the equation by 0.2, we get: x = $5,560

Therefore, Ryan paid $5,560 in 2009. I hope this helps.

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Answer:

Comparing the centers of the data sets:

- The median for Data Set A is greater than the median for Data Set B.

- The mean for Data Set A is greater than the mean for Data Set B.

Comparing the variability of the data sets:

- The range of Data Set A is 22, while the range of Data Set B is 27. Therefore, the range of Data Set B is greater.

- The standard deviation of Data Set A is greater than the standard deviation of Data Set B, indicating higher variability in Data Set A.

The equation is y = 7.75x, where x is the number of hours Steven babysits and y is the amount he charges.

To represent the relationship between the number of hours Steven babysits (x) and the amount he charges (y), we can use a linear equation in the form of y = mx + b, where m is the slope and b is the y-intercept.

From the given information, we can identify two data points:

(4, 31.00) and (8, 62.00)

Using these points, we can calculate the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

m = (62.00 - 31.00) / (8 - 4)

m = 31.00 / 4

m = 7.75

Now, we can substitute one of the points and the slope into the equation to find the y-intercept (b).

Using the point (4, 31.00):

31.00 = 7.75(4) + b

31.00 = 31.00 + b

b = 0

Therefore, the equation that represents the relationship between the number of hours Steven babysits (x) and the amount he charges (y) is:

y = 7.75x

The equation is y = 7.75x, where x is the number of hours Steven babysits and y is the amount he charges.

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Domain: The domain is the range of valid heights for the mountain, which is from 3300 feet to 8920 feet.

Range: The range is the set of all possible heights of the linear model, which in this case is also from 3300 feet to 8920 feet.

Domain: The domain of the linear model in this context would represent the possible values for the x variable, which is associated with the height of the mountain.

In this case, the meaningful domain would be the range of valid heights that the mountain can have.

Since the top of the mountain is at 8920 feet and the base is at 3300 feet, the meaningful domain would be the range of heights between 3300 feet and 8920 feet.

Therefore, the domain in this scenario would be [3300, 8920].

Range: The range of the linear model in this context would represent the possible values for the y variable, which is associated with the height of the mountain.

The range would be the set of all possible heights that the linear model can produce.

In this case, since the top of the mountain is at 8920 feet and the base is at 3300 feet, the range would encompass all the valid heights within this range.

Therefore, the range in this scenario would be [3300, 8920].

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Answer:

the first 2

Step-by-step explanation:

let me know if it is wrong

Answer:

x=50

Step-by-step explanation:

Make this equal to 180.

x+3x-35+x-35 = 180

5x = 180 + 70

5x=250

x=50

Answer: O (4, -4)

Step-by-step explanation:

To solve the system of equations using elimination, we can multiply the second equation by -3 to eliminate the y term:

Original equations:

5x + 3y = 8 (Equation 1)

4x + y = 12 (Equation 2)

Multiply Equation 2 by -3:

-3(4x + y) = -3(12)

-12x - 3y = -36 (Equation 3)

Now we can add Equation 1 and Equation 3 to eliminate the y term:

(5x + 3y) + (-12x - 3y) = 8 + (-36)

Simplifying:

5x - 12x + 3y - 3y = 8 - 36

-7x = -28

Divide both sides by -7:

x = -28 / -7

x = 4

Now substitute the value of x back into either of the original equations, let's use Equation 2:

4(4) + y = 12

16 + y = 12

y = 12 - 16

y = -4

Therefore, the solution to the system of equations is x = 4 and y = -4.

The perimeter of the rectangle is 140 inches.

Let's denote the width of the rectangle as w. According to the given information, the length of the rectangle is six times its width, so we can express the length as 6w.

The area of a rectangle is given by the formula A = length × width. Substituting the values we have:

A = (6w) × w

600 = 6w^2

To solve for w, we divide both sides of the equation by 6:

w^2 = 100

Taking the square root of both sides:

w = ±10

Since width cannot be negative in this context, we discard the negative value and consider the positive value, w = 10.

Now that we have the width, we can find the length of the rectangle:

Length = 6w = 6 × 10 = 60

The perimeter of a rectangle is given by the formula P = 2(length + width). Substituting the values:

P = 2(60 + 10)

P = 2(70)

P = 140

Therefore, the perimeter of the rectangle is 140 inches.

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The value of x that makes lines c and d parallel when cut by transversal p is 99 (option d).

To determine the value of x, we need to analyze the relationship between the given lines and transversal.

Recall that when two lines are cut by a transversal, the corresponding angles are congruent if the lines are parallel.

Since lines c and d are cut by transversal p, we need to find the corresponding angles that should be congruent.

Let's assume that angle 12 corresponds to angle 18. In order for lines c and d to be parallel, angle 12 must be congruent to angle 18.

However, angle 12 and angle 18 do not have equal values (12 ≠ 18). Therefore, we need to explore other possible values of x.

Let's try x = 81. With this value, angle 12 corresponds to angle 81. But again, angle 81 is not congruent to angle 18 (81 ≠ 18). Thus, x = 81 does not make lines c and d parallel.

Finally, let's try x = 99. With this value, angle 12 corresponds to angle 99. If angle 99 is congruent to angle 18, then lines c and d will be parallel.

Since 99 = 99, we can conclude that when x = 99, lines c and d are parallel when cut by transversal p.

Therefore, the value of x that makes lines c and d parallel when cut by transversal p is 99. Thus, the correct option is d.

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Solution:

Formula: Total = Group 1 + Group 2 - Both + Neither

where:

- Total = total number of girls in the class (34)

- Group 1 = number of girls playing tennis (21)

- Group 2 = number of girls playing netball (18)

- Both = number of girls playing both games (what we want to find)

- Neither = number of girls playing neither game (0, since all the girls play at least one game)

Plugging in the values, we get:

34 = 21 + 18 - Both + 0

Simplifying:

34 = 39 - Both

Both = 39 - 34

Both = 5

Answer:

Step-by-step explanation:

This may be wrong but hear me out, 40+10 is 50 and 11+1 is 12, so 12:50?

The measure of the interior angle at vertex F is 72 degrees.

A hexagon is a polygon with six sides. The sum of the interior angles of a hexagon is equal to 720 degrees.

The angle of the hexagon is given in terms of x,

The sum of the angle is equal to 720 degrees

[tex]4\text{x}+4\text{x}+4\text{x}+4\text{x}+2\text{x}+2\text{x} = 720[/tex]

[tex]20\text{x} = 720[/tex]

[tex]\text{x} = 36[/tex]

[tex]\bold{2x = 72^\circ}[/tex]

Therefore, the measure of interior angle at vertex F is equal to 72 degrees.

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Answer:

(fg)(x) = x^4 - x^3 + 15x^2 - 6x + 54

Step-by-step explanation:

We want to multiply and simplify as much as possible:

f(x) * g(x)

(x^2 + 6)(x^2 - x + 9)

(x^2 * x^2) + (x^2 * - x) + (x^2 * 9) + (6 * x^2) + (6 * - x) + (6 * 9)

Note that when you're multiplying exponents, we add them:

x^4 + - x^3 + 9x^2 + 6x^2 - 6x + 54

Now we add 9x^2 and 6x^2 as they are like terms:

x^4 - x^3 + 15x^2 - 6x + 54

Thus, (fg)(x) simplified is x^4 - x^3 + 15x^2 - 6x + 54.

Optional:  Check the validity of the answer:

We can check that our answer is correct by plugging in a number for x in both the unsimplified and simplified expression and seeing if we get the same answer.  Let's try 5:

Plugging in 5 for x in (x^2 + 6)(x^2 - x + 9):

(5^2 + 6)(5^2 - 5 + 9)

(25 + 6)(25 - 5 + 9)

(31)(20 + 9)

(31)(29)

899

Plugging in 5 for x in x^4 - x^3 + 15x^2 - 6x + 54:

5^4 - (5)^3 + 15(5)^2 - 6(5) + 54

625 - 125 + 15(25) - 30 + 54

625 - 125 + 375 - 30 + 54

500 + 375 - 30 + 54

875 - 30 + 54

845 + 54

899

Thus, our answer is correct.

Answer:

B)  There are two solutions, but only one is viable.

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}A=w^2+4w\\A=4w+45\end{cases}[/tex]

To solve the system of equations, substitute the first equation into the second equation:

[tex]w^2+4w=4w+45[/tex]

Solve for w using algebraic operations:

[tex]\begin{aligned}w^2+4w&=4w+45\\w^2+4w-4w&=4w+45-4w\\w^2&=45\\\sqrt{w^2}&=\sqrt{45}\\w&=\pm \sqrt{45}\\w &\approx \pm 6.71\; \sf cm\end{aligned}[/tex]

Therefore, there are two solutions to the given system of equations.

However, as length cannot be negative, the only viable solution is w ≈ 6.71 cm.

Answer:

Step-by-step explanation:

a. sin(0) = 0

The sine of 0 degrees is 0.

b. tan(N) = 6√5

We don't have enough information to determine the value of tan(N) without knowing the specific value of N.

c. cos(0) = 1

The cosine of 0 degrees is 1.

d. cos(N) = 6√5/6

Again, we can't determine the specific value of cos(N) without knowing the value of N.

Answer:

We can construct only one triangle with the given description(this triangle is unique).

It is isosceles so the two sides are congruent(

4

4 cm) each. The angle they form is specified

80

°

80° so there is no way to construct one more with the same characteristics(we will have to change the angle or the length of the two sides).

Step-by-step explanation:

Answer:

One triangle

Step-by-step explanation:

By the Law of Cosines, given two side lengths of 3 inches and an included angle of 20°, then we are able to get the length of the third side using the formula [tex]a^2=b^2+c^2+2bc\cos(A)[/tex]

Hence, you can construct only one triangle because of SAS Theorem.

...................................................................

Answer:

Step-by-step explanation:

the answer is 13 remaining papers

In a trial of 10 versus 500, the experimental probability is expected to be closer to the theoretical probability when there are more trials (500 in this case).

The experimental probability and theoretical probability can be compared in a trial of 10 versus 500 by understanding the concepts behind each type of probability.

Theoretical probability is based on mathematical calculations and is determined by analyzing the possible outcomes of an event. It relies on the assumption that the event is equally likely to occur, and it can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes. Theoretical probability is often considered the expected or ideal probability.

On the other hand, experimental probability is determined through actual observations or experiments. It involves conducting the event multiple times and recording the outcomes to determine the relative frequency of a specific outcome. The experimental probability is an estimation based on the observed data.

In the given trial of 10 versus 500, we can expect the experimental probability to be closer to the theoretical probability when the number of trials (or repetitions) is larger. In this case, with 500 trials, the experimental probability is likely to be a more accurate representation of the true probability.

When the number of trials is small, such as only 10, the experimental probability may deviate significantly from the theoretical probability. With a smaller sample size, the observed outcomes may not accurately reflect the expected probabilities calculated theoretically.

In summary, in a trial of 10 versus 500, the experimental probability is expected to be closer to the theoretical probability when there are more trials (500 in this case). As the number of trials increases, the observed frequencies are likely to converge towards the expected probabilities calculated theoretically.

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The equation 2y + 8x - 2 = 0 will satisfy the condition of having an infinite number of solutions when graphed with the given equation.

To form a system of equations that has an infinite number of solutions when graphed with the given equation, we need to find an equation that represents the same line or is a multiple of the given equation.

The given equation is: y + 4x - 1 = 0

To find an equation with an infinite number of solutions, we can multiply the given equation by a non-zero constant.

Let's multiply the given equation by 2:

2(y + 4x - 1) = 2(0)

2y + 8x - 2 = 0

The equation 2y + 8x - 2 = 0, when graphed with the given equation y + 4x - 1 = 0, will form a system that has an infinite number of solutions. The two equations represent the same line, just with different coefficients.

Therefore, the equation 2y + 8x - 2 = 0 will satisfy the condition of having an infinite number of solutions when graphed with the given equation.

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