Let f(x)=2x-1, h(x) = -x-5.
Find (f o h)(-3).
(foh)(-3)=

The side of the given square is 36W^2 + 12W +1 of is 6W +1 and 81W^2 -72W + 16 is (9W-4).

The area is calculated by multiplying the length of a shape by its width.

and the unit of the square is a square unit.

Given Area of the square :

1) [tex]36W^{2}+12W+1[/tex]

Area of square = [tex]36W^{2}+12W+1[/tex]

[tex]side^{2}[/tex] = [tex]36W^{2} + 6W +6W +1\\6W (6W +1) +1 (6W +1)\\(6W +1)(6W+1)\\(6W +1 )^{2} \\side^{2} = (6W + 1)^{2} \\side = 6W + 1[/tex]

[tex]Area of the square = 81W^{2} - 72W + 16\\(side)^{2} = (9W-4)(9W-4)\\(side)^{2} = (9W-4)^{2} \\side = (9W-4)[/tex]

Therefore the side of the square is 6W+1 and 9x-4.

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On solving the provided question we can say that As a result, the value angles of x is 23.

An angle is a shape in Euclidean geometry that is made up of two rays that meet at a point in the middle known as the angle's vertex. Two rays may combine to form an angle in the plane where they are located. When two planes collide, an angle is generated. They are referred to as dihedral angles. An angle in plane geometry is a possible configuration of two radiations or lines that express a termination. The word "angle" comes from the Latin word "angulus," which meaning "horn." The vertex is the place where the two rays, also known as the angle's sides, meet.

m(arc GH) = 122° plus 5x plus 7

5x + 129 = m(arc GH)

When we plug this into the equation we discovered earlier, we get:

5x + 7 = ½

(5x + 129)

10x + 14 = 5x + 129

5x = 115

x = 23

As a result, the value of x is 23.

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Answer:

Step-by-step explanation:

You want the 5th term and the general term of an geometric sequence with a1 = 7 and r = -3.

The general term of an arithmetic sequence is ...

  an = a1·r^(n-1)

For a1=7 and r=-3, the general term is ...

  an = 7·(-3)^(n-1)

Using n=5, the above equation evaluates to ...

  a5 = 7·(-3)^(5 -1)

  a5 = 7·(-3)^4 = 7·81

  a5 = 567

the correct answer is A: as x decreases to the vertical asymptote at x = -3, y decreases to negative infinity.

To determine the end behavior of the logarithmic function f(x) = log(x + 3) - 2, we need to look at what happens to the function as x approaches positive and negative infinity.

As x approaches negative infinity, the argument of the logarithm, (x + 3), becomes more and more negative. However, since logarithms are not defined for negative arguments, we need to shift the graph of the function to the left by 3 units to avoid the undefined region. This means that the vertical asymptote of the function is at x = -3. As x approaches -3 from the left, the argument of the logarithm becomes smaller and smaller negative numbers. However, the logarithm of a small negative number is a large negative number. Therefore, as x approaches -3 from the left, the function f(x) = log(x + 3) - 2 decreases to negative infinity. This eliminates options C and D.

As x approaches positive infinity, the argument of the logarithm, (x + 3), becomes more and more positive. Therefore, as x approaches positive infinity, the logarithm of (x + 3) becomes larger and larger. This means that the function f(x) = log(x + 3) - 2 approaches infinity as x approaches positive infinity. However, it approaches infinity from below since we subtract 2 from the logarithmic value.

To summarize, as x approaches -3 from the left, f(x) approaches negative infinity, and as x approaches positive infinity, f(x) approaches infinity from below. Therefore, the correct answer is A: as x decreases to the vertical asymptote at x = -3, y decreases to negative infinity.

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Step-by-step explanation:

The SSS (Side-Side-Side) Congruence Postulate states that if three sides of a triangle are congruent to three sides of another triangle, then the triangles are congruent.

To create your own SSS Congruence Postulate, you could use the following statement:

"If the corresponding sides of two triangles are congruent, then the triangles are congruent."

This postulate would encompass the SSS Postulate, as well as two other postulates: the SAS (Side-Angle-Side) Postulate and the ASA (Angle-Side-Angle) Postulate.

Using this postulate, you could show that two triangles are congruent if, for example, their corresponding sides are all 5cm long. This would mean that the triangles have the same shape and size, even if they are oriented differently.

Hopes this helps

Answer:

a) 4.46 miles

b) 3 miles

Step-by-step explanation:

Law of Sines:

[tex]\dfrac{\text{a}}{\text{sin(A)}} =\dfrac{\text{b}}{\text{sin(B)}}[/tex]

a) The distance of the plane from point A

The angle of depression corresponds to the congruent angle of elevation therefore, 180 - 28 - 52 = 100°

[tex]\dfrac{\text{6.7}}{\text{sin(100)}} =\dfrac{\text{b}}{\text{sin(41)}}[/tex]

[tex]\text{b}=\dfrac{6.7\text{sin}(41)}{\text{sin}(100)}[/tex]

[tex]\text{b}=4.46 \ \text{miles}[/tex]

b) Elevation of the plane

[tex]\text{sin}=\dfrac{\text{opposite}}{\text{hypotenuse}}[/tex]

hypotenuse is 4.46 and opposite is the elevation(h) to be found

[tex]\text{sin}(38)=\dfrac{\text{h}}{4.46}[/tex]

[tex]\text{h}=\text{sin}(38)4.46[/tex]

[tex]\text{h}=3[/tex]

Answer: Let's start by using the identity:

tan(arctan(x)) = x

to simplify the expression inside the sine function. So, we have:

arctan(u) / sqrt(3) = tan(arctan(u) / sqrt(3))

Now, using the trigonometric identity:

tan(x/y) = sin(x) / (cos(y) + sin(y))

with x = arctan(u) and y = sqrt(3), we get:

tan(arctan(u) / sqrt(3)) = sin(arctan(u)) / (cos(sqrt(3)) + sin(sqrt(3)))

Simplifying further, we know that:

sin(arctan(u)) = u / sqrt(1 + u^2)

and

cos(sqrt(3)) + sin(sqrt(3)) = 2cos(sqrt(3) - pi/4)

So, the expression becomes:

sin(arctan(u) / sqrt(3)) = u / sqrt(1 + u^2) / [2cos(sqrt(3) - pi/4)]

Simplifying the denominator, we have:

sin(arctan(u) / sqrt(3)) = u / sqrt(1 + u^2) / (2(cos(sqrt(3))cos(pi/4) + sin(sqrt(3))sin(pi/4)))

Using the values for cosine and sine of pi/4, we get:

cos(pi/4) = sin(pi/4) = 1/sqrt(2)

So, we have:

sin(arctan(u) / sqrt(3)) = u / sqrt(1 + u^2) / [2(sqrt(3)/2 + 1/2)]

Simplifying further:

sin(arctan(u) / sqrt(3)) = u / (sqrt(1 + u^2) * (sqrt(3) + 1))

Therefore, the algebraic expression for sin(arctan(u) / sqrt(3)) is:

u / (sqrt(1 + u^2) * (sqrt(3) + 1))

Step-by-step explanation:

The formula used to calculate the surface area of a triangular prism is:  

S = bh + 2ah  

Where S = surface area, b = length or side of the triangle, and h = height of the triangle.  

For right triangles, the height can be calculated as:  

c = a^(2) \+ b^(2)  

c = the hypotenuse  

a and b = the two sides of the triangle

Answer:

Step-by-step explanation:

A] five as 20 divided by four is five

The solution to the problem is that the number "x" must be greater than or equal to -12.

Let's define the variable as "x," representing the unknown number. According to the problem statement, one fourth of the number is no less than -3.

Mathematically, we can express this statement as:

x/4 ≥ -3

To solve for "x," we can start by multiplying both sides of the inequality by 4 to eliminate the fraction:

x ≥ -3*4

x ≥ -12

Therefore, the solution to the problem is that the number "x" must be greater than or equal to -12.

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so we're assuming there are 360 days in a year, so 83 days is really just 83/360 of a year, so

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$586.21\\ r=rate\to 6.3\%\to \frac{6.3}{100}\dotfill &0.063\\ t=years\dotfill &\frac{83}{360} \end{cases} \\\\\\ I = (586.21)(0.063)(\frac{83}{360}) \implies I \approx 8.51[/tex]

Step-by-step explanation:

6.

the figure can be considered as a combination of a 16×8 rectangle and a 10×8 right-angled triangle on the left side.

for both, perimeter and area, we need to find the length of the missing third side of the right-angled triangle, as this is a part of the long baseline of the overall figure.

as it is a right-angled triangle, we can use Pythagoras :

c² = a² + b²

"c" being the Hypotenuse (the side opposite of the 90° angle, in our case 10 ft). "a" and "b" being the legs (in our case 8 ft and unknown).

10² = 8² + (leg2)²

100 = 64 + (leg2)²

36 = (leg2)²

leg2 = 6 ft

that means the bottom baseline is 16 + 6 = 22 ft long.

a.

Perimeter = 10 + 16 + 8 + 22 = 56 ft

b.

Area is the sum of the area of the rectangle and the area of the triangle.

area rectangle = 16×8 = 128 ft²

area triangle (in a right-angled triangle the legs can be considered baseline and height) = 8×6/2 = 24 ft²

total Area = 128 + 24 = 152 ft²

7.

it was important that the bottom left angle of the quadrilateral was indicated as right angle (90°). otherwise this would not be solvable.

but so we know, it is actually a rectangle.

that means all corner angles are 90°.

therefore, the angle AMT = 90 - 20 = 70°.

the diagonals split these 90° angles into 2 parts that are equal in both corners of the diagonal, they are just up-down mirrored.

a.

so, the angle HTM = AMT = 70°.

b.

MEA is an isoceles triangle.

so, the angles AME and EAM are equal.

the angle AME = AMT = EAM = 70°.

the sum of all angles in a triangle is always 180°.

therefore,

the angle MEA = 180 - 70 - 70 = 40°

c.

both diagonals are equally long, and they intersect each other at their corresponding midpoints.

so, when AE = 15 cm, then AH = 2×15 = 30 cm.

TM = AH = 30 cm.

the overall score of Player A in the 2014 golf tournament was -15.

In golf, scores that are below par are represented with negative numbers. Therefore, to calculate the overall score, we need to add up all the scores.

Let's call the scores for each round A1, A2, A3, and A4, respectively. We can write the given scores as:

A1 = -4

A2 = -4

A3 = -4

A4 = -3

To find the overall score, we add up all the scores:

Overall score = A1 + A2 + A3 + A4

Overall score = (-4) + (-4) + (-4) + (-3)

Overall score = -15

Therefore, the overall score of Player A in the 2014 golf tournament was -15.

It's worth noting that in golf, the winner is the player who has the lowest score or the most negative score. So, in this case, Player A had the lowest score, making her the winner of the tournament.

In general, the overall score in golf can be calculated by adding up the scores for each hole or round. The player with the lowest score at the end of the tournament is declared the winner. Scores can be compared between different golfers or rounds, regardless of the difficulty of the course or weather conditions, by using the number of strokes above or below par.

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Answer:

The phase of the business cycle that would be marked by an increase in productivity while employment and profits also rise is known as the Expansion phase.

The solution of the equation is:  dy/dx = -3[tex]e^{3x}[/tex]/ √(1-[tex]e^{6x}[/tex])

What is the solution?

Let's start by using the chain rule to find dy/dx:

dy/dx = dy/du * du/dx

where u = [tex]e^{3x}[/tex]

We can find du/dx using the power rule:

du/dx = 3[tex]e^{3x}[/tex]

Now we need to find dy/du. We can use the derivative of arccos function:

dy/du = -1/√(1-u²)

Substituting u = [tex]e^{3x}[/tex], we get:

dy/dx = dy/du * du/dx

dy/dx = -1/√(1-[tex]e^{6x}[/tex]) * 3[tex]e^{3x}[/tex]

So the final answer is:

dy/dx = -3[tex]e^{3x}[/tex] / √(1-[tex]e^{6x}[/tex])

what is chain rule?

The chain rule is a fundamental rule of calculus that allows you to find the derivative of a composite function. A composite function is a function that is formed by taking one function and plugging it into another function.

For example, if we have two functions f(x) and g(x), the composite function is defined as:

h(x) = f(g(x))

To find the derivative of the composite function h(x), we use the chain rule, which states that:

h'(x) = f'(g(x)) * g'(x)

In words, this means that to find the derivative of the composite function, we first take the derivative of the outer function f(x) with respect to its input, evaluated at the inner function g(x), and then multiply it by the derivative of the inner function g(x) with respect to its input.

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Complete question is:  dy/dx = -3[tex]e^{3x}[/tex]/ √(1-[tex]e^{6x}[/tex])

The expression [tex]x^{5}[/tex]/[tex]x^{10}[/tex] can be written in two forms: Exponent form, which is simplified and has a base of x, and Fraction form, which has a numerator and denominator separated by a horizontal line.

Exponents are a shortened notation for repeated multiplication of a number, and exponent form is a means of formulating a mathematical equation using exponents. A superscript (a little raised number) is written to the right of a number or variable that has been raised to a power in exponent form.

There are two distinct but equal ways to write the expression "[tex]x^{5}[/tex]/[tex]x^{10}[/tex]":

Exponent form: In this format, the exponents of the equation are consolidated and made simpler. We may subtract the exponents in the denominator from the exponents in the numerator since the bases of the numerator and denominator are both x:

[tex]x^5/x^10 = x^(5-10) = x^(-5)[/tex]

Fraction form: In this format, the equation is expressed as a fraction with a horizontal line between the numerator and denominator. X is increased to the fifth power in the denominator and to the tenth power in the numerator:

[tex]x^5/x^10[/tex]

X is increased to the fifth power, or x, in the numerator. X is multiplied by 10 to create the denominator, or [tex]x^{10}[/tex].

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well, let's keep in mind that since a year has 12 months, then 17 months is really 17/12 of a year, so

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$1400\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\dotfill &\frac{17}{12} \end{cases} \\\\\\ I = (1400)(0.05)(\frac{17}{12}) \implies I \approx 99.17[/tex]

(A)  the annual rate of change between 1992 and 2006 was 0.0804

(B) r = 0.0804 * 100% = 8.04%

(C) value in 2009 = $11,650

What is the rate of change?

The rate of change is a mathematical concept that measures how much one quantity changes with respect to a change in another quantity. It is the ratio of the change in the output value of a function to the change in the input value of the function. It describes how fast or slow a variable is changing over time or distance.

A) The initial value is $44,000 and the final value is $15,000. The time elapsed is 2006 - 1992 = 14 years.

Using the formula for an annual rate of change (r):

final value = initial value * [tex](1 - r)^t[/tex]

where t is the number of years and r is the annual rate of change expressed as a decimal.

Substituting the given values, we get:

$15,000 = $44,000 * (1 - r)¹⁴

Solving for r, we get:

r = 0.0804

So, the annual rate of change between 1992 and 2006 was 0.0804 or approximately 0.0804.

B) To express the rate of change in percentage form, we need to multiply by 100 and add a percent sign:

r = 0.0804 * 100% = 8.04%

C) Assuming the car value continues to drop by the same percentage, we can use the same formula as before to find the value in the year 2009. The time elapsed from 2006 to 2009 is 3 years.

Substituting the known values, we get:

value in 2009 = $15,000 * (1 - 0.0804)³

value in 2009 = $11,628.40

Rounding to the nearest $50, we get:

value in 2009 = $11,650

Hence, (A)  the annual rate of change between 1992 and 2006 was 0.0804

(B) r = 0.0804 * 100% = 8.04%

(C) value in 2009 = $11,650

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According to the given condition, the correct expressions is:

cotαcotβ−1

Trigonometric equations are mathematical equations that involve trigonometric functions, such as sine, cosine, tangent, cotangent, secant, or cosecant, and their variables. Trigonometric equations typically involve finding the values of the unknowns that satisfy the given equation, subject to certain restrictions or conditions on the domain of the trigonometric functions.

According to the given information:

Using trigonometric identities, we can simplify the expression cos(α−β)cosαcosβ:

cos(α−β)cosαcosβ = cos(α−β) * (cosα * cosβ)

Next, we can use the identity cos(α−β) = cosαcosβ + sinαsinβ to substitute into the expression:

cos(α−β)cosαcosβ = (cosαcosβ + sinαsinβ) * (cosα * cosβ)

Now, we can distribute and simplify:

cos(α−β)cosαcosβ = cosα² * cosβ² + sinαsinβ * cosα * cosβ

Finally, using the identity cotα = 1/tanα, we can rewrite the expression as:

cos(α−β)cosαcosβ = cotαcotβ - 1

So, the equivalent expression is cotαcotβ - 1.

Therefore, according to the given condition. The correct answer is:

cotαcotβ−1

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The required answer is the speed limit of 90 km/h is equivalent to approximately 56 mph.

To convert the speed limit from kilometers per hour (km/h) to miles per hour (mph), use the conversion factor of 1 km/h = 0.621371 mph. Let's follow these steps:

Step 1: Determine the conversion factor.

Since we know the conversion factor is 1 km/h = 0.621371 mph,  use this to convert the speed limit from km/h to mph.

Step 2: Calculate the speed limit in mph.

The given speed limit is 90 km/h. Multiply this value by the conversion factor to obtain the equivalent speed in mph:

90 km/h x 0.621371 mph/km/h = 55.92339 mph

Step 3: Round the result, if necessary.

To provide a practical speed limit, we can round the result to the nearest whole number. Therefore, the speed limit in miles per hour is approximately 56 mph.

Hence, the speed limit of 90 km/h is equivalent to approximately 56 mph.

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Answer:

13.2 miles

Step-by-step explanation:

We can use the following conversion factors:

1 mile = 5,280 feet

Using this conversion, we can divide the height of the volcano in feet by 5,280 to get the height in miles:

69,657.652 ft ÷ 5,280 ft/mi ≈ 13.2 mi

Therefore, the height of the volcano on the recently discovered planet is approximately 13.2 miles.

Hopes this helps

Answer:

a) Area of STAR = 48 square units

b) Area of SKCO = 42 square units

Step-by-step explanation:

The formula for the area of a trapezoid is half the sum of the bases multiplied by the height:

[tex]\boxed{\sf Area=\dfrac{a+b}{2} \cdot h}[/tex]

The bases of a trapezoid are the parallel sides.

The height of a trapezoid is the perpendicular distance between the two bases.

The bases are parallel sides SR and TA.

The height is the perpendicular distance between SR and TA.

Therefore:

Substitute these values into the formula and solve for area:

[tex]\begin{aligned}\sf \implies Area\;STAR&=\dfrac{4+8}{2} \cdot 8\\\\&=\dfrac{12}{2} \cdot 8\\\\&=6\cdot 8\\\\&=48\;\sf square\;units\end{aligned}[/tex]

The bases are parallel sides SK and OC.

The height is the perpendicular distance between SK and OC.

Therefore:

Substitute these values into the formula and solve for area:

[tex]\begin{aligned}\sf \implies Area\;SKCO&=\dfrac{4+10}{2} \cdot 6\\\\&=\dfrac{14}{2} \cdot 6\\\\&=7 \cdot 6\\\\&=42\;\sf square\;units\end{aligned}[/tex]

Answer:

area=28cm^2

Step-by-step explanation:

4×5=20

20÷2=10 area of the bigger triangle

4×2=8

8÷2=4 area of the smaller triangle

10+10=20 for area of the the 2 bigger triangles

4+4=8 for the area of the 2 smaller triangles

area of kite= 20+8= 28

Answer:

2292.03

Step-by-step explanation:

Start with the formula for continuously compounded interest.

Then substitute all given values in the formula.

Finally, solve for the only variable remaining.

[tex] A = Pe^{rt} [/tex]

A = future value = $5000

P = principal (deposited amount) = unknown

r = 6.5% = 0.065

t = time = 12 years

[tex] 5000 = Pe^{0.065 \times 12} [/tex]

[tex] 5000 = Pe^{0.78} [/tex]

[tex]5000 = P \times 2.18147[/tex]

[tex] P = \dfrac{5000}{2.18147} [/tex]

[tex] P = 2292.03 [/tex]

Answer: $2292.03

Answer:

P = $2366.91

(maybe try answering without a comma)

Step-by-step explanation:

The formula for continuous compounding is:

A = Pe^(rt)

Where:

A = final amount

P = principal amount (initial deposit)

e = Euler's number (approximately 2.71828)

r = annual interest rate (as a decimal)

t = time (in years)

We are given:

r = 6.5% = 0.065 (annual interest rate)

t = 12 years

A = $5000 (final amount)

So we can rearrange the formula to solve for P:

P = A / e^(rt)

Substituting the values:

P = 5000 / e^(0.065*12)

P = $2366.91 (rounded to the nearest cent)

Therefore, you would need to deposit $2366.91 in an account with a 6.5% interest rate, compounded continuously, to have $5000 in your account 12 years later.

Answer:

50 spherical candles can be made with 152,604 cm³ of wax.

Step-by-step explanation:

Since the wax candles are in the shape of a solid sphere, we can calculate the volume of one candle by using the volume of a sphere formula.

[tex]\boxed{\begin{minipage}{4 cm}\underline{Volume of a sphere}\\\\$V=\dfrac{4}{3} \pi r^3$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

The diameter of a sphere is twice its radius.

Therefore, if the diameter of the spherical candle is 18 cm, its radius is:

[tex]\implies r=\dfrac{d}{2}=\dfrac{18}{2}=9\; \sf cm[/tex]

Substitute r = 9 and π = 3.14 into the formula to calculate the volume of one spherical candle.

[tex]\begin{aligned}\implies \textsf{Volume of one candle}&=\sf \dfrac{4}{3} \cdot 3.14 \cdot (9\;cm)^3\\\\&=\sf \dfrac{4}{3} \cdot 3.14 \cdot 729\;cm^3\\\\&=\sf 3052.08\; \sf cm^3\end{aligned}[/tex]

Given the company has a total of 152,604 cm³ of wax, to calculate how many candles can be made, divide the total amount of available wax by the wax needed to make one candle.

[tex]\begin{aligned}\textsf{Total number of candles}&=\sf \dfrac{152604\; cm^3}{3052.08 \;cm^3}\\\\&=\sf 50\end{aligned}[/tex]

Therefore, 50 spherical candles can be made with 152,604 cm³ of wax.

Answer:

The answer to your problem is, 75

Step-by-step explanation:

Yellow = [tex]\frac{1}{2}[/tex] of the marbles

Red = [tex]\frac{1}{8}[/tex] of the marbles

Blue = [tex]1 - \frac{1}{2} - \frac{1}{8} = \frac{1}{2} - \frac{1}{8}[/tex]

= [tex]\frac{1*4}{2*4} - \frac{1}{8}[/tex]

= [tex]\frac{1}{2} or \frac{4}{8} - \frac{1}{8}[/tex]

= [tex]\frac{3}{8}[/tex]

[tex]\frac{3}{8}[/tex] of the marbles are represented as blue.

200 x [tex]\frac{3}{8}[/tex] = 25 x 3 = 75

Thus the answer to your problem is, 75

D. Angle Addition Postulate is necessary when proving that the angles of a parallelogram are congruent.

What is parallelogram?

A parallelogram is a quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are equal in length, and the opposite angles are equal in measure.

To prove that opposite angles of a parallelogram are congruent, we need to use the properties of parallelograms, such as opposite sides are parallel and congruent, opposite angles are congruent, consecutive angles are supplementary, and diagonals bisect each other.

We do not need the Segment Addition Postulate, as it is used to find a length of a segment, not to prove the congruence of angles.

We also do not need to use the Opposite sides are perpendicular property, as this is only true for a rectangle or a rhombus, but not necessarily for a parallelogram.

Similarly, the Angle Addition Postulate is used to find the measure of an angle, not to prove that angles are congruent.

Therefore, the only necessary property to prove that opposite angles of a parallelogram are congruent is that opposite angles are congruent, which is a property of parallelograms.

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