multiply the y-value of each point by 1/2 and drag the blue point to its new location.​ using the cube root equation

According to given information, the solution to the given system of equations is (x, y) = (-1, -8).

In mathematics, an equation is a statement that two expressions are equal. It consists of two sides, a left-hand side and a right-hand side, separated by an equal sign (=).

A system of equations is a collection of two or more equations involving the same variables. The goal of solving a system of equations is to find the values of the variables that satisfy all the equations in the system simultaneously.

According to given information,

The given equations are:

y = 3x − 5

y = 10x + 2

To solve for x and y, we can equate the two expressions for y:

3x − 5 = 10x + 2

Simplifying this equation, we get:

3x - 10x = 2 + 5

-7x = 7

x = -1

Substituting the value of x in either of the original equations, we get:

y = 3(-1) - 5 = -8

or

y = 10(-1) + 2 = -8

Therefore, the solution to the given system of equations is (x, y) = (-1, -8).

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The solution to the system of equations is x = -1 and y = -8, written as the ordered pair (-1,-8).

What is an equation?

The equation is the mathematical statement showing that two mathematical expressions are equal. The equations have variables and the objective of solving an equation is to find the value of those variables.

To solve the system of equations:

Y = 3x − 5

Y = 10x + 2

This equation can be solved by substitution or elimination methods.

Using substitution method:

From the first equation,

Y = 3x - 5.

Substitute this value of Y into the second equation to get:

3x - 5 = 10x + 2

Simplifying and solving for x:

`7x = -7

x = -1

Substitute this value of x back into either of the original equations to get:

Y = 3(-1) - 5 = -8

Therefore, the solution to the system of equations is x = -1 and y = -8, written as the ordered pair (-1,-8).

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The location of the point W, the length of the altitude and the area of the triangle ΔXYZ are;

The coordinates of the point W is; (3.6, 5.8)

a) The altitude of the triangle is (12/5)·√5

b) The area of the triangle is 24 square units

The area of a triangle is the product of (1/2) × Base length × Height

The height of a triangle is the perpendicular distance from the base of the triangle to the vertex of the triangle, therefore;

The coordinates of the point W on the side XY, can be found from the coordinates of the points X and Y and the point Z as follows;

X(2, 5), Y(10, 9), and Z(6, 1)

The slope of the side XY = (9 - 5)/(10 - 2) = 4/8 = 1/2

The slope of the altitude is therefore; -2/1 = -2

The equation of XY is; y - 5 = (1/2)·(x -2)

y = x/2 - 2/2 + 5 = x/2 + 4

y = x/2 + 4

The equation of the altitude is; y - 1 = -2·(x - 6)

y = -2·x + 12 + 1

y = -2·x + 13

Therefore at W, we get;

x/2 + 4 = -2·x + 13

x = 18/5 = 3.6

y = -2 × (18/5) + 13 = 5.8

y = 5.8

The coordinate of the point W is (3.6, 5.8)

a. The altitude is therefore;

b. The area of the triangle, A = (1/2) × [tex]\overline{XY}[/tex] × [tex]\overline{ZW}[/tex]

Therefore; A = (1/2) × √((10 - 2)² + (9 - 5)²) × (12/5)·√5 = 24

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The TWO given model statements that are true for the given model are A and D.

The given passage describes a model that predicts the number of pounds of trash an apartment building needs to dispose of each week based on the number of tenants in the building.

The model is y = 6.4x + 13.9, where y is the number of pounds of trash, and x is the number of tenants in the building. The task is to select the TWO given model statements that are true for the given model. Let's analyze each statement:

A. For each additional tenant in the building, the amount of trash that needs to be disposed each week increases by 6.4 pounds.

This statement is true according to the given model equation, where the coefficient of x is 6.4. Therefore, for each additional tenant, the amount of trash that needs to be disposed of increases by 6.4 pounds.

B. When no tenants are in the building, other activities would require the disposal of 6.4 pounds of trash each week.

This statement is not true because the intercept of the model equation is 13.9, not 6.4. Therefore, when there are no tenants in the building, the amount of trash that needs to be disposed of is 13.9 pounds, not 6.4 pounds.

C. For each additional tenant in the building, the amount of trash that needs to be disposed each week increases by 13.9 pounds.

This statement is not true according to the given model equation, where the coefficient of x is 6.4, not 13.9. Therefore, for each additional tenant, the amount of trash that needs to be disposed of increases by 6.4 pounds, not 13.9 pounds.

D. When no tenants are in the building, other activities would require the disposal of 13.9 pounds of trash each week.

This statement is true according to the given model equation, where the intercept is 13.9. Therefore, when there are no tenants in the building, the amount of trash that needs to be disposed of is 13.9 pounds.

E. For each day, the building, the amount of trash that needs to be disposed each week increases by 20.3 pounds.

This statement is not true according to the given model equation, which only considers the number of tenants in the building, not the day of the week. Therefore, the amount of trash that needs to be disposed of does not increase by 20.3 pounds each day.

Therefore, the TWO given model statements that are true for the given model are A and D.

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Purposive sampling allows nurse researchers to select participants who fit specific criteria in qualitative studies, increasing the depth and richness of findings.

A nurse researcher would use purposive sampling when obtaining participants for a qualitative study because it allows researchers to select participants who fit the very specific types of criteria that are investigated in qualitative studies.

Purposive sampling is a non-random sampling method that is used when researchers want to select a sample that has certain characteristics or experiences that are relevant to the research question.

By using purposive sampling, the researcher can ensure that the participants have the specific knowledge or experience that is necessary to answer the research question, and can therefore provide more in-depth and insightful responses. This increases the richness and depth of the qualitative findings.

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For inequality –3(2x – 5) < 5(2 – x)  the correct option is (–6x + 15 < 10 – 5x).

What is inequality?

An inequality is a mathematical statement that describes a relationship between two values or expressions, indicating that they are not equal.

To solve the inequality –3(2x – 5) < 5(2 – x), we need to simplify the expression first.

Starting with the left-hand side, we can distribute the –3 to get:

–3(2x – 5) = –6x + 15

For the right-hand side, we can distribute the 5 to get:

5(2 – x) = 10 – 5x

Substituting these back into the original inequality, we get:

–6x + 15 < 10 – 5x

To solve for x, we can first move all the x terms to one side by adding 5x to both sides:

–x + 15 < 10

Then, we can move the constant term to the other side by subtracting 15 from both sides:

–x < –5

Finally, we can divide both sides by –1 (remembering to flip the inequality sign since we're dividing by a negative number) to get:

x > 5

So the first correct representation of the inequality is x > 5.

To get the second correct representation, we can also start with the inequality –6x + 15 < 10 – 5x, and move all the x terms to one side:

–6x + 5x < 10 – 15

So second option (–6x + 15 < 10 – 5x) are correct representations of the inequality.

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Emerson needs 3 bags in total to hold all of her snack mix .  

To determine the number of plastic bags that Emerson needs, we have to divide the total amount of snack mix by the amount of snack mix in each bag.      

Emerson made 8 cups of snack mix, and she puts 3 1/2 cups of mix into each bag. We can write this as a mixed number: 3 1/2 = 7/2. So Emerson puts 7/2 cups of mix into each bag.    

To find out how many bags Emerson needs, we divide the total amount of mix by the amount of mix in each bag:    

8 cups ÷ (7/2 cups per bag) = 16/7 bags

We can simplify 16/7 by dividing the numerator and denominator by 1 (the greatest common factor of 16 and 7)

16/7 ÷ 1/1 = 16/7 x 1/1 = 16/7

So Emerson needs 16/7, or approximately 2.29, bags. Since she can't use a fraction of a bag, she will need to round up to the nearest whole bag. Therefore, Emerson needs 3 bags in total to hold all of her snack mix.

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the solutions to the equation p²+14p=32 by square method are p = 2 or p = -16.

How to solve equation?

To solve the equation p²+14p=32 by the square method, we want to complete the square, which means transforming the left-hand side of the equation into a perfect square trinomial of the form (p + k)².

To do this, we need to add and subtract a constant term to the left-hand side of the equation.

First, we add (14/2)² = 49 to both sides of the equation:

p² + 14p + 49 = 81

Notice that we added 49 to both sides of the equation, not just the left-hand side. This maintains the equality of the equation.

Next, we can write the left-hand side as a perfect square trinomial:

(p + 7)² = 81

Now we take the square root of both sides of the equation:

p + 7 = ±9

Solving for p, we get:

p = -7 ± 9

which gives us two solutions:

p = 2 or p = -16

Therefore, the solutions to the equation p²+14p=32 by square method are p = 2 or p = -16.

In summary, to solve a quadratic equation by completing the square, we add and subtract a constant term to the left-hand side of the equation to create a perfect square trinomial. We then take the square root of both sides of the equation to solve for the variable.

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Answer:

P=20

Step-by-step explanation:

S=Ph+2B

96=4(P)+2(8)

96=4P+16

96-16=4P

80=4P

P=80/4

P=20

The answer is Positive Linear Correlation.

A scatter plot is a graphical representation of data points where each point represents two variables, typically plotted on the horizontal and vertical axes.

To construct a scatter plot, we need two sets of data:

one for the x-axis and one for the y-axis.

The data points are then plotted on the graph with the x-value along the horizontal axis and the y-value along the vertical axis.
To answer your question, I need to know what data you have to construct the scatter plot.

Once you provide me with the data, I can help you create the scatter plot and answer any questions you may have about it.
In general, scatter plots are used to identify any patterns or trends in the data.

By visually examining the scatter plot, we can determine whether the data points are positively or negatively correlated, or if there is no correlation between the two variables.

To determine the type of correlation, we can visually inspect the scatter plot. We see that as x increases, y tends to increase as well, indicating a positive linear correlation.

This can help us make predictions or draw conclusions about the relationship between the variables.
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The exact value of cos H from the right triangle is cos(H) = 0.98

From the question, we have the following parameters that can be used in our computation:

The right triangle

The exact value of cos H can be calculated as

cos(H) = HI/HJ

Where

HI = 40 and HJ = 41

So, we have

cos(H) = 40/41

Evaluate

cos(H) = 0.98

Hence, the value is 0.98

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Answer:

If the circular track has a circumference of 0.5 mile, then its circumference in feet is:

0.5 mile x 5,280 feet/mile = 2,640 feet

The formula for the circumference of a circle is:

C = 2πr

where C is the circumference and r is the radius of the circle. Substituting the values we have:

2,640 = 2 x 3.14 x r

Solving for r, we get:

r = 2,640 / (2 x 3.14) = 420.38 feet

Therefore, the radius of the circular track, in feet, is approximately 420.38 feet. Rounded to the nearest hundredth, the answer is 420.38 feet, which corresponds to the third option.

Answer: The equation a+b+c=240 degrees is not true for any triangle, since the sum of the angles of a triangle is always 180 degrees. However, it could be true for a quadrilateral, which has four angles. One way to explain why a+b+c=240 degrees is to use the fact that opposite angles of a cyclic quadrilateral (a quadrilateral that can be inscribed in a circle) are supplementary, meaning they add up to 180 degrees. If we label the opposite angle of c as d, then we have c+d=180 degrees. Subtracting c from both sides, we get d=180-c. Then, adding a+b to both sides, we get a+b+d=240-c+c, which simplifies to a+b+c=240 degrees. Another way to explain why a+b+c=240 degrees is to use the fact that an exterior angle of a triangle is equal to the sum of the opposite interior angles. If we extend one side of the triangle and label the exterior angle as e, then we have e=a+b. Then, adding c to both sides, we get e+c=a+b+c. Since e+c is an exterior angle of another triangle formed by extending the side, it is equal to 180 degrees. Therefore, we have 180=a+b+c, which implies that a+b+c=240 degrees.

Hence, if a cricket chirps 70 times, a good estimate of the outside temperature is 5.49 degrees Celsius.

A scatterplot is a particular kind of graphical display that uses a collection of dots on a this double coordinate plane to represent a collection of information values. A pair of values, often a variable shown on the horizontally (x) axis and a predictor variables plotted just on vertical (y) axis, are represented by each figure on the plot. Each point's location provides information about both variables' values, and the arrangement of the points can show any relationships between the two factors. Scatterplots are frequently used to spot patterns, correlations, or other connections between different data sets.

given

According to the scatterplot, a logical line of greatest fit would go via the points (15, 57) and (90, 89). We must first determine the slope of this line in order to determine its equation:

slope = (89 - 57) / (90 - 15) = 0.53

The equation of the line can therefore be expressed in the point-slope form of a linear equation as follows:

y - 57 = 0.53(x - 15) (x - 15)

If we simplify this equation, we get:

y = 0.53x - 30.11

If a cricket chirps 70 times, what will the outside temperature be? We may solve for y by substituting 70 for x and making the following prediction:

y = 0.53(70) - 30.11 = 5.49

Hence, if a cricket chirps 70 times, a good estimate of the outside temperature is 5.49 degrees Celsius.

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You can access the Cambridge Lower Secondary syllabus for Grade 8 on the official Cambridge Assessment International Education website.

You can access the Cambridge Lower Secondary syllabus for Grade 8 on the official Cambridge Assessment International Education website. The syllabus includes the learning objectives, recommended teaching and learning resources, and sample exam questions.

To access the syllabus, follow these steps:

The syllabus document includes sample questions and information about the assessment objectives for each subject. You can also find additional support materials and resources on the Cambridge International website to help you prepare for the exams.

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The interquartile range (IQR) is the difference between the third and first quartiles, so the third quartile is 33. So correct option is C.

Quartiles are statistical measures that divide a dataset into four equal parts. Each quartile represents 25% of the data, and there are three quartiles in total: the first quartile (Q1), the second quartile (Q2), and the third quartile (Q3).

To find the quartiles of a dataset, the data is first arranged in order from smallest to largest. The median (Q2) is then found, which divides the dataset into two halves: the lower half, which contains all the data points less than or equal to the median, and the upper half, which contains all the data points greater than or equal to the median.

Q1 is the median of the lower half of the dataset, and Q3 is the median of the upper half of the dataset. This means that Q1 represents the 25th percentile of the data, Q2 represents the 50th percentile (which is also the median), and Q3 represents the 75th percentile of the data.

To find the third quartile, we need to use the information we have about the first quartile, the median, and the interquartile range. We know that the interquartile range (IQR) is the difference between the third and first quartiles, so:

IQR = Q3 - Q1

Substituting the given values, we get:

27.75 = Q3 - 5.25

Adding 5.25 to both sides, we get:

Q3 = 33

Therefore, the answer is C. 33.

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The complete question is:

The equation will be  2r+5 = 9

Solving the equation we get the value of r=2

Each rock costs $2.

What is equation?

An equation is a mathematical statement which is built by two expressions connected by an equal('=') sign. For example, 3x – 8 = 16 is an equation. Solving this equation, we get the value of the variable x as x = 8.

Jiro buys 2 rocks that each cost the same amount ,r,

1  rock costs r rupees

2 rock costs 2r rupees

and the magnifying glass that cost $5

So the expression will be (2r+5) rupees

Given that total cost is $9

Equating both we get,

2r+5 = 9

Here we solve r from the equation

Subtracting 5 from both sides of the equation we get,

2r= 9-5

2r= 4

r= 2

A graph for the equation is attached below.

Hence, the value of r is 2.

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Answer: 3 days

Step-by-step explanation:

Answer:

I agree with 3 days

Step-by-step explanation:

1) Ratio for laps to meters to days

1 lap: 400 meters -> 10 laps: 400 meters = 1 day

OK, 1 kilometer is 1,000 meters. Keep that in mind.

*12 kilometers is the equivalent to 12000 meters*

2) Ratio problem and cross multiply

10:400 = 1 day so x laps :12000 meters

HOW MANY TIMES DOES 400 GO INTO 12000? 30 times

30 is the amount of laps ran.

If you multiply 10:400 by 3 it will equal 30:12000.

3 is your answer

The answer to the given question about data representation is option a and c  The Allstars, with a mean of about 67.1 inches and median of about 68 inches

To determine which team typically has the tallest players, we need to look at the measure of center for each data set. In this case, we are given the mean and the median for each team. Since the data sets are relatively small, both the mean and the median are good measures of center.  The mean is calculated by adding up all the values in the data set and dividing by the number of values. The median is the middle value when the data set is arranged in order. The Allstars have a mean of about 67.1 inches and a median of about 68 inches. The Champs have a mean of about 66.4 inches and a median of about 67 inches.

Since the mean and median of the Allstars are both higher than those of the Champs, we can conclude that the Allstars typically have taller players. Therefore, the correct answer is: The Allstars, with a mean of about 67.1 inches or The Allstars, with a median of about 68 inches

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To find the first four terms of the sequence given by the formula aₙ=43-4(n-1), we substitute n=1, 2, 3, and 4 in the formula and simplify.

a₁=43-4(1-1)=43-4(0)=43-0=43

a₂=43-4(2-1)=43-4(1)=39

a₃=43-4(3-1)=43-4(2)=35

a₄=43-4(4-1)=43-4(3)=31

Therefore, the first four terms of the sequence are 43, 39, 35, and 31

Answer:

To find what percent 120 is of 400, we can use either the percent proportion or the percent equation.

Using the percent proportion:

Let x be the percent we are looking for. Then we can write:

120/400 = x/100

Simplifying this equation, we get:

0.3 = x/100

Multiplying both sides by 100, we get:

x = 30

Therefore, 120 is 30% of 400.

Using the percent equation:

The percent equation states that:

part/whole = percent/100

In this case, the part is 120 and the whole is 400, so we can write:

120/400 = percent/100

Simplifying this equation, we get:

0.3 = percent/100

Multiplying both sides by 100, we get:

percent = 30

Therefore, 120 is 30% of 400.

Answer:

30%

Step-by-step explanation:

Write the expression:

x% of 400 = 120

Then solve:

x/100 x 400 = 120

4x = 120

x = 30%

Answer:

2+2=4

Step-by-step explanation:

I really hope this helps! =D

Mark me brianliest and have a good day! :)))

Answer:

4

Step-by-step explanation:

The calculated area of the parallelogram is 105.7 square feet

From the question, we have the following parameters that can be used in our computation:

Base = 7 and height = 15.1

The area is calculated as

Area = Base * Height

Substitute the known values in the above equation, so, we have the following representation

Area = 7 * 15.1

Evaluate

Area = 105.7

Hence, the area is 105.7

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The ticket price that will maximize the airline's revenue is $300, and the number of tickets sold at that price is 600.

To find the ticket price and the number of tickets sold that will maximize the airline's revenue, we will follow these steps:
Set up the given information as functions:
- The base ticket price (P) is $400.
- The base number of tickets sold (Q) is 100.
- For each $10 price reduction (x), 50 more tickets are sold.
Write the functions for price and quantity:
- Price: P(x) = 400 - 10x
- Quantity: Q(x) = 100 + 50x
Calculate the revenue function:
Revenue (R) = Price × Quantity
R(x) = P(x) × Q(x)
R(x) = (400 - 10x)(100 + 50x)
Expand the revenue function:
R(x) = 40000 + 20000x - 1000x^2
Find the critical points by taking the derivative of the revenue function and setting it equal to 0:
R'(x) = 20000 - 2000x
0 = 20000 - 2000x
Solve for x:
2000x = 20000
x = 10
Substitute the critical point (x=10) back into the price and quantity functions to find the optimal price and quantity:
- Price: P(10) = 400 - 10(10) = 400 - 100 = $300
- Quantity: Q(10) = 100 + 50(10) = 100 + 500 = 600

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In the word problem , the number of days were in the "13-18" category is  C)4.

What is word problem?

Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.

Here the given data represent the numbers of loaves sold in the last 10 days is 5, 12, 8, 15, 18, 20, 3, 17, 14, 21.

Now number of loaves sold in last 10 days between from 13-18 is

=> 15,18,17,14

Hence the number of days were in the "13-18" category is  C)4.

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a. The total amount Christian paid for FICA taxes (Social Security and Medicare) is $7,607.70

b. The main difference between how Social Security and Medicare are paid is in their funding sources.

Employers and workers both contribute a portion of an employee's income to Social Security through payroll taxes.

Medicare, on the other hand, is paid for by a combination of beneficiary premiums, payroll taxes, and general government income.

Furthermore, Medicare benefits are determined by age and eligibility requirements, whereas Social Security benefits are determined by a person's contributions and employment experience.

Social Security is the commonly used term for the federal Old-Age, Survivors, and Disability Insurance program and is administered by the Social Security Administration.

The amount Christian paid for Social Security taxes is therefore:

$87,000 x 0.071 = $6,177

To calculate the amount Christian paid for Medicare taxes, we simply multiply his total income by the Medicare tax rate:

$98,600 x 0.0145 = $1,430.70

Therefore, the total amount Christian paid for FICA taxes (Social Security and Medicare) is:

$6,177 + $1,430.70 = $7,607.70

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Answer: umm please provide the answers you can chose then maybe i can help

Step-by-step explanation:

It should be noted that ordering from least to greatest will be:

52,650 < 327,600 < 3,364,032 < 15,187,500

The letters can repeat, but the numbers cannot repeat.

There are 26 options for each of the two letters, and 9 options for each of the three digits. Therefore, the total number of possible license plates is:

26 x 26 x 9 x 8 x 7 = 3,364,032

The numbers can repeat, but the letters cannot repeat.

In this case, there are 26 options for the first letter and 25 options for the second letter (since the letters cannot repeat). There are 9 options for each of the three digits. Therefore, the total number of possible license plates is:

26 x 25 x 9 x 9 x 9 = 52,650

Neither the letters nor the numbers can be repeated.

For the first letter, there are 26 options. For the second letter, there are 25 options (since it cannot be the same as the first letter). For the first digit, there are 9 options. For the second digit, there are 8 options (since it cannot be the same as the first digit). For the third digit, there are 7 options (since it cannot be the same as the first two digits). Therefore, the total number of possible license plates is:

26 x 25 x 9 x 8 x 7 = 327,600

The letter "o" cannot be used, but there are no restrictions on repeating the other letters or numbers.

There are 25 options for each of the two letters (since "o" cannot be used). There are 9 options for each of the three digits. Therefore, the total number of possible license plates is:

25 x 25 x 9 x 9 x 9 = 15,187,500

Ordering from least to greatest:

52,650 < 327,600 < 3,364,032 < 15,187,500

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well, first off, hmmm let's find their slopes in the first place

[tex]p=\stackrel{\stackrel{m}{\downarrow }}{2}n+5\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad {\Large \begin{array}{llll} \boxed{x=2} \end{array}}[/tex]

now,  to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below for BrandY[tex](\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{9}-\stackrel{y1}{3}}}{\underset{\textit{\large run}} {\underset{x_2}{7}-\underset{x_1}{1}}} \implies \cfrac{ 6 }{ 6 } \implies {\Large \begin{array}{llll} 1=Y \end{array}}[/tex]

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture above for BrandZ

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{9}-\stackrel{y1}{3}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{ 6 }{ 4 } \implies {\Large \begin{array}{llll} \cfrac{3 }{ 2 }=Z \end{array}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{X}{2} ~~ > ~~ \stackrel{Y}{1}\hspace{5em}\stackrel{X}{2}~~ > ~~ \stackrel{Z}{\frac{3}{2}}~\hfill[/tex]