need help fast Geometry

Answer:

In right angle triangle ,hypotenuse is equal to sum of two other sides.so,

(h)^2=(p)^2+(b)^2

(8)^2=(3)^2+(x)^2

64=9+x^2

64-9=x^2

55=x^2

[tex]\sqrt{55}[/tex]=x

7.4=x

Step-by-step explanation:

Answer:

  The answer would be $1995

Step-by-step explanation:

Trust me

Answer:

Let's mark Pat's age is x. Then Mattie's age is 2x and Jon's age is 4x.

So (x + 4) + (2x + 4) + (4x + 4) = 61.

7x + 12 = 61 => 7x = 49 => x = 7.

So the answer is

Pat = 7

Mattie = 14

Jon = 28

The ages of Pat, Mattie, and Jon are as follows: 7 years, 14 years & 28 years.  

If we take Pat's age as = 'x' years,

so, Mattie's age will be = '2x' years.

and then, Jon would be = 2(2x)

                                        = '4x' years.

Now, the sum of their ages after 4 years =

 => (x+4) + (2x+4) + (4x+4) = 61

 => 7x+12 = 61

 => 7x= 61-12

 => 7x= 49

 => x= 49/7

 => x = 7

Therefore, Pat's age is  = 7 years.

              Mattie's age is = 14 years (2×7).

                  Jon's age is = 28 years (4×7).

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Answer:

e = 54

f = 20

d = 106

Step-by-step explanation:

Opposite angles are the same. Also, straight lines always equal 180 degrees.

Hope that this helps!

Answer:

The slope of the line perpendicular to the line C is 1/3.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-12-(-6))/(-1-(-3))

m=(-12+6)/(-1+3)

m=-6/2

m=-3

perpendicular lines have negative reciprocal slopes.

If the student perform one trial of scientific experiment , and the result of that trial do not support the prediction , then the student should repeat the experiment , modify the experiment and can use alternative Method .

If in the Scientific Experiment the result does not support the prediction of the student in one trial , then the student can :

(i) Modify the Experiment :

The students can modify scientific experiment in other way and try again. For Example, they student change variables being tested or methods used to collect data.

(ii) Use Alternative Explanations :

The students can use alternative explanations for  results. It may be possible that the prediction was correct, but there were other factors  that may influence outcome of experiment.

(iii) Repeat the Experiment :

The student can repeat the experiment by the same procedures to see if he gets same results and if results are consistent, it can concluded that the prediction was incorrect .

The given question is incomplete , the complete question is

Student perform one trial of a scientific experiment if the result of that trial do not support the prediction what should the student do next ?

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Answer:10 girls and 11 boys

Step-by-step explanation:

Answer:

b and d are closer to 0 than 1 mark me brainliest

Step-by-step explanation:

Answer:

B. and D the rest are half or closer to 1

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

1/100

or we can say 100/1

Answer:

[tex]{\huge{\underbrace{\overbrace{\color{red}{Answer...}}}}} \\ \\ [/tex]

[tex]\small\boxed{\mathfrak{\underline{Interior \: angles \: are \: not \: congruent}}} \\ \\ {\huge{\underbrace{\overbrace{\color{purple}{hope \: it \: helps... | \: | }}}}} \\ \\ [/tex]

If two parallel lines are cut by non-perpendicular transversal, then the interior alternate angles are NOT  congruent.  

By the Property of the alternate angles states, if two parallel lines are cut by a transversal, then the alternate angles are congruent. Two angles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

The Exterior angle is an measure of rotation between one extended side

Let assume ∠XWY and ∠ZYW represent the interior angles between the parallel lines and the transversal.

From the figure attached, we can see that  ∠XWY ≅ ∠ZYW

By this property, Both the Lines are the parallel lines intersected by a transversal.

Therefore, the interior alternate angles ∠XWY and ∠ZYW will be congruent.

Hence, If two parallel lines are cut by non-perpendicular transversal, then the interior alternate angles are NOT  congruent.

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The average rate of change is the ratio of the difference between the y coordinates of two points to the x coordinate of the same point.

It can be found by using two points on the graph and substitute into the formula: (y₀ - y₁) / (x₀ - x₁)

The square brackets [] is used to mean the end points as shown is inclusive

A quadratic equation is a polynomial of degree two

The average rate of change here is not constant and is usually  specified by the two points to which it is measured

For instance using points (-3, 0) and (0, -1) we have

=  (y₀ - y₁) / (x₀ - x₁)

=  (-1 - 0) / (0 - (-3))

= -1/3

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Answer: [tex]45.03\ ft[/tex]

Step-by-step explanation:

Given

The length of the shadow is 78 ft

the angle of elevation is [tex]\theta =30^{\circ}[/tex]

Suppose the height of the building is [tex]h[/tex]

From the figure, we can write

[tex]\tan 30^{\circ}=\dfrac{h}{78}\\\\h=78\tan 30^{\circ}\\\\h=45.03\ ft[/tex]

The height of the building is 45.03 ft

The value of sin(4π-x) is -sinx

The trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths.

Given that, express the given in terms of sinx or cosx sin (4π-x)

sin(4π-x) = sin(2π+2π-x)

We know, that, sin(a+b) = sina·cosb+sinb·cosa

Here, a = 2π and b = 2π-x

Therefore,

sin(2π+2π-x) = sin2πcos(2π-x)+sin(2π-x)cos2π

Now, sin2π = 0 and cos(2π) = 1

Therefore,

sin2πcos(2π-x)+sin(2π-x)cos2π

= sin(2π-x)

As we know that, sin(2π-x) = -sinx

Hence, sin(4π-x) = -sinx

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Answer: The Gradient of line A and B are

2 and -1

Step-by-step explanation:

For the given two points A(x1, y1) and B(x2, y2)

The gradient of the line AB is y2-y1/x2-x1

So the gradient of line A is

5-1/2-0

2

the gradient of line B is

5-0/0-5

-1

Answer:

The first answer to the fourth answer is rational numbers.

Step-by-step explanation:

Rational numbers are usually expressed as fractions or decimals, but rational numbers are never whole numbers. Hope this helps!

The size of the large tank is 6 liters and the size of the small tank is 3 liters.

The first step is to form a system of equations using the information provided in the question:

3l + 2s = 24 equation 1

2l + 3s = 21 equation 2

Where:

The elimination method would be used to solve the equations:

Multiply equation 1 by 2 and equation 2 by 3:

6l + 4s = 48 equation 3

6l + 9s = 63 equation 4

Subtract equation 3 from equation 4:

5s = 15

Divide both sides of the equation by 5

s = 15 / 5

s = 3 liters

Substitute for s in equation 1 :

3l + 2(3) = 24

3l + 6 = 24

3l = 24 -  6

3l = 18

l = 18 / 3

l = 6

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Definition of a rectangle

Explanation:

A rectangle has two sets of parallel sides, and those opposite sides are the same length. This is simply the definition of what it means to be a rectangle. Because ABCD is a rectangle, we have these two pairs of congruent opposite sides:

Answer:

2x+3y-(-4x+3y)=6-12

2x+3y+4x-3y. =-6

6x. = -6

X=-1

no

Answer:

No

Step-by-step explanation:

So, lets go over what we know:

Our x and y values are (0,2)

This means:

x=0

y=2

Lets plug these in for each equations:

2x+3y=6

=

2(0)+3(2)=6

=

0+6=6

=

6=6

So thie first equation is correct.

But we dont know if the second one will check out yet!

Lets plug our values in once more, only on the second equation instead of the first:

-4x+3y=12

=

-4(0)+3(2)=12

0+6=12

6=12

Uh oh...Thats not right.

So this means that (0,2) is not a solution to both equations.

Answer:

No

Hope this helps! :D

The square of the radius of the given circle is [tex]$OP^2 = 703$[/tex]

A quadrilateral is a four-sided polygon in geometry that has four edges and four corners. The word is a derivative of the Latin words quadri and latus. Having four sides, four vertices, and four corners, a rectangle is a two-dimensional form. Concave and convex come in primarily two varieties.

We can use the concept of the power of a point, which states that the square of the distance of a point from a line is equal to the product of the distances of the point from the two tangents to the line that are drawn from the point.

Let [tex]$O$[/tex] be the center of the inscribed circle.

The power of point O with respect to AB and CD is [tex]$(OPOQ) = (1937) = 703$[/tex]

Since the Circle is tangent to AB and CD at P and Q respectively, so [tex]$OP = OQ$[/tex]

So, [tex]$OP^2 = 703$[/tex]

Hence, the square of the radius of the circle is [tex]$OP^2 = 703$[/tex]

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Complete question is: A circle is inscribed in quadrilateral [tex]$A B C D$[/tex], tangent to [tex]$\overline{A B}$[/tex] at [tex]$P$[/tex] and to [tex]$\overline{C D}$[/tex] at [tex]$Q$[/tex]. Given that [tex]$A P=19, P B=26, C Q=37$[/tex], and [tex]$Q D=23$[/tex], find the square of the radius of the circle.

Answer:

jason: 60mph

marie: 50mph

Step-by-step explanation:

let jason drive at x miles per hour

let marie drive at x-10 miles per hour

let jason drive for y hours

let marie drive for y+1 hours

distance = speed * time

for jason:

300 = x * y

for marie:

300 = (x-10) * (y+1) = x*y + x - 10y -10

300 = x*y

divide both sides by x to solve for y

300/x = y

plug this into the second equation

300 = (x-10) * (300/x+1) = 300 -3000/x +x -10

300 = 300 -3000/x +x -10

subtract 300 from both sides

0 = -3000/x + x - 10

multiply both sides by x to get rid of the denominator

0 = x^2 -10x -3000

factor

0 = x^2 - 60x +50x -3000

0 = x(x-60) + 50(x-60) = (x+50)(x-60)

x = 60 or -50

x cannot be negative so x = 60mph

marie = 60-10 = 50mph

Answer:

x=800

Step-by-step explanation:

first you gonna take 3×x= 3x

then

3×200= 600

(3x+600)=3000

3x=3000-600

3x=2400

3x÷3=2400÷3

x=800

To Solve the inequalities , we take the variables on a side and the numbers on the other side and then apply mathematical operations to solve it .

What is Inequality ?

The Inequality is defined as a relationship between two values that are not equal to each other .

The method of solving the inequalities is a little different than solving equations.

To solve the inequalities, some simple rules should be followed .

(i) The inequality does not change if any number or variable is added or subtracted from both sides.

Similarly, the value of inequality is not affected if the same number is multiplied on both the sides.

(ii) If the inequality is divided by a negative variable or number on both  sides, then the inequality sign gets reversed.

(iii) On dividing inequality by a positive number, there is no change.

For Example : Solve the inequality [tex]4x+6 > 3x+7[/tex] ;

subtracting [tex]3x[/tex] from both the sides ,

we get ;

[tex]x+6 > 7[/tex],

Now subtracting [tex]6[/tex] from both sides of the inequality;

we get ;

[tex]x > 1[/tex] .

Therefore , the solution of the inequality [tex]4x+6 > 3x+7[/tex] is [tex]x > 1[/tex] .

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Answer:

he has 10.75 left over :)

Answer:

Step-by-step explanation:

20-3-5.50-2.25= $9.25

Answer:

The answers final

Simplify the expression

-2+6x+1/2x^2

Factor the expression

1/2x(-4+12x+x^2)

Step-by-step explanation:

I hope it will help you :)

Yes, it is a perfect square trinomial.

Perfect squares are numbers that are the product of a number multiplied by itself. Examples of perfect squares include 4 (2 x 2), 9 (3 x 3), 16 (4 x 4), 25 (5 x 5), 36 (6 x 6), 49 (7 x 7), and 64 (8 x 8). Perfect squares are also referred to as "square numbers" or "whole-number squares."

The equation X² + 10X + 25 can be factored into (X + 5)²,

which is a perfect square trinomial. In general, a perfect square trinomial is any polynomial of the form A² + 2AB + B² where A and B are constants or variables.

This is because such a polynomial can be factored into (A + B)².

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Answer:

Yes the data provide convincing statistical evidence that at women pay more than men for the same catalytic converter repair

Answer:

A, B, C

Step-by-step explanation:

Answer:

the answer of

[tex] \sqrt[3]{216} = 6[/tex]

is 6

Step-by-step explanation:

6^3=216

Step-by-step explanation:

The Radius of the larger semi circle = [tex]\frac{12}{2}[/tex] = [tex]6[/tex][tex]cm[/tex]

Area of the 2 larger semi Circles = [tex]\frac{\pi r^{2} }{2}[/tex][tex]X2[/tex]

                                                  = [tex]\frac{3.14X(6)^{2} }{2} X 2[/tex]

                                                   = [tex]\frac{113.04}{2} X2[/tex]

                                                    = [tex]113.04[/tex] [tex]cm^{2}[/tex]

Radius of the smaller semi circle = [tex]\frac{5}{2} = 2.5cm[/tex]

Area of the smaller semi circle = [tex]\frac{\pi r^{2} }{2}[/tex][tex]X2[/tex]

                                                    = [tex]\frac{3,14X(2.5)^{2} }{2} X 2[/tex]

                                                     = [tex]196.25[/tex][tex]cm^{2}[/tex]

Combined Area = [tex]113.04 + 196.25[/tex]

                           = [tex]309 . 29cm^{2}[/tex]