Newton has 10 more dimes than nickels. He has
twice the number of quarters than nickels. If he
has $6.20, how many of each coin does he have?

Answers

Answer 1

Given:

Newton has 10 more dimes than nickels.

He has  twice the number of quarters than nickels.

Total amount he has = $6.20.

To find:

The number of each coin.

Solution:

Let the number of nickels be x.

Newton has 10 more dimes than nickels.

Dimes = x+10

He has  twice the number of quarters than nickels.

Quarters = 2x

We know that, 1 nickel = $0.05, 1 dime = $0.10 and 1 quarter = $0.25.

Total amount he has is $6.20.

[tex]x\times 0.05+(x+10)\times 0.10+2x\times 0.25=6.20[/tex]

[tex]0.05x+0.10x+1+0.50x=6.20[/tex]

[tex]0.65x=6.20-1[/tex]

[tex]0.65x=5.20[/tex]

Divide both sides by 0.65.

[tex]x=\dfrac{5.20}{0.65}[/tex]

[tex]x=8[/tex]

Now,

Number of nickels = 8

Number of dimes = 8 + 10 = 18

Number of quarters = 2(8) = 16

Therefore, the number of nickels, dimes and quarters are 8, 18 and 16 respectively.


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Step-by-step explanation:

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I think that is the answer

Hope it helps :)

The number represented by 2² × 3² × 5  is 180.

What is prime factorisation ?

Prime factorisation is factoring a given composite number in terms of prime numbers multiplied with each other.

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1) 0.07 can only equal 0.07

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Answer:

First, you look at the y-intercept. It is positive 6 so you start at 6 on the y-axis. Then you look at the slope. It is negative 1/4. It is negative so the slope goes down and it goes down on the unit and 4 units right. That is how you graph y= -1/4x + 6

Both Andrew and Karleigh recorded the distance they ran in x minutes on treadmills. Andrew A 2-column table with 2 rows. Column 1 is labeled Time in Minutes with entries 18, 24. Column 2 is labeled Distance in miles with entries 1.5, 2. Karleigh A 2-column table with 2 rows. Column 1 is labeled Time in Minutes with entries 30, 40. Column 2 is labeled Distance in miles with entries 3, 4. Andrew and Karleigh each run for 1 hour. Which statement explains who ran a greater distance? Andrew ran a greater distance. The slope of the line described by the data in his table increased at a rate of StartFraction 1 Over 10 EndFraction mile per minute compared to Karleigh’s StartFraction 1 Over 12 EndFraction mile per minute. Karleigh ran a greater distance. The slope of the line described by the data in her table increased at a rate of StartFraction 1 Over 10 EndFraction mile per minute compared to Andrew’s StartFraction 1 Over 12 EndFraction mile per minute. Karleigh ran a greater distance. The slope of the line described by the data in her table increased at a rate of StartFraction 1 Over 12 EndFraction mile per minute compared to Andrew’s StartFraction 1 Over 10 EndFraction mile per minute. Andrew ran a greater distance. The slope of the line described by the data in his table increased at a rate of StartFraction 1 Over 12 EndFraction mile per minute compared to Karleigh’s StartFraction 1 Over 10 EndFraction mile per minute.

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Answer:

ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.

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Similarly, let's say Karleigh ran a distance

D2 = t × S2

= 3600S2

Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.

Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10

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This makes D2 bigger than D1. this is an example i found on the internet.

Step-by-

hope this helps, good luck

The ratio of the change in distance to the corresponding change in time

gives the speed of a runner.

The statement that explains who ran a greater distance is; Karleigh ran a greater distance. The slope of the line described by the data in her table increased at a rate of [tex]\displaystyle \frac{1}{10}[/tex] mile per minute compared to Andrew's [tex]\displaystyle \frac{1}{12}[/tex] mile per minute.

Reasons:

The tables are;

Andrew

[tex]\begin{tabular}{|cc|c|}Time in Minutes&&Distance in miles\\18&&1.5\\24&&2\end{array}\right][/tex]

Karleigh

[tex]\begin{tabular}{|cc|c|}Time in Minutes&&Distance in miles\\30&&3\\40&&4\end{array}\right][/tex]

The duration each on the treadmills is 1 hour = 60 minutes

[tex]\displaystyle Speed = \mathbf{\frac{Change \ in \ distance}{Change \ in \ time}}[/tex]

Therefore;

[tex]\displaystyle Andrew's \ speed = \frac{2 \, miles - 1.5 \, miles}{24 \, minutes - 18\, minutes} = \mathbf{\frac{1}{12} \ mile/minute}[/tex]

[tex]\displaystyle The \ distance \ Andrew \ ran = \frac{1}{12} \ miles/min \times 60 \ min = \mathbf{5 \ miles}[/tex]

[tex]\displaystyle Karleigh's \ speed = \frac{4 \, miles - 3 \, miles}{40 \, minutes - 30 \, minutes} = \mathbf{\frac{1}{10} \, mile/minute}[/tex]

[tex]\displaystyle The \ distance \ Karleigh \ ran = \frac{1}{10} \, miles/min \times 60 \ min = \mathbf{6 \ miles}[/tex]

Therefore;

Karleigh ran a greater distance

The correct option is; Karleigh ran a greater distance. The slope of the line in her table increased at a rate of [tex]\displaystyle \frac{1}{10}[/tex] mile per minute compared to Andrew's [tex]\displaystyle \frac{1}{12}[/tex] mile per minute.

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Answers

Answer:

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Answers

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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__

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Step-by-step explanation:

THAT DA ANSWER

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