One side of a rectangle is 4 ft longer than four times another side. The area of the rectangle is 440 ft?.
Find the length of the longer side.

Answer:

A: [tex]3\frac{1}{3}[/tex]

B: [tex]3\frac{2}{3}[/tex]

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

according to the dark spots which shows where each number goes to, it would be D.-2

Answer:

2,100 people

Step-by-step explanation:

~Divide to find the number of people in fifths

3,500 / 5 = 700

~Multiply to find 2/5 of the total people

700 * 2 = 1,400

~Subtract to find the number of people against building the school.

3,500 - 1,400 = 2,100

Best of Luck!

Step-by-step explanation:

hope you understand.

first simplify it by arranging correct signs then it's just subtraction or addition.

Answer: 25650

Step-by-step explanation: 10% of 28500 is well 2850

28500-2850=25650

(if only i could get good rates on my car)

Answer:

her goal is to have money 21250

I hope it helps u

Answer and Step-by-step explanation:

To round to the nearest whole number, you look at the number in the tenths place.

- If this number is 5 and higher, then you round up (the number to the left of the tenths place [the ones place]).

- If it is lower than 5, then the number (in the ones place) stays the same.

9 is greater than 5, so we round up.

9,910 is the answer.

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

D. On sale at 60% of the original price

Step-by-step explanation:

That just means they are taking off 40% off the original price.

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

a) 5151 b) 249001 c)24651 d)43561

Step-by-step explanation:

a) a1=1 a2=2

d=a2-a1= 2-1=1

Define the quantity of the terms of this sequence

an=a1+d(n-1)

101= 1+ 1(n-1)

n=101

Sn= (a1+an)/2*n=( (1+101)/2)*101=51*101=5151

b) a1=1  a2=3

d=a2-a1=3-1=2

an=a1+d(n-1)

997= 1+ 2(n-1)

498= n-1

n=499

Sn= (a1+an)/2*n= (1+997)/2*499= 249001

c) a1=4 a2=9

d=a2-a1=9-4=5

an=a1+d(n-1)

494=4+5(n-1)

n=99

Sn= (a1+an)/2*n=( 4+494) /2*99= 498/2*99= 249*99= 24651

d) a1=881, a2=872

d=a2-a1= 872-881=-9

an= a1+d(n-1)

8=881-9*(n-1)

9(n-1)= 873

n=98

Sn= (a1+an)/2*n= (881+8)/2*98= 889*49= 43561

Answer:

Some things you must have in order to be that certain profession is:

Accounts receivable (order to cash)

Accounts payable (procure to payment)

Financial close.

Time and expense capture.

Fund accounting.

Project accounting.

Revenue recognition and management.

Step-by-step explanation:

If need anything else let me know, if not pls mark me as brainliest :)

Answer:

all limits exist.

Step-by-step explanation:

plz see in the picture for more explaination.

Answer:

7

Step-by-step explanation:

f(x) = 3x+1

f(2)  means let x=2

f(2) = 3(2)+1

     = 6+1

     =7

[tex]\\ \sf\longmapsto f(2)[/tex]

[tex]\\ \sf\longmapsto 3(2)+1[/tex]

[tex]\\ \sf\longmapsto 6+1[/tex]

[tex]\\ \sf\longmapsto 7[/tex]

[tex]\\ \sf\longmapsto Perimeter=2(L+B)[/tex]

[tex]\\ \sf\longmapsto Perimeter=2(16+8)[/tex]

[tex]\\ \sf\longmapsto Perimeter=2(24)[/tex]

[tex]\\ \sf\longmapsto Perimeter=48cm[/tex]

Area:-

[tex]\\ \sf\longmapsto Area=Length\times Breadth[/tex]

[tex]\\ \sf\longmapsto Area=8(16)[/tex]

[tex]\\ \sf\longmapsto Area=128cm^2[/tex]

Answer:

9.857142857 ft

Step-by-step explanation:

We can use a ratio to solve

23 ft shadow        14 ft shadow

--------------------  = ---------------

x ft high                 6 ft high

Using cross products

23*6 = 14 * x

Divide each side by 14

23*6/14 = x

9.857142857 ft

Answer:

okbhyuugggfububububhhhukjgyi

This range contains 80 numbers (40 in 1-40, and another 40 in -39-0).

We have

S = 1 + 2 + 3 + … + 38 + 39 + 40

S = 40 + 39 + 38 + … + 3 + 2 + 1

==>   2S = (1 + 40) + (2 + 39) + … + (39 + 2) + (40 + 1)

==>   2S = 40 × 41

==>   S = 820

and

T = 0 + 1 + 2 + … + 37 + 38 + 39

T = 39 + 38 + 37 + … + 3 + 2 + 1

==>   2T = (0 + 39) + (1 + 38) + … + (38 + 2) + (39 + 0)

==>   2T = 40 × 39

==>   T = 780

The average of the numbers in this range is equal to the total divided by the amount of numbers in the range, so

average = (40 + 39 + … + 1 + 0 + (-1) + … + (-38) + (-39))/80

average = (S - T )/80

average = (820 - 780)/80

average = 40/80 = 1/2

Answer:

[tex]y=\frac{1}{3} x+7.[/tex]

Step-by-step explanation:

all the detail are in the attached picture, here is the short explanation step-by-step:

1) to select the values of slope and interception from the given equation;

2) using the rule of parallel lines to find the slope of the required line;

3) to write the required equation (the value of slope is known, the value of interception is inknown);

4) to calculate the unknown value of interception of the required equation after the substitution the coordinates of the point in the condition;

5) to make up the required equation using calculated slope and interception.

100-20=80%=400

[tex]\\ \rm\longmapsto 80\%\:of\:CP=400[/tex]

[tex]\\ \rm\longmapsto CP=400\times \dfrac{100}{80}[/tex]

[tex]\\ \rm\longmapsto CP=5(100)[/tex]

[tex]\\ \rm\longmapsto CP=500[/tex]

Step-by-step explanation:

Given,

S.p.=Rs400

Loss percent(L%) =20%

C.p.=?

We know,

S.p. =(100-L) % of c.p.

or,400=(100-20)% *c.p.

or,400=80% *c.p.

or, 400=80/100*c.p.

or,c.p.=Rs.500

Here, c.p.=Rs.500

Hi there!  

»»————-　★　————-««

I believe your answer is:  

Irrational

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻[tex]\rightarrow \sqrt{95} = 9.74679...\\\\\text{This does \textbf{NOT} simplify into a whole number. This means that it's not a perfect square.}\\\\\text{Since } \sqrt{95} \text{ is not a perfect square, it is \textbf{irrational.}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Step-by-step explanation:

x - 5 = -4x - 5

x + 4x = -5 + 5

5x = 0

x = 0/5

x = 0

A. x = 0

B. Yes, 0 is a real number

C. There is a solution

Answer:

98765 is the greatest digit that can be formed using those numbers

Answer:

4. 1/25

5. 1/16

6. 2/9

7. 5/567

8. 1/40

9. 2/175

10. 1/30

11. 2/5

12. 9/8

13. 4/3

14. 1

Step-by-step explanation:

sorry I only know how to do 4-14. I hope this helps you.

The information about the path is incomplete, so I'll just use a domain of a ≤ t ≤ b, where a > 0 and b < ∞.

Differentiating r(t) gives

[tex]\vec r(t) = 2t\,\vec\imath + 2t\,\vec\jmath + t\,\vec k \implies \dfrac{\mathrm d\vec r(t)}{\mathrm dt} = 2\,\vec\imath + 2\,\vec\jmath + \vec k[/tex]

with magnitude √(2² + 2² + 1²) = √5.

Then we have

[tex]\displaystyle \int_C f(x,y,z)\,\mathrm ds = \int_a^b f(2t,2t,t) \left\|\frac{\mathrm d\vec r(t)}{\mathrm dt}\right\| \,\mathrm dt \\\\= \sqrt5 \int_a^b \frac{2t+2t+t}{(2t)^2+(2t)^2+t^2}\,\mathrm dt \\\\ = \sqrt5 \int_a^b \frac{5t}{5t^2} \,\mathrm dt \\\\ = \sqrt5 \int_a^b \frac{\mathrm dt}t \\\\ = \sqrt5 (\ln(b)-\ln(a)) = \boxed{\sqrt5 \ln\left(\frac ba\right)}[/tex]

Answer:

n1= -4

n2= 1

n3= 6

Step-by-step explanation:

the n column represents the numbers that are in n's place

eg n=1

n=2

n=3

5x1 - 9

5x2 -9

5x3 -9

Answer and Step-by-step explanation:

What this question wants you to do is fill out the right side (or the outputs) of the table.

To do this, plug in the value of n into the equation and solve.

n = n, 5n - 9

n = 1, 5(1) - 9 = -4

n = 2, 5(2) - 9 = 10 - 9 = 1

n = 3, 5(3) - 9 = 15 - 9 = 6

So, the values (in bold) should go into the table as so:

1    | -4

2   |  1

3   |  6

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

A    d = 5+2

Step-by-step explanation:

There are two more drummers than violinists

There are 5 violinists

5 + 2 = d

or in other words, d = 7

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

9514 1404 393

Explanation:

For this purpose, we define your power function as ...

  f(x) = a·x^n

Most of the description here applies to any function. A "power function" is a special case of a polynomial function in that it only has one term. The parity of the exponent (even, odd) tells you whether the function is even or odd. As with any even or odd function, there will be a certain symmetry:

  f(-x) = f(x) . . . even function; symmetrical about the y-axis

  f(-x) = -f(x) . . . odd function; symmetrical about the origin

__

The coefficient of the function is the vertical scale factor. As with the vertical scale factor of any function, when it is negative, the function graph is reflected in the x-axis. When it increases in magnitude, points on the graph move farther from the x-axis; closer when it decreases.

__

A) The red graphs in the first attachment are graphs of f(x) = ax^2 for different values of 'a'. As described above, the graph is symmetrical about the y-axis.

B) The black graphs in the first attachment are graphs of f(x) = ax^3 for different values of 'a'. As described above, the graph is symmetrical about the origin.

C) As described above, when the coefficient is negative, the graph of the parent function is reflected across the x-axis. The dashed-line graphs in the first attachment are graphs of the function with a negative coefficient.

D) As described above, the coefficient is the vertical scale factor. Changing it stretches or compresses the graph vertically. The dotted red graph in the first attachment shows a vertical expansion; the dashed black graph shows a vertical compression (reduction in the coefficient magnitude).

__

The second attachment shows graphs with negative exponents. Otherwise, the graphs are scaled and reflected the same as they were in Part 1.

A) As described above, the graph is symmetrical about the y-axis.

B) As described above, the graph is symmetrical about the origin.

C) As described above, a negative coefficient causes the graph to be reflected across the x-axis.

D) As described above, the magnitude of the coefficient affects the distance of the graph from the x-axis. Increasing magnitude increases the distance; decreasing magnitude decreases the distance (proportionally).