please answer as soon as possible. How does the gravitational pull of different objects in space affect other objects in space?

First, we need to calculate force of the rocket.

What is Velocity?

Velocity is a vector quantity that describes the rate and direction of a body's motion. It is represented by an arrow pointing in the direction of motion and having a length equal to the rate of motion. Velocity is a fundamental concept in classical mechanics and is defined as the rate of change of position with respect to time.

Calculate the force of the rocket:

F = ma = (15,000 kg)(230 m/s) = 3,450,000 kg m/s2

Calculate the force of the exhaust gases:

F = ma = (1,000 kg)(-1,200 m/s) = -1,200,000 kg m/s2

Calculate the net force on the rocket:

Net Force = F_rocket + F_exhaust = 3,450,000 kg m/s2 + (-1,200,000 kg m/s2) = 2,250,000 kg m/s2

Calculate the acceleration of the rocket:

a = F/m = (2,250,000 kg m/s2)/(15,000 kg) = 150 m/s2

Calculate the change in velocity of the rocket:

Δv = a × t = (150 m/s2)(6.0 s) = 900 m/s.

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The 2.00-kilogram object weighs 19.6 newtons on Earth, its weight on the Mars is 2.00 kg.

The mass is known as the amount of matter which is contained in a body.  It is a property which is consistent in a body regardless of the body's current location, gravitational pull and various other factors which exist.

Mass and weight are two separate quantities. Weight is computed as a product of mass and acceleration. Mass has a property to remain constant and it means that whether the object is on any planet, irrespective of that, it will be constant. The mass remains the same that is 2.00 kg.

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Answer:

12 N

Explanation:

Given,

Mass ( m ) = 3 kg

Acceleration ( a ) = 4 m/s^2

To find : Force ( F ) = ?

Formula : -

F = ma

F

= 3 x 4

= 12 N

Therefore, the force acting on the object is 12 N.

Answer: 12 N

Explanation:

The intensity of 60 dB sound is 10⁻⁶ W/m².

A common conversation between two persons seated at a distance of around one meter (3 14 feet) is as loud as 60 dB. It is equivalent to the typical noise level in a restaurant or office.

The decibel scale is a logarithmic one rather than a linear one. Accordingly, 10 dB denotes a sound that is 10 times louder than 0 dB, which represents no sound at all. Now, a sound at 20 decibels is 100 times louder than one at 0 decibels. And so on until a sound that is 100 decibels is 1 billion times louder than total silence (0 decibels).

A sound at 60 dB is therefore 100 times louder than a sound at 40 decibels and 1000 times louder than a sound at 30 decibels, while being 10 times louder than a sound at 50 decibels.

The formula for sound volume is L = log(I/I₀), or (I/I₀) = 10^L.

Given that L = 60dB = 6bel and that we know that I₀ = 10⁻¹² W/m²,

I/I₀ = 10⁶.

or I = 10⁻¹² × 10⁶ = 10⁻⁶ W/m²

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Answer:

b. climb a mountain

A man is pushing a baby stroller. Compared to the magnitude of the force exerted on the stroller by the man, the magnitude of the force exerted on the man by the stroller is the same.

From Newton's third law of motion, the force exerted on the stroller by the man is same as the force exerted on the man by the stroller but is in the opposite direction.

Thus, the magnitude of the force exerted on the stroller by the man and the magnitude of the force exerted on the man by the stroller is same but in opposite direction.

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Answer:

b.

Explanation:

Answer:

b

Explanation:

when moving charged bodies move there is changing magnetic flux linking in the particles and thus magnetic field is created between them

A thermal emitter cannot be accurately approximated by hot, thin gas.

Devices known as thermal emitters radiate heat from a heated component. Some of them can be used as broadband infrared light sources for applications in spectroscopy, for instance, when the very low brightness is acceptable. Some of them are special types of incandescent lamps, sometimes in a very compact form. Their emission may be fairly continuous, but not always with high calibration accuracy. Unique designs, such as the globar and the Nernst lamp. These sources occasionally have an infrared filter installed that only allows the transmission of infrared light in a specific spectral range.

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Answer:

1. e

2. f

3. b

4. g

5. a

6. c

7. d

8. j

9. k

10. i

The points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.

[tex]1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l[/tex]

Energy is the capacity of a object to do a work. More the energy object posses, more the work it can do.

The main categories of energy

Let's match the point of Column A with Column B.

Thus, the points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.

[tex]1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l[/tex]

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Answer:

[tex]2.09 m/s^{2}[/tex]

Explanation:

The upward acceleration of an object can be calculated using the formula:

[tex]a = F / m[/tex]

where:

a is the acceleration of the object (in meters per second squared)

F is the force acting on the object (in newtons)

m is the mass of the object (in kilograms)

So in this case, we have:

[tex]a = 11000 N / 5250 kg = 2.09 m/s^2[/tex]

This is the upward acceleration of the helicopter when a force of 11000 N is acting on it.

Explanation:

Your wavelength is 0.4

Yout Amplitude is 1

The Cessna Cardinal, a single-engine light plane, has a wing area of 16.2 m² and an aspect ratio of 7.31 with span efficiency factor of 0.62 then the induced drag when the total weight is 9800 N is 18.8 N.

Given that,

Wing area (A) = 16.2m²

Aspect ratio (r) = 7.31

Efficiency factor (e) = 0.62

Weight of plane (W) = 9800 N

Velocity of airplane (v) = 251 km/h = 251× 5/18 = 69.72 m/s

We know,

Dynamic pressure (p) = 1/2ρv²

where ρ is density of plane = 1.225

p = 1/2 × 1.225 × 69.72 × 69.72 = 2977.29 pa

Lift coefficient Cl = W/p × A = W/(1/2ρv²) A

where, A is the area of wing

Cl = 9800/2977.29 × 16.2 = 0.203

Induced drag coefficient (Cd) = Cl²/πer² = (0.203 × 0.203)/(π × 0.62 × 7.31 × 7.31) = 0.041/(104.08) = 0.39×10⁻³

Induced drag (d) = p × A × Cd = 2977.29 × 16.2 × 0.39 × 10⁻³ = 18.8 N.

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51.6 seconds long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m.

The time it takes for an object to travel once around a circle of radius r at a constant speed v can be found using the equation:

T = 2 x π x r ÷ v

where T is the time in seconds, pi is approximately 3.14, r is the radius of the circle in meters, and v is the speed of the object in meters per second.

Given a constant speed of 130 m/s and a radius of 2650 m, the time it would take for a plane to fly once around the circle would be:

T = 2 x π x 2650 m / 130 m/s

T = 51.6 sec

So, it would take approximately 51.6 seconds for a plane traveling at a constant speed of 130 m/s to fly once around a circle whose radius is 2650 m.

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On gas-loaded accumulators, safety devices like relief valves, burst discs, and temperature fuse plugs are all used as  precautionary measures to maintain the efficiency​.

Accumulators are pressurized containers that can hold fluid. When a system needs a boost in power, this stored energy can be used, recharged, and then used again. The right precautions should be taken to keep pressure and temperatures under control because this stored energy can be hazardous.

On accumulators, a number of modest but crucial accessories can be placed to stop the release of this stored energy and guarantee that temperatures stay within their safe operating range.

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Explanation:

Always write what you know first about the problem

The surface of the piston that has the force applied is a circle

The area of a circle is pi x r^2

Pressure is Force / Area

Write this out

P = F / (pi x r^2)

solve for r

sqrt( F / (P x Pi)) = r

But dont forget that d = 2 x r

The diameter of the piston is equal to 3.38 inches.

The pressure can be defined as the force that is applied per unit area. Force will be applied perpendicular to the surface per unit area. pressure can be measured in the unit of pascal. A Pascal can be defined as the pressure exerted by one force Newton on one square area.

The mathematical expression to calculate pressure is:

Pressure = Force/area

Given, the maximum pressure of the piston, P = 2.5 psi

We know that 1 psi = 703.07 Kg/m²

P = 2.5 × 703.07 = 1757.67 Kg/m²

The force applied, F = 100N = 100/ 9.8 Kg = 10.20 Kg

The area of the piston, A = F/P

A = 10.20/1757.67

A = 0.00580 m²

Area of the piston, A = πr²

0.0058 = 3.14 × r²

r = 0.04297 m

Diameter, d = 2r = 0.0859 m

We know that one meter = 39.37 inch  

The diameter of the piston, d = 0.0859 × 39.37 = 3.384 inch

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A negatively charged object is one that has more electrons than protons.

A negative charge is present when an object has more electrons than protons. An atom has a positive charge when there are more protons than electrons in it. The charges of protons are positive while those of electrons are negative. The coulomb is used to measure charge (C).

The opposite of a charge's attraction is the opposite of its repellency. Therefore, a positive charge attracts a negative charge, whereas two negative charges repel one another. Along the boundary between the two charges, attraction or repulsion occurs.

Along the line that connects the centres of the two objects, the force is applied in that direction. Coulomb's law results in a negative value if the two charges have opposing signs. As a result, the force separating the particles is an attractive force.Coulomb's law produces a favourable outcome if the two charges have the same signs.

Therefore, the answer is 12.4 c positive.

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Two objects with negative charges of 6.2 nC (Coulomb) each are separated by 0.3 m. the size and direction of the force between the two charges is 3.8387038*10^12 N and toward left.

Solution:

Given :

Two objects with negative charges of 6.2 nC (nano coulomb ) each.

Separation= 0.3 m.

We will use the following Coulomb’s Law.

F = k*|q1| |q2|/r2             ∵ where k = 8.9876 × 109 N·m2

Putting the values, we get

F = 8.9876 × 109*|6.2| |6.2|/0.3^2

F=3.8387038*10^12 N

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Answer:

The bigger the energy source the more light it makes

Answer:

Energy effects light by heat, and radiation. and the depth of it and how big and other things, radiation can change the appearance slightly and heat also.

for example energy can make light, the light bulb in my opinion is electricity turned off and on Etc.

Energy can be made by light also, and other things that are completely complicated. Just look into generators and how they do that and etc.

The correct option is D, when a newly forming star is at its greatest luminosity, its energy source is gravitational contraction.

Gravitational contraction is the process by which objects in the universe collapse under their own gravity. It occurs when the internal pressure of an object is not strong enough to resist the pull of gravity. This can occur on small or large scales, from the collapse of a gas cloud to form stars to the collapse of entire galaxies.

As an object collapses, its temperature and density increase, and the collapse accelerate due to gravitational potential energy being converted into kinetic energy. This process can lead to the formation of stars, planets, and other objects in the universe. It is also the source of much of the energy released by stars, which powers the universe. Gravitational contraction is an important part of the astronomical theory of the formation of galaxies, stars, and planets.

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Answer:

A. rocky orbiting object

Answer:

A rocky orbiting object.

i hope it's helpful

The percentage of the lost kinetic energy of the car, at the midpoint of the skid, is 50%.

In physics, work is the measurement of the energy used to move objects. When you are walking, you're using energy to move your body so the work done would be greater than zero.

According to work-energy theorem, work is equal to force times displacement (W = F · x).

A type of energy is kinetic energy, which is the energy of a moving object. If an object is at rest, its kinetic energy is zero. Kinetic energy is equal to one half of a mass times velocity squared (KE = 0.5 · m · v²).

When a car goes into a skid and comes to a gradual stop, at the midpoint of the skid the car has spend 50% its kinetic energy. This is simply because the velocity of the car at the midpoint of the skid is half the velocity of the car when the car starts going into a skid, assuming constant acceleration.

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Answer:

C. -35N/m

Explanation:

Using Hooke's Law, we know that the elastic constant of a spring can be found with this formula:
[tex]F=-kx[/tex]

where:

[tex]F[/tex] is the force ( in Newtons)
[tex]k[/tex] is the constant ( in Newtons per meter)
[tex]x[/tex] is the extension ( in meters)

thus, by rearranging the formula we can get:
[tex]k=-\frac{F}{x}[/tex]

[tex]k = -\frac{10}{0.286}[/tex]

[tex]k=-34.96503N/m[/tex]

Rounding off the answer, we get -35N/m

The sky diver falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall.

What is Acceleration?

Acceleration is the rate of change of velocity over time. It is basically a vector quantity, meaning it has both magnitude and direction. Acceleration is caused by a force and is measured in meters per second squared (m/s2).

a) The speed of the skydiver when the parachute opens can be found by using the equation

v=gt,

where g is the acceleration due to gravity and t is the time of free fall.

We can substitute the given values into the equation to find the speed.

v=gt

v=(32ft/s^2)(10s)

v=320ft/s

b) The distance fallen before the parachute opens can be found by using the equation

s=1/2gt^2,

where g is the acceleration due to gravity and t is the time of free fall.

We can substitute the given values into the equation to find the distance.

s=1/2gt^2

s=(1/2)(32ft/s^2)(10s)^2

s=16000ft.

c) The limiting velocity after the parachute opens can be found by using the equation

v_L=√(2mg/ρA)

where m is the mass of the skydiver, g is the acceleration due to gravity, ρ is the density of air, and A is the projected area of the parachute.

We can substitute the given values into the equation to find the limiting velocity.

v_L=√(2(180lb)(32ft/s^2)/(1.225kg/m^3)(6m^2))

v_L=30.68ft/s.

d) The time the sky diver is in the air after the parachute opens can be found by using the equation

t=v/a

where v is the initial velocity, and a is the acceleration due to air resistance.

We can substitute the given values into the equation to find the time.

t=v/a

t=(320ft/s)/(12ft/s^2)

t=26.67s.

So, the sky diver is in the air for 26.67s after the parachute opens.

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Answer:

D(ensity) = M / V = 6.94 g / 13 cm^3 = .534 g / cm^3

Compare to H20 at 1 gm / cm^3

Answer:

D, the lithosphere. (CRUST AND UPPER MANTLE)

Explanation:

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere. Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest. Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).

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https://pubs.usgs.gov/gip/dynamic/tectonic.html#:~:text=A%20tectonic%20plate%20(also%20called,both%20continental%20and%20oceanic%20lithosphere.&text=Continental%20crust%20is%20composed%20of,such%20as%20quartz%20and%20feldspar.

When you touch a piece of wool against your skin, your skin acquires a negative charge because of the conservation of charge, which caused it to gain a positive charge.

Charge is a material's property that can be transferred into another person's body. The transfer of the charge results in the generation of electricity. The following are some examples of charge's various properties: 1 Electric charge addition 2 Electric charge conservation 3 Electric charge quantization. Equations in chemistry are denoted by the capital letter Q to denote charge, with the elementary charge of an electron (e) serving as a standard unit. The coulomb is the SI-derived unit of charge (C). In electrical engineering, the ampere-hour (Ah) unit of charge is frequently used.Dipole Definition in Chemistry and Physics. by this primary information we can consider that when you rub a piece of wool upon your skin and your skin becomes negatively charged because it gained a positive charge as the result of conservation of charge.

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Answer:

t = (x_ball + 8 ) / 0.6

Explanation:

To solve this problem, we can use the equations of motion for the paper ball and Alberta, and then set them equal to each other to find the time and position where they will meet.

The equation of motion for the paper ball is:

x = x0 + v0t + (1/2)at^2

where x is the position of the paper ball, x0 is the initial position (the door), v0 is the initial velocity (2.4 m/s to the right), t is the time, and a is the acceleration (which is 0 for a thrown ball).

The equation of motion for Alberta is:

x = x0 + v0t + (1/2)at^2

where x is the position of Alberta, x0 is the initial position (8 m to the right), v0 is the initial velocity (-0.6 m/s to the left), t is the time, and a is the acceleration (which is 0 for a person running).

If we set these two equations equal to each other, we get:

x_ball = x_alberta

x0 + v0t + (1/2)at^2 = x0 + v0t + (1/2)at^2

This simplifies to:

x_ball = x_alberta

Then we know that both x_ball and x_Alberta are the same point in space (where Alberta met the paper ball)

Now to find time, we need to use one of the original equation for time t. Using equation of motion for Alberta,

x_Alberta = x0 + v0t

So, t = (x_Alberta - x0) / v0

t = (x_ball - 8 ) / (-0.6) = (x_ball + 8 ) / 0.6

The negative sign of velocity of Alberta tells that she is running towards left whereas ball is thrown towards right.

So we can find time and position where Alberta will meet the paper ball by plugging in the specific distance (x_ball) and known values for x0, v0 and acceleration.

B. The springs stretched to double the original displacement, is the the statement that best describe the effect this had on the springs.

The displacement is the shortest distance in geometry and mechanics between the initial and final positions of a point P. From the starting position to the ending position of the point trajectory, it measures the length and direction of the net motion, or total motion, in a straight line. A displacement can be discovered by using the translation that joins the starting point and ending point.

Another way to define a displacement as a relative position is the relationship between a point's final position, or xf, and its starting position, or xi (resulting from motion). The corresponding displacement vector can be defined by the difference between the starting and final positions:

                                            [tex]$ s=x_{\textrm {f}}-x_{\textrm {i}}=\Delta {x}}$[/tex]

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Answer:

14.28 m/s

Explanation:

We use this equation to find ciruclar velocity: v = 2πr/T

Find your given:

r = 5 m

T = 2.2 s

Plug in your given into the equation:

v = 2π(5 m)/2.2 s

v = 14.28 m/s

Answer:

The box with a mass of 10 kilograms would have a greater amount of potential energy than the box with a mass of 4 kilograms.

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Let's assume the height is 5 meters.

Acceleration due to gravity, g = 10 m/s²

For box with mass of 10 kg

[tex] P.E = 10*10*5[/tex]

P.E = 500 Joules.

For box with mass of 4 kg;

[tex] P.E = 4*10*5[/tex]

P.E = 200 Joules.

Hence, the box with a mass of 10 kilograms would have a greater amount of potential energy than the box with a mass of 4 kilograms.

The  assumption which is important in models of galaxy formation is  Some regions in the universe start out denser than others. Option (D) is correct.

Models of galaxy formation begin with the premise that the universe was initially mostly uniformly filled with hydrogen and helium gas, with some regions of this gas being slightly denser than others.

The nucleus, a central bulge, a disc, spiral arms, and a large halo are the four main structural divisions of this structure. Some of the elements combine with one and other. A small portion of the galaxy, the galactic core is located about 400 light-years from the Milky Way's centre. Massive gas clouds which collapse and rotate are the initial point for galaxies. Stars develop within them as they develop. The collision of entire galaxies can change their appearance. When we look far into space, we can observe galaxies in their infancy.

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